Predict the product when 2-methylbutanol is oxidised with pyridium chlorochromate in dichloromethane (PCC/CH2C12) a. CH3CH2CH(CH3)COOH b. CH3CH2CH2CH(CH3)CHO C. CH3CH2CH(CH3)CHO d. CH3CH2CH(CH3)OH 8:40 PM Type a message​

Answers

Answer 1

Answer:

c. CH3CH2CH(CH3)CHO

Explanation:

Hello there!

In this case, according to the process for the one-step oxidation of a primary alcohol with a moderately strong oxidizing agent like pyridinium chlorochromate (PCC), whereby an aldehyde is produced, we infer that the corresponding product will be 2-methylbutanal, which matches with the choice c. CH3CH2CH(CH3)CHO according to the following reaction:

[tex]CH_3CH_2CH(CH_3)CH_2OH\rightarrow CH_3CH_2CH(CH_3)COH[/tex]

Regards!


Related Questions

1. A positive value for AH for a chemical reaction is an indication of which of the following?
A. Reactants have higher potential energy and the reaction is endothermic.
B. Reactants have higher potential energy, and the reaction is exothermic.
C. Products have higher potential energy, and the reaction is endothermic.
D. Products have higher potential energy, and the reaction is exothermic.

Answers

Answer:

C. Products have higher potential energy, and the reaction is endothermic.

Which equation obeys the law of conservation of
mass?

Answers

Answer:2C4H10+2C12+12O2 4CO2+CC14+H20

Consider equimolar samples of different ideal gases at the same volume and temperature. Gas A has a higher molar mass than gas B.

1. Compare the pressure
a. A > B
b. A= B
c. A < B

2. Compare the speed.

a. A > B
b. A= B
c. A < B

Answers

Answer:

I don't understand the question

Explanation:

1. c

2. c

Answer:

1. b. A = B

2. c. A < B

Explanation:

Consider equimolar samples of different ideal gases at the same volume and temperature. (nA = nB)

Gas A has a higher molar mass than gas B. (MA > MB)

1. We can calculate the pressure using the ideal gas equation.

P = n × R × T / V

Since n, T and V are equal, the pressure of both gases are equal as well.

2. We can calculate the root-mean-square of the velocity using the following expression.

v(rms) = √(3RT/M)

There is an inverse relationship between speed and molar mass. Since A has a higher molar mass, it has a lower speed.

A technical machinist is asked to build a cubical steel tank that will hold "265" L of water. Calculate in meters the smallest possible inside length of the tank. Round your answer to the nearest .

Answers

Answer:

0.64 m

Explanation:

Given that;

1L = 0.001 cubic metre

Then;

263 L = 263 L × 0.001 cubic metre/1L

= 0.263 cubic metre

Volume of a cube = l^3

l= 3√V

l= 3√0.263 cubic metre

l= 0.64 m

Suppose a 0.042M aqueous solution of phosphoric acid (H3PO4) is prepared. Calculate the equilibrium molarity of HPO4^−2.

Answers

Answer:

2.89x10⁻⁵M = [HPO₄²⁻]

Explanation:

The equilibrium of H3PO4 in water occurs H2PO4-:

H3PO4(aq) + H2O(l) ⇄ H3O⁺(aq) + H2PO4⁻(aq)

pKa = 2.16. And as pKa = -log Ka; Ka = 10^-2.16

Ka = 6.9183x10⁻³ = [H3O⁺] [H2PO4⁻] / [H3PO4]

As both [H3O⁺] and [H2PO4⁻] comes from the same equilibrium,

[H3O⁺]=[H2PO4⁻] :

[H3O⁺] = X

[H2PO4⁻] = X

[H3PO4] = 0.042 - X

Where X is reaction coordinate

Replacing:

6.9183x10⁻³ = [X] [X] / [0.042 - X]

6.9183x10⁻³ = X² / 0.042 - X

2.905686x10⁻⁴ - 6.9183x10⁻³X - X² = 0

Solving for X:

X = -0.02M. False solution. There is no negative concentration.

X = 0.014M. Right solution

[H2PO4⁻] = 0.014M

In the second equilibrium:

H2PO4⁻(aq) + H2O(l) ⇄ HPO4-(aq) + H3O+(aq)

Based on the same principles of the last equilibrium:

pKa2 = 7.21

Ka2 = 6.166x10⁻⁸ = [HPO4-] [H3O+] / [H2PO4⁻]

[HPO4-] = X

[H3O+] = X

[H2PO4⁻] = 0.014M - X

6.166x10⁻⁸ = X² / [0.014M - X]

8.3623x10⁻¹⁰ - 6.166x10⁻⁸X - X² = 0

Solving for X:

X = -0.0000289485. False solution.

X =

2.89x10⁻⁵M = [HPO₄²⁻]

name this organic compound​
I don't need explaination just give the name

Answers

Answer:

Toluene

Explanation:

This compound is called toluene.

It is a phenyl group where it is bonded a methyl.

It is an aromatic compound.

IUPAC name can be, Methylbenzene.

As an organic compound it can not be dissolved in water.

This can be a reaction of synthesis:

C₆H₅H + CH₃Cl → C₆H₅CH₃ + HCl

which is not one of daltons hypothesis of atomic theory
elements are composed of atoms
compounds are composed of atoms of more than one element
a chemical reaction involved the rearranging of atoms
all atoms of a given element are identical
the atoms of one element are the same as another

Answers

Answer:

because atoms is just a chemical ahahahah

Explanation:

hope it helps ☺️

Dalton's hypothesis of atomic theory was given by John Dalton. The atoms of one element are the same as another and are not part of Dalton. Thus, option E is correct.

What is Dalton's theory?

Dalton gave the atomic theory where atoms are the fundamental unit of the element of the periodic table. More than one element and atoms combine to form molecules and compounds.

The property of the atoms to get rearranged is the basis of the chemical reaction that results in the formation of the new product. This resulted in the formulation of chemical combinations. The atoms of the given element are said to be the same like the potassium contains the same atom.

The atoms of one element cannot be the same as another atom, like the atom of sodium and chloride are not the same. They are different in physical and chemical properties.

These atoms follow the law of conservation of mass. The atoms are composed of sub-atomic particles that have been constituted of neutrons, electrons, and protons.

Therefore, in option E. the atoms of two elements can never be the same.

Learn more about Dalton's theory, here:

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The number of moles of aluminum that react with 15.7 grams of oxygen according to the equation 4 Al + 3 0 2 - 2 Al 20 3

Answers

Answer:

Explanation:

1mol of [tex]O_2=2*16{gr\over{mol}}=32{gr\over{mol}}\\\\15.7gr->15.7gr*{1\over{32{gr\over{mol}}}}=0.491mol~of~O_2[/tex]

as 1mol of molecular oxigen reacts with 4 mol of aluminium

1 mol of O2         -----------------------------> 4 mol of Al

0.491 mol of O2  ------------------------------>     x

[tex]x={0.491*4\over{1}}~mol~of~Al=1.9625~mol~of~Al[/tex]

Pls pls pls help me

Answers

True it is true :) trust

. Gastric juice, the digestive fluid produced in the stomach, contains hydrochloric acid, HCl. Milk of Magnesia, a suspension of solid Mg(OH)2 in an aqueous medium, is sometimes used to neutralize excess stomach acid. Write a complete balanced equation for the neutralization reaction, and identify the conjugate acid-base pairs.

Answers

Answer:

Mg(OH)2 + 2HCI = MgCI2 + 2H2O

Explanation:

Please correct me if I am wrong

atomaticity of chlorine 1) 2, 2)1, 3) 32 , 4) 4.​

Answers

Answer:

ATOMICITY OF CHLORINE IS 2

Explanation:

Atomicity is defined as the total number of atoms present in a molecule.

13. What would you expect the pH of an aqueous solution of tertiary bromide in water to be (acidic, neutral, or basic)

Answers

Answer:

oshfjidgshsjdh

Explanation:

918474828

g The theoretical yield of a certain reaction is 123 g of Al2O3. If the actual yield when the experiment is performed is 0.209 mol Al2O3, what is the percent yield

Answers

Answer:

Percent yield = 17.3%

Explanation:

The percent yield is defined as 100 times the ratio between actual yield in grams and theoretical yield in grams (123g).

Percent Yield = Actual Yield / Theoretical yield (123g) * 100

To find actual yield we need to convert the 0.209moles to grams:

Actual yield -Molar mass Al2O3: 101.96g/mol-

0.209mol * (101.96g/mol) = 21.3g

Percent yield = 21.3g / 123g * 100

Percent yield = 17.3%

Increasing the temperature of a chemical reaction usually increases greatly the rate of the reaction. The most iportant reason for this is that increasing the temperature increases: _______.
A) the collision frequency
B) the probability factor
C) the fraction of collisions with energy greater than Bact
D) the energy of activation.
E) the amount of heat released in the reaction

Answers

Answer:

the fraction of collisions with energy greater than Eact

Explanation:

The activation energy of a reaction stands as a sort of energy barrier between reactants and products. It is only reactants that possesses energy greater than the activation energy that can be converted from reactants to products.

When the temperature of the system is increased, more particles acquire energy greater than the activation energy. Hence, the fraction of collisions with energy greater than the activation energy increases so the rate of reaction increases likewise.

What is the cell potential of an electrochemical cell that has the half-reactions shown below?
Ag⁺ + e⁻ → Ag
Fe → Fe³⁺ + 3e⁻

Answers

Answer:

E°(Ag⁺/Fe°) = 0.836 volt

Explanation:

3Ag⁺ + 3e⁻ => Ag°;            E° = +0.800 volt

Fe° => Fe⁺³ + 3e⁻ ;             E° = -0.036 volt

_________________________________

Fe°(s) + 3Ag⁺(aq) => Fe⁺³(aq) + 3Ag°(s) ...    

E°(Ag⁺/Fe°) = E°(Ag⁺) - E°(Fe°) = 0.800v - ( -0.036v) = 0.836 volt

What change would increase the amount of solid solute able to be dissolved in liquid water?
Decreasing rate of stirring
Decreasing surface area
Increasing pressure
Increasing temperature

Answers

Answer:

D: Increasing temperature

Explanation:

From collision theory, we know that the more the increase in collisions, the faster the rate of the chemical reaction.

Now, the amount of solid solute in a solvent will change with a corresponding change in temperature. What we mean is that, the higher the temperature increases, the higher the number of collisions between the solvent molecules as well as leading to an increase in the solute particles which will mean an increase in the amount of the solid solute dissolved. The correct answer is option D.

Answer:

Increasing temperature.

Explanation:

A student dropped a piece of silver metal into a solution of HCl(aq). He observed the formation of gas bubbles and collected the gas into another test tube. The student performed a splint test and observed that the splint produced a popping sound when he placed the splint into the test tube of the gas. What can be said about the results of this students experiment?

a. The student performed the splint test incorrectly. He should of observed the splint flare up when the splint was placed in the test tube.
b. The student completed the experiment correctly and there were no errors in the experiment.
c. The experiment was performed incorrectly. Silver doesn't react with HCl. Therefore, the student picked up the wrong metal when conducting the experiment.
d. The student performed the splint test incorrectly. He should of observed the flame being extinguished when the splint was placed in the test tube.

Answers

Answer:

The student completed the experiment correctly and there were no errors in the experiment.

Explanation:

When a pea size amount of Ag is dropped into a solution of HCl, the following reaction occurs;

Ag(s) + 2HCl(aq) ----> AgCl(aq) + H2(g)

The gas H2 burns with a pop sound. The gas obtained does not react to litmus. The products of the reaction are expected.

Hence, the experiment was properly conducted and the student completed the experiment correctly and there were no errors in the experiment.

If mass of an empty 9.4 mL pycnometer is 10.3 and the mass of the same pycnometer with an unknown liquid is 20.1. Determine the density of the unknown liquid to the correct number of significant figures in g/mL

Answers

Answer:

1.04 g/mL

Explanation:

Applying,

D = (m-m')/V................. Equation 1

Where D = Density of the unknown liquid, m = mass of the pycnometer when filled with unkwon liquid, m' = mass of the empty pycnometer, V = volume of the empty pycnometer

From the question,

Assuming the mass are in grams

Given: m = 20.1 g, m' = 10.3 g, V = 9.4 mL

Substitute these values into equation 1

D = (20.1-10.3)/9.4

D = 9.8/9.4

D = 1.04 g/mL

Calculate the mass of Na2S needed if a solution containing 2g of Hg(NO3)2 was added to Na2S solution.
( Hg= 200.59, N= 14, O= 16, Na= 23, S=32)​

Answers

Answer:

1.433g of HgS are produced

Explanation:

A Solution Containing 2.0 Grams Of Hg(NO3)2 Was Added To A Solution Containing 2.0 Grams Of Na2S. Calculate the mass of the HgS that was formed (it is a precipitate) according to this reaction:

Based on the reaction:

Na2S + Hg(NO3)2 → HgS + 2NaNO3

To solve this question we need to find the moles of each reactant in order to find the limiting reactant. The moles of limiting reactant = moles of HgS:

Moles Na2S -Molar mass: 78.0452 g/mol-

2.0g * (1mol / 78.0452g) = 0.0256 moles Na2S

Moles Hg(NO3)2 -324.7g/mol-

2.0g * (1mol / 324.7g) = 0.006159 moles Hg(NO3)2

As the reaction is 1:1, and moles of Hg(NO3)2 < moles Na2S

The moles of Hg(NO3)2 = Moles HgS = 0.006159 moles

The mass is:

Mass HgS -Molar mass: 232.66g/mol-:

0.006159 moles * (232.66g/mol) =

1.433g of HgS are produced

How many stereoisomers are possible for CHCl3 provided that the central carbon has a tetrahedral geometry

Answers

Answer:

How many stereoisomers are possible for CHCl3 provided that the central carbon has tetrahedral geometry?

Explanation:

The stereoisomers are the molecules with the same molecular formula but the different spatial arrangements of atoms around the central atom.

For the given molecule, [tex]CHCl_3[/tex]

only one spatial arrangement is possible.

Hence, one stereoisomer is possible.

It is shown below:

Calculate the molality of a solution containing 22.75 g of glycerol (C3H8O3) in 79.6 g of ethanol (C2H5OH).

Answers

Answer:

3.11 mol/kg

Explanation:

Molality M = number of moles of solute, n/mass of solvent, m

To calculate the number of moles of glycerol (C₃H₈O₃) in 22.75 g of glycerol, we find its molar (molecular) mass, M',

So, M' = 3 × atomic mass of carbon + 8 × atomic mass hydrogen + 3 × atomic mass of oxygen

= 3 × 12 g/mol + 8 × 1 g/mol + 3 × 16 g/mol = 36 g/mol + 8 g/mol + 48 g/mol = 92 g/mol.

So, number of moles of glycerol, n = m'/M' where m' = mass of glycerol = 22.75 g and M' = molecular mass of glycerol = 92 g/mol

So, n = m'/M'

n = 22.75 g/92 g/mol

n = 0.247 mol

So, the molality of the solution M = n/m

Since m = mass of ethanol = 79.6 g = 0.0796 kg, substituting the value of n into the equation, we have

M = 0.247 mol/0.0796 kg

M = 3.11 mol/kg

So, the molality of the solution is 3.11 mol/kg.

Consider the following reaction at equilibrium. What effect will decreasing the temperature have on the system? DH=+890kJCO2(g)+2H2O(l)<--> CH4(g)+2O2(g)a) the equilibrium constant will increaseb) the reaction will shift to the left in the direction of the reactantsc) the reaction will shift to the right in the direction of the productsd) no effect will be observed

Answers

Answer:

Option B. The reaction will shift to the left in the direction of the reactants.

Explanation:

The equation for the reaction is given below:

CO₂ + 2H₂O <=> CH₄ + O₂

Enthalpy change (ΔH) = +890 KJ

The reaction illustrated by the equation is endothermic reaction since the enthalpy change (ΔH) is positive.

Increasing the temperature of an endothermic reaction will shift the equilibrium position to the right and decrease the temperature will shift the equilibrium position to the left.

Therefore, decreasing the temperature of the system illustrated by the equation above, will shift the reaction to the left in the direction of the reactants.

Thus, option B gives the right answer to the question.

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Write the symbol for every chemical element that has atomic number less than 14 and atomic mass greater than 23.2 u.

Answers

Answer:

that symbol less than atomic number 14 and greater than mass number 23.2 is mg

Given the following list of densities, which materials would float in a molten vat of lead provided that they do not themselves melt? Densities (g/mL): lead = 11.4, glass = 2.6, gold = 19.3, charcoal = 0.57, platinum = 21.4.
a. gold and platinum
b. glass and charcoal
c. gold, platinum, glass and coal
d. gold and charcoal
e. None of these

Answers

Answer:

b. glass and charcoal

Explanation:

Step 1: Given data

Density of Pb: 11.4 g/mLDensity of Glass: 2.6 g/mLDensity of Au: 19.3 g/mLDensity of charcoal: 0.57 g/mLDensity of platinum: 21.4 g/mL

Step 2: Determine which material will float in molten lead

Density is an intrinsic property of matter. Less dense materials float in more dense materials. The materials whose density is lower than that of lead and will therefore float on it are glass and charcoal.

Calculate the mass percent of carbon in the following molecule: Mn3[Mn(CO)4]3

Answers

Answer:

21.63 %

Explanation:

The molar mass of Mn₃[Mn(CO)₄]₃ is 665.64 g/mol.

Let's assume we have 1 mol of Mn₃[Mn(CO)₄]₃, if that were the case then we would have 665.64 grams.

There are 12 C moles per Mn₃[Mn(CO)₄]₃, with that in mind we calculate the weight of 12 C moles:

12 mol C * 12 g/mol = 144 g

Finally we calculate the mass percent of carbon:

144 g / 665.64 g * 100% = 21.63 %

Suppose of sodium iodide is dissolved in of a aqueous solution of potassium carbonate. Calculate the final molarity of sodium cation in the solution. You can assume the volume of the solution doesn't change when the sodium iodide is dissolved in it. Round your answer to significant digits.

Answers

Answer:

0.2762M Na+ in the solution

Explanation:

2.07g of sodium iodide Is Dissolved In 50.ML Of A 0.30M...

To solve this question we need to find the moles of sodium iodide, NaI, that are the same than the moles of sodium cation, Na+. The volume in liters of the solution is 0.050L. The molarity is:

Moles NaI = Moles Na+ -Molar mass NaI: 149.89g/mol-

2.07g NaI * (1mol / 149.89g) = 0.01381 moles NaI = Moles Na+

Molarity:

0.01381 moles Na+ / 0.0500L =

0.2762M Na+ in the solution

At 298 K, AHO = -1652 kJ/mol and ASO = 0.097 kJ/(K•mol). What is the Gibbs
free energy of the reaction?

Answers

Based on the calculations, the Gibbs's free energy for this chemical reaction is equal to -1,680.906 kJ/mol.

Given the following data:

Enthalpy of reaction (ΔH°) = -1652 kJ/mol.Temperature = 298 K.Entropy of reaction (ΔS°) = 0.097 kJ/mol.

What is Gibbs's free energy?

Gibbs's free energy simply refers to the quantity of energy that is associated with a particular chemical reaction.

Mathematically, the Gibbs's free energy for this chemical reaction can be calculated by using this formula:

ΔG° = ΔH° - ΔS°

Substituting the given parameters into the formula, we have;

ΔG° = -1652 × 10³ - (298 × 0.097)

ΔG° = -1652 × 10³ - 28.906

ΔG° = -1,680.906 kJ/mol.

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What is the best explanation for why solid sodium chloride CANNOT conduct electricity and why molten sodium chloride can?

Answers

Answer: See explanation

Explanation:

The explanation for why solid sodium chloride can't conduct electricity while molten sodium chloride can is explained below:

Ionic compounds that are in their solid state like sodium chloride have their ions fixed in position. Due to this reason, the able to move, therefore we can say that the solid ionic compounds cannot be able to conduct electricity.

On the other hand, ionic compounds in their molten state, are free to flow unlike when they're in their solid state and therefore we can say that molten sodium chloride can be able to conduct electricity.

Classify each aqueous solution as acidic, basic, or neutral at 25 °C.
Acidic
Basic
Neutral
pH - 3.41
pH = 10.25
pH = 7.00
[H+] -3.5 x 10-5
[H+] - 6.7 x 10-9
[OH-]-5.8 x 10-4
[H0] -1.0 x 10-7
[OH-] - 4.5 x 10-13

Answers

Answer:

pH - 3.41 = acidic

pH = 10.25 = basic

pH = 7.00 = neutral

[H+] -3.5 x 10-5 = acidic

[H+] - 6.7 x 10-9 = basic

[OH-]-5.8 x 10-4 = basic

[H0] -1.0 x 10-7 = neutral

[OH-] - 4.5 x 10-13 = acidic

Explanation:

Let us note that from the pH scale, a pH of;

0 - 6.9 is acidic

7 is neutral

8 - 14 is basic

But pH= - log [H^+]

pOH = -log [OH^-]

Then;

pH + pOH = 14

Hence;

pH = 14 - pOH

For [H+] -3.5 x 10-5

pH = 4.46 hence it is acidic

For [H+] - 6.7 x 10-9

pH = 8.17 hence it is basic

[OH-]-5.8 x 10-4

pH= 10.76 hence it is basic

[H0] -1.0 x 10-7

pH = 7 hence it is neutral

[OH-] - 4.5 x 10-13

pH = 1.65 hence it is acidic

A sample of oxygen gas is compressed from 30.6 L to 1.8 L at constant temperature pressure of 1.8 atm. Calculate the amount of energy in joules when the system releases 1.5 KJ of heat?

Answers

Answer:

the change in the internal energy of the system is 3,752.67 J

Explanation:

Given;

initial volume of the gas, V₁ = 30.6 L

final volume of the gas, V₂ = 1.8 L

constant pressure of the gas, P = 1.8 atm

Energy released by the system, Q = 1.5 kJ = 1,500 J

Apply pressure-volume work equation, to determine the work done on the gas;

w = -PΔV

w = -P(V₂ - V₁)

w = - 1.8 atm(1.8 L - 30.6 L)

w = 51.84 L.atm

w = 51.84 L.atm x 101.325 J/L.atm

w = 5,252.67 J

The change in the internal energy of the system is calculated as;

ΔU = Q + w

Since the heat is given out, Q = - 1,500 J

ΔU = -1,500 J  +  5,252.67 J

ΔU = 3,752.67 J

Therefore, the change in the internal energy of the system is 3,752.67 J

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