Answer:
pf = 3750000 kg.m/s
F = 175000 N
Explanation:
Constant Acceleration
An object moves with constant acceleration if its velocity changes uniformly in time.
If we call vo to the initial speed, vf the final speed, and t the time, then the acceleration is calculated as:
[tex]\displaystyle a=\frac{v_f-v_o}{t}[/tex]
The new stealth helicopter was traveling at vo=180m/s and changed to vf=250 m/s in t=6 seconds, thus the acceleration was:
[tex]\displaystyle a=\frac{250-180}{6}[/tex]
[tex]a=11.67~m/s^2[/tex]
Please note this number is shown rounded to the nearest hundredth, but it was stored in the calculator's memory with full precision. This fact affects the next calculation as will be noted below.
The acceleration must be produced for some net force that can be calculated by:
F = m.a
Where m=15000 Kg is the mass of the helicopter. Thus:
F = 15000 * 11.67
F = 175000 N
The above product would lead to the inaccurate result of 175050 if the acceleration would have not used with its full representation in the calculator's memory.
The momentum of an object of mass m and velocity v is:
p = m. v
The final momentum of the helicopter is:
pf = m.vf = 15000*250 m/s
pf = 3750000 kg.m/s
Note: When performing calculations over intermediate results, it's important to keep them as accurate as possible to preserve the accuracy of the final result.
A film of soapy water ( n= 1.33 ) on top of a plastic cutting board has a thickness of 233 nm. What color is most strongly reflected if it is illuminated perpendicular to its surface?
Answer:
620nm
Explanation:
According to the question,
Refractive index, n = 1.33Thickness, t = 233 nmAs we know,
→ [tex]t = \frac{\lambda}{2n}[/tex]
or,
→ [tex]\lambda = 2tn[/tex]
By putting the values, we get
[tex]= 2\times 233\times 10^{-9}\times 1.33[/tex]
[tex]= 620 \ nm[/tex]
Thus the above response is correct.
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What is the ratio of the radii of curvature for a proton and an an electron traveling through this apparatus
Answer:
hello your question is incomplete below is the missing part of the question
Consider an experimental setup where charged particles (electrons or protons) are first accelerated by an electric field and then injected into a region of constant magnetic field with a field strength of 0.55 T.
answer : ≈ 42
Explanation:
Ratio of the Radii of curvature for a proton and an electron travelling through this apparatus
= [tex]\frac{Rp}{Re}[/tex] = 0.025 m / 5.94 * 10^-4 m = 42.08
Rp = 0.025 m ( calculated )
Re = 5.94 * 10^-4 ( calculated )
it is rate for any motion to
a. stay the same for very long
b. change quickly
c. increase in velocity
d. decrease in speed
Answer:
a. stay the same for very long
Explanation:
It is rare for any motion to stay the same for a very long time. The force applied on a body causes changes in the magnitude of motion.
For motion to remain constant, there must not be a net force acting on the body All the forces on the body must be balanced. This is very hard to come by. Motion changes very frequently.Freida wants to model the way atoms move when a substance changes its state. To do this, Freida makes a pyramid of marshmallows. Then, she knocked down the pyramid causing the marshmallows to fall. If the marshmallows represent the atoms in the substance, which change of state is Freida modeling?
Answer:melting 2020 edge
Explanation:
:)
Answer:
Melting
Explanation:
When Danny Diver who weighs 500 N steps off a diving board 10 m above the water, he hits the water with kinetic energy of
Answer:
5000 J
Explanation:
Given that,
Weight of Danny Diver, F = 500 N
He steps off a diving board 10 m above the water
We need to find the kinetic energy of the water with which it hits. Let its is K. It is given by :
E = mgh
Where g is acceleration due to gravity
[tex]E=500\ N\times 10\ m\\\\=5000\ J[/tex]
So, he hits the water with kinetic energy of 5000 J.
Why would a baseball traveling at 20 m/s have more kinetic energy than a baseball traveling at 5 m/s?
Answer:
because formula of kinetic energy is K=1/2mv^2 that means more the velocity then more kinetic energy
which of the following require that you also state direction
A. speed
B. displacement
C. acceleration
D. instantaneous speed
SCIENCE QUESTION FOR 20 POINTS
Answer:
d
Explanation:
Which describes an interaction in which organisms work together so that all organisms in the group benefit? cooperation parasitism commensalism competition
Answer:
Cooperation
Explanation:
Cooperation: Both organisms benefit in the relationship.
Parasitism: One organism benefits and the other is harmed in this relationship.
Commensalism: One organism benefits, while the other neither benefits of is harmed.
Competition: Organisms compete for resources.
The option that describes an interaction in which organisms work together so that all organisms in the group benefit is known as Cooperation.
What is Species interaction?Species interaction may be defined as a type of process through which the population of one species interacts with the population of other species that significantly lives in the same locality. This process either benefits or harm the population.
The categories of species interaction are as follows:
Cooperation: It is a type of +,+ interaction where both organisms benefit in the relationship. This is also known as mutualism. Parasitism: It is a type of +,- interaction where one organism benefits and the other is harmed. Commensalism: It is a type of +,0 interaction where one organism benefits, while the other neither benefits nor is harmed.Competition: It is a type of -,- interaction where both organisms are harmed and compete for the same resources.Therefore, the option that describes an interaction in which organisms work together so that all organisms in the group benefit is known as Cooperation.
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A toy rocket is launched straight up by using a spring. The rocket is initially pressed down on the spring so that the spring is compressed by 9 cm. If the spring constant is 830 N/m and the mass of the rocket is 50 g, how high will the rocket fly?
Answer:
6.86 meters
Explanation:
Let the compression of the string be represented by x, and the height of projection of the toy rocket be represented by h.
So that;
x = 9 cm = 0.09 m
In its rest position (i.e before the launch), the spring has a stored potential energy which is given as;
PE = [tex]\frac{1}{2}[/tex] K[tex]x^{2}[/tex]
= [tex]\frac{1}{2}[/tex] x 830 x [tex](0.09)^{2}[/tex]
= 415 x 0.0081
= 3.3615
The potential energy in the string = 3.36 Joules
Also,
PE = mgh
where: m is the mass, g is the gravitational force and h the height.
m = 50 g = 0.05 kg, g = 9.8 m[tex]s^{-2}[/tex]
Thus,
PE = 0.05 x 9.8 x h
3.3615 = 0.05 x 9.8 x h
3.3615 = 0.49h
⇒ h = [tex]\frac{3.3615}{0.49}[/tex]
= 6.8602
The height of the toy rocket would be 6.86 meters.
From the 1780s to the late 1800s, people thought the amount of land and resources in the West was limited
Answer:true
Explanation:
in the one pulley system when you move the Mass from The 20-centimeter Mark to the 15 centimeter mark it moves to my 5cm how far did you pull the string?
5 cm
10cm
15cm
20cm
Answer:
5 cm
Explanation:
Remember that in the pulley system the rope moves the same distance in both ends of the pulley, what the pulley system does is creating a mechanical advantage which basically means that it takes less effort to pull than the actual effort it would take, so for example if you have to lift a box that is 800 N, with a pulley system and the mechanical advantage you'd have to pull with less force.
How much energy is transported across a 1.25 cm2 area per hour by an EM wave whose E field has an rms strength of 38.5 mV/m
Answer:
The energy transported per hour is 4.92 x 10⁻¹⁰ J.
Explanation:
Given;
root mean square strength of the field, [tex]E_{rms}[/tex] = 38.5 mV/m
area per hour, A = 1.25 cm²/hr = 1.25 x 10⁻⁴ m²/hr
The peak strength of the field is given by;
E₀ = [tex]E_{rms}[/tex]√2
E₀ = (38.5 mV)√2
E₀ = 54.45 mV
the average intensity is given by;
[tex]I_{avg} = \frac{c\epsilon E_o^2}{2}\\\\ I_{avg} = \frac{(3*10^8)(8.85*10^{-12})(54.45*10^{-3})^2}{2}\\\\I_{avg} = 3.936*10^{-6} \ W/m^2[/tex]
Energy transported per hour is given by;
[tex]E = \frac{P}{t} = \frac{I*A}{t} = (\frac{A}{t})(I)\\\\E = (1.25*10^{-4} \ \frac{m^2}{hr} )(3.936*10^{-6} \ \frac{W}{m^2} )\\\\E = 4.92*10^{-10} \ J[/tex]
Therefore, the energy transported per hour is 4.92 x 10⁻¹⁰ J.
A 0.106-A current is charging a capacitor that has square plates 4.60 cm on each side. The plate separation is 4.00 mm.
(a) Find the time rate of change of electric flux between the plates in V·m/s
(b) Find the displacement current between the plates in A
Answer:
a
[tex]\frac{d \phi_{E}}{dt} =1.1977 *10^{10} \ V\cdot m/s[/tex]
b
[tex]I = 0.106 \ A[/tex]
Explanation:
From the question we are told that
The current is [tex]I = 0.106 \ A[/tex]
The length of one side of the square [tex]a = 4.60 \ cm = 0.046 \ m[/tex]
The separation between the plate is [tex]d = 4.0 mm = 0.004 \ m[/tex]
Generally electric flux is mathematically represented as
[tex]\phi_E = \frac{Q}{\epsilon_o}[/tex]
differentiating both sides with respect to t is
[tex]\frac{d \phi_{E}}{dt} = \frac{1}{\epsilon_o} * \frac{d Q}{ dt}[/tex]
=> [tex]\frac{d \phi_{E}}{dt} = \frac{1}{\epsilon_o} *I[/tex]
Here [tex]\epsilon_o[/tex] is the permitivity of free space with value
[tex]\epsilon _o = 8.85*10^{-12} C/(V \cdot m)[/tex]
=> [tex]\frac{d \phi_{E}}{dt} = \frac{0.106}{8.85*10^{-12}}[/tex]
=> [tex]\frac{d \phi_{E}}{dt} =1.1977 *10^{10} \ V\cdot m/s[/tex]
Generally the displacement current between the plates in A
[tex]I = 8.85*10^{-12} * 1.1977 *10^{10}[/tex]
=> [tex]I = 0.106 \ A[/tex]
Need help with this physics question!
A baseball is hit straight up at 60 m/s. At 9 seconds what is the displacement, the acceleration and velocity?
Answer:
Acceleration: -9.8 m/s^2
Velocity: -28.2 m/s
Displacement: 143.1 m
Explanation:
The acceleration of gravity for any object close to earth is approximately -9.8 m/s^2.
Now, to find the velocity after 9 seconds, we can use a kinematics formula, where x is the final velocity:
Final Velocity = Initial Velocity + Acceleration * Time
x = 60 + -9.8*9
x = 60 - 88.2
x = -28.2
The velocity is -28.2 m/s.
Lastly, to find the displacement, we can use another kinematics formula, where y is the displacement:
Displacement = (Final Velocity + Initial Velocity)/2 * Time
y = (-28.2 + 60)/2 * 9
y = 143.1
The displacement is 143.1 meters.
When a person wearing a helmet rides a bicycle, the helmet experiences which type of friction?
A. Fluid
B. Static
C. Sliding
D. Rolling
Answer:
B
Explanation:
Answer:
B.)Static
Hope I helped
A 56 kg woman climbs the stairs to a height of 5 m. Determine: a) what mechanical work
she performed; b) what work the woman will do when climbing the stairs and carrying a 5 kg load.
Answer:
a) W = 2746.8[J]
b) W = 2992.05 [J]
Explanation:
Work is defined as the product of force by distance. We must bear in mind that the force that performs the work is the one that acts in the same direction of displacement.
For this case, we must calculate the weight of the woman, the weight is defined as the product of mass by gravity.
[tex]w=m*g\\[/tex]
where:
w = weight [N] (units of Newtons]
m = mass = 56 [kg]
g = gravity acceleration = 9.81 [m/s²]
[tex]w=56*9.81\\w=549.36[N][/tex]
a)
[tex]W=F*d[/tex]
where:
F = weight = 549.36[N]
d = distance = 5 [m]
[tex]W = 549.36*5\\W = 2746.8[J][/tex]
b)
The new mass will be the combination of the mass of the woman plus that of the load.
[tex]m_{new} = 56+5\\m_{new}=61[kg][/tex]
[tex]w_{new}=61*9.81\\w_{new}=598.41[N][/tex]
The new work done.
[tex]W =598.41*5\\W=2992.05[J][/tex]
A bag of groceries has a weight of 44 Newton’s. Find it’s mass in kilograms
Answer:
It's mass would be 4.486768kg..
5. A man has a weight of 100 Newtons. How much work is done if he climbs 4 meters up a ladder? Plug numbers under the equation. Solve and circle your answer. Include the proper units.
Answer:
400 JExplanation:
The work done by an object can be found by using the formula
workdone = force × distance
From the question we have
workdone = 100 × 4
We have the final answer as
400 JHope this helps you
A dog walks 24 steps north and then walks 55 steps west to bury a bone. If the dog walks back to the starting point in a straight line, how many steps will the dog take and in which direction will the dog walk? On paper, use the graphical method to find the magnitude of the net displacement.
Answer:
The dog should walk 60 steps to the southeast to return to its starting point.
Explanation:
To solve the present mathematical problem, we must use the Pythagorean theorem. This establishes that in right triangles the sum of their squared legs is equal to the hypotenuse squared, that is:
A ^ 2 + B ^ 2 = X ^ 2
Thus, in the case, the calculation would be the following:
24 ^ 2 + 55 ^ 2 = X ^ 2
576 + 3,025 = X ^ 2
√3,601 = X
60 = X
Therefore, the dog should walk 60 steps to the southeast to return to its starting point.
Selection
boy throws a 1.2 kg ball straight up at 12 m/s. How high does the ball go? 1 point
(Answer to two digits)
Answer:
69
Explanation:
The earth rotates every 86,160 seconds. What is the tangential speed (in m/s) at Livermore (Latitude 37.6819° measured up from equator, Longitude 121.
Answer:
The tangential speed at Livermore is approximately 284.001 meters per second.
Explanation:
Let suppose that the Earth rotates at constant speed, the tangential speed ([tex]v[/tex]), measured in meters per second, at Livermore (37.6819º N, 121º W) is determined by the following expression:
[tex]v = \left(\frac{2\pi}{\Delta t}\right)\cdot R \cdot \sin \phi[/tex] (1)
Where:
[tex]\Delta t[/tex] - Rotation time, measured in seconds.
[tex]R[/tex] - Radius of the Earth, measured in meters.
[tex]\phi[/tex] - Latitude of the city above the Equator, measured in sexagesimal degrees.
If we know that [tex]\Delta t = 86160\,s[/tex], [tex]R = 6.371\times 10^{6}\,m[/tex] and [tex]\phi = 37.6819^{\circ}[/tex], then the tangential speed at Livermore is:
[tex]v = \left(\frac{2\pi}{86160\,s} \right)\cdot (6.371\times 10^{6}\,m)\cdot \sin 37.6819^{\circ}[/tex]
[tex]v\approx 284.001\,\frac{m}{s}[/tex]
The tangential speed at Livermore is approximately 284.001 meters per second.
a sample of steam at 15 bar pressure and 400°c temperature is first expanded at a constant enthalpy to 6 bar and then expanded isentropically where the dryness fraction of the steam is 0.90. find the change of enthalpy, the pressure of isentropically expanded steam and change of entropy.
Answer:
Answer.
Explanation:
Explanation.
What is the approximate efficiency of the engine?
A heat engine has a temperature of 1800 K. Some of the
heat from the engine flows to the surroundings, which
are at a temperature of 160 K.
0 16%
O 91%
O 103%
O 109%
Answer:91% I think
Explanation:
The typical engine efficiency for a modern petrol combustion engine is from 20 to 30 percent. The remaining 70 to 80 percent of the heat energy of the petrol is released from the engine as friction loss, mechanical sound energy, or exhaust heat. Thus, option B is correct.
What approximate efficiency of the engine?An engine's efficiency is measured by the heat produced divided by the amount of useful work done. Is the task complete. Is the task finished. Please be aware that the phrase “work done” refers to the force applied to the clutch or driveshaft.
Utilizing the following formula, efficiency may be represented as a ratio: output input. Output, often called work output, is the entire quantity of productive work completed, excluding waste and spoilage.
You may determine the efficiency by figuring out what proportion of the energy input results in the desired output: Efficiency is defined as Energy Out/Energy In 100%.
Therefore, This implies that the work produced by thermodynamic expansion is reduced by the friction and other losses.
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I need the answer asap thank you !!!
Answer:
whats the question??????
Each mass in the figure is 3 kg. Find the magnitude and direction of the net gravitational force on mass A due to the other masses.
A. 2.45 × 10–7 N toward B
B. 3.75 × 10–7 N toward C
C. 2.00 × 10–7 N toward D
D. 1.15 × 10–7 N toward D
Answer:
THE ANSER IS B
Explanation:
The magnitude and direction of the net gravitational force on mass A due to the other masses is 1.15 × 10⁻⁷ N toward D.
The gravitational force between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. In this case, all of the masses are equal to 3 kg, and the distance between mass A and mass D is 3 m.
The gravitational force between mass A and mass D is therefore:
F = G * m_A * m_D / r²
= 6.674 × 10⁻¹¹ N m² / kg² * 3 kg * 3 kg / 3 m²
= 1.15 × 10⁻⁷ N
The direction of the gravitational force is towards mass D.
Therefore, the net gravitational force on mass A due to the other masses is 1.15 × 10⁻⁷ N toward D.
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A car is traveling at 15 m/sm/s . Part A How fast would the car need to go to double its kinetic energy
Answer:
21.21 m/s
Explanation:
Let KE₁ represent the initial kinetic energy.
Let v₁ represent the initial velocity.
Let KE₂ represent the final kinetic energy.
Let v₂ represent the final velocity.
Next, the data obtained from the question:
Initial velocity (v₁) = 15 m/s
Initial kinetic Energy (KE₁) = E
Final final energy (KE₂) = double the initial kinetic energy = 2E
Final velocity (v₂) =?
Thus, the velocity (v₂) with which the car we travel in order to double it's kinetic energy can be obtained as follow:
KE = ½mv²
NOTE: Mass (m) = constant (since we are considering the same car)
KE₁/v₁² = KE₂/v₂²
E /15² = 2E/v₂²
E/225 = 2E/v₂²
Cross multiply
E × v₂² = 225 × 2E
E × v₂² = 450E
Divide both side by E
v₂² = 450E /E
v₂² = 450
Take the square root of both side.
v₂ = √450
v₂ = 21.21 m/s
Therefore, the car will travel at 21.21 m/s in order to double it's kinetic energy.
For the car to be able to double its kinetic energy, it would need to travel at a speed of approximately 21.21m/s.
Given the data in the question;
Speed of the car; [tex]v_1 = 15m/s[/tex]
Speed for the car to double its kinetic energy; [tex]v_2 = \ ?[/tex]
Using the expression for kinetic energy:
[tex]K_E = \frac{1}{2}mv^2[/tex]
Where m is the mass and v is the velocity
Now, Initial Kinetic Energy will be;
[tex]K_E_1 = \frac{1}{2}mv_1^2 \\\\K_E_1 = \frac{1}{2}*m*(15)^2\\\\K_E_1 = \frac{1}{2}*m*225\\\\K_E_1 = 112.5*m[/tex]
For the kinetic energy to become double
[tex]K_E_2 = 2 * K_E_1\\\\\frac{1}{2}mv_2^2 = 2 * ( 112.5 * m)\\\\\frac{1}{2}mv_2^2 = 2m( 112.5)\\\\v_2^2 = 4( 112.5)\\\\v_2^2 = 450\\\\v_2 = \sqrt{450}\\\\v_2 = 21.21m/s[/tex]
Therefore, for the car to be able to double its kinetic energy, it would need to travel at a speed of approximately 21.21m/s.
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An astronaut with mass 84kg is at rest in space, before firing her water pack to move toward the shuttle. If the amount of water shot out is
2kg and it is fired at a speed of 10m/s, what will the speed of the astronaut be?
Answer:
The astronaut is moving at a speed of 0.238 m/s in a direction opposite the direction of the water shot out.
Explanation:
We are given;
Mass of astronaut; m1 = 84 kg
Mass of water shoot out; m2 = 2 kg
Initial speed of astronaut; u1 = 0 m/s
Initial speed of water shoot out; u2 = 0 m/s
Final speed of shoot out; v2 = 10 m/s
From law of conservation of momentum, we can say that;
Initial momentum = final momentum
Thus;
m1•u1 + m2•u2 = m1•v1 + m2•v2
Where v1 is the final speed of the astronaut
Plugging in the relevant values, we get;
(84 × 0) + (2 × 0) = (84 × v1) + (2 × 10)
0 = 84v1 + 20
-20 = 84v1
v1 = -20/84
v1 = -0.238 m/s
The negative sign indicates that the astronaut is moving 0.238 m/s in a direction opposite the direction of the water shot out.
Now write a short paragraph comparing "fast" to "speeding up quickly" and "slow" to "speeding up slowly".
Answer:ok yes
Explanation:yes of course
A local AM radio station broadcasts at a frequency of 627 kHz. Calculate the wavelength at which it is broadcasting. Wavelength
Answer:
Wavelength = 478.46 m
Explanation:
It is given that,
A local AM radio station broadcasts at a frequency of 627 kHz, f = 627000 Hz
We need to find the wavelength at which it is broadcasting. The wavelength is given by :
[tex]\lambda=\dfrac{c}{f}\\\\=\dfrac{3\times 10^8}{627\times 10^3}\\\\=478.46\ m[/tex]
So, the wavelength is 478.46 m.
In a two-dimensional Cartesian system, the x-component of a vector is known, and the angle between vector and x-axis is known. Which operation is used to calculate the magnitude of the vector?
a. dividing by cosine
b. dividing by sine
c. multiplying by cosine
d. multiplying by sine