Answer:
BCF is the correct answer
Answer:
b, c, and f
Step-by-step explanation:
because on the negative scale -5 is closer to 0 than -7, -4 is closer to 0 than -6, and -4 is closer to 0 than -5. So in this case b, c, and f are true because it is greater than. Sorry if I explained it badly, but im pretty sure its b, c, and f.
I’m doing algebra homework and I’m really stumped on this problem I could use the help
Step-by-step explanation:
Zeros : -2
axis of symmetry : x = -2
Max or Min : min
Vertex : (-2, 0)
algebra help please answer
Answer:
Answer is 1st and Last
Step-by-step explanation:
Because if you use logic you should know why
If a number is chosen at random from the numbers 1 to
20 inclusive, what is the probability that a single-digit
number will be picked? ( give your answer in simplified
fractions eg. 2/5 when necessary)
Answer:
1/20
Step-by-step explanation:
only a single number can be chosen out of 20. And 1/20 is the most simplified it can get.
Which equation shows how to use equivalent fractions to evaluate 5/7 + 1/2.
Choose 1 answer:
Answer:
last one
Step-by-step explanation:
[tex]\frac{5}{7}[/tex] = [tex]\frac{10}{14}[/tex]
[tex]\frac{1}{2}[/tex] = [tex]\frac{7}{14}[/tex]
need common denominators to add fractions.
what ever is multiplied to the bottom needs to be multiplied to the top
for example : [tex]\frac{5}{7}[/tex] x [tex]\frac{2}{2}[/tex] = [tex]\frac{10}{14}[/tex]
Find the set of values of k for which the line y=kx-4 intersects the curve y=x²-2x at 2 distinct points?
Answer:
[tex]-6 < k < 2[/tex]
Step-by-step explanation:
Given
[tex]y = x^2 - 2x[/tex]
[tex]y =kx -4[/tex]
Required
Possible values of k
The general quadratic equation is:
[tex]ax^2 + bx + c = 0[/tex]
Subtract [tex]y = x^2 - 2x[/tex] and [tex]y =kx -4[/tex]
[tex]y - y = x^2 - 2x - kx +4[/tex]
[tex]0 = x^2 - 2x - kx +4[/tex]
Factorize:
[tex]0 = x^2 +x(-2 - k) +4[/tex]
Rewrite as:
[tex]x^2 +x(-2 - k) +4=0[/tex]
Compare the above equation to: [tex]ax^2 + bx + c = 0[/tex]
[tex]a = 1[/tex]
[tex]b= -2-k[/tex]
[tex]c =4[/tex]
For the equation to have two distinct solution, the following must be true:
[tex]b^2 - 4ac > 0[/tex]
So, we have:
[tex](-2-k)^2 -4*1*4>0[/tex]
[tex](-2-k)^2 -16>0[/tex]
Expand
[tex]4 +4k+k^2-16>0[/tex]
Rewrite as:
[tex]k^2 + 4k - 16 + 4 >0[/tex]
[tex]k^2 + 4k - 12 >0[/tex]
Expand
[tex]k^2 + 6k-2k - 12 >0[/tex]
Factorize
[tex]k(k + 6)-2(k + 6) >0[/tex]
Factor out k + 6
[tex](k -2)(k + 6) >0[/tex]
Split:
[tex]k -2 > 0[/tex] or [tex]k + 6> 0[/tex]
So:
[tex]k > 2[/tex] or k [tex]> -6[/tex]
To make the above inequality true, we set:
[tex]k < 2[/tex] or [tex]k >-6[/tex]
So, the set of values of k is:
[tex]-6 < k < 2[/tex]
Does the set of numbers form a Pythagorean triple? Explain.
Explanation:
Pythagorean Triples are sets of whole numbers for which the Pythagorean Theorem holds true. The most well-known triple is 3, 4, 5. This means that 3 and 4 are the lengths of the legs and 5 is the hypotenuse.
Check if the point (-3, -5) lies on the line y= 2x -1
Plzzzzz hurry
Answer:
no
Step-by-step explanation:
To determine if the point lies on the line, substitute x = - 3 into the equation and if the value obtained equals - 5 then it lies on the line.
y = 2(- 3) - 1 = - 6 - 1 = - 7 ≠ - 5
Then the point (- 3, - 5 ) is not on the line
Does 12, 24, 36 form a right triangle?
Answer:
no bc pythagorean
Step-by-step explanation:
which linear function represents a slope of 1/4
Answer:
B
Step-by-step explanation:
The line goes down 1 and right 4.
Answer:
Option 2 represents a slope of 1/4.
How do i solve 1+1=0
Answer:
Logically that's not possible but if you want to prove it then, you have to use a trick.
Step-by-step explanation:
1 + 1 = 1 + [tex]\sqrt{1}[/tex]
= 1 + [tex]\sqrt{(-1) * (-1)}[/tex]
= 1 + [tex]\sqrt{(-1)}[/tex] * [tex]\sqrt{(-1)}[/tex]
= 1 + [tex]\sqrt{i^2}[/tex] * [tex]\sqrt{i^2}[/tex]
= 1 + i * i
= 1 + i^2
= 1 + (-1)
= 1 - 1
= 0
So, 1 + 1 = 0
Hope this will help. Please give me brainliest.
Write the ratio of corresponding sides for the similar triangles and reduce the ratio to lowest terms.
2 similar triangles. Triangle 1 has side lengths 16, 24, blank. Triangle 2 has side lengths 12, 18, blank.
a.
StartFraction 12 Over 24 EndFraction = StartFraction 18 Over 16 EndFraction = StartFraction 1 Over 2 EndFraction
b.
StartFraction 12 Over 18 EndFraction = StartFraction 16 Over 24 EndFraction = StartFraction 2 Over 3 EndFraction
c.
StartFraction 12 Over 16 EndFraction = StartFraction 18 Over 24 EndFraction = StartFraction 3 Over 4 EndFraction
d.
StartFraction 18 Over 12 EndFraction = StartFraction 24 Over 16 EndFraction = StartFraction 3 Over 2 EndFraction
Please select the best answer from the choices provided
A
B
C
D
Answer:
the correct answer is
C.
StartFraction 12 Over 16 EndFraction = StartFraction 18 Over 24 EndFraction = StartFraction 3 Over 4 EndFraction
A random experiment was conducted where a Person A tossed five coins and recorded the number of ""heads"". Person B rolled two dice and recorded the larger number out of the two dice. Simulate this scenario (use 10000 long columns) and answer questions 10 to 13.
Answer:
(10) Person B
(11) Person B
(12) [tex]P(5\ or\ 6) = 60\%[/tex]
(13) Person B
Step-by-step explanation:
Given
Person A [tex]\to[/tex] 5 coins (records the outcome of Heads)
Person [tex]\to[/tex] Rolls 2 dice (recorded the larger number)
Person A
First, we list out the sample space of roll of 5 coins (It is too long, so I added it as an attachment)
Next, we list out all number of heads in each roll (sorted)
[tex]Head = \{5,4,4,4,4,4,3,3,3,3,3,3,3,3,3,3,2,2,2,2,2,2,2,2,2,2,1,1,1,1,1,0\}[/tex]
[tex]n(Head) = 32[/tex]
Person B
First, we list out the sample space of toss of 2 coins (It is too long, so I added it as an attachment)
Next, we list out the highest in each toss (sorted)
[tex]Dice = \{2,2,3,3,3,3,4,4,4,4,4,4,5,5,5,5,5,5,5,5,6,6,6,6,6,6,6,6,6,6\}[/tex]
[tex]n(Dice) = 30[/tex]
Question 10: Who is likely to get number 5
From person A list of outcomes, the proportion of 5 is:
[tex]Pr(5) = \frac{n(5)}{n(Head)}[/tex]
[tex]Pr(5) = \frac{1}{32}[/tex]
[tex]Pr(5) = 0.03125[/tex]
From person B list of outcomes, the proportion of 5 is:
[tex]Pr(5) = \frac{n(5)}{n(Dice)}[/tex]
[tex]Pr(5) = \frac{8}{30}[/tex]
[tex]Pr(5) = 0.267[/tex]
From the above calculations: [tex]0.267 > 0.03125[/tex] Hence, person B is more likely to get 5
Question 11: Person with Higher median
For person A
[tex]Median = \frac{n(Head) + 1}{2}th[/tex]
[tex]Median = \frac{32 + 1}{2}th[/tex]
[tex]Median = \frac{33}{2}th[/tex]
[tex]Median = 16.5th[/tex]
This means that the median is the mean of the 16th and the 17th item
So,
[tex]Median = \frac{3+2}{2}[/tex]
[tex]Median = \frac{5}{2}[/tex]
[tex]Median = 2.5[/tex]
For person B
[tex]Median = \frac{n(Dice) + 1}{2}th[/tex]
[tex]Median = \frac{30 + 1}{2}th[/tex]
[tex]Median = \frac{31}{2}th[/tex]
[tex]Median = 15.5th[/tex]
This means that the median is the mean of the 15th and the 16th item. So,
[tex]Median = \frac{5+5}{2}[/tex]
[tex]Median = \frac{10}{2}[/tex]
[tex]Median = 5[/tex]
Person B has a greater median of 5
Question 12: Probability that B gets 5 or 6
This is calculated as:
[tex]P(5\ or\ 6) = \frac{n(5\ or\ 6)}{n(Dice)}[/tex]
From the sample space of person B, we have:
[tex]n(5\ or\ 6) =n(5) + n(6)[/tex]
[tex]n(5\ or\ 6) =8+10[/tex]
[tex]n(5\ or\ 6) = 18[/tex]
So, we have:
[tex]P(5\ or\ 6) = \frac{n(5\ or\ 6)}{n(Dice)}[/tex]
[tex]P(5\ or\ 6) = \frac{18}{30}[/tex]
[tex]P(5\ or\ 6) = 0.60[/tex]
[tex]P(5\ or\ 6) = 60\%[/tex]
Question 13: Person with higher probability of 3 or more
Person A
[tex]n(3\ or\ more) = 16[/tex]
So:
[tex]P(3\ or\ more) = \frac{n(3\ or\ more)}{n(Head)}[/tex]
[tex]P(3\ or\ more) = \frac{16}{32}[/tex]
[tex]P(3\ or\ more) = 0.50[/tex]
[tex]P(3\ or\ more) = 50\%[/tex]
Person B
[tex]n(3\ or\ more) = 28[/tex]
So:
[tex]P(3\ or\ more) = \frac{n(3\ or\ more)}{n(Dice)}[/tex]
[tex]P(3\ or\ more) = \frac{28}{30}[/tex]
[tex]P(3\ or\ more) = 0.933[/tex]
[tex]P(3\ or\ more) = 93.3\%[/tex]
By comparison:
[tex]93.3\% > 50\%[/tex]
Hence, person B has a higher probability of 3 or more
Find the x-intercept of the graph of the linear equation y= - 1/3 x+3?
x-intercept =
Answer:
9
Step-by-step explanation:
Plug in 0 for y and solve for x.
0 = (-1/3)x + 3
(-1/3)x = -3
x = 9
Podemos ver una muestra de laboratorio que contiene 32 bacterias inicialmente, y que luego de aplicar una vacuna, se autodestruyen a la mitad cada una hora. ¿Al cabo de cuántas horas no quedará ninguna bacteria?. Resuelve utilizando potencias y sus propiedades.
Answer:
10 horas.
Step-by-step explanation:
Dado que una muestra de laboratorio contiene 32 bacterias inicialmente, y luego de aplicar una vacuna, se autodestruyen a la mitad cada una hora, para determinar al cabo de cuántas horas no quedará ninguna bacteria se debe realizar el siguiente cálculo:
32 / 2 = 16
16 / 2 = 8
8 / 2 = 4
4 / 2 = 2
2 / 2 = 1
1 / 2 = 0.5
0.5 / 2 = 0.25
0.25 / 2 = 0.125
0.125 / 2 = 0.0625
0.0625 / 2 = 0.03125
Por lo tanto, al cabo de 10 horas no quedará ninguna bacteria.
Please Help. Thank You
Answer:
x = 21
Step-by-step explanation:
We can use ratios to solve
35 x
------ = ----------
25 15
Using cross products
35*15 = 25x
525 = 25x
Divide each side by 25
525/25 =25x/25
21 =x
Which ratios are equal to cos(B)? Choose the TWO ratios that apply.
Answer:2 and 5
Step-by-step explanation:
The ratios that are equal to [tex]cos(B)[/tex] : [tex]\bold{\frac{BC}{AB}}[/tex] and [tex]\bold{\frac{EF}{DE}}[/tex]
What are similar triangles?"Two triangles are said to be similar
- if corresponding angles are equal and the sides
- if corresponding sides of the triangles are in proportion."
What is cosine angle?In a right triangle,
cos(Ф) = (adjacent side of angle Ф) ÷ hypotenuse
For given example,
Triangles ABC and DEF are similar triangles.
This means, ∠A = ∠D, ∠B = ∠E, ∠C = ∠F
And, [tex]\frac{AB}{DE} = \frac{BC}{EF} = \frac{AC}{DF}[/tex] ..............(i)
For a right triangle ABC,
the cosine of angle B is,
[tex]cos(B)=\frac{BC}{AB}[/tex]
From (i),
[tex]\frac{BC}{AB}=\frac{EF}{DE}[/tex]
So, the cosine of angle B is,
[tex]cos(B)=\frac{EF}{DE}[/tex]
Therefore, the ratios that are equal to [tex]cos(B)[/tex] : [tex]\frac{BC}{AB}[/tex] and [tex]\frac{EF}{DE}[/tex]
Learn more about similar triangles here:
https://brainly.com/question/25882965
#SPJ2
(05.02)
Solve the following system of equations: (1 point)
x − 2y = 14
x + 3y = 9
Group of answer choices
(1, 12)
(−1, −12)
(12, −1)
(12, 1)
How much will this trash can hold? It is 4 feet tall and has a base radius of 1 foot.
_____ cubic feet
Answer:
volume = 12.56 cubic feet
Step-by-step explanation:
[tex]volume = \pi r^2 \times h \\\\volume = 3.14 \times 1 ^2 \times 4 = 3.14 \times 4 = 12. 56 \ cubic \ feet[/tex]
Geometry is fun or ducks like water
Answer:
i am a duck and i can confirm water is pretty poggers
Step-by-step explanation:
Find the value of x.
42°
(5x + 2)
Answer:
x=8
Step-by-step explanation:
assuming this is what you mean:
(5x+2)=42
try to
isolate the variable by subtracting 2 from both sides
5x=40
continue to isolate the variable
divide by 5 on both sides
5x/5=40/5
x=8
Three students found the mean of the data set given. Their work is shown below. Choose the student who correctly found the mean. 10, 10, 13, 14, 16, 19, 23
Answer:
15
Step-by-step explanation:
To find the mean you add all the numbers together then divide by how many numbers there are.
10+10+13+14+16+19+23=105
105÷7=15
So the student who found 15 as their mean is correct.
5 1 point In the standard form of a circle (x – h)^2 + (y - k)^2 = r^2, which of the following represents the center of the circle?
A:(h,k)
B:r
C:(x,y)
D:r^2
Option C with h and k
see screenshot for an example
general formula is
r² = (x - x-center)² + (y - y-center)²
PLEASE HELP ME FOR 15 POINTS AND BRAINLIEST QUICK! thanks.
Answer:
cumulative frequency
1
8
25
45
58
62
Answers:
Cumulative frequencies from top to bottom:
1825455862Other answers:
There are 62 golfers total mode = 72Median is between slots 31 and 32 Median = 72Refer to the diagram below
================================================
Explanation:
In the first row, the frequency is 1, so that's the cumulative frequency for that row. It's the total frequency so far.
In the second row, the cumulative frequency is now 8 because we add the two frequencies so far (1+7 = 8)
The third row will have a cumulative frequency of 1+7+17 = 25.
The rest of the rows will follow this pattern to fill out the table. Refer to the diagram below to see the filled out table.
----------------------------
At the very end, you should get 62 golfers total (the cumulative frequency for the bottom row).
The mode score is the most frequent value. In this case, that's the score 72 since it shows up the most times (ie has the largest frequency).
Because we have n = 62 people total, the median is between slots n/2 = 62/2 = 31 and 32
Go back to the table and note how 25 is the cumulative frequency for the third row. Since 25 is smaller than 31 and 32, this means that the median cannot be in the first three rows. Instead, it's in the fourth row because the frequency 17 here is more than enough to get us from slot 25 to slots 31 and 32.
In other words, the values 72 and 72 are in slots 31 and 32. The midpoint of which is 72.
The median is therefore 72.
Side note: the mode and median aren't always the same value.
10 POINTS!!! 1 to 16 please hurry and answer correctly
Answer:
1.false
2.true
3.true
4.true
5.120
6.105
7.85
8.100
9.115
10.40
11.13
12.30
13.36
14.65
15.35
16.75
solve the equation (log base 3^x)^2_6log base 3^x+9=0
Step-by-step explanation:
the answer is in the above image
Helpppp and explain :)
Answer:
Problem 1: 25
Problem 2: 693
Step-by-step explanation:
Problem 1:
f(x) = -5n + 1
g(x) = -6n + 2
(f + g)(-2) = f(-2) + g(-2)
f(-2) = -5(-2) + 1
f(-2) = 10 + 1
f(-2) = 11
g(-2) = -6(-2) + 2
g(-2) = 12 + 2
g(-2) = 14
(f + g)(-2) = 11 + 14
(f + g)(-2) = 25
Problem 2:
f(x) = 7 + 2x
g(x) = 5x - 2
fg(7) = f(7) × g(7)
f(7) = 7 + 2(7)
f(7) = 7 + 14
f(7) = 21
g(x) = 5(7) - 2
g(x) = 35 - 2
g(x) = 33
Therefore:
fg(7) = 21 × 33
fg(7) = 693
Which of following equations have a solution y = 8. A:4y + 3 = 32. B:6 + 5y = 46. C:9y ÷ 4 = 8. D:10y ÷ 4 = 20. E:65 - 3y = 27
The figure is a parallelogram. One diagonal measures 28 units.
A parallelogram is shown. It has side lengths 21, 20, 21, and 20. The length of a diagonal is 28.
Is the figure a rectangle? Explain.
Answer:
It is not a rectangle
Step-by-step explanation:
A rectangle is a shape with 4 sides, such that we have two pairs of parallel sides, where the length of the parallel sides is equal.
so we have two parallel sides with length L and two parallel sides with length L'.
In this figure ,we can see two sides with length 20 and other two with length 21, and this is a rectangle only if the sides meet at 90°degree angles (this would mean that the opposite sides are parallel)
To see this, we can think that the triangle formed by the diagonal and two sides is a triangle rectangle, then using the Pythagorean theorem we should have that:
20^2 + 21^2 = 28^2
841 = 784
So this is not a triangle rectangle, meaning that the angle between the side of 20 and the side of 21 is not a right triangle, then the figure is not a rectangle.
Therefore, it is not a rectangle
Hope u understand
Please mark the brainliest
Thank You
In 2001 , a youth clubs total income was £1000 the club spent 60% of its total income on renting a hall it further spent £250 on prizes work out the ratio
The amount spent on hall : amount spent on prizes
Answer:
12:5
Step-by-step explanation:
To calculate the ratio, we must first find the values of the two expenditures. The amount spent on renting a hall was 60% of £1000. To represent percentages in decimals, we can simply divide the percentage by 100, resulting in 0.6 here. We can then multiply this value by 1000 to get the amount spent on renting a hall, which comes out to £600
The ratio is then 600 : 250, 60 : 25 (divide both sides by 10) , or 12:5 (divide both sides by another 5)
The two triangles are similar.
What is the value of x?
Enter your answer in the box HELP PLS
The Above triangles are similar, Therefore the corresponding sides would be proportional.
that is : -
[tex] \dfrac{16}{12} = \dfrac{6x}{5x - 2} [/tex][tex]16 \times (5x - 2) = 12 \times 6x[/tex][tex]80x - 32 = 72x[/tex][tex]80x - 72x = 32[/tex][tex]8x = 32[/tex][tex]x = 32 \div 8[/tex][tex]x = 4[/tex][tex]\mathfrak{best \: \: of \: \: luck \: \: for \: \: your \: \: assignment}[/tex]