A 10 kg weight is suspended in the air by a strong cable. How much work is done, per unit time, in suspending the weight

Answers

Answer 1

Answer:

There is no work done.

Explanation:

Given the following data;

Mass = 10 kg

To find the work done?

In Physics, work done can be defined as the amount of energy transfered when an object or body is moved over a distance due to the action of an external force.

Mathematically, work done is given by the formula;

Work done = force * distance

[tex] W = F * d[/tex]

Where,

W is the work doneF represents the force acting on a body. d represents the distance covered by the body.

However, the weight suspended in the air by a strong cable does not move or experience any form of displacement. Therefore, there is no work done.


Related Questions

For an organism to survive, it must acquire energy. What is an example of acquiring energy?
Question 3 options:


healing a cut or wound


eating an apple


sweating


running

answer quick plz

Answers

Answer:

eating an apple

Explanation:

Eating food gives your body the nutrients and energy it needs.

Which has more volume a liter of a quart?
1. A quart
2. Both are the same
3. Neither describes volume
4. A liter

Answers

answer 4, liter
it’s not the same and it does describe volume

Supplements are designed to replace a meal.
True
False

Answers

Answer:

the answer to your question is false.

If a dog that has moved has a displacement of zero, it means that the dog's initial position and final position are the same. Is it T or F

Answers

Answer:

true

Explanation:

the dog hasn't moved, displacement has direction, and there is no movement or direction involved, his final position and initial are the same

A television connected to a 120 V line uses 102 Watts of power. How much current flows through it?
a. 12240 amps
b. 0.85 amps
c. 0.85 Watts

Answers

Answer: 0.85amps

Explanation: Power = 102watts; Voltage = 120voltsP = IxV ; I = P divided by V = 102 divided by 120 = 0.85amps

The human nervous system can propagate nerve impulses at about 102 m>s. Estimate the time it takes for a nerve impulse to travel 2 m from your toes to your brain.

Answers

Answer:

t = 0.196 s

Explanation:

The speed of a pulse is determined by the characteristics of the medium, its density and its resistance to stress, as long as these remain the speed will be constant for which we can use the kinetic expressions of the uniform movement

          v = x / t

          t = x / v

calculate

          t = 2/102

          t = 0.196 s

What is the maximum mass that can hang without sinking from a 50-cm diameter Styrofoam sphere in water

Answers

This question is incomplete, the complete question is;

Styrofoam has a density of 32kg/m³.

What is the maximum mass that can hang without sinking from a 50-cm diameter Styrofoam sphere in water

Answer: the required maximum mass is 63.3459 kg

Explanation:

Given that;

diameter d = 50 cm = 0.5 m

radius r = 0.5 / 2 = 0.25 m

Styrofoam density = 32kg/m³

Volume of sphere V = 4/3 πr³.

we substitute

V = 4/3 π(0.25)³

V = 0.06544 m³

Mass of sphere M = Volume × Density

we substitute

Mass of sphere M = 0.06544 m³ × 32kg/m³

Mass of Sphere M = 2.09408 kg

Mass of the water it displace will be;

volume × density

we know that density of water = 1000 kg/m³

so

Mass of the water it displace = 0.06544 m³ × 1000kg/m³

= 65.44 kg

Now the difference between mass of water and mass of the Styrofoam will be the amount of mass that the sphere can support

so

65.44 kg - 2.09408 kg = 63.3459 kg

Therefore, the required maximum mass is 63.3459 kg

Find the magnitude of the impulse delivered to a soccer ball when a player kicks it with a force of 1360 N. Assume that the player's foot is in contact with the ball for 5.85 times 10^{-3} s. (Show your work)
please

Answers

Answer:

7.59Ns

Explanation:

Given parameters:

Force  = 1360N

Time of contact  = 5.85 x 10⁻³s

Unknown:

Impulse  = ?

Solution:

The impulse of the ball is given as:

        Impulse  = Force x time

       Impulse  = 1360 x 5.85 x 10⁻³ = 7.59Ns

Is this statement true or false?

Tornadoes are accompanied by spinning downdrafts and updrafts that form a funnel cloud.

Answers

Answer:

true true true true true

True true true true true

Gizmo Warm-up: Lifting a piano A pulley is a simple machine that is used to lift heavy objects. A pulley is a wheel with a groove for a rope. Pulling down on one end of the rope causes the other end to pull up. In the Object to lift menu choose Piano. What is the weight of the piano

Answers

Answer:

bruuuuuuuuh

Explanation:

id                  

If a man traveled to a different planet

Answers

Answer:

He would be in space.

Explanation:

Answer: What would happen if a human traveled to Uranus?

As an ice giant, Uranus doesn't have a true surface. The planet is mostly swirling fluids. While a spacecraft would have nowhere to land on Uranus, it wouldn't be able to fly through its atmosphere unscathed either. The extreme pressures and temperatures would destroy a metal spacecraft.

Explanation:

What is the balance of
C2H6=C2H4+H2

Answers

Answer:

I don't get the question

What must be the length of a simple pendulum if its oscillation frequency is to be equal to that of an air-track glider of mass 0.250 kg attached to a spring of force constant 9.75 N/m

Answers

Answer:

the length of the simple pendulum is 0.25 m.

Explanation:

Given;

mass of the air-track glider, m = 0.25 kg

spring constant, k = 9.75 N/m

let the length of the simple pendulum = L

let the frequency of the air-track glider which is equal to frequency of simple pendulum = F

The oscillation frequency of air-track glider is calculated as;

[tex]F = \frac{1}{2\pi } \sqrt{\frac{k}{m} } \\\\F = \frac{1}{2\pi } \sqrt{\frac{9.75}{0.25} } \\\\F = 0.994 \ Hz[/tex]

The frequency of the simple pendulum is given as;

[tex]F = \frac{1}{2\pi} \sqrt{\frac{g}{l} } \\\\2\pi(F) = \sqrt{\frac{g}{l} } \\\\2\pi (0.994) = \sqrt{\frac{9.8}{l} } \\\\6.2455 = \sqrt{\frac{9.8}{l} } \\\\(6.2455)2 = \frac{9.8}{l} \\\\39.006 = \frac{9.8}{l} \\\\l = \frac{9.8}{39.006} \\\\l = 0.25 \ m[/tex]

Thus, the length of the simple pendulum is 0.25 m.

Does Newton’s 1st Law of Motion apply to sports

Answers

Answer: Yes indeed it does.

Explanation: Newton's Three Laws of Motion explain how forces create motion in sport. These laws are usually referred to as the Laws of Inertia, Acceleration, and Reaction. maybe brainliest to level up.

A 200-kg car is moving at 50 mis. What is the kinetic energy of the car? show

Answers

Answer:

Ekin = 250000 [J]

Explanation:

The kinetic energy of a body or object can be calculated based on the mass and the speed with which it moves. This energy can be easily calculated by means of the following equation.

[tex]E_{kin}=\frac{1}{2} *m*v^{2}[/tex]

where:

m = mass = 200 [kg]

v = velocity = 50 [m/s]

Now replacing:

[tex]E_{kin}=\frac{1}{2} *200*(50)^{2}\\E_{kin}=250000[J][/tex]

Two laboratories use radiocarbon dating to measure the age of two wooden boat fragments found at the site of an ancient
shipwreck. Lab A finds an age of 515 +/-20 years for the first object; lab B finds an age of 585 +/-30 years for the second
object. Which of the following is true?
a. Lab B's reading is more accurate than Lab A's.
b. Lab B's reading is less accurate than Lab A's.
Lab B's reading is more precise than Lab A's.
d Lab B's reading is less precise than Lah A's
C

Answers

Answer:

Answer d) Lab B's reading is less precise than Lab A's

Explanation:

Recall that accuracy is a measure of how close to the actual physical quantity the experiment leads to. In this case, we don't know what the true age is,so we cannot tell which reading is more accurate.

But we can tell which reading is more precise given the value of their reported errors. Since Lab A shows a smaller error in years (+/- 20 years versus 30 years), as well as a smaller percent error (3.9% versus 5.1%), we can say that Lab's A reading is more precise than Lab B's reading.

This agrees with answer labeled d).

3.) Brady walks 5 meters forward, turns right, walks 25 meters, turns right again, walks 5
meters, then turns left and walks 10 meters. What are Brady's distance and
displacement?

Answers

Answer:

Distance covered is: 45 meters

Displacement is 15 meters to the right of where he started

Explanation:

Notice that Brady has walk a path that looks like an incomplete rectangle of height 5 meters and length 25meters, although he actually didn't cover the full length (25 meters) when getting back to the point where he started (he made just 10 meters instead of 25 after the third turn right) See attached image.

Therefore, Brady's displacement is 15 meters to the right of where he started, and the total distance he covered is :

Distance = 5m + 25m + 5m + 10m = 45m

Scientists create models to better understand Earth. Which evidence has led scientists to conclude that there are different layers within Earth's interior?

A.analysis of seismic wave data


B.measurement of Earth's diameter


C.temperatures taken within each layer


D.rock samples taken from Earth's core

Answers

Answer:

it is A or D

Explanation:

     

Answer:

ANswer:A

Explanation:

Help me with this, I'm being timed.

Answers

Answer:

I guess C

Explanation:

cause you can just try with hot water and ice cubes you know.

and we all know that ice will melt and the hot tea will get cold.

Answer:

D option

Explanation:

heat move from hot source to cold sink untill equilibrium reached

In a particular crash test, an automobile of mass 1577 kg collides with a wall and bounces back off the wall. The x components of the initial and final speeds of the automobile are 17 m/s and 1.5 m/s, respectively. If the collision lasts for 0.18 s, find the magnitude of the impulse due to the collision. Answer in units of kg · m/s.

Answers

Answer:

Ft=24,443.5 kgm/s

Explanation:

Step one

Given data

Mass of automobile m=1577kg

Initial Velocity u=17m/s

Final Velocity v=1.5m/s

Time t=0.18s

Step two

From the impulse and momentum equation

Ft=mΔv

Substitute

Ft=1577*(17-1.5)

Ft=1577*15.5

Ft=24,443.5 kgm/s

What is the difference between a graph of linear motion and a graph of harmonic motion?

Answers

Hope this helps :)

When describing linear motion, you need only one graph representing each of the three terms, while projectile motion requires a graph of the x and y axes. Graphs of simple harmonic motion are sine curves. Circular motion is different from other forms of motion because the speed of the object is constant.

A force of 40 N accelerates a 5 block at 6 m/s ^ 2 along a horizontal surface a. What would the block's acceleration be if the surface were frictionless. b. How large is the kinetic friction force? cWhat is the coefficient of kinetic friction?

Answers

Answer:

a = 8 m/s^2, Ffriction = 10 N, μk = 0.205

Explanation:

a. Force = Mass*Acceleration,

(since you didn't add the units..."5 block"....for the mass, I will assume it to be in kg, per SI units)

40 N = 5 kg*acceleration,

a = 40/5 = 8 m/s^2

b. As you know newtons second law (F=m*a) is actually in the form Fnet = m*a. Which means that if the friction force comes into play, it would be Fapplied - Ffriction = m*a.

Fapplied - Ffriction = m*a,

40 - Ffriction = 5*6,

40 - Ffriction = 30,

Ffriction = 40 - 30 = 10 N

c. The coefficient of kinetic friction is calculated by the formula "Ffriction = μk*Fnormal".

10 = μk*Fnormal (Fnormal = m*g = 5*9.8)

10 = μk*49,

μk=10/49 ≈ 0.205

A simple pendulum is constructed by hanging a 3 kg mass on the end of a 0.8 m long string. The pendulum is pulled back to a height of 0.2 m and released. At what time will the mass first reach its maximum velocity

Answers

Answer:

The time when the mass will reach its first maximum velocity  is 1.8 s.

Explanation:

Given;

mass of the pendulum, m = 3 kg

length of the pendulum, l = 0.8 m

height in which the pendulum is raised to, h = 0.2 m

the mass will reach its first maximum velocity when it returns to its initial position, i.e at the middle (x = 0).

the distance between the initial position of the pendulum and the height in which it is raised is the maximum displacement (A).

If we form a right angle triangle with respect to the height in which the pendulum is raised;

the height of the right triangle, H = L - 0.2 = 0.8 - 0.2 = 0.6 m

the hypotenuse side, = L = 0.8 m

the base of the triangle (opposite side) = A

A² = L² - H²

A² = (0.8)² - (0.6)²

A² = 0.28

A = √0.28

A = 0.529 m

The maximum velocity of the pendulum is calculated as;

[tex]V_{max} = A \omega\\\\V_{max} = A \sqrt{\frac{g}{l} } \\\\V_{max} = (0.529)\sqrt{\frac{9.8}{0.8} }\\\\V_{max} = 1.852 \ m/s[/tex]

The period is calculated as;

[tex]V_{max} = A\omega\\\\V_{max} = A (\frac{2\pi}{T} )\\\\T = \frac{2\pi A }{V_{max}}\\\\T = \frac{2\pi \ \times \ 0.529}{1.852} \\\\T = 1.8 \ s[/tex]

Therefore, the time when the mass will reach its first maximum velocity  is 1.8 s.

What does a neutron look like

Answers

A neutron is part of an atom

PLEASE PLEASE HELP!!!!

Answers

Which ones do you need help with?

Which term is applied to an object through which light passes?
A. Absorbent
B. Opaque
C. Reflective
D. Transparent

Answers

Answer:

D

Explanation:

transparent_objects that allows light to pass through and can you see through them

If a 15kg mass weighs 372 N on Jupiter, what is Jupiter's gravitational acceleration?

Answers

Answer:

Jupiter's gravitational acceleration is 24.8 m/s^2

Explanation:

Recall that the weight under the influence of a gravitational acceleration G is defined as:

Weight = m * G

Then, in our case we have

372 N = 15 kg * G

G = 372/15  m/s^2

G = 24.8 m/s^2

Which title goes with this list: Amendments Articles Preamble?
A. Florida and County Government
B. Florida and U.S. Government
C. City and County Government
D. City and U.S. Government

Answers

D. City and U.S. Government, but I’m not sure what the context is though.

A 450-N rightward force is used to drag a large box across the floor with a constant velocity of 1.2 m/s. The coefficient of friction between the box and the floor is 0.795. Determine the mass of the box.

Answers

Answer:

the mass of the box is 51.98 kg.

Explanation:

Given;

applied horizontal force, F = 450 N

coefficient of friction, μ = 0.795

constant velocity, v = 1.2 m/s

At constant velocity, the acceleration of the object is zero and the net force will be zero.

[tex]F_{Net} = F - F_k\\\\0 = F - F_k\\\\F_k = F\\\\\mu \ N = F\\\\\mu (mg) = F\\\\m = \frac{F}{\mu g} \\\\m = \frac{405}{0.795 \ \times \ 9.8} \\\\m = 51.98 \ kg[/tex]

Therefore, the mass of the box is 51.98 kg.

a student connects an object with mass m to a rope with a length r and then rotates the rope around her head parallel to the ground. the object takes 0.5 seconds to complete one rotation.
mass= 50 kg. length of the rope = 1.2 m
what is the objects speed of rotation?
what is the objects centripetal acceleration?
what tension force is required to maintain this motion?​

Answers

The object takes 0.5 seconds to complete one rotation, so its rotational speed is 1/0.5 rot/s = 2 rot/s.

Convert this to linear speed; for each rotation, the object travels a distance equal to the circumference of its path, or 2π (1.2 m) = 2.4π m ≈ 7.5 m, so that

2 rot/s = (2 rot/s) • (2.4π m/rot) = 4.8π m/s ≈ 15 m/s

thus giving it a centripetal acceleration of

a = (4.8π m/s)² / (1.2 m) ≈ 190 m/s².

Then the tension in the rope is

T = (50 kg) a9500 N.

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