Answer:
gains 2 electrons. In order for the new ionic compound to form a a neutral compound, the oxygens must gain 6 electrons
Answer:
C
Explanation:
because you got to share
How many moles of gold, Au, are in 3.60 x 10^-5 g of gold?
1.83 × 10⁻⁷ mol Au
General Formulas and Concepts:Math
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightChemistry
Atomic Structure
Reading a Periodic TableUsing Dimensional AnalysisExplanation:Step 1: Define
3.60 × 10⁻⁵ g Au (Gold)
Step 2: Identify Conversions
Molar Mass of Au - 196.97 g/mol
Step 3: Convert
Set up: [tex]\displaystyle 3.60 \cdot 10^{-5} \ g \ Au(\frac{1 \ mol \ Au}{196.97 \ g \ Au})[/tex]Multiply: [tex]\displaystyle 1.82769 \cdot 10^{-7} \ mol \ Au[/tex]Step 4: Check
Follow sig fig rules and round. We are given 3 sig figs.
1.82769 × 10⁻⁷ mol Au ≈ 1.83 × 10⁻⁷ mol Au