PLEASE HELP!!!!!!!
25.0g of Aluminum metal is combined with
45.Og Copper(ll) Chloride to produce Aluminum Chloride
and Copper metal
1. Write and balance the chemical equation.
2. Write the needed mole ratio between reactants.
3. What is the mole ratio you have from the data?
4. What is in excess and what is limited? (Show Work)
5. What is the theoretical yield of Aluminum Chloride?
Answers
Answer: 1. [tex]2Al+3CuCl_2\rightarrow 2AlCl_3+3Cu[/tex]
2. 3 moles of [tex]CuCl_2[/tex] : 2 moles of [tex]Al[/tex]
3. 0.33 moles of [tex]CuCl_2[/tex] : 0.92 moles of [tex]Al[/tex]
4. [tex]CuCl_2[/tex] is the limiting reagent and [tex]Al[/tex] is the excess reagent.
5. Theoretical yield of [tex]AlCl_3[/tex] is 29.3 g
Explanation:
To calculate the moles :
[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]
[tex]\text{Moles of} Al=\frac{25.0g}{27g/mol}=0.92moles[/tex]
[tex]\text{Moles of} CuCl_2=\frac{45.0g}{134g/mol}=0.33moles[/tex]
The balanced chemical equation is:
[tex]2Al+3CuCl_2\rightarrow 2AlCl_3+3Cu[/tex]
According to stoichiometry :
3 moles of [tex]CuCl_2[/tex] require = 2 moles of [tex]Al[/tex]
Thus 0.33 moles of [tex]CuCl_2[/tex] will require=[tex]\frac{2}{3}\times 0.33=0.22moles[/tex] of [tex]Al[/tex]
Thus [tex]CuCl_2[/tex] is the limiting reagent as it limits the formation of product and [tex]Al[/tex] is the excess reagent.
As 3 moles of [tex]CuCl_2[/tex] give = 2 moles of [tex]AlCl_3[/tex]
Thus 0.33 moles of [tex]CuCl_2[/tex] give =[tex]\frac{2}{3}\times 0.33=0.22moles[/tex] of [tex]AlCl_3[/tex]
Theoretical yield of [tex]AlCl_3=moles\times {\text {Molar mass}}=0.22moles\times 133.34g/mol=29.3[/tex]
Thus 29.3 g of aluminium chloride is formed.
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Explanation:
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Answer: d. Determining empirical formula
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Molecular formula is the chemical formula which depicts the actual number of atoms of each element present in the compound.
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Answer:
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Hope it helps!
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The iodide slats are suitably precipitated in the alkaline solution, and thus limits the use of the mohr method.
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Answer:
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In point 2:
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Adding water to an acid or base will change its pH. ... The acid is becoming less acidic. Similarly, when an alkali is diluted with water the concentration of OH - ions decreases. This causes the pH of the alkali to fall towards 7, making the solution less alkaline as more water is added
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C. electroscope
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Clear selection
Answers
Answer:
Explanation:
Alpha particles,
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Answer:
it is your answer..... if it is helpful plzz like and comment.....
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Answers
Answer:
about 6664 grams of hydro phosphoric acid are in a sample of 4 L of 17 M solution
Explanation:
grams of H3PO4 = 4 L | 17 mol | 98 grams H3PO4
| 1 L | 1 mol
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Answers
One mole of a substance is equal to 6.022 × 10²³ units of that substance (such as atoms, molecules, or ions). The number 6.022 × 10²³ is known as Avogadro's number or Avogadro's constant. The concept of the mole can be used to convert between mass and number of particles.
Rank the following compounds in order of increasing solubility in water. Items (4 items) (Drag and drop into the appropriate area) No more items Items in order most soluble CaO BaO KCI KI
I have tried CaO> BaO > KCl > KI, this is incorrect.
Answers
Answer:
CaO < BaO < KCl <KI
Explanation:
Let us remember that the solubility of an ionic substance in water depends on the magnitude of the lattice energy and the hydration energy. If the hydration energy is equal to or is greater than the lattice energy, the substance dissolves in water.
However, the lattice energy depends on the size of the ions. The smaller the ions in the ionic compound, the higher the lattice energy and the lesser the solubility of the ionic compound.
KI has the least lattice energy and the highest solubility in water while CaO has the highest lattice energy and the least solubility in water.
Which is a saturated solution?
A）40g NH4Cl in 100g water at 50°C
B）2g SOz in 100g water at 10°C
C）52g KCl in 100g water at 80°C
D）120g KI in 100g water at 20°C
Answers
Answer:
C）52g KCl in 100g water at 80°C
Explanation:
A saturated solution is one that contains as much solute as it can dissolve in the presence of excess solute at that particular temperature.
A solutibility curve is a graph that shows the variability with temperature of the solubility of a solute in a given solvent. A solutibility curve can provide information of whether a solution formed frommthe solute and solvent are saturated or not at a given temperature.
From the solubility curve in the attachment below:
A) A saturated solution of NH₄Cl will contain about 52 g solute per 100 g sat 50 °C. Thus, a solution of 40 g NH₄Cl in 100 g water at 50 °C is an unsaturated solution.
B) A saturated solution of SO₂ at 10°C will contain about 70 g of solute in 100 g of water. Thus a solution of 2g SO₂ in 100g water at 10°C is an unsaturated solution.
C) A saturated solution of KCl at 80 °C will contain about 52 g of solute in 100 g of water. Thus, a solution of 52g KCl in 100g water at 80°C is a saturated solution.
D) A saturated solution of Kl at 20 °C will contain about 145 g of solute in 100 g of water. Thus, a solution of 120g KI in 100g water at 20°C is an unsaturated solution.
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HELP FAST 75 PTS Calculate the amount of heat needed to melt 35.0 g of ice at 0 ºC. must show work
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Answer:
It takes 12,000 Joules of energy to melt 35 grams of ice at 0 °C
Explanation:
Good Luck!