help me please I have no clue how to do these

[tex]\huge\boxed{\boxed{\underline{\textsf{\textbf{Answer}}}}}[/tex]

Given,

ΔABC ≅ ΔXYZ

If these 2 triangles are congruent with each other then,

∠ A = ∠ X [tex]\boxed{\bf{Corresponding \ parts \ of \ congruent \ triangles}}[/tex]

∠ B = ∠ Y [tex]\boxed{\bf{Corresponding \ parts \ of \ congruent \ triangles}}[/tex]

∠ C = ∠ Z [tex]\boxed{\bf{Corresponding \ parts \ of \ congruent \ triangles}}[/tex]

Now,

We saw that ∠ C = ∠ Z.

⟹ So, if ∠ C = 32°, then even ∠ Z will be equal to 32°. [tex]\boxed{\sf{Equal \ angles \ have \ equal \ measurements}}[/tex]

ᶛɲƧཡэʀ ↦ C. m ∠X = 32°

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ

꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐

Answer: 3(x-3y)

Step-by-step explanation: first you have to take the 3x and split it up so it can make 3(x-3y) then you have to rewrite it to -9 as 3x3 and then factor out common term 3 which would be your final answer 3(x-3y)

Answer:

19

Step-by-step explanation:

Answer:

2

Step-by-step explanation:

Please Mark me brainliest

Hello,

In prime decomposition:

180=2²*3²*5

140=2²*5*7

lcm(180,140)=2²*3²*5*7=1260

Proof: 1260/180=7 and 1260/140=9

Answer:

(4 , -25)

Step-by-step explanation:

that is the procedure above

the vertex of the parabola is calculated by the formula                                          

[tex]\displaystyle\ ax^2+bx+c\quad ;\quad \boxed{x_0=\frac{-b}{2a} \ \ ;\quad y_0 =ax_0^2+bx_0+c} \\\\x_0=-\frac{-8}{2} =4 \quad ; \ \ y_0 =16-32-9=-25 \\\\\ \ Answer: Coordinates \ \ of \ the \ vertex \ of \ the \ \ parabola \ \ (4;-25)[/tex]

Answer:

endo 2 17uni

Step-by-step explanation:

Hello,

First, you must understand that

(f-g)(x) means f(x)-g(x) it is the difference of two functions :

f(x)=2x+4 and g(x)=3x-7

f(5)=2*5+4=10+4=14

g(5)=3*5-7=15-7=8

So, (f-g)(5)= f(5)-g(5)=14-8=6

Answer A: none of the choices are correct.

An other way to do it:

(f-g)(x)=f(x)-g(x)=2x+4-(3x-7)= 2x-3x+4+7=-x+11

if x= 5 then (f-g)(5)=-5+11=6

(1) False. [tex]\{0\}\in\mathscr{U}[/tex] is saying "the set containing only 0 (that is, {0}) is an element of [tex]\mathscr U[/tex]", but this is not the case. [tex]\mathscr U[/tex] is the set containing only 0 and 1.

(2) True. [tex]\{0\}\subset\mathscr{U}[/tex] means "the set {0} is a subset of [tex]\mathscr{U}[/tex]". 0 itself is an element of [tex]\mathscr U[/tex], so {0} is indeed a subset of [tex]\mathscr U[/tex].

(3) True. 0 is clearly an element of [tex]\mathscr U[/tex].

(4) False. This statement says "0 is a subset of [tex]\mathscr U[/tex]" but 0 itself is not a set, it's a number.

Answer:

-3.855

Step-by-step explanation:

Not sure if you need the weight of each screw! but you just subtract 80.955-84.81

Answer:

1

Step-by-step explanation:

itnisbbsndnfnfnfnnfnfnfncjcjccjcj

Answer:

-7x and -2x

Step-by-step explanation:

because -7x and -2x are on the same side of the equation. the equal sign in the equation, -7x+12-2x = 23+13x is basically a different way of writing -7x+12-2x and 23+13x.

they're kind of like 2 separate equations. hope this helped! :)

Answer:

1/10, 0.9, 3/10

Step-by-step explanation:

#carryonlearning

Answer:

k(x) = -2|x - (-3)| + 4

Step-by-step explanation:

Parent function for the graph is,

f(x) = |x|

If the parent function is vertically stretched by a scale factor of 2,

New function will be,

g(x) = 2|x|

If the function 'g' is reflected across x-axis,

h(x) = -2|x|

If the function 'h' is translated 3 units left and 4 units upwards, new function will be,

k(x) = -2|x - (-3)| + 4

Answer:

To change a number from scientific notation to standard form, move the decimal point to the left (if the exponent of ten is a negative number), or to the right (if the exponent is positive). You should move the point as many times as the exponent indicates. Do not write the power of ten anymore

Answer:

it's a trinomial

Answer:

6x - 15

Step-by-step explanation:

f(x) = 2x + 3 and g(x) = 3x - 9.

[tex]f(g(x))=2(3x-9)+3\\f(g(x))=6x-18+3\\f(g(x))=6x-15[/tex]

Answer:

Option (2)

Step-by-step explanation:

From the table attached.

First column is representing the x-values (input values) and second column is representing the value of the function (output values).

For x = -6,

f(x) = 8

For x = 7,

f(x) = 3

For x = 4,

f(x) = -5

For x = 3,

f(x) = -2

For x = -5,

f(x) = 12

Therefore, f(x) = -2 is one of the output values.

Option (2) will be the correct option.

The value that is an output of the function among the options is -2.

A function relates an input to an output.

A function relates each element of a set with exactly one element of another set.

Therefore, the output are the dependent variable. They are also called range.

Generally, they are regarded as range, output or dependent variables.

Therefore, the output of the table is f(x) values which includes the following:

Hence, the output of the function in the option is -2.

learn more on functions here: https://brainly.com/question/26608835

Answer:

B

Step-by-step explanation:

plss pa brainliest me thanks

Answer:

i dont know

Step-by-step explanation:

figure it out yourself

Answer:

y is 4

Step-by-step explanation:

x is 3

y is 4 coordinate is (3,4)

Answer:

4

Step-by-step explanation:

Answer:

Step-by-step explanation:

If the 2 lines are parallel

then x = 70 cos ( alternate interior angle)

but if not sorry man I just in grade 9 its my best effort

Really sorry. <3

:(

Answer:

6/20

Step-by-step explanation:

3/10*2/2=6/20

hope it helped, please mark me brainliest.

Answer:

Step-by-step explanation:

Answer:

m=f+Frt

M=f(1+rt)

M\1+rt=F

Answer:

p = 2/3

q = 1/2

Step-by-step explanation:

The given equation is ,

[tex]\sf\to px^2 + px + 3q = 1 + 2x [/tex]

We can write it as ,

[tex]\sf\to px^2 + px + 3q - 1 -2x=0 [/tex]

Rearrange the terms ,

[tex]\sf\to px^2 - 2x + px + (3q -1)=0 [/tex]

This can be written as ,

[tex]\sf\to px^2 + x ( p - 2) + (3q -1) =0[/tex]

Now wrt Standard form of a quadratic equation ,

[tex]\bf \implies ax^2+bx + c = 0 [/tex]

we have ,

We know that product of zeroes :-

[tex]\to \sf q \times \dfrac{1}{p} = \dfrac{3q-1}{p } \\\\\sf\to 3q - 1 = q \\\\\sf\to 2q = 1 \\\\\sf\to \boxed{ q =\dfrac{1}{2}}[/tex]

Sum of roots :-

[tex]\to \sf q + \dfrac{1}{p} = \dfrac{2-p}{p} \\\\\sf\to \dfrac{ qp + 1}{p}= \dfrac{2-p}{p} \\\\\sf\to qp + 1 = 2 - p \\\\\sf\to p/2 + p = 1 \\\\\sf\to 3p/2 = 1 \\\\\sf\to \boxed{ p =\dfrac{2}{3}}[/tex]

Step-by-step explanation:

Four friends all give each other presents. The total cost of the presents is £80.52. We need to find the mean cost of a present in pounds. So, the mean cost of a present is equal to 20.13 .