The current through a 0.1 Henrys (H) inductor is i(t) = 10 t e^-5tA. Find the voltage across the inductor.

a. v(t) = 10 te^-5t V
b. v(t) = 0.1 (10te^-5t) V
c. v(t) = 5te^-5t V
d. v(t) = (1 - 5t) e^-5t V

Answers

Answer 1

Answer: d. [tex]v(t)=(1-5t)e^{-5t}[/tex]V

Explanation: Inductance is a property of an inductor: when there is a change in current passing through a conductor, it creates a voltage in the conductor itself and in the other conductors. Inductance unit is Ω.s or henry (H)

So, the relation between Voltage and Current in an inductor is given by

[tex]v=L\frac{di}{dt}[/tex]

in which

L is inductance in H

i is current in A

Current is [tex]i(t)=10te^{-5t}[/tex], so, derivative will be:

[tex]\frac{di}{dt}=10e^{-5t}+10t(-5)e^{-5t}[/tex]

[tex]\frac{di}{dt}=10e^{-5t}-50te^{-5t}[/tex]

[tex]\frac{di}{dt}=10e^{-5t}(1-5t)[/tex]

Then, voltage is

[tex]v=0.1.10.e^{-5t}(1-5t)[/tex]

[tex]v=(1-5t)e^{-5t}[/tex]

Voltage across the 0.1H inductor is [tex](1-5t)e^{-5t}[/tex] V


Related Questions

Simplify the following expression: T =(AB)'B

Answers

Idjfjfkffiigorjss ohe and didnt g gg. Ff s wjjehwhwhdr h Roa answer ok this is the answer 25T

What does an environmental science and protection technician have in common with a microbiologist

Answers

Answer:

Environmental science and protection technicians both use laboratory equipment, such as microscopes, to analyze samples collected in the field. Environmental science and protection technicians also monitor the environment and investigate sources of pollution and contamination, including those affecting public health.

Hope this was helpful ;)

answer is a and b                                        jjjjxjxjxjxjx        xxxjxjxj

A rod with a length of L has to be made to carry load F. You need to select from the following alloys: Material Density g/cc Yield Strength, MPa AI 7075 2.81 503 AISI 4340/SAE 7.85 1160 Mg-ZK61 1.83 195 Ti8Al1Mo1V 4.37 570 Which one will have the lightest weight

Answers

Answer:

AI 7075

Explanation:

Material                Density g/cc         Yield strength      

AI 7075                   2.81                         503

AISI 4340/SAE       7.85                         1160

Mg-ZK61                 1.83                          195

Ti8A|1Mo1V             4.37                         570

Determine the alloy with the lightest weight using this relationship

weight ∝  ( S / E )

E = yield strength

S = density

for AI 7075   =  2.81 / 503 = 0.00558648for AISI 4340/SAE = 7.85 / 1160 = 0.00676724for Mg-ZK61  = 1.83 / 195 = 0.00938462for Ti8A|1Mo1V  = 4.37 / 570 = 0.00766667

from the above calculation the alloy with the lightest weight is ;

AI 7075

A motor driven water pump operates with an inlet pressure of 96 kPa (absolute) and mass flow rate of 120 kg/min. The motor consumes 0.8 kW of electrical power, determine the maximum water pressure at the discharge of the pump.

Answers

Answer:

The maximum water pressure at the discharge of the pump (exit) = 496 kPa

Explanation:

The equation expressing the relationship of the power input of a pump can be computed as:

[tex]E _{pump,u} = \dfrac{m(P_2-P_1)}{\rho}[/tex]

where;

m = mass flow rate = 120 kg/min

the pressure at the inlet [tex]P_1[/tex] = 96 kPa

the pressure at the exit [tex]P_2[/tex] = ???

the pressure [tex]\rho[/tex] = 1000 kg/m³

[tex]0.8 \times 10^{3} \ W = \dfrac{(120 \ kg/min * 1min/60 s)(P_2-96000)}{1000}[/tex]

[tex]0.8 \times 10^{3}\times 1000 = {(120 \ kg/min * 1min/60 s)(P_2-96000)}[/tex]

[tex]800000 = {(120 \ kg/min * 1min/60 s)(P_2-96000)}[/tex]

[tex]\dfrac{800000}{2} = P_2-96000[/tex]

400000 = P₂ - 96000

400000 +  96000 = P₂

P₂ = 496000 Pa

P₂ = 496 kPa

Thus, the maximum water pressure at the discharge of the pump (exit) = 496 kPa

simple Brayton cycle using air as the working fluid has a pressure ratio of 10. The minimum and maximum temperatures in the cycle are 295 and 1240 K. Assuming an isentropic efficiency of 83 percent for the compressor and 87 percent for the turbine, determine (a) the air temperature at the turbine exit, (b) the net work output, and (c) the thermal efficiency.

Answers

Answer:

a) 764.45K

b) 210.48 kJ/kg

c) 30.14%

Explanation:

pressure ratio = 10

minimum temperature = 295 k

maximum temperature = 1240 k

isentropic efficiency for compressor = 83%

Isentropic efficiency for turbine = 87%

a) Air temperature at turbine exit

we can achieve this by interpolating for enthalpy

h4 = 783.05 kJ/kg ( calculated in the background ) at state 4 using Table A-17  for  Ideal gas properties of air

T4 ( temperature at Turbine exit ) = 760 + ( 780 - 760 ) [tex](\frac{783.05-778.18}{800.13-778.18} )[/tex] = 764.45K

b) The net work output

first we determine the actual work input to compressor

Wc = h2 - h1  ( calculated values )

     = 626.57 - 295.17 =  331.4 kJ/kg

next determine the actual work done by Turbine

Wt = h3 - h4  ( calculated values )

     = 1324.93 - 783.05 = 541.88 kJ/kg

finally determine the network output of the cycle

Wnet = Wt - Wc

         = 541.88 - 331.4  = 210.48 kJ/kg

c) determine thermal efficiency

лth = Wnet / qin  ------ ( 1 )

where ; qin = h3 - h2

equation 1 becomes

лth = Wnet / ( h3 - h2 )

      = 210.48 / ( 1324.93 - 626.57 )

      = 0.3014  =  30.14%

25 points and brainiest if correct A, B, C, D

Which option identifies whether Juna's answer in the following scenario is right, and correctly explains why or why not?
The problem asks to convert 63" to its feet and inches equivalent. Juna's answer is 5' .

A. Juna's answer is correct because both the number of feet and the number of inches are correct.

B. Juna's answer is correct because although the number of inches is wrong, the number of feet is correct.

C. Juna's answer is incorrect because even though the number of feet is correct, the number of inches is wrong.

D. Juna's answer is incorrect because even though the number of inches is correct, the number of feet is wrong.

Answers

Answer:

A. Juna's answer is correct because both the number of feet and the number of inches are correct

Explanation:

How does the span of a truss relate to load-carrying capacity and when a truss fails, how much area is involved?

Answers

Answer:

For a deeper material truss, increase in distance between the top chord and bottom chord will cause the truss to bear more load with increase in Span

For Cantilever Truss ; increase in span will result in decrease in load bearing capacity of the truss

When a truss fails the areas that are affected are the supports of the truss and its corresponding spam. i.e. 4 crossbars at quarter of the span

Explanation:

The load-carrying capacity of a truss on the span  is basically based on the type of truss ,

For a deeper material truss, increase in distance between the top chord and bottom chord will cause the truss to bear more load with increase in Span

For Cantilever Truss ; increase in span will result in decrease in load bearing capacity of the truss

When a truss fails the areas that are affected are the supports of the truss and its corresponding spam. i.e. 4 crossbars at quarter of the span

Tank has an average bearing pressure of 105 kPa. Ground water is deep. Calculate the total, pore and effective stress before tank loading and with tank

Answers

Answer:

Hello your question is incomplete attached below is the complete question

answer :

A) At 8 meters below center

Total stress = 228.827 KN/m^2

pore water pressure = 0 KN/m^2

effective stress = 228.827 - 0 = 228.827 KN/m^2

B) At 8 meters below tank edge

Total stress = 186.289 KN/m^2

pore water stress = 0 Kn/m^2

effective stress = 186.289 - 0 = 186.289 KN/m^2

Explanation:

Given data :

Diameter = 21 m

radius = 21 / 2 = 10.5 m

soil moist = 18.4 KN/cubic meter

Average bearing pressure = 105 kPa

i) Before Loading Tank

 Total stress = 8 * 18.4 = 147.2 KN/m^2

 Pore pressure = 0 KN/m^2

 Effective stress = 147.2 - 0 = 147.2 KN/m^2

ii) After loading Tank

  No change occurs

A) At 8 meters below center

Total stress = 228.827 KN/m^2

pore water pressure = 0 KN/m^2

effective stress = 228.827 - 0 = 228.827 KN/m^2

B) At 8 meters below tank edge

Total stress = 186.289 KN/m^2

pore water stress = 0 Kn/m^2

effective stress = 186.289 - 0 = 186.289 KN/m^2

attached below is the detailed solution

four subjects civil engineers need to study​

Answers

Answer:

A civil engineering degree program applies mathematics and physical science to solve specific, real-world problems in commerce and industry. A strong civil engineering program typically emphasizes the practical use of geometry, trigonometry, and calculus in conjunction with physics, material science, and chemistry.

Explanation:

Hope this helps!! Please consider marking brainliest! Have a good one!!

The water in a soil flows from Point K to Point L, a distance of 250 ft. Point K is at elevation 543 ft and Point L is at elevation 461 ft. Piezometers have been installed at both points, and their water levels are 23 ft and 74 ft, respectively, above the points. Compute the average hydraulic gradient between these two points.

Answers

Answer:

0.124

Explanation:

We calculate the hydraulic gradient by the formulas below.

I = (change in h)/(change in l)-----eqn 1

I = (hk-hl)/change in L ----- equation 2

At k the headloss = hk,

At L the headloss = hL

The distance of water travel is change in I

Total head at k

hk = 543+23

= 566 ft

Total head at L

hL = 461+74

= 535 ft

Change in L = 250

When we substitute these values in equation 2

566-535/250

= 0.124

The hydraulic gradient is 0.124

What is different about residential construction on the local level from residential construction on the national level?

Answers

Answer:

The difference lies in the coverage of the construction.  While local level construction focuses on the local area, national level construction has a nation-wide coverage.

Explanation:

Residential construction concentrates on the construction of residential buildings that have sleeping accommodations.  Such constructions are opposed to the construction of other buildings that are meant for commercial uses as they lack sleeping accommodations.  The federal, state, and local governments can embark on the construction of residential quarters for their residents.  The constructions are also funded at the given level.  When it is locally funded, the construction is meant to satisfy specific local needs.  The constructions by the federal government consider the needs of many localities, and may not meet specific local needs.

Answer: A Residential construction is local in its effects even though those effects have a national impact.

Explanation:

Describe the role of C-S-H in providing strength for cement. Discuss which compounds produce C-S-H and why balancing the amounts of those compounds is important.

Answers

Answer:

Following are the solution to this question:

Explanation:

Whenever a chemical reaction occurs between water and cement the heat is released, and a [tex]CaOSiO_2H_2O[/tex] (C-S-H gel) gel constructs gel is also recognized as "tobermorite gel."

This one gel acts like a pack of gum and also has a cement quality, that holds its particles intact and therefore contributes to the overall compression mix. An increase in supply explicitly causes the movement in the outcome of power. C3S and C2S are both the compounds of Bouge that produce hydration C-S-H gel.

It mixture must be balanced as [tex]Ca(OH)_2[/tex] with C-S-H gel also is given as a byproduct. It [tex]Ca(OH)_2[/tex] , that cause sudden with sulphate and form [tex]CaSO_4[/tex] , is an unacceptable substance. Sulfate attack or later deterioration of its cement is caused by this [tex]CaSO_4[/tex] .

All C3S and C2S generate various amounts of C-S-H gel so, the required strength can be maintained without compromising on real term durability.

What major financial flop led to the end of the Sega Dreamcast and ultimately caused Sega to stop making game consoles altogether?

1: The founder and CEO of Sega was found to be secretly skimming money off of the top of profits, leading to widespread distrust by the public and a sharp decline in sales until they ultimately had to shut down due to making no profit.

2: A small group of employees found a way to drain all of the Sega Corporation funding accounts and flee the country with all of the money, never to be heard from again.

3: A game called Shenmue, that cost more than $70 million to make, meant that everyone who owned a Dreamcast needed to buy two copies of the game just for Sega to make back the money they had spent to develop it-which didn't happen.

4: A game called Katamari Damacy that carried a virus that would infect any console that it was played on forced Sega to spend millions of dollars in refunds and bankrupted the company.​

Answers

Answer:

The major financial flop that led to the end of the Sega Dreamcast and ultimately caused Sega to stop making game consoles altogether is:

3: A game called Shenmue, that cost more than $70 million to make, meant that everyone who owned a Dreamcast needed to buy two copies of the game just for Sega to make back the money they had spent to develop it-which didn't happen.

Explanation:

Shenmue, released on December 29, 1999, was created for Dreamcast by Suzuki.  It was widely described as the most expensive video game ever produced.  It had an estimated production and marketing cost of between US$47 and $70 million, according to the latest available data.

35 points and brainiest is it A, B, C, D
Which of the following nails would most likely be used in securing a delicate, decorative piece of thin wood trim to a cabinet face?

A. 2d
B. 10d
C. 60d
D. 100d

Answers

Answer:

c thereeeeeeeeeeeeeeeeee

I believe the correct answer is C.

What is least conducive to a rich tradition of master craftsmanship?

A. A reliance on mass production of necessary parts.

B. A demand for unique features.

C. A way for passing on knowledge of craft.

D. A respect for high craftsmanship as a kind of art.

Answers

/~\ The correct answer is:

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

B. A demand for unique features.

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

I hope this helps! /~\

Answer:

A. A reliance on mass production of necessary parts.

Explanation:

Took the test

The velocity in a channel that is 3 m deep is 1 m/s. What is the Froude number in a 1/6 scale model of that channel that satisfies dynamic similarity?a. 1.b. 0.45.c. 0.18.d. 5.4.e. 0.08.

Answers

Answer:

c. 0.18

Explanation:

The Formula for Froude Number is given as follows:

Froude No. = Inertial Forces/Gravity Forces

Froude No. = v/√(gD)

where,

v = velocity = 1 m/s

g = 9.8 m/s²

D = Depth of channel = 3 m

Therefore,

Froude No. = (1 m/s)/√[(9.8 m/s²)(3 m)]

Froude No. = 0.18

hence, the correct option will be:

c. 0.18

Refrigerant-134a enters an adiabatic compressor as saturated vapor at 160 kPa at a rate of 2.4 m3/min and is compressed to a pressure of 900 kPa. Determine the minimum power that must be supplied to the compressor. Use the tables for R-134a

Answers

Answer:

11.65kW

Explanation:

Step one:

given data

from the table  for R-134a

For the given pressure state the following data were extracted.

s=0.94202kJ/kg.K

h1=241.14kJ/kg

∝1=0.12355m^3/kg

By interpolation, the final enthalpy and pressure with data from the table of  R-134a

h2=277.12kJ/kg

The minimum power output is then determined from the energy balance

W=m(h2-h1)

W=V1/∝1(h2-h1)

W=2.4/60/0.12355(277.12-241.14)

W=0.04/0.12355(35.98)

W=0.3237(35.98)

W=11.65kW Approx.

The minimum power output of the compressor is 11.65kW

An automotive fuel has a molar composition of 85% ethanol (C2H5OH) and 15% octane (C8H18). For complete combustion in air, determine: (a) the molar air-fuel ratio and air-fuel ratio by mass. (b) the lower heating value, in kJ per kmol of fuel and in kJ per kg of fuel.(c) the higher heating value, in kJ per kmol of fuel and in kJ per kg of fuel. (d) the dew point temperature of the combustion products at 1 atm, in °C. Consider a reference temperature and pressure of 25°C, 1 atm.

Answers

Answer:

a) 1

b) 1813.96 MJ/kmol

c) 32.43 MJ/kg ,  1980.39 MJ/Kmol

Explanation:

molar mass of  ethanol (C2H5OH) = 46 g/mol

molar mass of   octane (C8H18) = 114 g/mol

therefore the moles of ethanol and octane

ethanol =  0.85 / 46

octane = 0.15 / 114

a) determine the molar air-fuel ratio and air-fuel ratio by mass

attached below

mass of air / mass of fuel = 12.17 / 1 = 12.17

b ) Determine the lower heating value

LHV  of  ( C2H5OH) = 26.8 * 46 = 1232.8 MJ/kmol

LHV  of (C8H18). = 44.8 mj/kg * 114 kg/kmol = 5107.2 MJ/Kmol

LHV ( MJ/kmol)  for fuel mixture = 0.85 * 1232.8 + 0.15 * 5107.2 = 1813.96 MJ/kmol

c) Determine higher heating value  ( HHV )

HHV of (C2H5OH) = 29.7 * 46 = 1366.2 MJ/kmol

HHV of C8H18 = 47.9 MJ/kg * 114 = 5460.6 MJ/kmol

HHV  in MJ/kg  = 0.85 * 29.7 + 0.15 * 47.9  = 32.43 MJ/kg

HHV in  MJ /kmol  =  0.85 * 1366.2 + 0.15 * 5460.8 = 1980.39 MJ/Kmol

What is the heat loss coefficient that has a symbol Uair and is found from (volumetric flow * density * specific heat capacity) of a building with a volume of 19456 cubic feet, if there is a natural air change per hour of 0.4

Answers

Answer:

Uair = 0.0749 KW/k = 74.9 W/k

Explanation:

The natural air change per hour is given by the formula:

Natural Air Change per Hour = ACPH = 60*Volume Flow/Volume

where,

ACPH = 0.4

Volume Flow = ? in ft³/min

Volume = 19456 ft³

Therefore,

0.4 = (60 min)(Volume Flow)/(19456 ft³)

Volume Flow = (0.4)(19456 ft³)/(60 min) = (129.7 ft³/min)(1 min/60 s)

Volume Flow =  (2.16 ft³/s)(0.3048 m/1 ft)³ = 0.061 m³/s

Now, we find heat loss coefficient:

Uair = Volumetric Flow*Density of air*Specific Heat Capacity of air

Uair = (0.061 m³/s)(1.225 kg/m³)(1 KJ/kg.k)

Uair = 0.0749 KW/k = 74.9 W/k

Select a Goulds 3196 pump to operate at 3560 rpm to deliver 500 gpm of water at a head of 250 ft. What impeller diameter should be installed in the pump

Answers

Answer:

Impeller diameter should be 0.02 meter

Explanation:

The Impeller diameter is a parameter with a circular design of a high speed pump. The performance of the pump depends on this parameter.

As per the given data

Speed of pump = 3,560 rpm

Rate of water flow = 500 gpm = 0.0005 m^3/minutes

Size of head = 250 ft = 250 ft x 0.3048 m/ft = 76.2 m

The impeller diameter can be calculated using following formula

Impeller diameter =0.1 x  [tex]\sqrt{Water flow rate X 60}[/tex]

Impeller diameter =0.1 x  [tex]\sqrt{0.0005 X 60}[/tex]

Impeller diameter =0.1 x  [tex]\sqrt{0.03}[/tex]

Impeller diameter = 0.1 x 0.1732

Impeller diameter = 0.01732

Impeller diameter = 0.02 m

35 points and brainiest. A, B, C, D
Which of the following identifies what carbide-tipped bits, lines on machine bolts, and lock washers all have in common?

A. All are very expensive items.
B. All are very recent inventions.
C. All are rather outdated inventions.
D. All provide an added level of strength.

Answers

Answer:c

Explanation:

List the three main phases of photo interpretation in photogrammetry

Answers

Answer:

Stages of Interpretation and Mapping

Selection of photographs. Whenever possible, all photographs of a site or small area should be assessed for fitness of purpose. ...

Control points. A good spread of control points on a photograph is vital to establish the exact location or size of features. ...

Transformation.

Explanation:

35 points an brainiest if correct

Which of the following nails would most likely be used in securing a delicate, decorative piece of thin wood trim to a cabinet face?

2d
10d
60d
100d

Answers

i think the answer is B. 10D

how do the brushes control the amount of charging an alternator does

Answers

Explanation:

Think of brushes as a sliding contact.

In an alternator the brushes provide power to the field coil which is physically mounted on the rotating shaft. They provide this direct current through two slip rings.

By controlling the power flow to the field, the power output of the alternator can be controlled. A regulator circuit is used to control the field so that the output voltage is maintained to about 13.5 to 14.5 VDC.

FUN FACT: Many brush holders have a small holes near the brush exit. When you assemble the alternator you physically push the brushes all the way into their holder and then thread a small wire through these hole. After the alternator is assembled you can pull the wire out and the brushes will snap into position.

Cody’s car accelerates from 0m/s to 45 m/s northward in 15 seconds. What is the acceleration of the car

Answers

Answer:

3 m/s²

Explanation:

Acceleration is calculated as :

a= Δv/ t

where ;

Δv = change in velocity

Δv = 45 - 0 = 45  m/s

t= 15 s

a= 45 /15

a= 3 m/s²

What simple changes would you make to a basic PID controller if you expected the sensors to be very noisy and the target to change by large steps?

Answers

Answer:

tuning the value of  Ki termincreasing/changing the Kp term

Explanation:

The simple change that would be made to a basic PID controller to prevent it from been noisy  is tuning the value of  Ki term   while

The simple change that would be made to a PID controller if you want to  change the target by large steps is increasing/changing the Kp term associated with the PID  controller

Select one correct statement: A) Specific ions are necessary for metals and alloys.B) An environment that causes SCC of one alloy would also causes SCC of another alloy.C) As specific ions form a film on the metal surface, hence, those ions which form films may be adequate to cause SCC.

Answers

Answer:

option  C

Explanation:

The correct statement is As specific ions form a film on the metal surface, hence those ions which form films may be adequate to cause SCC

other options are wrong as ; specific ions are not necessary for metals and alloys and also an environment causing SCC for an alloy might not cause SCC of another alloy found in the environment

Tahir travel twice as far as ahmed, but onley one third as fast. Ahmed starts travel on tuesday at noon at point x to point z 300km, by 9:00pm. Tahir starts travel same day after 3hr of ahmed. In which time tahir reach at point z?

Answers

Answer:

6:00 pm the next day

Explanation:

Given that

Tahir traveled twice as far as Ahmed. We say,

Ahmed traveled a distance, D

Tahir would travel a distan, 2D

Tahir traveled 1/3 as fast as Ahmed, so we say

Ahmed traveled at a speed, S

Tahir would travel at a speed, S/3

If Ahmed starts travel on tuesday at noon at point x to point z 300km, by 9:00pm,

Time taken by Ahmed to travel is

9:00 pm - 12:00 pm = 9 hours

Ahmed, traveled 300 km in 9 hours, meaning he traveled at 33.3 km in an hour.

Speed, S that Ahmed traveled with is 33.3 km/h

Remember, we stated that Tahir travels at a speed of S/3, that is, The speed of Tahir is

33.3/3 = 11.1 km/h.

300 km would then be traveled in 300 km/11.1 km/h = 27 hours.

Tahir started traveling, 3 hours after Ahmed, that is 12:00 pm + 3:00 hrs = 3:00 pm, and if he's to spend 27 hours on the journey he would reach destination z at 6:00 pm the next day

The article provides information by using a list. What does it list? A. Thanksgiving food B. places where clams can be found C. birds served at the first Thanksgiving D. four men who went on a "fowling" mission

Answers

Answer:

C

Explanation:

I can't log in even though it says all ages are accepted.Instead when I TRY logging in it says this. "We're sorry, but we are not able to complete your registration at this time". And I have tried refreshing the page and and X-ing out of the tab and restarting my computer and it doesn't work! And I know people aren't that crazy to get a account for brainly. Please help me out I really need a answer.

Answers

Answer:

Explanation:

This is not a question so to say. This is more like a complaint about how the platform works. Are you needing help with solving a personal problem or having troubles with the platform in itself

Other Questions
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