Answer:
The interpretation of the subject in question is characterized in the discussion section below.
Explanation:
The atom seems to be the smallest particle of negatively charged electrons as well as positive. The negative particulates are comparatively small, as well as distant from both the considerably high beneficial particles. When the negative objects traveled away from the desired ones those who formed an intangible beam which was electrically charged.Thomson would use a closed glass globe with just a single positive and another negative electrode with extraordinarily low present pressure. He was forced to submit those other gases to quite a voltage level, and also that the rise in popularity of emission levels, which have been called cathode rays, must have been observed.As the negatives shifted away from those in the positives, an imaginary electrically conductive beam was formed. Not only that but the negative particles have been completely circumvented due to the extreme distance seen between positively and negatively particle size.Mention four importance of writing the physical quantities as vectors.
Answer:
Explanation:
Knowledge of vectors is important because many quantities used in physics are vectors. If you try to add together vector quantities without taking into account their direction you'll get results that are incorrect.
Some of the key vector quantities in physics: force, displacement, velocity, and acceleration.
An example of the importance of vector addition could be the following:
Two cars are involved in a collision. At the time of the collision car A was travelling at 40 mph, car B was travelling at 60 mph. Until I tell you in which directions the cars were travelling you don't know how serious the collision was.
The cars could have been travelling in the same direction, in which case car B crashed into the back of car A, and the relative velocity between them was 20 mph. Or the cars could have been travelling in opposite directions, in which case it was a head on collision with a relative velocity between the cars of 100 mph!
Vector is defined as a quantity having direction as well as magnitude, especially as determining the position of one point in space relative to another
What is vector quantity?Vector is defined as a quantity having direction as well as magnitude, especially as determining the position of one point in space relative to another
Knowledge of vectors is important because many quantities used in physics are vectors. If you try to add together vector quantities without taking into account their direction you'll get results that are incorrect.
Some of the key vector quantities in physics: force, displacement, velocity, and acceleration.
An example of the importance of vector addition could be the following:
Two cars are involved in a collision. At the time of the collision car A was travelling at 40 mph, car B was travelling at 60 mph. Until I tell you in which directions the cars were travelling you don't know how serious the collision was.
The cars could have been travelling in the same direction, in which case car B crashed into the back of car A, and the relative velocity between them was 20 mph. Or the cars could have been travelling in opposite directions, in which case it was a head on collision with a relative velocity between the cars of 100 mph!
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What is the acceleration of a proton moving with a speed of 7.7 m/s at right angles to a magnetic field of 1.9 T
Answer:
The acceleration of the proton is 1.403 x 10⁹ m/s²
Explanation:
Given;
speed of proton, v = 7.7 m/s
magnitude of magnetic field, B = 1.9 T
Magnetic force of moving proton is given by;
F = qvBsinθ
Centripetal force on the moving proton is given by;
[tex]F = m(\frac{v^2}{r})\\\\F = m(a_c) \\\\a_c \ is \ the \ centripetal \ acceleration[/tex]
[tex]qvBsin\theta = ma_c\\\\ac = \frac{qvBsin(90)}{m}[/tex]
where;
q is charge of the proton = 1.602 x 10⁻¹⁹ C
m is mass of proton = 1.67 x 10⁻²⁷ kg
[tex]ac = \frac{(1.602*10^{-19})(7.7)(1.9)sin(90)}{1.67*10^{-27}}\\\\a_c = 1.403*10^{9} \ m/s^2[/tex]
Therefore, the acceleration of the proton is 1.403 x 10⁹ m/s²
the heaviest weight ever lifted by a human ear is 51.7kg. how many pounds is this?
Answer:
hey!
Your answer will be EXACTLY 113.97899 Pounds
Explanation:
BUT IF YOU ROUND THIS UP TO THE WHOLE NUMBER etc IT WILL BECOME 114 POUNDS!
Hope This Helped!
itsMATT04
While skiing , Sam flies down hill and hits a jump. He has a mass of 75 kg. And he leaves the jump at 18m/s what is his momentum as he leaves the jump
A westward-moving bicycle increased its speed from 2.0m/s to 12.0m/s in 4.0 seconds. What is the magnitude and direction of the acceleration?
Answer:
2.5 m/s^2
Explanation:
Acceleration = (Final Velocity - Initial Velocity) / TIme
Acceleration = 12 - 2 / 4
=> Acceleration = 10 /4
=> Accelration = 5/2
=> Acceleration = 2.5 m/s^2
So, Acceleration is 2.5 m/s^2
The acceleration of the bicycle which is the change in the velocity of the bike with change in time will be 2.5m/s in the Westward direction
Initial speed = 2.0 m/s Final speed = 12.0 m/s Change in time, △t = 4.0 secondsWe define acceleration thus :
Acceleration = (△velocity / △time) Change in velocity = (12 - 2) = 10 m/s Acceleration = 10 / 4 = 2.5 m/s²Therefore, the acceleration of the bike will be 2.5m/s² in the West direction
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Convert 200in/10s into m/s (1m = 39.37in)
Which of these forces help protons and neutrons to stay at the center of the Atom
Hydrogen atom number 1 is known to be in the 4f state. Hydrogen atom number 2 is in the 5d state.
Required:
a. What is the energy of the atom?
b. WHat is the magnitude of this atom's orbital angular momentum?
c. Hydrogen atom number 2 is in the 5d state. Is this atom's energy greater than, less than, or the same as that of atom 1? Explain.
d. Is the magnitude of the orbital angular momentum of atom 1 greater than, less than, or the same as that of atom 2? Explain.
Answer:
4f E₄ = 0.85 eV, L₄ = 4.22 10⁻³⁴ ,
5d E₅ = 0.544 eV , L5 = 5.28 10⁻³⁴
Explanation:
Let's use the Bohr model, stable the energy of the hydrogen atom
E = -13.606 / n2
where Eo = 13.606 eV is the energy of the ground states.
a) the energy of each atom
level 4f
In this nomenclature enumeration is the number n
E = -13606 / 42
E₄ = 0.85 eV
level 5d
E₅ = -13.606 / 5 2
E₅ = 0.544 eV
b) The angular momentum is given in Boh's model
L = n h / 2pi
let's calculate
level 4f L₄ = 4 6.63 10⁻³⁴-34 / 2 pi
L₄ = 4.22 10⁻³⁴
level 4d
L5 = 5 6.63 10-⁻³⁴ / 2pi
L5 = 5.28 10⁻³⁴
c) The hydrogen atom in state n = 5 has lower energy than the other state
d) Atom 1 has less angular momentum than atom 2
difference between far point and near point
Answer:
Far point = is the farthest point where you can see the object
near point= is the nearest distance where you can see the object.
Explanation:
The far point of human eye is upto infinity & the near point is 25cm.
An electron from a Ti ^ + 2 hydrogen ion leaps from one orbit with radius 13.25 angstrom to another orbit with radius 2.12 angstrom. determine the energy (Joule) e produced in said transition and the wavelength (in cm)
Answer:
E = 0.2276 10⁻¹⁹ J , λ = 8.73374 10⁻⁴ cm
Explanation:
Bohr's atomic model can be used for hydrogen-type atoms, that is, they have a single electron in their last orbit, this is the case of doubly ionized Titanium.
It is much easier to work in EV units.
r = a₀ / Z n²
E = - 13.606 (Z² / n²)
where ao is the Bohr radius, which is the ground state orbital of hydrogen a₀ = 0.0529 nm, Z is the atomic number of titanium, and n is an integer that represents the different states of the system.
a) Let's look for the energy, for this we look for the integer numbers of these orbits
r = 13.25 A = 1.325 nm
r = a₀ / Z n²
n = √(Z r / a₀)
the atomic number of titanium is Z = 22
n = √ (22 1.325 / 0.0529)
n = 23
r = 2.12 A = 0.212 nm
n = √ (22 0.212 / 0.0529)
n = 9
now we can calculate the energy of the transition
E = 13.606 (1 / [tex]n_{f}^2[/tex] - 1 / [tex]x_{o}^2[/tex])
E = 13.606 (1/9² - 1/23²)
E = 13.6060 (0.010455)
E = 0.1423 eV
Let's reduce to J
E = 0.1423 eV (1.6 10⁻¹⁹ J / 1eV) = 0.2276 10⁻¹⁹ J
To find the wavelength of the transition, use the Planck relation
E = h f
the relationship of frequency and speed of light
c = λ f
we substitute
E = h c /λ
λ = hc / E
λ = 6.626 10⁻³⁴ 3 10⁸ / 0.2276 10⁻¹⁹
λ = 8.73374 10⁻⁶ m
λ = 8.73374 10⁻⁴ cm
Using the Bohr model what is the radius of the electron orbit in the Hydrogen atom when the electron is in the n = 10 state?
Answer:
r₁₀ = 52.9 nm
Explanation:
In Bohr's model of the hydrogen atom, the radius of the orbitals can be written as a function of the radius of the first orbit
rₙ = n² a₀
where ao is 0.0529 nm and is the radius of the ground state of the atom
the radius for the excited state with n = 10
r₁₀= 10² a₀
r₁₀ = 100 a₀
r₁₀ = 52.9 nm
What is the difference between
Dobereiner's triads and Newland's octaves
Answer:
Newlands law of octave was the first logically basis on the atomic weight. Demerits of dobereiner's triads system: - This system fails because it does not hold good for all the elements discovered till date time. It is limited to only few elements.
Explanation:
Which of the following is an SI unit
Answer:
liter is the SI unit
idk how to explain it
A 19.5-cm-diameter loop of wire is initially oriented perpendicular to a 1.8-T magnetic field. The loop is rotated so that its plane is parallel to the field direction in 0.22 s .
Required:
What is the average induced emf in the loop?
Given that,
Diameter of the loop, d = 19.5 cm
Magnetic field, B = 1.8 T
The loop is rotated so that its plane is parallel to the field direction in 0.22 s. We need to find the average induced emf in the loop.
When it is placed perpendicular to the magnetic field, angle between Area vector and Magnetic Field will be 0. Flus is BA.
When it is rotated so that its plane is parallel to the field direction, angle between Area vector and Magnetic Field will be 90. Flus is 0.
The induced emf is given by :
[tex]\epsilon=\dfrac{-d\phi}{dt}\\\\\epsilon=\dfrac{BA}{t}\\\\\epsilon=\dfrac{1.8\times \pi \times (19.5/2)^2}{0.22}\\\\\epsilon=2443.48\ V[/tex]
So, the average induced emf in the loop is 2443.48 volts.
An astronaut in an inertial reference frame measures a time interval Δt between her heartbeats. What will observers in all other inertial reference fr
Answer:
It will be more than deta t
Explanation:
Because
deta t' = န deta t
But န= 1/√ (1 - v²/c²
So the observers in all the initial frames will be more than deta t
A 1890 kg truck traveling north at 34 km/h turns east and accelerates to 62 km/h. (a) What is the change in the truck's kinetic energy
Answer:
2540.18 kJExplanation:
The change in the trucks kinetic energy is same as the net work done by the truck in covering the said distance
Given data
mass of truck m= 1890 kg
initial velocity of truck u1= 34 km/h
final velocity v1= 62 km/h
applying the kinetic energy formula we have
[tex]K.E= \frac{1}{2}mv^2[/tex]
K.E(initial)
[tex]K.E(initial)= \frac{1}{2}*1890*34^2\\\\ K.E(initial)= \frac{1}{2}*1890*1156\\\\ K.E(initial)= \frac{1}{2}*2184840\\\\ K.E(initial)= 1092420J\\\\\ K.E(initial)= 1092.4kJ[/tex]
K.E(final)
[tex]K.E(initial)= \frac{1}{2}*1890*62^2\\\\ K.E(initial)= \frac{1}{2}*1890*3844\\\\ K.E(initial)= \frac{1}{2}*7265160\\\\ K.E(initial)= 3632580J\\\\\ K.E(initial)= 3632.58kJ[/tex]
The change in K.E= K.E(final)- K.E(initial) = 3632.58-1092.4= 2540.18 kJ
the change in the truck's K.E is 2540.18 kJ
A 500-kilogram sports car accelerates uniformly from rest, reaching a speed of 30 meters per second in 6 seconds. During the 6 seconds, the car has traveled a distance of:_______
(A) 15 m
(B) 30 m
(C) 60 m
(D) 90 m
(E) 180 m
Answer:
90 m
Explanation:
Given that
Mass of the car, m = 500 kg
Initial speed of the car, u = 0 m/s
Final speed of the car, v = 30 m/s
Time taken to travel, t = 6 s
average speed v = (30 + 0) / 2 = 15
We are going to be using the most very basic equations to solve this.
speed can be defined as the ratio of distance with respect to time.
v = d/t, Where
v = speed.
d = distance travelled and
t = time taken
if we invert this, we can get that
d = v.t
distance is multiplication of speed and time. We will be using the average speed we calculated above, so
Distance travelled in 6 s,
d = 15 * 6
d = 90 m.
therefore, the distance travelled by the car in this 6 s is 90 m
The system is immersed in an environment with a constant high temperature T. What would be the energy expectation value of the system
Answer:
The energy value is expected to rise steadily until it is equal to a value that depends on the temperature T of the environment.
Explanation:
If a system is immersed into an environment with a constant high temperature, the temperature of the system will also rise until it comes to equilibrium with the temperature of the environment. When this happens, the energy expectation value of the system will now be dependent on the temperature of the environment. This means that the energy of the system will be a function of the temperature of the environment.
This means that
E = f(T)
where E is the energy value of the system
T is the temperature of the environment.
Physical Science questions that I need HELP ON
Answer:
7a. CO2 => carbon dioxide
b. H2O => water
8. The mass of carbon dioxide, CO2 plus the mass of water, H2O is equal to the mass of sugar, C6H12O6 plus the mass of oxygen, O2.
Explanation:
7. Selecting the names of the reactant.
6CO2 + 6H2O —> C6H12O6 + 6O2
From the above equation, the reactants are: CO2 and H2O
Thus, the names of the reactants are:
a. CO2 => carbon dioxide
b. H2O => water
8. Determination of masses of the CO2, H2O, C6H12O6 and O2 from the balanced equation. This can be obtained as follow:
6CO2 + 6H2O —> C6H12O6 + 6O2
Molar mass of CO2 = 12 + (2x16) = 44 g/mol
Mass of CO2 from the balanced equation = 6 x 44 = 264 g
Molar mass of H2O = (2x1) + 16 = 18 g/mol
Mass of H2O from the balanced equation = 6 x 18 = 108 g
Molar mass of C6H12O6 = (12x6) + (12x1) + (16x6) = 72 + 12 + 96 = 180 g/mol
Mass of C6H12O6 from the balanced equation = 1 x 180 = 180 g
Molar mass of O2 = 16x2 = 32 g/mol
Mass of O2 from the balanced equation = 6 x 32 = 192 g
Summary:
Mass of Reactant:
CO2 = 264 g
H2O = 108 g
Total = 372 g
Mass of Product:
C6H12O6 = 180 g
O2 = 192 g
Total = 372 g
From the above calculations,
The mass of carbon dioxide, CO2 plus the mass of water, H2O is equal to the mass of sugar, C6H12O6 plus the mass of oxygen, O2.
The potential energy U of an object of mass m that is separated by a distance R from an object of mass M is given by U= -GMm/RA. What is the kinetic energy K of the satellite?Express your answer in terms of the potential energy .
B. Find an expression for the square of the orbital period.
Answer:
A) K = ½ U / r , B) T² = (4π² / G M) r³
Explanation:
A) It asks us for the kinetic energy of the satellite and they give us the relation of the potential synergy
U = - G M m / r
the force can be found from this expression
F = - dU / dr
F = - G M m / r²
The kinetic energy is given by the formula
K = ½ m v²
let's use Newton's second law
F = m a
G M m / r² = m a
where the acceleration is centripetal
a = v² / r
G M r² = v² / r
v² = G M r³
we substitute the expression for the kinetic energy
K = ½ m v²
K = ½ m G M r³
in terms of potential energy is
K = ½ (G M m r²) 1 / r
K = ½ U / r
B) The period of the orbit
We write Newton's second law
G M m / r² = m a
a = v² / r
in a circular orbit the speed of the velocity is constant
v = d / t
the longitude of the orbit is
d = 2π r
v = 2π r / T
we substitute
G Mm / r² = m (2πr / T)² / r
G M / r³ = 4π² / T²
T² = (4π² / G M) r³
(A) The kinetic energy of satellite in terms of potential energy is,
K = 1/2 U / R.
(B) The expression for the square of the orbital period is,
T² = (4π² / G M) R³
Given data:
The potential energy of object is, U.
The mass of object is, m.
The distance from the other object of mass M is, R.
A.
The kinetic energy of the satellite and they give us the relation of the potential synergy,
U = - G M m / R
And the force can be found from this expression
F = - dU / dR
F = - G M m / R²
The kinetic energy is given by the formula
K = 1/2 m v²
Now use Newton's second law
F = m a
G M m / R² = m a
where the acceleration is centripetal
a = v² / R
G M R² = v² / R
v² = G M R³
we substitute the expression for the kinetic energy
K = 1/2 m v²
K = 1/2 m G M R³
in terms of potential energy is
K = 1/2 (G M m R²) 1 / R
K = 1/2 U / R
Thus, we can conclude that the kinetic energy of satellite in terms of potential energy is K = 1/2 U / R.
(B)
Now we need to obtain the period of the orbit of satellite. For that we write Newton's second law as
G M m / r² = m a
Since,
a = v² / r
In a circular orbit the speed is constant,
v = d / t
For the longitude of the orbit is
d = 2π R
v = 2π R / T
here,
T is the orbital period of satellite.
Substituting the values as,
G Mm / R² = m (2πR / T)² / R
G M / R³ = 4π² / T²
T² = (4π² / G M) R³
Thus, we can conclude that the expression for the square of the orbital period is T² = (4π² / G M) R³.
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A point charge Q moves on the x-axis in the positive direction with a speed of A point P is on the y-axis at The magnetic field produced at the point P, as the charge moves through the origin, is equal to What is the charge Q?
Answer: q = -52.5 μC
Explanation:
The complete question is given thus;
A point charge Q moves on the x-axis in the positive direction with a speed of 280 m/s. A point P is on the y-axis at y=+70mm. The magnetic field produced at the point P, as the charge moves through the origin, is equal to -0.30uTk. What is the charge Q? (uo=4pi x 10^-7 T m/A).
SOLVING:
from the given parameters we can solve this problem.
Given that the
Speed = 280 m/s
y = 70mm
B = -30 * 10⁻⁶T
Using the equation for magnetic field we have;
Β = μqv*r / 4πr²
making q (charge) the subject of formula we have that;
q = B * 4 *πr² / μqv*r
substituting the values gives us
q = (-0.3*10⁻⁶Tk * 4π * 0.07²) / (4π*10⁻⁷ * 280 ) = - [14.7 * 10⁻¹⁰k / 2.8 * 10⁻⁵ k ]
q = -52.5 μC
cheers i hope this helped !!!
The human eye is most sensitive to 560-nm (green) light. What is the temperature of a black body that would radiates most intensely at this wavelength
Given that,
Wavelength of the human light is 560 nm
To find,
The temperature of a black body that would radiates most intensely at this wavelength.
Solution,
The relation between temperature and the wavelength is given by :
[tex]\lambda=\dfrac{c}{T}[/tex]
T is temperature
c is [tex]2.898\times 10^{-3}\ m-K[/tex]
So,
[tex]T=\dfrac{c}{\lambda}\\\\T=\dfrac{2.898\times 10^{-3}}{560\times 10^{-9}}\\\\T=5175\ K[/tex]
So, the temperature of a black body that would radiates most intensely at this wavelength is 5175 K.
which formula is used to calculate average velocity?
The answer is:
the first oneThe formula to calculate average velocity is a) V (average ) = x(f) - x(i) /t(f) - t(i)
What is average velocity ?Average velocity is a vector quantity . It is defied as the change in displacement over a time interval .
Average velocity can be calculated as
Average velocity = change in displacement / change in time travel
correct answer is a) V (average ) = x(f) - x(i) /t(f) - t(i)
where
x(f) = final position
x(i) = initial position
t(f) = final time
t(i) = initial time
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Consider a conducting rod of length 34 cm moving along a pair of rails, and a magnetic field pointing perpendicular to the plane of the rails.
Required:
At what speed (in m/s) must the sliding rod move to produce an emf of 0.75V in a 1.75T field?
Answer:
v = 1.26 m/s
Explanation:
Given that,
Length of the conducting rods = 34 cm = 0.34 m
Magnetic field, B = 1.75 T
Induced emf is 0.75 V
we need to find the speed with which it slides. Due to the motion of the rod an emf is induced in it which is given by :
[tex]\epsilon=Blv[/tex]
v is the speed of rod
[tex]v=\dfrac{\epsilon}{Bl}\\\\v=\dfrac{0.75}{1.75\times 0.34}\\\\v=1.26\ m/s[/tex]
So, the speed of the sliding rod is 1.26 m/s.
These spectra are from the same element. Which is an emission spectrum, which an absorption spectrum?
A. Either could be emission (or absorption), depending on the conditions with which they were made.
B. Top is absorption; bottom emission.
C. Can't tell without knowing the element.
D. Top is emission; bottom absorption.
Answer:
D. Top is emission; bottom absorption.
Explanation:
Emission and spectrum of elements are due to the element absorbing or emitting wavelength of e-m energy. Elementary particles of elements can absorb energy from a ground state to enter an excited state, creating an absorption spectrum, or they can lose energy and fall back to a lower energy state, creating an emission spectrum. A simple rule to differentiate between an emission and an absorption spectrum is that: "all absorbed wavelength is emitted, but not all emitted wavelength is absorbed."
From the image, the lines indicates wavelengths. We can see that all of the wavelengths of the bottom absorption spectrum coincides with some of the wavelength of the upper emission wavelengths.
At what speed does a clock move if it is measured to run at a rate two-fifths the rate of a clock at rest with respect to an observer
Answer:
0.44c
Explanation:
We know that
Time interval at speed (ts)= time interval at rest(tr) / gamma
where
gamma = √[1-(v/c)²]
ts = tr / gamma
tr/ts = gamma
But
Ss/Sr = gamma
Where
Sr = clock speed at rest, Ss at speed):
So
√[1-(v/c)²] = 2/5
1 - (v/c)² = 4/25
(v/c)²= 5/25
v/c = √5 / 5
v = 0.444c
What is the difference between 103.5 and 102.24 written with the correct number of significant figures?What is the difference between 103.5 and 102.24 written with the correct number of significant figures?
Answer:
1.260
Explanation:
103.5 has 4 significant figures.
102.24 has 5 significant figures.
We will need to round the answer to the least number of significant figures available (in this case, 4).
103.5 − 102.24 = 1.26 = 1.260
The difference between 103.5 and 102.24 is equal to 1.3 in the correct number of significant figures.
What are significant figures?Significant figures can be utilized to produce numbers that can be written in the form of figures. We can determine the number of significant figures by simply counting the values starting from the first non-zero digit placed on the left.
We can calculate the number of significant digits by counting from the first non-zero figure placed on the left. The significant digits of a given number are those significant digits, which convey the meaning with respect to its accuracy.
In the case of division or multiplication or subtraction and addition, the number of significant figures must be the same as the value with the fewest significant figures.
We have to find the difference between 103.5 and 102.24:
103.5 - 102.24 = 1.26 = 1.3
The number 103.5 has one significant figure after the decimal. Therefore, the answer will be equal to 1.3.
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What is your hypothesis regarding difference in urine specific gravity between subjects who drank water and subjects who a drank sports drink
Answer:
Sports drink will show increase in specific gravity
While
Water will decrease in SG
Explanation:
This is because the relative density of urine will increase because of presence of ions in the sport drink unlike in water that has very little ions
The velocity time graph of a car shown below a) Calculate the magnitude of displacement of the car in 40 seconds. b) During which part of the journey was the car accelerating? c) Calculate the magnitude of average velocity of the car.
Answer:
a) 0 metres
b) From time 0 s to 10 s , the car was accelerated. Its velocity accelerated from 0m/s to 20 m/s
c) 20 m/s
Explanation:
a) Formula of displacement= velocity x time
time=40 s
velocity =0 m/s
∴ displacement= 0 x 40 = 0 m
Magnitude of displacement is 0 m
b) The increase in velocity shows that there has been acceleration.
c) The average velocity of the car is =[tex]\frac{0+40}{2\\}[/tex] {initial velocity + final velocity}
=[tex]\frac{40}{2}[/tex]
=20
Therefore, the magnitude of the average velocity of the car is 20 m/s
Planet Tatoone is about 1.7 AU from its Sun. Approximately how long will it take for light to travel from the Sun to Tatoone in minutes? Use 3 × 108 m/s for the speed of light.
Answer:
The value is [tex]t = 14.129 \ minutes[/tex]
Explanation:
From the question we are told that
The distance of planet Tatoone is [tex]d = 1.7 \ AU = 1.7 *1.496* 10^{11}=2.543*10^{11} \ m[/tex]
The speed of light is [tex]c = 3.0*10^{8} \ m/ s[/tex]
Generally the time taken is mathematically represented as
[tex]t = \frac{d}{c}[/tex]
=> [tex]t = \frac{2.543*10^{11}}{3.0*10^{8} }[/tex]
=> [tex]t = 847.7 \ s[/tex]
Now converting to minutes
[tex]t = \frac{847.7}{60}[/tex]
=> [tex]t = 14.129 \ minutes[/tex]