I’m not sure the steps to figure out the problem. X = 2 to x =4

Answer:

86.5

Step-by-step explanation:

Length of the string forms the hypotenuse AC of right angle triangle ABC.

C is the kite. A is the hand of the person (or, one end of the string). CB is the perpendicular

(height of the kite) from C on the ground. BC is the horizontal.

Sin 60° CB/AC = √3/2

height = 1.73/2 AC = 0.865 * 100 m = 86.5 m

Answer:

Graphs pairs of numerical data, with one variable on each axis, to look for a relationship between them

Step-by-step explanation:

The scatter diagram graphs pairs of numerical data, with one variable on each axis, to look for a relationship between them. If the variables are correlated, the points will fall along a line or curve. The better the correlation, the tighter the points will hug the line.

Answer:

D

Step by step explanation:

[tex]x^3 \cdot \sqrt[3]{x}\\\\=x^3 \cdot x^{\tfrac 13}\\\\=x^{3+ \tfrac 13}\\\\=x^{\tfrac{10}3}[/tex]

As 12 visitors went down a water slide 4, 22, 16, 10, 11, 20, 20, 12, 6, 3, 11 and 1 times, the average number of times each visitor went down is 11.41.

To reach that answer, the following calculation must be performed:

Therefore, each visitor went down, on average, 11.41 times.

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Answer:

True I'm pretty sure. Just check to be sure.

Step-by-step explanation:

Answer:

D is d because when You have to do they graph You have multiplicar

The cost to buy the flooring for Raul's bedroom is $364.65.

A scale drawing is a reduced form in terms of dimensions of an original image / building / object

Actual length of the bedroom = 4 x 3.25 = 13 feet

Actual length of the bedroom = 4 x 2.75 = 11 feet

Area = 143 square feet

Cost = 143 x 2.55 = $364.65

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YES IS THE ANSWER BECAUSE X=9

AND 11+3=87

Answer:

11.9

Step-by-step explanation:

Making sure your calculator is in degree mode, we have:

[tex] \cos(32) = \frac{x}{14} [/tex]

[tex]x = 14 \cos(32) = 11.9[/tex]

Question :-

Answer :-

Explanation :-

As per the provided information in the given question, we have been given that the Area of Triangle is 48 cm² . It's Height is given as 6 cm . And, we have been asked to calculate the Base of Triangle .

For calculating the Base of Triangle , we will use the Formula :-

[tex] \bigstar \: \: \: \boxed{ \sf{ \: Area \: _{Triangle} \: = \: \frac{1}{2} \: \times \: B \: \times \: H \: }} [/tex]

Where ,

Therefore , by Substituting the given values in the above Formula :-

[tex] \dag \: \: \: \sf { Area \: _{Triangle} \: = \: \dfrac{1}{2} \: \times \: Base \: \times \: Height } [/tex]

[tex] \longmapsto \: \: \: \sf {48 \: = \: \dfrac {1}{2} \: \times \: Base \: \times \: 6 } [/tex]

[tex] \longmapsto \: \: \: \sf {48 \: \times \: 2 \: = \: 1 \: \times \: Base \: \times \: 6} [/tex]

[tex] \longmapsto \: \: \: \sf {96 \: = \: 1 \: \times \: Base \: \times \: 6} [/tex]

[tex] \longmapsto \: \: \: \sf {96 \: = \: 6 \: \times \: Base } [/tex]

[tex] \longmapsto \: \: \: \sf {Base \: = \: \dfrac {96}{6} } [/tex]

[tex] \longmapsto \: \: \: \textbf {\textsf {Base \: = \: 16 \: cm}} [/tex]

Hence :-

[tex] \underline {\rule {180pt} {4pt}} [/tex]

A triangle has an area of 48 square centimetres. The height of the triangle is 6 centimetres. What is the base of the triangle ?

[tex] \blue{\boxed{Area \: of \: triangle = \frac{1}{2} \times b \times h}}[/tex]

Where ,

In this question the concept belongs to the areas of two dimensional shapes i.e. how we can find length , breadth or height with the help of given area .

[tex] \longmapsto \: 48 = \frac{1}{2} \times b \times 6[/tex]

Now , transposing 2 to left hand side :

[tex] \longmapsto \: 48 \times 2 = 1 \times b \times 6[/tex]

Now , multiplying 48 with 2 and multiplying b with 1 and 6 :

[tex] \longmapsto \: 96 = 6b[/tex]

Now , transposing 6 to left hand side :

[tex] \longmapsto \: \cancel\frac{96}{6} = b[/tex]

Now , by cancelling them we get :

[tex] \longmapsto \: \red{ \boxed{ \sf{b = 16 \: cm}}}[/tex]

We know that area of triangle is equal to 48 cm². So :

[tex] \rightarrow \: \frac{1}{ \cancel2} \times \cancel{16} \times 6 = 48[/tex]

Now , by cancelling 16 with 2 we get :

[tex] \rightarrow \: 8 \times 6 = 48[/tex]

So , by multiplying we get :

[tex] \rightarrow \: 48 = 48[/tex]

That means :

[tex] \rightarrow \: L.H.S = R.H.S[/tex]

Answer:

the answer without rounding is 147 but with its 100

Step-by-step explanation:

firsts you add up both sides of the triangle and then you subtract by 180 and now that you your answer but you had to round AN anyting above 150 you would have to run to 200 but you had one 47 so it's 100

Answer:

160 cm²

Step-by-step explanation:

Hello!

We can find the area of the blue shaded. region by finding the area of the rectangle, and subtracting the area of the triangle.

Area of rectangle:

Find the area of the rectangle

The units are cm so the area is 200 cm²

Area Triangle:

Find the area of the triangle

The units are cm so our area is 40 cm²

Area Shaded:

Now we can simply subtract the triangle area from the rectangle.

Answer:

B. A gravestone protrudes from the ground.

Step-by-step explanation:

To protrude means to stick out. All other answers describe the object behind or inside something.

Answer:

30 ft.³

Step-by-step explanation:

3ft. × 5ft. × 2ft. = 30 ft.³

Please rate!! I hope this helps!!

Answer:

mean

Step-by-step explanation:

The mean will decrease, in an option of mean, mode, median and range:)

The length of the wire is the perimeter of the wire

The radius of the circle is 1.59 meters

The length of the wire is given as:

L  = 20m

When cut into two pieces, we have:

The circumference of the circle is calculated using:

C = 2πr

So, we have:

2πr = 10

Make r the subject

r = 10/2π

Evaluate the quotient

r = 1.59

Hence, the radius of the circle is 1.59 meters

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Answer:

perimeter=21 area=12

Step-by-step explanation:

perimeter- 5+6+10=21

area- b x h x 1/2

6x4/2

24/2

12

Step-by-step explanation:

each pack 15 pencil

n* 15= 15n

Answer:

Maybe 8

Step-by-step explanation:

because its the same side

Answer:

49cm^2

Step-by-step explanation:

The perimeter is just a continuous line which forms the boundaries of a geometric figure.

The perimeter is just all the sides added up.

12cm+10cm+10cm+8cm+6cm+3cm = 49cm^2

Answer:

Step-by-step explanation:

Since surface area is the total area from each side, we will take the area of 3 unique sides (ie. dimensions of A x B x C will give 3 unique surfaces of dimensions A x B, B x C and A x C) and multiply each one by 2 to get the area from its duplicate. This condenses to SA (Surface Area) = 2(AB) +2(BC) + 2(AC).

Substituting in our dimensions:

[tex]SA=2(8\frac{1}{4} * 6\frac{2}{3} )+2(8\frac{1}{4}*12)+2(6\frac{2}{3}*12)[/tex]

Evaluate: SA = 468 yd²

The car on a Ferris wheel with a radius of 20 feet. travels a distance of 125.6 feet.

In order to determine the distance that the car has travelled, we will use the formula for calculating the circumference of a circle.

C = 2πr

where

r = radius

Therefore,

r is the radius of the fairy wheel

r = 20 ft

C = 2 × 3.14 × 20

C = 40 × 3.14

C = 125.6 ft

This shows that the car on a Ferris wheel with a radius of 20 feet. travels a distance of 125.6 feet

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Please don't spam the questions.

Step-by-step explanation:

Answer:

Step-by-step explanation:

The largest number of groups they can be split into and have the same number of boys and girls on each team is 6 groups

Given:

Number of girls = 12

Number of boys = 16

Find the highest common factor of 12 and 16

12 = 1, 2, 4

18 = 1, 2,4

The highest common factor of 12 and 16 is 4

Number of girls in each group = 12/4

= 3 girls

Number of boy in each group = 18/4

= 4.5 boys=5

Therefore, the group can be split into 4 groups to have 3 girls and 5 boys in each group

Answer: 64 inches

Step-by-step explanation:

Answer:

⠀

Step-by-step explanation:

⠀

We know,

[tex]{\longrightarrow \qquad \boldsymbol{\pmb{Area_{(semicircle)} = \dfrac{1}{2}( \pi {r}^{2} ) }}}[/tex]

⠀

Where,

⠀

Now, Substituting the values in the formula :

⠀

[tex]{\longrightarrow \qquad \rm{{Area_{(semicircle)} = \it \dfrac{1}{2} \times 3.14 \times ({8})^{2} }}}[/tex]

[tex]{\longrightarrow \qquad \rm{{Area_{(semicircle)} = \it \dfrac{1}{ \cancel2} \times 3.14 \times \cancel{64} }}}[/tex]

⠀

[tex]{\longrightarrow \qquad \rm{{Area_{(semicircle)} = \it {1} \times 3.14 \times 32 }}}[/tex]

⠀

[tex]{\longrightarrow \qquad \rm{{Area_{(semicircle)} = \it {1} \times 100.48 }}}[/tex]

⠀

[tex]{\longrightarrow \qquad \boldsymbol{ \pmb{Area_{(semicircle)} \approx \it 100.48 }}}[/tex]

⠀

Therefore,

Answer:

100.48 cm² ( option 2 )

Step-by-step explanation:

Given:-

To find:-

Solution:-

Area of semi-circle :-

[tex] \frac{1}{2} \pi \: r {}^{2} [/tex]

1/2 × 3.14 × 8²

[tex]100.48 \: cm {}^{2} [/tex]

Answer:

1152°

Step-by-step explanation:

interior angles of polygon = (n - 2) x 180, where n is the number of sides.

Decagon has 10 sides. 10 - 2 = 8 and 8 x 180 = 1440

Since there are 10 angles, Each angle a= 1440 / 10, which equals 144.

Finally, multiply 144 by 8 and you get 1152°

Answer:

Question 3

Given expression:

[tex]\sf \left(\dfrac{-8}{9} \times \dfrac{1}{-5}\right)+\left(\dfrac{-8}{9} \times \dfrac{-7}{11}\right)[/tex]

Both parentheses share a common term.

To factor out a common term: ab + ac = a(b + c)

[tex]\textsf{Factor out the common term }\dfrac{-8}{9}[/tex]

[tex]\sf \implies\dfrac{-8}{9} \times \left(\dfrac{1}{-5}+\dfrac{-7}{11}\right)[/tex]

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Question 4

To calculate the amount of money Rajni had to begin with, sum the three amounts she spent:

[tex]\sf \implies total=10\frac14+25\frac34+16\frac12[/tex]

As [tex]\sf a\frac{b}{c}=a+\frac{b}{c}[/tex], then:

[tex]\sf \implies 10+\frac14+25+\frac34+16+\frac12[/tex]

Collect and sum the whole numbers:

[tex]\sf \implies (10+25+16)+\frac14+\frac34+\frac12[/tex]

[tex]\sf \implies 51+\frac14+\frac34+\frac12[/tex]

As  [tex]\sf \frac14+\frac34=\frac44=1[/tex], then

[tex]\sf \implies 51+1+\frac12[/tex]

[tex]\sf \implies 52+\frac12[/tex]

[tex]\sf \implies 52\frac12[/tex]

The weight of the third heaviest among the four dogs is 2 kg.

An equation is an expression that shows the relationship between two or more numbers and variables.

The 4 dogs weight is 60 kg with each dog weight been different. The second heaviest dog weighs 28 kg.

Let the heaviest dog be 29 kg, the third heaviest be 2 kg and the fourth be 1 kg.

29 + 28 + 2 + 1 = 60 kg

The weight of the third heaviest among the four dogs is 2 kg.

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