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[tex]\tt\displaystyle\ 3c\underline{(p-6)}+4\underline{(p-6)}=(p-6)(3c+4)[/tex]

Answer:

Step-by-step explanation:

z = (k*x*y) / w²

Where,

k = constant of proportionality

z = 72 when x = 80, y = 30 and w = 5

z = (k*x*y) / w²

72 = (k * 80 * 30) / 5²

72 = 2400k / 25

Cross product

72 * 25 = 2400k

1800 = 2,400k

k = 2,400/1800

k = 24/18

= 4/3

k = 1 1/3

k = 1.33

find z when x = 20, y = 60 and w=9

z = (k*x*y) / w²

z = (1.33 * 20 * 60) / 9²

z = (1596) / 81

Cross product

81z = 1596

z = 1596/81

z = 19.703703703703

Approximately,

z = 19.7

Answer:

The equation of line which is parallel to the given line is y =  3 x + k.

Step-by-step explanation:

The equation of the line is

y = 3 x - 8

Compare with the standard equation

y = mx + c

The slope of line is

m = 3

So, the line parallel to the given line is

y = 3 x + k

where, k is any real number.

Answer:

0.1

Step-by-step explanation:

r = y/x

r = 1.4 / 14 = 0.1

Answer:

y = - 7

Step-by-step explanation:

The equation of a horizontal line parallel to the x- axis is

y = c

where c is the value of the y- coordinates the line passes through.

The line passes through all points with a y- coordinate of - 7, then

y = - 7 ← equation of line

Answer:

D. ADC EBC

Step-by-step explanation:

cb & cd have that little line showing they're the same

Answer:

g = 48

k = 18

Step-by-step explanation:

h / 10 = 60 / 12

h / 10 = 5

h = 5 x 10

h = 50

40 / h = g / 60

40 / 50 = g / 60

4 / 5 = g / 60

g = ( 60 x 4 ) / 5

= 12 x 4

g = 48

90 / k = 60 / 12

90 / k = 5

k = 90 / 5

k = 18

Answer:

120 in^2

Hope it helps

Answer: 45

Step-by-step explanation: 9*5=45

Step-by-step explanation:

hope it helps you........

Answer:

The second one (answer of 3), but the other ones could've worked, they were just calculated wrong.

Step-by-step explanation:

Here's why each one did or didn't work:

First answer- you had the right idea by cancelling out the two in the denominator, however if you're going to divide 2, you have to divide it from everything in the equation. Meaning you would divide 4 by 2 to get 2, and then add the 1 + 2 to get final answer 3.

Second answer- since you added the numerator separately and then did the basic division, this worked.

Third one- similarly to the first one, you would have to also divide the 2 by 2 to get 1, then adding 1 + 2 to get 3.

Answer:

m+10 has the solution of 11

Answer:

y = one-third x + 3

Step-by-step explanation:

Answer:

Step-by-step explanation:

H

Answer:

15/12

Step-by-step explanation:

[tex]x = \frac{31}{12} - \frac{8}{6} = \frac{15}{12} [/tex]

and it says don't reduce otherwise u could also say 5/4

Answer:

No

Step-by-step explanation:

No we cannot say that eating strawberries causes freckles. The question says that the study showed a strong positive correlation. The answer is no because a positive correlation does not mean that there is a causation. When two things are said to correlate, it does not mean that one causes the other, correlation between two things could be as a result of another third variable that affects the both of them. The lurking variable here is going to be sunlight. this is because sunlight exposure affects both variables by causing increases  in the growth of strawberries and freckles.

The answer to whether eating strawberries causes freckles is; No, it doesn't cause freckles

A lurking variable is an explanatory variable that was not considered in a​ study, but yet affects the value of the response variable in the study.

In this question, the lurking variable is going to be sunlight due to the fact that sunlight exposure affects both variables by causing increase in the growth of strawberries and freckles.

Thus, we can conclude that there is no way we can say that eating strawberries causes freckles due to the fact that a positive correlation does not mean that there is a causation.

Read more about Lurking variables at; https://brainly.com/question/14289293

Answer:

3/4

Step-by-step explanation:

tangent is opp/ad

so that is 15/20, or 3/4

Answer:

length divided by breadth divided by  height

pls add me as brainliest

Solution:

20 - 1 1 = 9 cm

We can divide figure in 2 parts

rectangle = 14 cmx 11 cm

square = 9 cm x 9  cm

Area of rectangle = 14 * 11 = 154 cm²

Area of square = 9 * 9 = 81 cm²

Total area = 154 + 81

= 235 cm²

Answer:

4

Step-by-step explanation:

3*10=10+5s

30 = 10 + 5s

30-10 = 5s

or, 20/5= s

or, 4 =s

therefore the value of s is 4.

thank you

Answer:[tex]-0.802; \ 1.517[/tex]

Step-by-step explanation:

Given

[tex]3^x=x^4[/tex]

Here, two functions are given that is [tex]y=3^x[/tex] and [tex]y=x^4[/tex]

Check for the intersection of the graph of two curves

From the graph, they cut at two different points  i.e. [tex]x=-0.802\ \text{and}\ x=1.517[/tex]

Rest two roots are negative.

Step-by-step explanation:

hope it helps

Answer:

Step-by-step explanation:

Multiply the numbers. For multiplying variables, if they have same variables, add the exponents.

(3a²b⁷)*(5a³b⁸) = 3*5* a²⁺³ *b⁷⁺⁸

                         = 15a⁵b¹⁵

Answer:

1) 11.75

2) 11.5

3) 11 and 14

4) 16.75

5) 13, and 16

Step-by-step explanation:

The given data is 14, 14, 10, 12, 11, 13, 11, 11, 14, 10, 13, 8

1) The mean, [tex]\overline x[/tex] = (14+14+10+12+11+13+11+11+14+10+13+8)/12 = 11.75

2) The data arranged in increasing order is presented as follows;

8, 10, 10, 11, 11, 11, 12, 13, 13, 14, 14, 14

The count of he data points = 12

The median = The data at the (n + 1)/2 = (12 + 1)/2 = 6.5th position = 11 + (12  11)/2 = 11.5

The median = 11.5

3) The mode of the data set are 11 and 14

4) Where there are 5 more days per month that had a temperature above 40°C, we get;

The mean, [tex]\overline x_1[/tex] = (14+14+10+12+11+13+11+11+14+10+13+8+5×12 )/12 = 16.75 = [tex]\overline x[/tex] + 5

5) Given that there are 2 more days per month that had a temperature above 40°C, we get the days per month with temperatures above 40°C as follows;

8 + 2, 10 + 2, 10 + 2, 11 + 2, 11 + 2, 11 + 2, 12 + 2, 13 + 2, 13 + 2, 14 + 2, 14 + 2, 14 + 2

10, 12, 12, 13, 13, 13, 14, 15, 15, 16, 16, 16

Therefore, the mode are 13, and 16

Answer:

answer

Step-by-step explanation:

h+2 ≥ 10

h ≥ 10 - 2

h ≥ 8

Answer:

x= -5 + 5[tex]\sqrt{97}[/tex], x= -5 - 5[tex]\sqrt{97}[/tex]

Step-by-step explanation:

Since this quadratic is set to zero, we can use the quadratic formula to solve this.

x^2 + 10x - 2400 = 0​

Quadractic formula =  x= -b +- [tex]\sqrt{b^2 - 4ac}[/tex] /2a

For this equation:

a= 1, b=10, c=-2400

Plug these numbers into the equation and solve.

x= -10 +- [tex]\sqrt{10^2 - 4(1)(-2400}[/tex])/2(1)

x= -10 +- [tex]\sqrt{100 + 9,600}[/tex]/2

x= -10 +- [tex]\sqrt{9,700}[/tex]/2

x= -10 +- [tex]\sqrt{2^2 * 5^2 * 97}[/tex]/2

x= -10 +- 5 * 2[tex]\sqrt{97}[/tex]/2

x= -10 +- 10[tex]\sqrt{97}[/tex] / 2

Divide by 2.

x= -5 +- 5[tex]\sqrt{97}[/tex]

Answer:

x= -5 + 5[tex]\sqrt{97}[/tex] or x= -5 - 5[tex]\sqrt{97}[/tex]

Answer:

parallel

Step-by-step explanation:

Let's rewrite each equation into the slope-intercept form so that we can easily identify the slope of each line.

slope-intercept form: y= mx +c, where m is the gradient and c is the y-intercept.

9x +3y= 12

3x +y= 4 (÷3 throughout)

y= -3x +4 -----(1)

24x +8y= 35

8y= -24x +35 (-24x on both sides)

[tex]y = - 3x+ 4 \frac{3}{8} [/tex] -----(2)

Thus, the slopes of the lines are both -3. Since both lines have the same gradient, they are parallel to each other.

Notes:

• parallel lines have the same gradient

• the product of the gradients of two perpendicular lines is -1

• gradient and slope has the same meaning and can thus be used interchangeably

Answer:

C

Step-by-step explanation:

In order to prove congruency using SSS, we need to prove that all three pairs of sides are congruent.

We are already given that EF ≅ HI and that FG ≅ IJ.

Therefore, the last bit of information we need to prove congruency using SSS is that EG ≅ HJ.

Hence, our answer is C.

Given equation of the Circle is ,

[tex]\sf\implies x^2 + y^2 = 25 [/tex]

And we need to tell that whether the point (-4,2) lies inside or outside the circle. On converting the equation into Standard form and determinimg the centre of the circle as ,

[tex]\sf\implies (x-0)^2 +( y-0)^2 = 5 ^2[/tex]

Here we can say that ,

• Radius = 5 units

• Centre = (0,0)

Finding distance between the two points :-

[tex]\sf\implies Distance = \sqrt{ (0+4)^2+(2-0)^2} \\\\\sf\implies Distance = \sqrt{ 16 + 4 } \\\\\sf\implies Distance =\sqrt{20}\\\\\sf\implies\red{ Distance = 4.47 }[/tex]

Here we can see that the distance of point from centre is less than the radius.

Hence the point lies within the circle .

inside the circle

Step-by-step explanation:

we want to verify whether (-4,2) lies inside or outside or on the circle to do so recall that,

step-1: define h,k and r

the equation of circle given by

[tex] \displaystyle {(x - h)}^{2} + (y - k) ^2= {r}^{2} [/tex]

therefore from the question we obtain:

step-2: verify

In this case we can consider the second formula

the given points (-4,2) means that x is -4 and y is 2 and we have already figured out h,k and r² therefore just substitute the value of x,y,h,k and r² to the second formula

[tex] \displaystyle {( - 4 - 0)}^{2} + (2 - 0 {)}^{2} \stackrel {?}{ < } 25[/tex]

simplify parentheses:

[tex] \displaystyle {( - 4 )}^{2} + (2 {)}^{2} \stackrel {?}{ < } 25[/tex]

simplify square:

[tex] \displaystyle 16 + 4\stackrel {?}{ < } 25[/tex]

simplify addition:

[tex] \displaystyle 20\stackrel { \checkmark}{ < } 25[/tex]

hence,

the point (-4, 2) lies inside the circle

Answer:

35/40

Step-by-step explanation:

To compare, both denominator should be same.

[tex]\frac{15}{20}=\frac{15*2}{20*2}=\frac{30}{40}\\\\\\\frac{30}{40} \ < \ \frac{35}{40}\\\\\\\frac{15}{20} \ < \ \frac{35}{40}[/tex]

[tex]\sf{\bold{\blue{\underline{\underline{Given}}}}}[/tex]

[tex]\sf{\bold{\red{\underline{\underline{To\:Find}}}}}[/tex]

⠀⠀⠀⠀

[tex]\sf{\bold{\purple{\underline{\underline{Solution}}}}}[/tex]

we have to find the greater number between 15/20 and 35/40

To do this,

we have to compare the denominator same.

According to the question,

we have to find the greatest one

[tex]\sf{\bold{\green{\underline{\underline{Answer}}}}}[/tex]

⠀⠀

[tex]\therefore\mathrm{\dfrac{35}{40} > \dfrac{15}{20} }[/tex]

⠀⠀