The a oranial price of a skate broad was reduced by 15 dollars .the new price is 49 dollars if p=the stakebroads oranail price in dollars what mathematical sentence expresses the information
a.49-p=15
b.15-p=49
c.15+p=49
d.p-15=49
Answer:
d. p - 15 = 49
Step-by-step explanation:
p = original price
The price was reduced by 15 dollars.
The new price is p - 15.
The new price is 49.
p - 15 = 49
Answer: d. p - 15 = 49
write the equation of the line that passes through the points (1,6) and (9,-8). put your answer in fully reduced slope form, unless it is a vertical or horizontal line.
Answer:
Y = - 7/4 X + 31/4
Step-by-step explanation:
M = 14/-8 = - 7/4
6 = - 7/4 + B
24 = -7 + 4B
31 = 4B
B = 31/4
100 people study one language at a college. Some people study French, some study Spanish. The rest of the people study German. 54 of the people in Year 10 and the rest in Year 11. 20 of 29 people who study Spanish in Year 11. 31 people study German, 15 year 11 students study French. Work out the number of Year 10's who study German.
Hello,
[tex]Data:\\\\\begin{array}{|c|c|c|c|c|}Year&French&Spanish&German&Total\\----&----&----&----&---\\Y10&-&-&-&54\\Y11&15&20&-&-\\----&----&----&----&---\\&-&29&31&100\\\end{array}\\\\Calculus:\\\\\begin{array}{|c|c|c|c|c|}Year&French&Spanish&German&Total\\----&----&----&----&---\\Y10&25&9&20&54\\Y11&15&20&11&46\\----&----&----&----&---\\&40&29&31&100\\\end{array}\\\\[/tex]
20 Year10's students learn German.
========================================================
Explanation:
Make a table that has "Year 10", "Year 11", and "Total" as the three rows.
Then you'll have the columns "French", "Spanish", "German", "Total".
In the bottom right corner is the value 100. This is the grand total of everyone surveyed.
We're told that 54 people are in Year 10, which leaves 100-54 = 46 people in Year 11.
Along the "total" column on the far right side, we'll have 54, 46, and 100 in that order from top to bottom.
--------------------------
The info that "20 of the 29 people who study Spanish in Year 11" tells we have 20 people in year 11 who study Spanish, out of 29 people who study Spanish. That leaves 29-20 = 9 people in Year 10 who study Spanish. In the "Spanish" column, we have the values 9,20,29 in that exact order from top to bottom.
Next, we'll write 31 at the bottom of the "German" column to indicate 31 people study German.
The last bit of info is that "15 Year 11 students study French". So we'll write 15 in the "year 11" row and "french" column.
--------------------------
After all that info is sorted out and entered into the table, you should end up with what is shown in figure 1 (see attached image below). Ignore figure 2 for now as we'll work our way to getting there eventually.
The variables a,b,c,d are placeholders for positive whole numbers.
There are probably a few approaches to take, but possibly the quickest is to notice that in the second row, we can say
15+20+c = 46
c+35 = 46
c = 46-35
c = 11
We have 11 students who study German in Year 11.
Once you determine c, it helps us find b. Focus on the German column to see that
b+11 = 31
b = 31-11
b = 20
There are 20 students in Year 10 who study German. You could stop here if you want.
--------------------------
Just two more variables to go.
Along the top row, we see that
a+9+20 = 54
a+29 = 54
a = 54-29
a = 25
and along the bottom row we see that
d+29+31 = 100
d+60 = 100
d = 100-60
d = 40
Or you could note along this first column to say
a+15 = d
d = a+15
d = 25+15
d = 40
So there are a few alternative paths to take.
--------------------------
All of the sections mentioned so far only involve filling out the table that is shown below in figure 2.
To answer the question your teacher wants to ask, which is how many Year 10 students study German, well that's simply 20 students. Refer to the conclusion of the previous two sections earlier.
By this point, we just simply copy the value from the completed table. This value being of course in the "Year 10" row and "German" column.
The angle of elevation of a tree at a distance of 10m from the foot of the tree is 43°. Find the height of the tree
Answer:
9.32m is the height of. the tree from the ground.
Can someone help me?
Answer:
C
Step-by-step explanation:
its asking for y, on the graph, the line is placed on point 4
8 Find the value of x a (22²)x is exponent of (22²) = 64
Given:
Consider the given equation is:
[tex](2\cdot 2^2)^x=64[/tex]
To find:
The value of x.
Solution:
We have,
[tex](2\cdot 2^2)^x=64[/tex]
It can be written as:
[tex](2\cdot 4)^x=8\times 8[/tex]
[tex]8^x=8^2[/tex]
On comparing the exponents of both sides, we get
[tex]x=2[/tex]
Therefore, the value of x is 2.
Solve simultaneously
4X + 3y= 19
2X +5y= 20
answer
4
2
Step-by-step explanation:
4x+3y=19
4x=19-3y
4x=16
x=16/4
x=4
2x+5y=20
5y=20/2x
5y= 10
y=10/5
y=2
find f(-2)for f(x)=5*3^x
f ( - 2 ) = 5 × 3^( - 2 )
f ( - 2 ) = 5 × 1/9
f ( - 2 ) = 5/9
Solve The inequality
Answer:
D is the correct answer.
Please thank me
Step-by-step explanation:
If and are the zeroes of the polynomial 2x^2+3x+5 then the value of 1/alpha + 1/beta
Pls answer fast..I’ll mark the brainlest
Answer:
-4/15
Step-by-step explanation:
Mathematically, we know that;
alpha= -b/a and beta = c/a
a refers to the coefficient of the x^2 which is 2
b is the coefficient of x which is 3
c is the last number which is 5
alpha = -b/a = -3/2
beta = c/a = 5/2
1/alpha = -2/3
1/beta = 2/5
so we have the sum as;
-2/3 + 2/5
= -5(2) + 3(2)/15 = (-10 + 6)/15 = -4/15
Find the area of the triangle whose vertices are (2, 3); (-1, 0); (2, -4)...
[Also show the steps of the solution]
Please answer correctly, it's really urgent!
Answer:
Area = 14.5
Step-by-step explanation:
Let's label the given coordinates A, B, C;
Thus;
A = (2, 3)
B = (-1, 0)
C = (2, -4)
From the coordinate geometry formula, the formula for area of a triangle with 3 vertices is;
Area = [Ax(By - Cy) + Bx(Cy - Ay) + Cx(Ay - By)]/2
Area = [2(0 - (-4)) + (-1)(-4 - 3) + 2(3 - (-4))]/2
Area = 29/2
Area = 14.5
Two
1 1 sides of trapezium are bound 60 cm & 77cm
outer sides are 25cm. & 26cm Find the
area of trapezium
Answer:
area ABEC[tex]s =\frac{25 + 26 + 17}{2} = 34[/tex]
area ∆ BEC[tex] = \sqrt{34 \times 9 \times 8 \times 17} [/tex]
[tex]17 \times 3 \times 2 \times 2 = 204cm ^{2} [/tex]
area ∆ BEC
[tex] = \frac{1}{2} \times 17 \times h = 204[/tex]
[tex]h = \: \frac{204 \times 2}{17} = 24[/tex]
[tex]area \: trap \: \: abcd \\ = \frac{1}{2}(60 + 77) \times 24 \\ = 137 \times 12 = 1644cm ^{2} [/tex]
Step-by-step explanation:
❣️Jess bragoli❣️#keep learning!!
Which of the following square root of the following number below? Check all that apply. 361
Answer:
strangely worded question....
[tex]361^{1/2} = \sqrt{361}[/tex]
Step-by-step explanation:
=========================================================
Explanation:
Notice how (19)^2 = 19*19 = 361
This shows that 19 is a square root of 361. We can say [tex]\sqrt{361} = \sqrt{19^2} = 19[/tex]
Similarly, (-19)^2 = (-19)*(-19) = 361. The two negatives cancel each other out. So that's why there are two solutions to [tex]x^2 = 361[/tex] which are x = 19 and x = -19.
So far that accounts for answer choices B and D.
-------------------------------------------
The other two answers are [tex]-361^{1/2}[/tex] and [tex]361^{1/2}[/tex] (choices C and F) because anything to the 1/2 power represents a square root.
[tex]x^{1/2} = \sqrt{x}[/tex]
anything to the 1/3 power is a cube root
[tex]x^{1/3} = \sqrt[3]{x}[/tex]
anything to the 1/4 power is a fourth root
[tex]x^{1/4} = \sqrt[4]{x}[/tex]
and so on.
-------------------------------------------
Side note: For choice C, the exponent is done first before we apply the negative. So technically we could say [tex]-1*(361)^{1/2}[/tex] for choice C to mean the same exact thing. If your teacher said [tex](-361)^{1/2}[/tex] then this would not be an answer because this results in a non-real number.
I need help plz help
answer is C. 252 ft^2
split the figure into two pieces and first figure out the rectangle (shown in turquoise).
If you multiply the width and length (18*6) you should get 108.
Then figure out the trapezoid (in magenta). the formula is (a+b)/2*h where a and b are the bases and h is the height. the bases are given, 6 and 18. to find the height, subtract the entire figure's height by 6, which is 18-6 and gives us 12. so the formula converted to this problem is (6+18)/2*12. simplify parenthesis and get 24/2*12. 24/2=12, so multiply 12*12. The area of the trapezoid is 144. Add the areas of both figures together and get 252.
a. 1.3
b. 9.6
c. 13
d. 1
Answer: I believe the answer would be 1.3
HOWEVER, if you do have to round to the nearest tenth then the answer would be 1
Step-by-step explanation:
2x+7 = 12x - 6
(subtract 2x from both sides)
7 = 10x - 6
(add 6 to both sides)
13 = 10x
(divide 13/10)
1.3 = x
Which of the four graphs has the greatest standard deviation? please help me
Answer:
Standard deviation is how far away the values are from the mean.All of your graphs have normal distribution, meaning the mean is in the center.The more spread out your graph is, the greater the standard deviation.
So the option with the most spread out graph, which I think is A, can't see very clear.
Determine if the ordered pair (-1,-5) is a solution to the inequality y<_ -3/4x-1.
A.) No,because (-1,-5) is above the line
B.) Yes, because (-1,-5) is below the line
C.) No, because (-1,-5) is on the line
D.) Yes, because (-1,-5) is on the line
Answer:
the answer is B, comment if you need explanation
Step-by-step explanation:
Which graph represents the solution of x2 + 9y2 ≤ 81 and y2 + 2 < x? On a coordinate plane, an ellipse has center (0, 0) and goes through (3, 0), (0, negative 9), (negative 3, 0), and (0, 9). A parabola opens to the right and goes through (6, 2), has vertex (2, 0), and goes through (6, negative 2). Everything inside of the ellipse and outside of the parabola is shaded. On a coordinate plane, an ellipse has center (0, 0) and goes through (3, 0), (0, negative 9), (negative 3, 0), and (0, 9). A parabola opens to the right and goes through (6, 2), has vertex (2, 0), and goes through (6, negative 2). Everything inside of the ellipse and inside of the parabola is shaded. On a coordinate plane, an ellipse has center (0, 0) and goes through (9, 0), (0, negative 3), (negative 9, 0) and (0, 3). A parabola opens to the right and goes through (6, 2), has vertex (2, 0), and goes through (6, negative 2). Everything inside of the ellipse and inside of the parabola is shaded. On a coordinate plane, an ellipse has center (0, 0) and goes through (9, 0), (0, negative 3), (negative 9, 0) and (0, 3). A parabola opens to the right and goes through (6, 2), has vertex (2, 0), and goes through (6, negative 2). Everything inside of the ellipse and outside of the parabola is shaded.
9514 1404 393
Answer:
C
Step-by-step explanation:
The ellipse y-intercepts are ±3, the x-intercepts are ±9, eliminating choices A and B. The parabola is shaded inside, eliminating choice D.
The correct choice is the third one.
what is the quotient of 3/4 ÷ 5/12
Answer:
1 4/5
Step-by-step explanation:
3/4 ÷ 5 /12
Copy dot flip
3/4 * 12/5
Rewriting
3/5 * 12/4
3/5 * 3
9/5
1 4/5
Can some help with this problem
Answer:
x+115=180 x=65
90+65+y=180 y=25
Step-by-step explanation:
All current-carrying wires produce electromagnetic (EM) radiation, including the electrical wiring running into, through, and out of our homes. High frequency EM is thought to be a cause of cancer; the lower frequencies associated with household current are generally assumed to be harmless. The following table summarizes the probability distribution for cancer sufferers and their wiring configuration in the Denver area.
Leukemia Lymphoma Other Cancers
High Frequency wiring 0.242 0.047 0.079
Low frequency wiring 0.391 0.098 ???
(a) What is the missing probability (labelled ???) in the above table?
(b) What is the probability of having high frequency wiring among cancer suffers in the Denver area?
(c) Is the event "Having Leukemia" independent of the event "Having high frequency frequency wiring"? Explain.
Answer:
[tex]x = 0.143[/tex]
[tex]P(High\ |\ Cancer) = 0.215[/tex]
Not independent
Step-by-step explanation:
Given
See attachment for proper table
Solving (a): The missing probability
First, we add up the given probabilities
[tex]Sum = 0.242+0.047+0.079+0.391+0.098[/tex]
[tex]Sum = 0.857[/tex]
The total probability must add up to 1.
If the missing probability is x, then:
[tex]x + 0.857 = 1[/tex]
Collect like terms
[tex]x = -0.857 + 1[/tex]
[tex]x = 0.143[/tex]
Solving (b): P(High | Cancer)
This is calculated as:
[tex]P(High\ |\ Cancer) = \frac{n(High\ n\ Cancer)}{n(Cancer)}[/tex]
So, we have:
[tex]P(High\ |\ Cancer) = \frac{0.079}{0.242+0.047+0.079}[/tex]
[tex]P(High\ |\ Cancer) = \frac{0.079}{0.368}[/tex]
[tex]P(High\ |\ Cancer) = 0.215[/tex]
Solving (c): P(Leukemia) independent of P(High Wiring)
From the attached table
[tex]P(Leukemia\ n\ High\ Wiring) = 0.242[/tex]
[tex]P(Leukemia) = 0.242 + 0.391 =0.633[/tex]
[tex]P(High\ Wiring) = 0.242+0.047+0.079=0.368[/tex]
If both events are independent, then:
[tex]P(Leukemia\ n\ High\ Wiring) = P(Leukemia) * P(High\ Wiring)[/tex]
[tex]0.242 = 0.633 * 0.368[/tex]
[tex]0.242 \ne 0.232[/tex]
Since the above is an inequality, then the events are not independent
© Find the quotient of 3/8 and ,4/9
Give your answer as a fraction in its simplest form.
[tex] \frac{3}{8} \div \frac{4}{9} \\ = \frac{3}{8} \times \frac{9}{4} \\ = \frac{27}{32} [/tex]
Hope it helps!!!
Thanks!!!
In ΔCDE, the measure of ∠E=90°, ED = 28, CE = 45, and DC = 53. What ratio represents the tangent of ∠C?
Answer:
3/5
Step-by-step explanation:
prependicular / hypotenuse
sin C=ED/CD
=3/5
Question 18 (5 points)
Determine the sum of the measures of the interior angles of a dodecagon (12-sided
polygon).
540°
1,800°
360°
2,160°
Answer:
its 540 bro
Step-by-step explanation:
Really struggling with these problems please help!
Solve.
[tex] \sqrt{10y + 24} - 3 = y + 1[/tex]
Answer:
[tex]y_1 = -2[/tex] and [tex]y_2 = 4[/tex]
Step-by-step explanation:
[tex] \sqrt{10y + 24} - 3 = y + 1[/tex]
Move the constant to the right-hand side and change their sign.
[tex] \sqrt{10y + 24} = y + 1 + 3 [/tex]
combine like terms
[tex] \sqrt{10y + 24} - 3 = y + 4[/tex]
Square both side to remove square brackets.
10y + 24 - 3 = y²+ 8y + 16
Move the expression to the left-hand side and change its sign.
10y + 24 - y² - 8y - 16 = 0
Combine like terms
10y - 8y + 24 - 16 - y² = 0
2y + 8 - y² = 0
Use commutative property to reorder the terms.
-y² + 2y + 8 = 0
Change the sign of expression.
y² -2y -8 = 0
split -2y
y² + 2y - 4y - 8 = 0
Factor out y from the first pair and -4 from the second equation.
y ( y + 2 ) - 4 ( y + 2 ) = 0
Factor out y+2 from the expression.
( y + 2 ) ( y - 4)
When the products and factors equals 0, at least one factor is 0.
y + 2 = 0
y - 4 = 0
Solve for y
y = -2
y = 4
When we plug the both solution as y we found that both is true solution of this equation.
This equation has two solutions which are -2 and 4.
Answer:
Solution given:
[tex] \sqrt{10y + 24} - 3 = y + 1[/tex]
keep the constant term in one side
[tex] \sqrt{10y + 24} =y+1+3[/tex]
solve possible one
[tex]\sqrt{10y+24}=y+4[/tex]
now
squaring both side
[tex](\sqrt{10y+24})²=(y+4)²[/tex]
10y+24=y²+8y+16
taking all term on one side
10y+24-y²-8y-16=0
solve like terms
8+2y-y²=0
doing middle term factorisation
8+4y-2y-y²=0
4(2+y)-y(2+y)=0
(2+y)(4-y)=0
either
y=-2
or
y=4
y=-2,4
Plis help me it’s for today
Answer:
Following are the solution to the given points:
Step-by-step explanation:
For question 1:
[tex]\to 3^{-4}= \frac{1}{3^4}=\frac{1}{81}=0.0123456789[/tex]
For question 2:
[tex]\to (-2)^{3}\cdot(-2)^{4}\cdot(-2)^{-1}=-8\cdot-16\cdot -\frac{1}{2}= 128\cdot -\frac{1}{2}=-64[/tex]
For question 3:
[tex]\to 7^{-4} \div 7^{-2}= \frac{1}{7^{4}} \div \frac{1}{7^{2}}=\frac{1}{7^{4}} \times \frac{7^{2}}{1}=\frac{1}{7^{2}} =\frac{1}{49} =0.0204081633[/tex]
For question 4:
[tex]\to [(-3)^{2}]^3= (-3)^{2\cdot 3}= (-3)^{6}=729[/tex]
For question 5:
[tex]\to [5 \cdot (-3)]^{2}= 25 \cdot 9=225[/tex]
For question 6:
[tex]\to [(10 \div 5)]^{3}= [(\frac{10}{5})]^{3}=[2]^{3}=8[/tex]
For question 7:
[tex]\to 10^6 \cdot 10^{-4} \cdot 10^2= 10^6 \cdot \frac{1}{10^{4}} \cdot 10^2= 10^2 \cdot 10^2=10^4=10,000[/tex]
For question 8:
[tex]\to (-4)^{-5}=\frac{1}{(-4)^{5}}=- \frac{1}{1,024}=-0.0009765625[/tex]
For question 9:
[tex]\to \frac{2^3}{2^4}= \frac{8}{16}=\frac{1}{2}=0.5[/tex]
For question 10:
[tex]\to (-6)^3 \cdot (-6)^5 \cdot (-6)^{-5}= (-6)^3 \cdot (-6)^5 \cdot \frac{1}{(-6)^{5}}= (-6)^3 =-216[/tex]
is Catholic Schools bad?
Answer:
Not really。。
Step-by-step explanation:
this school had remained excellent。students grduating from these school have higher ACT scores
I forgot to label the triangle below! I just know that the cos A = 0.48. Based on this information, which angle should be marked A?
Answer:
angle 1
Step-by-step explanation:
Using the trigonometric mnemonic SOH CAH TOA, we know that cos or cosine is the ratio between the adjacent side and hypotenuse side.
This means that if cos A = 0.48, A is the measure of the angle which it's relative adjacent side divided by the hypotenuse of the triangle will be around 0.48.
Let's try angle 2, cos (angle 2) = adjacent / hypotenuse = 7.8 / 8.9 = 0.876404494382 ≈ 0.87 ≠ 0.48. Since the proportions are not equal, this angle cannot be the one marked as A.
Since angle 3 is a right angle, the adjacent could be either side so it cannot be correct. Thus angle 1 is correct.
Which point is a solution to the inequality shown in this graph
Answer: C. (0, -3)
Step-by-step explanation:
You don't even need to find the function, just mentally graph every point in the options on the graph.
If it land in the white area, it's not a solution.If it land in the blue area or on the line, it's a solution.The line is not dotted, showing that the inequality is probably either ≥ or ≤, so points on the line do count as solution.
If f(x) = 3x + 10 and g(x) = 2x - 4, find (f+g)(x).
O A. (f+g)(x) = -34 - 2x - 14
B. (f+ g)(x) = 3x - 2x + 14
O C. (f+ g)(x) = 5x + 6
D. (f+ g)(x) = 3x + 2x + 6
Help! I’m getting really confused which one it is
Answer:
O D
Step-by-step explanation:
f+g(x)
3x+10+2x-4
3x +2x+6