Answer:
balenced
Explanation:
Which formula uses mass in the equation?
The mass can be calculated by dividing the net force acting on an object by the acceleration of the object. When talking about net force, we use the units kilogram meter per second squared. This is also known as a Newton. The units for acceleration is meters per seconds squared, and the units for mass are kilograms.
briefly discuss university need based scholarships and explain them.
Answer: Scholarships are given to reduce the burden of finance to be payed for academics and learning.
Explanation:
The need based scholarships are given in the following matters:
1. Research based scholarships: Scholarships should be given to meritorious students to conduct research in a particular discipline.
2. Student fails to submit fees: The student if meritorious and family is not able to fees then university can either postpone the date for fees payment or can give some concession in fees or fund the student fees for a tenure. It is a kind of scholarship for meritorious students.
3. Teacher scholarships: Teachers are allowed to learn new teaching methodologies with other institutions so that they can help students to learn well. They are provided with scholarships to avail admission in those institutions.
Geologists know the past temperature of the planet based on rock and fossil evidence. Why do you think it is difficult to determine what has caused climate change in the distant past?
Answer: Greenhouse gases affect how much of the Sun's energy the Earth loses back to space. Predicting global temperature change is hard, even though the principle sounds easy. In simple terms, energy reaches Earth from the Sun.
Explanation:
What is the speed of a 1600kg car if its momentum is 120,000kgms?
Answer:
Velocity of car = 75 m/s
Explanation:
Given:
Mass = 1,600 kg
Momentum = 120,000kgm/s
Find:
Velocity of car
Computation:
Velocity = Momentum / mass
Velocity of car = 120,000 / 1,600
Velocity of car = 75 m/s
Q11) If you were standing at the top of a building and you dropped a rock.
you noticed that the rock took 5.2 s to hit the ground. Find the total
distance the rock traveled and the speed when the rock hit the ground.
Answer:
Part A
The distance travel by the rock is approximately 132.496 m
Part B
The speed when the rock hits the ground is approximately 50.96 m/s
Explanation:
Part A
The question is focused on the kinetics equation of a free falling object
The given parameter is the time it takes the rock to hit the ground, t = 5.2 s
For an object in free fall, we have;
h = 1/2·g·t²
Where;
h = The height from which the object is dropped
g = The acceleration due to gravity ≈ 9.8 m/s²
t = The time taken to travel the distance, h = 5.2 s
∴ h = 1/2 × 9.8 m/s² × (5.2 s)² ≈ 132.496 m
The distance travel by the rock, h ≈ 132.496 m
Part B
The speed, 'v', when the rock hits the ground, is given by the following kinematic equation,
v = g·t
∴ v = 9.8 m/s² × 5.2 s = 50.96 m/s
The speed when the rock hits the ground, v ≈ 50.96 m/s.
Alannah added a strip of zinc to a beaker containing a solution of copper
sulfate, as shown in the photo. She expected to observe the immediate
formation of solid copper in the beaker but saw no evidence of a reaction.
Alannah predicted that the reaction was happening too slowly to observe.
Which statement could best explain this result?
The solution of copper sulfate was too cold
Explanation:
The lack of an observable reaction when adding a zinc strip to a copper sulfate solution could be due to the zinc not being reactive enough, the reaction occurring too slowly, or an experimental error.
What is the lack of an observable reaction?The lack of an observable reaction refers to a situation where no visible or measurable change occurs when two or more substances are mixed or brought into contact with each other, even though a reaction was expected based on the chemical properties of the substances involved.
Here in the Question,
The lack of an observable reaction when Alannah added a strip of zinc to a beaker containing a solution of copper sulfate could be due to the following reasons:
Zinc and copper sulfate do not react: It is possible that the zinc strip and copper sulfate solution do not react with each other, leading to no observable change. This could occur if the zinc strip is not reactive enough to displace the copper in the copper sulfate solution.
Reaction is slow: Another possibility is that the reaction between zinc and copper sulfate is occurring but is happening too slowly to be observed. In this case, the reaction rate may be too low to produce an observable amount of solid copper in the beaker in a short period of time.
Experimental error: It is also possible that an error was made during the experiment that prevented the expected reaction from occurring. For example, the concentration of the copper sulfate solution may have been too low, or the zinc strip may have been coated with a layer of oxide that prevented it from reacting with the solution.
Therefore, Zinc may not be sufficiently reactive, the reaction may proceed too slowly, or there may have been a mistake in the experiment if there was no detectable reaction when a zinc strip was added to a copper sulphate solution.
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Two people are talking at a distance of 3.0 m from where you are, and
you measure the sound intensity as 1.1'10 W/m. Another student
is 4.0 m away from the talkers. Calculate a reasonable estimate for the
sound intensity that the other student measures.
A) 62' 10-8 W/m2
B) 1.5'10-7 W/m2
8.3' 10-8 W/m2
D) 7.8'10-7 W/m2
Answer:
The sound intensity that the other student measure, I₂ is expected to be;
A) 6.2 × 10⁻⁸ W/m²
Explanation:
The measure of sound intensity is given by the following formula;
[tex]I = \dfrac{P}{4 \cdot \pi \cdot R^2}[/tex]
[tex]\dfrac{I_2}{I_1} = \dfrac{R_1^2}{R_2^2}[/tex]
Where;
I = The intensity
R = The radius
P = The power of the sound
Whereby we have;
The distance of the two people talking, R₁ = 3.0 m
The measure of the sound intensity, I₁ = 1.1 × 10⁻⁷ W/m² (from an online source)
The distance of the other student from the two people talking, R₂ = 4.0 m
Therefore, the estimate of the sound intensity, I₂, is given as follows;
[tex]{I_2} = \dfrac{R_1^2}{R_2^2} \times {I_1}[/tex]
[tex]{I_2} = \dfrac{(3.0 \, m)^2}{(4.0 \, m)^2} \times 1.1 \times 10^{-7} \ W/m^2 = 6.1875 \times 10^{-8} \ W/m^2[/tex]
I₂ = 6.1875 × 10⁻⁸ W/m²
∴ The sound intensity that the other student measure, I₂ ≈ 6.2 × 10⁻⁸ W/m²
A 500 kg car traveling at 20 m/s rear ends another car of 600 kg at rest. The collision is great enough that the two cars stick together after they collide. How fast will both cars be going after the collision?
Answer: its 50
Explanation:
im waffling does anybody have syrup
PLEASE HELP ME
NEED IT FAST WILL GIVE B !! If correct
Answer:
25% :)
Explanation:
Brainliest for correct answer :)
Answer:
B- They both have travelled equal distances in 7 minutes
Hope this helps!
Answer:
B!
Explanation:
Which factors could be potential sources of error in the experiment? Check all that apply.
energy lost in the lever due to friction
color of the soda bottle used in the experiment
visual estimation of height of the beanbag
temperature of the lab at the time of the experiment
position of the fulcrum for the lever affecting transfer of energy
Answer:
1. energy lost in the lever due to friction
3. visual estimation of height of the beanbag
5. position of the fulcrum for the lever affecting transfer of energy
Explanation:
Edge 2021
The factors that could be potential sources of error in the experiment are
Energy lost in the lever due to frictionVisual estimation of height of the beanbag Position of the fulcrum for the lever affecting transfer of energyOptions A,C,E
What is an error in the experiment?Error in the experiment is simply defined as the inaccuracies that prevent us from seeing an entirely correct measurement.
In conclusion, Errors in experiments are inevitable but the average is used to curtail them.
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Use appropriate units and signficant figures.
You drive 67.0 mi 35.0º south of east and then drive 40.0 mi 20.0º west of south. What is your displacement?
Answer:
D = 54.9 mi, 71.6 South of the East
Explanation:
In this exercise it is asked to find the displacement of the body, one of the easiest tasks is to dispose each displacement in a Cartesian coordinate system, let's use trigonometry
* first displacement d₁ = 67.0 mi
the angle is 35 south of east, measured from the axis x θ = -35
cos -35 = x₁ / d₁
sin -35 = y₁ / d₁
x₁ = d₁ cos (-35)
y₁ = d₁ sin (-35)
x₁ = 67 cos 35 = 54.88 mi
y₁ = -67 sin 35 = -38.43 mi
* second displacement d₂ = 40, mi
the angle is 20 to the west of the south, so mean from the axis x is
θ = 180+ 20 = 200º
cos 200 = x₂ / d₂
sin 200 = y₂ / d₂
x₂ = d₂ cos 200
y₂ = d₂ sin 200
x₂ = 40.0 cos 200 = -37.59 mi
y₂ = 40.0 sin 200 = -13.68 mi
now we can find the displacement in each exercise
X_total = x₁ + x₂
X_total = 54.88 -37.59
X_total = 17.29 mi
Y_total = y₁ + y₂
Y_total = -38.43 -13.68
Y_total = - 52.11 mi
Let's use the Pythagorean theorem to find the displacement
D = [tex]\sqrt{x_{total}^2 + y_{total}^2}[/tex]
D = [tex]\sqrt { 17.29^2 + 52.11^2}[/tex]
D = 54.9 mi
to find the angle let's use trigonometry
tan θ = [tex]\frac{y_{total} }{x_{total} }[/tex]
θ = tan⁺¹ \frac{y_{total} }{x_{total} }
θ = tan⁻¹ (-52.11 / 17.29)
θ = -71.6º
the negative sign indicates that it is measured clockwise from the x-axis.
In cardinal coordinates it is 71.6 South of the East
What would be the wavelength of the sound
when it travels through the concreate wall
with the frequency of 4500 hertz?
Answer: 0,96 m
Explanation: speed in concrete is 4300 m/s
According to wave equation speed v = lambda × frequency
Lambda = speed /frequency
AWARDING BRAINLIEST
Compared to water, most metals have low specific heats.
Please select the best answer from the choices provided
T
F
Answer:
it is true
Explanation:
i think so
not really sure
Pls help I want to give more points to people this is for 100. yes 100 points
Who is number 15 on the Kansas City Chiefs
Answer:Patrick Mahomes
Explanation:
Answer:
Patrick Lavon Mahomes II
Explanation:
anyone know how to select someone as brainiest?!!!!!!!!!!!!!!!
Cynthia forgot to put the fabric softener in the wash. As her socks tumbled in the dryer, they became charged. If a small piece of lint with a charge of +1.25 E - 10 C is attracted to the socks by a force of 3.0 E - 6 N, what is the magnitude of the electric field at this location?
Answer:
E = 24000 N/C = 24 KN/C
Explanation:
The electric field experienced by a test charge is given by the following formula:
[tex]E = \frac{F}{q}\\\\[/tex]
where,
E = Electric Field = ?
F = Force of attraction = 3 x 10⁻⁶ N
q = Charge on piece of lint = 1.25 x 10⁻¹⁰ C
Therefore, using these values in the equation, we get:
[tex]E = \frac{3\ x\ 10^{-6}\ N}{1.25\ x\ ^{-10}\ C}\\\\[/tex]
E = 24000 N/C = 24 KN/C
Grant sprints 50 m to the right with an average velocity of 3.0 m/s how many seconds did grant sprint
Answer:
The time is 16.667 seconds
Explanation:
Velocity is a physical quantity that expresses the relationship between the space traveled by an object and the time used for it. Then, the average velocity results from the quotient between the change in position and the time taken to effect said change:
[tex]velocity=\frac{distance}{time}[/tex]
In this case:
velocity: 3 m/sdistance: 50 mtime: ?Replacing:
[tex]3 \frac{m}{s} =\frac{50 m}{time}[/tex]
Solving:
[tex]time =\frac{50 m}{3 \frac{m}{s}}[/tex]
time= 16.667 seconds
The time is 16.667 seconds
Grant sprints 50 m o the right with an average velocity of 3.0 m/s.
How many seconds did Grant sprint?
Answer: 16.667
Question: Why do you think the door opens, even if it is pushing back at equal force?
A scooter acquires a speed of 36km/ h in 5s just after the start. Calculate the acceleration of the scooter
Answer:
We need to convert seconds to hours:
5s= (5/60)min= 0.08min=(0.08/60)h=0.001h
a=v/t=36/0.001=36.000km/h^2
What is the transfer of energy that occurs when a force causes an object to move?
O Energy
Force
Power
O Work
Answer:
huh? I think it's Power.....
why must the lamina swing freely in physics
Answer:
Unless the lamina is able to move freely under the influence of gravity, you do not know where to draw that line.
Explanation:
an organism that cannot make its own food called
Answer:
heterotroph
Explanation:
Answer:
a predator cannot make its own food
An object is placed on a surface. A student tries to apply various combinations of forces on the object. Which pair of forces will not move the object?
Answer:
See Explanation
Explanation:
The question is incomplete, as there are no diagrams or options to provide more information to the question.
The general explanation is as follows:
For the object not to move
(1): The forces acting on the object must opposite each other. i.e. if force A acts at the right (or positive direction), force B will act at the left (or negative direction).
(2) The two forces must be equal.
So, for instance:
If the pair of forces are 5N and 5N in opposite directions, the object wil not move.
However, if one of the forces is greater, the object will move towards the direction of the greater force.
What are the 3 basic parts of an atom and what are their charges?
Answer:
electrons neutrons and protons
Explanation:
electron are negative
nuetron are neutral
protons are positive
A stone falls from rest from the top of a cliff,a second stone is thrown do wnward from the same height 2sec later with an initial speed of 30m/s.If both stones hit the ground below simultaneously,how high is the cliff?
Answer:
The cliff is 12.632 meter high.
Explanation:
Each stone experiments a free fall motion, that is, an uniformly accelerated motion due to gravity. We construct the respective equations of motion for each stone:
First stone
[tex]y_{1} = y_{o,1} +v_{o,1}\cdot t +\frac{1}{2}\cdot g\cdot t^{2}[/tex] (1)
Second stone
[tex]y_{2} = y_{o,2} +v_{o,2}\cdot (t-2) +\frac{1}{2}\cdot g\cdot (t-2)^{2}[/tex] (2)
Where:
[tex]y_{1}[/tex], [tex]y_{2}[/tex] - Final height of the first and second stone, in meters.
[tex]y_{o,1}[/tex], [tex]y_{o,2}[/tex] - Initial height of the first and second stone, in meters.
[tex]v_{o,1}[/tex], [tex]v_{o,2}[/tex] - Initial speed of the first and second stone, in meters per second.
[tex]t[/tex] - Time, in seconds.
[tex]g[/tex] - Gravitational acceleration, in meters per square second.
If we know that [tex]y_{o,1} = y_{o,2}[/tex], [tex]y_{1} = y_{2} = 0\,m[/tex], [tex]v_{o,1} = 0\,\frac{m}{s}[/tex], [tex]v_{o,2} = -30\,\frac{m}{s}[/tex] and [tex]g = -9.807\,\frac{m}{s^{2}}[/tex], then we find that time when both stones hit the ground simultaneously is:
[tex]4.904\cdot t^{2} = -30\cdot (t-2)+4.904\cdot (t-2)^{2}[/tex]
[tex]4.904\cdot t^{2} = -30\cdot t + 60 +4.904\cdot (t^{2}-4\cdot t +4)[/tex]
[tex]-30\cdot t +60 -19.616\cdot t +19.616 = 0[/tex]
[tex]49.616\cdot t = 79.616[/tex]
[tex]t = 1.605\,s[/tex]
The height of the cliff is:
[tex]y_{1} = y_{o,1} +v_{o,1}\cdot t +\frac{1}{2}\cdot g\cdot t^{2}[/tex]
[tex]y_{o,1} = 12.632\,m[/tex]
The cliff is 12.632 meter high.
A cement mixer with a radius of 2 m spins with a tangential velocity of 0.4 m/s. Determine the centripetal acceleration of a piece of dried cement stuck to the inside wall of the mixer.
Answer:
[tex]a=0.08\ m/s^2[/tex]
Explanation:
Given that,
The radius of the mixer, r = 2 m
Tangential velocity of the mixer, v = 0.4 m/s
We need to find the centripetal acceleration of a piece of dried cement stuck to the inside wall of the mixer. The formula for the centripetal acceleration is given by :
[tex]a=\dfrac{v^2}{r}\\\\a=\dfrac{(0.4)^2}{2}\\\\a=0.08\ m/s^2[/tex]
So, the centripetal acceleration is equal to [tex]0.08\ m/s^2[/tex].
A student bangs a brick at the head of a table. Three students are positioned equal distance from the head with their hands on the table. What conclusion can be made about how they each will feel the vibrations?
Explanation:
that the people closer too the head of the table will feel more vibrations than the people at the end of the table. since the vibrations will slow down as they travel farther down the table
Hope this helps!!
A circus stuntman holds himself straight out by his arms from a vertical pole. If the stuntman's center of gravity is located 0.75 m away from the pole and he weights 650 N, how much force do is arms have to apply if they exert their force upwards at 0.10 m away from the pole? [4875 N]
Answer: 4875 N
Explanation:
Given
Stuntman weight is [tex]W=650\ N[/tex]
His center of gravity is located at [tex]x=0.75\ m[/tex] away from pole
If he applies an upwards force at 0.10 m away from the pole
Suppose F is the applied force
To remain vertical, the torque of weight must be canceled by the vertical force
[tex]\Rightarrow 650\times 0.75-F\times 0.10=0\\\\\Rightarrow 650\times 0.75=F\times 0.10\\\\\Rightarrow F=\dfrac{487.5}{0.10}=4875\ N[/tex]
Kyra and Pari are timing how long it takes for 1 g of sugar to dissolve in hot water. Kyra records a time of 24.3 seconds. Pari records a time of 24 seconds. Whose reading is more precise? Why?