in what direction will the seesaw rotate and what will the sign of the angular acceleration be?

Answers

Answer 1

Answer:

It can rotate in any direction. The sign of the angular acceleration depends on how you set the reference system, it can be both negative or positive.


Related Questions

Resolve the weight of the box to find the component of the weight acting parallel to the slope.
W = 50N
30

Answers

Answer:

here's your answer below

Explanation:

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The density of gold is 19.3 g/cm3. What is the volume of a 13 g gold nugget? (Density: D = m/v)

Answers

Answer:

Formula = D = m/v

Given value of D = 19.3 and m = 13g

19.3 = 13/v

V × 19.3 = 13

v = 13/19.3

v = 0.67

what's the difference between a lunar eclipse and a solar eclipse?

Answers

Answer:

passes

Explanation:

Traditionally, eclipses are divided into two major types: solar and lunar. Solar eclipses occur when the Moon passes between Earth and the Sun, leaving a moving region of shadow on Earth's surface. Lunar eclipses occur when Earth passes between the Sun and the Moon, casting a shadow on the Moon.

why efficiency of energy converters is less than 100%

Answers

The output work is always less than the input work because some of the input work is used to overcome friction.

what happens to the state of motion of the object, when you don't exert a force on it???​

Answers

Answer: It eventually loses its stamina, and would come to a stop.

Explanation:

What is the final temperature if it requires 5000 J of heat to warm 2.38892 x10-2 kg of water that starts at 5oC? Remember Cp for water is 4186 J/kgC

Answers

The final temperature of water is equal to 50.9999°C

Given the following data:

Mass = [tex]2.38892 \times 10^{-2}\;kg[/tex]Quantity of heat = 5000 J Specific heat capacity of water = 4186 J/kg°C

To determine the final temperature of water:

Mathematically, quantity of heat is given by the formula;

[tex]Q=mc\theta[/tex]

Where:

Q represents the quantity of heat.m represents the mass of an object.c represents the specific heat capacity.∅ represents the change in temperature.

Substituting the given parameters into the formula, we have;

[tex]5000=2.38892 \times 10^{-2}\times 4186 \times \theta\\\\5000=100.0001912 \theta\\\\ \theta=\frac{5000}{100.0001912} \\\\ \theta=49.9999^{\circ}C[/tex]

For the final temperature:

[tex]\theta = T_2 - T_1\\\\T_2 = \theta+T_1\\\\T_2 = 49.9999 + 50[/tex]

Final temperature = 50.9999°C

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A 25 N force acts on a box moving along a plane at a distance of 20 meters. What is the work it does with this force?

Help!!​

Answers

Answer:

500 J.

Explanation:

Work done = force * distance

= 25 * 20

= 500 Joules.

Halpinium metal (Jh(s)) can lose electrons via the photoelectric effect. The binding energy for Jh is 2.25x10-19 J. If a photon having an energy of 4.52x10-19 J strikes the surface of halpinium, calculate the de Broglie wavelength (in nm) of the electron that is ejected.

Answers

The relationship of the photoelectric effect and the de Broglie expression allows us to find the result for the wavelength of the ejected electrons is:

Wavelength of de Broglie is λ= 1.03 10⁻⁹m

The photoelectric effect was explained by Einstein assuming that the light rays behave like particles called photons, therefore the

                 [tex]E_{photon} = K + \Phi[/tex]  

where [tex]E_{photon}[/tex] is the energy of the photon given by the Planck relation, K is the kinetic energy of the ejected electrons and Ф the work function of the material.

The Planck relationship states that the energy of the photons is proportional to the frequency.

            [tex]E_{photon} = h f[/tex]

Where h is Planck's constant and f is the frequency of the photons.

They indicate The work function is Ф= 2.25 10⁻¹⁹ J, the energy of the photon [tex]E_{photon}[/tex] = 4.52 10⁻¹⁹ J, let's find the kinetic energy of the ejected electrons.

            [tex]K = E_{photon} - \Phi[/tex]  

Let's calculate.

           K = (4.52-2.25) 10⁻¹⁹

           K = 2.27 10⁻¹⁹ J

Kinetic energy is the energy of motion and is given by the relationship.

          [tex]K = \frac{p^2}{2m}[/tex]  

The wave-particle duality was established by de Broglie with the relation.

         [tex]p = \frac{h}{\lambda }[/tex]  

Let's replace.

         [tex]K = \frac{1}{2m} (\frac{h}{\lambda} )^2 \\\lambda^2 = \frac{h^2}{2m K}[/tex]

       

let's calculate.

        [tex]\lambda^2 = \frac{(6.63 \ 10^{-34})^2 }{2 \ 9.1 \ 10^{-31 } \ 2.27 \ 10^{-19}}[/tex]

        [tex]\lambda = \sqrt{1.06397 \ 10^{-18}}[/tex]

        λ  = 1.03 10⁻⁹m

In conclusion with the relationship of the photoelectric effect and the de Broglie expression we can find the result for the wavelength of the ejected electrons is:

Wavelength of de broglie is:  λ  = 1.03 10⁻⁹m

Learn more about the photoelectric effect here: brainly.com/question/25730863

What is the final velocity of an object that starts from rest and travels for 5 seconds at an acceleration of 4.3 m/s2? ____________________

Answers

The final velocity of an object that starts from rest and travels for 5 seconds at an acceleration of 4.3 m/s² is 21.5m/s.

EQUATION OF MOTION:

The final velocity of a moving object can be calculated by using one of the equations of motion as follows:

V = u + at

Where;

V = final velocity (m/s)u = initial velocity (m/s)a = acceleration (m/s²)t = time (s)

According to this question,

t = 5sa = 4.3m/s²u = 0 m/s (at rest)v = ?

v = 0 + 4.3(5)

v = 21.5m/s.

Therefore, the final velocity of an object that starts from rest and travels for 5 seconds at an acceleration of 4.3 m/s² is 21.5m/s.

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Stacey runs around a 400 meter track 2 times in 5 minutes. How does her displacement differ from her distance? *

Answers

Answer:

Distance is 800 m and Displacement is 0 m

Explanation:

Total Distance

= 400(2)

= 800 m

Total Displacement

= 0 m since she returns to the same spot

Define "one solar day".​

Answers

Answer:

the interval between transits of the apparent or mean sun across the meridian at any place.

2. Think about an activity you may have learned that involves muscle memory. Consider when you first learned the activity, how easy or difficult it was the first time, and if you can do it now without thinking. What happened in your brain during practices that resulted in muscle memory for you?

Answers

Answer:

Muscle memory is found in many everyday activities that become automatic and improve with practice, such as riding bicycles, driving motor vehicles, playing ball sports, typing on keyboards, entering PINs, playing musical instruments, poker, martial arts, and dancing.

Explanation:

plssssss look at the picture i need it right hurry pls

Answers

Answer:

it is B

Explanation:

Answer:

CO and H20

Explanation:

I couldn't find one .

Answers

Start from the top and go 7 down then go to the right 9 times and there you should fine the letter "one"

What is the energy of a 5 kg object that is held at a height of 3 m above the ground?
I really need the Formula, substitute, answer

Answers

Answer:

a 5 kilogram mass, at a height of 3 meters, while acted on by Earth's gravity would have 147.15 Joules of potential energy, PE = 3kg * 9.81 m/s2 * 5m = 147.15 J.

Explanation:

Which source of evidence did Wegener use to support his theory of continental drift?

fossils found on Earth
magnetic fields of Earth
satellite mapping of the tropical islands
glaciers found near the poles

Answers

Answer:

fossils found on Earth

Explanation:

i just did the test 100%

Answer:

Fossils on Earth

Explanation:

Fossils can show that the continents were all together by putting them together on a map you can see the fit. and when you look where fossils were, they would be right next to each other.

Select the correct answer

1. Instruments that produce sound are called sources of light.

2. Music has no ability to heal the mental stress.

3. A medium is necessary for sound travel.

4. We hear sounds of frequencies below 20 Hz. O First answer O Second answer O Third answer O Forth answer​

Answers

Answer:

C or 3

Explanation:

A: no they are called sources of sound. A is incorrect.

B: It does. Many people attest to this. But this is not a property of physics.

C: A media is required is the correct answer.

D: Dogs might. In general we don't.

I would pick C

A 0.24 kg mass with a speed of 0.60 m/s has a head-on collision with a 0.26 kg mass that is traveling in the opposite direction at a speed of 0.20 m/s. Assuming that the collision is perfectly inelastic, what is the final speed of the combined masses?

Answers

Answer:

  0.184 m/s

Explanation:

Momentum is conserved. If the velocity of the 0.24 kg mass is positive, then ...

  m1v1+m2v2 = m3v3

  (0.24 kg)(0.60 m/s) +(0.26 kg)(-0.20 m/s) = (0.24 +0.26 kg)(v)

  v = (0.144 -0.052 kg·m/s)/(0.50 kg) = 0.184 m/s

The speed of the combined masses is 0.184 m/s.

_____

Additional comment

The positive sign indicates the combined masses are moving in the direction of the original 0.24 kg mass.

what are two variables that are always in every experiment?

Answers

the independent variable and the dependent variable.



A roller coaster goes from 2.00 m/s [forward] to 10.0 m/s [forward) in 4.50 s. What is its acceleration?

Answers

The answer would be 1.77778:

We must use the kinematic equation v = v0 + at, then fill in the elements given and solve which equals 1.77778

What type of bond is found in pure gold?
A) Metallic
B) Ionic
C)Covalent
D)Diatomic

Answers

Pure gold is a metallic bond as well as silver, iron and platinum

The type of bond found in pure gold is metallic bonding, indicated by metallic bonds. Therefore option A is correct.

Metallic bonding occurs between metal atoms, such as gold, and is characterized by the sharing of electrons among a sea of delocalized electrons.

In metallic bonds, the valence electrons of metal atoms are not strongly bound to any particular atom but are free to move throughout the metal lattice.

This sharing of electrons gives rise to properties such as high electrical and thermal conductivity, malleability, and ductility, which are characteristic of metals like gold.

Unlike ionic or covalent bonds, metallic bonds do not involve the transfer or sharing of electrons between different elements.

Know more about metallic bonding:

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Both igneous and sedimentary rock can become metamorphic rock if enough ________________ are applied.

Answers

Enough heat and pressure
I hope this helps.

A massless string connects a 1.00 kg mass to a 3.00 kg cart which is resting on a frictionless horizontal surface. The mass hangs over a
frictionless pulley. When the mass is released, the cartaccelerates to the right
2.45 m/s2
4.90 m/s
9.80 m/s?
19.6 m/s

Answers

Both masses will have the same acceleration. The cart accelerates to the right with a magnitude of 4.9 m/[tex]s^{2}[/tex]. The correct answer is 4.90 m/[tex]s^{2}[/tex]

Given that a massless string connects a 1.00 kg mass to a 3.00 kg cart which is resting on a frictionless horizontal surface.

Let M = 1kg and m = 3 kg

Since the horizontal surface is frictionless, the tension in the string will be the same. when the mass is hanged over a frictionless pulley, the tension will also be the same.

When the mass is released, the cart accelerates to the right can be calculated  from Newton' second law of motion. That is,

M( g + a) = m(g - a)

1(9.8 + a) = 3( 9.8 - a)

9.8 +a = 29.4 - 3a

collect the like terms

4a = 19.6

a = 19.6/4

a = 4.9 m/[tex]s^{2}[/tex]

Therefore, the cart accelerates to the right with a magnitude of 4.9 m/[tex]s^{2}[/tex]. The correct answer is 4.90 m/[tex]s^{2}[/tex]

Learn more about dynamics here: https://brainly.com/question/24994188

Calcula el valor de la velocidad de las ondas sonoras en el agua sabiendo que su
densidad es 1.10 3 kg/m 3 y su módulo de comprensibilidad vale 2,16x10 9 N/m 2 ¿Cuál
es la longitud de onda de las ondas sonoras en el agua si su frecuencia es de 1000hz?

Answers

La velocidad de las ondas sonoras es aproximadamente 1469,694 metros por segundo. La longitud de onda de las ondas sonoras es 1,470 metros.

1) Inicialmente, debemos determinar la velocidad de las ondas sonoras a través del agua ([tex]v[/tex]), en metros por segundo:

[tex]v = \sqrt{\frac{K}{\rho} }[/tex] (1)

Donde:

[tex]K[/tex] - Módulo de compresibilidad, en newtons por metro cuadrado.[tex]\rho[/tex] - Densidad del agua, en kilogramos por metro cúbico.

Si sabemos que [tex]\rho = 1\times 10^{3}\,\frac{kg}{m^{3}}[/tex] y [tex]K = 2,16\times 10^{9}\,\frac{N}{m^{2}}[/tex], entonces la velocidad de las ondas sonoras es:

[tex]v = \sqrt{\frac{2,16\times 10^{9}\,\frac{N}{m^{2}}}{1\times 10^{3}\,\frac{kg}{m^{3}} } }[/tex]

[tex]v\approx 1469,694\,\frac{m}{s}[/tex]

La velocidad de las ondas sonoras es aproximadamente 1469,694 metros por segundo.

2) Luego, determinamos la longitud de onda ([tex]\lambda[/tex]), en metros, mediante la siguiente fórmula:

[tex]\lambda = \frac{v}{f}[/tex] (2)

Donde [tex]f[/tex] es la frecuencia de las ondas sonoras, en hertz.

Si sabemos que [tex]v\approx 1469,694\,\frac{m}{s}[/tex] y [tex]f = 1000\,hz[/tex], entonces la longitud de onda de las ondas sonoras es:

[tex]\lambda = \frac{1469,694\,\frac{m}{s} }{1000\,hz}[/tex]

[tex]\lambda = 1,470\,m[/tex]

La longitud de onda de las ondas sonoras es 1,470 metros.

Para aprender más sobre las ondas sonoras, invitamos a ver esta pregunta verificada: https://brainly.com/question/1070238

What is the radius of a circular space station that spins with a linear speed of 90.0 m/s I’m order for its walls to supply a centripetal acceleration equal to the acceleration provided by gravity on the surface of the earth?

Answers

Answer:

a = v^2 / R      centripetal acceleration

R = v^2 / a     a at the surface of earth is 9.8 m/s^2

R = (90 m/s)^2 / 9.8 m/s^2 = 827 m

how to calculate velocity with acceleration and time

Answers

Answer:

Multiply the acceleration by time to obtain the velocity change:

Example:

Velocity change = 6.95 * 4 = 27.8 m/s . Since the initial velocity was zero, the final velocity is equal to the change of speed. You can convert units to km/h by multiplying the result by 3.6: 27.8 * 3.6 ≈ 100 km/h


PLEASE HELP LIKE AN ACUALL ANSWER NOT SPAM NO ONE IS GUNNA CLICK THE LINK

Answers

Answer:

C. 9.8

Explanation:

The answer is 9.8 to this question

A cat that has a mass of 6 kg climbs to the top of a tree that is 20 m high. How much potential energy does the cat have at the top of the tree?

Have a great day!

Answers

Answer:

1176.798 J

Explanation:

[] Use the following equation:

U = mgh

m - mass

g - gravitational field

h - height

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

How much work can a 22 kW (22000W) car engine do in 60 s if it is 100% efficient?

Answers

The amount of work done by the car engine if it is 100% efficient is 366.67 Joules.

Given the following data:

Time = 60 secondsPower = 22,000 Watt

To determine the amount of work done by the car engine if it is 100% efficient:

Mathematically, the work done by an object with respect to power and time is given by the formula:

[tex]Work\;done = \frac{Power}{time}[/tex]

Substituting the given parameters into the formula, we have;

[tex]Work\;done = \frac{22000}{60}[/tex]

Work done = 366.67 Joules.

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The position as a function of time for two objects moving along a straight line is shown in the graph,
Which statement is true about the distances the two object have traveled at time ty?
Object 1 has traveled a greater distance.
B
Object 2 has traveled a greater distance.
Both objects have traveled the same distance
D
The total distance traveled by each object cannot be compared using the graph.

Answers

The distance traveled by object 1 is greater than the distance traveled by object 2.

The shortest distance between two points is a straight line. More distance is covered when the path of motion is curved.

The distance traveled by each object at different time is compared as follows;

[tex]at \ t_ A , \ \ \ d_1>d_2 \ \ \ (d_2 = 0)\\\\at \ t_B, \ \ d_1 > d_2 \\\\at \ t_C, \ \ \ d_2 > d_1 \\\\at \ t_D \ \ \ d_1 = d_2\\\\at \ t_f \ \ \ d_2 > d_1 \ \ \ (d_1 = 0)[/tex]

The major distinguishing distance traveled by each occurs at [tex]t_B[/tex] and [tex]t_C[/tex].

[tex]d_{(t_B)} > d_{(t_C)} \\\\d_1 > d_2[/tex]

Thus, we can conclude that the distance traveled by object 1 is greater than the distance traveled by object 2.

Learn more about distance of object on straight and curved path here: https://brainly.com/question/7447601

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