Which of the following are valid names for the triangle below? Check all that
apply.
K
s
E
D
o
M
A. ADKM
B. AKMD
C. ASKD
D. ΔKE
E. AMDK
F. ASKMO

Answer:

61

Step-by-step explanation:

3x + 6 = 183

3x = 177

x = 59

(x+2) = (59+2) = 61

It is correct on khan academy

Answer:

The third number in this sequence is 63.

Step-by-step explanation:

Let the first odd number be x.

Since our sequence are consecutive odd numbers, the second term must be (x + 2) and the third (x + 4). If we only add one, we will get even numbers.

Their sum is 183. Hence:

[tex]x+(x+2)+(x+4)=183[/tex]

Solve for x. Combine like terms:

[tex]3x+6=183[/tex]

Subtract six from both sides:

[tex]3x=177[/tex]

And divide both sides by three. Hence:

[tex]x=59[/tex]

Therefore, our sequence is 59, 61, and 63.

The third number in this sequence is 63.

Note: If we do not get an odd number or if we get a fraction for x, we can conclude that no three consecutive integers sum to 183.

Answer:

4th option

Step-by-step explanation:

tanZ = [tex]\frac{opposite}{adjacent }[/tex] = [tex]\frac{XY}{ZY}[/tex]

Answer:

Hence the answers are,

a) Probability that in the past 12 months the car had more than one problem = P(X > 1) is 0.2716.

b) The Probability that in the past 12 months the car had almost two problems = P( X < 2) is 0.9160.

c) The Probability that in the past 12 months the car had zero problems = P(X= 0 ) is 0.3606.

Step-by-step explanation:

Let's take X to be the number of problems per car.

By considering the given statement, X follows a Poisson Distribution with Mean (X) = 1.02.

The Poisson probability formula is :

e Pr( X = k) = e- k! k= 0,1,2...

a)

The Probability that in the past 12 months the car had more than one problem = P(X > 1)

[tex]P(X > 1) =1- P(X < 1) \\\\=1- (P(X = 0) + P(X = 1)-1.021.02 e + 1.021.02 =1-6 0!\\= 1-0.3606 + 0.3678\\= 1-0.7284\\= 0.2716[/tex]

b)

The Probability that in the past 12 months the car had almost two problems = PX < 2)

[tex]Pr(X < 2) = Pr(X = i) = Pr(X = 0) + Pr(X = 1) + Pr(X = 2)\\-1.021.020 -1.021.02 -1.021.02 e e + e + 0! 1! 2!\\= 0.3606 + 0.3678 + 0.1876\\= 0.9160[/tex]

c)

The Probability that in the past 12 months the car had zero problems = P(X= 0 )

[tex]- 1.021.02 e 0!\\= 0.3606[/tex]

Given:

Net income = $19,090

Assets at the beginning of the year = $209,000.

Assets at the end of the year total = $264,000.

To find:

The return on assets.

Solution:

Formula used:

[tex]\text{Return of assets}=\dfrac{\text{Net income}}{\text{Average of assets at the beginning and at the end}}[/tex]

Using the above formula, we get

[tex]\text{Return of assets}=\dfrac{19090}{\dfrac{20900+264000}{2}}[/tex]

[tex]\text{Return of assets}=\dfrac{19090}{\dfrac{473000}{2}}[/tex]

[tex]\text{Return of assets}=\dfrac{19090}{236500}[/tex]

[tex]\text{Return of assets}\approx 0.0807[/tex]

The percentage form of 0.0807 is 8.07%.

Therefore, the return on assets is 8.07%.

Answer:

The length is of 59 cm.

Step-by-step explanation:

Perimeter of a rectangle:

The perimeter of a rectangle with width w and length l is given by:

[tex]P = 2(w + l)[/tex]

Width of 49 centimeters and a perimeter of 216 centimeters:

This means that [tex]w = 49, P = 216[/tex]

The length is cm.

We have to solve the equation for l. So

[tex]P = 2(w + l)[/tex]

[tex]216 = 2(49 + l)[/tex]

[tex]216 = 98 + 2l[/tex]

[tex]2l = 118[/tex]

[tex]l = \frac{118}{2}[/tex]

[tex]l = 59[/tex]

The length is of 59 cm.

Answer:

Step-by-step explanation:

Since EF = 20 and E is at 4

F is at:

Answer:

50 dozen total

Step-by-step explanation:

8/12 & 10/12.... average 9/12

11/12 - 9/12 =

2/12x = 100

2x = 1200

x = 600/12

50 dozen total

Answer:

The width is 10 feet.

Step-by-step explanation:

We know that the area of a rectangle is given by the formula:

[tex]\displaystyle A=L\cdot W[/tex]

Where L is the length and W is the width.

We are given that the length of the rectangle is three times the width. In other words:

[tex]L=3W[/tex]

The total area is 300 square feet. And we want to determine the width of the rectangle.

So, substitute 300 for A and 3W for L:

[tex](300)=(3W)\cdot W[/tex]

Multiply:

[tex]300=3W^2[/tex]

Divide both sides by three:

[tex]W^2=100[/tex]

And take the principal square root of both sides. So:

[tex]W=10[/tex]

Thus, the width of the rectangle is 10 feet.

Answer:

A

Step-by-step explanation:

since it's negative so it will get smaller

Answer

a) chart

Step-by-step explanation:

a) chart best represents the following information about student results from a class assignment

Answer:

10

Step-by-step explanation:

5C2 =5!

       2! (3)!

=1 x 2 x 3 x 4 x 5

(1 x 2) (1 x 2 x 3)

=4 x 5

   2

=20

  2

5C2 = 10

Hello,

2 points of the line: (2,0) and (0,3)

[tex]\Delta\ y=3-0=3\\\Delta\ x=0-2=-2\\\dfrac{\Delta\ y}{\Delta\ x} =\dfrac{-3}{2} \\\\y-0=\dfrac{-3}{2}*(x-2)\\\\\boxed{y=-\dfrac{3x}{2}+3}\\[/tex]

Answer:

38.74%

Step-by-step explanation:

Given the data:

21 21 22 22 23 23 23 24 24 24 24 24 25 25 25 26 26 27 27

We obtain the beginner running population and standard deviation

Population mean, μ = Σx/n = 456/19 = 24

Standard deviation, σ = 1.747 (using calculator)

Friend's Runtime, x = 23.5 minutes

Obtaining the friend's Zscore :

Z = (x - μ) / σ

Z = (23.5 - 24) / 1.747

Z = - 0.286

Obtaining the Pvalue :

Using a standard normal distribution table :

P(Z < - 0.286) = 0.38744

Hence. Percentage of population that has lesser time :

0.38744 * 100% = 38.74%

The global climate is undergoing significant changes.

Answer:

Good sampling technique

Step-by-step explanation:

In other to determine the mean value for a population, it may be necessary to make inference from the a small subset of the population, called the sample, if it is impossible, difficult or inefficient to get all population data. Hence, in other to select a subset of the population, then the sample must be selected at random, such that all elements of the population have equal chances of being selected and hence, be representative of the population. Since, the sampling technique adopted above is done at random, hence, it is a good sampling technique.

Answer:

the answer is 8

Step-by-step explanation:

Total amount Ted wishes to spend this month is $5000.

Mahogany costs $450 per block, and he has already bought 7 blocks of spruce at $200 each.

So, money spent on spruce =  dollars

Money left after buying spruce =  dollars

Now as $450 will be spent on buying 1 block of mahogany.

So, $3600 will be spent

and then your answer will be 8

Answer:

[tex]8 \ feet[/tex]

Step-by-step explanation:

In this situation, one is given the following information. A ladder is leaning against a wall and has a measure of (17) feet. The bottom of the ladder is (15) feet away from the wall. One can infer that the wall forms a right angle with the ground. Thus, the triangle formed between the ground, ladder, and wall is a right triangle. Therefore, one can use the Pythagorean theorem. The Pythagorean theorem states the following,

[tex]a^2+b^2=c^2[/tex]

Where (a) and (b) are the legs or the sides adjacent to the right angle of the right triangle. The parameter (c) represents the hypotenuse or the side opposite the right angle. In this case, the legs are the ground and wall, and the hypotenuse is the ladder. Substitute this into the formula a solve for the height of the wall.

[tex]a^2+b^2=c^2[/tex]

Substitute,

[tex](ground)^2+(wall)^2=(ladder)^2\\\\(15)^2+(wall)^2=(17)^2\\[/tex]

Simplify,

[tex](15)^2+(wall)^2=(17)^2\\\\225+(wall)^2=289[/tex]

Inverse operations,

[tex]225+(wall)^2=289\\\\(wall)^2=64\\\\wall=8[/tex]

9514 1404 393

Answer:

  $4000

Step-by-step explanation:

The problem tells you the relation between commission (c) and stock value (v) is ...

  c = 10 + 0.025v . . . . $10 + .025 of the value traded

We want to find the value (v) for the given commission (c=110). We can put these numbers into the formula and solve for v:

  110 = 10 + 0.025v

  100 = 0.025v . . . . . . . subtract 10

  100/0.025 = v = 4000 . . . . divide by the coefficient of v

The value of stock traded was $4000.

_____

Additional comment

As always, you start by reading and comprehending the problem. You look for what is being asked for, what is being given, and any information that relates one to the other.

Here, the value of stock traded is asked for, the amount of commission is given, and a description of the relation of one to the other is provided. Translate that description to an equation, fill in the given value, and solve for the unknown. (That's what we did above.)

__

You can also work this in your head. The commission is $10 more than some fraction of the amount traded. Since the commission is $110, only $100 of that is the fraction of the amount traded. With a little experience, you can recognize the fraction 0.025 as being 1/40. That means $100 is 1/40 of the value traded, or the value traded is 40 × $100 = $4000.

Answer:

Yes, it is possible to have  a relation on the set {a, b, c} that is both symmetric and transitive but not reflexive

Step-by-step explanation:

Let

Set A={a,b,c}

Now, define a relation R on set A is given by

R={(a,a),(a,b),(b,a),(b,b)}

For reflexive

A relation is called reflexive if (a,a)[tex]\in R[/tex] for every element a[tex]\in A[/tex]

[tex](c,c)\notin R[/tex]

Therefore, the relation R is  not reflexive.

For symmetric

If [tex](a,b)\in R[/tex] then [tex](b,a)\in R[/tex]

We have

[tex](a,b)\in R[/tex] and [tex](b,a)\in R[/tex]

Hence, R is symmetric.

For transitive

If (a,b)[tex]\in R[/tex] and (b,c)[tex]\in R[/tex] then (a,c)[tex]\in R[/tex]

Here,

[tex](a,a)\in R[/tex] and [tex](a,b)\in R[/tex]

[tex]\implies (a,b)\in R[/tex]

[tex](a,b)\in R[/tex] and [tex](b,a)\in R[/tex]

[tex]\implies (a,a)\in R[/tex]

Therefore, R is transitive.

Yes, it is possible to have  a relation on the set {a, b, c} that is both symmetric and transitive but not reflexive.

Answer:

[tex]\angle ADB \cong \angle CDB[/tex]

[tex]\angle DBA \cong \angle DBC[/tex]

[tex]BD = BD[/tex]

Step-by-step explanation:

Given

[tex]\triangle ABD \cong \triangle CBD[/tex]

Required

The congruent segments by CPCTC

From the question, we have:

[tex]\angle ADB \cong \angle CDB[/tex] --- given

[tex]\angle DBA \cong \angle DBC[/tex] --- given

Both triangles share a common side (length BD);

So, we have:

[tex]BD = BD[/tex]

Hence, the congruent segments are:

[tex]\angle ADB \cong \angle CDB[/tex]

[tex]\angle DBA \cong \angle DBC[/tex]

[tex]BD = BD[/tex]

First, find 40% of 3,000:

0.40 * 3000 = 1200

So they raised 1200 so far.

Now subtract 1200 from the total they want to raise:

3000 - 1200 = 1800

So they need $1,800 more to meet their goal.

Answer:

8iriiruruj

Step-by-step explanation:

u4u the UK. We have a good idea to advertise the UK. I have been a

Answer:

325 and 375 mph

Step-by-step explanation:

Given :

Distance between plane A and B = 2800

Recall :

Distance = speed * time

Let speed of A = v1

Speed of B = v2

v1 = v2 + 50

Time taken = 4 hours

Distance = speed * time

Total distance = 2800

2800 = v1 * 4 + v2 * 4

2800 = (4v1) + (4v2)

2800 = 4(v2+50) + 4v2

2800 = 4v2 + 200 + 4v2

2800 = 8v2 + 200

2800 - 200 = 8v2

2600 = 8v2

v2 = 2600/8

v2 = 325 mph

v1 = v2 + 50

v1 = 325 + 50

v1 = 375 mph

Answer:

c) tan

Step-by-step explanation:

tan = Opposite side / close side

When close side = v         and     Opposite side = 2,8m

Answer:

The expected value of the proposition is of -0.29.

Step-by-step explanation:

For each free throw, there are only two possible outcomes. Either the player will make it, or he will miss it. The probability of a player making a free throw is independent of any other free throw, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

Suppose a basketball player has made 231 out of 361 free throws.

This means that [tex]p = \frac{231}{361} = 0.6399[/tex]

Probability of the player making the next 2 free throws:

This is P(X = 2) when n = 2. So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 2) = C_{2,2}.(0.6399)^{2}.(0.3601)^{0} = 0.4095[/tex]

Find the expected value of the proposition:

0.4095 probability of you paying $31(losing $31), which is when the player makes the next 2 free throws.

1 - 0.4059 = 0.5905 probability of you being paid $21(earning $21), which is when the player does not make the next 2 free throws. So

[tex]E = -31*0.4095 + 21*0.5905 = -0.29[/tex]

The expected value of the proposition is of -0.29.

9514 1404 393

Answer:

  2/7

Step-by-step explanation:

Any unit fraction with a denominator between 3 and 4 will be between 1/3 and 1/4. For example, ...

  1/3.5 = 2/7 . . . . is between 1/3 and 1/4

__

You can also go at this considering decimal equivalents.

  1/4 = 0.25

  1/3 = 0.333... (repeating)

So, decimal numbers like 0.26, 0.295, 0.3330 are all values that are between 1/4 and 1/3.