The county fair charges $.50 per ride and $10 to get
in. If you have $32, write an equation to find the
number of rides (r) you can go on.

Question 6

1) [tex]\overline{AB} \cong \overline{BD}[/tex], [tex]\overline{CD} \perp \overline{BD}[/tex], O is the midpoint of [tex]\overline{BD}[/tex], [tex]\overline{AB} \cong \overline{CD}[/tex] (given)

2) [tex]\angle ABO, \angle ODC[/tex] are right angles (perpendicular lines form right angles)

3) [tex]\triangle ABO, \triangle CDO[/tex] are right triangles (a triangle with a right angle is a right triangle)

4) [tex]\overline{BO} \cong \overline{OD}[/tex] (a midpoint splits a segment into two congruent parts)

5) [tex]\triangle ABO \cong \triangle CDO[/tex] (LL)

Question 7

1) [tex]\angle ADC, \angle BDC[/tex] are right angles), [tex]\overline{AD} \cong \overline{BD}[/tex]

2) [tex]\overline{CD} \cong \overline{CD}[/tex] (reflexive property)

3) [tex]\triangle CDA, \triangle CDB[/tex] are right triangles (a triangle with a right angle is a right triangle)

4) [tex]\triangle ADC \cong \triangle BDC[/tex] (LL)

5) [tex]\overline{AC} \cong \overline{BC}[/tex] (CPCTC)

Question 8

1) [tex]\overline{CD} \perp \overline{AB}[/tex], point D bisects [tex]\overline{AB}[/tex] (given)

2) [tex]\angle CDA, \angle CDB[/tex] are right angles (perpendicular lines form right angles)

3) [tex]\triangle CDA, \triangle CDB[/tex] are right triangles (a triangle with a right angle is a right triangle)

4) [tex]\overline{AD} \cong \overline{DB}[/tex] (definition of a bisector)

5) [tex]\overline{CD} \cong \overline{CD}[/tex] (reflexive property)

6)  [tex]\triangle ADC \cong \triangle BDC[/tex] (LL)

7) [tex]\angle ACD \cong \angle BCD[/tex] (CPCTC)

Answer:

Your simply dividing by 11

Step-by-step explanation:

0.008...

0.0007...

0.00006...

All you have to do is turn these numbers into fractions!

Answer:

1/121, 1/1331, 14641

Step-by-step explanation:

121, 11 ,1 , 1/11

We need to find the next three terms in the pattern

We are taking each term and dividing by 11

121/11 =11

11/11 =1

1/11 = 1/11

1/11 divided by 11

1/(11*11) = 1/121

1/121 * 1/11 = 1/1331

1/1331 * 1/11 = 14641

a) As the constants are equal, the situation represents a proportional relationship.

b) The constant of 2/3 cupcakes per minute means that in a minute, 2/3 of a cupcake is made.

A proportional relationship is a function in which the output variable is given by the input variable multiplied by a constant of proportionality, that is:

y = kx

In which k is the constant of proportionality.

In this problem, the constants for each situation are:

k = 30/45 = (30/15)/(45/15) = 2/3 = 20/30.

Since the constants are equal, the situation represents a proportional relationship.

The constant of 2/3 cupcakes per minute means that in a minute, 2/3 of a cupcake is made.

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We know that ratios can be shown with both fractions and colons.

20:705

or

[tex]\frac{20}{705}[/tex]

It also looks like we can simplify this by dividing by 5.

20/5 = 4

705/5 = 141.

This means that for every 4 teachers, there are 141 students.

The ratio for teachers to students is:

4 : 141

Considering the piece-wise function described, the catering cost for a dinner with 40 guests is of $600.

A piece-wise function is a function that has different definitions, depending on the input.

In this problem, considering between 0 and 40 guests, the definition is the open circle at (0, 100) and goes up to a closed circle at (40, 600), hence the catering cost for a dinner with 40 guests is of $600.

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Answer:

600

Step-by-step explanation:

edge

In a two-tailed hypothesis test the null hypothesis is rejected.

According to the statement

The test statistic is 3.06 and the critical values are /-2.086.

If we find the value of t by using the formula the then it comes with Negative sign and it lies under the critical region.

That's why In a two-tailed hypothesis test the null hypothesis is rejected.

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The vertices of abc given the transition rule (x,y)-->(x,y-3) are (-6, -10), (-3, -13) and (-5, -1)

The vertices are given as:

a (-6,-7)

b(-3,-10)

c(-5,2)

The transition rule is given as

(x,y)-->(x,y-3)

So, we have

a' = (-6, -7 - 3)

a' = (-6, -10)

b' = (-3, -10 - 3)

b' = (-3, -13)

c' = (-5, 2 - 3)

c' = (-5, -1)

Hence, the vertices of abc given the transition rule (x,y)-->(x,y-3) are (-6, -10), (-3, -13) and (-5, -1)

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When the completing the square is applied, the rewritten function is (x + 2)^2 = 4

The equation is given as:

x^2 + 4x = 0

The above equation is a quadratic equation and the coefficient of x in the above equation is 4.

So, we have:

k = 4

Divide the variable k by 2

k/2 = 4/2

k/2 = 2

Square the above result

(k/2)^2 = 4

Next, we add 4 to both sides of x^2 + 4x = 0

x^2 + 4x + 4 = 4

Expand the equation by expressing 4x as 2x + 2x

This gives

x^2 + 2x + 2x + 4 = 4

Factorize the above equation

x(x + 2) + 2(x + 2) = 4

Factor out x + 2 from the above equation

(x + 2)(x + 2) = 4

Rewrite the equation as a perfect square of (x + 2)

(x + 2)^2 = 4

Hence, the rewritten function after completing the square is (x + 2)^2 = 4

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Answer:

No. The slopes of parallel lines are equal.

Step-by-step explanation:

If you have two lines and their slopes are the same, then the lines are parallel.

If the two lines have slopes that are negative reciprocals (opposite signs and flipped over) then when you multiply the slopes together, you get -1... THOSE lines are perpendicular (they make right angles or make 90° angles or square angles).

Lines in the same plane that have different slopes will intersect at one point.

Answer: D

Step-by-step explanation:

Answer:

25 miles

Step-by-step explanation:

2 inches represents 10 miles ( divide both parts by 2 )

1 inch represents 5 miles , then

5 inches represents 5 × 5 = 25 miles

The solution of the given equation can be all real numbers, except c = 0 and c = 3.

Lets simplify the given problem,

1/c-3 - 1/c = 3/ (c-3)

As the denominators cannot be equal to zero (0) because a division by zero (0) is undefined.

Next, we would multiply both sides of the given by the lowest common multiple (LCM).

The lowest common multiple (LCM) is c(c - 3).

c-[c-3] = 3

c-c+3 = 3

0 = 3-3

0=0

Therefore, the solution of the given equation can be all real numbers, except c = 0 and c = 3.

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Answer:

A. 14, because it says that only 14 liked English language ONLY

B. It’s 7.

14 liked only English, 7 liked both languages, 12 liked only French.

Add those them together.

14 + 7 + 12

21 + 12

33

33 - 40 = 7

( 33 is the number of students that liked a language and 40 is ALL the students in total )

So it would be 7.

C. 26 liked one language.

7 liked both languages and 7 didn’t like neither. You could add them together.

7 + 7 = 14

40 - 14 = 26

OR

14 + 12 = 26
( just English + just French )

D. The probability of a student chosen at random that ONLY likes French would be 12/40.

Since only 12 of the 40 students liked ONLY French, it would be 12/40 or 12 : 40

Step-by-step explanation:

I hope it helps! Have a great day!

Pan~

Answer:

a) 14
b) 7
c) 33
d) P = 12/40 = 3/10 (In decimal P=0.3)

Step-by-step explanation:

Hope this helps

Postulate: SAS

Similarity statement: [tex]\triangle CAB \sim \triangle EDF[/tex]

The area of the semicircle = 8π

A semicircle is formed when the panel passing through the center touches both ends of the circle. Therefore, if you connect two semicircles, you get a circle

If you cut them in half or divide the circumference of the circle by 2, you will get a semi-circle. Area of ​​semicircle The area of ​​the semicircle is half the area of ​​the circle. Because the area of ​​the circle is πr2. Therefore, the area of ​​the semicircle is 1/2 (πr2). Where r is the radius. The value of π is 3.14 or 22/7.

Semi-circular area = 1/2 (πr2)

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The solution set to the inequality 5.1(3 + 2.2x) > –14.25 – 6(1.7x + 4) gives x > -2.5

An equation is an expression that shows the relationship between two numbers and variables.

An independent variable is a variable that does not depend on any other variable for its value whereas a dependent variable is a variable that depend on any other variable for its value.

Inequality shows the non equal comparison of two or more numbers and variables.

Given the inequality:

5.1(3 + 2.2x) > –14.25 – 6(1.7x + 4)

Simplifying:

15.3 + 11.22x > –14.25 – 10.2x - 24

21.42x > -53.55

x > -2.5

The solution set to the inequality 5.1(3 + 2.2x) > –14.25 – 6(1.7x + 4) gives x > -2.5

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Answer:

B.

Step-by-step explanation:

A C and D are not functions as they are one - to - many  whereas B is many-to-one.

Answer:

16

Step-by-step explanation:

You replace m with 14. 2 + 14 = 16.

[tex]\huge\text{Hey there!}[/tex]

[tex]\huge\textsf{Assuming equation:}[/tex]

[tex]\mathsf{\dfrac{m}{2} + m}[/tex]

[tex]\huge\textsf{If so, let's solve for your equation:}[/tex]

[tex]\mathsf{\dfrac{m}{2} + m}[/tex]

[tex]\mathsf{= \dfrac{14}{2} + 14}[/tex]

[tex]\mathsf{= 7 + 14}[/tex]

[tex]\mathsf{= 21}[/tex]

[tex]\huge\textsf{Therefore, your answer should be:}[/tex]

[tex]\huge\boxed{\frak{21}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

B

Step-by-step explanation:

44/77

=0.55

The measure of the angle is 51 degrees.

If the sum of two angles is ninety levels, then we say that they may be complementary. thus, the supplement of an attitude is received by means of subtracting it from 90. as an example, the supplement of 40° is ninety° - forty° = 50°.

If two attitudes are complementary, the sum in their measure is ninety tiers. So, the measures of the 2 complementary angles are 51 degrees and 39 degrees.

While the sum of angles is equal to ninety ranges, they are known as complementary angles. For example, 30 stages and 60 stages are complementary angles.

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The inequality passing through (1, 4), (-2, -2), intersecting the y-axis at 2 units and intersects the x-axis at (-1, 0) to form shaded portions on the left side is y > 2x+2

An equation is an expression that shows the relationship between two or more variables and numbers.

An inequality shows the non equal comparison of two or more numbers and variables.

The inequality passing through (1, 4), (-2, -2), intersecting the y-axis at 2 units and intersects the x-axis at (-1, 0) to form shaded portions on the left side is y > 2x+2

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Answer:

Step-by-step explanation:

380 rows in total

bcs

use sense

The events are independent events and probability of tossing a head and drawing a red marble is 1/7

a) The answer is present in the image attached below

b) Tossing of a coin and drawing of a marble are independent events as these two events do not interfere in the probability of each others events.

c) The probability of tossing a head and drawing a red marble is = [tex]\frac{1}{2}.\frac{2}{7}[/tex]=1/7 as we can see from the tree diagram that probability of tossing a coin and getting head is 1/2 and probability of drawing a red marble is 1/7. As they are independent events, their probability can be multiplied. Hence the probability of tossing a head and drawing a red marble is 1/7.

d) The probability of drawing two blue marbles if the first marble is not replaced and one at a time is 1/7. Probability of drawing first blue marble from the lot is 3/7 as favorable outcomes are 3 and total outcomes are 7. As the ball is not replaced the outcomes are changed. Now the number of blue balls are 2 and total number of balls are 6. So now the probability becomes 2/6. Hence the total probability becomes = 1/7

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The box-and-whisker plot for the data can be seen in the attachment.

The data given to us is:

50, 51, 54, 55, 57, 61, 62, 63, 65, 66, 67, 68, 71, 71, 76, 76, 77.

As the data is already ordered from least to greatest, we can apply the formulas.

The sample size, n = 17.

Start point = 50.

First quartile, Q1 = (n + 1)/4 th observation = (17 + 1)/4 th observation = 18/4 th observation = 4.5 th observation = average of the 4th and the 5th observation = (55 + 57)/2 = 112/2 = 56.

Median, Q2 = (n + 1)/2 th observation = (17 + 1)/2 th observation = 18/2 th observation = 9th observation = 65.

Third quartile, Q3 = 3(n + 1)/4 th observation = 3(17 + 1)/4 th observation = 3*18/4 th observation = 54/4 th observation = 13.5 th observation = average of the 13th and the 14th observation = (71 + 71)/2 = 142/2 = 71.

End point = 77.

Thus, the box-and-whisker plot should be designed as follows:

The start of the first whisker is from 50, representing the start point.

The start of the box is from 56, representing the first quartile.

The line inside the box is at 65, representing the median.

The end of the box is at 71, representing the third quartile.

The end of the whisker is at 77, representing the endpoint.

The box-and-whisker plot can be seen in the attachment.

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Answer:

y is less than or equal to 2/3x + 1/5

Step-by-step explanation:

Answer:

Step-by-step explanation:

y=2*|x-3|+2

y=|2*x-2*3|+2

y=|2x-6|+2

1)

y=2x-6

x | 2 | 3 |

y | -2| 0 |

2)

y=|2x-6|

3)

y=|2x-6|+2

y=2*|x-3|+2.