Answer:
slope is 2÷3 of giving line points
Please help me with solving these. I’d really appreciate your help. Thank you very much.
Answer:
Problem 17)
[tex]\displaystyle y=-\frac{5}{2}x+\frac{7}{2}[/tex]
Problem 18)
[tex]\displaystyle y=\frac{3}{2}x-\frac{3}{2}+\frac{\pi}{4}[/tex]
Step-by-step explanation:
Problem 17)
We have the curve represented by the equation:
[tex]\displaystyle 4x^2+2xy+y^2=7[/tex]
And we want to find the equation of the tangent line to the point (1, 1).
First, let's find the derivative dy/dx. Take the derivative of both sides with respect to x:
[tex]\displaystyle \frac{d}{dx}\left[4x^2+2xy+y^2\right]=\frac{d}{dx}[7][/tex]
Simplify. Recall that the derivative of a constant is zero.
[tex]\displaystyle \frac{d}{dx}[4x^2]+\frac{d}{dx}[2xy]+\frac{d}{dx}[y^2]=0[/tex]
Differentiate. We can differentiate the first term normally. The second term will require the product rule. Hence:
[tex]\displaystyle 8x+\left(2y+2x\frac{dy}{dx}\right)+2y\frac{dy}{dx}=0[/tex]
Rewrite:
[tex]\displaystyle \frac{dy}{dx}\left(2x+2y\right)=-8x-2y[/tex]
Therefore:
[tex]\displaystyle \frac{dy}{dx}=\frac{-8x-2y}{2x+2y}=-\frac{4x+y}{x+y}[/tex]
So, the slope of the tangent line at the point (1, 1) is:
[tex]\displaystyle \frac{dy}{dx}\Big|_{(1, 1)}=-\frac{4(1)+(1)}{(1)+(1)}=-\frac{5}{2}[/tex]
And since we know that it passes through the point (1, 1), by the point-slope form:
[tex]\displaystyle y-1=-\frac{5}{2}(x-1)[/tex]
If desired, we can simplify this into slope-intercept form. Therefore, our equation is:
[tex]\displaystyle y=-\frac{5}{2}x+\frac{7}{2}[/tex]
Problem 18)
We have the equation:
[tex]\displaystyle y=\tan^{-1}\left(x^3\right)[/tex]
And we want to find the equation of the tangent line to the graph at the point (1, π/4).
Take the derivative of both sides with respect to x:
[tex]\displaystyle \frac{dy}{dx}=\frac{d}{dx}\left[\tan^{-1}(x^3)][/tex]
We can use the chain rule:
[tex]\displaystyle \frac{d}{dx}[u(v(x))]=u'(v(x))\cdot v(x)[/tex]
Let u(x) = tan⁻¹(x) and let v(x) = x³. Thus:
(Recall that d/dx [arctan(x)] = 1 / (1 + x²).)
[tex]\displaystyle \frac{d}{dx}\left[\tan^{-1}(x^3)\right]=\frac{1}{1+v^2(x)}\cdot 3x^2[/tex]
Substitute and simplify. Hence:
[tex]\displaystyle \frac{d}{dx}\left[\tan^{-1}(x^3)\right]=\frac{1}{1+v^2(x)}\cdot 3x^2=\frac{3x^2}{1+x^6}[/tex]
Then the slope of the tangent line at the point (1, π/4) is:
[tex]\displaystyle \frac{dy}{dx}\Big|_{x=1}=\frac{3(1)^2}{1+(1)^6}=\frac{3}{2}[/tex]
Then by the point-slope form:
[tex]\displaystyle y-\frac{\pi}{4}=\frac{3}{2}(x-1)[/tex]
Or in slope-intercept form:
[tex]\displaystyle y=\frac{3}{2}x-\frac{3}{2}+\frac{\pi}{4}[/tex]
Plz help I’ll mark you
Answer:
option (B) is the answer
A study was conducted to investigate the effectiveness of hypnotism in reducing pain. Results for randomly selected subjects are given below. At the 1% level of significance, test the claim that the sensory measurements are lower after hypnotism (scores are in cm. on a pain scale). Assume sensory measurements are normally distributed. Note: You do not need to type these values into Minitab Express; the data file has been created for you.Before 6.6 6.5 9.0 10.3 11.3 8.1 6.3 11.6 After 6.8 2.4 7.4 8.5 8.1 6.1 3.4 2.0
Answer:
sensory measurement are lower after hypnotism
Step-by-step explanation:
Given the data :
Before 6.6 6.5 9.0 10.3 11.3 8.1 6.3 11.6
After 6.8 2.4 7.4 8.5 8.1 6.1 3.4 2.0
The difference ;
After - Before, d = 0.2, - 4.1, - 1.6, - 1.8, - 3.2, - 2, - 2.9, - 9.6
Hypothesis :
H0 : μd = 0
H0 : μ < 0
The test statistic ;
T = μd / sd/√n
Where, xd = mean of difference
sd = standard deviation of difference
n = sample size
Mean of difference, μd = Σx/n = - 3.13
Standard deviation of difference, sd = 2.91
T = - 3.13 / 2.91/√8
T = - 3.13 / 1.0288403
T = - 3.042
α = 0.01
The Pvalue using a Pvalue calculator ;
Degree of freedom, df = n - 1 ; 8-1 = 7
Pvalue(-3.042, 7) = 0.00939
Pvalue < α ; we reject the null and conclude that sensory measurement are lower after hypnotism
Need help with this math
Answer:
first option : sqrt(26) + 6 units
Step-by-step explanation:
distance office to supermarket OS
OS² = (-7 - -2)² + (-5 - -6)² = (-7+2)² + (-5+6)² = (-5)² + 1² =
= 25 + 1 = 26
OS = sqrt(26)
distance supermarket to home SH
SH² = (-2 - 4)² + (-6 - -6)² = (-6)² + 0² = 36
SH = 6
so in total she travels sqrt(26) + 6 units
Sarah invests £2000 for 2 years in a saving account. She earns 3% per annum in compound interest.
How much did Sarah have in her saving account after 2 years?
£
Use the formula:
A=P(1+r100)n
Where;
A = the amount of money accumulated after n years, including interest
P = the principal sum (the initial amount borrowed or invested)
r = the rate of interest (percentage)
n = the number of years the amount is borrowed or invested
Answer:
£2120.27
Step-by-step explanation:
A = P (1 + r100)
A = 2000 (1+ 0.03/365)^365(2)
A = 2000 ( 1.00008)^730
A = 2000 (1.060)
A = £2120.27
In the xy-plane, line / passes through the origin and is perpendicular to the line with equation 5x - 2y = 8.
Which of the following could be an equation of line /?
Answer:
[tex]ac - bd[/tex]
Step-by-step explanation:
[tex]ac - bd [/tex]
Plz help. Last one today. 20 points. Thx!
find the first three common multiplies
6 and 8
Answer:
24,48,72
Step-by-step explanation:
multiples of 6- 6,12,18,24,30,36,42,48,54,60,66,72
multiples of 8- 8,16,24,32,40,48,56,64,74,80
Solve the following inequality.
- 202-16
Which graph shows the correct solution?
At a sale, a sofa is being sold for 64% of the regular price. The sale price is $592. What is the regular price?
Answer:
925
Step-by-step explanation:
Formula =592 x 100/64 = 925
Last year, each Capulet wrote 4 essays, each Montague wrote 6 essays, and both families wrote 100 essays in total.
This year, each Capulet wrote 8 essays, each Montague wrote 12 essays, and both families wrote 200 essays in total.
How many Capulets and Montagues are there?
Choose 1 answer:
A: There is not enough information to determine the exact number of Capulets and Montagues.
B: The given information describes an impossible situation.
C: There are 16 Capulets and 6 Montagues.
D: There are 6 Capulets and 16 Montagues
Answer: There are 16 Capulets and 6 Montaques.
Step-by-step explanation:Other choices were either less than or greater than 200 multiplied by each other. If we do 16x8 which is 128 for the Capulets. Also, if we do 12x6 which is 72 for the Montaques. 128+72=200 essays in total
Can the following two triangles be proven congruent through AAS?
A. Yes, since three pairs of angles are congruent, ∠C≅∠V
∠
C
≅
∠
V
, ∠B≅∠W
∠
B
≅
∠
W
, and ∠A≅∠U
∠
A
≅
∠
U
, the triangles are congruent through AAS.
B.No, since ∠C≅∠V
∠
C
≅
∠
V
, ∠B≅∠W
∠
B
≅
∠
W
, and a pair of included sides are congruent, AC⎯⎯⎯⎯⎯⎯⎯⎯≅UV⎯⎯⎯⎯⎯⎯⎯⎯⎯
A
C
¯
≅
U
V
¯
, the triangles aren’t congruent through AAS.
C.Yes, since two pairs of angles are congruent,∠C≅∠V
∠
C
≅
∠
V
and ∠B≅∠W
∠
B
≅
∠
W
, and a pair of non-included sides are congruent, AC⎯⎯⎯⎯⎯⎯⎯⎯≅UV⎯⎯⎯⎯⎯⎯⎯⎯⎯
AC¯≅UV¯, the triangles are congruent through AAS.
D.No, since only two pairs of angles are congruent, the triangles aren’t congruent through AAS.
Answer:
C. YES
Step-by-step explanation:
If two angles and the non-included side of one triangle are equal to the corresponding angles and side of another triangle, the triangles are congruent.
Solve algebraically.
6(t-2) + 15t < 5(5 + 3t)
With work shown please!!
Step-by-step explanation:
6t-12+15t | 25+15t
21t-12 | 25+15t
21t-12 < 25+15t
hence proved..
Answer:
21t - 12 < 25 + 15t
Step-by-step explanation:
6( t - 2 ) + 15t < 5 ( 5 + 3t )
Distribute .6t - 12 + 15t < 25 + 15t
Combine like terms.21t - 12 < 25 + 15t.
Hence , Proved.
Which of the following is a correctly written algebraic equation?
a + 0.2x
5b - 5x + 2
a- 3x = 0
The equation "a - 3x = 0" is correctly written because it follows the standard format of an algebraic equation.
Given that,
All the equations are,
1. a + 0.2x
2. 5b - 5x + 2
3. a - 3x = 0
Now, from equation ''a - 3x = 0'',
In this equation, the variable "a" subtracted from 3 times the variable "x" equals zero.
The equal sign (=) indicates that the expression on both sides of the equation is equivalent.
The equation is properly balanced and expresses equality between the two sides.
It accurately represents a relationship between the variables "a" and "x" where the value of "a" is dependent on the value of "x" in order to satisfy the equation.
So, The correctly written algebraic equation is:
a - 3x = 0
To learn more about the equation visit:
brainly.com/question/28871326
#SPJ4
f it take 20 minutes to boil 6 crates of eggs, how much time will it take to boil 18 crates of eggs
a hour,.....................
Find the missing term in the following pattern.
320, 160, 80 blank space then, 20, 10
40
Step-by-step explanation:
Each number is followed by a number that is half its value, so the sequence goes like
320, 160, 80, 40, 20, 10.
A three-dimensional object's measurement(s) include which of the following?
Check all that apply.
A. Width
B. Length
C. Height
D. None of these
Answer:
A.
B.
C.
Step-by-step explanation:
all three are used in 3 dimensional objects hence the name 3 dimensions.
divide 18/7 by 8/26. Pls give the correct ans
Answer:
8.35714285714
Step-by-step explanation:
Hope it help you
Write the rule that describes the first transformation?
RED —> BLUE
Looking at Point A to A', the rectangle moves 5 places to the left which is the x value + 5 and it shifts 1 place down which would be the y value - 1
This gets written as:
(x+5, y-1)
Question 5 of 10
Select the correct answer.
The graph shows a line of best fit for data collected on the average temperature, in degrees Fahrenheit, during a month and the
number of inches of rainfall during that month.
Average Temp.
90
80
70
60
50
404
30
20
10
1 1 2 3 4 5 6
X
Inches of Rain
The equation for the line of best fit is y = -3.32x + 97.05.
Based on the line of best fit, what would be the prediction for the average temperature during a month with 13.25 inches of rainfall?
Answer:
53.06°F
Step-by-step explanation:
Given the equation of best fit :
y=-3.32x +97.05.
The average temperature for a month with 13.25 inches of Rainfall
Amount of Rainfall = x
Average temperature = y
To make our prediction ; put x = 13.25 in the equation and solve for y ;
y = -3.32x +97.05
Put x = 13.25
y = -3.32(13.25) +97.05
y = - 43.99 + 97.05
y = 53.06°F
Suppose 35.45% of small businesses experience cash flow problems in their first 5 years. A consultant takes a random sample of 530 businesses that have been opened for 5 years or less. What is the probability that between 34.2% and 39.03% of the businesses have experienced cash flow problems?
1) 0.6838
2) 20.3738
3) 0.3162
4) - 11.6695
5) 1.2313
Answer:
1) 0.6838
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]
35.45% of small businesses experience cash flow problems in their first 5 years.
This means that [tex]p = 0.3545[/tex]
Sample of 530 businesses
This means that [tex]n = 530[/tex]
Mean and standard deviation:
[tex]\mu = p = 0.3545[/tex]
[tex]s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.3545(1-0.3545)}{530}} = 0.0208[/tex]
What is the probability that between 34.2% and 39.03% of the businesses have experienced cash flow problems?
This is the p-value of Z when X = 0.3903 subtracted by the p-value of Z when X = 0.342.
X = 0.3903
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{0.3903 - 0.3545}{0.0208}[/tex]
[tex]Z = 1.72[/tex]
[tex]Z = 1.72[/tex] has a p-value of 0.9573
X = 0.342
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{0.342 - 0.3545}{0.0208}[/tex]
[tex]Z = -0.6[/tex]
[tex]Z = -0.6[/tex] has a p-value of 0.27425
0.9573 - 0.2743 = 0.683
With a little bit of rounding, 0.6838, so option 1) is the answer.
Find the maximum and the minimum value of the following objective function, and the value of x and y at which they occur. The function F=2x+16y subject to 5x+3y≤37, 3x+5y≤35, x≥0, y≥0
The maximum value of the objective function is ___ when x=___ and y=___
Answer:
The maximum value of the objective function is 112 when x = 0 and y = 7.
Step-by-step explanation:
Given the constraints:
5x+3y≤37, 3x+5y≤35, x≥0, y≥0
Plotting the above constraints using geogebra online graphing tool, we get the solution to the constraints as:
A(0, 7), B(7.4, 0), C(5, 4) and D(0, 0)
The objective function is given as E =2x+16y, therefore:
At point A(0, 7): E = 2(0) + 16(7) = 112
At point B(7.4, 0): E = 2(7.4) + 16(0) = 14.8
At point C(5, 4): E = 2(5) + 16(4) = 74
At point D(0, 0): E = 2(0) + 16(0) = 0
Therefore the maximum value of the objective function is at A(0, 7).
The maximum value of the objective function is 112 when x = 0 and y = 7.
3.
If 9x = 27, what is the value of x?
Jamie left home on a bike traveling at 24 mph. Five hours later her brother realized Jamie had forgotten her wallet and decided to take it to her. He took his car and traveled at 64 mph. How many hours must the brother drive to catch Jamie?
Answer:
3 hrs
Step-by-step explanation:
5 * 24 = 120 miles
64x = 120 + 24x
40x = 120
x = 3 hrs
Given the functions below, find f(x)+g(x)
CHECK MY ANSWERS PLEASE
Answer:
It's the last one
Step-by-step explanation:
(3x-1)-(x²+4)
3x-1-x²-4
-x²+3x-5
For any real number √a²
a
- |al
lal.
-a
Answer:
|a|
Step-by-step explanation:
For any positive or negative a, when you square it, the answer is positive.
The square root symbol means the principal square root. For a positive number, the principal square root is positive. To make sure the square root is always non-negative, use absolute value.
Answer: |a|
The cone and the cylinder below have equal surface area. O A. True O B. False
Answer:
the answer is false
Step-by-step explanation:
comment if you want explanation
Answer:
True
Step-by-step explanation:
When using the formulas to find the surface area, both have equal surface area
Chris is riding her bike for 10 miles. She averages 12 mi/h. how many more minutes must she ride before she travels 60 miles?
Answer:
5 Minutes
take 10 and add 12 for each minute until you pass 60
Given: f(x) = x- 7 and h(x) = 2x + 3
Write the rule for f(h(xc)).
Answer:
[tex]f(h(xc)) = 2xc-4[/tex]
Step-by-step explanation:
Given
[tex]f(x) = x - 7[/tex]
[tex]h(x) = 2x + 3[/tex]
Required
[tex]f(h(xc))[/tex]
First, calculate h(xc)
If [tex]h(x) = 2x + 3[/tex]
Then
[tex]h(xc) = 2xc + 3[/tex]
Solving further:
[tex]f(x) = x - 7[/tex]
Substitute h(xc) for x
[tex]f(h(xc)) = h(xc) - 7[/tex]
Substitute [tex]h(xc) = 2xc + 3[/tex]
[tex]f(h(xc)) = 2xc + 3 - 7[/tex]
[tex]f(h(xc)) = 2xc-4[/tex]
The of the matrix whose columns are vectors which define the sides of a parallelogram one another is the area of the parallelogram?
Answer:
absolute value of the determinant, adjacent to, equal to
Step-by-step explanation:
The absolute value of a determinant of the [tex]\text{matrix whose}[/tex] columns are the vectors and they define the [tex]\text{sides}[/tex] of a [tex]\text{parallelogram}[/tex] which is adjacent to one another and is equal to the [tex]\text{area}[/tex] of the [tex]\text{parallelogram}[/tex].
The determinant is a real number. They are like matrices, but we use absolute value bars to show determinants whereas to represent a matric, we use square brackets.