Translate the sentence into an inequality. The product of w and 2 is less than 23.​

Answer: About 72%

Step-by-step explanation:

It's a conditional probability.

(Number of graduates on financial aid)/(Number of graduates)

[tex]\frac{1879}{2610} =0.7199[/tex]

0.7199 = 71.99% ≈ 72%

9514 1404 393

Answer:

Step-by-step explanation:

Each image point has its signs reversed from the pre-image point.

  (x, y) ⇒ (-x, -y) . . . . describes the rotation

Rotation from the third quadrant (A) to the first quadrant (A') is a rotation of 180°.

Answer:

3rd and 2nd option

Step-by-step explanation:

Answer:

[tex]41\text{ [units squared]}[/tex]

Step-by-step explanation:

The octagon is irregular, meaning not all sides have equal length. However, we can break it up into other shapes to find the area.

The octagon shown in the figure is a composite figure as it's composed of other shapes. In the octagon, let's break it up into:

Formulas:

Area of triangles:

All four triangles we broke the octagon into are congruent. Each has a base of 2 and a height of 2.

Thus, the total area of one is [tex]A=\frac{1}{2}\cdot 2\cdot 2=2\text{ square units}[/tex]

The area of all four is then [tex]2\cdot 4=8[/tex] units squared.

Area of rectangles:

The two smaller rectangles are also congruent. Each has a length of 3 and a width of 2. Therefore, each of them have an area of [tex]3\cdot 2=6[/tex] units squared, and the both of them have a total area of [tex]6\cdot 2=12[/tex] units squared.

The last rectangle has a width of 7 and a height of 3 for a total area of [tex]7\cdot 3=21[/tex] units squared.

Therefore, the area of the entire octagon is [tex]8+12+21=\boxed{41\text{ [units squared]}}[/tex]

Answer:

51°,51°,78°

Step-by-step explanation:

The sum of angles in a triangle add up to 180°

Answer:

A. x=2 y=7

Step-by-step explanation:

-12x -3 = 3y

6x + 3y = 33

sooo you add them up...

so its

-6x = -12

x=2

and then you plug in the x value into one of the equations

6x + 3y = 33

6(2) + 3y = 33

12 + 3y = 33

3y = 33 - 12

3y = 21

21/3=7

y=7

Answer:

H1 : P1 - P2 = 0

H1 : P1 - P2 > 0

Step-by-step explanation:

The test to be performed on the given data is ; difference in proportion ;

P1 = proportion od rooms in current year

P2 = proportion of rooms

The null hypothesis ``, H0 : p1 - p2 (this onstage null hypothesis and it is the initial truth, representing the notion that no difference in proportion exists.

H1 : P1 - P2 = 0

The alternative hypothesis takes takes the side that there is an increase on proportion of rooms occupied :

H1 : P1 - P2 > 0

For now, I'll focus on the figure in the bottom left.

Mark the point E at the base of the dashed line. So point E is on segment AB.

If you apply the pythagorean theorem for triangle ABC, you'll find that the hypotenuse is

a^2+b^2 = c^2

c = sqrt(a^2+b^2)

c = sqrt((8.4)^2+(8.4)^2)

c = 11.879393923934

which is approximate. Squaring both sides gets us to

c^2 = 141.12

So we know that AB = 11.879393923934 approximately which leads to (AB)^2 = 141.12

------------------------------------

Now focus on triangle CEB. This is a right triangle with legs CE and EB, and hypotenuse CB.

EB is half that of AB, so EB is roughly AB/2 = (11.879393923934)/2 = 5.939696961967 units long. This squares to 35.28

In short, (EB)^2 = 35.28 exactly. Also, (CB)^2 = (8.4)^2 = 70.56

Applying another round of pythagorean theorem gets us

a^2+b^2 = c^2

b = sqrt(c^2 - a^2)

CE = sqrt( (CB)^2 - (EB)^2 )

CE = sqrt( 70.56 - 35.28 )

CE = 5.939696961967

It turns out that CE and EB are the same length, ie triangle CEB is isosceles. This is because triangle ABC isosceles as well.

Notice how CB = CE*sqrt(2) and how CB = EB*sqrt(2)

------------------------------------

Now let's focus on triangle CED

We just found that CE = 5.939696961967 is one of the legs. We know that CD = 8.4 based on what the diagram says.

We'll use the pythagorean theorem once more

c = sqrt(a^2 + b^2)

ED = sqrt( (CE)^2 + (CD)^2 )

ED = sqrt( 35.28 + 70.56 )

ED = 10.2878569196893

This rounds to 10.3 when rounding to one decimal place (aka nearest tenth).

==============================================================

Now I'm moving onto the figure in the bottom right corner.

Draw a segment connecting B to D. Focus on triangle BCD.

We have the two legs BC = 3.7 and CD = 3.7, and we need to find the length of the hypotenuse BD.

Like before, we'll turn to the pythagorean theorem.

a^2 + b^2 = c^2

c = sqrt( a^2 + b^2 )

BD = sqrt( (BC)^2 + (CD)^2 )

BD = sqrt( (3.7)^2 + (3.7)^2 )

BD = 5.23259018078046

Which is approximate. If we squared both sides, then we would get (BD)^2 = 27.38 which will be useful in the next round of pythagorean theorem as discussed below. This time however, we'll focus on triangle BDE

a^2 + b^2 = c^2

b = sqrt( c^2 - a^2 )

ED = sqrt( (EB)^2 - (BD)^2 )

x = sqrt( (5.9)^2 - (5.23259018078046)^2 )

x = sqrt( 34.81 - 27.38 )

x = sqrt( 7.43 )

x = 2.7258026340878

x = 2.7

--------------------------

As an alternative, we could use the 3D version of the pythagorean theorem (similar to what you did in the first problem in the upper left corner)

The 3D version of the pythagorean theorem is

a^2 + b^2 + c^2 = d^2

where a,b,c are the sides of the 3D block and d is the length of the diagonal. In this case, a = 3.7, b = 3.7, c = x, d = 5.9

So we get the following

a^2 + b^2 + c^2 = d^2

c = sqrt( d^2 - a^2 - b^2 )

x = sqrt( (5.9)^2 - (3.7)^2 - (3.7)^2 )

x = 2.7258026340878

x = 2.7

Either way, we get the same result as before. While this method is shorter, I think it's not as convincing to see why it works compared to breaking it down as done in the previous section.

Answer:

Qu 2    =  10.3 cm

Qu 3.   = 2.7cm

Step-by-step explanation:

Qu 2. Shape corner of a cube

We naturally look at sides for slant, but with corner f cubes we also need the base of x and same answer is found as it is the same multiple of 8.4^2+8/4^2 for hypotenuse.

8.4 ^2 + 8.4^2 = sq rt 141.42 = 11.8920141 = 11.9cm

BD = AB =  11.9 cm  Base of cube.

To find height x we split into right angles

formula slant (base/2 )^2 x slope^2  = 11.8920141^2 - 5.94600705^2 =  sq rt 106.065

= 10.2987863

height therefore is x = 10.3 cm

EB = 5.9cm

BC = 3.7cm

CE^2  = 5.9^2 - 3.7^2  = sqrt 21.12 = 4.59565012 = 4.6cm

2nd triangle ED = EC- CD

= 4.59565012^2- 3.7^2 = sq rt 7.43000003 =2.72580264

ED = 2.7cm

x = 2.7cm

Answer:

B

Step-by-step explanation:

49x^2=9

solve for x

x^2= 9/49

x=± [tex]\sqrt{9/49\\}[/tex]

which is x = ±3/7 (B)

Answer: b x=1/9 and x=-1/9

Step-by-step explanation:

Work Shown:

Apply the slope formula

m = (y2-y1)/(x2-x1)

m = (1-3)/(3-(-1))

m = (1-3)/(3+1)

m = -2/4

m = -1/2 is the slope

In decimal form, this converts to -0.5, though usually slopes are in fraction form.

Answer:

Chips: 1.25 and Sandwiches: 6.5

Step-by-step explanation:

3s+2c=22

2s+c=14.25

The cost of bag and chips should be 1.25 and 6.5.

3s+2c=22

2s+c=14.25

Here we need to multiply by 2 in equation 2

3s + 2c = 22

2s + 2c = 28.25

s = 6.5

Now

c should be

2(6.5) + c = 14.25

13 +  c = 14.25

c = 1.25

Learn more: brainly.com/question/16911495

Step-by-step explanation:

Answer:

F(x) moved right 2 units to become G(X).

According to graph transformations, that means G(X) = F(X - 2) = [tex](X-2)^{3}[/tex].

I think that's how you do it :\

Answer:

assuming that you start at the origin (0,0)

(-4,-1) would be the poiny

x coord = -4

y coord = -1

the point is in the 3 quadrant

Step-by-step explanation:

Answer:

DK = 10.23 units (approx)

Step-by-step explanation:

(DK * (CK + KE))/2 = 29

DK * CK = 29

180 - 31 = 149

149/2 = 74.5 --> degree of other angles

tan 74.5 = DK/CK

CK * tan 74.5 = DK

CK * CK * tan 74.5 = 29

CK = 2.83591462

2.83591462 * tan 74.5 = DK

DK = 10.22597776

So DK is approximately 10.23 units.

Hope this helps!

Hello,

in France, the mode is the value having the greater repetition

mode= 5 (repetition=11)

Answer:

Calculating p-value from excel  

p-value = 0.144458 (From excel  =T.DIST.RT(1.091,19))  

p-value = 0.144458 > 0.05  

So, we failed to reject the null hypothesis. There is sufficient evidence to conclude that they pay not more than the national average of $4172.

Step-by-step explanation:

Here the given de4tails are,

Hypothesized mean = 4172

Sample Standard deviation = 1590

Sample mean = 4560

Sample size n = 20

Formulation of hypothesis

Answer:

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

Step-by-step explanation:

The vessels are destroyed without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

In this question:

Fleet of 17 means that [tex]N = 17[/tex]

4 are carrying nucleas weapons, which means that [tex]k = 4[/tex]

9 are destroyed, which means that [tex]n = 9[/tex]

What is the probability that more than 1 vessel transporting nuclear weapons was destroyed?

This is:

[tex]P(X > 1) = 1 - P(X \leq 1)[/tex]

In which

[tex]P(X \leq 1) = P(X = 0) + P(X = 1)[/tex]

So

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]

[tex]P(X = 0) = h(0,17,9,4) = \frac{C_{4,0}*C_{13,9}}{C_{17,9}} = 0.0294[/tex]

[tex]P(X = 1) = h(1,17,9,4) = \frac{C_{4,1}*C_{13,8}}{C_{17,9}} = 0.2118[/tex]

Then

[tex]P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0294 + 0.2118 = 0.2412[/tex]

[tex]P(X > 1) = 1 - P(X \leq 1) = 1 - 0.2412 = 0.7588[/tex]

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

Answer:

C'

Step-by-step explanation:

Given

ABCD to A'B'C'D'

Required

Corresponding angle of C

ABCD to A'B'C'D' means that the following angles are corresponding

[tex]A \to A'[/tex]

[tex]B \to B'[/tex]

[tex]C \to C'[/tex]

[tex]D \to D'[/tex]

Hence, C' corresponds to C

Answer:

C

Step-by-step explanation:

I took the test :)

Answer:

its a

Step-by-step explanation:

trust did test

Answer:

See below

Step-by-step explanation:

Hi there!

We're given that ΔABC≅ΔXYZ

When two triangles are congruent, their corresponding parts are congruent

Because of that, it means vertex A in ΔABC is congruent to vertex X in ΔXYZ, vertex B is congruent to vertex Y, and vertex C is congruent to vertex Z

Since we don't have a picture of the triangles given, we can use the names of the triangles to find the corresponding parts

so, to find the corresponding congruent angle to <BCA:

B is the first letter in the angle, and the corresponding letter in ΔXYZ is Y.

C is the second letter in the angle, and the corresponding letter is Z.

A is the last letter in the angle, and the corresponding letter is X

so that means <YZX is congruent to <BCA

now let's do the same for <ZYX

Z is the first letter in the angle, and the corresponding letter that's in the same place in ΔABC is C

Y is the second letter in the angle, and the corresponding letter is B

X is the last letter in the angle, and the corresponding letter is A

So that means <CBA is congruent to <ZYX

Now to find corresponding sides:

We can still use the names of the triangles, ΔABC and ΔXYZ

so to find the corresponding side to AB,

in ΔABC, AB makes up the first and second letter of the name of the triangle

The corresponding side must also make up the first and second letter of the name of the triangle

in ΔXYZ, the letters X and Y make up the first and second letter

so that means XY must be corresponding to AB

finally,

we need to find the segment congruent to YZ

in ΔXYZ, YZ makes up the second and third letter of the name of the triangle

the corresponding side must also make up the second and third letter of the name of the triangle

in ΔABC,  the letters B and C make up the second and third letter in the triangle

So that means BC must be congruent to YZ

Hope this helps!

Answer:

81

Step-by-step explanation:

Given data:

mean μ = 70.

standard deviation σ, 9.6.

P(Z < 1.123) = 0.13

z = 1.13

Use the z-score formula,

x = z×σ +μ

Substitute the values in the above equation.

x = 1.13 9.6 + 70 = 81

The minimum score required for an A grade is = 81

Answer:

It will take about 109.3 seconds for nine grams of the element to decay to 0.72 grams.

Step-by-step explanation:

We can write a half-life function to model our function.

A half-life function has the form:

[tex]\displaystyle A=A_0\left(\frac{1}{2}\right)^{t/d}[/tex]

Where A₀ is the initial amount, t is the time that has passes (in this case seconds), d is the half-life, and A is the amount after t seconds.

Since the half-life of the element is 30 seconds, d = 30. Our initial sample has nine grams, so A₀ is 9. Substitute:

[tex]\displaystyle A=9\left(\frac{1}{2}\right)^{t/30}[/tex]

We want to find the time it will take for the element to decay to 0.72 grams. So, we can let A = 0.72 and solve for t:

[tex]\displaystyle 0.72=9\left(\frac{1}{2}\right)^{t/30}[/tex]

Divide both sides by 9:

[tex]\displaystyle 0.08=\left(\frac{1}{2}\right)^{t/30}[/tex]

We can take the natural log of both sides:

[tex]\displaystyle \ln(0.08)=\ln\left(\left(\frac{1}{2}\right)^{t/30}\right)[/tex]

By logarithm properties:

[tex]\displaystyle \ln(0.08)=\frac{t}{30}\ln(0.5)[/tex]

Solve for t:

[tex]\displaystyle t=\frac{30\ln(0.08)}{\ln(0.5)}\approx109.3\text{ seconds}[/tex]

So, it will take about 109.3 seconds for nine grams of the element to decay to 0.72 grams.

Answer:

x=40

Step-by-step explanation:

In the picture, it seems that angles BHC, CHD, and DHE form a line, 180 degrees. So to solve, set up an equation:

[tex](2x+5)+55+40=180[/tex]

Take off the parentheses and solve.

Subtract 5, 55 and 40 from both sides, or add them together, then subtract.

5+55+40=100

You get:

[tex]2x=80[/tex]

Divide both sides by 2

You get:

I hope this helps!

Answer:

The slope is -3/4 because it rises goes down 3 and runs 4. the Y-intercept or where the line meets the y line is 3.

Hello,

Since (BD) bissects angle ABC,

18-x=26-3x

2x=8

x=4

18-x=18-4=14

m angle ABC=14°*2=28°

9514 1404 393

Answer:

  (c)  2^r = a

Step-by-step explanation:

The relationship between log forms and exponential forms is ...

  [tex]\log_2(a)=r\ \Leftrightarrow\ 2^r=a[/tex]

__

Additional comment

I find this easier to remember if I think of a logarithm as being an exponent.

Here, the log is r, so that is the exponent of the base, 2.

This equivalence can also help you remember that the rules of logarithms are very similar to the rules of exponents.

Answer: Choice C)  [tex]2^r = a[/tex]

This is the same as writing 2^r = a

==========================================================

Explanation:

Assuming that '2' is the base of the log, then we'd go from [tex]\log_2(a) = r[/tex] to [tex]2^r = a[/tex]

In either equation, the 2 is a base of some kind. It's the base of the log and it's the base of the exponent.

The purpose of logs is to invert exponential operations and help isolate the exponent. A useful phrase to help remember this may be: "if the exponent is in the trees, then we need to log it down".

The general rule is that [tex]\log_b(y) = x[/tex] converts to [tex]y = b^x[/tex] and vice versa.

Answer:

B. Ray FD

Step-by-step explanation:

A common side of two angles is the side shared by the two angles. It is part of the sides that forms both angles.

The common side of <CFD and <DFE is therefore ray FD. Ray FD is part of the sides that forms <CFD and also <DFE.

Answer:

B. Ray FD

Step-by-step explanation:

A common side of two angles is the side shared by the two angles. It is part of the sides that forms both angles.

The common side of <CFD and <DFE is therefore ray FD. Ray FD is part of the sides that forms <CFD and also <DFE.