The triangles are similar by:
the ASA similarity theorem.
the SSS similarity theorem.
the AAS similarity theorem.
the AA similarity postulate.
the SAS similarity theorem.

Answer:

(3 × 3) - (3 ÷ 3) = 8

Step-by-step explanation:

We want to find an expression that when solved will be equal to 8.

But we are restricted to using only the number "3" four times with any Maths operation.

Thus let's try;

(3 × 3) - (3 ÷ 3) = 9 - 1 = 8

Answer:

A. (1, -5), (2, -1), (-1, 7)

Step-by-step explanation:

Reflecting a function over the x-axis:

When a function is reflected over the x-axis, the x-value stays the same, while y changes the signal, so the transformation rule is:

[tex](x,y) \rightarrow (x,-y)[/tex]

To find the range:

We apply the transformation to the points in the domain. Thus:

[tex](1,5) \rightarrow (1,-5)[/tex]

[tex](2,1) \rightarrow (2,-1)[/tex]

[tex](-1,-7) \rightarrow (-1,-(-7)) = (-1, 7)[/tex]

Thus the correct answer is given by option a.

Answer:

It is letter A and please give me brainliest

Step-by-step explanation:

Answer:

[tex]x=-1\text{ or }x=11[/tex]

Step-by-step explanation:

For [tex]a=|b|[/tex], we have two cases:

[tex]\begin{cases}a=b,\\a=-b\end{cases}[/tex]

Therefore, for [tex]18=|15-3x|[/tex], we have the following cases:

[tex]\begin{cases}18=15-3x,\\18=-(15-3x)\end{cases}[/tex]

Solving, we have:

[tex]\begin{cases}18=15-3x, -3x=3, x=\boxed{-1},\\18=-(15-3x), 18=-15+3x, 33=3x, x=\boxed{11}\end{cases}[/tex].

Therefore,

[tex]\implies \boxed{x=-1\text{ or }x=11}[/tex]

9514 1404 393

Answer:

  44°

Step-by-step explanation:

The sum of the marked angles on the right is equal to the sum of the marked angles on the left:

  ? + 74 = 92 + 26

  ? = 92 +26 -74 = 44

The missing angle is 44°.

_____

Additional comment

The vertical angles in the center of the figure are v = 62°, the measure required to bring the total to 180° in each triangle. We have shortcut the equation(s) ...

  ? + 74 + v = 180 = 92 + 26 + v

by subtracting v from both sides, giving ...

  ? +74 = 92 +26

Answer:

30 minutes

Step-by-step explanation:

that problem description is imprecise.

I think what is meant here : they each keep jogging at their own same speed.

Diane's speed is 1/3 miles / 10 min.

Jack's speed is 2/3 miles / 10 min.

now, to bring this to regular miles/hour format, we need to find the factor between 10 minutes and an hour (60 minutes) and multiply numerator and denominator (top and bottom of the ratio) by it.

60/10 = 6.

so, we need to multiply both speeds up there by 6/6 to get the miles/hour speeds.

Diane : (1/3 × 6) / hour = 2 miles / hour

Jack : (2/3 × 6) / hour = 4 miles / hour

since Jack is running twice as fast as Diane, she will finish one length in the same time he finishes a round trip (back and forth).

Diane running 1 mile going 2 miles/hour takes her 30 minutes.

Jack running 2 miles (back and forth) going 4 miles/hour will take him also 30 minutes.

so, they will meet at his starting point after 30 minutes.

Answer:

[tex](a)\ m = \frac{4}{3}[/tex] --- slope of OA

[tex](b)\ y = \frac{4}{3}x[/tex] --- the equation

Step-by-step explanation:

Given

The attached graph

Solving (a): Slope of OA

First, we identify two points on OA

[tex](x_1,y_1) = (0,0)[/tex]

[tex](x_2,y_2) = (3,4)[/tex]

So, the slope (m) is:

[tex]m = \frac{y_2 -y_1}{x_2 - x_1}[/tex]

This gives:

[tex]m = \frac{4-0}{3-0}[/tex]

[tex]m = \frac{4}{3}[/tex]

Solving (b): The equation

This is calculated as:

[tex]y = m(x - x_1) + y_1[/tex]

Recall that:

[tex](x_1,y_1) = (0,0)[/tex]

[tex]m = \frac{4}{3}[/tex]

So, we have:

[tex]y = \frac{4}{3}(x - 0) + 0[/tex]

[tex]y = \frac{4}{3}(x)[/tex]

[tex]y = \frac{4}{3}x[/tex]

Answer:

[tex]\lim_{(x,y) \to (0,0)} \frac{x^2 \sin^2y}{x^2+2y^2} = 0[/tex]

Step-by-step explanation:

Given

[tex]f(x,y) = \frac{x^2 \sin^2y}{x^2+2y^2}[/tex]

Required

[tex]\lim_{(x,y) \to (0,0)} f(x,y)[/tex]

[tex]\lim_{(x,y) \to (0,0)} f(x,y)[/tex] becomes

[tex]\lim_{(x,y) \to (0,0)} \frac{x^2 \sin^2y}{x^2+2y^2}[/tex]

Multiply by 1

[tex]\lim_{(x,y) \to (0,0)} \frac{x^2 \sin^2y}{x^2+2y^2}\cdot 1[/tex]

Express 1 as

[tex]\frac{y^2}{y^2} = 1[/tex]

So, the expression becomes:

[tex]\lim_{(x,y) \to (0,0)} \frac{x^2 \sin^2y}{x^2+2y^2} \cdot \frac{y^2}{y^2}[/tex]

Rewrite as:

[tex]\lim_{(x,y) \to (0,0)} \frac{x^2 y^2}{x^2+2y^2} \cdot \frac{\sin^2y}{y^2}[/tex]

In limits:

[tex]\lim_{(x,y) \to (0,0)} \frac{\sin^2y}{y^2} \to 1[/tex]

So, we have:

[tex]\lim_{(x,y) \to (0,0)} \frac{x^2 y^2}{x^2+2y^2} *1[/tex]

[tex]\lim_{(x,y) \to (0,0)} \frac{x^2 y^2}{x^2+2y^2}[/tex]

Convert to polar coordinates; such that:

[tex]x = r\cos\theta;\ \ y = r\sin\theta;[/tex]

So, we have:

[tex]\lim_{(x,y) \to (0,0)} \frac{(r\cos\theta)^2 (r\sin\theta;)^2}{(r\cos\theta)^2+2(r\sin\theta;)^2}[/tex]

Expand

[tex]\lim_{(x,y) \to (0,0)} \frac{r^4\cos^2\theta\sin^2\theta}{r^2\cos^2\theta+2r^2\sin^2\theta}[/tex]

Factor out [tex]r^2[/tex]

[tex]\lim_{(x,y) \to (0,0)} \frac{r^4\cos^2\theta\sin^2\theta}{r^2(\cos^2\theta+2\sin^2\theta)}[/tex]

Cancel out [tex]r^2[/tex]

[tex]\lim_{(x,y) \to (0,0)} \frac{r^2\cos^2\theta\sin^2\theta}{\cos^2\theta+2\sin^2\theta}[/tex]

[tex]\lim_{(x,y) \to (0,0)} \frac{r^2\cos^2\theta\sin^2\theta}{\cos^2\theta+2\sin^2\theta}[/tex]

Express [tex]2\sin^2 \theta[/tex] as [tex]\sin^2\theta+\sin^2\theta[/tex]

So:

[tex]\lim_{(x,y) \to (0,0)} \frac{r^2\cos^2\theta\sin^2\theta}{\cos^2\theta+\sin^2\theta+\sin^2\theta}[/tex]

In trigonometry:

[tex]\cos^2\theta + \sin^2\theta = 1[/tex]

So, we have:

[tex]\lim_{(x,y) \to (0,0)} \frac{r^2\cos^2\theta\sin^2\theta}{1+\sin^2\theta}[/tex]

Evaluate the limits by substituting 0 for r

[tex]\frac{0^2 \cdot \cos^2\theta\sin^2\theta}{1+\sin^2\theta}[/tex]

[tex]\frac{0 \cdot \cos^2\theta\sin^2\theta}{1+\sin^2\theta}[/tex]

[tex]\frac{0}{1+\sin^2\theta}[/tex]

Since the denominator is non-zero; Then, the expression becomes 0 i.e.

[tex]\frac{0}{1+\sin^2\theta} = 0[/tex]

So,

[tex]\lim_{(x,y) \to (0,0)} \frac{x^2 \sin^2y}{x^2+2y^2} = 0[/tex]

Answer:

y - 2 = 2/3 (x-1)

y - 4 = 2/3(x-4)

Step-by-step explanation:

With this graph,the equation can be found on a straight line as the graph is .

So the formula is

[tex]y - y1 = m(x - x1)[/tex]

where your m is your gradient or slope as already said,the equation can be used by this formula (note;after finding your normal slope (not on a straight line ) firstly)

When you are done take any of the points connecting to the x axis and y axis directly as in (4,-4) or (2,1)

Let your first number be x1 and second y1 and place it in the formula .

where m is still your normal slope.

Answer:

Total earning last month with x articles is:

This is same amount as 2000

The equation is:

Answer:

-73, -71, -69

Step-by-step explanation:

Suppose the middle of the 3 integers is x.

(x-2)+(x)+(x+2)=-213

x-2+x+x+2=-213

3x=-213

x=-71

The integers are -69, -71, and -73

Answer:

-73,-71,-69

Step-by-step explanation:

Let x represent an odd interger

Odd intergers are serpated by the value of 2 so let the three consective intergers be represented by

[tex](x )+ (x + 2) +( x + 4)[/tex]

Set that equation equal to 213.

[tex]x + x + 2 + x + 4 = - 213[/tex]

[tex]3x + 6 = - 213[/tex]

[tex]3x = - 219[/tex]

[tex]x = - 73[/tex]

Plug -73 in the consective intergers expression.

[tex] - 73 + ( - 73 + 2) + ( - 73 + 4)[/tex]

So our three intergers are

[tex] - 73[/tex]

[tex] - 71[/tex]

[tex] - 69[/tex]

Answer:

The right solution is "0.5".

Step-by-step explanation:

According to the question,

P(pay with the sponsored credit card | order exceeds $110)

= [tex]\frac{P(Pay \ with \ the \ sponsored \ credit\ card\ and\ order\ exceeds\ 110)}{P(order \ exceeds \ 110)}[/tex]

= [tex]\frac{P(A \ and \ B)}{P(A)}[/tex]

By putting the values, we get

= [tex]\frac{0.17}{0.34}[/tex]

= [tex]0.5[/tex]

Thus, the above is the right solution.

Explanation:

There are 8 different flavors and 3 types of cones. This means there are 8*3 = 24 different combos possible.

Imagine a table with 8 rows and 3 columns. Each row is a different flavor and each column is a different cone type. The table formed has 24 inner cells to represent a different combination of flavor + cone type. So that's why we multiplied those values earlier.

Note: This only works if you're only able to select one type of flavor.

Division yields

[tex]\dfrac{x^4+7}{x^3+2x} = x-\dfrac{2x^2-7}{x^3+2x}[/tex]

Now for partial fractions: you're looking for constants a, b, and c such that

[tex]\dfrac{2x^2-7}{x(x^2+2)} = \dfrac ax + \dfrac{bx+c}{x^2+2}[/tex]

[tex]\implies 2x^2 - 7 = a(x^2+2) + (bx+c)x = (a+b)x^2+cx + 2a[/tex]

which gives a + b = 2, c = 0, and 2a = -7, so that a = -7/2 and b = 11/2. Then

[tex]\dfrac{2x^2-7}{x(x^2+2)} = -\dfrac7{2x} + \dfrac{11x}{2(x^2+2)}[/tex]

Now, in the integral we get

[tex]\displaystyle\int\frac{x^4+7}{x^3+2x}\,\mathrm dx = \int\left(x+\frac7{2x} - \frac{11x}{2(x^2+2)}\right)\,\mathrm dx[/tex]

The first two terms are trivial to integrate. For the third, substitute y = x ² + 2 and dy = 2x dx to get

[tex]\displaystyle \int x\,\mathrm dx + \frac72\int\frac{\mathrm dx}x - \frac{11}4 \int\frac{\mathrm dy}y \\\\ =\displaystyle \frac{x^2}2+\frac72\ln|x|-\frac{11}4\ln|y| + C \\\\ =\displaystyle \boxed{\frac{x^2}2 + \frac72\ln|x| - \frac{11}4 \ln(x^2+2) + C}[/tex]

Answer:

6x = 180

x = 30

Step-by-step explanation:

Answer:

y = x + 6

Step-by-step explanation:

rise = 1

run = 1

slope = rise/run = 1

y-intercept = 6

y = mx + b

y = x + 6

Answer:

I think you have a type.. "the seventh number must be a 1"

there are no 1's in the original set of numbers

Step-by-step explanation:

Answer:

19.14

Step-by-step explanation:

You have a half circle and a square, look at them separate then add for the area.

Circle

Your radius is half the diameter, so 4/2

Radius  = 2

[tex]A = 3.14 * radius\\A = 3.14 * 2\\A = 6.28[/tex]

This is for the entire circle, half of that would be 3.14

Square

[tex]A = 4^{2} \\A = 16[/tex]

Add them both together for a total area of 19.14 square miles

Answer:

0.2

Step-by-step explanation:

The total number of points in PS is a sum of the number of points in :

PQ + QR + RS ;

PQ = 7 ; QR = 13 ; RS = 5

PS = (7 + 13 + 5) = 25

Probability that point selected at random is in RS ;

Required outcome = point in RS

Total possible outcomes = points in PS

Probability = RS / PS = 5 / 25 = 0.2

Step-by-step explanation:

I suspect we don't see the full information for the problem here.

all listed 3 methods are typically used to prove that triangles are congruent (= when turned to have the same orientation, they would simply cover each other completely - no overhanging parts from either triangle).

I guess there is a diagram with 2 triangles and what is known about them.

and since we cannot see them, we cannot tell you which method would apply here.

just remember

SSS means all 3 sides of one triangle are exactly the same as the 3 sides of the other triangle. if you know the lengths of all 3 sides, there is only one triangle you can create. you can only orient it differently.

SAS means two sides and the enclosed angle are the same. again, only one triangle can be created with that information.

ASA means one side and the 2 angles at the end points of that side are known. again, only one triangle can be created with that information.

Answer:

c

Step-by-step explanation:

when we take the 5 inside the root the 5 vil be 5^2 times 2 which is equal to 50

Answer:

pixxer

Step-by-step explanation:

please pick inside please

Answer:

I dont now

Step-by-step explanation:

plz conprendation

Answer:

Step-by-step explanation:

Answer:

[tex]\displaystyle V = \frac{176 \pi}{15}[/tex]

General Formulas and Concepts:

Pre-Algebra

Algebra I

Calculus

Integrals

Integration Rule [Reverse Power Rule]:                                                                  [tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]

Integration Rule [Fundamental Theorem of Calculus 1]:                                        [tex]\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)[/tex]

Integration Property [Multiplied Constant]:                                                              [tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]

Integration Property [Addition/Subtraction]:                                                           [tex]\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx[/tex]

Shell Method:

[tex]\displaystyle V = 2\pi \int\limits^b_a {xf(x)} \, dx[/tex]

Step-by-step explanation:

Step 1: Define

Identify

Graph of region

y = x²

x = 2

y = 4

Axis of Revolution: y = -1

Step 2: Sort

We are revolving around a horizontal line.

Step 3: Find Volume Pt. 1

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Applications of Integration

Book: College Calculus 10e

Answer:

6

Step-by-step explanation:

Answer:

89.6 miles

Step-by-step explanation:

[tex]\frac{8}{5}[/tex] = [tex]\frac{x}{56}[/tex]

5x = 448

x=89.6

Step-by-step explanation:

if 8km=5

x =56km

5x=8×56

5x=448

x=89.6 miles

Answer:

Random sample, [tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex], so yes, both conditions were satisfied.

Step-by-step explanation:

60% of the people in a certain midwest city who are responsible for preparing the evening meal have no idea what they are going to prepare as late as 4PM in the afternoon.

This means that [tex]p = 0.6[/tex]

A recent survey was conducted from 1000 of these individuals.

This means that [tex]n = 1000[/tex]

Also, a random sample, so the first condition was satisfied.

The sample size must be large (so that at least 10 or more successes and failures).

[tex]np = 1000*0.6 = 600 \geq 10[/tex]

[tex]n(1-p) = 1000*0.4 = 400 \geq 10[/tex]

So yes, both conditions were met.

Answer:

the scores on her last test is x (x > 0)

because on her last tests she scored 4 points lower than she did on her fifth test

=> the scores in the 5th test is x + 4

because Angela’s average for six math tests is 87, we have:

[tex] \frac{93 + 87 + 82 + 86 + x + x + 4}{6} = 87 \\ \\ < = > \frac{352 + 2x}{6} = 87 \\ \\ < = > 352 + 2x = 522 \\ \\ < = > 2x = 170 \\ \\ < = > x = 85[/tex]

=> on her last test, she had 85

=> on her 5th test, she had 85 + 4 = 89

Answer:

(4, 2 )

Step-by-step explanation:

Given the 2 equations

3x + y = 14 → (1)

7x - 4y = 20 → (2)

Rearrange (1) making y the subject by subtracting 3x from both sides

y = 14 - 3x → (3)

Substitute y = 14 - 3x into (2)

7x - 4(14 - 3x) = 20 ← distribute parenthesis and simplify left side

7x - 56 + 12x = 20

19x - 56 = 20 ( add 56 to both sides )

19x = 76 ( divide both sides by 19 )

x = 4

Substitute x = 4 into (3) for corresponding value of y

y = 14 - 3(4) = 14 - 12 = 2

solution is (4, 2 )

Answer:

[tex]3x + y = 14 \\ y = 14 - 3x \\ substitute \: y \: into \: equation \: 2\\ 7x - 4(14 - 3x) = 20 \\ 7x - 56 + 12x = 20 \\ 19x = 76 \\ x = \frac{76}{19} =4 \\ y = 14 - 3( 4 ) = 2 \\ [/tex]