the force that makes objects keep traveling is ____.


a.gravity
b.inertia
c.attraction
d.energy

Answers

Answer 1

Answer:

D-Energy

Explanation:

Answer 2

Answer:  b. inertia

According to Newton's First Law of Motion, if an object is at rest, then it stays at rest as long as no external forces are applied to get the object moving. If an object is in motion, then it stays in motion (again as long as no external forces are applied to say otherwise). This is known as inertia.

For example, if you were to launch a baseball into deep space (far from any planet), then the ball will travel in a straight line at a constant speed until it either hits another object to have it slow down, or another planet's gravity starts to pull on the ball.


Related Questions

A baseball player uses a pitching machine to help him improve his batting average. He places the 67.1 kg machine on a frozen pond. The machine fires a 0.101 kg baseball horizontally at a speed of 32.6 m/s. What is the magnitude of the recoil velocity of the machine

Answers

Answer:

The magnitude of the recoil velocity of the machine is 0.05  m/s.

Explanation:

Given;

mass of the baseball, m₁ = 0.101 kg

mass of the machine, m₂ = 67.1 kg

velocity of the baseball, v₁ = 32.6 m/s

let v₂ be the recoil velocity of the machine.

Apply the principle of conservation of linear momentum; the total momentum before and after firing the ball must be constant.

sum of the initial momentum of the ball and the machine = 0  (at rest)

sum of the final momentum of the ball and the machine = m₁v₁ + m₂v₂

Since total momentum is constant; m₁v₁ + m₂v₂ = 0

m₁v₁ + m₂v₂ = 0

(0.101 x 32.6) + (67.1)v₂ = 0

67.1v₂ = -3.2926

v₂ = (-3.2926) / 67.1

v₂ = -0.05  m/s (the negative sign shows that it is the opposite direction)

Thus, the magnitude of the recoil velocity of the machine is 0.05  m/s.

An LED operation at 850 nm center wavelength has a spectral width of 45 nm. What is the pulse spreading in ns/km

Answers

Answer:

[tex]\mathbf{\dfrac{\sigma_{mat}}{L} = 3.6 \ ns/ km}[/tex]

Explanation:

From the given information, the LED is operating with a given wavelength of 850 nm or 0.85 μm.

Hence, the material dispersion is [tex]\dfrac {d \tau _{mat}}{d \lambda } \simeq (80 \ ps / (nm.km) \ )[/tex]

Now, using the pulse spread formula:

[tex]\dfrac{\sigma_{mat}}{L} = \dfrac{d \tau _{mat} }{d \lambda} \sigma \lambda[/tex]

[tex]\dfrac{\sigma_{mat}}{L} = (80 \ ps/ ( m.km) \ ) \times (45 \ nm)[/tex]

Thus, the pulse spreading as a result of  material dispersion is:[tex]\mathbf{\dfrac{\sigma_{mat}}{L} = 3.6 \ ns/ km}[/tex]

The pulses spreading will be 3.6 ns/km. The greatest frequency or the number of pulses per second that may be transmitted into a fiber is pulse spreading.

What is pulse spreading?

As an optical pulse travels the length of a fiber, it widens. This feature, which is commonly represented in nanoseconds of widening per kilometer, restricts the usable bandwidth of the Fiber.

The greatest frequency, or the number of pulses per second that may be transmitted into a fiber and anticipated to emerge intact at the other end, has a limit.

This is due to a process known as pulse spreading, which restricts the file's "Bandwidth."

The given data in the problem is;

[tex]\lambda[/tex] is the wavelength = 850 nm

The pulse spreading formula is given as;

[tex]\rm \frac{\sigma_{mat}}{L} =\frac{d \tau_{mat}}{d \lambda} \sigma\lambda \\\\ \rm \frac{\sigma_{mat}}{L} = 80 \times 45 \\\\ \frac{\sigma_{mat}}{L} =3.6 \ ns/km[/tex]

Hence the pulses spreading will be 3.6 ns/km

To learn more about the pulse spreading refer to the link;

https://brainly.com/question/9351212

An inductor is connected to a 120-V, 60-Hz supply. The current in the circuit is 2.4 A. What is the inductive reactance

Answers

Answer:

Inductive reactance is 50.00 ohms

Explanation:

Given the following data;

Voltage = 120v

Frequency = 60Hz

Current = 2.4 A

To find the inductive reactance;

Inductive reactance, XL = V/I

Where;

XL represents the inductive reactance. V represents the voltage. I represents the current.

Substituting into the equation, we have;

XL = 120/2.4

XL = 50.00 ohms

explain why astronauts around the earth either in spaceship, a space station, or on a spacewalk appear to be weightless but are not actually weightless.​

Answers

Answer:

Zero gravity

Explanation:

Astronauts around the earth either in spaceship, a space station or on a space walk appear to be weightless because of the zero gravity in such environment.

Weight is a function of the mass and acceleration due to gravity a body has.

   Weight  = mass  x  acceleration due to gravity

In a place where acceleration due to gravity is 0, the weight would be zero and a person would appear to be weightless.

Q2. Point D is located at 49.3 m above the ground. The speed of the roller
coaster at point D is 0.49 m/s. Find the speed of the roller coaster at A, B, C
and E, located at the following heights above the ground:
A - 12.4 m
B-3.2 m
C-41.8 m
E-35.3 m

Answers

b hope this help u!!!

What are input energy and output energy?​

Answers

Answer:

Explanation:

Input​ refers to the amount of energy put into a device, and ​ output​ refers to the amount of energy that comes out. A device may change the type of energy but not the amount. For example, a light bulb's input energy is the form of electrical energy, and its output energy is in the form of light and heat. Efficiency.

If earth suddenly stops rotating, how will the 'Acceleration due to Gravity' change?

Answers

If the earth suddenly stops rotating about its axis, there is no effect of centrifugal force on the gravitational acceleration. So, the value of gravitational will be same at all places.

Hope this helps

Two students race up a flight of steps together. "Student A" reaches the top of the steps 2 seconds ahead of
"Student B". Which of the students is more powerful?

Answers

Um student a because they were there a few seconds ahead

Yeah, so, my teacher finna kill me if I don't turn this in today..

The Fnet = m • a equation is often used in algebraic problem solving. The table below can be filled by substituting into the equation and solving for the unknown quantity. Try it yourself and then use the click on the buttons to view the answers. To get a (acceleration) by itself, you must divide net Force by mass.

Answers

Answer:

Blank 1: 10

Blank 2: 4

Blank 3: 10

Blank 4: 5

Blank 5: 5

To move the Center of Gravity (CG) forward, you could do which of the following?
Add clay to the nose.
Increase the density of the nose material.
Decrease the volume of the horizontal and vertical stabilizer material.
All of the above.
its not Increase the density of the nose material bc i tried that so help pleasee

Answers

Answer:

I think it's no. 3

Decrease the volume of the horizontal and vertical stabilizer material.

Explanation:

Lemme know if it's correct

Answer:

all of the above

Explanation:

A standard 1 kilogram weight is a cylinder 47.0 mm in height and 49.0 mm in diameter. What is the density of the material

Answers

Answer:

11,627.91 kg/m^3

Explanation:

The computation of the density of the material is shown below

Given that

Mass , m = 1 kg

Height, H - 47 mm = 0.047 m

Diameter, d = 49 mm = 0.049 m

Now radius, r = D ÷ 2

= 0.049 ÷ 2

= 0.0245

Volume = πr^2h

= 3.14 × (0.0245)^2 × 0.047

= 0.000086m^3

Now the density of the material is

= mass ÷ volume

=  1÷  0.000086m^3

= 11,627.91 kg/m^3

Answer: 11,282.8 kg/m^3

Explanation:

We know:

Density = mass/volume

1 kg = mass

(π)(r^2)(h) = volume

Density = m/(πr^2h)

Plug in your values:

Density = 1kg/(π)(24.5 mm)^2(47 mm)

^we have to cut 49 (the diameter) in half because the equation calls for radius

Remember to multiply the density by 10^9 mm/ 1 m because the answer asks for kg/m^3

The electric field strength at a point in space a fixed (known) distance from a point charge source is 5000 N/C. How does the field strength change if the source charge has doubled charge

Answers

Answer:

See explanation

Explanation:

Electric field strength;

E = kq/d^2

k= coulombs constant

q= magnitude of charge

d = distance if separation

If

d is constant

q = 2q

Then;

E = 2 kq/d^2

Hence, the electric field strength will double.

A light wave travels from one medium into a second medium with a greater absolute index of refraction. Which characteristic of the wave can

Answers

Explanation:

With the change in medium the speed of light wave travel changes. Therefore, the absolute refractive index changes. The speed of light is maximum is vacuum and changes with the change in medium. This is the refractive indices of different medium are different.

The refractive index is the characteristic of the wave that can not change as the wave enters the second medium.

What is a refractive index?

The refractive index of a substance also known as the refraction index or index of refraction is a dimensionless quantity that specifies how quickly light passes through it in optics.

When the refractive index of a substance is increased, the speed of light in the material decreases.

The speed at which light waves travel changes as the medium changes. The absolute refractive index changes.

As a result, the speed of light is greatest in a vacuum and decreases as the medium changes. This is due to the fact that the refractive indices of various media are different.

Hence the refractive index is the characteristic of the wave that can not change as the wave enters the second medium.

To learn more about the refractive index refer to the link;

https://brainly.com/question/14592350

A ball is thrown straight up and rises to a maximum height of 22 m. At what height is the speed of the ball equal to half of its initial value

Answers

Answer:

The height of the ball when the speed of the ball is half of its initial value is 16.5 m

Explanation:

Given;

maximum height reached by the ball, h = 22 m

let the initial velocity of the = u

The equation of maximum height reached by the ball is calculated as;

v = u² - 2gh

where;

v is the final velocity at the maximum height = 0

0 = u² - (2 x 9.8)22

0 = u² - 431.2

u² = 431.2

u = √431.2

u = 20.765 m/s

Half of the initial speed = ¹/₂ x 20.765 m/s = 10.383 m/s

The height of the ball at this half value of speed is calculated as;

v² = u² - 2gh

where;

v is the final speed = 10.383 m/s

u is the initial speed = 20.765 m/s

(10.383)² = (20.765)² - (2 x 9.8)h

(2 x 9.8)h = (20.765)² - (10.383)²

19.6h = 323.379

h = 323.379 / 19.6

h = 16.5 m

Therefore, the height of the ball when the speed of the ball is half of its initial value is 16.5 m

Suppose you stand on a bathroom scale and it reads 580.0 N (about 130 lbs). Afterwards, a giant vacuuum machine sucks all the air out of the room. Would the scale reading increase, decrease, or remain the same

Answers

Answer:

the reading of the balance must decrease

Explanation:

The balance of the span is within a fluid the air, for which it is subjected to the pressure of the same, if we write the equilibrium equation we have

          F_net = B -W - F_armosphere

in this case F_net = 540 N

where the thrust is given by Archimedes' principle which states that the thrust is equal to the weight of the fluid dislodged

          B = ρ g V

in this case the density of the air is

           ρ = 1.1 kg / m³

therefore the value of the thrust is small

the force of the air is

            P = F / A

            F = P A

the air pressure is approximately P = 1 10⁵ Pa

Thus

      B <F_atmosphere

Now we can analyze what happens when we remove the air from the room, the pressure at atmospheric pressure decreases therefore the force of the air decreases, while there is some air the thrust is maintained even when it also decreases since the density of the air decreases when decreasing the Pressure.

Consequently, the reading of the balance changes depending on how the thrust and the air force decreases, in general the air force decreases much faster than the thrust, therefore the reading of the balance must decrease

The velocity of a bob on a simple pendulum at the lowest position is 10.56 m/s. What is the maximum vertical height it is able to rise to?

Answers

um I do not know sorry

Explanation:

ummmmmmjjhfgfffff

for the same type of atom with 8 protons, 9 neutrons, and 10 electrons, what type of atom or ion is it​

Answers

Answer:

O²⁻

Explanation:

Number of protons  = 8

Number of neutrons  = 9

Number of electrons  = 10

What type of atom or ion is it = ?

Solution:

Protons are the positively charged particle in an atom

Neutrons do not carry any charges

Electrons are negatively charged particles

 For this atom, the number of protons helps to identify what specie it is; so this is an oxygen atom.

Now,

     Charge  = Number of protons  - Number of electrons

      Charge  =  8  - 10  = -2

The charge on the atom is -2 and so it is an oxygen ion with -2 charge

 The ion is O²⁻

How could you find the mass of a box of pencils?
Find the mass of the parts, and then add those masses together.
Find the mass of each pencil and the mass of the box, and then add those masses together.
Find the mass of the whole.
all of the above

Answers

Explanation:

All of the ways mentioned can be used to determine the mass of the box and pencils contained.

Mass is the amount of matter contained in a substance. The substance here is the box and the pencils it contains. We can set off to measure the mass of the box and pencil as a wholeAlso, we can group the pencil find their mass and add to the mass of the box. All of these methods will accurately give us the mass of the box and pencil it contains.

A system dissipates 12 JJ of heat into the surroundings; meanwhile, 28 JJ of work is done on the system. What is the change of the internal energy ΔEthΔEthDeltaE_th of the system?

Answers

Given that,

A system dissipates 12 J of heat into the surroundings.

28 J of work is done on the system.

To find,

The internal energy of the system.

Solution,

The first law of thermodynamics is used here. According to this law,

[tex]\Delta E=Q-W[/tex]

Q is heat and W is work done

Here,

Q = -12 J is the heat dissipated by the system

W = -28 J is the work done on the system

ATQ,

[tex]\Delta E=(-12)-(-28)\\\\=-12+28\\\\=16\ J[/tex]

So, the change of internal energy of the system is 16 J.

The % DV (percent Daily Value) is based on an average 2,000-calorie diet. One gram of carbohydrate provides 4 calories of energy. If Anna’s doctor recommends getting 60% of her calories from carbohydrates, how many grams of carbohydrates should she consume each day?

Answers

Answer:

300

Explanation:

If the %DV is based on an average 2,000 calorie diet, and one gram of carbohydrate provides 4 calories, you would divide 2,000 by 4.

2,000 divided by 4 equals 500.

If Anna's doctor recommends 60% of her calories, you find out how much 60% of 500 is.

60% of 500 is 300.

Anna should consume 300 grams of carbohydrates daily.

Hope this helps!

Answer:

300

Explanation:

A student has a rectangular block. It is 2 cm wide, 2 cm tall, and 25 cm long. It has a mass of 600 g. First, calculate the volume of the block. Then, use that answer to determine the density of the block. *


Answers

Answer:

6g/cm³

Explanation:

Given parameters;

Mass  = 600g

Dimension  = 2cm wide, 2cm tall and 25cm long

Unknown:

Density  = ?

Solution

Density is the mass per unit volume of any substance. To solve this problem:

   

   Density  = [tex]\frac{mass}{volume}[/tex]  

 Since mass = 600g

Let us find the volume;

    Volume  = length x width x height

   Volume  = 25cm x 2cm x 2cm  = 100cm³  

Therefore;

         Density  = [tex]\frac{600}{100}[/tex]    = 6g/cm³

Find the length of a simple pendulum that has a period of 1.00 s. Assume that the acceleration of gravity is g

Answers

Answer:

The length of the simple pendulum is 0.248 m.

Explanation:

Given;

period of the simple pendulum, T = 1.00 s

let the length of the simple pendulum = L

The period of oscillation of a simple pendulum is calculated as;

[tex]T = 2\pi \sqrt{\frac{l}{g} } \\\\\frac{T}{2\pi } = \sqrt{\frac{l}{g} }\\\\\frac{T^2}{4\pi ^2 } = \frac{l}{g}\\\\l = \frac{gT^2}{4\pi ^2 } \\\\l = \frac{(9.8)(1)^2}{4\pi ^2 } \\\\l = 0.248 \ m[/tex]

Therefore, the length of the simple pendulum is 0.248 m.

Which color of visible light has a higher frequency than blue light?
A. Green
B. Yellow
C. Red
D. Violet

Answers

The answer I think is Violet :))

Answer:

D. violet

Explanation:

think of a UV light

If an ice cube has a mass of 5g and is left in the sun in a beaker, what will happen to its mass?​

Answers

Answer:

The mass remains the same

Explanation:

An ice cube of mass 5g left in the sun in a beaker will have no mass difference.

For this system, mass is conserved.

The ice cube begins to melt and the state changes. The state change is from solid to liquid. Since no mass is loss, the mass of the liquid formed and the ice will remain the same. In retrospect, this physical change ensures that mass is conserved.

A tourist drops (from rest) a ping pong ball from the top of the tower, which has a height of 324 meters. Assuming no air resistance, how long does it

Answers

Answer:

8.13secs

Explanation:

From the question weal are given

Height H =324m

Required

time it takes to drop t

Using the equation of motion

H = ut + 1/2gt²

Substitute the given values

324 = 0(t)+1/2(9.8)t²

324 = 1/2(9.8)t²

324 = 4.9t²

t² =324/4.9

t² = 66.12

t = √66.12

t = 8.13secs

Hence the time taken to drop is 8.13secs

A truck engine slows down from 3700 rpm to 1800 rpm in 4.25 s. How many revolutions were made by the engine during this time

Answers

Answer:

194.81 revolutions

Explanation:

Given that,

Initial angular velocity, [tex]\omega_i=3700\ rpm[/tex]

Final angular velocity, [tex]\omega_f=1800\ rpm[/tex]

Time, t = 4.25 seconds

We need to find the number of revolutions occur during this time.

3700 rpm = 387.46 rad/s

1800 rpm = 188.49 rad/s

Let [tex]\alpha[/tex] is angular acceleration. Using first equation to find it.

[tex]\alpha =\dfrac{\omega_f-\omega_i}{t}\\\\\alpha =\dfrac{188.49 -387.463 }{4.25}\\\\\alpha =-46.81\ rad/s^2[/tex]

Now let us suppose that the number of revolutions are [tex]\theta[/tex].

[tex]\theta=\dfrac{\omega_f^2+\omega_i^2}{2\alpha}\\\\=\dfrac{188.49 ^2-387.463 ^2}{2\times -46.81}\\\\=1224.087\ rad[/tex]

or

[tex]\theta=\dfrac{1224.087}{2\pi}\\\\=194.81\ rev[/tex]

Hence, there are 194.81 revolutions.

is prey abiotic or biotic?

Answers

biotic because of the prey of the reasoning

Imagine you are ice skating with your BFF. Both of you are at rest in the middle of the ice, when you shove your BFF away from you. You have a mass of 70 kg and your BFF has a mass of 60kg. When you shove off, you are moving with a velocity of 2.5 m/s.
What should the total net momentum be after the push?

Answers

Answer:

The total net momentum after the push is 0.

   

Explanation:

The total net momentum is given by:

[tex] p_{f} = p_{1_{f}} + p_{2_{f}} = m_{1}v_{1} + m_{2}v_{2} [/tex]

Where:

m₁: is the mass of 70 kg

m₂: is the mass of 60 kg

v₁: is the speed of 2.5 m/s

v₂:?

To find the final momentum first we need to find the speed v₂:

[tex]m_{1}v_{1} + m_{2}v_{2} = p_{i}[/tex]  

Where [tex]p_{i}[/tex] is the initial momentum = 0 (they are at rest)          

[tex] v_{2} = -\frac{m_{1}v_{1}}{m_{2}} = -\frac{70 kg*2.5 m/s}{60 kg} = -2.92 m/s [/tex]          

The minus sign is because the second person is moving in the opposite direction to the first person.

Now, the total net momentum is:

[tex] p_{f} = m_{1}v_{1} + m_{2}v_{2} = 70 kg*2.5 m/s + 60 kg*(-2.92 m/s) = 0 [/tex]

The final total momentum (after the push) should be zero because of momentum conservation.

Therefore, the total net momentum after the push is 0.

I hope it helps you!                

How come the arrow points the other direction when we look at it through a glass of water?

Answers

Reflection changes the way the light hits our eyes, changing the direction.

What can we conclude from observing an attractive force between a positively charged rod and some object

Answers

Answer: that the object is negatively charged.

Explanation:

We know that the force between objects that have the same type of charge is a repulsive force, while for objects with an opposite charge, the force is attractive.

In this case, we know that we have an attractive force between an object and a positively charged rod.

Then the only conclusion we can take in this situation is that the object is negatively charged.

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