Represent a vector of 100 N in North-East direction

Answer:

The speed stays constant after the force stops pushing.

Explanation:

Speed always stays constant when the force stops pushing it.

Answer:

Explanation:

given, work function of Φ = 2.46 eV.

converting the eV to joule, we have

2.45 * 1.6*10^-19 J

The cutoff wavelength is the wavelength where the incoming light does not have enough energy to free an electron, i.e. all of

the photon’s energy will be channeled into trying overcoming the work function barrier.

It is mathematically given as

Φ = hf

f = Φ/h

f = (2.46 * 1.6*10^-19) / 6.63*10^-34

f = 3.936*10^-19 / 6.63*10^-34

f = 5.94*10^14 Hz as our cut off frequency

λf = c,

λ = c/f

λ = 3*10^8 / 5.94*10^14

λ = 5.05*10^-7

λ = 505 nm as our cut off wavelength

K(max) = hf - Φ

K(max) = hc/λ - Φ

K(max) = [(6.63*10^-34 * 3*10^8) / 181*10^-9] - 3.936*10^-19

K(max) = (1.989*10^-25/181*10^-9) - 3.936*10^-19

K(max) = 1.1*10^-18 - 3.936*10^-19

K(max) = 7.064*10^-19 J or 4.415 eV

V(s) = K(max) / e

V(s) = 4.612 V

Answer:

16.26 cm in front of the mirror

Explanation:

Using,

1/f = 1/u+1/v....................... Equation 1

Where f = focal focal length of the concave mirror, u = object distance, v = image distance.

make v the subject of the equation

v = fu/(u-f)................... Equation 2

Note: The focal length of a concave mirror is positive

Using the real- is- positive convention

Given: f = 22/2 = 11 cm, u = 34 cm.

Substitute into equation 2

v = (34×11)/(34-11)

v = 374/23

v = 16.26 cm.

The image will be formed 16.26 cm in front of the mirror.

Answer:

Advertising, events and experiences, and personal selling all become more important in the maturity stage.

Explanation:

In the growth stage, demand has its own momentum through word of mouth and interactive marketing. hope this helps you :)

Answer:

OB.It has definite shape and definite volume

Answer:

a) The planet experiences a centripetal force towards its star

b) The universal attractive force (Gravitational force)

c)None of these choices are true.

Explanation:

This problem raise several claims, let's review some aspects of circular motion

            F = m a

the centripetal acceleration is

            a = v² / r

where v is the speed (modulus of velocity) that is constant and r is the radius

The direction of the acceleration is perpendicular to the motion.

Let's review the different claims

Part a) the orbital velocity is constant

The correct statement is: The planet experiences a centripetal force towards its star

Part b) what is the centripetal force

The correct statement: The universal attractive force (Gravitational force)

Part c) which statement is true

1) False. There can be no tangential force

2) False. There is a centripetal force that creates the movement, but there is no centrifugal force because the system is accelerated and there is no tangential force because the movement is circular.

3) False. There is no tangential force

4) True none is true

5) False. There is a force because movement has acceleration

Answer:

The magnetic force is  [tex]\= F = 400\r j + 2800\r i[/tex]

Explanation:

From the question we are  told that

  The  charge is  [tex]q = -5C[/tex]

  The  velocity is  [tex]v = (1.00\ \r i + 7.00 \ \r j )\ m/s[/tex]

   The  magnetic field is  [tex]B = 80 \r k \ \ T[/tex]

Generally the magnetic force is mathematically represented as

        [tex]\= F = q \= v \ \ X \ \ \= B[/tex]

=>     [tex]\= F = -5 (1.0 \r i + 7.0 \r j ) \ \ X \ \ 80 \r k[/tex]

=>    [tex]\= F = -5.0 \r i + 35\r j \ \ \ X \ \ 80\r k[/tex]

=>  [tex]\= F = 400\r j + 2800\r i[/tex]    N/B - Applied cross - product of unit vector

Answer:

24.7°C

Explanation:

Heat lost by brass = heat gained by aluminum and water

-q = q

-mCΔT = mCΔT + mCΔT

-(50 g) (0.380 J/g/°C) (T − 200°C) = (50 g) (0.900 J/g/°C) (T − 20°C) + (160 g) (4.186 J/g/°C) (T − 20°C)

-(19 J/°C) (T − 200°C) = (45 J/°C) (T − 20°C) + (670 J/°C) (T − 20°C)

-(19 J/°C) (T − 200°C) = (715 J/°C) (T − 20°C)

-19 (T − 200°C) = 715 (T − 20°C)

-19T + 3800°C = 715T − 14300°C

18100°C = 734T

T = 24.7°C

Answer:

What is the intensity is 1.3349 × 10⁻⁷ w/m²

Explanation:

Given that;

λ = 582 nm = 582 × 10⁻⁹

R = 75.0 cm = 0.75 m

d = 0.640 mm = 0.000640 m

a = 0.434 mm = 0.000434 m

I₀ =  4.40×10⁻⁴ W/m²

y = 0.710 mm  = 0.00071 m

Now to get our tanФ we say

tanФ = y/R =  0.00071 / 0.75 = 0.0009466  

Ф is so small

∴ tanФ ≈ sinФ

So

∅ = 2πdsinФ / λ

we substitute

∅ = ( 2π × 0.000640 × 0.0009466  ) /  582 × 10⁻⁹

=  6.54 rad

Now

β = 2πasinФ / λ

we substitute

β = ( 2π × 0.000434 × 0.0009466  ) /  582 × 10⁻⁹

β = 4.435 rad

I = I₀ cos²(∅/2) [(sin(β/2))/(β/2)]²

we substitute

I = 4.40×10⁻⁴ cos(3.27)² [ (sin(2.2175)) / (2.2175) ]²  

= 4.40×10⁻⁴ × 0.9967 × 0.0003044

= 1.3349 × 10⁻⁷ w/m²

Answer:

mA=2,mB=4

mA=2,mB=4 and

mA=3,mB=6

Explanation:

First of all we need to write the equation of the networks

sin θ = mA λ / dA

sin θ = mB λ / dB

Equating we have

mA λ/ dA = mB λ / dB

We are given the ratio as

dB / dA = 2

So

mA 2 = mB

Finally overlapping orders

We have

mA=2,mB=4

mA=2,mB=4

and mA=3,mB=6

Answer:

allows for better thermal equilibrium

Explanation:

Due to the cone shape, most of the liquid will be closer to the bottom than the top.  The large surface area of the bottom allows for faster heating.

Answer:

To find out the area of the hot filament of a light bulb, you would need to know the temperature, the power input, the Stefan-Boltzmann constant and Emissivity of the Filament.

Explanation:

The emissive power of a light bulb can be given by the following formula:

E = σεAT⁴

where,

E = Power Input or Emissive Power

σ = Stefan-Boltzmann constant

ε = Emissivity

A = Area

T = Absolute Temperature

Therefore,

A = E/σεT⁴

So, to find out the area of the hot filament of a light bulb, you would need to know the temperature, the power input, the Stefan-Boltzmann constant and Emissivity of the Filament.

Answer:

t = 7.5 s

Explanation:

The distance traveled by the car at the time of meeting of the two cars must be the same. First, we calculate the distance traveled by the police car. For that we use 2nd equation of motion. Here, we take the time when police car starts to be reference. So,

s₁ = Vi t + (0.5)gt²

where,

s₁ = distance traveled by police car

Vi = Initial Velocity = 0 m/s

t = time taken

Therefore,

s₁ = (0 m/s)(t) + (0.5)(9.8 m/s²)t²

s₁ = 4.9 t²

Now, we calculate the distance traveled by the car. For constant speed and time to be 1 second more than the police car time, due to car starting time, we get:

s₂ = Vt = V(t + 1)

where,

s₂ = distance traveled by car

V = Velocity of car = (100 km/h)(1000 m/1 km)(1 h/ 3600 s) = 27.78 m/s

Therefore,

s₂ = 27.78 t + 27.78

Now, we know that at the time of meeting:

s₁ = s₂

4.9 t² = 27.78 t + 27.78

4.9 t² - 270.78 t - 27.78 = 0

solving the equation and choosing the positive root:

t = 6.5 s

since, we want to know the time from the moment car crossed police car. Therefore, we add 1 second of starting time in this.

t = 6.5 s + 1 s

t = 7.5 s

Answer

The potential energy is  less

Explanation:

From the question we are told that

   The  source of  the emf is  by wires to a resistor.

Now  the potential energy of electron before leaving the source emf will be greater than the potential energy of an electron after leaving the source of emf because the resistor connected to the source emf will reduced the potential energy as it will convert some of the energy to heat

The potential energy of an electron after leaving the source of emf is lesser.

Electro motive force is the voltage or potential difference of an electrical energy device such as battery.

The  source of  the emf is  by wires to a resistor.Now,  the potential energy of an electron before leaving the source emf will be greater than the potential energy of an electron.

After leaving the source of emf because the resistor connected to the source of emf will reduce the potential energy as it will convert some of the energy to heat.

Thus the potential energy of an electron after leaving the source of emf is lesser.

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Answer:

A) correct answer is C,   B)   correct answer is b  and C) The correct answer is b

Explanation:

In the exercises of geometric optics, the equation of the constructor tells us the location of the image.

        1 / f = 1 / p + 1 / q

where f is the focal length of the cornea-crystalline system, p and q are the distances to the object and the image.

In this case, the distance to the image on the retina is constant, about 3 cm. Therefore depending on the distance to the object) p = the focal length must change

        1 / q = 1 / f 1 / p

let's apply this expression to our case

A) indicates that the tree is at a medium distance

so that the image is formed on the retina THE SAME AS

correct answer is C

B) The squirrel is at a smaller distance (p ') than the tree (p), therefore if we substitute in the equation above we find that q must decrease. Consequently the image is in front of the retina

The mountain is very far, suppose in infinity, so the image is BEHIND THE RETINA

therefore the correct answer is b

C) The squirrel is very close so the curvature of the lens INCREASES, resulting in a DECREASE in the focal length

The correct answer is b

Answer:

the answers d

A Carnot heat engine and an irreversible heat engine both operate between the same high-temperature and low-temperature reservoirs. They absorb the same energy from the high-temperature reservoir as heat. The irreversible engine cannot absorb the same energy from the high-temperature reservoir as heat without violating the second law of thermodynamics, therefore the correct option is E.

It is a theoretical engine assumed to have the maximum efficiency among all engines out there in the universe.

No other engine can have greater efficiency than the Carnot engine.

The Carnot engine work on the principle of the Carnot cycle which assume that the heat and work tranfer processes are reversible in nature. there is no loss due to the friction of the piston.

As we know from the second law of thermodynamics that no other engine can have greater efficiency than the Carnot engine.

Thus, the irreversible engine cannot absorb the same energy from the high-temperature reservoir as heat without violating the second law of thermodynamics, therefore the correct option is E.

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Answer:

Transverse

Explanation:

It's tranverse because the water molecules are moving repeatedly up and down vertically when the waves move horizontally across the waters surface.

Answer:

See the explanation

Explanation:

Given:

Distance of Firecrackers A and B = 600 m

Event 1 = firecracker 1 explodes

Event 2 = firecracker 2 explodes

Distance of lab partner from cracker A = 300 m

You observe the explosions at the same time

to find:

does event 1 occur before, after, or at the same time as event 2?

Solution:

Since the lab partner is at 300 m distance from the firecracker A and Firecrackers A and B are 600 m apart

So the distance of fire cracker B from the lab partner is:

600 m  + 300 m = 900 m

It takes longer for the light from the more distant firecracker to reach so

Let T1 represents the time taken for light from firecracker A to reach lab partner

T1 = 300/c

It is 300 because lab partner is 300 m on other side of firecracker A

Let T2 represents the time taken for light from firecracker B to reach lab partner

T2 = 900/c

It is 900 because lab partner is 900 m on other side of firecracker B

T2 = T1

900 = 300

900 = 3(300)

T2 = 3(T1)

Hence lab partner observes the explosion of the firecracker A before the explosion of firecracker B.

Since event 1 = firecracker 1 explodes and event 2 = firecracker 2 explodes

So this concludes that lab partner sees event 1 occur first and lab partner is smart enough to correct for the travel time of light and conclude that the events occur at the same time.

Answer:

Initial state    Final state

     3           ⇒        2

     3           ⇒        1

     2          ⇒         1

Explanation:

For this exercise we must use Bohr's atomic model

         E = - 13.606 / n²

where is the value of 13.606 eV is the energy of the ground state and n is the integer.

The energy acquired by the electron in units of electron volt (eV)

          E = e V

          E = 12.5 eV

all this energy is used to transfer an electron from the ground state to an excited state

        ΔE = 13.6060 (1 / n₀² - 1 / n²)

the ground state has n₀ = 1

       ΔE = 13.606 (1 -  1/n²)

        1 /n² = 1 - ΔE/13,606

         1 / n² = 1 - 12.5 / 13.606

         1 / n² = 0.08129

          n = √(1 / 0.08129)

          n = 3.5

 since n is an integer, maximun is

         n = 3

because it cannot give more energy than the electron has

From this level there can be transition to reach the base state.

Initial state    Final state

     3           ⇒        2

     3           ⇒        1

     2          ⇒         1

The possible quantum-jump transitions by which the excited atom emits a photon are :

Initial state    Final state

    3          --->       2

    3          ---->      1

    2          ---->      1

Given data :

Potential difference through which an electron accelerates = 12.5 V

Energy acquired by the the electrons = 12.5 eV  ( e * 12.5 )

The Model we will use to determine the possible quantum jump transition is  Bohr's atomic model

 E = - 13.606 / n²    

where ; n = integer

energy at ground state = 13.606 eV

The energy acquired by the electrons ( 12.5 eV )  is used to move the electron from its ground state to an excited state.

Therefore

ΔE = 13.606 * (1 / n₀² - 1 / n²)  ---- ( 1 )  

where n₀ = 1

Back to equation ( 1 )

ΔE = 13.606 (1 -  1/n²)   -- ( 2 )

Resolving equation ( 2 )

1 / n² = 0.08129

n = 3.5 .    Therefore the maximum integer = 3  

Hence The collision between the electron and the hydrogen atom will undergo three ( 3 ) transition to reach the base state.

In Conclusion The possible quantum-jump transitions by which the excited atom emits a photon are :

Initial state    Final state

    3          --->       2

    3          ---->      1

    2          ---->      1

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Answer:

3.1 × 10^- 7 m and 2.1 × 10^-7 m

Explanation:

First we must convert each value of energy to Joules by multiplying its value by 1.6 ×10^-19. After that, we can now obtain the wavelength from E= hc/λ

Where;

h= planks constant

c= speed of light

λ= wavelength of light

For 6.0ev;

E= 6.0 × 1.6 ×10^-19

E= 9.6 × 10^-19 J

From

E= hc/λ

λ= hc/E

λ= 6.6 × 10^-34 × 3 × 10^8/9.6 × 10^-19

λ= 2.1 × 10^-7 m

For 4.0 eV

4.0 × 1.6 × 10^-19 = 6.4 × 10^-19 J

E= hc/λ

λ= hc/E

λ= 6.6 × 10^-34 × 3 × 10^8/6.4 × 10^-19

λ= 3.1 × 10^- 7 m

(a) The wavelength of the atom's emission spectrum when the energy is 4 eV is [tex]3.1 \times 10^{-7} \ m[/tex]

(b) The wavelength of the atom's emission spectrum when the energy is 6 eV is

[tex]2.1 \times 10^{-7} \ m[/tex]

The wavelength of the atom's emission spectrum is calculated as follows;

[tex]E = hf\\\\E = \frac{hc}{\lambda}[/tex]

where;

For 4 eV;

[tex]\lambda = \frac{hc}{E} \\\\\lambda = \frac{(6.626 \times 10^{-34}) \times 3\times 10^8}{4 \times 1.602 \times 10^{-19}} \\\\\lambda = 3.1 \times 10^{-7} \ m[/tex]

For 6 eV;

[tex]\lambda = \frac{hc}{E} \\\\\lambda = \frac{(6.626 \times 10^{-34}) \times 3\times 10^8}{6 \times 1.602 \times 10^{-19}} \\\\\lambda = 2.1 \times 10^{-7} \ m[/tex]

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Answer:

32.13 N

Explanation:

Given that

mass of the crate, m = 3 kg

angle of inclination, = 35°

coefficient of static friction, = 0.3

To solve this, we can assume that the minimum force is F Newton, then use the formula

mgsinA = coefficient of static friction * [F + mgcosA]

=>3 * 9.8 * sin35 = 0.3 * [F + 3 * 9.8 * cos35]

=> 29.4 * 0.5736 = 0.3 * [F + 29.4 * 0.8192]

=> 16.86 = 0.3 [F + 24.08]

=> 16.86 = 0.3F + 7.22

=> 16.86 - 7.22 = 0.3F

=> 0.3F = 9.64

=> F = 9.64/0.3

=> F = 32.13 N

Therefore, the Force that must be applied is 32.13 N

The  net force that must be applied is  9.8 N.

The minimum force required is Fnet.

Fnet = -Ff + mgsinθ

But Ff = μN = μmgcosθ

Fnet = - μmgcosθ + mgsinθ

Where;

m = 3.00 kg

μ =  0.300

θ = 35.0o

Substituting values;

Fnet = mgsinθ - μmgcosθ

Fnet = (3 × 10 × sin 35.0o) - (3 × 0.300  × 10 × cos  35.0o)

= 17.2 - 7.4

Fnet = 9.8 N

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Answer:

9 Ω

Explanation:

The following data were obtained from the question:

Resistor 1 (R1) = 3 Ω

Resistor 2 (R2) = 3 Ω

Resistor 3 (R3) = 3 Ω

Resistor 4 (R4) = 3 Ω

Resistor 5 (R5) = 3 Ω

Resistor 6 (R6) = 3 Ω

Resistor 7 (R7) = 3 Ω

Resistor 8 (R8) = 3 Ω

Resistor 9 (R9) = 3 Ω

Resistor 10 (R10) = 3 Ω

Resistor 11 (R11) = 3 Ω

Resistor 12 (R12) = 3 Ω

Equivalent Resistance (R) =.?

From the above diagram,

Resistor 1, 2, 3, 4, 5 and 6 are in series connection and in parralle connections with Resistor 7, 8, 9, 10, 11 and 12 which are also in series connection.

Thus we shall determine the equivalent resistance of Resistor 1, 2, 3, 4, 5 and 6

This is illustrated below:

Resistance Ra = R1 + R2 + R3 + R4 + R5 + R6

Ra = 3 + 3 + 3 + 3 + 3 + 3

Ra = 18 Ω

Next, we shall determine the equivalent resistance of Resistor 7, 8, 9, 10, 11 and 12.

This is illustrated below:

Resistance Rb = R7 + R8 + R9 + R10 + R11 + R12

Rb = 3 + 3 + 3 + 3 + 3 + 3

Rb = 18 Ω

Thus, Ra and Rb are in parallel connections. The equivalent resistance between A and B can be obtained as shown below :

Ra = 18 Ω

Rb = 18 Ω

Equivalent resistance R =?

1/R = 1/Ra + 1/Rb

1/R = 1/18 + 1/18

1/R = 2/18

1/R = 1/9

Invert

R = 9 Ω

Therefore, the equivalent resistance between A and B is 9 Ω.

Answer:

y = 1.75 cm

Explanation:

In the double-slit experiment the equation for destructive interference is

           d sin tea = (m + ½)

λ

let's use trigonometry to find the angle

         tan θ = y / L

as all the experiment does not occur at small angles

          tan θ = sin θ / cos θ = sin θ = y / L

we substitute

        y = (m + 1/2 ) λ  L / d

we calculate

         y = (3 + ½) 500 10⁻⁹ 5.00 / 0.5 10⁻³

         y = 1.75 10⁻² m

         y = 1.75 cm

Complete Question

The image for this question is shown on the first uploaded image

Answer:

[tex]v = 3.4 \ m/s[/tex]

Explanation:

From the question we are told that

   The mass of the collar is  [tex]m = 2 \ kg[/tex]

    The original length is  [tex]L = 3.0 \ m[/tex]

     The spring constant is  [tex]k = 3.0 \ N/m[/tex]

Generally the extension of the spring  is  mathematically evaluated as

        [tex]e = 4 -3 = 1 \ m[/tex]

Now with Pythagoras theorem we can obtain the length from A to B as

        [tex]AB = \sqrt{5 ^2 + 4^2}[/tex]

       [tex]AB = 6.4 \ m[/tex]

The  extension of the spring at B is  

     [tex]e_b = 6.4 - 3 = 3.4 \ m[/tex]

According to the law of energy conservation

   The energy stored in the spring at point A +  the kinetic energy of the  spring =  The  energy stored on the spring at B

So

     [tex]\frac{1}{2} * k * e + \frac{1}{2} * m* v^2 = \frac{1}{2} * k * e_b[/tex]

substituting values

    [tex]\frac{1}{2} * 3 * 1^2 + \frac{1}{2} * 2* v^2 = \frac{1}{2} * 3 * 3.4^2[/tex]

=>   [tex]v = 3.4 \ m/s[/tex]

Answer:

5 hours

Explanation:

Given that

Speed of the airplane, v = 400 mile/hr

Distance of the airport, s = 2000 miles

This is quite a straightforward question that deals with one of the basic formulas in physics.

Speed.

speed is said to the the ratio of distance covered with respect to the time taken. This can be mathematically expressed as

Speed, v = distance covered, d / time taken, t

v = d / t

In the question above, we're looking for the time taken. So, so make t, subject of formula.

t = d / v, now we proceed to substituting the earlier given values into this equation.

t = 2000 / 400

t = 5 hrs,

therefore we can conclude that the airplane was airborne for 5 hours

Answer:

98 N.

Explanation:

Given data: mass= 10 kg,      gravity= 9.8 m/s2

required: tension in the cord=  ?

solution:

formula of tension= mass x gravity

by putting values of mass and gravity, we get

tension= 10 x 9.8

tension= 98 N.  Ans

If the mass of the object which is attached with both ends of cord is 10 kg, so the tension which is a opposite force of weight is 98 N.

Answer:

It can be said to be reliable although it is not valid

Explanation:

This is because Reliability means an indicator of consistency, A measure should produce similar or the same results consistently if it measures the same quantity. So does the thermometer measures over 5days but it is not valid because it deviates from the real value

Answer:

Explanation:

With the help of expression of  time period of pendulum we can calculate the height of the branch . The swinging tire can be considered equivalent to swinging bob of a pendulum . Here length of pendulum will be equal to height of branch .

Let it be h . Let the time period of swing of tire be T then from the formula of time period of pendulum

[tex]T = 2\pi\sqrt{\frac{l}{g} }[/tex]  where l is length of pendulum .

here l = h so

[tex]T = 2\pi\sqrt{\frac{h}{g} }[/tex]  

[tex]h = \frac{T^2g}{4\pi^2}[/tex]

If we calculate the time period of swing of tire , we can calculate the height of branch .

The time period of swing of tire can be estimated with the help of a stop watch . Time period is time that the tire will take in going from one extreme point to the other end and then coming back . We can easily estimate it with the help of stop watch .

Answer:

5) 4.00, 2.00, 1.0

Explanation:

wave equation is given as;

F₀ = V / λ

Where;

F₀ is the fundamental frequency = first harmonic

Length of the string for first harmonic is given as;

L₀ = (¹/₂) λ  

λ  = 2 L₀

when L₀ = 1

λ  = 2 x 1 = 2m

when L₀ = 2m

λ  = 2 x 2 = 4m

For First harmonic, the wavelength is 2m, 4m

For second harmonic;

L₁ = (²/₂)λ  

L₁ = λ

When L₁ = 1

λ  = 1 m

when L₁ = 2

λ  = 2 m

For second harmonic, the wavelength is 1m, 2m

Thus, the wavelength that could represent harmonics present on both strings is 4m, 2m, 1 m

Answer:

The  pressure difference is  [tex]\Delta P = 1.46 *10^{5}\ Pa[/tex]

Explanation:

From the question we are told that

   The  density is  [tex]\rho = 1250 \ kg/m^3[/tex]

   The  speed at location 1  is  [tex]v_1 = 9.93 \ m/s[/tex]

    The  diameter at location 1 is  [tex]d_1 = 11.1\ cm = 0.111 \ m[/tex]

     The  diameter at location 2 is  [tex]d_1 = 16.7\ cm = 0.167 \ m[/tex]

     The  height at location 1 is  [tex]h_1 = 8.89 \ m[/tex]

       The  height at location 2  is  [tex]h_2 = 1 \ m[/tex]

Generally the cross- sectional area at location 1 is mathematically represented as

       [tex]A_1 = \pi * \frac{d^2}{4}[/tex]

=>     [tex]A_1 = 3.142 * \frac{ 0.111^2}{4}[/tex]

=>     [tex]A_1 = 0.0097 \ m^2[/tex]

Generally the cross- sectional area at location 2 is mathematically represented as

           [tex]A_2 = \pi * \frac{d_1^2}{4}[/tex]

=>     [tex]A_2= 3.142 * \frac{ 0.167^2}{4}[/tex]

=>     [tex]A_2 =0.0219 \ m^2[/tex]

From continuity formula

       [tex]v_1 * A_1 = v_2 * A_2[/tex]

=>     [tex]v_2 = \frac{A_1 * v_1}{A_2 }[/tex]

=>      [tex]v_2 = \frac{0.0097 * 9.93}{0.0219 }[/tex]

=>      [tex]v_2 = 4.398 \ m/s[/tex]

Generally according to Bernoulli's theorem

     [tex]P_1 + \rho * g * h_1 + \frac{1}{2} \rho * v_1^2 = P_2 + \rho * g * h_2 + \frac{1}{2} \rho * v_2^2[/tex]

=>   [tex]P_2 - P_1 = \frac{1}{2} \rho (v_1 ^2 - v_2^2 ) + \rho* g (h_1 - h_2)[/tex]

=> [tex]\Delta P = \frac{1}{2}* 1250* (9.93 ^2 - 4.398^2 ) + 1250* 9.8 (8.89- 1)[/tex]

=> [tex]\Delta P = 1.46 *10^{5}\ Pa[/tex]