In 16% of all homes with a stay-at-home parent, the father is the stay-at-home parent (Pew Research, June 5, 2014). An independent research firm has been charged with conducting a sample survey to obtain more current information.

Required:
a. What sample size is needed if the research firm's goal is to estimate the current proportion of homes with a stay-at-home parent in which the father is the stay-at-home parent with a margin of error of 0.03 (round up to the next whole number).
b. Repeat part (a) using a 99% confidence level (round up to the next whole number).

Answers

Answer 1

Answer:

a)

[tex]n = (\frac{z\sqrt{0.16*0.84}}{0.03})^2[/tex], in which z is related to the confidence level.

b) A sample size of 991 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].

The margin of error is:

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In 16% of all homes with a stay-at-home parent, the father is the stay-at-home parent

This means that [tex]\pi = 0.16[/tex]

a. What sample size is needed if the research firm's goal is to estimate the current proportion of homes with a stay-at-home parent in which the father is the stay-at-home parent with a margin of error of 0.03 (round up to the next whole number).

This is n for which [tex]M = 0.03[/tex]. So

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

[tex]0.03 = z\sqrt{\frac{0.16*0.84}{n}}[/tex]

[tex]0.03\sqrt{n} = z\sqrt{0.16*0.84}[/tex]

[tex]\sqrt{n} = \frac{z\sqrt{0.16*0.84}}{0.03}[/tex]

[tex](\sqrt{n})^2 = (\frac{z\sqrt{0.16*0.84}}{0.03})^2[/tex]

[tex]n = (\frac{z\sqrt{0.16*0.84}}{0.03})^2[/tex], in which z is related to the confidence level.

Question b:

99% confidence level,

So [tex]\alpha = 0.01[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.01}{2} = 0.995[/tex], so [tex]Z = 2.575[/tex].

[tex]n = (\frac{z\sqrt{0.16*0.84}}{0.03})^2[/tex]

[tex]n = (\frac{2.575\sqrt{0.16*0.84}}{0.03})^2[/tex]

[tex]n = 990.2[/tex]

Rounding up

A sample size of 991 is needed.


Related Questions

What are the solutions of x^2-12x+27

Answers

Answer:

it will be (x-9)(x-3)

Step-by-step explanation:

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then we find common factors -3 and -9

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Step-by-step explanation:

1- 1/6 - 1/4

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Answer:\b

Step-by-step explanation:

1. There are 180 girls in the sophomore class of 300.
a. what is the ratio of girls to boys?
b. what is the ratio of girls to total students?​

Answers

Answer:

girls to boys: 3:2

girls to students: 3:5

Step-by-step explanation:

180:120 can be simplified by dividing both by 6 (GCF)

180:300 can be simplified by dividing both by 6 (GCF)

Answer: 1) 180:120 2) 180:300

Step-by-step explanation: so girls to boys there is 180 girls so to find the boys you do 300-180 because there’s only males and females in the school so if they give you the number of females the rest are males. And because they gave you the girls and the total students it’s just 180:300

Sarah and Nathan each picked a bucket of strawberries. Sarah picked 4 pounds, and Nathan picked 3 pounds. How much more did Sarah pick than Nathan?

1 pounds
2 pounds
pound
1 pound

Answers

Answer:1  pound

Step-by-step explanation:

Directly you see  from Qestion Sarah picked 4  pounds and Nathan 3...for difference  4-3=1

Answer:

A: 1 pound

Step-by-step explanation:

4lbs -- 3lbs = 1lbs

Lena won a charity raffle. Her prize will be randomly selected from the 9 prizes shown below. The prizes include 7 rings, 1 camera, and 1 headset.
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(b) Find the odds in favor of Lena winning a headset ​

Answers

Answer:

(b) Find the odds in favor of Lena winning a headset ​

Step-by-step explanation:

Daniel has 250 songs on his MP3 player.
Ninety-five of the songs are by the same singer.
What percent of Daniel's songs are by that one
singer??
A. 26%
B. 38%
C. 62%
D. 83%

Answers

Its B which is 38%..............

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A. Stephen can use a sample of size 10 to reliably determine if the truck load contains damaged apples.
B. Stephen could use a sample of size less than 10 to reliably determine if the truck load contains damaged apples.
C. Stephen could have used a normal approximation to determine this probability.
D. A sample of size 10 is too small to reliably determine if the truck load contains damaged apples.
E. Stephen should sample with replacement so that the probability is exactly binomial.

Answers

Answer:

D. A sample of size 10 is too small to reliably determine if the truck load contains damaged apples.

Step-by-step explanation:

We have probability of having damaged apple = 13%

= 13/100

= 0.13

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Using the binomial distribution

P(X=x) = nCx * P^x(1-P)^n-x

Probability sample will have at least one damaged apple

= P(X>=1) = 1-p(x<1)

= 1 - P(X=0)

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= 1 - 1(1-0.13)¹⁰

= 1 - 0.87¹⁰

= 1 - 0.2484

= 0.7516

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Answers

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Answer:

Step-by-step explanation:

76/100

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Answer:

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Step-by-step explanation

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Answer:

Step-by-step explanation:

Answer:

I have answerd now you can mark him brainliest :D

Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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Answers

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Answers

Answer:

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Step-by-step explanation:

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The function that matches the graph and the given points (7, 0) and (-8, 5) is: y = 2X + 2 + 3. (option b)

This function seems to have a typo, as it simplifies to y = 23, which is a constant value and does not depend on the variable x. This means the graph would be a horizontal line at y = 23 and would not pass through the points (7, 0) and (-8, 5).

y = 2X + 2 + 3

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For (7, 0):

y = 2 * 7 + 5

y = 14 + 5

y = 19

For (-8, 5):

y = 2 * (-8) + 5

y = -16 + 5

y = -11

y = 2X - 3 + 2 Y = 2ˣ + 3 + 2:

It seems there is a typo in this option with "Y" being capitalized. Assuming it is meant to be y, we have two separate functions:

a. y = 2X - 3 + 2

b. y = 2ˣ + 3 + 2

a. For y = 2X - 3 + 2:

Evaluating the points (7, 0) and (-8, 5):

For (7, 0):

y = 2 * 7 - 3 + 2

y = 14 - 3 + 2

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For (-8, 5):

y = 2 * (-8) - 3 + 2

y = -16 - 3 + 2

y = -17

b. For y = 2ˣ + 3 + 2:

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Answers

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Answer:

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Step-by-step explanation:

xy = 80.......................... Equation 1

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logx-logy² = 1

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Substitute the value of x in therms of y equation 2 into equation 1

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Answers

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Step-by-step explanation:

to understand thisyou need to know about:equationPEMDASlet's solve:

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according to the question

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divide both sides by 4:

[tex] \sf \frac{4(8x + 2) }{2}= \frac{488}{2} \\ \sf \frac{ \cancel4 ^{} (8x + 2)}{ \cancel{4}} = \frac{ \cancel{488} \: ^{122} }{ \cancel{ \: 2}} \\ 8x + 2 = 122[/tex]

cancel 2 from both sides:

[tex] \sf 8x + 2 - 2 = 122 - 2 \\ \sf 8x = 120[/tex]

divide both sides by 8

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Margo can purchase tile at a store for $0.59 per tile and rent a tile saw for $49. At another store she can borrow the tile saw for free if she buys tiles there for $1.29 per tile. How many tiles must she buy for the cost to be the same at both stores?


Margo must buy
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Answers

Answer:

Also need help

Five cards (a hand) are dealt from a randomly shuffled deck of cards. For those of you that are not familiar with playing cards: each card has a suit (hearts, spades, diamonds, clubs) and a symbol (aces, kings, queens, etc.). The deck contains a total of 52 cards, with 13 of each suit and 4 of each symbol. What is the probability that the hand contains a) all spades

Answers

Answer: 0.0004951

Step-by-step explanation:

Given

Five cards are from the deck

The total number of cards in the deck is 52

total spades card is [tex]13[/tex]

We have to choose 5 cards out of 13, this can be done in

[tex]\Rightarrow ^{13}C_5[/tex]

The probability of choosing 5 spade cards is

[tex]\Rightarrow P=\dfrac{^{13}C_5}{^{52}C_5}\\\\\Rightarrow P=\dfrac{1287}{2598960}=0.0004951[/tex]

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