Which statement describes the magnetic field inside a bar magnet? It points from north to south. It points from south to north. It forms loops inside the magnet. There is no field within the magnet.

Answers

Answer 1

Inside the bar magnet, the magnetic field points from north to south. Statement A is correct.

Magnetic Field:

It is defined as a vector field or the influence of the magnet on the electric current, charges and ferromagnetic substance.

The strength of magnetic field is depends up on the numbers of magnetic field lines per unit area.

Magnetic field lines emerge from the North pole and end in the South pole of a bar magnet. Inside the magnet are also present inside the bar magnet and never intersect at any point.

Therefore, inside the bar magnet, the magnetic field points from north to south.

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Answer 2

Answer:b

Explanation:


Related Questions

what is the cost of monthly (30 days) electric bill of ana if her city's cost of electricity is 0.05$ per kwh and she uses three refrigerators running in 600-watt power rating and open 24 hours

Answers

Answer:

1kW = 1000W

600W = 0.6kW

Cost of electric bill = 0.6kWh × 24 × 30 × $0.05

                               = $21.60

the smallest division value of electronic balance​

Answers

Answer:

0.1g to 0.0000001g hope it helps uu

A 0.15 kg baseball moving at 20 m/s is stopped by a player in 0.010 s. What is the average force of the ball?

Answers

Answer: 300N

Explanation:

Impulse= Mass * Velocity

F.T = M * V

F= MV/T

F= (0.15*20)/ 0.01

F= 300N

anyone to help with this question​

Answers

Answer:

i can

Explanation:

i know what's the answer

what is the energy (in j) of a photon required to excite an electron from n = 2 to n = 8 in a he⁺ ion? submit an answer to three signficant figures.

Answers

Answer:

Approximately [tex]5.11 \times 10^{-19}\; {\rm J}[/tex].

Explanation:

Since the result needs to be accurate to three significant figures, keep at least four significant figures in the calculations.

Look up the Rydberg constant for hydrogen: [tex]R_{\text{H}} \approx 1.0968\times 10^{7}\; {\rm m^{-1}[/tex].

Look up the speed of light in vacuum: [tex]c \approx 2.9979 \times 10^{8}\; {\rm m \cdot s^{-1}}[/tex].

Look up Planck's constant: [tex]h \approx 6.6261 \times 10^{-34}\; {\rm J \cdot s}[/tex].

Apply the Rydberg formula to find the wavelength [tex]\lambda[/tex] (in vacuum) of the photon in question:

[tex]\begin{aligned}\frac{1}{\lambda} &= R_{\text{H}} \, \left(\frac{1}{{n_{1}}^{2}} - \frac{1}{{n_{2}}^{2}}\right)\end{aligned}[/tex].

The frequency of that photon would be:

[tex]\begin{aligned}f &= \frac{c}{\lambda}\end{aligned}[/tex].

Combine this expression with the Rydberg formula to find the frequency of this photon:

[tex]\begin{aligned}f &= \frac{c}{\lambda} \\ &= c\, \left(\frac{1}{\lambda}\right) \\ &= c\, \left(R_{\text{H}}\, \left(\frac{1}{{n_{1}}^{2}} - \frac{1}{{n_{2}}^{2}}\right)\right) \\ &\approx (2.9979 \times 10^{8}\; {\rm m \cdot s^{-1}}) \\ &\quad \times (1.0968 \times 10^{7}\; {\rm m^{-1}}) \times \left(\frac{1}{2^{2}} - \frac{1}{8^{2}}\right)\\ &\approx 7.7065 \times 10^{14}\; {\rm s^{-1}} \end{aligned}[/tex].

Apply the Einstein-Planck equation to find the energy of this photon:

[tex]\begin{aligned}E &= h\, f \\ &\approx (6.6261 \times 10^{-34}\; {\rm J \cdot s}) \times (7.7065 \times 10^{14}\; {\rm s^{-1}) \\ &\approx 5.11 \times 10^{-19}\; {\rm J}\end{aligned}[/tex].

(Rounded to three significant figures.)

What ions are produced from acids and bases?

Answers

Answer:

Give person above me brainliest

Explanation:

what is value of 2.37 in sl units

Answers

The question is not clear

A box slides across a rough surface, eventually coming to rest.
Part A
a. Use the work-energy principle (Khan Academy:Work and the work-Energy Principle and the definition of work to explain why the box comes to rest.

b. Explain how the motion of the box is consistent with the Law of Conservation of Energy.

Answers

Answer:

he was a random act like you to be the first time I see is a great day and night to get a very happy to see you soon I hope that the world is not the same thing to say about this

a) When a box slides across a rough surface, eventually coming to rest, its kinetic energy is used during work done against frictional resistance force.

b) This work done is stored in the box as a potential energy. Thus the motion of the box is consistent with the Law of Conservation of Energy.

What is  work-Energy Principle?

According to the work-energy theorem, the work done by the net force acting on a body equals the change in kinetic energy.

It can simply be written as:

Work done = initial kinetic energy - final kinetic energy

The work energy theorem equation is the one presented above.

Now when a box slides across a rough surface, eventually coming to rest, frictional force comes into play. This force is opposite to the direction of motion of the box. Hence, the kinetic energy of the box is used during work done against frictional resistance force and stored in the box as a potential energy and thus  Law of Conservation of Energy followed.

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Tim is pushing a heavy box across the floor. He is using 300N of force and can accelerate at 2m/s/s. What is the mass of the box?

-298 kg
-600 kg
-0.006 kg
-150 kg

Answers

F=300Na=2m/s^2

Using Newton's second law

[tex]\\ \sf\Rrightarrow F=ma[/tex]

[tex]\\ \sf\Rrightarrow 300=2m[/tex]

[tex]\\ \sf\Rrightarrow m=150kg[/tex]

Hey there!

The formula of “mass” in physics is:

m = F/a

Whereas “f” is ‘force’, “a” is ‘acceleration’, & “m” is your ‘mass’ of course.

mass = 300 Net force/2 acceleration

300 Net force/2 acceleration = m

mass = 150

Therefore, your answer is: 150 kg

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

Under the Big Top elephant. Ella [2500 kg]. is attracted to Phant, the 3,000 kg elephant. They are separated by 8 m. What is the gravitational attraction between them? G=6.67×10^-11 (-11 is an exponent)​​

Answers

Hi there!

We can use the same equation for Gravitational Force:

[tex]\large\boxed{F_g = G\frac{m_1m_2}{r^2}}[/tex]

Fg = force due to gravity (N)

G = gravitational constant

m1,m2 = masses of objects (kg)

r = distance between objects (m)

Plug in the values provided:

[tex]F_g = (6.67*10^{-11})\frac{(2500)(3000)}{8^2} = \large\boxed{7.814 * 10^{-6}N }[/tex]

[tex]\huge\bf\underline{\underline{\pink{A}\orange{N}\blue{S}\green{W}\red{E}\purple{R:-}}}[/tex]

Here we've been given,

Universal gravitational constant (G) = [tex] \sf{6.67 \times {10}^{ - 11} }[/tex]

Mass of object 1 (m1) = 2500 kg

Mass of object 2 (m2) = 3000 kg

Distance between two objects (r) = 8 m

We have to find the gravitational attraction force (Fg) = ?

The standard formula to solve is given by,

[tex]:\implies\tt{F_g = g \frac{m_1m_2}{ {r}^{2} } } [/tex]

[tex]:\implies\tt{F_g = 6.67 \times {10}^{ - 11} \times \frac{(2500 )(3000)}{ {8}^{2} } }[/tex]

[tex]:\implies\tt{F_g = 6.67 \times {10}^{ - 11} \times \frac{7500000}{64} }[/tex]

[tex]:\implies\tt{F_g = 7.814 \times {10}^{ - 6} }[/tex]

Gravitational force of attraction is 7.814 × 10^-6 N.

what does the slope of the curve on a velocity vs. time graph represent?

Answers

Answer:

the slope of velocity-time graph represent an object acceleration

Which statement best explains the environmental drawback of using geothermal energy over energy generated by fossil fuels?

More cost-effective over time
Less pollution than fossil fuel plants
More energy plant locations available
Changes to regional landscapes

Answers

Answer:

Die Antwort lautet: Weniger Umweltverschmutzung als Kraftwerke mit fossilen Brennstoffen

Explanation:

hoffe das hat geholfen!! :))

Answer:

Changes to regional landscapes

Explanation:

It would be D because this is a cost or drawback and geothermal energy production would cause changes to the landscape, unlike how fossil fuels would.  I also got this right on the quiz.

Hope this helps!

which is the hottest and coldest planet in solar system ?​

Answers

Answer:

hottest plant: vensus, close to the sun

coldest plant: Neptune, farthest from the sun

Explanation:

Yoo what it do I don’t know the answer tho

Answers

Answer:

You should try your best to answer the question.

Question:
The US Navy is developing a railgun that uses magnetic field repulsion. The railgun can propel a 981 N projectile at seven times the speed of sound. How much energy is stored in this magnetic field? Assume a complete conversion of energy and a speed of sound of 340 m/s.

Answer choices:
A. 119 MJ
B. 283 MJ
C. 578 MJ
D. 2780 MJ

Answers

The relation of the kinetic energy allows to find the correct result for the energy stored in the electromagnet is:

B) 283 MJ

Kinetic energy is the energy due to the movement of bodies.

          K = ½ m v²

     

Where K is the kinetic energy, m is  the mass and v the spped.

They indicate that the weight of the bodye is W = 981 N and its final velocity is v = 7 [tex]v_s[/tex].

          W = m g

           

Since the projectile starts from rest, its initial velocity is zero, therefore the change in energy is

        ΔK = [tex]K_f - K_o = K_f[/tex]  

we substitute

        ΔK = ½ 981 / 9.8 (7 340) ²

         ΔK = 2.835 10⁸ J

They indicate that all the energy of the electromagnet is transformed into the energy of the projectile,

          Em = K

When reviewing the results, the correct one is:

       B) 283 MJ

In conclusion, using the relationship of kinetic energy we can find the correct result for the energy stored in the electromagnet is:

   B)  283 MJ

learn more about kinetic energy here: brainly.com/question/8101588


It takes a car 4 seconds to slow down from 22 m/s to 6 m/s , what was its acceleration?

Answers

To Find The Acceleration of  A Car Slowing Down:

The change in speed is the final speed minus the initial speed. To find acceleration, divide the change in velocity by the length of time during which the velocity changed.

do forces that act a distance come in pairs?

Answers

Answer:

Forces come in pairs.

Explanation:

Distances are between two points. The distance from A to B is equal but opposite the distance from B to A.

if vector b is added to vector a under what conditions does the resultant vector has magnitude a+b?​

Answers

Explanation:

hope it's useful for you knows

the impulse-momentum relationship is a direct result of

Answers

Newton's second law.

__________________

o0o0o0o0o0o0o0o0o0

The impulse-momentum relationship is a direct result of Newton's second law of motion.

What is the impulse-momentum?

The impulse-momentum theorem states that the impulse applied to an object is equal to the change in its momentum. It proves that the change in momentum of an object depends not only on the amount of force applied but also on the duration of force applied.

Newton's second law states that the force acting on an object is equal to the rate of change of its momentum.

This means that a force applied to an object will cause a change in its momentum. The impulse-momentum relationship describes the relationship between the force applied to an object and the resulting change in its momentum.

The impulse-momentum relationship states that the impulse acting on an object is equal to the change in its momentum.

Impulse is defined as the force applied to an object over a period of time, while momentum is the product of an object's mass and velocity. Therefore, the impulse-momentum relationship can be expressed as:

Impulse = Change in momentum

This relationship is important in understanding the behavior of objects in motion, particularly in collisions or other situations where forces act over a period of time.

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what is the energy equivalent of an object with a mass of 2.5 kg?

Answers

Answer:

2,500g is the answer yes

Which are examples of perfectly inelastic collisions? Check all that apply.

a baseball bouncing off a bat
bumper cars bumping off of each other
a cue ball hitting an eight ball and stopping
a plane landing on an aircraft carrier
rain sticking to a window
two train cars coupling together

Answers

A plane landing on an aircraft carrier
Rain sticking to a window
Two train cars coupling together

Answer:

D. a plane landing on an aircraft carrier

E. rain sticking to a window

F. two train cars coupling together

Explanation:

How do you un rewrap something?

Answers

wrap it back up……….

Which branch of science deals with the study of the structures shown here?

FISH
AMPHIBIAN
REPTILE
BIRD?

Answers

Vertebrate Zoology, I’m pretty sure

Answer:

Vertebrate zoology

Explanation:

Have a great day!

The magnetic field 0. 02 m from a wire is 0. 1 T. What is the magnitude of the magnetic field 0. 01 m from the same wire? 0. 01 T 0. 05 T 0. 1 T 0. 2 T.

Answers

The magnitude of the magnetic field 0.01 m from the same wire is 0.2 T.

Given to us:

Magnetic field, [tex]B_1 = 0.1\ T[/tex]

Radius of wire, [tex]R_1 = 0.02\ m[/tex]

To find out the magnitude of the magnetic field 0. 01 m from the same wire, we need to find out current first. we will use the formula,

[tex]B = \dfrac{\mu_oI }{2\pi R},\\\rn\\where,\\B= magnetic\ field\\\mu_o = 4\pi\times 10^{-7} m\cdot kg\cdot s^{-2} A^{-2}\ is\ the\ magnetic\ constant\\I= current\\R= radius\ of\ the\ wire[/tex]

Putting the values,

[tex]B_1 = \dfrac{\mu_oI }{2\pi R_1},\\\rn\\\\0.1= \dfrac{4\times \pi \times 10^{-7}\times I}{2\times \pi\times0.02}\\\\I=10,000\ A[/tex]

Now, for [tex]B_2[/tex]

[tex]B_2 = \dfrac{\mu_oI }{2\pi R_2},\\\rn\\\\B_2= \dfrac{4\times \pi \times 10^{-7}\times 10,000}{2\times \pi\times0.01}\\\\B_2= 0.2\ T[/tex]

Hence, the magnitude of the magnetic field 0. 01 m from the same wire is 0.2 T.

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. a. Calculate the work done while lifting 300 kg of wate through a vertical height of 6 m. (Assume g = 10 m a =​

Answers

Answer:

potential energy = mgh = 300 × 10 × 6m = 18000 joule or 18 kilo joule.

Explanation:

Why aren’t the Appalachian Mountains still as tall as the Himalayas?

Answers

Answer:

mountains are limited in their theoretical height by several processes. First is isostasy: the bigger a mountain gets, the more it weighs down its tectonic plate, so it sinks lower. ... Bottom line: mountains can get taller than Mount Everest in earth gravity, like the Appalachians probably did—but not much taller.

Answer:

It probably won't get any taller, though. From a geological standpoint, the Appalachians haven't seen much growth in quite a while. Since the dawn of the dinosaurs about 225 million years ago, this range has been getting whittled down by weathering forces.

Explanation:

how do you find average velocity (average) from acceleration) and time (t)?

Answers

Average velocity is defined as the ratio in change in position to change in time,

v[ave] = ∆x/∆t

which on its own doesn't have anything to do with acceleration.

If acceleration is constant, the average velocity is the literal average of the initial and final velocities,

v[ave] = (v[final] + v[initial]) / 2

If this constant acceleration has magnitude a, the final velocity can be expressed in terms of the initial velocity by

v[final] = v[initial] + a*t

and plugging this into the previous equation gives

v[ave] = (v[initial] + a*t + v[initial])/2

v[ave] = v[initial] + 1/2*a*t

If the body in consideration is initially at rest, then

v[ave] = 1/2*a*t

which might be the relation you're looking for. But bear in mind the conditions I've underlined.

If acceleration is not constant and changes over time, so that the acceleration is some function of time a(t), then you can determine the velocity function v(t) by using the fundamental theorem of calculus. You need to know a particular velocity for some time to completely characterize v(t), though. For example, if you're given the initial velocity v[initial] = v(0), then

[tex]\displaystyle v(t) = v(0) + \int_0^t a(u) \, du[/tex]

or if you know any other velocity for some time t₀ > 0,

[tex]\displaystyle v(t) = v(t_0) + \int_{t_0}^t a(u) \, du[/tex]

The decomposition of dinitrogen pentoxide is described by the reaction: 2N2O5(g)→4NO2(g)+O2(g). If O2 is being formed at a rate of 2.40 mol/min, what is the rate at which N2O5 is being used up?

Answers

Answer:

4.80 mol N2O5/min

Explanation:

The balanced equation tells us that 2 moles of N2O5 are required for every 1 mole of O2.  Therefore:

(2.40 mol O2/min)*(2 mol N2O5/mol O2) = 4.80 mol N2O5/min

A 2.0 kg block rests on a level surface. The coefficient of static friction is, and the coefficient of kinetic friction is A horizontal force, X, is applied to the block. As X is increased, the block begins moving. Describe how the force of friction varies as X increases from the moment the block is at rest to when it begins moving. Indicate how you could determine the force of friction at each value of X―before the block starts moving, at the point it starts moving, and after it is moving. Show your work.

ps. I had to change F to X because of brainly.

Answers

By Newton's second law, the net force acting on the block in the vertical direction is

∑ F [ver] = n - mg = 0

where n = magnitude of normal force and mg = weight of the block. It follows that n = mg.

When the block is at rest, the applied force X will not be enough to move the box until it can overcome the maximum mag. of static friction. If µ[s] is the coefficient of static friction, then the maximum mag. of the frictional force is

f = µ[s] n = µ[s] mg

The net horizontal force would be

∑ F [hor] = X - µ[s] mg = 0

so a minimum force of X = µ[s] mg is required to get the block moving. Any mag. smaller than this and the block stays at rest/in equilibrium.

Once the mag. of X exceeds µ[s] mg, the block will begin to move. At that point, if the coefficient of kinetic friction is µ[k], then the net force on the block is

∑ F [hor] = X - µ[k] mg = 0

so a minimum force of X = µ[k] mg would be needed to keep the block moving at constant speed, or otherwise X = µ[k] mg + ma if the block is accelerating with mag. a.

The principles here are captured in the attached plot.

how did you identify the layer that belonged next to the cambrian layer?

Answers

Answer:

Morphology and phylogenetics revealed by fossils. Perhaps the strongest evidence to support the Cambrian evolutionary explosion of animal forms is the first clear appearance, in the Early Cambrian, of skeletal fossils representing members of many marine bilaterian animal phyla

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