PLEASE HELP
The function in the table is quadratic
True
False

Answer:

Calculating p-value from excel  

p-value = 0.144458 (From excel  =T.DIST.RT(1.091,19))  

p-value = 0.144458 > 0.05  

So, we failed to reject the null hypothesis. There is sufficient evidence to conclude that they pay not more than the national average of $4172.

Step-by-step explanation:

Here the given de4tails are,

Hypothesized mean = 4172

Sample Standard deviation = 1590

Sample mean = 4560

Sample size n = 20

Formulation of hypothesis

Answer:

Andres

why?

Because he is median salary for cpa

Answer:

The slope is -3/4 because it rises goes down 3 and runs 4. the Y-intercept or where the line meets the y line is 3.

Answer:

numerator degree of freedom = 3

Denominator degree of freedom = 47

Step-by-step explanation:

The numerator degree of freedom is given by :

p - 1 ; where p = number of predictors ;

p = number of independent variables + 1

Number of independent variables = 3

p = 3 + 1 = 4

Numerator degree of freedom = p - 1 = 4 - 1 = 3

The denominator degree of freedom = n - p ; where n = number of observations

Number of observations, n = 51

Denominator degree of freedom = n - p = 51 - 4 = 47

9514 1404 393

Answer:

  (c)  2^r = a

Step-by-step explanation:

The relationship between log forms and exponential forms is ...

  [tex]\log_2(a)=r\ \Leftrightarrow\ 2^r=a[/tex]

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Additional comment

I find this easier to remember if I think of a logarithm as being an exponent.

Here, the log is r, so that is the exponent of the base, 2.

This equivalence can also help you remember that the rules of logarithms are very similar to the rules of exponents.

Answer: Choice C)  [tex]2^r = a[/tex]

This is the same as writing 2^r = a

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Explanation:

Assuming that '2' is the base of the log, then we'd go from [tex]\log_2(a) = r[/tex] to [tex]2^r = a[/tex]

In either equation, the 2 is a base of some kind. It's the base of the log and it's the base of the exponent.

The purpose of logs is to invert exponential operations and help isolate the exponent. A useful phrase to help remember this may be: "if the exponent is in the trees, then we need to log it down".

The general rule is that [tex]\log_b(y) = x[/tex] converts to [tex]y = b^x[/tex] and vice versa.

Answer:

if the sum of two angles is 90° they are said to be complementary

If one angle is x

the other should be (90 - x)°

so the complementary angle of x is (90 - x)

Answer:

It will take about 109.3 seconds for nine grams of the element to decay to 0.72 grams.

Step-by-step explanation:

We can write a half-life function to model our function.

A half-life function has the form:

[tex]\displaystyle A=A_0\left(\frac{1}{2}\right)^{t/d}[/tex]

Where A₀ is the initial amount, t is the time that has passes (in this case seconds), d is the half-life, and A is the amount after t seconds.

Since the half-life of the element is 30 seconds, d = 30. Our initial sample has nine grams, so A₀ is 9. Substitute:

[tex]\displaystyle A=9\left(\frac{1}{2}\right)^{t/30}[/tex]

We want to find the time it will take for the element to decay to 0.72 grams. So, we can let A = 0.72 and solve for t:

[tex]\displaystyle 0.72=9\left(\frac{1}{2}\right)^{t/30}[/tex]

Divide both sides by 9:

[tex]\displaystyle 0.08=\left(\frac{1}{2}\right)^{t/30}[/tex]

We can take the natural log of both sides:

[tex]\displaystyle \ln(0.08)=\ln\left(\left(\frac{1}{2}\right)^{t/30}\right)[/tex]

By logarithm properties:

[tex]\displaystyle \ln(0.08)=\frac{t}{30}\ln(0.5)[/tex]

Solve for t:

[tex]\displaystyle t=\frac{30\ln(0.08)}{\ln(0.5)}\approx109.3\text{ seconds}[/tex]

So, it will take about 109.3 seconds for nine grams of the element to decay to 0.72 grams.

Answer:

C. 3rd quartile

Step-by-step explanation:

Percentile:

A data belonging to the xth percentile means that the data is greater than x% of the values of the data-set, and smaller than (100 - x)%.

Point below 75% of the cases lie:

This is the 75th percentile, which is the 3rd quartile, as 75 = 3*100/4. Thus, the correct answer is given by option c.

Answer:

[tex]41\text{ [units squared]}[/tex]

Step-by-step explanation:

The octagon is irregular, meaning not all sides have equal length. However, we can break it up into other shapes to find the area.

The octagon shown in the figure is a composite figure as it's composed of other shapes. In the octagon, let's break it up into:

Formulas:

Area of triangles:

All four triangles we broke the octagon into are congruent. Each has a base of 2 and a height of 2.

Thus, the total area of one is [tex]A=\frac{1}{2}\cdot 2\cdot 2=2\text{ square units}[/tex]

The area of all four is then [tex]2\cdot 4=8[/tex] units squared.

Area of rectangles:

The two smaller rectangles are also congruent. Each has a length of 3 and a width of 2. Therefore, each of them have an area of [tex]3\cdot 2=6[/tex] units squared, and the both of them have a total area of [tex]6\cdot 2=12[/tex] units squared.

The last rectangle has a width of 7 and a height of 3 for a total area of [tex]7\cdot 3=21[/tex] units squared.

Therefore, the area of the entire octagon is [tex]8+12+21=\boxed{41\text{ [units squared]}}[/tex]

Answer:

Chips: 1.25 and Sandwiches: 6.5

Step-by-step explanation:

3s+2c=22

2s+c=14.25

The cost of bag and chips should be 1.25 and 6.5.

3s+2c=22

2s+c=14.25

Here we need to multiply by 2 in equation 2

3s + 2c = 22

2s + 2c = 28.25

s = 6.5

Now

c should be

2(6.5) + c = 14.25

13 +  c = 14.25

c = 1.25

Learn more: brainly.com/question/16911495

Answer:

C'

Step-by-step explanation:

Given

ABCD to A'B'C'D'

Required

Corresponding angle of C

ABCD to A'B'C'D' means that the following angles are corresponding

[tex]A \to A'[/tex]

[tex]B \to B'[/tex]

[tex]C \to C'[/tex]

[tex]D \to D'[/tex]

Hence, C' corresponds to C

Answer:

C

Step-by-step explanation:

I took the test :)

Answer:

assuming that you start at the origin (0,0)

(-4,-1) would be the poiny

x coord = -4

y coord = -1

the point is in the 3 quadrant

Step-by-step explanation:

jvdhvfggvvvbbbbbbbbb

Answer:

A. x=2 y=7

Step-by-step explanation:

-12x -3 = 3y

6x + 3y = 33

sooo you add them up...

so its

-6x = -12

x=2

and then you plug in the x value into one of the equations

6x + 3y = 33

6(2) + 3y = 33

12 + 3y = 33

3y = 33 - 12

3y = 21

21/3=7

y=7

Work Shown:

Apply the slope formula

m = (y2-y1)/(x2-x1)

m = (1-3)/(3-(-1))

m = (1-3)/(3+1)

m = -2/4

m = -1/2 is the slope

In decimal form, this converts to -0.5, though usually slopes are in fraction form.

Answer:

0.1143 = 11.43% probability that all but one of them are using Chrome as their browser

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they use Chrome, or they do not. The probability of a person using Chrome is independent of any other person, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

Chrome: 52.57%

This means that [tex]p = 0.5257[/tex]

Sample of 6 people

This means that [tex]n = 6[/tex]

What is the probability that all but one of them are using Chrome as their browser?

5 using Chrome, so:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 5) = C_{6,5}.(0.5257)^{5}.(1-0.5257)^{1} = 0.1143[/tex]

0.1143 = 11.43% probability that all but one of them are using Chrome as their browser

Answer:

a)  b^5/12

Step-by-step explanation:

b^2/3 ÷ b^1/4    [if bases are the same then subtract the exponents]

2/3 - 1/4 = 5/12

Answer:

The gradient is -0.25

Step-by-step explanation:

Given

[tex](x_1,y_1) = (-5,3)[/tex]

[tex](x_2,y_2) = (5,0.5)[/tex]

Required

The gradient (m)

This is calculated as:

[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

So, we have:

[tex]m = \frac{0.5-3}{5--5}[/tex]

[tex]m = \frac{-2.5}{10}[/tex]

[tex]m = -0.25[/tex]

Hello,

in France, the mode is the value having the greater repetition

mode= 5 (repetition=11)

Answer: hello there here is your answer:

Still air speed:450 mph.

Step-by-step explanation:

500-450=450-400=50 mph

Still air speed:450 mph. Wind speed:50 mph..

hope this help have a good day

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Explanation:

The phrasing "2/3 of 4/5 of his 2nd exam on his 3rd test" is a bit clunky in my opinion. It seems more complicated than it has to be.

The student got 80 on the second exam. 4/5 of this is (4/5)*80 = 0.8*80 = 64. Then we take 2/3 of this to get (2/3)*64 = 42.667 approximately. If we assume only whole number scores are given, then this would round to 43.

Let x be the score on the fourth exam. Since 5 points of extra credit are given, the student actually got x+5 points on this exam.

So we have these scores

Adding up these scores and dividing by 4 will get us the average

(sum of scores)/(number of scores) = average

(70+80+43+x+5)/4 = 80

(x+198)/4 = 80

x+198 = 4*80

x+198 = 320

x = 320 - 198

x = 122

So the student got a score of x+5 = 122+5 = 127 on the fourth exam.

9514 1404 393

Answer:

Step-by-step explanation:

Each image point has its signs reversed from the pre-image point.

  (x, y) ⇒ (-x, -y) . . . . describes the rotation

Rotation from the third quadrant (A) to the first quadrant (A') is a rotation of 180°.

Answer:

3rd and 2nd option

Step-by-step explanation:

Step-by-step explanation:

k=8.6

i think it is the right answer

12.8, pythagorean theorem.

Answer:

[tex]\bar x = 107.11[/tex]

[tex]\sigma_x = 31.07[/tex]

Step-by-step explanation:

See comment for complete question

Given

[tex]x: 97\ 178\ 129\ 90\ 75\ 94\ 116\ 100\ 85[/tex]

Solving (a): The sample mean

This is calculated using:

[tex]\bar x = \frac{\sum x}{n}[/tex]

So, we have:

[tex]\bar x = \frac{97+ 178+ 129+ 90+ 75+ 94+ 116+ 100+ 85}{9}[/tex]

[tex]\bar x = \frac{964}{9}[/tex]

[tex]\bar x = 107.11[/tex]

Solving (b): The sample standard deviation

This is calculated as:

[tex]\sigma_x = \sqrt{\frac{\sum(x - \bar x)^2}{n-1}}[/tex]

So, we have:

[tex]\sigma_x = \sqrt{\frac{(97 - 107.11)^2 +.............+ (85- 107.11)^2 }{9-1}}[/tex]

[tex]\sigma_x = \sqrt{\frac{7720.8889}{8}}[/tex]

[tex]\sigma_x = \sqrt{965.1111125}[/tex]

[tex]\sigma_x = 31.07[/tex]

Answer:

x=40

Step-by-step explanation:

In the picture, it seems that angles BHC, CHD, and DHE form a line, 180 degrees. So to solve, set up an equation:

[tex](2x+5)+55+40=180[/tex]

Take off the parentheses and solve.

Subtract 5, 55 and 40 from both sides, or add them together, then subtract.

5+55+40=100

You get:

[tex]2x=80[/tex]

Divide both sides by 2

You get:

I hope this helps!

Answer:

F(x) moved right 2 units to become G(X).

According to graph transformations, that means G(X) = F(X - 2) = [tex](X-2)^{3}[/tex].

I think that's how you do it :\

Answer:

0.7123 = 71.23% probability that a random sample of 75 detached houses in Franklin County had a mean price greater than $190,000 in 2009.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The mean price for a detached house in Franklin County, OH in 2009 was $192,723. Suppose we know that the standard deviation was $42,000.

This means that [tex]\mu = 192723, \sigma = 42000[/tex]

Sample of 75:

This means that [tex]n = 75, s = \frac{42000}{\sqrt{75}}[/tex]

What is the probability that a random sample of 75 detached houses in Franklin County had a mean price greater than $190,000 in 2009?

1 subtracted by the p-value of Z when X = 190000. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{190000 - 192723}{\frac{42000}{\sqrt{75}}}[/tex]

[tex]Z = -0.56[/tex]

[tex]Z = -0.56[/tex] has a p-value of 0.2877

1 - 0.2877 = 0.7123

0.7123 = 71.23% probability that a random sample of 75 detached houses in Franklin County had a mean price greater than $190,000 in 2009.

Step-by-step explanation: