(pre calc) HELP ASAP

A function is decreasing if as x-values increase, the y-values decrease.  Graphically this means that if you move from left-to-right, the graph goes down.

The downhill portion of this curve is on the interval [tex](1,\infty)[/tex].

Answer:

2.5!

Step-by-step explanation:

round 0.93 up to 1 and 2.6 down to 2.5

1*2.5 = 2.5

Answer:like 3

Step-by-step explanation:

Since the pavement at the new shopping mall is being laid, a transformation that is applied from brick A to brick B include the following: D. translation.

In Mathematics, a transformation can be defined as the movement of a point from its original (actual) position to a final (new) location. This ultimately implies that, when an object (pre-image) is transformed, all of its points would be transformed as well to form a new image such as the following:

In Mathematics, a translation can be defined as a type of transformation which moves every point of the object in the same direction, as well as for the same distance.

In conclusion, a translation was applied to both brick A and brick B.

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Answer:

Step-by-step explanation:

its 18+27 because you have to do 6x3 wich is 18 and add 27 to 18

Answer:

4

Step-by-step explanation:

Answer:

square 3. Multipky the result by -2 and then subtract 4.

Step-by-step explanation:

comment if u need explanation

Yes, this is correct. If you solve the first equation it equals the second equation.

The speed of the cars are 50mph and 60mph

Let's call the speed of the slower car "x". The faster car is traveling at "x + 10 mph".

The total distance both cars travel is 660 miles, and the time it takes for them to meet is 6 hours.

Using the formula for distance = rate x time, we can set up the equation:

x * 6 + (x + 10) * 6 = 660

Expanding and simplifying, we get:

12x + 60 = 660

Subtracting 60 from both sides:

12x = 600

Dividing both sides by 12:

x = 50 mph

So the slower car is traveling at 50 mph and the faster car is traveling at 60 mph.

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Answer: 3 1/2

Step-by-step explanation:

Since positive and a negative make a negative the product would be a negative. Now we multiply 2/1 (because is the same as 2) times - 7/4, which gives us - 14/4. -14/4 = 3 1/2. Have a nice day ;)

Answer:

The scarf cost:

$9.91

Step-by-step explanation:

9.92 - 0.01 = 9.91

Answer:

Below

Step-by-step explanation:

The two angles at U   are equal....so the triangles have TWO equal angles: 72° and the angles at U

Answer A

Geometric mean is the square root of the two numbers after multiplying them     sqrt ( 48* 12) = sqrt( 576) = 24

On solving the provided question, we can say that the inequality formed is 1 ≥ 2(3)-5 => 1 ≥ 1

An inequality in mathematics is a relationship between two expressions or values that is not equal. Thus, imbalance leads to inequality. An inequality creates the link between two values that are not equal in mathematics. Egality is distinct from inequality. When two values are not equal, most commonly use the not equal sign (). Different inequalities are used to contrast values, no matter how little or large. Many simple inequalities may be resolved by modifying the two sides until the variables are all that remain. But a number of things contribute to inequality: Negative values on both sides are divided or added. Trade off the left and right.

The ordered pair is (3, 1)

Substitute (x, y)=(3, 1) in the given inequality, we get

the inequality formed is

1 ≥ 2(3)-5

1 ≥ 1

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Answer:

Below

Step-by-step explanation:

sin (90 -0) = sin (90) = 1

Remember   sin^2 + cos^2 =1

  for theta       sin2 + (3/4)^2

                         sin^2 = 1 - 9/16 = 7/16

                            sin (theta) = ± sqrt(7) /4

The vertical value in a pair of coordinates. How far up or down the point is. The Y Coordinate is always written second in an ordered pair of coordinates (x,y) such as (12,5). In this example, the value "5" is the Y Coordinate.

Answer:

(a)

f(x) = 30, for x ≤ 200

f(x) = 0.03(x - 200) + 30, for x > 200

(b) $34.50

(c) 356

Step-by-step explanation:

Let x = number of minutes.

(a)

f(x) = 30, for x ≤ 200

f(x) = 0.03(x - 200) + 30, for x > 200

(b)

Here, x = 350, so x > 200.

f(x) = 0.03(x - 200) + 30

f(350) = 0.03(350 - 200) + 30

f(350) = 0.03(150) + 30

f(350) = 4.5 + 30

f(350) = 34.5

$34.50

(c)

f(x) = 0.03(x - 200) + 30

0.03(x - 200) + 30 = 34.68

0.03(x - 200) = 4.68

x - 200 = 156

x = 356

Answer: Dude this is pretty easy!

Step-by-step explanation: Use the process of elimination.

Hint: It's just subtraction or addition. Trust me it's easy.

Answer:

Step-by-step explanation:

1/4 min, 15 sec

Answer:

Below

Step-by-step explanation:

From 7 to 10 AM is THREE hours (if the times are all on the same day)

Answer:

Good luck man.

Step-by-step explanation:

Ima be honest, I got no idea.

Answer:

The exponential growth function 0f3=61025/ 04-0295254 0f=423 0fx)=(-1257 is not a valid equation.

Step-by-step explanation:

Answer:

I don’t even know

Step-by-step explanation:

Answer:

[tex]2x(x^2+4x-2)[/tex]

Step-by-step explanation:

We can factor out 2x:

[tex]2x^3+8x^2-4x=2x(x^2+4x-2)[/tex]

Answer: Not necessarily. Dividing the pie chart into 5 equal sections might be a way to display categorical data if the number of categories is 5. However, dividing it into 5 sections might not be the best way to display the data if the number of categories is different than 5 or if any category has a significantly higher or lower proportion than the others. In this case, it may be more appropriate to use a different scale to display the correct ratio. It is important to consider data distribution and visualization clarity before choosing how to display categorical data.

The simplified form of the exponential expression [tex]b^{n- 2}\times{b^{n-3} = b^{2n - 5}[/tex].

Some common rules of exponents are

xᵃ×xᵇ = xᵃ⁺ᵇ.

xᵃ/xᵇ = xᵃ⁻ᵇ.

Addition and subtraction of exponents are only possible for the same base value and when the base is different and both have the same exponent we just multiply the bases and write the exponent.

Given, An exponential expression [tex]b^{n- 2}\times{b^{n-3}[/tex].

We know, Same base multiplication is exponent addition.

Therefore,

[tex]b^{n- 2}\times{b^{n-3} = b^{n - 2 + n - 3}[/tex].

[tex]b^{n- 2}\times{b^{n-3} = b^{2n - 5}[/tex].

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The area of the rectangle =  9x² +18x−16

What is the area of the rectangle?

The area of a rectangle is calculated by multiplying the height by the width. If the height of the rectangle is represented by h and the width is represented by w, then the area is given by:

A = h * w

In this case, the height of the rectangle is given as 3x - 2 yards, and the width is given as 3x + 8 yards. So, substituting these values into the formula:

A = (3x - 2) * (3x + 8)

A = (3x - 2)(3x + 8)

A = 9x² +18x−16

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The answer is:

Work/explanation:

To find the rectangle's area, we use the formula

[tex]\pmb{A=LW}[/tex]

Where A = area;

L = length;

w = width.

Plug in the data

[tex]\sf{A=(3x+8)(3x-8)}[/tex]

To multiply, use FOIL:

F = first

o = outside

i = inside

l = last

Multiply

[tex]\sf{3x\cdot3x=9x^2}[/tex]

[tex]\sf{3x\cdot(-8)=-24x}[/tex]

[tex]\sf{8\cdot3x=24x}[/tex]

[tex]\sf{8\cdot(-8)=-64}[/tex]

-------------------

[tex]\sf{9x^2-24x+24x-64}[/tex]

[tex]\sf{9x^2-64}[/tex]

We can classify them as -

There are six primary statement forms in Propositional Logic -

Given are the statements as -

We can classify them as -

Therefore, we can classify them as -

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The equation of the line is y = x + 6

From the question, we have the following parameters that can be used in our computation:

The graph

On the graph, we have the following highlights

The graph intersect the y-axis at y = 6

This means that the intercept c is 6

Also, as x changes by 1, the y values changes by 1

This mean sthat the slope is 1

So, we have

y = mx + c

This gives

y = x + 6

Hence, the equation is y = x + 6

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The linear equation on the graph can be written as:

y = (3/2)*x + 6

A general linear equation can be written as:

y = a*x + b

Where a is the slope and b is the y-intercept.

If the line passes through two points (x₁, y₁), then the slope will be:

a = (y₂ - y₁)/(x₂ - x₁)

In this case we can see the points (0, 6)  (so the y-intercept is b = 6)  and (4, 10)

Then the slope will be:

a = (10 - 6)/(4 - 0) = 6/4 = 3/2

Then the linaer equation is:

y = (3/2)*x + 6

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A catapult launches a pumpkin from the base of a hill. The hill follows an incline with the height in meters, y, in terms of horizontal distance in meters, x, given by the equation y=0.9x. 40m is the height, where the pumpkin lands on the hill.

The term "horizontal distance" refers to the separation between two places measured with a slope of 0%. Vertical distance is the distance following the direction of gravity, while horizontal distance is the distance along the ground surface. The distance between an observer and a building represents as that of an example of horizontal distance, and the structure's height serves as an illustration of vertical distance. A projectile's range is the horizontal distance it covers. Horizontal refers to something that is parallel to it. Anything that forms a 90-degree angle (right angle) with the horizontal or the horizon is referred to as vertical since it is the opposite of the horizontal. The line that spans from left to right is therefore considered to be horizontal.

Given that,

The hill follows an incline with the height in meters y,

in terms of horizontal distance in meters x,

The given equation becomes: y = 0.9x

The height of the pumpkin, as it is launched up hill, is given by the function:

y = -0.1x² + 4.9x

now, finding point of intersection, we get:

0.9x = -0.1x² + 4.9x    [as y = 0.9x]

or, 0.1x² - 4x = 0

or,  x (0.1x - 4) = 0

or, x = 0 (this is not possible)

and 0.1x = 4

or, x = 40

40 is the height, in meters, where the pumpkin lands on the hill.

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4(-6), 6(-4), and 12(-2). (-2). Each one adds up to -24. I am aware of this because if you multiply the two numbers and one of the numbers is negative, the result will also be negative. The item will be favorable if there are just two drawbacks.

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Answer:

a) Let's call the length of a call "t" (in minutes). The cost of a call can be represented as follows:

C(t) = 0.99 if t <= 20

C(t) = 0.99 + 0.07(t - 20) if t > 20

b) The domain of the function is all non-negative real numbers (t >= 0), since a call can have any non-negative length in minutes. The range of the function is all non-negative real numbers, since the cost of a call can never be negative.

c) If a call lasts 12 minutes, then the cost would be 0.99:

C(12) = 0.99

d) If a call lasts 1 hour (60 minutes), then the cost would be:

C(60) = 0.99 + 0.07(60 - 20) = 0.99 + 0.07(40) = 0.99 + 2.80 = 3.79

Step-by-step explanation: