The following circuit diagram is partially incomplete. A device is added to the electrical circuit to vary the current in Lamp 2 only. Which of the following circuit symbols should be included in the diagram to represent this device?

Answer:produces red and white blood cells

Explanation: the bone marrow helps with the blood but cannot produce red and white blood cells

Answer:

"prevents movement of limbs and digits" is NOT a function of the skeletal system.

The correct option for the problem is option D. they reach the bottom together. Their gravitational potential energy is converted to kinetic energy, total energy will be conserved for the system and we can safely say they will reach the bottom together without considering their shape.

Here sphere and cylinder both have equal mass and equal radius and it is given that both are simultaneously released also.

When two objects with equal mass and equal radius like these two, the time taken for them to roll down and reach the bottom will be their gravitational potential energy.

Here what happens is that their gravitational potential energy is converted to kinetic-energy and both of them rolling down the incline.

Total energy will be conserved for the system and we can safely say they will reach the bottom together without considering their shape.

Inertia and rotational energy are also there in this context for their motion but they do not take part any role for the time taken to slide down.

Instead, they affect the stability and trajectory of the objects as they roll down the incline.

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The definition of horsepower is . A. the amount of force used to cover the length of an English associated activities track B. the practical benefit of utilizing a standard horse

Who developed the horsepower?

James Watt, an engineer, is credited with creating the term horsepower. According to legend, Watt wanted to find a method to describe the power that one of those animals could produce while he was dealing with ponies in a coal mine. An engine is connected to a dynamometer in order to determine its horsepower.

What is the power of a horse?

The most prevalent unit of power is horsepower , which measures how quickly work is completed. According to the British Imperial Units, a horsepower is equivalent to 33,000 walking of work per minute, or the force required to elevate a mass of 3 million pounds one foot in a minute.

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Answer:

130.34 m/s²

Explanation:

see attachment

hope this helps!

The tension in the cord will be 6.99 N. To solve this problem we will refer to the laws of Mersenne. Mersenne's laws are regulations relating to the frequency of oscillation of a stretched string or monochord, helpful in musical tuning and musical instrument building.

This law suggests that the velocity in a string is directly proportional to the root of the applied tension and inversely proportional to the root of the linear density, that is,

v = √T/μ

Here,

v = Velocity

μ = Linear density ( mass per unit length)

T = Tension

Rearranging to find the Period we have that

T = v²μ

T = v²(m/L)

As we know that speed is equal to displacement in a unit of time, we will have to

T = (L/t)² (m/L)

T = (7.3/0.72)² (0.50/7.3)

T = 6.99 N

Therefore, the tension in the cord will be 6.99 N.

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a. The mass is doubled = 4 s

b. The string length is doubled= 5.66 s

c. The string length is halved=2.83 s

d.The amplitude is doubled= 4 s

(a) The period of the pendulum is independent of the mass, therefore, the period when the mass is doubled is

T= To =4.00s

(b) Let I be the new length of the pendulum and Lo be the original length of the pendulum. The period of the pendulum if the string length is doubled is found by substituting 2Lo for L in Equation (*):

2π=√2Lo/g

√2=(2π(√Lo/g)

where the term in parenthesis is the original period of the pendulum To:

T=√√2To

T=√2.(4seconds)

T=5.66 s

c) The period of the pendulum if the string length is halved is found by substituting Lo/2 for L in Equation (*):

T=2π(√Lo/2 :g)

T= 1/√2 (2π√(Lo/g)

where the term in parenthesis is the original period of the pendulum To:

T =To /√2

T=4.00s/√2

T=2.83 s

d.) The period of the pendulum is independent of the amplitude, therefore, the period when the amplitude is halved is

T= To 4.00s

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Answer:

-11.29 m

Explanation:

The length of the incline can be calculated using the following formula:

L = (Vf^2 - Vi^2) / (2 * a)

where:

L = length of incline

Vf = final speed (15 m/s)

Vi = initial speed (2 m/s)

a = acceleration due to gravity (9.8 m/s^2 on the surface of the Earth)

Since the skier is going downhill, the acceleration is negative.

Substituting the given values into the formula:

L = (15^2 - 2^2) / (2 * -9.8)

L = (225 - 4) / -19.6

L = 221 / -19.6

L = -11.29 m

So the length of the incline is approximately -11.29 meters. This negative value indicates that the skier's final position is lower than the starting position.

When the car reaches 7 m it has a kinetic energy of 14364 J and a terminal velocity of 4.67 m/s.

Speed defines the direction in which a body or object is moving. Speed is primarily a scalar quantity. Velocity is basically a vector quantity. Rate of change of distance. Rate of change of displacement.

(a) The rate of change of displacement is known as velocity. It can be calculated by finding the ratio of displacement and total required time. The SI unit for velocity is "m/s", just like velocity.

The work done by the forward force is:

W1 = F1d = 1143 N × 7 m = 8001 J The work done by the second force is:

W2 = F2d = 909 N x 7 m = 6363 J The net work done on the car is the sum of the following he two works.

[tex]\mathrm{W_{net}}[/tex] = W1 + W2 = 8001 J + 6363 J = 14364 J According to the work energy principle, the net work done in a car is equal to the change in its kinetic energy.

[tex]\mathrm{W_{net}}[/tex] = ΔK where ΔK is the change in kinetic energy. Since the car starts from a standing start, the initial kinetic energy is 0, so ΔK equals the final kinetic energy. So it looks like this:

[tex]\mathrm{W_{net}}[/tex] = 14364 J Finally, we can convert this energy to Joules using the following formula:

1 J = 1 kg m²/s²

So it looks like this:

K = 14364 J = (2.2 × 10³ kg) × v² where v is the final velocity of the car. Solving for v gives:

v = √(K / (2.2 × 10³ kg))

= √(14364 J / (2.2 × 10³ kg))

= 4.67 m/s

So when the car reaches 7 m it has a kinetic energy of 14364 J and a terminal velocity of 4.67 m/s.

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The amount of work done by the applied force on the skier is 500 J.

The amount of work done by the applied force on the skier is calculated by applying the following equation as shown below.

W = Fd

where;

The amount of work done by the applied force on the skier is calculated as;

W = (25 N ) x ( 20 m )

W = 500 J

Thus, the work done by a force is defined to be the product of component of the force in the direction of the displacement and the magnitude of this displacement.

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The velocity of the football that is thrown by Felipe to Lilah will be 23 km per hour.

The movement of an object in relation to another observer is known as its relative velocity. It is the pace at which one object's relative location changes in relation to another object over time.

Felipe is riding his skateboard toward Lilah at 15 km/h. He throws a football to Lilah. The football is thrown at 8 km/h.

Then the velocity of the ball is given as,

v = 15 + 8

v = 23 km/h

The velocity of the ball will be 23 km / h.

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A) Motion 1: The car starts at rest at the stop sign, at x=0, and then accelerates in the east (positive x) direction.

Acceleration is the rate of change of an object's velocity over time. It is a vector quantity, meaning that it has both magnitude and direction. Acceleration is usually measured in meters per second squared (m/s2). It is a fundamental concept in physics, and is used to describe the motion of objects in a variety of contexts, from astronomy to everyday life. Acceleration can result from a force, from a change in direction, or from a change in speed.

The correct position vs time graph for this motion is a line with a positive slope, starting at the origin and going up to the right. This shows that the car is accelerating in the positive x direction and is increasing its position over time.

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(a) Normalization factor for wavefunction 1 is, [tex]A = \sqrt{\dfrac{3^3}{{(16\pi a^5)}}[/tex], for wavefunction 2 is, [tex]B = \sqrt{\dfrac{15}{16\pi a^5}}[/tex]. The two wavefunctions are mutually orthogonal. (b) The expectation value of r for [tex]\psi_1[/tex] is 32.

(a) To normalize the wavefunctions, we need to find the normalization constants A and B such that

[tex]\int \|{\psi_1}\|^2 dV = 1[/tex] and [tex]\int \|{\psi_2}\|^2 dV = 1[/tex]

where [tex]\psi_1[/tex] and [tex]\psi_2[/tex] are the two wavefunctions given.

(i) [tex]\psi_1 = (2 - \dfrac{r}{a}) \times e^{\dfrac{-r}{2a}}[/tex]

The normalization condition for psi1 is:

[tex]\int \|\psi_1\|^2 dV = \int \{2 - \dfrac{r}{a} \times e^{\dfrac{-r}{a}}\}^2 r^2 sin\theta dr d\theta d\phi\\\\ = 1[/tex]

Evaluating the integral using spherical coordinates, we get:

[tex]\int_0^\infty \int_0^\pi \int_0^{2\pi} [(2 - r/a)^2 e^{-r/a} r^2 sin\theta]\ dr\ d\theta\ d\phi = 1\\\\\dfrac{(16\pi a^5)}{(3^3)} \times \|A\|^2 = 1\\A = \dfrac{3^3}{{(16\pi a^5)}^{0.5}}[/tex]

(ii) [tex]\psi_2 = r sin\theta\ cos\phi\ e^{\dfrac{-r}{2a}}[/tex]

Evaluating the integral using spherical coordinates, we get:

[tex]\int_0^\infty \int_0^\pi \int_0^{2\pi} r^4 sin^3\theta cos^2\phi e^{-r/a} dr\ d\theta\ d\phi = 1\\\\\dfrac{16\pi a^5}{15} \times \|B\|^2 = 1\\B = \sqrt{\dfrac{15}{16\pi a^5}}[/tex]

To confirm that the two wavefunctions are mutually orthogonal, we need to evaluate the integral [tex]\int \psi_1\times \psi_2 dV[/tex] and show that it is equal to zero. Using spherical coordinates, we get:

[tex]\int_0^\infty \int_0^\pi \int_0^{2\pi} [(2 - r/a) \times e^{-r/a} \times r sin\theta cos\phi \times e^{-r/2a}]\ r^2\ sin\theta\ dr\ d\theta\ d\phi\\\\= 8\pi a^5 \times [\int_0^\infty e^{-r/a} r^2 (2 - r/a) e^{-r/2a}\ dr] \times [\int_0^\pi sin\theta\ cos\theta\ d\theta] \times [\int_0^{2\pi} cos\phi\ d\phi]\\= 0[/tex]

Therefore, the two wavefunctions are mutually orthogonal.

(b) To evaluate the expectation values of r and r^2, we need to calculate the integrals [tex]\int psi_1 \times r\ \psi_1 dV[/tex] and [tex]\int \psi_1 \times r^2\ \psi_1 dV[/tex]. Using spherical coordinates, we get:

For psi1:

[tex]\int psi_1 \times r\ \psi_1 dV = 4\pi \int_0^\infty (2 - r/a)^2 e^{-r/a} r^4 dr\\\\ = \dfrac{32\pi a^5}{15}[/tex]

[tex]\int \psi_1 \times r^2\ \psi_1 dV = 4\pi \int (2 - r/a)^2 e^{-r/a} r^5 dr\\\\ = \dfrac{128\pi a^6}{45}[/tex]

Therefore, the expectation value of r for [tex]\psi_1[/tex] is 32.

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The change in the velocity of the planet is 18.55 m/s.

The gravitational force between the star and the planet, is calculated by applying Newton's third law of motion.

F = Gm₁m₂ /r²

where;

The distance between the start and the planet is calculated as;

r = √ ( 8 x 10¹² - 5 x 10¹² )² + ( 5 x 10¹² - 8 x 10¹² )²

r = 4.24 x 10¹² m

F = ( 6.67 x 10⁻¹¹ x 5 x 10³⁰ x 6 x 10²⁴ ) / ( 4.24 x 10¹² )²

F = 1.11 x 10²⁰ N

The acceleration of the planet is calculated as;

a = F / m₂

a = ( 1.11 x 10²⁰ N ) / ( 6 x 10²⁴ kg )

a = 1.85 x 10⁻⁵ m/s²

The change in the velocity of the planet;

Δv = at

Δv = ( 1.85 x 10⁻⁵ x 1 x 10⁶ s )

Δv = 18.55 m/s

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Answer:

The velocity of the ball before it hit the ground was (3.59 m/s, -3.32 m/s) in the horizontal and vertical direction

Explanation:

The velocity of the ball can be calculated using the equation of motion:

v^2 = u^2 + 2as,

where

u = initial velocity,

v = final velocity,

a = acceleration due to gravity (9.8 m/s^2),

s = vertical height fallen (0.86 m).

Solving for u:

u = sqrt(v^2 - 2as)

We know the final velocity, v = 0 (the ball lands on the ground and stops), so

u = sqrt(2as) = sqrt(2 * 9.8 * 0.86) = 3.32 m/s.

The direction of the velocity before it hit the ground can be determined using horizontal distance traveled and time of flight.

The time of flight, t, can be found using:

t = sqrt(2s/a) = sqrt(2 * 0.86 / 9.8) = 0.39 s.

The horizontal velocity, vx, can be found using:

vx = d / t = 1.4 / 0.39 = 3.59 m/s.

The first and third statements for the positive charge which moves in the electric field are correct.

When placed in an electric field, the positive charge typically flows in the direction of the electric field. The work done by the electric field in this situation is positive because both the electric field vector and the displacement vector point in the same direction and there is no angle between them.

The potential will also decrease in the direction of the electric field. This is because the work done in the order of the electric field is called the potential. electric potential is the amount of work required to move a unit charge from a reference point against an electric field to a particular point 

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For part 4 after solving the equation the the rotation rate is 0.74 rev/s.

What is rotation rate?

Rotation rate is the angular velocity of a body or object in a circular motion. It is typically measured in rotations per minute (RPM) and is the number of times a full rotation is completed in one minute.

Part 1 of 4 - Conceptualize: Look carefully at the figure and imagine you are the astronaut sitting in the seat at the far right. As the centrifuge rotates, you are experiencing an acceleration toward the center of the device.

The faster the centrifuge spins, the larger is that acceleration. The problem is asking for a rotation rate, measured in revolutions per second. Because the period of circular motion is the number of seconds per revolution, we see that the rotation rate will be the inverse of the period.

Part 2 of 4 - Calculate: To calculate the rotation rate, we need to find the period of the motion. The period of circular motion is given by:

T = 2π√(L/2a)

Where L is the length of the centrifuge and a is the centripetal acceleration.

Part 3 of 4 - Calculate: In this problem, L = 59.0 ft, and a = 20.0g. Since gravitational acceleration is equal to 9.8 m/s2, we need to convert the acceleration from g to m/s2. We can do this by multiplying the acceleration by 9.8. Thus, a = 20.0g × 9.8 m/s2 = 196.0 m/s2. Substituting the numerical values into the equation, we get:

T = 2π√(59.0 ft/2 × 196.0 m/s2) = 2π√(29.5 ft × 9.8 m/s2) = 2π√(291.1 m2/s2) = 2π√(291.1) s = 5.15 s

Part 4 of 4 - Calculate: Since the period of circular motion is the number of seconds per revolution, the rotation rate is equal to the inverse of the period. Thus, the rotation rate is:

Rotation rate = 1/T = 1/5.15 s = 0.74 rev/s

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Monkey Mo is in a static equilibrium because of the balance of all these forces acting on him.

The interaction between two things or the pressure applied to alter an object's motion is described by the physical quantity known as force. An object can change direction, accelerate, decelerate, or continue in motion as a result of force.

The forces at work on Monkey Mo when he is hung at rest while grasping a rope in one hand and the side of his cage in the other are as follows:

Gravitational force, which is vertically downward operating force of attraction between Monkey Mo and the Earth.

The tension force, which acts upward along the length of the rope, is the force the rope applies to Monkey Mo.

Normal force, which force balances the gravitational pull by operating perpendicular to the surface of the cage and being applied to Monkey Mo by the side of the cage.

Frictional force prevents Monkey Mo from falling out of the cage by acting between his hand and the side of the cage.

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The resultant force acting on the gate is equal to zero, the gate will not rotate and the pin can be placed at any location on the circumference of the gate.

To determine the placement of the pin on the circular gate, we need to consider the forces acting on the gate when the water reaches a height h = 10 ft.

When water reaches a height h = 10 ft, the gate is subjected to two types of forces: (1) buoyant force and (2) weight of the gate. The buoyant force acts upwards and is equal to the weight of the fluid displaced by the gate. The weight of the gate acts downwards and is equal to the mass of the gate multiplied by the acceleration due to gravity (g).

Let's assume that the gate has a uniform thickness and its density is equal to the density of water (ρ). Then, the volume of the gate can be calculated as follows:

V = (π/4) * d² * t

where d is the diameter of the gate and t is its thickness. The mass of the gate can be calculated as follows:

m = ρ * V

The buoyant force can be calculated as follows:

F_b = ρ * g * V

The weight of the gate can be calculated as follows:

F_w = m * g

The net force acting on the gate can be calculated as the difference between the buoyant force and the weight of the gate:

F_net = F_b - F_w = ρ * g * V - m * g = (ρ - ρ) * g * V = 0

Since the net force is equal to zero, the gate will not rotate and the pin can be placed at any location on the circumference of the gate.

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0.0018 moles of air must be pumped into the tire to increase its pressure to 272 kPa.

We can use the ideal gas law to find the number of moles of air in the tire.

The ideal gas law states that PV = nRT,

where

P is pressure,

V is volume,

n is the number of moles of gas,

R is the ideal gas constant, and

T is temperature.

The initial number of moles of air in the tire:

n1 = (P1 * V) / (R * T)

= (217 kPa * 0.0185 m³) / (8.31 J/mol * K * 289 K)

= 0.00625 moles

Next, we can find the final number of moles of air in the tire, assuming the temperature and volume remain constant:

n2 = (P2 * V) / (R * T)

= (272 kPa * 0.0185 m³) / (8.31 J/mol * K * 289 K)

= 0.00805 moles

Finally, we can find the difference between the final and initial number of moles, which represents the number of moles of air that must be pumped into the tire:

n2 - n1 = 0.00805 moles - 0.00625 moles = 0.0018 moles.

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Answer:

A) 3.0 ohms

Explanation:

R=V/I=12V/4.0A=3.0 ohms

the girl's velocity after they push off is 0.816 m/s.

Velocity is described as the directional speed of an object in motion as an indication of its rate of change in position as observed from a particular frame of reference and as measured by a particular standard of time.

The momentum of the boy after he pushes off is given by m_boy * v_boy = -747 N * 0.540 m/s = -405.08 N * m/s.

The momentum of the girl after she pushes off is denoted as   m_girl * v_girl, where m_girl is the mass of the girl and v_girl is her velocity.

The principle of conservation of momentum requires that the total momentum of the two-person system before and after the push off must be the same, hence we have:

m_boy * v_boy + m_girl * v_girl = 0

Substituting in the values for m_boy and v_boy, we find:

-405.08 N * m/s + m_girl * v_girl = 0

Solving for v_girl, we find:

v_girl = 405.08 N * m/s / m_girl = 405.08 N * m/s / 497 N = 0.816 m/s.

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To find the resultant force and magnitude of charges in a right-angled triangle, you need to use Pythagorean theorem and principles of electrostatics respectively.

The magnitude of the charges can be determined using Coulomb's law, which states that the force between two charges is proportional to the product of their magnitudes and inversely proportional to the square of the distance between them.

To find the resultant force, you need to resolve each individual force into its x and y components and then add them up vectorially.

The magnitude of the resultant force can then be found using the Pythagorean theorem, which states that the magnitude of the resultant force is equal to the square root of the sum of the squares of its x and y components.

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The frequency of electromagnetic radiation with a wavelength of 536.0 nm is 5.6 x 10¹¹ Hz.

Electromagnetic radiation is a form of energy that consists of waves of electric and magnetic fields, travelling through the air or other substances at the speed of light. These waves are created when an electric charge is accelerated and can be generated from a variety of sources, such as a light bulb, the sun, a microwave oven, or a radio transmitter.

The frequency (f) of electromagnetic radiation is calculated using the equation:
f = c/λ
where c is the speed of light (3.00 x 10⁸ m/s) and λ is the wavelength of the radiation (536.0 nm).
Therefore, we can calculate the frequency (f) as follows:
f = (3.00 x 10⁸ m/s) / (536.0 nm)
First, we need to convert the wavelength from nanometers (nm) to meters (m). We can do this by dividing 536.0 nm by 1,000,000 to get 0.000536 m.
Therefore, we can calculate the frequency (f) as follows:
f = (3.00 x 10⁸ m/s) / (0.000536 m)
f = 5.6 x 10¹¹ Hz
The frequency of electromagnetic radiation with a wavelength of 536.0 nm is 5.6 x 10¹¹ Hz.

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Using Thomson's cathode ray tube and Millikan's oil drop experiment, the charge of an electron was determined.

Thomson's cathode ray tube and Millikan's oil drop experiment were two important experiments in the history of physics. Thomson used his cathode ray tube to observe the behavior of electrons, while Millikan used his oil drop experiment to measure the charge of an electron. By combining the results of these two experiments, scientists were able to determine the charge of an electron, which is a fundamental unit of electrical charge in the study of electricity and electromagnetism.

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Answer:

20Ω

Explanation:

we are here given that,

From Ohm's law ,

[tex]\implies V = iR \\[/tex]

where,

on substituting the respective values, we have,

[tex]\implies 8V = 0.4A \times R\\[/tex]

[tex]\implies R =\dfrac{8V}{0.4A} \\[/tex]

[tex]\implies \underline{\underline{ R = 20\Omega}}\\[/tex]

and we are done!

A. Slow, legato. for a love story, we use slow and legato tempo to reflect the mood when the ice cream van interrupted the wedding ceremony.

The beats per minute are the most precise way for a composer to specify the intended speed (BPM). This means that a specific note value is designated as the beat (for instance, a quarter note), and the marking specifies that a specific number of these beats must be performed each minute.

The music's performance speed is thus determined by the tempo. So you can rapidly establish the Beats Per Minute, or BPM, by counting how many beats there are in a music played at a particular rate. If you're pushed for time, you can also double the amount of beats in 15 seconds of music by four.

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The total energy of the system remains constant.

Option B.

The law of conservation of energy states that energy can neither be created nor destroyed but can be transferred from one form to another.

When you let go of the book,  and it is pushed up by the spring, the elastic potential energy of the spring will be converted into potential energy and kinetic energy of the block.

elastic potential energy = potential energy + kinetic energy

Thus, we can conclude that the total energy of the system is constant.

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The correct order from dimmest to brightest as these stars would appear in the sky is Star C (0.0), Star A (0.4), Star D (4.2), Star B (5.6).

Apparent magnitude is a measure of the star brightness as seen from the Earth. Lower magnitudes indicate brighter stars and higher magnitudes indicate dimmer stars.

In the case of the four stars listed, Star C has the lowest magnitude of 0.0, making it the brightest of the four. Star A is slightly dimmer with a magnitude of 0.4. Star D is dimmer still with a magnitude of 4.2, and Star B is the dimmest of the four with a magnitude of 5.6. It's important to note that this is just a relative comparison and does not necessarily indicate the true brightness of the stars, only how bright they appear from our perspective on Earth.

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