Answer:
v= 14 m/s
Explanation:
Assuming no friction losses, the total mechanical energy must be conserved.At the top of the slide, all the energy is gravitational potential energy, as she starts at rest.At the bottom of the slide, if we choose this level as our zero reference level for the gravitational potential energy, all the energy will be purely kinetic.So, we can write the following equality:[tex]\Delta K + \Delta U =0[/tex]⇒ΔK = -ΔU
⇒ [tex](\frac{1}{2}*m*v^{2}-0) =-(0- m*g*h) = m*g*h[/tex]
Rearranging terms and simplifying we can solve for v, as follows:[tex]v_{f} = \sqrt{2*g*h} =\sqrt{2*9.8m/s2*10.0m} = 14 m/s[/tex]
Katie's speed at the bottom of the slide will be 14 m/s.please please please please
Answer:
....................
Answer:
20
Explanation:
40/2.0=20.......
hope it helps
what’s the answer?? middle question
Invisible fence for dogs. In this type of system, a wire is buried under the surface and a current at a given frequency passes through the wire. The dog wears a small unit made of a pickup coil and electronics that delivers a short high-voltage pulse to the dog through a couple of electrodes pressed against its skin. The pulse is not harmful, but it does provide a correction that encourages the dog to keep away. In an invisible fence, the wire carries a 10kHz sinusoidal current with an amplitude of 0.5 Amps. The dog carries a sensoron its collar made as a coil with 150 turns and 30 mm in diameter.If the detection level at the coil inside the collar is set at 200 μV RMS (i.e., the level at which the dog will receive a correction pulse), what is the furthest distance from the wire the dog will "feel" the presence of the fence?
Answer:
The distance is [tex] s = 2.3 \ m [/tex]
Explanation:
From the question we are told that
The frequency of the current is [tex]f = 10\ kHz = 10 *10^{3} \ Hz[/tex]
The magnitude of the current is [tex]I_o = 0.5\ Amps[/tex]
The number of turns is [tex]N = 150\ turns[/tex]
The diameter is [tex]d = 30 mm = 0.03 \ m[/tex]
The detection level is [tex]V_{rms} = 200 \mu V = 200 * 10^{-6} \ V[/tex]
Generally the radius is mathematically represented as
[tex]r = \frac{d}{2}[/tex]
=> [tex]r = \frac{0.03}{2}[/tex]
=> [tex]r 0.015 \ m [/tex]
Generally the magnetic field generated by the fence is mathematically represented as
[tex]B = \frac{\mu_o * N * I}{2 * \pi * s}[/tex]
Here s is the point where the do will feel the magnetic field
[tex]\mu_o[/tex] is the permeability of free space with value [tex]\mu_o = 4\pi * 10^{-7} N/A^2 [/tex]
So
[tex]B = \frac{ 4\pi * 10^{-7} * 150 * I}{2 * 3.142 * s}[/tex]
Generally the magnetic flux is mathematically represented as
[tex]\Phi = B * \pi * r^2[/tex]
=> [tex]\Phi = \frac{ 4\pi * 10^{-7} * 150 * I}{2 * 3.142 * s} * \pi * r^2[/tex]
=> [tex]\Phi = \frac{2.121 *10^{-8} * I }{s}[/tex]
Generally the induced emf is mathematically represented as
[tex]\epsilon =- \frac{d \Phi}{dt}[/tex]
=> [tex]\epsilon =- \frac{ 2.121 *10^{-8} }{ s } * \frac{d I}{dt}[/tex]
Generally the angular frequency is mathematically represented as
[tex]w = 2 \pi f[/tex]
=> [tex]w = 2 * 10*10^{3} \pi [/tex]
=> [tex]w = 20000 \pi [/tex]
So the current is mathematically represented as
[tex]I = I_o sin (wt)[/tex]
=> [tex]I = I_o sin ( 20000 \pi * t)[/tex]
So
[tex]\epsilon =- \frac{ 2.121 *10^{-8} }{ s } * \frac{d [ I_o sin ( 20000 \pi * t)]}{dt}[/tex]
[tex]\epsilon =- \frac{ 2.121 *10^{-8} }{ s } * I_o * 20000 \pi [ cos ( 20000 \pi * t) [/tex]
[tex]\epsilon =- \frac{ 2.121 *10^{-8} }{ s } * 0.5 * 20000 \pi [ cos ( 20000 \pi * t) [/tex]
[tex]\epsilon =- \frac{ 6.6*10^{-4} }{ s } [ cos ( 20000 \pi * t) [/tex]
Here the
[tex]\epsilon_{rms} = \frac{ \frac{ 6.6*10^{-4} }{ s }}{\sqrt{2} }[/tex]
=> [tex]\epsilon_{rms} = \frac{ 6.6*10^{-4} }{ s\sqrt{2} }[/tex]
But from the question we are told that [tex]V_{rms} = 200 \mu V = 200 * 10^{-6} \ V[/tex]
So
[tex]\frac{ 6.6*10^{-4} }{ s\sqrt{2} } = 200 * 10^{-6}[/tex]
=> [tex]6.6*10^{-4}= 2.8284 *10^{-4} * s[/tex]
=> [tex] s = 2.3 \ m [/tex]
What is the purpose of a free body diagram?
CO
to show the velocity of an object
to show the acceleration of an object
to show the forces acting on an object
to show the direction of motion vectors of an object
Answer:
i think the answer is c
Explanation:
zrrxtcyvjvugugyctcyvjv
A free body diagram consists of a diagrammatic representation of a single body or a subsystem of bodies isolated from its surroundings showing all the forces acting on it.
What is free body ?
"A body is said to be "free" when it is singled out from other bodies for the purposes of dynamic or static analysis." The object does not have to be "free" in the sense of being unforced, and it may or may not be in a state of equilibrium; rather, it is not fixed in place and is thus "free" to move in response to forces and torques it may experience.
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corona virus vaccine
Answer:
BIOFLU TABLET
Explanation:
PAG MAY LAGNAT UBO IBIOFLU NAYAN
Answer:
Antibodies are the answer.
Explanation:
Many companies are adding antibodies to ring a bell in the cells to tell the white blood cells to be able to notice the Corona Virus in the blood stream.
A wind tunnel draws atmospheric air at 20°C and 101.3 kPa by a large fan located near the exit of the tunnel. If the air velocity in the tunnel is 80 m/s, determine the pressure in the tunnel.
Answer:
The pressure in the tunnel is 97.45 kPa
Explanation:
Given;
atmospheric pressure, P₁ = 101.3 kPa
air velocity in the tunnel, v₂ = 80 m/s
density of air at 20°C, ρ = 1.204 kg/m³
pressure in the tunnel, P₂ = ?
Apply Bernoulli's equation;
P₁ + ¹/₂ρv₁² + ρgz₁ = P₂ + ¹/₂ρv₂² + ρgz₂
v₁ = 0
z₁ = z₂ = 0
P₁ = P₂ + ¹/₂ρv₂²
P₂ = P₁ - ¹/₂ρv₂²
P₂ = 101.3 kPa - (0.5 x 1.204 x 80²)
P₂ = 101.3 kPa - 3.8528 kPa
P₂ = 97.45 kPa
Therefore, the pressure in the tunnel is 97.45 kPa
I WILL MARK YOU AS BRAINLIEST IF RIGHT
In order to climb up a mountainside, a train needs to start at a speed of 40 mph. The speed limit on the track, however, is 25 mph. How much time does the train need to get up to 40 mph if it can accelerate 4 mph per minute ?
-Cesar the monkey observed the swinging behaviors of his parents. He is now able to swing from branch to branch after much practice. The observation of his parents swinging and practicing what he saw mainly involved _____ neurons; the neurons that are the basis of
Motor
Mirror
Sensory
Reticular
The observation of his parents swinging and practicing what he saw mainly involved sensory neurons.
There are five senses in the human body, they are;
SightSmellTouch TasteHearingInformation is passed to the central nervous system (CNS) from each of these senses.
The neurons that convey sensory information of sight, smell, touch, taste and hearing to the brain are called sensory neurons.
Thus, the observation of his parents swinging and practicing what he saw mainly involved sensory neurons.
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FIGURE 1 shows a horizontal human arm lifting a dumbbell. The forearm is
in equilibrium under the action of the weight of the dumbbell, the tension
in the tendon connected to the biceps muscle, and the force exerted on the
forearm itself. (For clarity, the point A where the tendon is attached is drawn
farther from the elbow than its actual position) Given the weight of the forearm
is 20 N and the mass of the dumbbell is 20 kg. The angle between the tension
force and the horizontal, is 80°. The length of the horizontal arm is 0.30 m.
The horizontal distance between elbow pivot and point A is 0.050 m. Find and
the vector and draw free body diagram for this case
Answer:
Explanation:
See attached file for answer.
A small truck has a mass of 2145 kg. How much work is required to decrease the speed of the vehicle from 25.0 m/s to 12.0 m/s on a level road?
Answer:
The work required is -515,872.5 J
Explanation:
Work is defined in physics as the force that is applied to a body to move it from one point to another.
The total work W done on an object to move from one position A to another B is equal to the change in the kinetic energy of the object. That is, work is also defined as the change in the kinetic energy of an object.
Kinetic energy (Ec) depends on the mass and speed of the body. This energy is calculated by the expression:
[tex]Ec=\frac{1}{2} *m*v^{2}[/tex]
where kinetic energy is measured in Joules (J), mass in kilograms (kg), and velocity in meters per second (m/s).
The work (W) of this force is equal to the difference between the final value and the initial value of the kinetic energy of the particle:
[tex]W=\frac{1}{2} *m*v2^{2}-\frac{1}{2} *m*v1^{2}[/tex]
[tex]W=\frac{1}{2} *m*(v2^{2}-v1^{2})[/tex]
In this case:
W=?m= 2,145 kgv2= 12 [tex]\frac{m}{s}[/tex]v1= 25 [tex]\frac{m}{s}[/tex]Replacing:
[tex]W=\frac{1}{2} *2145 kg*((12\frac{m}{s} )^{2}-(25\frac{m}{s} )^{2})[/tex]
W= -515,872.5 J
The work required is -515,872.5 J
The amount of work needed by the vehicle to decrease its speed from 25 m/s to 12 m/s is 515872.5 J.
The amount of work required by the truck to decrease its speed can be calculated using the formula below.
Formula:
W = m(u²-v²)/2............. Equation 1Where:
W = amount of work required to decrease the speed of the vehicle.m = mass of the truckv = Final speedu = initial speed.From the question,
Given:
m = 2145 kgv = 12 m/su = 25 m/s.Substitute these values into equation 1
W = 2145(25²-12²)²/2W = 2145(481)/2W = 515872.5 J.Hence, The amount of work needed by the vehicle to decrease its speed from 25 m/s to 12 m/s is 515872.5 J.
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When using the superposition theorem on a two-source network, if the current produced by one source is in one direction, while that produced by the other source is in the opposite direction through the same resistor Select one: A. a mistake in the sign of the result occurred. B. the resulting current is the difference of the two and has the direction of the larger current. C. all voltage sources were not properly converted to current sources. D. the absolute values of the two currents add algebraically, and the direction is the same as the direction of the larger current.
Answer: B. The resulting current is the difference of the two and has the direction of the larger current.
Explanation: Superposition Theorem states that the result in a particular branch of a linear circuit when a variety of sources are acting at the same time equals the sum of the response of each particular source acting at a time, i.e., if sources are acting on a line circuit, the resulting current in any branch is the sum of all the currents produced if each source is producing it by itself.
To solve by this method:
1) Find current in a particular branch considering one only independent source and deactivating the others;
2) Repeat the first step for all the sources in the circuit;
3) Add all the results: If the current obtained is in the same direction, add them; If it's in the opposite direction, subtract them and obtain the net current;
Therefore, when using superposition, if one current is in one direction and the other produced by other source is in the opposite direction, the net current is the difference between the two abd has the direction of the larger current.
A 30.0 g object fell from a height y = 2.94 m. It’s velocity when y is zero is approximately equal to (in m/s) (a) 0 (b) 19.6 (c) 29.4 (d) 8.64
Analysing the question:
We are given:
mass of object (m) = 0.03 kg
height of object (h) = 2.94 m
acceleration due to gravity (a) = 10 m/s²
initial velocity (u) = 0 m/s [the object fell, we are NOT given any initial velocity]
final velocity (v) = v m/s
Solving for Final velocity:
from the third equation of motion:
v² - u² = 2ah
replacing the variables
(v)² - (0)² = 2(10)(2.94)
v² = 58.8
v = 7.67 m/s
Sheba is texting and driving. She does not see the baby chinchila
sitting in the road! If she was traveling at 35 m/s, and at best her
car can accelerate at -3.5 m/p/s, how far would it take her to stop?
Answer:
dfmwekognjioq 4eijqgi24gno3p2qtijoq2 gjo23ijgto32tneqew gqewkgnoweqgmnlqwe gwjoegkqwji4toqn34goti34
Explanation:
A barometer accidentally contains 6.5 inches of water on top of the mercury column (so there is also water vapor instead of a vacuum at the top of the barometer). On a day when the temperature is 70oF, the mercury column height is 28.35 inches (corrected for thermal expansion). (a) Determine the barometric pressure in psia. If the ambient temperature increased to 85oF and the barometric pressure did not change, (b) would the mercury column be longer, be shorter, or remain the same length
Answer:
(a). 14.4 lbf/in^2.
(b). 27.8 in, AS THE TEMPERATURE INCREASES, THE LENGTH OF MERCURY DECREASES.
Explanation:
So, from the question above we are given the following parameters which are going to help us in solving this particular Question;
=> The "barometer accidentally contains 6.5 inches of water on top of the mercury column (so there is also water vapor instead of a vacuum at the top of the barometer)"
=> "On a day when the temperature is 70oF, the mercury column height is 28.35 inches (corrected for thermal expansion)."
With these knowledge, let us delve right into the solution;
(a). The barometric pressure = water vapor pressure + acceleration due to gravity (ft/s^2) × water density(slug/ft^3) × {ft/12 in}^3 × [ height of mercury column + specific gravity of mercury × height of water column].
The barometric pressure= 0.363 + {(62.146) ÷ (12^3) × 390.6425}. = 14.4 lbf/in^2.
(b). { (13.55 × length of mercury) + 6.5 } × (62.15÷ 12^3) = 14.4 - 0.603.
Length of mercury = 27.8 in.
AS THE TEMPERATURE INCREASES, THE LENGTH OF MERCURY DECREASES.
Before Collision Consider a system to be one train car moving toward another train car at rest When the train cars collide, the two cars stick together What is the total momentum of the system after the collision? O 800 kg . m/s m, = 600 kg V,= 4 m/s m = 400 kg v2 = 0 m/s 1,600 kg. m/s 0 2,400 kg • m/s 0 4,000 kg . m/s After Collision
Answer:
2,400kg * m/s
Explanation:
You are missing some information in the question but the rest could be found some where else.
The question gives the masses and starting velocity of each car.
Car 1: m = 600kg and sv = 4m/s
Car 2: m 400kg and sv = 0m/s
Find the momentum of both cars.
Car 1: 600 * 4 = 2400
Car 2: 400 * 0 = 0
Add both.
2400 + 0 = 2400
Best of Luck!
Answer: answer C
Explanation:
Your welcome
What is the equivalent temperature in kelvin if you have a metal at 50°F?
A.
50 K
B.
150 K
C.
283 K
D.
300 K
Answer:
The answer is C 283 kelvin
Answer: C.
283 K
Explanation: edmentum
The current in the wires of a circuit is 180.0 milliamps. If the resistance of the circuit were doubled ( with no change in voltage), then its new current would be
Answer:
I = 0.09[amp] or 90 [milliamps]
Explanation:
To solve this problem we must use ohm's law, which tells us that the voltage is equal to the product of the voltage by the current.
V = I*R
where:
V = voltage [V]
I = current [amp]
R = resistance [ohm]
Now, we replace the values of the first current into the equation
V = 180*10^-3 * R
V = 0.18*R (1)
Then we have that the resistance is doubled so we have this new equation:
V = I*(2R) (2)
The voltage remains constant therefore 1 and 2 are equals and we can obtain the current value.
V = V
0.18*R = I*2*R
I = 0.09[amp] or 90 [milliamps]
Physics Vectors-- Please could you help me ? For first question.
What happens to the acceleration of a ball if the force increases while the mass remains the same?
Answer:
if the force increases while the mass of the ball remains the same, the acceleration increases.
Explanation:
According to Newton's second law of motion, the acceleration of an object produced by a net force is directly proportional to the magnitude of the net force Fn and inversely proportional to the mass of the object m.
[tex]\displaystyle a=\frac{Fn}{m}[/tex]
Suppose the net force doubles to 2Fn. The new acceleration will be:
[tex]\displaystyle a'=\frac{2Fn}{m}=2\frac{Fn}{m}=2a[/tex]
The acceleration doubles too. Thus, if the force increases while the mass of the ball remains the same, the acceleration increases.
Why does a sound come out when you blow into a bottle?
When does the jet of air convert to vibrations?
True or false:
A small wire can conduct an infinite amount of current.
Answer:
True
Explanation:
Answer: very true
Explanation:
g A person exploring a deep cave system becomes injured and needs to be rescued. The fastest way to get them is to pull them straight up out of the cave through a small opening just overhead, using a motor-driven cable. The lift is performed in three stages, each of them 10 m in height (total of 30 meters to extract the person). In the first stage, the person is accelerated to a speed of 5 m/s. They are then lifted at constant speed of 5 m/s, then in the last stage they are slowly decelerated to zero speed. If the person weighs 80 kg, how much work is done in each stage
Answer:
1. W = 8848 J
2. W = 7848 J
3. W = 6848 J
Explanation:
The work (W) can be found using the following equation:
[tex] W = E_{k} + E_{p} [/tex]
Where: E(k) is the kinetic energy and E(p) is the potential energy
Now let's find the work for every stage.
Stage 1:
[tex] W = E_{k} + E_{p} = \frac{1}{2}mv^{2} + mgh [/tex]
Where: m is the mass, g is the gravity, h is the height, v is the speed
[tex] W = \frac{1}{2}mv^{2} + mgh = \frac{1}{2}80 kg*(5 m/s)^{2} + 80 kg*9.81 m/s^{2}*10 m = 8848 J [/tex]
Stage 2:
[tex] W = E_{k} + E_{p} = 0 + E_{p} [/tex]
The kinetic energy is equal to zero because the acceleration is constant.
[tex] W = E_{p} = mgh = 80 kg*9.81 m/s^{2}*10 m = 7848 J [/tex]
Stage 3:
[tex] W = E_{k} + E_{p} = \frac{1}{2}mv^{2} + mgh = -\frac{1}{2}80 kg*(5 m/s)^{2} + 80 kg*9.81 m/s^{2}*10 m = 6848 J [/tex]
I hope it helps you!
Consider the data table charting the speed of a toy car moving across the floor. The line graph representing this data would BEST be described as a?
A) Curved line with varying slope
B) Diagonal line with a slope of 3
C) Horizontal line with a slope of 3
D) Diagonal line with varying slope, from 3 to 4
Answer:
The answer is D) diagonal line with varying slope, from 3 to 5 on USATestprep
Explanation:
To a stationary observer, a man jogs east at 2 m/s and a woman jogs west at
3 m/s. From the woman's frame of reference, what is the man's velocity?
Answer:
5 m/s east
Explanation:
i just took the test and it was correct
Answer:
Just took the test. 5 m/s east.
Explanation:
How do waves transfer energy? Be detailed.
Answer:
Electromagnetic waves transfer energy through vibrations of electric and in magnetic fields. For sound waves the energy is transferred through the vibration of air particles or particles of a solid. Waves also carry energy, the amount of energy they carry depends on their frequency and their amplitude. The more energy and the higher frequency amplitude, the more energy waves are ^‿^
What element has similar chemical properties to lodine?*
Answer:
Iodine is most similar to the other non- metals in the Halogen Family, such as Fluorine, Chlorine, Bromine, Astatine .
Explanation:
PLS HELP THIS IS FOR AN EXAM!!!
How many exercises encompass stretching in the human body
A) eight
B) too many to count
C) that depends on each individual
D) none
Answer: (B) Too many to count
Explanation: Have a wonderful day everyone! :D
The exercises that encompasses stretching in the human body is : B) too many to count
Meaning of exerciseexercises can be defined as any activity that puts your muscle to work and helps burn calories in your body.
exercises are one of the keys to staying and living healthy.
exercises are of different types and forms and some encompasses stretching in the human body.
In conclusion, The exercises that encompasses stretching in the human body is too many to count
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The superhero Green Lantern steps from the top of a tall building. He falls freely from rest to the ground, falling half the total distance to the ground during the last 1.00 s of his fall (Fig. 2.30). What is the height h of the building?
SOLUTION GUIDE
IDENTIFY and SET UP
1. You’re told that Green Lantern falls freely from rest. What does this imply about his acceleration? About his initial velocity?
2. Choose the direction of the positive y -axis. It’s easiest to make the same choice we used for freely falling objects in Section 2.5.
3. You can divide Green Lantern’s fall into two parts: from the top of the building to the halfway point and from the halfway point to the ground. You know that the second part of the fall lasts 1.00 s. Decide what you would need to know about Green Lantern’s motion at the halfway point in order to solve for the target variable h. Then choose two equations, one for the first part of the fall and one for the second part, that you’ll use together to find an expression for h. (There are several pairs of equations that you could choose.)
EXECUTE
4. Use your two equations to solve for the height h. Heights are always positive numbers, so your answer should be positive.
Answer:
1) its initial velocity is zero, 2) the downward direction as positive
3) h = 25.66 m
Explanation:
This is a free fall exercise.
1) with falls, its initial velocity is zero and the acceleration is constant throughout the path and is equal to the acceleration due to gravity.
2) a widely used selection to estimate the downward direction as positive
3) We know that for the second part of the fall
y₀ -y = h/2 at t = 1 s
y = y₀ + v₁ t + ½ g t²
where v₁ is the initial velocity of this interval at the point y = h / 2
v₁ t = (y -y₀) - ½ g t²
v₁ = h / 2 - ½ g t²
v₁ = h/2 - g/2
now let's write the equation for the first interval
v₁² = v₀² + 2 g (y₁ - y₀)
in this interval v₀ = 0
v₁² = 2 g (y₁ -y₀)
v₁² = 2g h/2
we write our system of equations
v₁² = (h/2 - g/2)²
v₁² = (2g h / 2)
(h /2 - g/2)² = (2g h / 2)
h² / 4 - 2 g/2 h/2 + (g/2)² = g h
h² / 4 - g h/2 - g h + g²/4 = 0
h² - 3 g h + g² =0
h² - 29.4 h +96.04 = 0
we solve the quadratic equation
h = [29.4 ±√ (29.4² - 4 96.04)] / 2
h = [29.4 ± 21.91] / 2
h₁ = 25.66 m
h₂ = 3.75 m
As the system takes more than 1 S to fall, the correct answer for the height is h = 25.66 m
Answer 1)
This is a free fall exercise with falls, its initial velocity is zero and the acceleration is constant throughout the path and is equal to the acceleration due to gravity.
Answer B :
A widely used selection to estimate the downward direction as positive.
Answer 3:
We know that for the second part of the fall:
y₀ -y = h/2 at t = 1 s
y = y₀ + v₁ t + ½ g t²
where v₁ is the initial velocity of this interval at the point
y = h / 2
v₁ t = (y -y₀) - ½ g t²
v₁ = h / 2 - ½ g t²
v₁ = h/2 - g/2
Answer 4:
Now let's write the equation for the first interval
v₁² = v₀² + 2 g (y₁ - y₀)
in this interval v₀ = 0
v₁² = 2 g (y₁ -y₀)
v₁² = 2g h/2
we write our system of equations
v₁² = (h/2 - g/2)²
v₁² = (2g h / 2)
(h /2 - g/2)² = (2g h / 2)
h² / 4 - 2 g/2 h/2 + (g/2)² = g h
h² / 4 - g h/2 - g h + g²/4 = 0
h² - 3 g h + g² =0
h² - 29.4 h +96.04 = 0
we solve the quadratic equation
h = [29.4 ±√ (29.4² - 4 96.04)] / 2
h = [29.4 ± 21.91] / 2
h₁ = 25.66 m
h₂ = 3.75 m
As the height is h = 25.66 m.
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Explain whether the size of an object's displacement could be greater than the distance the object travels
Answer:
Displacement is always less than or equal to distance. Note that distance is a scalar whereas displacement is a vector. So displacement cannot be more than distance.
The size of an object's displacement can never be greater than the distance the object travels by the object because displacement is the shortest distance traveled between the initial and the final position.
What is displacement?An object's position changes if it moves in relation to a reference frame, such as when a passenger moves to the back of an airplane or a professor moves to the right in relation to a whiteboard.
Displacement can never be greater than the distance covered by any moving body.
Since displacement is the smallest distance between the beginning and final positions, the size of an object's displacement can never be more than the distance the object travels.
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what happends when you slowly pull out the paper while theirs a coin on top