AVERAGES 1. Find the mean, mode and median of: (a) 1.5, 1.2, 1.3, 1.5, 1.4 (b) 2.3, 1.2, 2.4, 1.2​

Answer:

the answer to both are 1. 3.77 2.19.94

Answer:

We can find the system equivalent to this one by replacing one of the equations with a multiply of itself, so:

Let’s multiply y = x-2 by 2

2y=2x-4

A system equivalent to this one is

y = -2x^2 (this remains the same)

2y= 2x-4

Our point is at -5, 3. -5 represents its x coordinate, and 3 represents its y coordinate. 3 units right makes it -2, while 2 units down makes it 1. Final coords of the point are (-2,1).

Answer:

given point is (-5,3)

right unit means positive and down unit means negative so,

image of (-5,3)---------->(-5+3-2,3+3-2)

=>(-7+3,6-2)

=>(-4,4) ANS.

Answer:

100 dimes and 50 nickels

Step-by-step explanation:

5×50=2.00

10×100=10.00

Answer: slope is -3/2

Step-by-step explanation:

(-2,5) (4,-4)

Use the slope formula y2-y1/x2-x1

5-(-4)/-2-4 = -3/2

Answer:

The slope of the line containing (-2,5) and (4,-4) is [tex]-\frac{3}{2}[/tex]

Step-by-step explanation:

Answer:

2 x 2 x 2 x 3 x 5

Step-by-step explanation:

The first and smallest prime number that can be divisible by 120 is 2; 120/2 = 60, 60/2 = 30, 30/2 = 15; and the smallest prime number divisible by 15 is 3; 15/3 = 5; and the smallest prime number divisible by 5 is 5; 5/5 = 1.

hence, we have 2 x 2 x 2 x 3 x 5 = 2³ x 3 x 5

Answers:

=================================================

Explanation:

Let's say that the letter k replaces the green box

We have the equation y = kx

Plug in (x,y) = (7,35) to get the equation 35 = k*7

Dividing both sides by 7 leads to k = 5

Therefore, the direct variation equation is y = 5x

We can check this by plugging in x = 7

y = 5x

y = 5*7

y = 35

So x = 7 leads to y = 35 as expected.

-------------

Do the same for x = 4

y = 5x

y = 5*4

y = 20 when x = 4

Side note: direct variation equations always go through the origin.

Answer:

20

Step-by-step explanation:

if y varies directly with x, then it takes the form y=mx

to find m, substitute in the values of x and y to get 35=m*7 and simplify to get that m=5

then the equation becomes y=5x

substitute in the value they gave for x which is 4 to get y=5*4

to get that y=20

Answer:

There was no van stated in the question, but if the van was the truck, the answer would be $50.

Step-by-step explanation:

We can split the problem into 2 parts. First, there is a flat fee of $30 to rent the truck.

Now, we can calculate the cost to rent the truck for 80 miles excluding the flat fee by multiplying the values together.

$0.25/mile * 80 miles = $20

Now, we can add the values up.

This will give us: $30 + $20 = $50

Answer:

8 tails I think so If the answer is correct plz mark me the brainliest

Answer:

The relationship is not linear.

Hope this answer is right!!

Answer:

[tex]192.27\:\mathrm{cm^2}[/tex]

Step-by-step explanation:

The area of sector with radius [tex]r[/tex] and measure [tex]\theta[/tex] is give by [tex]A=r^2\pi\cdot \frac{\theta}{360^{\circ}}[/tex]. Since vertical angles are congruent, the two shaded sectors in the figure are congruent.

What we're given:

Therefore, the area of the shaded regions (two sectors) is:

[tex]A=2\cdot 9^2\pi\cdot \frac{136}{360}=192.2654704\approx \boxed{192.27\:\mathrm{cm^2}}[/tex]

Answer:

8 - 42x - 56y - 12xy

Step-by-step explanation:

Length = 4 - 7(3x + 4y)

= 4 - 21x - 28y

Width = 3x(-2y)

= -6xy

Perimeter of the rectangle = 2(length + width)

= 2{(4 - 21x - 28y) + ( -6xy)}

= 2(4 - 21x - 28y - 6xy)

= 8 - 42x - 56y - 12xy

Perimeter of the rectangle = 8 - 42x - 56y - 12xy

Answer:

[tex]the \: equation \: is \: equivalent \: to \\ 2 \: { \sin }^{2} (( \: \frac{\pi}{2}) \: {cos}^{2} x ) = \\ \: 2 \: {sin}^{2} (( \frac{\pi}{2} sin \: 2x \: ) \\ = {cos}^{2} x = sin \: 2x \\ = \: \cos \: x(cos \: x \: - \: 2 \: sin \: x) \: = \: 0 \\ = \: 1 - 2 \tan \: x = 0 \: as \: cos \: x \: ≠ 0 \\ x ≠ (2n + 1) \frac{\pi}{2} \\ = \tan(x) = \frac{1}{2} \\ = \cos(2x) = \frac{1 - {tan \: }^{2}x }{1 + {tan \: }^{2} \:x } = \frac{3}{5} [/tex]

Given:

The function is:

[tex]f(x)=\{(1,0),(2,3),(3,6)\}[/tex]

The given function is:

[tex]f(x)=1-2x[/tex]

The range of this function is [tex]\{-3,-5,-7\}[/tex].

To find:

The range of first function.

The domain of second function.

Solution:

Domain is the set of input or x-values and range is the set of output or y-values.

We have,

[tex]f(x)=\{(1,0),(2,3),(3,6)\}[/tex]

Here, the x-values are 1, 2, 3 and the y-values are 0, 3, 6.

Therefore, the range of the given function is [tex]\{0, 3, 6\}[/tex]. Hence, the correct option is C.

The given function is:

[tex]f(x)=1-2x[/tex]            ...(i)

The range of this function is [tex]\{-3,-5,-7\}[/tex].

Putting [tex]f(x)=-3[/tex] in (i), we get

[tex]-3=1-2x[/tex]

[tex]-3-1=-2x[/tex]

[tex]\dfrac{-4}{-2}=x[/tex]

[tex]2=x[/tex]

Similarly,

Putting [tex]f(x)=-5[/tex] in (i), we get

[tex]-5=1-2x[/tex]

[tex]3=x[/tex]

Putting [tex]f(x)=-7[/tex] in (i), we get

[tex]-7=1-2x[/tex]

[tex]4=x[/tex]

The domain of this function is [tex]\{2,3,4\}[/tex]. Hence, the correct option is A.

Answer:

Step-by-step explanation:

x/7 - 13 ≥ -11

x/7 ≥ 2

x ≥ 14

m/-6 + 16 ≥ 19

m/-6 ≥ 3

m/6 ≤ -3

m ≤ -18

Answer:

See Explanation

Step-by-step explanation:

The question is incomplete, as the required data are not given.

I will use the following data as an illustration of how to calculate median and range.

We have:

[tex]x: 11, 13, 14, 15, 18, 20[/tex]

Calculate range

Identify the highest and the least

[tex]Highest = 20[/tex]

[tex]Least = 11[/tex]

So, the range is:

[tex]Range = Highest -Least[/tex]

[tex]Range =20-11[/tex]

[tex]Range =9[/tex]

Calculate the median

The number of data we are using is 6 (i.e. even).

So, the position of the median item is:

[tex]Median =\frac{1}{2}(n+1)[/tex]

[tex]Median =\frac{1}{2}(6+1)[/tex]

[tex]Median =\frac{1}{2}*7[/tex]

[tex]Median =3.5th[/tex]

A decimal result implies that the median is the mean of the integer values before and after the result.

In this case, the median is the mean of the item at 3rd and 4th positions.

So:

[tex]Median = \frac{14+15}{2}[/tex]

[tex]Median = \frac{29}{2}[/tex]

[tex]Median = 14.5[/tex]

Answer:

Step-by-step explanation:

Explanation:

First, find two points on the line if you change the inequality to an equation.

For  

x

=

0

:  

0

+

2

y

=

4

2

y

=

4

2

y

2

=

4

2

y

=

2

or  

(

0

,

2

)

For  

y

=

0

:  

x

+

0

=

4

x

=

4

or  

(

4

,

0

)

We can plot these two points and draw a line through them to get the border of the inequality:

graph{(x^2+(y-2)^2-0.075)((x-4)^2+y^2-0.075)(x+2y-4)=0}

The line will be solid because the inequality operator has a "or equal to" clause in it. We can now shade the area to the right of the line because the inequality has a "great than" clause in it.

graph{(x+2y-4)>=0}

Answer:

x = - 72

Step-by-step explanation:

Given

- 16 = [tex]\frac{x}{4}[/tex] + 2 ( subtract 2 from both sides )

- 18 = [tex]\frac{x}{4}[/tex] ( multiply both sides by 4 to clear the fraction )

- 72 = x

Answer is = - 72

It's a Right answer....

Mark me as brainliest....

Answer:

14. (8,9,10)

15.no(A)

this is the answer

Answer:

ssueuwuwiaiwaiaiiaiw

Answer:

angle TVU

Step-by-step explanation:

angle UVT

please mark as brainliest

Answer:

a) 16 + 29 = p

or

a) p - 16 = 29

b) is confusing

Step-by-step explanation:

Answer:

"A"

Step-by-step explanation:

C & D start at 12... story starts at 15

3*3600 = 10,800 ....   15,000-10,800 = 4200

at 3 the graph has to be at 4200 (which is above 3)

note at 3 "B" is at 3 so answer has to be "A"

Step-by-step explanation:

a) fg(x) = f(x²-1) = 2(x²-1) + 3

= 2x² + 1

b) gf(x) = (2x+3)² - 1

= 4x² + 12x + 9 - 1

= 4x² + 12x + 8

c) fg(2) replace the value in a)

fg(2) = 2(2²) + 1

= 9

Answer:

None, each of the four given system of equations have only one solution

Step-by-step explanation:

A system of equations have infinitely many solutions, when the equations represent the same line and therefore, the two equations are the same;

Each of the options are examined as follows;

a. 4·x + 2·y = 5...(1)

-4·x - 2·y = 1...(2)

Expressing both equations with y as the subject, we have;

The value of y in equation (1) is given as follows;

4·x + 2·y = 5

2·y = 5 - 4·x

∴ y = 5/2 - 2·x

The value of y in equation (2) is given as follows;

-4·x - 2·y = 1

-2·y = 1 + 4·x

∴ y = -1/2 - 2·x

Therefore, equation (1) and equation (2) represent the same equation and are therefore equal and have only one solution

b. -10·x + y = 4...(1)

10·x - y = 4...(2)

Therefore, we have;

Adding equation (1) to equation (2) gives;

-10·x + 10·x + y - y = 4 + 4

0 + 0 = 8

0 = 8

Given that 0 ≠ 8, equation (1) is not equal to equation (2) and the two equations have only one solution

c. -8·x + y = 2...(1)

8·x - y = 0...(2)

By examination, the values on the left hand side, LHS, of both equations are the same magnitude but opposite in sign, while the right hand side, RHS, of both equations, have different magnitude

Therefore, the two equations are different and have only one solution

d. -x + 2·y = 6...(1)

7·x - 2·y = 12...(2)

Making y the subject of both equations gives;

Equation (1)

2·y = 6 + x

y = 3 + x/2

Equation (2)

2·y = 12 - 7·x

y = 6 - 3.5·x

Therefore, the two equations are different and have only one solution

Answer:

B

Step-by-step explanation:

I'm guessing the answer is B. I know why the other person said all of them only have one solution. But, On b You wrote -10x+y=4  10x-y=4

When really it was supposed to be -10x+y=4  10x-y=-4

Step-by-step explanation:

Answer

Open in answr app

Correct option is

B

±2

x=3+22   x1=3+221×3−223−22

=3−22

(x−21)2=x+x1−2

=3+22+3−22−2=4

So, x−x1=4=±2 Ans 

Answer:

36.32

Step-by-step explanation:

Given the data:

X = 12,106,94,100,180

The mean absolute deviation is calculated thus :

MAD = |x - mean| / n

Where n = sample size

Mean = Σx / n = (12 + 106 + 94 + 100+ 180) / 5 = 98.4

MAD = (|12 - 98.4| + |106 - 98.4| + |94 - 98.4| + |100 - 98.4| + |180 - 98.4|) / 5

MAD = 36.32

Answer:

[tex](a)\ \sqrt5 <2.3 < 5.6[/tex]

[tex](b)\ \sqrt 5 <2.4 < 5.6[/tex]

[tex](e)\ \sqrt 8 <2.9[/tex]

[tex](f)\ \sqrt5 <4.5 < 5[/tex]

Step-by-step explanation:

Required

Which are true

[tex](a)\ \sqrt5 <2.3 < 5.6[/tex]

Take square root of 5

[tex]2.2 <2.3 < 56[/tex] --- This is true

[tex](b)\ \sqrt 5 <2.4 < 5.6[/tex]

Take square root of 5

[tex]2.2 <2.4 < 56[/tex]  --- This is true

[tex](c)\ 7.4 < 5 <5.5[/tex]

This is false because [tex]7.4 > 5[/tex]

[tex](d)\ \sqrt 3 <3 <3[/tex]

This is false because [tex]3 = 3[/tex] not [tex]3 < 3[/tex]

[tex](e)\ \sqrt 8 <2.9[/tex]

Take square root of 8

[tex]2.8 <2.9[/tex] --- This is true

[tex](f)\ \sqrt5 <4.5 < 5[/tex]

Take square root of 5

[tex]2.2 <4.5 < 5[/tex] --- This is true