Answer:
50%
Explanation:
Assuming no external forces acting during the collision, total momentum must be conserved.As one of the mass was initially at rest, the initial momentum can be written as follows:[tex]p_{o} = m* v_{1o} (1)[/tex]
If the collision is totally inelastic, both masses must move as one after the collision, so we can write the following equation:[tex]p_{f} = (m+m)* v_{f} = 2*m*v_{f}[/tex] (2)As po = pf, we can solve for vf in terms of v1o, as follows:[tex]v_{f} =\frac{v_{1o}}{2}[/tex]
The initial kinetic energy will be:[tex]K_{1o} =\frac{1}{2} * m *v_{1o}^{2} (1)[/tex]
The final kinetic energy of both masses will be as follows:[tex]K_{f} =\frac{1}{2} * 2*m *(\frac{v_{1o}}{2}) ^{2} (2)[/tex]
Rearranging in (2) we get:[tex]K_{f} =\frac{1}{2} *m *v_{1o} ^{2} *\frac{1}{2} = \frac{K_{1o} }{2}[/tex]
So, the fraction of the initial kinetic energy lost is just the half of the initial value.An airplane has a maximum airspeed velocity of 140 mph South. If the wind is 60 mph West, what is the resultant velocity (groundspeed) and direction of the airplane?
Answer:
R∠ is 152,3 ∠ 246,8
Explanation:
We need to add (vectorially) these two velocities. We can choose the coordinates system just that speed of the airplane is the negative part of the y-axis, and negative region of the x-axis, for wind speed, according to
this, the module of the resultant velocity R is:
R =√ (60)² + (140)²
R = √( 3600) + ( 19600)
R =√ 23200
R = 152,315 mph
The tangent of the angle (α ) between R and the y-axis is:
tan α = 60/140
tan α = 0,4286
From tangent tables, we get arctan 0.4286
α = 23,2⁰
Then R∠ is 152,3 ∠ 246,8
Answer:
R∠ is 152,3 ∠ 246,8
When a carpet is beaten with a stick dust particles off
...why
Answer:
An object's inertia tends to resist any change in its state of rest or motion. If a carpet is beaten with a stick then the carpet begins to move. But, the particles of dust are trying to resist their state of rest.
When jumping straight down, you can be seriously injured if you land stiff-legged. One way to avoid injury is to bend your knees upon landing to reduce the force of the impact. A 60.0-kg man just before contact with the ground has a speed of 4.18 m/s. (a) In a stiff-legged landing he comes to a halt in 1.00 ms. Find the magnitude of the average net force that acts on him during this time. (b) When he bends his knees, he comes to a halt in 0.245 s. Find the magnitude of the average net force now. (c) During the landing, the force of the ground on the man points upward, while the force due to gravity points downward. The average net force acting on the man includes both of these forces. Taking into account the directions of the forces, find the magnitude of the force applied by the ground on the man in part (b).
Answer:
a) The average force that acts on the man is [tex]2.508\times 10^{8}[/tex] newtons.
b) The average force that acts on the man is 1023.673 newtons.
c) The force of the ground on the man is 1612.093 newtons upwards.
Explanation:
a) After a careful reading of the statement we construct the following model by applying Impact Theorem, that is:
[tex]m\cdot \vec v_{A} + \vec F \cdot \Delta t = m\cdot \vec v_{B}[/tex] (Eq. 1)
Where:
[tex]m[/tex] - Mass of the man, measured in kilograms.
[tex]\vec v_{A}[/tex] - Initial velocity of the man, measured in meters per second.
[tex]\vec v_{B}[/tex] - Final velocity of the man, measured in meters per second.
[tex]\Delta t[/tex] - Impact time, measured in seconds.
[tex]\vec F[/tex] - Average net force, measured in newtons.
Now we proceed to clear average net force within expression:
[tex]\vec F \cdot \Delta t = m\cdot (\vec v_{B}-\vec v_{A})[/tex]
[tex]\vec F = \frac{m}{\Delta t}\cdot (\vec v_{B}-\vec v_{A})[/tex] (Eq. 2)
If we know that [tex]m = 60\,kg[/tex], [tex]\vec v_{A} = -4.18\,\hat{j}\,\,\,\left[\frac{m}{s} \right][/tex], [tex]\vec v_{B} = 0\,\hat{j}\,\,\,\left[\frac{m}{s} \right][/tex] and [tex]\Delta t = 1\times 10^{-6}\,s[/tex], we obtain the following vector:
[tex]\vec F = \frac{60\,kg}{1\times 10^{-6}\,s} \cdot (4.18\,\hat{j})\,\,\,\left[\frac{m}{s} \right][/tex]
[tex]\vec F = 2.508\times 10^{8}\,\hat{j}\,\,\,[N][/tex]
The average force that acts on the man is [tex]2.508\times 10^{8}[/tex] newtons.
(b) If we know that [tex]m = 60\,kg[/tex], [tex]\vec v_{A} = -4.18\,\hat{j}\,\,\,\left[\frac{m}{s} \right][/tex], [tex]\vec v_{B} = 0\,\hat{j}\,\,\,\left[\frac{m}{s} \right][/tex] and [tex]\Delta t = 0.245\,s[/tex], we obtain the following vector:
[tex]\vec F = \frac{60\,kg}{0.245\,s} \cdot (4.18\,\hat{j})\,\,\,\left[\frac{m}{s} \right][/tex]
[tex]\vec F = 1023.673\,\hat{j}\,\,\,\left[N\right][/tex]
The average force that acts on the man is 1023.673 newtons.
(c) From Second Newton's Law we find the following equation of equilibrium:
[tex]\vec F = \vec N -\vec W[/tex] (Eq. 3)
Where:
[tex]\vec F[/tex] - Average force that acts on the man, measured in newtons.
[tex]\vec N[/tex] - Force of the ground on the man, measured in newtons.
[tex]\vec W[/tex] - Weight of the man, measured in newtons.
By applying the concept of weight, we expand the previous equation:
[tex]\vec F = \vec N -m\cdot \vec g[/tex] (Eq. 3b)
Where [tex]\vec g[/tex] is the gravitational acceleration, measured in meters per square second.
And then we clear the force of the ground on the man:
[tex]\vec N = \vec F +m\cdot \vec g[/tex] (Eq. 4)
If we get that [tex]\vec F = 1023.673\,\hat{j}\,\,\,\left[N\right][/tex], [tex]m = 60\,kg[/tex] and [tex]\vec g = 9.807\,\hat{j}\,\,\,\left[\frac{m}{s^{2}} \right][/tex], the average force is:
[tex]\vec N = 1023.673\,\hat{j}\,\,\,[N]+(60\,kg)\cdot (9.807\,\hat{j})\,\,\,\left[\frac{m}{s^{2}} \right][/tex]
[tex]\vec N = 1612.093\,\hat{j}\,\,\,\left[N\right][/tex]
The force of the ground on the man is 1612.093 newtons upwards.
what was the main idea of Malthus theory of population
Answer:
The idea that population growth is potentially exponential while the growth of the food supply or other resources is linear.
Explanation:
What is meant by the term straight line motion?
A. An object can turn, but after each turn, it moves in a straight line, not curves
B. A path taking between two points, without turning left or right
C. An object is moving at a constant speed
D. Motion where the object faces forward, regardless of the path taken
Answer:
A
Explanation:
Answer: B
Explanation: I got it right
You are sitting still at a stoplight. The light turns green and you
accelerate to 35 m/s and it takes you 3.2 sec. What is your acceleration? *
Answer:
Your accleration would be 3.2 seconds because it takes you that long to reach 35 miles per hour.
Explanation:
I really hopes this helps.
A pigeon takes off from where it was initially on the ground, near where home base is located at Regions Field (close to 1st Ave. South and 14th street in Birmingham), and the bird flies at what you can consider a constant speed of 18 m/s along a direct straight line to Birmingham International Airport, where he lands on the roof of one of the main terminals there. 5.E. How many seconds does it take the bird to make this trip
Answer:
1.84 secondsExplanation:
Given
initial velocity u = 0m/s
final velocity v = 18m/s
To get the time it takes the bird to make this trip, we will use the equation of motion
v = u+gt
g is the acceleration due to gravity = 9.81m/s²
t is the time
Substitute into the formula:
[tex]18 = 0+(9.81)t\\18 = 9.81t\\9.81t = 18\\t = \frac{18}{9.81}\\ t = 1.84secs[/tex]
Hence it took the bird 1.84seconds to make this trip
1) The equilibrium constant Kc for the reaction N 2(g) + O 2(g) 2NO(g) at 1200 C is 1.00x 10^-5. Calculate the molar concentration of NO, N2 and O2 in equilibrium at 1200 C in a 1.00L container that initially had 0.114 mol of N2 and 0.114 mol of O2
2) A 2.0 mmol sample of Cl2 was closed inside a 2.0 L reaction vessel and heated to 1000k to study its dissociation into Cl atoms, Kc= 1.2x10^- 7 (a) Calculate the composition of the mixture in equilibrium. What is the percentage of decomposition of Cl2? (b) If 2.0 mmol of F2, Kc= 1.2x10^-4, is placed inside the container instead of chlorine, what will be its equilibrium composition at 1000k? Use your results from (a) and (b) to determine which is the most stable with respect to your atoms, Cl2 or F2, at 1000k
Explanation:
1) N₂ + O₂ → 2 NO
Kc = [NO]² / ([N₂] [O₂])
Set up an ICE table:
[tex]\left[\begin{array}{cccc}&Initial&Change&Equilibrium\\N_{2}&0.114&-x&0.114-x\\O_{2}&0.114&-x&0.114-x\\NO&0&+2x&2x\end{array}\right][/tex]
Plug into the equilibrium equation and solve for x.
1.00×10⁻⁵ = (2x)² / ((0.114 − x) (0.114 − x))
1.00×10⁻⁵ = (2x)² / (0.114 − x)²
√(1.00×10⁻⁵) = 2x / (0.114 − x)
0.00316 = 2x / (0.114 − x)
0.00361 − 0.00316x = 2x
0.00361 = 2.00316x
x = 0.00018
The volume is 1.00 L, so the concentrations at equilibrium are:
[N₂] = 0.114 − x = 0.11382
[O₂] = 0.114 − x = 0.11382
[NO] = 2x = 0.00036
2(a) Cl₂ → 2 Cl
Kc = [Cl]² / [Cl₂]
[tex]\left[\begin{array}{cccc}&Initial&Change&Equilibrium\\Cl_{2}&2.0&-x&2.0-x\\Cl&0&+2x&2x\end{array}\right][/tex]
1.2×10⁻⁷ = (2x)² / (2 − x)
1.2×10⁻⁷ (2 − x) = 4x²
2.4×10⁻⁷ − 1.2×10⁻⁷ x = 4x²
2.4×10⁻⁷ ≈ 4x²
x² ≈ 6×10⁻⁸
x ≈ 0.000245
2x ≈ 0.00049
2(b) F₂ → 2 F
Kc = [F]² / [F₂]
[tex]\left[\begin{array}{cccc}&Initial&Change&Equilibrium\\F_{2}&2.0&-x&2.0-x\\F&0&+2x&2x\end{array}\right][/tex]
1.2×10⁻⁴ = (2x)² / (2 − x)
1.2×10⁻⁴ (2 − x) = 4x²
2.4×10⁻⁴ − 1.2×10⁻⁴ x = 4x²
2.4×10⁻⁴ ≈ 4x²
x² ≈ 6×10⁻⁵
x ≈ 0.00775
2x ≈ 0.0155
F₂ dissociates more, so Cl₂ is more stable at 1000 K.
Eating chocolates cause pimples?
I need hypotheses answer
Answer:
Yes, eating chocolate causes pimples.. usually on your forehead
Explanation:
Chocolate may increase the severity and frequency of acne breakouts by encouraging the immune system to react more aggressively to the two bacteria that cause acne, aka pimples [found this image on internet]
The period of a pendulum is measured 16 times. The average value of the period over these 16 trials is calculated to be 1.50 seconds, whereas the standard deviation is found to be 0.24 seconds. The standard error (or standard deviation of the mean) therefore is 0.24 seconds divided by the square root of 16, yielding 0.06 seconds. Assuming that the uncertainty of this period arises solely from random error for these 16 trials, about how many additional trials would need to be completed to reduce the standard error to 0.03 seconds? ______________
Answer:
The additional trials needed is 48 trials
Explanation:
Given;
initial number of trials, n = 16 trials
the standard deviation, σ = 0.24 s
initial standard error, ε = 0.06 s
The standard error is given by;
[tex]\epsilon = \frac{\sigma}{\sqrt{n} }[/tex]
To reduce the standard error to 0.03 s, let the additional number of trials = x
[tex]0.03= \frac{0.24}{\sqrt{n+x} } \\\\0.03= \frac{0.24}{\sqrt{16+x} }\\\\0.03\sqrt{16+x} = 0.24\\\\\sqrt{16+x} = \frac{0.24}{0.03} \\\\\sqrt{16+x} = 8\\\\16+x = 8^2\\\\16+x = 64\\\\x = 64 -16\\\\x = 48 \ trials[/tex]
Therefore, the additional trials needed is 48 trials.
Nervous tissue makes up most of the
Brain
Lungs
Kidneys
Stomach
Answer:
, Nervous tissue is composed of two types of cells, neurons and glial cells. Neurons are the primary type of cell that most anyone associates with the nervous system. They are responsible for the computation and communication that the nervous system provides.
A father fashions a swing for his kids out of a long rope that he fastens to the limb of a tall tree. As one of the kids swings from this rope that is 7.00 m long his tangential speed at the bottom of the swing is 8.65 m/s. What is his angular speed in rad/s
Answer:
1.236 rad/s
Explanation:
From the question above,
v = ωr................ Equation 1
Where v = tangental speed, ω = angular speed, r = radius = length of the rope.
Make ω the subject of the equation
ω = v/r.............. Equation 2
Given: v = 8.65 m/s, r = 7.00 m
Substitute these values into equation 2
ω = 8.65/7
ω = 1.236 rad/s
Hence the angular speed is 1.236 rad/s
List the 4 materials that would light up this light bulb when dropped onto the crocodile clips. In 1 -2 sentences describe why it caused the light to turn on using these 4 key terms Conductors, circuit, electrons and flow.
Answer:
Ok I might be wrong but I think its the screwdriver, screw, key and the fork
Explanation:
Why because they all have metal in them if am wrong am sorry buddy i was struggling on the same thing
Which best illustrates the electromagnetic force in action?
-a football being kicked
-leaves falling from tree
-flashlight
-neutron beta particle and proton
Answer:
neutron beta particle and proton (last option in the list)
Explanation:
The neutron beta particle and proton inside a neutron is a clear example of a negative particle (beta particle) and a positive particle (proton) experiencing electromagnetic force (attraction between positive and negative charges) at a very short distance.
Answer:
I'm pretty sure it's the flashlight because electromagnetic force produces electricity.
I WILL MARK YOU AS BRAINLIEST IF RIGHT
A 2300 kg bus travels 15 miles in 0.75 hours . What is the average speed of the bus?
Which statement correctly identifies the scientific question and describes why the question is scientific?
Answer:
i had this question as well!
Explanation:
Answer:
1. to the Mystic 2. A Theme or social value 3. Something that can be valued 4. Can’t be observed/ Noticed.
Explanation:
Q.3 There is two conductors A and B of same
material having lengths L and 2L and radii r and
r/2 respectively. What is the ratio of their
resistance?
Answer:
resistance = (resistivity.(l/A))
so for the 2 materials we get
r1 = resistivity.(l/r)
r2=resistivity.(2l/(r/2))
so ratio r1/r2=1/4
Explanation:
The resistance is proportional to the length and inversely proportional to the area (which is proportional to the square of the radius). Thus if we are just comparing the two (so the constants will cancel out).
r1 = l/r^2 (r squared).
r2 = (2l)/(1/2r)^2
r2 = 2l/(1/4)r^2
dividing by 1/4 is the same as multiplying to 4, so you are multiplying by 2 and then by 4, thus by 8.
Thus R2 is 8 times more than R1.
Consider the head-on collision between a nitrogen molecule, mass 28u and a water molecule mass 18u. Prior to the collision, the nitrogen molecule is moving with velocity 0.4390 km/s and the water molecule is moving with velocity -0.7690 km/s. Positive velocities indicate a molecule moving to the right and a negative velocities indicate a molecule moving to the left. Immediately after the collision, the velocity of the water molecule is v = 0.7016 km/s. The atomic mass unit (u) is commonly used to indicate the mass of atoms and molecules: 1u=1.66×10-27kg. What is the velocity of the nitrogen molecule immediately after the collision? (in km/s)
The velocity of the nitrogen molecule immediately after the collision (in km/s) is -0.5064 km/s.
What is conservation of linear momentum?When there is no external force acting on the system, the initial momentum before collision is equal to the final momentum after collision.
According to the momentum conservation principle,
m₁u₁ +m₂u₂ =m₁v₁ +m₂v₂
here, u represents the initial velocities, v represents final velocities and m represents the masses.
Given is the mass of nitrogen molecule, m₁ =28u =28 x 1.66×10⁻²⁷kg = 46.48 x 10⁻²⁷kg
the mass of water molecule, m₂ =18u =18 x 1.66×10⁻²⁷kg = 29.88 x 10⁻²⁷kg
initial velocity of nitrogen molecule u₁ = 0.4390 km/s
initial velocity of water molecule u₂ = -0.7690 km/s
final velocity of water molecule v₂ = 0.7016 km/s
Substituting the values into the above expression, we get the final velocity of the nitrogen molecule
46.48 x 10⁻²⁷kg x 0.4390 km/s + 29.88 x 10⁻²⁷kg x (-0.7690 km/s) = 46.48 x 10⁻²⁷kg x v₁ + 29.88 x 10⁻²⁷kg x 0.7016 km/s
v₁ = -0.5064 km/s
Thus, the final velocity of nitrogen molecule is -0.5064 km/s (to left).
Learn more about conservation of linear momentum.
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HURRY PLS 30 MINS LEFT
A ball is rolling across the floor so that it is traveling along the positive x axis at 5.00 m/s. Due to the bend of the carpet fibers it experiences an acceleration of 1.25 m/s2 at an angle of -125.0o from the x axis.
A. What is the x component of the acceleration?
B. What is the y component of the acceleration?
C. What is the x component of the balls displacement after 3.00s?
D. What is the y component of the balls displacement after 3.00s?
E. What is the displacement of the ball over 3.00s?
Answer:
A) aₓ = -0.717 m / s² , B) a_{y} = -1.024 m / s², C) x = 11.77 m , D) y = -4.6 m ,
E) d = 12.64 m
Explanation:
For this exercise we will use trigonometry to decompose the acceleration, we are told that
a = 1.25 m /s² with an angle tea = 125º in a clockwise direction
A) cos θ = aₓ / a
aₓ = a cos θ
aₓ = 1.25 cos (-125)
aₓ = -0.717 m / s²
B) sin θ = [tex]a_{y}[/tex] / a
a_{y} = a sin θ
a_{y} = 1.25 sin (-125)
a_{y} = -1.024 m / s²
C) The displacement component
x = v₀ₓ t + ½ aₓ t²
let's calculate
x = 5 3 + ½ (-0.717) 3²
x = 11.77 m
D) the y component of the displacement
y = [tex]v_{oy}[/tex] t + ½ [tex]a_{y}[/tex] t²
in this case the initial velocity is zero
y = 0 + ½ (-1,024) 3²
y = -4.6 m
E) Let's use the Pythagorean theorem
d =√ (x² + y²)
d = √ (11.77² + 4.6²)
d = 12.64 m
1. Earth releases about 44-46 Tw of heat, in fact heat can be converted into
other forms of energy that follows the law of conservation of energy. At present
a part of electrical energy in the Philippines is derived from electrical energy.
Briefly explain why our country cannot depend on this alternative source of
energy alone.
Answer:
even if it all could be used, it wouldn't be enough
Explanation:
The land area of the US is about 5.45% of the world's area, so the amount of released heat over the area of the US is on the order of 2.4 Tw. Current technology for converting geothermal energy to electricity is about 12% efficient, so the available energy might amount to 0.29 Tw if it could all be captured.
Energy consumption in the US in 2019 was on the order of 0.46 Tw. This suggests that even if all of the thermal energy radiated by the Earth from the US could be turned to useful forms of energy, it would meet only about 60% of the US need for energy.
Part 2: Vertical Distance
1
do
2.942
d, = vertical distance
g = acceleration due to gravity (10m/s2)
t = time
How high was a brick dropped from if it falls in 2.5 seconds?
2.5 m
Ob
12.5 m
25 m
с
Od
31.25 m
Answer:
31.25m
Explanation:
Given parameters:
Acceleration due to gravity = 10m/s²
Time of drop = 2.5s
Unknown
Height of drop = ?
Solution:
To solve this problem, we must note that the brick was originally at rest. The appropriate motion equation to solve this is shown below;
H = ut + [tex]\frac{1}{2}[/tex]gt²
H is the height
u is the initial velocity
g is the acceleration due to gravity
t is the time taken
Input the parameters and solve;
H = 0 + [tex]\frac{1}{2}[/tex] x 10 x 2.5²
H = 31.25m
A 60kg woman on skates throws a 3.9kg ball with a velocity of
37m.s west. What is the velocity of the woman?
Answer:
2.405 m/s
Explanation:
Given that,
Mass of a women, m₁ = 60 kg
Mass of a ball, m₂ = 3.9 kg
Velocity of the ball, v₂ = 37 m/s
We need to find the velocity of the woman. It is a concept based on the conservation of linear momentum. Let v₁ is the velocity of the woman. So,
[tex]m_1v_1=m_2v_2\\\\v_1=\dfrac{m_2v_2}{m_1}\\\\v_1=\dfrac{3.9\times 37}{60}\\\\v_1=2.405\ m/s[/tex]
So, the velocity of the woman is 2.405 m/s.
An object is thrown vertically upward at 35 m/s. Taking g=10 m/s2, the velocity of the object 5 s later is?
Given :
Initial Velocity (u) = 35 m/s.Time taken (t) = 5 secondsgravitation (g) = 10 m/s²Final Velocity (u) = ?Answer:
↪ v = u + gt
↪ v = 35 - 10 × 5
↪ v = 35 - 50
↪ v = -15 m/s
Therefore,the Velocity of the object 5 seconds later is -15 m/s.
Question 4
10 pts
Que
A ping pong ball is thrown straight up into the air and has an initial velocity of 20.5 m/s.
Determine the peak height to which the ping pong ball rises.
Time Runnir
Attempt due:
30 Minutes
O 21 m
O 1 m
O 43 m
O Om
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Answer:
I have no clue what this means or what the answer is i am just trying to get my points up so i can ask questions
Explanation:
i am going to put something here so it looks like an explanation so yeah this has no meaning whatsoever i am very sorry that i am not able to give you the answer try looking the answer up im very very very very sorry :(
PLEASE HELP ASAP
A 744N object falling in the air experiences 434N of air resistance. what is the amount if net force of the falling objec
Answer:
The amount of net force of the falling object is -310 N, or 310 N downwards
Explanation:
Net Force
Being the force a vector, the net force is the sum of all the force vectors acting on an object at a given time:
[tex]\vec F_n=\vec F_1+\vec F_2+\vec F_3+.....\vec F_m[/tex]
When the forces are acting in one axis, say the y-axis, the direction of the forces can be considered by the sign of the magnitude of the force.
For example, the weight of the object is usually assigned a negative direction. In our problem:
W=-744 N
The air resistance always opposes the direction of motion. Since the object is falling, the air resistance is positive:
Fa = +434 N
The net force is the sum of both, including their signs:
Fn = -744 N + 434 N = -310 N
The amount of net force of the falling object is -310 N, or 310 N downwards
A ball of mass 0.1kg is thrown vertically upwards with an initial velocityof 80 m/s. calculate the pontential energy (i) half way up (ii) at its maximum height. what is its kinetic energy as it leaves the ground
Answer:
Stated below:
Explanation:
Let's calculate the maximum height
.
H=v^2/2g=320mH=v
2
/2g=320m
PE=mgh=0.1*10*320=320 J
at halfway up PE will be half of max = 320/2=160 J
KE will be equal to PEmax=320 J.
Hope I helped! ☺
In a two-slit experiment, the slit separation is 3.00 × 10-5 m. The interference pattern is created on a screen that is 2.00 m away from the slits. If the 7th bright fringe on the screen is a linear distance of 10.0 cm away from the central fringe, what is the wavelength of the light? In a two-slit experiment, the slit separation is 3.00 × 10-5 m. The interference pattern is created on a screen that is 2.00 m away from the slits. If the 7th bright fringe on the screen is a linear distance of 10.0 cm away from the central fringe, what is the wavelength of the light? 214 nm 204 nm 224 nm 100 nm 234 nm
Answer:
The value is [tex]\lambda = 214.3 \ nm [/tex]
Explanation:
From the question we are told that
The slit separation is [tex]d = 3.00 * 10^{-5} m[/tex]
The distance of the screen is [tex]D = 2.00\ m[/tex]
The order of fringe is n = 7
The path difference is [tex]y = 10.0 \ cm = 0.1 \ m[/tex]
Generally the path difference is mathematically represented as
[tex]y = \frac{n * \lambda * D}{ d}[/tex]
=> [tex]0.1 = \frac{7 * \lambda * 2.00 }{ 3.00 * 10^{-5}}[/tex]
=> [tex]\lambda = \frac{0.1 *3.00 * 10^{-5} }{7 * 2.00 }[/tex]
=> [tex]\lambda = \frac{0.1 *3.00 * 10^{-5} }{7 * 2.00 }[/tex]
=> [tex]\lambda = 2.143 *10^{-7} \ m [/tex]
=> [tex]\lambda = 214.3 \ nm [/tex]
ILL GIVE BRAINLIEST AND 5 POINT STAR RATING!!!! Which cultural region of the United States has the most Native American influence today? 1.South 2.Northeast 3.Midwest 4.West
Answer:
The answer is 4, the west.
Answer:
The west
Explanation:
hopes this helps you and your questions
HELP! IDENTIFY AND DRAW A CONCLUSION FOR THIS PROBLEM PLS! ASAP.
Answer:
the conclusion is that the plant that had been given fertilizer B grew more than the plant with fertilizer A and the plant without fertilizer. so in conclusion fertilizer B is better for growing plants fastly.
the problem is that you noticed your tomatoes were not growing properly.
Hope this helps!❤
please please please please please please
9514 1404 393
Answer:
Mona
Explanation:
Speed is the slope of the position vs. time curve. The higher speed will have the greater slope.
Mona's curve has a greater slope, so Mona is fastest.