If you cut 20 lemons by half and then cut half of these halves by half, how many lemon parts will you have?

Answer:

(B) 30

Step-by-step explanation:

Imagine you drew a line from Point T until it touched Line PR. Let's call that point where it touched Line PR "Point Z".

That line (called Line TZ) would be perpendicular to PR, forming a 90 degree angle.

Now, TZW is a triangle.

To find x, we need to find the angle measurment of Angle ZTW.

This is where we use the hexagon.

A hexagon's interior angle sum is 720, meaning each interior angle is equal to 120 degrees. So Angle UTS would equal 120 degrees.

However, Line TZ bisects that 120 degree angle, so Angle ZTW would equal 60 degrees (because 120/2 = 60).

Now we have two angles of the triangle: 90 & 60.

A triangle's interior angle sum is 180.

Add 90 & 60, which is 150, and subtract 150 from 180.

The result is 30, which is the angle measurement of x.

Hope it helps (●'◡'●)

Answer:

graph 1

Step-by-step explanation:

if it's all the times BETTER

then it shouldn't include 15

Answer:

Graph 3.

Step-by-step explanation:

.

Answer:

y = f(t) = 6t + 50

Step-by-step explanation:

Given:

y = 2x + 50

Where,

x = 3t

Substitute x = 3t into the equation

y = 2x + 50

y = 2(3t) + 50

Open parenthesis

y = 6t + 50

y = f(t) = 6t + 50

Answer:

(- ∞,∞)

there is no restriction when taking  cube roots

Step-by-step explanation:

Answer:

y int = -6

x = 1 axis symmetry

vertex : (1,-8)

x int: (3,0),(-1,0)

Step-by-step explanation:

Answer:

e t

Step-by-step explanation:

Answer:

x = 2.5

Step-by-step explanation:

Because the triangles are similar, you can divide the sides and equal the results:

24/6 = 10/x

24•x/6 = 10

24•x = 10•6

24•x = 60

x = 60/24

x = 2.5

Answer:

x = 2.5 km

Step-by-step explanation:

In similarity triangles, corresponding sides are in same ratio.

[tex]\frac{DF}{BC}=\frac{EF}{AC}\\\\\frac{10}{24}=\frac{x}{6}\\\\\frac{10}{24}*6=x\\\\x=\frac{10}{4}\\\\x=\frac{5}{2}\\\\x= 2.5[/tex]

Area of a triangle formula: 1/2 x base x height

Area = 1/2 x 2 x 3.8

Area = 3.8 square km

Answer:

The area of triangle = 3.8km²

Step-by-step explanation:

Given :-

A triangle having length of base is 2km and length of height is 3.8km.

To find :-

Solution :-

We know that ,

Area of triangle = ½ × Base × height

Area of triangle = ½ × 2km × 3.8km

Area of rectangle = ½ × 7.6km²

Area of triangle = 3.8km²

very easy    

[tex]\displaystyle\ (f-g)(x)=f(x)-g(x)=4x^2-5x-3x^2-6x+4=\boxed{x^2-11x+4}[/tex]

[tex]\\ \sf\longmapsto f(x)=4x^2-5x[/tex]

[tex]\\ \sf\longmapsto g(x)=3x^2+6x-4[/tex]

Now

[tex]\\ \sf\longmapsto (f-g)(x)[/tex]

[tex]\\ \sf\longmapsto f(x)-g(x)[/tex]

[tex]\\ \sf\longmapsto 4x^2-5x-(3x^2+6x-4)[/tex]

[tex]\\ \sf\longmapsto 4x^2-5x-3x^2-6x+4[/tex]

[tex]\\ \sf\longmapsto x^2-11x+4[/tex]

Answer:

[tex] \rm\displaystyle D) \left (1,3\right)[/tex]

Step-by-step explanation:

well to figure out the point we can consider the following formula:

[tex] \rm\displaystyle \text C(x,y)= \left (\frac{m x_{2} + n x_{1} }{m + n} , \frac{m y_{2} + n y_{1} }{m + n} \right)[/tex]

from the given we acquire that,

therefore substitute:

[tex] \rm\displaystyle \text C(x,y)= \left (\frac{(2) (4)+ 3( - 1) }{2 + 3} , \frac{(2) ( - 3) + (3)(7)}{2 + 3} \right)[/tex]

simplify multiplication:

[tex] \rm\displaystyle \text C(x,y)= \left (\frac{8 - 3 }{2 + 3} , \frac{ - 6+ 21}{2 + 3} \right)[/tex]

simplify:

[tex] \rm\displaystyle \text C(x,y)= \left (\frac{5}{5} , \frac{ 15}{5} \right)[/tex]

simplify division:

[tex] \rm\displaystyle \text C(x,y)= \left (1,3\right)[/tex]

hence our answer is D)

[tex] \huge\boxed{\mathfrak{Answer}}[/tex]

Points => (-1, 7) & (4, -3)

Ratio => 2 : 3

(x₁, y₁) = (-1, 7)

(x₂, y₂) = (4, -3)

(m₁, m₂) = (2, 3)

Formula = [tex]\large\left (\frac{m_{1} x_{2} + m_{2} x_{1} }{m_{1} + m_{2}} , \frac{m_{1} y_{2} + m_{2} y_{1} }{m_{1} + m_{2}} \right)[/tex]

Points which divide the line segment

= [tex]( \frac{2 \times 4 + 3 \times - 1}{2 + 3}, \frac{2 \times -3 + 3 \times 7}{2 + 3})[/tex]

[tex] =( \frac{8 - 3}{5} , \frac{ - 6 + 21}{5}) \\ = ( \frac{5}{5} , \frac{15}{5} ) \\ = (1,3)[/tex]

Answer => (1, 3) [option D]

Answer:

Step-by-step explanation:

We have to solve the given expression,

[tex]\frac{9y-33y^2-3y^4}{100-49y^2}.\frac{7y^2+17y+10}{14y^2+28y}[/tex]

[tex]\frac{9y-33y^2-3y^4}{100-49y^2}.\frac{7y^2+17y+10}{14y^2+28y}[/tex] = [tex]\frac{-y(-9+33y+3y^3)}{100-49y^2}.\frac{7y^2+17y+10}{14y(y+2)}[/tex]

                                   = [tex]\frac{-y(-9+33y+3y^3)}{(10-7y)(10+7y)}.\frac{7y^2+10y+7y+10}{14y(y+2)}[/tex]

                                   = [tex]\frac{-y(-9+33y+3y^3)}{(10-7y)(10+7y)}.\frac{y(7y+10)+1(7y+10)}{14y(y+2)}[/tex]

                                   = [tex]\frac{-y(-9+33y+3y^3)}{(10-7y)(10+7y)}.\frac{(y+1)(7y+10)}{14y(y+2)}[/tex]

                                   = [tex]\frac{-3y(-3+11y+y^3)}{(10-7y)}.\frac{(y+1)}{14y(y+2)}[/tex]

                                   = [tex]\frac{-3(-3+11y+y^3)}{(10-7y)}.\frac{(y+1)}{14(y+2)}[/tex]

                                   = [tex]\frac{3(3-11y-y^3)(y+1)}{(10-7y)(14(y+2)}[/tex]

Answer:

16.8

Step-by-step explanation:

Answer:

5.60

Step-by-step explanation:

To find what 10 pens cost we have to go down to the cost of 1 pen first.

If 3 pens costs 1.68 then the cost of 1 pen is 1.68 divided by 3.

[tex]\frac{1.68}{3} = 0.56[/tex]  

If one pen costs 0.56 then 10 pens cost 0.56 multiplied by 10.

0.56 × 10 = 5.60

Answer:

$1.70

Step-by-step explanation:

To figure out how much each apple costs, divide $1.50 by the quantity of apples (6). The answer to that is $0.25, so multiply it by the two apples to get $0.50.

For the oranges, divide $3 by 5. The answer for that is $0.60. Multiply that by the two oranges to get $1.20.

Then, add $0.50 to $1.20 to get a total of $1.70

Answer:

$1.70

Step-by-step explanation:

We know that you can buy 6 apples for $1.50 and 5 oranges for $3.00. So let's look at the cost for one individual apple first.

To find the amount/apple we can divide $1.50 by 6. Here's another way to look at it:

Assume A is cost per apple.

6A = $1.50

6A/6 = $1.50/6

A = $0.25

Now to find the amount for 2 apples, you want to multiply the amount it costs for one apple by 2, because you are multiplying the quantity by 2 as well.

A= $0.25

A *2 = $0.25 * 2

2A = $0.50

So for two apples, it is 50 cents.

We can use a similar process for oranges but with a different price and quantity.

Assume R is cost per orange.

5R = $3.00

5R/5 = $3.00/5

R = $0.60

To find the amount for two oranges we multiply the cost by two.

R = $0.60

R*2 = $0.60*2

2R = $1.20

Finally, we want the total amount for apples AND oranges so we find the sum.

$0.50 + $1.20 = $1.70

Answer:

it would appear tp benefit the borrower. if interest (which is paid by the borrower) is computed on a 360 day year and there are 365 days in a year....

one could consider the "Bankers Rule" to give the borrower 5 "free" days of no interest paid

Step-by-step explanation:

Answer:

12.6

Step-by-step explanation:

[tex]\frac{84}{87}[/tex] = [tex]\frac{x}{13}[/tex]

cross multiply

87x = 1092

x =  12.6 rounded

Answer:

Step-by-step explanation:

distance =  square root [ [tex](x2-x1)^{2}[/tex] + [tex](y2-y1)^{2}[/tex] ]

where you have two points on the line

Point 1 = P1 = (x1,y1)

point 2 = P1 =(x2,y2)

Answer:

The smallest number is 10

Step-by-step explanation:

x+y=24---equation 1

x-y=¹/6×24=>x-y=4---equation 2

Add both equations

2x=28

x=14

put x=14 into equation 1

14+y=24

y=24-14=10

Answer:

D......................

Answer:

Step-by-step explanation:

Answer:

y - 10 = -7 (x + 1)

Step-by-step explanation:

pont = (-1,10)     slope = -7

y - 10 = -7 (x + 1)

Answer:

I believe that the answer is B as well

Step-by-step explanation:

This might be for Ap3x but not 100% sure

Note: There must be -4 instead of 4 otherwise all options are incorrect.

Given:

A polynomial function has a leading coefficient of 3 and roots -4, 1, and 2, all with multiplicity 1.

To find:

The polynomial function.

Solution:

The general polynomial function is defined as:

[tex]P(x)=a(x-c_1)^{m_1}(x-c_2)^{m_2}...(x-c_n)^{m_n}[/tex]

Where, a is the leading coefficient, [tex]c_1,c_2,...,c_n[/tex] are the zeros  with multiplicity [tex]m_1,m_2,...,m_n[/tex] respectively.

It is given that a polynomial function has a leading coefficient of 3 and roots 4, 1, and 2, all with multiplicity 1. So, the polynomial function is defined as:

[tex]P(x)=3(x-(-4))^1(x-1)^1(x-2)^1[/tex]

[tex]P(x)=3(x+4)(x-1)(x-2)[/tex]

Therefore, the correct option is A.

Answer:

% change in perimeter = 43. 44 %

% change in area = 16 %

Step-by-step explanation:

initial perimeter of the rectangle = 2(2p + p)

= 6p

initial area of the rectangle = 2p × p

= 2p²

therefore,

= 2p + 0.8p = 2.8 p

= p - 0.4p

= 0.6 p

= 3.4 p

= 1.68 p²

% change in perimeter

[tex] = \frac{6p - 3.4p}{6p} \times 100 \\ = \frac{2.6p}{6p} \times 100 \\ = 43.33\%[/tex]

% change in area

[tex] \frac{2 {p}^{2} - 1.68 {p}^{2} }{2 {p}^{2} } \times 100 \\ = \frac{0.32}{2} \times 100 \\ = 16\%[/tex]

Answer:

1.5m + 1 ≤ 25

Step-by-step explanation:

Given:

Total amount of gift card Miguel have = $25

Cost of each song = $1.50

Account activation fee = $1

Find:

Inequality

Computation:

Assume;

Number of song Miguel have = m

So,

Total amount of gift card Miguel have ≥ (Cost of each song)(Number of song Miguel have) + Account activation fee

1.5m + 1 ≤ 25

heyy im not sure if you meant origin instead of original but the origin would be (0,0)

Answer:

2/3

Step-by-step explanation:

the slope form equation is :  y2 - y1/ x2-x1 (aka change in y divided by change in x)

so it would be  2-0/ 3-0 = 2/3

the slope is 2/3

Answer:

ayan po answer nasa picture po

Step-by-step explanation:

where

x

is the number you are trying to compute the (2/3) rds of

Answer:

3[tex]\sqrt{2}[/tex]

Step-by-step explanation:

[tex]\sqrt{18}[/tex]

[tex]\sqrt{9}[/tex] [tex]\sqrt{2}[/tex]

3[tex]\sqrt{2}[/tex]

Answer:

x = [tex]\frac{3}{20}[/tex]

Step-by-step explanation:

Given

x + [tex]\frac{3}{2}[/tex] + (x - 1) = [tex]\frac{4}{5}[/tex]

Multiply through by 10 ( the LCM of 2 and 5 ) to clear the fractions

10x + 15 + 10(x - 1) = 8

10x + 15 + 10x - 10 = 8

20x + 5 = 8 ( subtract 5 from both sides )

20x = 3 ( divide both sides by 20 )

x = [tex]\frac{3}{20}[/tex]

x + 3/2 + x - 1 = 4/5

Collect the same terms

x + x + 3/2 - 1 = 4/5

2x + 3/2 - 2/2 = 4/5

2x + (3 - 2)/2 = 4/5

2x + 1/2 = 4/5

2x + 0.5 = 0.8

Subtract both sides 0.5

2x + 0.5 - 0.5 = 0.8 - 0.5

2x + 0 = 0.3

2x = 3/10

Divide both sides by 2

2x ÷ 2 = ( 3/10 ) ÷ 2

x = 3/10 × 1/2

x = 3/20

_________________________________

3/20 + 3/2 + ( 3/20 - 1 ) = 4/5

3/20 + 30/20 + ( 3/20 - 20/20 ) = 4/5

(3 + 30)/20 + (3 - 20)/20 = 4/5

33/20 - 17/20 = 4/5

(33 - 17)/20 = 4/5

16/20 = 4/5

4 × 4 / 4 × 5 = 4/5

4/5 = 4/5

Thus we found the correct value of x .

And we're done...

The students eligible to ride the bus are: Marinna, Kaleb and Thomas

The distance between two points [tex](x_1,y_1),(x_2,y_2)[/tex] is,

[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

An equation of circle with center at (h, k) and radius 'r' is,

[tex](x-h)^2 + (y-k)^2=r^2[/tex]

For given example,

Town hall is located downtown at point (0,0). A new school is located 3 miles north and 2 miles east of town hall.

Considering positive x-axis = East

negative x-axis = West

positive y-axis = North

negative y-axis =South

Also, locate the position of each student on the graph.

Then the given situation would as shown in following diagram.

We have been given, only students who live outside a 5-mile radius from the school are eligible to ride the school bus.

Using the equation of the circle,

the equation for the area within a circle of 5-mile radius from the school would be,

[tex](x-2)^2+(y-3)^2=5^2[/tex]

From the graph we can observe that, Marinna, Kaleb and Thomas live outside a 5-mile radius from the school.

Therefore, the students eligible to ride the bus are: Marinna, Kaleb and Thomas

Learn more about the equation of circle here:

https://brainly.com/question/10618691

#SPJ2

Answer:

Quadratic equations of second degree.

[tex]{ \bf{a {x}^{2} + bx + c = 0}}[/tex]

Quadratic equations of third degree.

[tex]{ \bf{a {x}^{3} + {bx}^{2} + cx + d = 0}}[/tex]