Answer:
Respuesta correcta, opción D: Es la fuerza que un cuerpo ejerce perpendicularmente sobre el área en la que actúa.
Explanation:
La definición de presión es la fuerza que un cuerpo ejerce en dirección perpendicular sobre el área en la que actúa.
Cuando se aplica una fuerza sobre la superficie de un cuerpo, la presión es la siguiente:
[tex] P = \frac{F}{A} [/tex]
En donde:
F es la fuerza aplicada.
A es el área del cuerpo.
Por lo tanto la opción correcta es la D: es la fuerza que un cuerpo ejerce perpendicularmente sobre el área en la que actúa.
Espero que se sea de utilidad!
1. How many inches are in 6 meters?
Answer:
236.22 inches
Explanation:
There are 39.3701 inches in 1 meter. So to find 6 meters, multiply 6 times 39.3701.
6·39.3701=236.22
Answer:
236.22
Explanation:
just because itit's common sense
lab safety test Safety goggles and an apron must be worn when handling chemicals labeled corrosive because they:________.
Answer:
The terms of biosafety in a laboratory require that the person must not have the eyes and skin exposed.
Explanation:
A corrosive substance is a substance that can damage a surface when they come into contact.
These substances represent a danger in people since they can burn the eyes, the skin, and the inside of the body since the inhalation of gases can burn the respiratory tract.
These chemical burns can be avoided by properly following the biosafety protocol that a laboratory requires the use of masks, goggles, gloves, and an apron or lab coat.
3. With a
you can measure just about anything.
Se lanza una bala con una velocidad inicial de 200 m/s y con un ángulo de inclinación de 30º respecto a la horizontal. Si se considera g=10 m/s2. ¿Cuál es el alcance de la bala?
Answer:
El alcance de la bala es 3464,1 m.
Explanation:
El alcance de la bala se puede calcular como sigue:
[tex]y = y_{0} + tan(\theta)*x - \frac{g}{2}*\frac{x^{2}}{(v_{0}cos(\theta))^{2}}[/tex]
En donde:
y: es la altura final = 0
[tex]y_{0}[/tex]: es la altura inicial = 0
x: es el alcance
θ: es el angulo respecto a la horizontal = 30°
[tex]v_{0}[/tex]: es la velocidad inicial = 200 m/s
g: es la gravedad = 10 m/s²
Entonces, tenemos:
[tex] y = y_{0} + tan(\theta)*x - \frac{g}{2}*\frac{x^{2}}{(v_{0}cos(\theta))^{2}} [/tex]
[tex] x = \frac{2tan(\theta)*(v_{0}cos(\theta))^{2}}{g} = \frac{2tan(30)*(200 m/s*cos(30))^{2}}{10 m/s^{2}} = 3464,1 m [/tex]
Por lo tanto, el alcance de la bala es 3464,1 m.
Espero que se te sea de utilidad!
A plane took 7 hours to travel 2020 km. For the first 4 hours,
it travelled at an average speed of 310 km/h. What was the
average speed for the remaining time of the journey?
km/h
Answer:
260
Explanation:
The average speed for the remaining time of the journey is 260 km/h.
What is average speed?The average speed of any moving object is the ratio of the total distance covered and the total time taken to cover that distance.
Given is a plane took 7 hours to travel 2020 km. For the first 4 hours,
it travelled at an average speed of 310 km/h.
Average Speed S1= distance /time
310 km/h = d/4
d = 1240 km
The remaining distance will be
2020 - 1240 = 780 km
The remaining hours are 7 - 4 =3 h
The average speed for the remaining distance is
Avg speed S2= 780 / 3
S2 = 260 km/h
Thus, the average speed of the car for the remaining is 260 km/h.
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Part B – Scientific Method
READ THIS STORY AND ANSWER THE QUESTIONS:
Joe baked a cake for his mother's birthday. When he removed the cake from the oven, Joe noticed that the cake had not risen. Joe guessed that the baking powder he had used was too old. He designed the following experiment to test his idea.
Joe prepared two cakes – one using the same ingredients as his first cake and one using fresh baking powder. After preheating the oven to 350°F, he placed both cakes in the oven for 30 minutes. After 30 minutes, he removed both cakes and noticed that neither one had risen. He decided that the baking powder wasn’t the cause of his problem.
What is Joe's hypothesis?
What is Joe's conclusion?
What did Joe’s observe?
What was the independent variable in Joe’s experiment?
What was the dependent variable in Joe’s experiment?
What was the control in Joe’s experiment?
What were the constants in Joe’s experiment (assuming he did it correctly)?
8. Based on his conclusion, what should Joe do next?
Answer:
1) Joe's hypothesis was that the baking powder he used was too old and that was why the cake did not rise
2) Joe concluded that the baking powder was not the cause of the cake not rising
3) Joe observed that the cake he made for his mother's birthday did not rise
4) The independent variable was the baking powder
5) The dependent variable was the rising cake
6) Joe's control in the experiment was the extra cake made using the same ingredient as the first
7) The constants were the heat and time to bake both cakes
8) He should recheck all the variables and constants (recipes and procedures) are correct as can be found in baking books
Explanation:
Answer: Please find the answers in the explanation
Explanation:
From the given description, when Joe noticed that the cake had not risen, he guessed that the baking powder he had used was too old.
Hypothesis is one of the scientific methods which means guessing.
What is Joe's hypothesis?
Joe's hypothesis is that the baking power used was not effective to make the cake rise believing that it was too old.
After Joe prepared two cakes, one using the same ingredients as his first cake and one using fresh baking powder. After preheating the oven to 350°F, he placed both cakes in the oven for 30 minutes. After 30 minutes, he removed both cakes and noticed that neither one had risen. He decided that the baking powder wasn’t the cause of his problem.
What is Joe's conclusion?
The conclusion is that the inability for the cake to rise wasn't as a result of ineffectiveness of the baking powder used.
What did Joe’s observe?
Joe observed that the cake had not risen.
What was the independent variable in Joe’s experiment?
The independent variable determines the dependent variable.
The independent variable is therefore, the different types of baking powder used.
What was the dependent variable in Joe’s experiment?
The dependent variable is the volume of the cakes.
What was the control in Joe’s experiment?
Joe was able to control the time and the temperature.
What were the constants in Joe’s experiment (assuming he did it correctly)?
The constant were the quantities of the cake ingredient, time used, and the temperature
8. Based on his conclusion, what should Joe do next?
Joe can try another ingredient like yeast or reconsider the ratio of the baking powder to the flour.
Which statement best describes the similarities between fundamental forces? a Electromagnetic and strong nuclear forces influence the interaction between charged particles within an atom. b Gravitational and magnetic forces are the most alike because they are both types of charges that occur in nature. c Nuclear and magnetic forces are the most alike because they are both related to mass and weight. d Strong nuclear force is most like electrical force because they are both related to distance.
Answer:
a
Explanation:
............
..............option A
Answer:
A is the answer as electromagnetic and strong nuclear forces influence the interaction between charged particles within an atom the only difference being their intensity! Hope this helps :) and if you dont mind, mark me brainliest so i can get to the next rank :(
Two students are watching a person riding a skateboard up and down a ramp. Each student shares what they think about the energy of the skateboarder as they ride up and down the ramp.
Elisa: I think the skateboarder has the more total energy at the top bottom of the ramp than the bottom of the ramp.
Raymond: I think the skateboarder has the same total energy at all points on the ramp.
Which student do you agree with? Why?
Answer:
The correct option is;
Raymond: I think the skateboarder has the same total energy at all points on the ramp
Explanation:
The total energy, also known as the total mechanical energy, is the sum of the kinetic and potential energies of the skateboarder
Given that the potential energy is the energy gained due to elevation, the maximum potential energy is obtained at the top of the ramp, while the maximum kinetic energy, which is the energy due to motion, is at the bottom of the ramp where the skateboarder moves fastest.
However, by the energy conservation principle, the kinetic energy of he skateboarder comes from the conversion of the potential energy, such that the total energy is the same at any particular point on the ramp.
Which of these item(s) are NOT mentioned in Stuff Matters? Leather Shoes Microphones Candles Jet Engine Teacup
Answer:
Leather Shoes, Microphones, Candles
Explanation:
Surprisingly, leather Shoes, Microphones, Candles were not mentioned in Stuff Matters a book written by Mark Miodownik which according to him explored "the marvelous things that shape our man-made world."
a child hits a ball with a force of 350 N. (a) If the ball and bat are in contact for 0.12 is, what impulse does the ball receive? (b) what is its change in momentum?
Explanation:
Given that,
Force with which a child hits a ball is 350 N
Time of contact is 0.12 s
We need to find the impulse received by the ball. The impulse delivered is given by :
[tex]J=F\times t\\\\J=350\times 0.12\\\\J=42\ N-m[/tex]
So, the impulse is 42 N-m..
We know that he change in momentum is also equal to the impulse delivered.
So, impulse = 42 N-m and change in momentum =42 N-m.
Solve the following numerical problems. a) A load of 400N is liſted up by an effort of 100N. If load distance is 20cm, what will be the effort distance? (Ans 80cm)
Answer:
Solution
Load(L)=400
Effort(E)=100
Load distance (Ld)=20cm
Effort distance(Ed)=?
Now,from the principle of equilibrium
L×Ld=E×Ed
or,Ed=L×Ld/E
or,Ed=400×20/100
:.Ed=80cm and
Therefore,the effort distance will be 80cm
Answer:
80cm
Explanation:
load l = 400
Effort e = 100
load distance Ld = 20
Effort distance Ed = ?
L×ld= E×Ed
Ed=L×Ld \ E
Ed=400×20/100
Ed=80cm Ans
If an object on a horizontal frictionless surface is attached to a spring, displaced, and then released, it will oscillate. If it is displaced a distance 0.110 m from its equilibrium position and released with zero initial speed. Then after a time 0.815 s its displacement is found to be a distance 0.110 m on the opposite side, and it has passed the equilibrium position once during this interval.
Find (a) the amplitude; (b) the period; (c) the frequency.
a)The amplitude of the wave will be 0.120m.
b)The period of the wave will be 1.60s.
What is the frequency?Frequency is defined as the number of repetitions of a wave occurring waves in 1 second.
a)The amplitude of the wave will be 0.120m.
A is the initial displacement =0.120m
The amplitude represents the largest deviation from equilibrium. So that the amplitude of the wave will be equal to the maximum position.
Hence the amplitude of the wave will be 0.120m.
b)The period of the wave will be 1.60s.
The movement from maximum positive displacement to maximum negative displacement. The time period will be;
[tex]\rm \frac{T}{2} = 0.800 \\\\\ T= 1.6 \ sec[/tex]
Hence the period of the wave will be 1.60s.
c) The frequency of the wave will be 0.625Hz.
The frequency is inversely proportional to the time period. Frequency is found as;
[tex]\rm f=\frac{1}{T} \\\\ \rm f=\frac{1}{0.625} \\\\ \rm f=0.625 \ Hz[/tex]
Hence the frequency of the wave will be 0.625Hz.
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Simple Harmonic Motion: A simple harmonic oscillator oscillates with frequency f when its amplitude is A. If the amplitude is now doubled to 2A, what is the new frequency
Answer:
The frequency will still remain F
Explanation:
Firstly, we should remember that the frequency of a simple harmonic oscillator doesn't depend on the amplitude. Rather, it depends on the spring constant, k, and the mass of the attached weight, m. This means that the change in amplitude will not lead to a corresponding change in frequency.
the frequency is represented by the formula
f = 1/2π * √(k/m),
where
f = frequency of the oscillator
k = spring constant and
m = mass attached to the spring
From the formula above, we can state that the frequency doesn't depend on the amplitude at all, and as such, the amplitude changing from A to 2A, will effect no change in the frequency F.
What subatomic particle identified this atom
Answer:
protons
Explanation:
the protons identifies an atoms as that of a particular element the atomic number is equal to the number of protons in the nucleus of an atom
7. Una locomotora de 80.000 kilogramos de masa, parte del reposo y a los 10 segundos lleva una velocidad de 36Km/h. Halla: A. La aceleración del movimiento. B. La fuerza que causa el movimiento.
Answer:
a) La aceleración del movimiento es 1 metros por segundo al cuadrado, b) La fuerza que causa el movimiento es 80.000 newtons.
Explanation:
a) Supóngase que la locomotora acelera uniformemente, la aceleración se está descrita por la siguiente ecuación cinemática:
[tex]v = v_{o}+a\cdot t[/tex]
Donde:
[tex]v_{o}[/tex] - Rapidez inicial, medida en metros por segundo.
[tex]v[/tex] - Rapidez final, medida en metros por segundo.
[tex]a[/tex] - Aceleración, medida en metros por segundo al cuadrado.
[tex]t[/tex] - Tiempo, medido en segundos.
Se despeja la aceleración:
[tex]a = \frac{v-v_{o}}{t}[/tex]
Si [tex]v_{o} = 0\,\frac{m}{s}[/tex], [tex]v = 10\,\frac{m}{s}[/tex] y [tex]t = 10\,s[/tex], la aceleración del movimiento es:
[tex]a = \frac{10\,\frac{m}{s}-0\,\frac{m}{s}}{10\,s}[/tex]
[tex]a = 1\,\frac{m}{s^{2}}[/tex]
La aceleración del movimiento es 1 metros por segundo al cuadrado.
b) Dado que una locomotora es un sistema de masa constante, la fuerza ([tex]F[/tex]) que genera el movimiento es igual a:
[tex]F = m\cdot a[/tex]
Donde:
[tex]m[/tex] - Masa, medida en kilogramos.
[tex]a[/tex] - Aceleración, medida en metros por segundo al cuadrado.
Dados que [tex]m = 80.000\,kg[/tex] y [tex]a = 1\,\frac{m}{s^{2}}[/tex], la fuerza que causa el movimiento es:
[tex]F = (80.000\,kg)\cdot \left(1\,\frac{m}{s^{2}} \right)[/tex]
[tex]F = 80.000\,N[/tex]
La fuerza que causa el movimiento es 80.000 newtons.
which phrase describes what a scientist does? A.Tells People how they should behave B .Answers ethical questions C. Ask questions about the world D. Determines right from wrong
Answer:
C. Ask questions about the world
Explanation:
A scientist is a person who conducts scientific research and provide scientific proves on the area of their interest such as physica, chemistry, biology or history.
A scientist gives the answers of the question about the world based on their scietifc research such as how does plant breath? effects of global warming on earth? what if we don't drink water for a particular time period? et-cetera.
Hence, the correct option is "C. Ask questions about the world".
A cement block accidentally falls from rest from the ledge of a 55.9-m-high building. When the block is 11.2 m above the ground, a man, 1.70 m tall, looks up and notices that the block is directly above him. How much time, at most, does the man have to get out of the way?
Answer:
0.3 seconds approximately
Explanation:
Given that the height of the building is 55.9 m and cement block accidentally falls from rest from the edge of a 55.9-m-high building. The initial velocity of the block will be equal to zero. The final velocity will be achieved by using the formula:
V^2 = U^2 + 2gH
Where g = 9.8 m/s^2
H = 55.9m
V^2 = 0 + 2 × 9.8 × 55.9
V^2 = 1095.64
V = sqrt(1095.64)
V = 33.1 m/s
The velocity When the block is 11.2 m above the ground will be 33.1 m/s and the height h = 11.2 - 1.7 = 9.5 m
The time of escape can be calculated by using the formula;
h = Ut + 1/2gt^2
9.5 = 33.1t + 1/2 × 9.8 × t^2
9.5 = 33.1t + 4.9t^2
4.9t^2 + 33.1t - 9.5
By using quadratic formula to calculate the time, the negative value is ignored and the positive values will be the time the man has to get out of the way.
Please find the attached file for the remaining solution.
What are the balanced forces for someone in a parachute? A. Gravity and Earth B. Gravity and air resistance C. Gravity and centripetal D. Centripetal and air resistance
Answer:
B. Gravity and air resistance
Explanation:
Experimentation has proven that :
When the parachute opens, air resistance becomes much greater than gravity. The forces are no longer balanced and this changes the
speed
Answer:
[tex]\large \boxed{\mathrm{B. \ Gravity \ and \ air \ resistance}}[/tex]
Explanation:
Gravity and air resistance are the forces that get balanced out during a free fall. This is also known as terminal velocity, when gravity = air resistance.
You are out on the water in foggy conditions. You hear one prolonged blast plus two short blasts every two minutes. What does this sound signal mean?
The sound signal helps to caution and let other people know the exact
position or location during sailing in limited visibility conditions.
Sailors are in which charge of controlling and movement of ships. In limited
visibility conditions such as during fogs, one prolonged blast plus two short
blasts every two minutes are done.
This helps to alert people and other sailors of their location at sea to prevent
accidents and death.
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The sound signal helps to know the exact location during sailing in foggy conditions.
Who are sailors?
Sailors are the in charge of controlling and movement of ships. In limited visibility conditions such as fogs, one prolonged blast plus two short blasts every two minutes are done.
This helps to caution people and other sailors around their location at the sea to prevent accidents and death.
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Consider three widely separated galaxies in an expanding universe. Imagine that you are located in galaxy 1 and observe that both galaxies 2 and 3 are moving away from you. If you asked an observer in galaxy 3 to describe how galaxy 2 appears to move, what would he or she say?
Answer:
The observer will say that galaxy 2 is moving away from galaxy 3 where he stands.
Explanation:
Since the galaxies are expanding, each one would move away from the others. Observers on all three galaxies have their frame of reference fixed on their own galaxies. Judging from their own galaxies, each observer will perceive the other galaxies moving away from his/or galaxy.
The observer at galaxy 3 will talk about galaxy 2 by doing is; he will say that galaxy 2 is moving far from him.
We are told that the universe is expanding and as such, the galaxies would be expanding and moving away from each other.
Since the galaxies are expanding, it means that they will be moving away from each other.
From time dilation principle, an observer at galaxy 3 will say that galaxy 2 is moving far from him.
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Find the density of a substance that has a volume of 754 cm3 and a mass of 7,917 grams. Don't forget your units!
Answer:
[tex] \boxed{\sf Density \ of \ the \ substance = 10.5 \ g/cm^3} [/tex]
Given:
Mass (M) = 7917 grams
Volume (V)= 754 cm³
To Find:
Density of the substance
Explanation:
[tex] \boxed{ \bold{\sf Density \ (\rho) = \frac{Mass \: (M)}{Volume \: (V)}}}[/tex]
Substituting values of M & V in the equation:
[tex] \sf \implies \rho = \frac{7917}{754} [/tex]
[tex]\sf \implies \rho = 10.5 \: g/ {cm}^{3} [/tex]
A train starts from rest with acceleration of 0.5ms-2 find speed in Kmh-1 when it moved through 100m. (36kmh-1)
Answer:
36km/h
Explanation:
since the acceleration of the train was 0.5m/s² i.e it is constant . since the acceleration is constant you can use one of the "SUVAT" equations to find the answer.
the equation that best fits this question is: v²=u² + 2āS.
v stands for final velocity
u stands for intial velocity
v²=u² + 2āS since the car started from rest the intial velocity is zero.
v²=u² + 2āS
v²= 0 + 2(0.5m/s²)*100m
v²= 1m/s²*100m
√v²=√100m²/s²
v=10m/s
1km/hr = 1/3.6m/s
x. = 10m/s.
use criss cross method to find the value of x
x=( 1km/hr* 10m/s)
1/3.6m/s
x= 36km/hr
Help plssssss asap:(((
Answer:
5 blocks south
Explanation:
Answer:
5 blocks south
Explanation:
She ran 8 block south, then 3 blocks north.
8 - 3 = 5.
What is the standard unit for time
standerd unit of time is second
Answer:
The standard unit for time is second (s).
an object is placed at a distance of 10cm from a convex mirror of focal length 15 cm find the position and nature of the image
Answer:
[tex]\boxed{\sf Position \ of \ the \ image = 6 \ cm}[/tex]
[tex]\boxed{\sf Nature \ of \ the \ image = Virtual \ and \ Erect}[/tex]
Given:
Object distance (u) = -10 cm
Focal length (f) = 15 cm
To Find:
Image distance (v) and nature of the image
Explanation:
Mirror Formula:
[tex]\boxed{\bold{\sf \frac{1}{v} + \frac{1}{u} = \frac{1}{f}}}[/tex]
Substituting values of u and f in the equation:
[tex]\sf \implies \frac{1}{v} -\frac{1}{10} =\frac{1}{15}[/tex]
[tex]\sf \implies \frac{1}{v}=\frac{1}{15} +\frac{1}{10}[/tex]
[tex]\sf \implies \frac{1}{v}=\frac{2}{30}+\frac{3}{30}[/tex]
[tex]\sf \implies \frac{1}{v}=\frac{2+3}{30}[/tex]
[tex]\sf \implies \frac{1}{v}=\frac{5}{30}[/tex]
[tex]\sf \implies v=\frac{30}{5}[/tex]
[tex]\sf \implies v=6 \ cm[/tex]
[tex]\therefore[/tex]
Image distance (v) = 6 cm
Nature of the image = Virtual and Erect
To expel hot air out of the kitchen, A has an exhaust fan fitted on the window of her kitchen and B has a similar exhaust fan fitted on the wall near the ceiling of the kitchen. Which one of the exhaust fan will expel the hot air more effectively? Explain why.
Answer:
Kitchen B
Explanation:
This all boils Down to the phenomenon of convection current of àir where warmer air rises up and is replaced by cooler air, the fan is placed higher up in B and because hot air rises higher up it will remove more hot air here
What is the net force on an object that is experiencing a force of 25 N north, a force of 25 N
south, a force of 50 N to the east and a force of 45 N to the west?
Answer:
net 5N of force will act in east direction.
Explanation:
force acting in North and South direction will cancel each other.
force in east direction - force in west direction = 5N
I WILL GIVE BRAINLIEST!! :) The value of the total current is: A. 3.5A B. 4.0 A C. 4.5A D. 5.0 A
Answer:
Option C. 4.5 A
Explanation:
We'll begin by calculating the equivalent resistance of R1 and R3. This can be obtained as follow:
R1 = 6 Ω
R3 = 3 Ω
Equivalent of R1 and R3 =?
Since R1 and R3 are in parallel connections, we shall their equivalence as follow:
Equivalent of R1 and R3 = (R1×R3) /(R1 + R3)
Equivalent of R1 and R3 = (6×3)/(6+3)
Equivalent of R1 and R3 = 18/9
Equivalent of R1 and R3 = 2 Ω
Next, we shall determine the equivalent resistance in the circuit.
This is illustrated below:
R2 = 2 Ω
Equivalent of R1 and R3 = 2 Ω
Equivalent resistance (R) in the circuit =?
Note: Equivalent of R1 and R3 is in series connection with R2.
Equivalent Resistance (R) = (Equivalent of R1 and R3) + R2
Equivalent Resistance (R) = 2 + 2
Equivalent Resistance (R) = 4 Ω
Finally, we shall determine the total current in the circuit as follow:
Potential difference (V) = 18 V
Equivalent Resistance (R) = 4 Ω
Current (I) =.?
From ohm's:
V = IR
Where V is the potential difference.
I is the current.
R is the resistance.
V = IR
18 = I × 4
Divide both side by 4
I = 18/4
I = 4.5 A
Therefore, the total current in the circuit is 4.5 A.
(b) The table below shows the mass and volume of four objects.
object
mass (g)
volume (cm)
aluminium figure
230
85
lead weight
800
70
steel block
200
25
wood puzzle
400
500
(i) Which object is the heaviest? *
Tour answer
Answer:
I think lead is the heaviest one
The radius of a small ball is around 2.8436 cm. The radius of a basketball is about 4.22 times larger. What is the ratio of the surface areas of the small ball and a basketball? Part 2 What is the ratio of their volumes?
help please
Answer:
Explanation:
Both small ball and a basketball are in form of a sphere. Total surface area of a sphere is gotten using the formula;
surface area of a sphere S = 4πr²
If the radius of a small ball is around 2.8436 cm, its total surface area will be:
S = 4π(2.8436)²
S =4π(8.086)
S = 101.61 cm²
If the radius of a basketball is about 4.22 times larger, the radius will be 4 times larger as well. The radius of the basket ball = 4.22*2.8436
radius of thr basketball = 11.99cm
Surface area of the basketball S2 = 4π(11.99)²
S2 =4π(143.76)
S2 =1806.54cm²
The ratio of the surface areas of the small ball and a basketball S:S2
S:S2 = 101.61 cm² : 1806.54cm²
S:S2 = 0.0562
Hence, the ratio of the surface areas of the small ball and a basketball is approximately 0.0562.
2) The volume of a sphere = 4/3πr³
Volume of the small ball = 4/3π(2.8436)³
Volume of the small ball = 4/3 π * 22.994
Volume of the small ball= 96.315cm³
Similarly;
Volume of the basketball = 4/3π(11.99)³
Volume of the small ball = 4/3 π * 1723.68
Volume of the small ball= 7220.14cm³
The ratio of the volume of the small ball and a basketball V:V2
V:V2 = 96.315 : 7220.14
V:V2 = 0.01333
Hence, the ratio of the volumes of the small ball and a basketball is approximately 0.01333