The type of intermolecular forces existing between different pairs of molecules depends on the nature of the molecules involved.
(a) HBr and H2S: The intermolecular forces between HBr and H2S molecules are dipole-dipole forces. HBr is a polar molecule, with a partial positive charge on the hydrogen atom and a partial negative charge on the bromine atom. H2S is also a polar molecule, with a partial positive charge on the hydrogen atoms and a partial negative charge on the sulfur atom.
(b) Cl2 and CBr4: Cl2 and CBr4 are both nonpolar molecules, meaning they do not have a net charge distribution. As a result, the intermolecular forces between these molecules are dipole-dipole forces. These forces result from the interaction between the dipoles of the individual molecules.
(c) I2 and NO3-: I2 is a nonpolar molecule, while NO3- is a polar ion with a net negative charge. The intermolecular forces between these molecules are dipole-dipole forces, which occur between the dipoles of the individual molecules.
(d) NH3 and C6H6: NH3 is a polar molecule, with a partial positive charge on the hydrogen atoms and a partial negative charge on the nitrogen atom. C6H6 is a nonpolar molecule. The intermolecular forces between NH3 and C6H6 molecules are dipole-dipole forces, which occur between the polar NH3 and nonpolar C6H6 molecules.
In conclusion, the intermolecular forces between the pairs of molecules listed above are dipole-dipole forces, which are a result of the interaction between the polar or charged regions of the molecules.
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What consists of an elemental symbol surrounded by one dot for each of its valence electrons?
The dots represent the valence electrons, and the elemental symbol represents the nucleus and inner electrons. The number of dots in a Lewis dot structure corresponds to the number of valence electrons in an element, which can be determined from the periodic table.
An elemental symbol surrounded by one dot for each of its valence electrons is called an electron dot diagram or a Lewis dot structure. These diagrams are used to represent the valence electrons of an element and to show how elements bond with each other to form compounds.
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Based on the data gathered in Millikan's oil-drop experiments, the concept of atomic structure was modified. Which of the following aspects of the structure of the atom was validated by these experiments?
Check all that apply.
- mass of an electron
- mass of the atom
- charge on a proton- charge on an electron
- mass of a proton
Correct options are option (a) and option (d) are correct. Mass of an electron and charge of an electron was validated by the Millikan's oil drop experiments.
The oil drop experiment was proposed by Robert Millikan. This oil drop experiment allowed Millikan to determine the charge on the electron. This experiment is known as Millikan's oil drop experiment. Later on he used the data and information from his oil drop experiment to determine the mass of the electron. Millikan determined the charge of an electron to be 1.5924×10−19C, where C stands for coulomb which is one ampere*second. At first he direct and compel the measurement of the electric charge of a single electron. He defined the force on any electric charge in an electric field is equal to the product of the charge and the electric field.
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The correct question is,
Based on the data gathered in Millikan's oil-drop experiments, the concept of atomic structure was modified. Which of the following aspects of the structure of the atom was validated by these experiments?
Check all that apply.
(a) mass of an electron
(b) mass of the atom
(c) charge on a proton
(d) charge on an electron
(e) mass of a proton
why did you choose table salt is the best substance
Table salt is sodium chloride, which gives taste to food items and is easily available in its pure form. It can be easily purified and it is readily soluble in water.
What is table salt ?The chemical compound sodium chloride is used as table salt in food. The formula of sodium chloride is NaCl. It is formed by the ionic bonding between sodium and chlorine.
Sodium metal donates one electron to the electronegative chlorine atom and the electrostatic attraction between positive and negative ions create the ionic bond.
NaCl is easily soluble in water. It can be easily purified using phase separation and distillation methods. NaCl is mostly available from the sea in abundant quantity.
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Determine the oxidation number of each element in these species: permanganate ion Mn O calcium phosphide Ca P?
The oxidation number of each element in these species are
Oxidation number Mn is +7, Oxidation number O is -2 Oxidation number Ca is +2Oxidation number P is -3The total number of electrons that an atom acquires or loses to establish a chemical bond with another atom is known as the oxidation number, also known as the oxidation state.
Each constituent element in a compound has the following oxidation number:
Mn in MnO4⁻MnO4 =-1
Where; O = -2, Mn = x
MnO4 =-1
x -2(4) = -1
x - 8 = -1
x - 7 = 0
x = +7
Ca₃P₂Ca₃P₂ = 0
Where; Ca =+2, P = x
Ca₃P₂ = 0
+2(3) + 2P = 0
+6 + 2P = 0
P = -3
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2 NH3 + 3 CuO → 3 Cu + N2 + 3 H2OIn the above equation, how many grams of N2 can be made when 15 moles of CuO are consumed?Round your answer to the nearest tenth. If you answer is a whole number like 4, report the answer as 4.0
The balanced chemical equation is:
2 NH3 + 3 CuO → 3 Cu + N2 + 3 H2O
140.1 grams of N2 can be made when 15 moles of CuO are consumed.
The balanced chemical equation is:
2 NH3 + 3 CuO → 3 Cu + N2 + 3 H2O
According to the equation, 2 moles of NH3 react with 3 moles of CuO to produce 1 mole of N2.
Number of moles of N2 = (15 moles of CuO) x (1 mole of N2 / 3 moles of CuO) = 5 moles of N2
we need to use the molar mass of N2, which is approximately 28.02 g/mol. Therefore:
Mass of N2 = (5 moles of N2) x (28.02 g/mol) = 140.1 g
Rounding this to the nearest tenth gives us 140.1 g of N2.
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Put these steps in the mechanism of chymotrypsin catalysis in order from first to last. Note that your textbook may not break out each of these steps individually, but all steps should be ordered. (There will be eight steps.) A. His 57 catalyzes removal of H from Ser 195 hydroxyl. B. His 57 donates H to N of sissile peptide bond, tetrahedral intermediate decomposes. C. The portion (N-terminal end) of the original substrate with the new carboxylate terminus diffuses away. D. Water donates H to His 57. E. Resulting OH attacks carbonyl of remaining substrate. F. His 57 donates H to Ser 195 O, leading to collapse of thtrahedral intermediate. G. the portion (the C-terminal end) of original substrate with the new amino terminus diffuses away. H. Ser 195's nucleophilic O attacks carbonyl C of substrate.
The mechanism of chymotrypsin catalysis involves several steps:
Ser 195 attacks the carbonyl carbon of the substrate, forming a tetrahedral intermediate.His 57 removes a proton from the hydroxyl group of Ser 195.The tetrahedral intermediate collapses.Water donates a proton to His 57.His 57 donates a proton to the oxygen atom of Ser 195.The resulting hydroxyl group attacks the carbonyl carbon of the substrate.The original substrate is cleaved into two parts.Explanation: The mechanism of chymotrypsin catalysis is a multi-step process that involves several key amino acid residues in the active site of the enzyme. The steps in the mechanism are as follows:
The substrate binds to the active site of chymotrypsin and Ser 195, a nucleophilic residue in the enzyme, attacks the carbonyl carbon of the substrate. This forms a tetrahedral intermediate, which is stabilized by hydrogen bonds with the backbone amide groups of the enzyme.His 57, a basic residue in the enzyme, then removes a proton from the hydroxyl group of Ser 195, which helps to facilitate the reaction and stabilize the negative charge that develops on the oxygen atom of Ser 195.The tetrahedral intermediate then collapses, resulting in the cleavage of the peptide bond between the substrate residues. This releases the N-terminal end of the original substrate with a new carboxylate terminus.Water then donates a proton to His 57, regenerating its active form.His 57 then donates a proton to the oxygen atom of Ser 195, which is now in its deprotonated, negatively charged state. This helps to restore the active site of the enzyme and prepares it for the next round of catalysis.The resulting hydroxyl group of Ser 195 attacks the carbonyl carbon of the remaining substrate residue, forming another tetrahedral intermediate.The tetrahedral intermediate collapses again, resulting in the cleavage of the peptide bond between the substrate residues. This releases the C-terminal end of the original substrate with a new amino terminus.Overall, the mechanism of chymotrypsin catalysis involves a series of nucleophilic attacks, proton transfers, and intermediate stabilization, which work together to efficiently cleave peptide bonds in the substrate.
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Draw a diagram showing how the parts of an atom are related
The relationship between the three fundamental parts of an atom is best represented by the diagram: e- (outside), p+, and n0 (nucleus/inside e-).
What is a foundational concept?
the support or basis of something, n. a subterranean support system that evenly distributes the weight of a wall, structure, etc. 3 the basis upon which something is built. establishing, the act of establishing, the state of being established, or even the state of establishing.
An exact definition of a fundamental skill
It discusses the foundational skills of literacy, numeracy, and transferable skills, which form the basis for a lifetime of learning. Just as we wouldn't build a house without solid foundations, we cannot expect a child to develop without strong fundamental skills.
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Na S=0 N H N H2N Sulfadiazine pk, 6.3 Given the pka of sulfadiazine is 6.3, then what would be the ratio of sulfadiazine's (A-)[HA) in blood plasma with a pH = 7.4? Be sure to show your calculations. Edit View Insert Format Tools Table 12pt v Paragraph BIU A & Tv :
The ratio of A- to HA in blood plasma with a pH of 7.4 would be approximately 2.5119 : 1.
The dissociation reaction of sulfadiazine can be represented as follows:
HA ⇌ H+ + A-
Where HA represents the protonated form of sulfadiazine and A- represents the deprotonated form.
The pKa of sulfadiazine is given as 6.3. This means that at pH values below 6.3, sulfadiazine will predominantly exist in its protonated form (HA), while at pH values above 6.3, it will exist mostly in its deprotonated form (A-).
In blood plasma with a pH of 7.4, the ratio of A- to HA can be calculated using the Henderson-Hasselbalch equation:
pH = pKa + log([A-]/[HA])
Rearranging this equation, we get:
[A-]/[HA] = 10^(pH - pKa)
Substituting the values given:
[A-]/[HA] = 10^(7.4 - 6.3) = 2.5119
Therefore, the ratio of A- to HA in blood plasma with a pH of 7.4 would be approximately 2.5119 : 1.
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A nonapeptide was determined to have the following amino acid composition: (Arg)2, (Gly)2, (Phe)2, His, Leu, Met. 1-fluoro-2,4-dinitrobenzene (FDNB) reacts with free amino (but not amido or guanidino) groups in proteins to produce dinitrophenyl (DNP) derivatives of amino acids. The native peptide was incubated with 1-fluoro-2,4-dinitrobenzene (FDNB) and then completely hydrolyzed; 2,4-dinitrophenylhistidine was identified by HPLC. What does this tell you about the peptide sequence? When the native peptide was exposed to cyanogen bromide (CNBr), an octapeptide and free glycine were recovered. What does this tell you about the peptide sequence? Incubation of the native peptide with trypsin gave a pentapeptide, a tripeptide, and free Arg.The peptides were separated and treated with FDNB. 2,4-Dinitrophenyl-histidine was recovered from the pentapeptide, and 2,4-dinitrophenylphenylalanine was recovered from the tripeptide.What does this tell you about the peptide sequence? Digestion with the enzyme pepsin produced a dipeptide, a tripeptide, and a tetrapeptide. The tetrapeptide was composed of (Arg) 2, Phe, and Gly. What does this tell you about the peptide sequence? What is the sequence of the nonapeptide?
The information provided tells us that the peptide sequence contains a histidine residue at some position.
This information indicates that the peptide sequence contains a histidine residue, which is covalently modified by FDNB to form 2,4-dinitrophenylhistidine. The fact that the histidine residue is modified by FDNB suggests that it is in the free amino form, rather than being part of an amide or guanidino group.
This is because FDNB reacts with free amino groups, but not with amido or guanidino groups. The presence of a histidine residue in the peptide sequence can provide information about the functional and structural properties of the peptide, as histidine is known to play important roles in protein structure and function.
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A car traveling along the highway brakes to stop over a certain distance. More braking force is required if the car hasA. less stopping distanceB. more massC. more momentumD. all of the above
Braking power is required to stop at a certain distance which is greater if the car has D. all of the above
What are car brakes?Car brakes are components of the vehicle engine that play a role in regulating the speed of the vehicle. Brakes are often considered part of a vehicle's safety features.
Brake components can function properly because each component in them is interrelated and works together.
If a car traveling along a road brakes to stop a certain distance, it requires more braking force if the car has a shorter stopping distance, has more mass, and has more momentum.
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What is the energy; in J, of light that must be absorbed by a hydrogen atom to transition an electron from n = 3ton = 7?
A hydrogen atom must absorb 1.815x10⁻¹⁹ Joules of energy in order to transfer electrons from n=3 to n=6.
Let,
Energy absorbed by photon=13.6 z²(1/n₁²-1/n₂²)
E₃₋₆=13.6×1²(1/3²-1/6²)
=(13.6×3/36)ev
E₃₋₆=1.133 eV
to convert energy into J from eV,
E₃₋₆=1.133 eV× 1.602×10⁻¹⁹
E₃₋₆=1.815x10⁻¹⁹ Joules
Electrons are subatomic particles that have a negative electric charge. They are one of the building blocks of matter and are found in the shells that orbit the nucleus of an atom. Electrons play a crucial role in many physical and chemical processes, such as electricity, magnetism, and chemical bonding. They are incredibly tiny, with a mass of about 9.11 x 10⁻³¹ kg and a size of about 10⁻¹⁸ meters. They are also incredibly fast, moving at speeds close to the speed of light. Electrons can be found in a variety of environments, from the atoms that make up the world around us to the free electrons in metals that allow for the flow of electricity.
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A 2.25−L vessel contains 4.70 g of a gas at 1.00 atm and 27.0°C. (a) Calculate the density of the gas in g/L.
Give the reaction of carboxylic acid with ammonia
Answer:
Reactions of carboxylic acids with ammonia
It transfers a hydrogen ion to the lone pair on the nitrogen of the ammonia and forms an ammonium ion. If you mix together a solution of ethanoic acid and a solution of ammonia, you will get a colourless solution of ammonium ethanoate
Explanation:
If a particular solution process is endothermic, then it will be accompanied by ___ in the disorder of the system.
If a particular solution process is endothermic, then it will be accompanied by temperature changes in the disorder of the system.
What is endothermic?An endothermic reaction is a chemical reaction in which the reactants have a low enthalpy, but produce products with a high enthalpy. Because the enthalpies of the reactants are low, the system requires additional energy to release bonds so that heat absorption occurs from the surrounding environment to the system. This causes a decrease in temperature in an endothermic reaction.
So if there is a solution that has endothermic properties it will be accompanied by a disturbance of the temperature changes system.
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A solution is prepared by mixing 1.28 mol C7H16, 2.92 mol C8H18, and 2.64 mol C9H20. What is the (a) mole fraction and (b) mole percent of each component of the solution?
Mole fraction is indeed a unitless phrase since it represents a ratio. Therefore, 0.18 is the mole fraction of C[tex]_7[/tex]H[tex]_{16}[/tex].
What is mole fraction?Mole fraction is a concentration unit defined as the amount of moles of a constituent divided by the total amount of moles of a solution. Mole fraction is indeed a unitless phrase since it represents a ratio.
When the mole fractions of all constituents of a solution are put together, the result is 1. The molar ratio of acetone in a solution containing 1 mol toluene, 2 mol tetrachloroethylene, as well as 7 mol acetone is 0.7.
mole fraction of C[tex]_7[/tex]H[tex]_{16}[/tex] = 1.28/ (1.28+ 2.92+ 2.64)= 1.28/ 6.84=0.18
mole fraction of C[tex]_8[/tex]H[tex]_{18}[/tex]=2.92/ (1.28+ 2.92+ 2.64)=2.92/6.84=0.42
mole fraction of C[tex]_9[/tex]H[tex]_{20}[/tex]= 2.64/ (1.28+ 2.92+ 2.64)=2.64/ 6.84 = 0.38
Therefore, 0.18 is the mole fraction of C[tex]_7[/tex]H[tex]_{16}[/tex].
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what do the Irish traditionally treat fevers?
the Irish traditionally believe in treating fevers with what on dry sugar?
Answer: Spirit
Explanation:
i looked it up and there was a quizlet that asked the same question.
Which choice identifies the limiting reactant
and correct reasoning?
4A1+302 → 2Al2O3
AI —> initial mass 162
—> theoretical yield Al2O3 306
0₂ —> initial mass 97
—> theoretical yield Al2O3 206
A. O2 because it produces a lower theoretical yield.
B. Al because it produces a larger theoretical yield.
C. O2 because it starts with a lower mass.
D. Al because it has a higher initial mass.
The limiting reactant is O2 because it produces a lower theoretical yield. Option A.
Limiting reactantTo identify the limiting reactant, we need to compare the amount of product that can be produced from each reactant, based on the balanced chemical equation and the amount of each reactant that is available.
Using the given information, we can calculate the amount of product that can be produced from each reactant:
For Al:
The molar ratio of Al to Al2O3 is 4:2, or 2:1.
The number of moles of Al is: 162 g / 26.98 g/mol = 6.00 mol.
The theoretical yield of Al2O3 from Al is: 6.00 mol Al x (2 mol Al2O3 / 2 mol Al) x (101.96 g Al2O3 / 1 mol Al2O3) = 611 g Al2O3.
For O2:
The molar ratio of O2 to Al2O3 is 3:2.
The number of moles of O2 is: 97 g / 32.00 g/mol = 3.03 mol.
The theoretical yield of Al2O3 from O2 is: 3.03 mol O2 x (2 mol Al2O3 / 3 mol O2) x (101.96 g Al2O3 / 1 mol Al2O3) = 205 g Al2O3.
Comparing the theoretical yields of Al2O3 from Al and O2, we can see that the theoretical yield of Al2O3 from Al (611 g) is greater than the theoretical yield of Al2O3 from O2 (205 g). Therefore, the limiting reactant is O2, since it will be completely consumed before all of the Al is used up.
The correct answer is A. O2 because it produces a lower theoretical yield.
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Which one of the following cannot form a solid with a lattice based on the sodium chloride structure? A) NaBr. B) LiF. C) RbI. D) CuO. E) CuCl2.
The cannot form a solid with a lattice based on the sodium chloride structure is E) CuCl2
Since, NaCl is a linear molecule and it contain only two ions. In the given options, NaBr, LiF, RbIl and CuO all are linear molecules and it contain only two ions. So, NaBr, LiF, Rbl and CuO will form similar lattice to the NaCl. On the other hand in case of CuCl, there are total three ions and it is not linear molecule. So, it will form different lattice but not NaCl based lattice. The crystal lattice of NaCl is face -centered cubic. Sodium Chloride is an alkali halide with an fcc crystal structure. The basis is two ions, a sodium cation and a chlorine anion.
Then the correct option will be (E) CuCl2.
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How many ATOMS of boron are present in 5.44 grams of boron tribromide, BBr3?
Answer:
Explanation:
To calculate the number of atoms of boron present in 5.44 grams of boron tribromide (BBr3), we need to use Avogadro's number and the molar mass of BBr3.
The molar mass of BBr3 can be calculated by adding the atomic masses of boron and three bromine atoms:
BBr3 molar mass = 1 x atomic mass of B + 3 x atomic mass of Br
BBr3 molar mass = 1 x 10.81 g/mol + 3 x 79.90 g/mol
BBr3 molar mass = 295.41 g/mol
Next, we can calculate the number of moles of BBr3 in 5.44 grams:
moles of BBr3 = mass of BBr3 / molar mass of BBr3
moles of BBr3 = 5.44 g / 295.41 g/mol
moles of BBr3 = 0.0184 mol
Since there is one boron atom in each molecule of BBr3, the number of atoms of boron is the same as the number of molecules of BBr3. We can calculate the number of molecules of BBr3 using Avogadro's number:
number of molecules of BBr3 = moles of BBr3 x Avogadro's number
number of molecules of BBr3 = 0.0184 mol x 6.022 x 10^23/mol
number of molecules of BBr3 = 1.11 x 10^22
Therefore, there are 1.11 x 10^22 atoms of boron in 5.44 grams of BBr3.
which of the following are ways carbon is transferred between the surface and deep ocean? select all that apply.
Carbon is transferred between the surface and deep ocean through a variety of processes, including vertical mixing and diffusion, upwelling, and biological processes such as photosynthesis, respiration, and excretion.
Vertical mixing and diffusion occur when currents and waves mix the surface and deep water layers, allowing carbon to be transferred from one layer to the other. Upwelling is the process of deep ocean water rising to the surface, bringing with it dissolved carbon from the deep ocean. Finally, biological processes such as photosynthesis, respiration, and excretion also move carbon from the surface to the deep ocean.
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Which of the following are ways carbon is transferred between the surface and deep ocean? select all that apply.
diffusionupwellingadvectionphotosynthesisrespiration.Determine if each statement is True or False and put True or False in the blank. A-COOH group is considered an alcohol and a ketone as well as a carboxylic acid. Alcohols, ethers, and esters all contain O atoms. Amides contain a CEO and a C-N on the same carbon. Esters, amides, carboxylic acids and nitriles all contain C=O groups. Alkenes, alkynes, and aromatics are all types of hydrocarbons. Alkanes typically have the formula CnH2n.
A). The statement is False.
B). The statement is True.
C). The statement is True.
D). The statement is False.
E). The statement is True.
F). The statement is False.
In organic chemistry, a hydrocarbon is an organic compound consisting entirely of hydrogen and carbon.: 620 Hydrocarbons are examples of organization 14 hydrides. Hydrocarbons are normally colorless and hydrophobic; their smell is typically faint and may be much like that of gasoline or lighter fluid. They occur in a various variety of molecular structures and stages: they may be gases (such as methane and propane), liquids (including hexane and benzene), low melting solids (such as paraffin wax and naphthalene), or polymers (which include polyethylene and polystyrene).
within the fossil gas industries, hydrocarbon refers to evidently taking place petroleum, herbal gas, and coal, or their hydrocarbon derivatives and purified paperwork. The combustion of hydrocarbons is the principal source of the world's energy. Petroleum is the dominant raw-material source for natural commodity chemical compounds such as solvents and polymers. maximum anthropogenic (human-generated) emissions of greenhouse gases are both carbon dioxide released with the aid of the burning of fossil fuels, or methane launched from the coping with natural gas or from agriculture.
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At 27c and 750 mm hg a sample of hydrogen occupies 5.00l how much space will it occupy at stp
Considering the ideal gas law, the gas will ocuppy a volume of 0.0299 L at STP.
Definition of ideal gas lawAn ideal gas is a gas made up of certain particles that, despite having a random displacement, do not interact with each other, having perfect elastic collisions without suffering attraction or repulsion. These gases are known as ideal because they have only been described theoretically, although they are useful for the analysis of real gases.
An ideal gas can be fully described by the ideal gas equation:
P×V = n×R×T
Where:
P is the gas pressure.V is the volume that occupies.T is its temperature.R is the ideal gas constant. The universal constant of ideal gases R has the same value for all gaseous substances. n is the number of moles of the gas.Definition of STP conditionsThe STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C are used and are reference values for gases. And in these conditions 1 mole of any gas occupies an approximate volume of 22.4 liters.
Volume at STPIn first place, you know:
P= 750 mmHg= 0.00657895 atm (760 mmHg= 1 atm)V= 5 Ln= ?R= 0.082 (atmL)/(molK)T= 27 C= 300 K (being 0 C= 273 K)Replacing in the ideal gas law:
0.00657895 atm× 5 L = n× 0.082 (atmL)/(molK)× 300 K
Solving:
(0.00657895 atm× 5 L)÷ (0.082 (atmL)/(molK)× 300 K)= n
1.337×10⁻³ moles= n
This number of moles will be the same although you change the pressure and temperature. For STP, you know:
P= 1 atmV= ?n= 1.337×10⁻³ molesR= 0.082 (atmL)/(molK)T= 0 C= 273 KReplacing in the ideal gas law:
1 atm× V= 1.337×10⁻³ moles× 0.082 (atmL)/(molK)× 273 K
Solving:
V= (1.337×10⁻³ moles× 0.082 (atmL)/(molK)× 273 K)÷ (1 atm)
V= 0.0299 L
Finally, the volume will be 0.0299 L.
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how to calculate 100 ton/h to kmol/h
You just need to calculate the following to go from kg/hour to kmol/s: For instance, 1 kmol/h should represent 36 kg with 1 kg/s should equal 1/36 kmol/h if there was 3 kmol in 1 kilogram and 12 seconds in 1 hour.
Is mol the same as KMOL?1000 moles make up one kilomole. 1 Mole: Denotes the quantity of a chemical compound that has the same number of atoms as there are in Twelve grams of natural carbon-12. 103 moles are equivalent to one kilogram, or one kilomole, in the SI system of measurement (metrology).
A Kmol contains how many mmol?mmol↔kmol 1000000 mmol make up 1 kmol.
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How many grams do 2.354E+25 molecules of chromium 2 permanganate weigh?
Chromium 2 permanganate weighs 1117.12 grams or 2.354E+25 molecules.
Why does the body need chromium?Increasing glucose tolerance and enhancing protein, glycogen, and lipid metabolism are two benefits of the crucial trace mineral chromium. People only require very little amounts of this metal coating.
Molar mass of chromium(II) permanganate = (1 x atomic mass of Cr) + (2 x atomic mass of Mn) + (8 x atomic mass of O)
Let's assume the atomic mass of Cr is 52, atomic mass of Mn is 54, and atomic mass of O is 16.
Molar mass of chromium(II) permanganate = (1 x 52) + (2 x 54) + (8 x 16) = 52 + 108 + 128 = 288 g/mol
Moles of chromium(II) permanganate = 2.354 x 10^25 molecules / 6.022 x 10^23 molecules/mol = 3.9 x 10^2 mol
Weight in grams = moles of chromium(II) permanganate x molar mass = 3.9 x 10^2 mol x 288 g/mol = 1117.12 g
So, 2.354 x 10^25 molecules of chromium(II) permanganate weigh approximately 1117.12 grams.
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Calculate the root mean square (rms) average speed of the atoms in a sample of argon gas at 0.13 atm and -60.
The RMS speed of the atoms in the sample of argon gas at 0.13 atm and -60°C is[tex]533.5 m/s.[/tex]
Root mean square (RMS) average speed is the average speed of the atoms in a sample of gas, calculated by taking the square root of the average of the squares of the individual speeds. To calculate the RMS speed of argon gas at 0.13 atm and -60°C, we first need to calculate the mean kinetic energy (mKE) of the gas. The mKE can be calculated using the formula [tex]mKE = \frac{3}{2}kT[/tex],
where k is Boltzmann's constant ([tex]1.38 * 10^{-23} J/K[/tex]) and T is the temperature of the gas in Kelvin. At -60°C, the temperature is 213.15 K, so the mKE of the gas is [tex]0.845 * 10^{-21} J.[/tex].
The RMS speed of the atoms can then be calculated using the formula [tex]RMS speed = \sqrt{} (2mKE/m)[/tex], where m is the mass of the atom. The mass of an argon atom is[tex]6.63 * 10^{-26} kg[/tex], so the RMS speed of the atoms in the sample of argon gas at 0.13 atm and -60°C is [tex]533.5 m/s.[/tex]
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helppppppppppppppppppppppppppppppppppppppppppppppp
Answer: B
Explanation:
2 Bd + Ch --> Bd₂Ch
The 2 on the left side of the equation represents 2 separate pieces of bread (answer B).
They are trying to use this illustration to help with understanding stoichiometry in chemistry.
scenario: a certain first-order reaction is 58 percent complete in 65 seconds. calculate the rate constant for this reaction.
The rate constant for a first-order reaction of a certain first-order reaction is 58 percent complete in 65 seconds is [tex]\frac{-\ln\left(\ln\left(0.42\right)\right)}{65}[/tex].
To calculate the rate constant for a first-order reaction, you need to use the following equation:
The reaction progress can be expressed as a fraction of the initial concentration of the reactant:
[tex]\frac{A}{A_0} = 1 - x[/tex]
where x is the fraction of the reaction that has occurred, and in this case, x = 0.58.
Rearranging the above equation to solve for A:
[tex]A = A_0 - A_0x = A_0(1 - x) = A_0 \cdot 0.42[/tex]
The rate constant can be found by using the equation:
[tex]\ln\left(\frac{A_0}{A}\right) = -kt[/tex]
Plugging in the value of A from step 2 into the above equation:
[tex]\ln\left(\frac{A_0}{A_0 \cdot 0.42}\right) = -kt[/tex]
Simplifying the above equation:
[tex]\ln\left(\frac{1}{0.42}\right) = -kt[/tex]
Using the natural logarithm properties to simplify further:
[tex]\ln\left(\frac{1}{0.42}\right) = \ln\left(\frac{1}{e^{-\ln(0.42)}}\right) = \ln\left(e^{\ln(0.42)}\right) = \ln\left(0.42\right)[/tex]
t = 65 seconds
Solving for k:
[tex]k = \frac{-\ln\left(\frac{1}{0.42}\right)}{t} = \frac{-\ln\left(\ln\left(0.42\right)\right)}{65}[/tex]
We do not know the initial concentration [tex]$A_0$[/tex], so we cannot solve for k exactly. However, we can use the calculated value of k to find the concentration of the reactant at any time during the reaction.
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1.SEP Communicate Information In addition
to properties of elements, list at least two other
things or events that are periodic.
Other happenings that are also in periods would be: tides and biological rhythms.
What events are in periods?There are many things and events that exhibit periodicity, or a repeating pattern over time. Some examples include:
Tides: The rise and fall of sea levels due to the gravitational pull of the moon and the sun on Earth's oceans. Tides follow a predictable pattern and repeat every 12 hours and 25 minutes.
Biological Rhythms: Many living organisms have internal biological clocks that regulate various physiological processes such as sleep, hunger, and hormone secretion. These rhythms repeat in a periodic manner, such as the 24-
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Rutherford bombarded gold foil with alpha particles and found that a small percentage of the
particles were deflected. Which of the following was not accounted for by the model he proposed
for the structure of atoms?
A. the small size of the nucleus B. the charge on the nucleus
C. the total mass of the atom D. the existence of protons
E. the presence of electrons outside the nucleus
The following are not taken into account by the proposed model
for atomic structure Is B. the charge on the nucleus
What is atomic structure?Atomic structure is the basic unit of matter consisting of an atomic nucleus and a cloud of electrons with a negative charge surrounding it. In the nucleus of each atom, there is a mixture.
The mixture inside the atomic nucleus is a proton with a positive charge and a neutron with a neutral charge. Electrons that surround the atomic nucleus will be bound because of the electromagnetic force.
So if a small part of the alpha particle is found to be deflected, what is not taken into account by the atomic structure is the charge on the nucleus.
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The concentration of the alkane C20H42 in a particular sample of rainwater is 0.13 ppb. Assume that the density of rainwater is close to 1.00 g/mL and find the molar concentration of C20H42.
The molar concentration of alkane C₂₀H₂₄ is 3.6731 x 10 ⁻⁵ M
A chemical species' concentration in a solution, specifically the amount of a solute per unit volume of solution, is measured by its molar concentration. The most used molarity unit in chemistry is the number of moles per liter, denoted by the unit symbol mol/L or mol/dm3 in SI units.
The Concentration of alkane C₂₀H₂₄ = 0.13 ppb
since 1 ppb =10⁻³ mg/L concentration of C₂₀H₂₄ is 1.3 x10⁻⁴ mg/L
Density of water = 1.00 g/mL
Molar concentration = mass / (molar mass x Volume)
Formula weight of C₂₀H₂₄= 282.55
Mass C₂₀H₂₄ = 1.3 x10⁻⁴ mg/L =1.3 x10⁻⁷g/L
Molar concentration = mass / (molar mass x Volume)
Molar concentration C₂₀H₂₄ = 1.3 x10⁻⁷g/L / 282.55 g / moles
Molar concentration C₂₀H₂₄ = 3.6731 x 10 ⁻⁵ M
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