Select the correct answer. Jennifer, a construction manager at a construction firm, has to hire several contractors and subcontractors for a new project. She negotiates and finalizes contracts with the selected contractors and subcontractors. Which responsibility of a construction manager does Jennifer portray? A. project planning B. time management C. contract administration D. quality management

Answer:

Rubber Mallet

Explanation:

It is the most common types of hammers, it has a rubber head that allows a soft bang. They are used on sheet metal, woodworking, and filling. A rubber mallet is soft enough to force it without damaging the plasterboard.

Answer:

D. Hydrostatics

Explanation:

The term hydrostatic is defined as the science of fluids with no motion. In this definition a fluid is a substance that flows continually when a shear stress is applied. A fluid can be liquids or gases.

A fluid at rest can experience shear stresses mainly caused by friction between fluid particles caused by fluid viscosity. Such fluids can not resist this type of stress hence they will move in respond to the shear stress applied.

Answer: drive

Explanation:

The best word that would fit this sentence is drive. A vehicle owner should know how to drive, and they can get their vehicle checked by a qualified technician. The best word that would fit this sentence is drive. If you have power steering and you are able to drive, you should have your vehicle checked by a qualified technician.

Answer:

speed, and using light

Explanation:

Answer:

A moving inclined plane is called a wedge.

Answer:

340 mph

Explanation:

Answer:

1

Explanation:

Given :

i=7;j=8;k=9;

printf(“%d”,(i+10)%k/j);

The printf function only displays the result

%d - is used for the display format

However, the actual calculation is in the expression: (i+10)%k/j

Given the variables :

i = 7 ;

j = 8 ;

k = 9 ;

(i + 10) = (7 + 10) = 17

(i + 10) % k = 17 % 9

% = remainder value after division

17 % 9 = (17 / 9) = 1 remainder 8

17 % 9 = 8

Hence,

(i + 10) % k = 8

(i + 10) % k / j

j = 8

8 / 8

= 1

Answer:

498 mm

Explanation:

The height of the tire sidewall is ; 117 mm

The height of the rim of the tire is: 381 mm

Total height of the rim and tire together is : 117 + 381 = 498 mm

Answer:

hope this helps!

Explanation:

Answer:

A convertible jacket/poncho that can transform into a floatation device

Explanation:

A product concept normally on the assumption that it will attract customers to select the product due to its better qualities, features and performances.

A product concept is important because it will makes it necessary for a marketer to meet the demands and the wishes of users by delivering the best product.

Answer:

its only 50 points

Explanation:

Answer:

Solve the problem

Explanation:

The statement is : The team requests bids from a vendor to offer alternatives to raw materials that are too expensive for the proposed

price of the tablet.

The team wanted vendors to submit bids so that it can choose an alternative to raw materials to replace those that were expensive as compared to previous proposed price of a tablet. This is a process of solving the problem to identify a better solution.

Answer:

forwarder

Explanation:

Answer: from what i know im pretty sure its isometrics or sketches im certain its sketches but not 100%

Explanation: A sketch is a rapidly executed freehand drawing that is not usually intended as a finished work. A sketch may serve a number of purposes: it might record something that the artist sees, it might record

Answer: Sketches

Explanation:

Explanation:

Trigonometric table :-

[tex]\begin{gathered}\begin{gathered}\begin{array}{ |c |c|c|c|c|c|} \bf\angle A & \bf{0}^{ \circ} & \bf{30}^{ \circ} & \bf{45}^{ \circ} & \bf{60}^{ \circ} & \bf{90}^{ \circ} \\ \\ \rm sin A & 0 & \dfrac{1}{2}& \dfrac{1}{ \sqrt{2} } & \dfrac{ \sqrt{3} }{2} &1 \\ \\ \rm cos \: A & 1 & \dfrac{ \sqrt{3} }{2}& \dfrac{1}{ \sqrt{2} } & \dfrac{1}{2} &0 \\ \\ \rm tan A & 0 & \dfrac{1}{ \sqrt{3} }& 1 & \sqrt{3} & \rm Not \: De fined \\ \\ \rm cosec A & \rm Not \: De fined & 2& \sqrt{2} & \dfrac{2}{ \sqrt{3} } &1 \\ \\ \rm sec A & 1 & \dfrac{2}{ \sqrt{3} }& \sqrt{2} & 2 & \rm Not \: De fined \\ \\ \rm cot A & \rm Not \: De fined & \sqrt{3} & 1 & \dfrac{1}{ \sqrt{3} } & 0 \end{array}\end{gathered}\end{gathered}[/tex]

Explanation:

[tex]\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\sf Trigonometry\: Table \\ \begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\boxed{\begin{array}{ |c |c|c|c|c|c|} \bf\angle A & \bf{0}^{ \circ} & \bf{30}^{ \circ} & \bf{45}^{ \circ} & \bf{60}^{ \circ} & \bf{90}^{ \circ} \\ \\ \rm sin A & 0 & \dfrac{1}{2}& \dfrac{1}{ \sqrt{2} } & \dfrac{ \sqrt{3}}{2} &1 \\ \\ \rm cos \: A & 1 & \dfrac{ \sqrt{3} }{2}& \dfrac{1}{ \sqrt{2} } & \dfrac{1}{2} &0 \\ \\ \rm tan A & 0 & \dfrac{1}{ \sqrt{3} }&1 & \sqrt{3} & \rm \infty \\ \\ \rm cosec A & \rm \infty & 2& \sqrt{2} & \dfrac{2}{ \sqrt{3} } &1 \\ \\ \rm sec A & 1 & \dfrac{2}{ \sqrt{3} }& \sqrt{2} & 2 & \rm \infty \\ \\ \rm cot A & \rm \infty & \sqrt{3} & 1 & \dfrac{1}{ \sqrt{3} } & 0\end{array}}}\end{gathered}\end{gathered}\end{gathered} \end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}[/tex]

Trigonometric table :-

[tex]\begin{gathered}\begin{gathered}\begin{array}{ |c |c|c|c|c|c|} \bf\angle A & \bf{0}^{ \circ} & \bf{30}^{ \circ} & \bf{45}^{ \circ} & \bf{60}^{ \circ} & \bf{90}^{ \circ} \\ \\ \rm sin A & 0 & \dfrac{1}{2}& \dfrac{1}{ \sqrt{2} } & \dfrac{ \sqrt{3} }{2} &1 \\ \\ \rm cos \: A & 1 & \dfrac{ \sqrt{3} }{2}& \dfrac{1}{ \sqrt{2} } & \dfrac{1}{2} &0 \\ \\ \rm tan A & 0 & \dfrac{1}{ \sqrt{3} }& 1 & \sqrt{3} & \rm Not \: De fined \\ \\ \rm cosec A & \rm Not \: De fined & 2& \sqrt{2} & \dfrac{2}{ \sqrt{3} } &1 \\ \\ \rm sec A & 1 & \dfrac{2}{ \sqrt{3} }& \sqrt{2} & 2 & \rm Not \: De fined \\ \\ \rm cot A & \rm Not \: De fined & \sqrt{3} & 1 & \dfrac{1}{ \sqrt{3} } & 0 \end{array}\end{gathered}\end{gathered}[/tex]