Which of the following properties of a photon are required to calculate the energy emitted by an electron returning to its ground state?

A. wavelength
B. frequency
C. either A or B
D. both A and B

Answers

Answer 1

Answer:

C. either A or B

Explanation:

To calculate the energy of a photon returning to its ground state, we required either the frequency or the wavelength. Often times, not both.

The wavelength of a photon can be derived by;

     E = hf

 or

        E  = [tex]\frac{hc}{wavelength}[/tex]  

 h is the Planck's constant

 c is the speed of light

 f is the frequency


Related Questions

A compound composed of 3.3% H, 19.3% C, and 77.4% O3.3% H, 19.3% C, and 77.4% O has a molar mass of approximately 60 g/mol.. What is the molecular formula of the compound?

Answers

Answer:

Molecular formula of the compound = H₂CO₃

Explanation:

First, the empirical formula of the compound is determined

Percentage by mass of each element is given as shown below:

H = 3.3% ; C = 19.9%; O = 77.4%

Mole ratio of the elements= percentage mass/ molar mass

H = 3.3/ 1 = 3.3

C = 19.3/12 = 1.6

O = 77.4/16 = 4.8

whole number ratio is obtained by dividing through with the smallest ratio

H = 3.3/1.6; C = 1.6/1.6; O = 4.8/1.6

H : C : O = 2 : 1 : 3

Empirical formula = H₂CO₃

Molecular formula/mass = n(empirical formula/mass)

60 = n(2*1 + 12*1 + 16*3)

60 = n(62)

n = 60/62 = 0.96

n is approximately = 1

Therefore, molecular formula of the compound = (H₂CO₃) * 1

Molecular formula of the compound = H₂CO₃

The molecular formula of a compound composed of 3.3% H, 19.3% C, and 77.4% O and a molar mass of approximately 60 g/mol is CH2O3.

HOW TO CALCULATE MOLECULAR FORMULA:

The molecular formula of an unknown compound can be calculated from the empirical formula. The empirical formula can be calculated as follows:

C = 19.3% = 19.3gH = 3.3% = 3.3gO = 77.4% = 77.4g

First, we calculate the number of moles in each element by dividing by their respective atomic mass.

C = 19.3g ÷ 12g/mol = 1.61molH = 3.3g ÷ 1g/mol = 3.3molO = 77.4g ÷ 16g/mol = 4.84mol

Next, we divide by the smallest mole value. C = 1.61mol ÷ 1.61 = 1 H = 3.3mol ÷ 1.61 = 2.05O = 4.84mol ÷ 1.61 = 3.01

Approximately, the empirical ratio of CHO is 1:2:3. Hence, the empirical formula is CH2O3.

{CH2O3}n = 60g/mol

{12 + 2 + 48}n = 60

62n = 60

n = 60 ÷ 62

n = 0.968

n = 1

Therefore, the molecular formula of a compound composed of 3.3% H, 19.3% C, and 77.4% O and a molar mass of approximately 60 g/mol is CH2O3.

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Silver has a density of 10.5 g/cm³, and gold has a density of 19.3 g/cm³. Which would have a greater mass, 5 cm³ of silver or 5 cm³ of gold?

Answers

Gold have a greater mass

Further explanation  

Density is a quantity derived from the mass and volume  

Density is the ratio of mass per unit volume  

The unit of density can be expressed in g/cm³ or kg/m³  

Density formula:  

[tex]\large {\boxed {\bold {\rho ~ = ~ \frac {m} {V}}}}[/tex]

ρ = density  

m = mass  

v = volume  

mass of Silver :

[tex]\tt mass=\rho\times V\\\\mass=10.5\times 5=52.5~g[/tex]

mass of Gold :

[tex]\tt mass=\rho\times V\\\\mass=19.3\times 5=96.5~g[/tex]

A 12.0 m hcl solution has a density of 1.18 g ml. What is the concentration of tthis solution in weight percent and moliarty?

Answers

Answer:

Percentage of HCL = 37.11 % (Approx)

Molarity = 16.17 m (Approx)

Explanation:

Given:

Molarity = 12.0 M  of hcl

Density = 1.18 g/ml

Computation:

1L of hcl solution contains = 12 moles

Mass = Moles x Molar mass

Mass of HCl = 12 x 36.5

Mass of HCl  = 438 g  = 0.438 kg

Mass of 1 L solution =  1.18 x 1,000 ml

Mass of 1 L solution = 1180 g

Percentage of HCL = [438/1180]100

Percentage of HCL = 37.11 % (Approx)

Molarity = 12 / [1.18 - 0.438]

Molarity = 12 / [0.742]

Molarity = 16.17 m (Approx)

. Calculate the entropy change associated with the isothermal compression of 0.720 mol of an ideal gas from 24.32 L to 3.90 L.

Answers

Answer:

[tex]$\Delta S = -10.95 \ \frac{J}{K}$[/tex]

Explanation:

Given :

Number of mole, n = 0.720 mol

Initial volume, [tex]$V_1$[/tex] = 24. 32 L

Final volume, [tex]$V_2$[/tex] = 3.90 L

We know entropy change,

[tex]$\Delta S = c_V\ln \left(\frac{T_2}{T_1}\right) + n R \ln \left(\frac{V_2}{V_1}\right)$[/tex]

For isothermal compression temperature constant,

[tex]$\Delta S = n R \ln \left(\frac{V_2}{V_1}\right)$[/tex]

[tex]$\Delta S = 0.720 \times 8.314 \times \ln \left(\frac{3.90}{24.32}\right)$[/tex]

[tex]$\Delta S = -10.95 \ JK^{-1}$[/tex]

[tex]$\Delta S = -10.95 \ \frac{J}{K}$[/tex]

The isotope of carbon used in archaeological dating is 14^6C . How many protons, neutrons, and electrons does an atom of 14^6C have?

Answers

Answer:

6

8

6

Explanation:

 Isotope given:

                       ¹⁴₆C

In specie written as this;  

   Superscript  = Mass number

   Subscript  = Atomic number

To find the protons, it is the same as the atomic number;

                Protons  = Atomic number  = 6

Neutrons have no charges;

 Neutrons  = Mass number - Atomic number  =

  Neutrons  = 14 - 6  = 8

The number of electrons is the same as the atomic number = 6

The velocity of a car changes from 10 m/s east to 30 m/s east in 4 seconds.
What is the acceleration of the car?
A. 5 m/s2 east
B. 10 m/s2 west
c. 10 m/s2 east
D. 5 m/s2 west

Answers

Answer:

5m/s²

Explanation:

Given parameters:

Initial velocity  = 10m/s due east

Final velocity  = 30m/s due east

Time = 4s

Unknown:

Acceleration of the car = ?

Solution:

Acceleration is the rate of change of velocity with time.

Mathematically;

 Acceleration  = [tex]\frac{v - u}{t}[/tex]  

v is the final velocity

u is the initial velocity

t is the time taken

  Insert the parameters and solve;

  Acceleration  = [tex]\frac{30 - 10}{4}[/tex]   = 5m/s²

Calculate the molar mass of Al(CH3O2)3

Answers

Answer:

The molar mass and molecular weight of Al(CH3CO2)3 is 204.1136.

Explanation:

Answer:

168.1 g/mol

General Formulas and Concepts:

Chemistry

Reading a Periodic Table

Explanation:

Step 1: Define

Al(CH₃O₂)₃

Step 2: Find molar masses

Molar Mass of Al - 26.98 g/mol

Molar Mass of C - 12.01 g/mol

Molar Mass of H - 1.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Al(CH₃O₂)₃ - 26.98 + 3(12.01) + 9(1.01) + 6(16.00) = 168.1 g/mol

Calculate the pH of the cathode compartment solution if the cell emf at 298 K is measured to be 0.660 V when (Zn^2+)=0.22 M and(P_H2)= 0.87atm.

Answers

Answer:

pH = 2.059

Explanation:

At the Cathode:

The reduction reaction is:

[tex]2H^+ + 2e^- \to H_2 \ \ \ \mathbf{E^0_{red}= 0.00 \ V}[/tex]

At the anode:

At oxidation reaction is:

[tex]Zn \to Zn^{2+} +2e^- \ \ \ \mathbf{E^0_{ox} = 0.76 \ V}[/tex]

The overall equation for the reaction is:

[tex]\mathbf{Zn + 2H^+ \to Zn^{2+} + H_2}[/tex]

The overall cell potential is:

[tex]\mathbf{E^0_{cell}= E^0_{ox} + E^0_{red}}[/tex]

[tex]\mathbf{E^0_{cell}= 0.76 \ V +0.00 \ V}[/tex]

[tex]\mathbf{E^0_{cell}= 0.76\ V}[/tex]

Using the formula for the Nernst equation:

[tex]E = E^0 - ( \dfrac{0.0591}{n})log (Q)\\[/tex]

where;

E = 0.66

(Zn^2+)=0.22 M

Then

[tex]0.66 =0.76- ( \dfrac{0.0591}{2})log \bigg ( \dfrac{[Zn^{2+} ] PH_2}{[H^+]^2} \bigg )[/tex]

[tex]0.66 =0.76- 0.02955 * log \bigg ( \dfrac{0.22*0.87}{[H^+]^2} \bigg )[/tex]

3.4 = log ( 0.1914) - 2 log [H⁺]

3.4 = -0.7180 - 2 log [H⁺]

3.4 + 0.7180 = - 2 log  [H⁺]

4.118  = - 2  log  [H⁺]

pH = log [H⁺] = 4.118/2

pH = 2.059

The pH of the solution as described in the question is 2.7.

The equation of the reaction is;

Zn(s) + 2H^+(aq) ----> Zn^2+(aq) + H2(g)

The partial pressure of hydrogen can be converted to molarity using;

P= MRT

M = P/RT

M =  0.87atm/0.082 LatmK-1mol-1 × 298 K = 0.036 mol/L

We have to obtain the reaction quotient

Q = [Zn^2+] [H2]/[H^+]^2

Q = [0.22 ] [0.036]/[H^+]^2

Recall that, from Nernst equation;

E = E° - 0.0592/nlog Q

E° = 0.00V - (-0.76V) = 0.76V

0.660 =  0.76 - 0.0592/2logQ

0.660 - 0.76  =  - 0.0592/2logQ

-0.1 =  - 0.0592/2logQ

-0.1 × 2/ - 0.0592 = logQ

3.38 = log Q

Q = Antilog (3.38)

Q= 2.39 × 10^3

Now;

2.39 × 10^3 =  [0.22 ] [0.036]/[H^+]^2

2.39 × 10^3 = 7.92  × 10^-3/[H^+]^2

[H^+]^2 = 7.92  × 10^-3/2.39 × 10^3

[H^+] = 1.82  × 10^-3

pH = -log[H^+]

pH = -log[ 1.82  × 10^-3]

pH = 2.7

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Which of the following would be a clue that a rock is metamorphic?
A It has a complete fossil in it.
B It has gas bubbles.
с It is very soft.
D It has ribbon-like layers, or bands.​

Answers

This answer would be B

How many moles of H20 are required to react completely with 7.30 moles of NO2?
3NO2(g) + H20(1)
NO(g) + 2HNO3(aq)
1.86 mol
2.19 mol
2.43 mol
6.12 mol
7.30 mol

Answers

Answer:

2.43 moles of water are required.

Explanation:

Given data:

Moles of H₂O required = ?

Moles of NO₂ present = 7.30 mol

Chemical equation:

3NO₂+ H₂O  →     NO + 2HNO₃

Now we will compare the moles of NO₂ and H₂O.

                    NO₂       :           H₂O

                      3          :              1

                   7.30        :          1/3×7.30 = 2.43 mol

A 49 gram sample of an unknown metal requires 717 Joules of energy to heat it from 30.5◦C to 101◦C. What is the specific heat of this metal? Answer in units of J/g · ◦ C.

Answers

Answer:

The specific  heat  capacity  of  unknown  metal  is  calculated  using the  following  formula

Q=MC  delta  T  where

Q= heat(862 j)

M=  mass  (17 g)

C=  specific  heat capacity=?

delta T = change in  temperature  (  35-10= 25 c)

by making  C the  subject  of the  formula  C=Q/m  delta T

=  862 j/( 17 g  x25 c) = 2.028 j/g/c

Explanation:

10. How many electrons did Br?- gain or lose?
It did not gain or lose any electrons, it lost a proton.
It did not gain or lose any electrons, it gained a proton.
O It lost one electron because it has a charge of negative one.
0 It gained one electron because it has a charge of negative one.

Answers

Hi :)

The answer is D

Because Bromine atoms usually gain just one electron to get to a full outer shell

Hope this helps!

What is the Molarity 2 mol of KL discovered in 1 L water

Answers

Answer:

Molarity = 2 M

Explanation:

Given data:

Molarity of solution = ?

Number of moles = 2 mol

Volume of water = 1 L

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula

Molarity = number of moles of solute / L of solution

Molarity = 2 mol / 1 L

Molarity = 2 M

How many atoms of Chlorine would there be in 6.8 mol of Cl?

Answers

Answer:

241.08039999999588

Explanation:

If 42.389 g of Fe3Br2 is dissolved in enough water to give a total volume of 750 mL, what is the molarity of the solution

Answers

Answer:

[tex]M=0.173M[/tex]

Explanation:

Hello!

In this case, since the molarity of a solution is defined in terms of the moles of solute divided by the volume of the solution in liters and has units of mol/L or M:

[tex]M=\frac{n}{V}[/tex]

For the solute, Fe3Br2, which has a molar mass of 327.3430 g/mol, the moles in 42.389 g are:

[tex]n=42.389g*\frac{1mol}{327.3430g} =0.12949mol[/tex]

Thus, since the volume in liters is 0.750 L from those given 750 mL, the molarity turns out:

[tex]M=\frac{0.12949mol}{0.750L}\\\\M=0.173M[/tex]

Best regards!

It isa sex characteristic that has direct relation to sexual reproduction?what is it..

Answers

The appropriate answer is "Secondary Sexual Characteristics!

Which of the following examples from everyday life are made possible or explained possible or explained by modern chemistry

Answers

Answer: Where is the folowing?

Explanation:

Can you repost this with the choices . Thanks .

How many moles of water would be produced from 3 moles of oxygen in the following reaction? Don’t forget to include units in your answer.
PLZHELP I'LL AWARD BRAINLIEST

Answers

Answer:

6 mol H₂O

General Formulas and Concepts:

Chemistry

Stoichiometry

Explanation:

Step 1: Define

RxN:     2H₂ + O₂ → 2H₂O

Given:   3 moles O₂

Step 2: Stoichiometry

[tex]3 \ mol \ O_2(\frac{2 \ mol \ H_2O}{1 \ mol \ O_2} )[/tex] = 6 mol H₂O

Step 3: Check

We are given 1 sig fig.

Our final answer has 1 sig fig, so no need to round.

Solve each of the following problems using ​dimensional analysis​.

Answers

Answer:

12ml should be the answer

Explanation:

Which compound contains a double bond?
ethene (C2H4)
chlorine (C12)
ammonia (NH3)
methane (CH)

Answers

The answer would be ethane (C2H4)

Answer:

ethene

Explanation:

just took the test :D

5. What is the speed (Velocity) of a cyclist who covers 10 km (convert to meters
first!) in 14 minutes and 30 seconds? Remember time must be in seconds first!

Answers

[tex]\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}[/tex]

Actually Welcome to the Concept of the Kinematics.

Here, we know that, Velocity = Distance / Time,

So here, Distance = 10km = 10×1000 = 10000 metres.

, Time = 14 min 30 sec = 870 seconds,

so now, we get velocity as,

=> V = 10000 ÷ 870 => 11.49 m/s .

Hence, Velocity is 11.49 m/s.

What is accretion?????

Answers

Answer:

the process of growth or increase, typically by the gradual accumulation of additional layers or matter.

Explanation:

Answer:

The process of growth or increase, typically by the gradual accumulation of additional layers or matter.

Explanation:

What type of wave is shown here?
:transverse wave
:longitudinal wave

Answers

Answer: Longitudinal wave


Which of the following is a consequence of humans using fossil fuels?
O A. All of these
B. Rising sea level
C. Destruction of habitats
D. More severe storms

Answers

I think it’s A, because all of these are related to fossil fuel somehow.

A balloon is filled to a volume of 1.50 L with 3.00 moles of gas at 25 °C. With pressure and temperature held constant, what will be the volume (in L) of the balloon if 0.80 moles of gas are added?

Answers

We know, when temperature and pressure is constant :

[tex]\dfrac{V_1}{n_1}=\dfrac{V_2}{n_2}[/tex]      ....1)

[tex]n_1 = 3\ moles,\ V_1 = 1.50\ L[/tex]

[tex]n_2 = 3 + 0.80 = 3.80 \ moles[/tex]

Let, final volume is [tex]V_2[/tex].

Putting all values in equation 1), we get :

[tex]\dfrac{V_1}{n_1}=\dfrac{V_2}{n_2}\\\\\dfrac{1.50}{3}=\dfrac{V_2}{3.80}\\\\V_2 = \dfrac{1.50\times 3.80}{3}\\\\V_2 = 1.9\ L[/tex]

Therefore, volume (in L) of the balloon if 0.80 moles of gas are added is 1.9 L.

Hence, this is the required solution.

About 25% of the world's population lives:

in the United States
without access to energy
in industrialized areas
near nuclear power plants

Answers

Answer:

I believe it is "in industrialized areas"

Explanation:

According to Calvert Academy it says "Only 25% of the world's population lives in industrial areas. Hope this helps :)

help me plz plz plz plz plz plz plz plz plz plz plz plz plz :(

Do you think these molecules are larger or smaller than a cell in the human body? Explain your answer.

Answers

Yes they in fact are because they are smaller components that are sometimes in cells! Your welcome :)

Molecules which have a larger size as compared to pores of cell membrane then they can't pass through it.

Small size molecules

Water, carbon dioxide, glucose and oxygen are some of the molecules that can pass through the cell membrane of the cell by the process of diffusion while on the other hand, large molecules such as sugars and proteins can't enter inside the cell due to their large size.

Pores present in cell membrane

The cell has semipermeable membrane which has small pores. Through these pores small size materials can pass through whereas large molecules can't pass through it due to their large size so we can conclude that molecules which have a larger size as compared to pores of cell membrane then they can't pass through it.

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PLS HELP THE QUESTION IS ON THE PICTURE

Answers

Concepts used:

1 mole of an element or a compound has 6.022 * 10²³ formula units

So, we can say that: Number of formula units = number of moles * 6.022*10²³

number of moles of an element or a compound = given mass/molar mass

__________________________________________________________

003 - Number of CaH₂ formula units in 6.065 grams

Number of Moles:

We know that the molar mass of CaH₂ is 42 grams/mol

Number of Moles of CaH₂ = given mass/molar mass

Number of moles = 6.065 / 42

Number of moles = 0.143 moles

Number of Formula units:

Number of formula units = number of moles * 6.022*10²³

= 0.143 * 6.022 * 10²³

= 0.86 * 10²³ formula units

__________________________________________________________

004 - Mass of 6.34 * 10²⁴ formula units of NaBF₄

Number of Moles:

We mentioned this formula before:

Number of formula units = number of moles * 6.022*10²³

Solving it for number of moles, we get:

Number of moles = Number of Formula units / 6.022* 10²³

replacing the variable

Number of moles = 6.34 * 10²⁴ / 6.022*10²³

Number of moles=  10.5 moles

Mass of 10.5 moles of NaBF₄:

Molar mass of NaBF₄ = 38 grams/mol

Mass of 10.5 moles = 10.5 * molar mass

Mass of 10.5 moles = 10.5 * 38

Mass = 399 grams

__________________________________________________________

005 - Number of moles in 9.78 * 10²¹ formula units of CeI₃

Number of Moles:

We have the formula:

Number of moles = Number of Formula units / 6.022* 10²³

replacing the variables

Number of Moles = 9.78 * 10²¹ / 6.022*10²³

Number of Moles = 1.6 / 10²

Number of Moles = 1.6 * 10⁻² moles   OR   0.016 moles

Match the description to the advancement

Answers

Answer:

i podwmk

Explanation:

What is meant by the "frequency of light"? What symbol is used for it, and what is the SI unit for frequency?

Answers

Answer: Units. The SI derived unit of frequency is the hertz (Hz), named after the German physicist Heinrich Hertz. One hertz means that an event repeats once per second.

The frequency is the number of waves that pass a point in space during any time interval, usually one second. We measure it in units of cycles (waves) per second, or hertz. The frequency of visible light is referred to as color, and ranges from 430 trillion hertz, seen as red, to 750 trillion hertz, seen as violet.

Frequency of an electromagnetic wave is the number of wave cycles per unit time. The SI unit of frequency is Hertz or Hz. Frequency is represented by the symbol v called neu.

What is electromagnetic wave?

Waves are propagation or transfer of energy through air or vacuum. An electromagnetic wave is associated with a combined electric field and magnetic field.

Waves are associated with characteristic frequency and wavelength. Wavelength of a wave is the distance between its two consecutive crests or troughs.

Frequency of a wave is the number of wave cycles per unit time. Its is expressed in the unit of Hertz or Hz. Frequency and wavelength are in inverse relation. The shortest waves have greater energy and greater frequency.

Frequency is inverse of time of propagation. So that it can also be used in s⁻¹ which is equal to one hertz.

To find more about frequency, refer the link below:

https://brainly.com/question/5102661

#SPJ2

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