Answer:
it change by the pressure of the air and how its pulling the elastic even more
Explanation:
therefore it changes shape and has more differences than before sometimes the colour of it will go lighter if a lot of air and darker if not a lot
How does the mass of and distance between the Sun and the Earth impact the number of days in a year?
Answer:
Force of sun on earth can be written:
F = G M m / R^2
Centripetal force on earth can be written:
F= m w^2 R
Equating these:
G M / R^2 = w^2 R
Or w^2 = G (M / R^3)
Since no/ days per year is proportional to w (time for 1 revolution)
Increasing M (mass of sun) would increase w or decrease length of year
Increasing the mean radius R would decrease w or increase length of year
A coin lies at the bottom of a tank containing water to a Dept of 130cm. If the refractive index of the water is 1.3, calculate the apparent displacement of the coin viewed vertically from above
Answer: 100 cm
Explanation: When an object at the bottom of a tank with water is viewed vertically from above, to the observer, it seems the object is closer to the eye, i.e., the apparent depth of the object is less than the real depth the object is. This is caused by Refraction, which happens when an incident light passing through an interface between two different media causing the light to be deflected.
The relation between real and apparent depths is given by:
[tex]n=\frac{Dr}{Da}[/tex]
where
n is refractive index of the surface
Dr is real depth
Da is apparent depth
For the coin at the bottom of a tank, apparent depth is:
[tex]n=\frac{Dr}{Da}[/tex]
[tex]Da=\frac{Dr}{n}[/tex]
[tex]Da=\frac{130}{1.3}[/tex]
Da = 100
Apparent displacement of the coin viewed vertically from above is 100 cm.
A projectile is launched at an angle of 60° from the horizontal and at a velocity of
12.0 m/s. What is the horizontal velocity of the projectile? *
Answer:
60*12.0= 720 = v/60 * 12.0 squared which is 1,728
Explanation:
Horizontal velocity component: Vx = V * cos(α)
The horizontal velocity of the projectile is 6.0m/s
If a projectile is launched at an angle from the horizontal and at a velocity v, the horizontal velocity of the projectile is expressed as:
[tex]v_x =vcos \theta[/tex]
Given the following parameters
v = 12.0m/s
[tex]\theta=60^0[/tex]
Substitute the given parameters into the formula to have:
[tex]v_x=12.0cos60\\v_x=12.0(0.5)\\v_x=6.0m/s\\[/tex]
Hence the horizontal velocity of the projectile is 6.0m/s
Learn more here: https://brainly.com/question/23916021
Potential energy diagrams for a particle are useful in predicting the motion of that particle.
a. True
b. False
Answer:
True
Explanation:
What is the Pythagorean Theorem used to find and what must you have to use it?
a. magnitude, fight triangle
b. direction, right triangle
c. magnitude, parallelogram
d. direction, parallelogram
Answer:
A
Explanation:
Air in a balloon does 40 J of work expanding the balloon while absorbing 60 J of heat. What is the change in internal energy
Answer:
DU = 20 Joules
Explanation:
Given the following data;
Heat absorbed, Q = 60J
Workdone, W = 40J
To find the internal energy;
We would use first law of thermodynamics given by the formula;
Change in internal energy (DU) = Q - W
where;
U is internal energy.
Q is the heat absorbed.
W is the work done.
Substituting into the equation, we have;
DU = 60 - 40
DU = 20 Joules
Sorry it’s twisted but please help, thank you!
Answer:
A-50 N
Explanation:
A person runs up 33 stairs of height 0.25 m. The person weighs 599.85 N. How much energy does it take for the person to reach the top of the stairs? I need the answer ASAP
Answer:
149.96J
Explanation:
Given parameters:
Number of stairs = 33
Height = 0.25m
Weight = 599.85N
Unknown:
Energy the person takes to reach the top = ?
Solution:
To solve this problem;
The energy it takes is given as:
Energy = weight x height
Energy = mass x gravity x height
Now,
Insert the given parameters and solve;
Energy = 599.85 x 0.25 = 149.96J
A system increases in internal energy by 80 J and 50 J of work are done on it at the same time. What is the heat change of the system
Answer:
The heat change of the system is 30 J.
Explanation:
Given;
increase in internal energy of a system, ΔU = 80 J
work done on the system, W = 50 J
The heat change of the system can be calculated from first law of Thermodynamics;
ΔU = Q - W
where;
Q is the heat absorbed by the system
W is the work done by the system (negative when work is done by the system and positive when work is done on the system)
Since work was done on the system the increase internal energy is given as;
ΔU = Q + W
ΔU - W = Q
80 J - 50 J = Q
30 J = Q
Therefore, the heat change of the system is 30 J.
Match each disease to the correct pathogen type
Protist:
Virus:
Fungus:
A) AIDS
B) Histoplasmosis
C) Amoebic dysentery
Answer:
Protist: C) Amoebic dysentery
Virus: A) AIDS
Fungus: B) Histoplasmosis
Hope that helps
A missile is launched upward with a speed that is half the escape speed. What height (in radii of Earth) will it reach?
Answer:
The height (h) will be: [tex]\frac{3}{4}R =h[/tex]
Explanation:
The scape speed equation is given by:
[tex]v_{scape}=\sqrt{\frac{2GM}{R}}[/tex]
Now, the speed of the missile is
[tex]v_{missile}=\frac{1}{2}v_{scape}[/tex]
[tex]v_{scape}=\frac{1}{2}\sqrt{\frac{2GM}{R}}[/tex]
Using the conservation of energy, we can find the maximu height of the missile.
[tex]E_{i}=E_{f}[/tex]
[tex]\frac{1}{2}mv_{scape}^{2}-mgR =-mgh[/tex]
[tex]\frac{1}{2}\frac{2GM}{4R}-gR =-gh[/tex]
[tex]\frac{GM}{4R}-gR =gh[/tex]
Let's recall that g = GM/R², using the equivalence principle. When R is the radius of the earth and M is the mass of the earth.
[tex]\frac{1}{4}gR-gR =-gh[/tex]
[tex]\frac{1}{4}R-R =-h[/tex]
Therefore the height (h) will be:
[tex]\frac{3}{4}R =h[/tex]
I hope it helps you!
How many significant figures are there in each of the following?
(a) 85.8 + 0.9
Answer:
86.7
Explanation:
sana makatulong yung answer ko
Planet Zero has a mass of 4.0 x 1023 kg and a radius of 2.0 x 106 m. A 10-kg space probe is launched vertically from the surface of Zero with an initial kinetic energy of 8.0 x 107 J. What maximum distance from the center of Zero is achieved by the probe
Answer:
r2 = 1.25 × 10^(6) m
Explanation:
We are given;
Initial kinetic energy; K_1= 8.0 x 10^(7) J
Mass of planet zero; M = 4.0 x 10^(23) kg
Mass of space probe; m = 10 kg
Radius of planet zero; r1 = 2 × 10^(6) m
From conservation of energy, we can say that;
Initial potential energy + Initial kinetic energy = Final potential energy + Final kinetic energy
This is;
U1 + K1 = U2 + K2
Using formula for potential energy: U = GMm/r, we can write it as;
GMm/r1 + K1 = GMm/r2 + K2
Where Maximum distance = r2
At maximum distance from the center of Zero, K2 = 0.
Thus;
GMm/r1 + K1 = GMm/r2
Making r2 the subject, we have;
r2 = GMm/((GMm/r1)+ K1)
Where G is gravitational constant = 6.67 × 10^(-11) N/m²/kg2
Thus;
r2 = (6.67 × 10^(-11) × 4.0 x 10^(23) × 10)/((6.67 × 10^(-11) × 4.0 x 10^(23) × 10)/(2 × 10^(6)) + (8.0 × 10^(7)))
r2 = 1.25 × 10^(6) m
what are examples of an insulator, conductor, and semiconductor?
Curious George is whirling a 2.0 kg bunch of bananas on a smooth floor in a circular path having a radius of 0.50 m. What force must he apply to keep the motion constant so that the bananas complete one revolution every 4.0 seconds
Answer:
The force will be [tex]F_{c}=2.47 N[/tex]
Explanation:
Let's use the centripetal force equation.
[tex]F_{c}=m\omega ^{2}R[/tex]
Where:
m is the mass of the bunch of bananas
ω is the angular speed
R is the radius
Now, 1 rev every 4 seconds or 0.25 rev/sec is the angular speed, but we need to write this speed in rad per second.
[tex]\omega =0.25\frac{rev}{s}=0.25*2\pi \frac{rad}{s}=1.57 \frac{rad}{s}[/tex]
FInally, the force will be:
[tex]F_{c}=2.0*1.57^{2}*0.5[/tex]
[tex]F_{c}=2.0*1.57^{2}*0.5[/tex]
[tex]F_{c}=2.47 N[/tex]
I hope it helps you!
A particle moves in a circle 1.50 m in radius. Through what angle in radians does it rotate if it moves through an arc length of 2.50 m
Answer:
95.7 degrees
Explanation:
The angle through which the particle rotate in radians is 1.667 rad.
Given the following data:
Radius of circle = 1.50 meterArc length = 2.50 meters.To determine the angle through which the particle rotate in radians:
Mathematically, the angular displacement or arc length in circular motion is given by the formula:
[tex]S=r\theta[/tex]
Where:
S is the angular displacement or arc length.r is the radius.[tex]\theta[/tex] is the angle measured in radians.Making [tex]\theta[/tex] the subject of formula, we have:
[tex]\theta=\frac{S}{r}[/tex]
Substituting the given parameters into the formula, we have;
[tex]\theta = \frac{2.50}{1.50} \\\\\theta =1.667 \;rad[/tex]
Read more: https://brainly.com/question/8898885
Given an area of 8 ft^2. Express this area in the following terms. (a)m^2 5.9458 Incorrect: Your answer is incorrect. m^2 (b) in^2 WebAssign will check your answer for the correct number of significant figures. 96 Incorrect: Your answer is incorrect. in^2 (express to 4 significant figures)
Answer:
0.7432m²
1152in²
Explanation:
a) Usng the conversion
1ft² = 0.0929m²
8ft² = y
y = 8 × 0.0929
y = 0.7432m²
Hence 8ft² in m² is 0.7432m²
For ft² to in²
1ft² = 144in²
8ft² = x
X =8×144
x = 1152in²
Hence 8ft² expressed in in² is 1152in²
C
D
А
E
15
Which letter represents the position at which the basketball has the greatest potential energy? Explain
Which letter represents the position at which the basketball has the greatest potential energy? Explain. Point C. At this point, which is the highest point, all of the ball's energy is gravitational potential energy.
A 100g mouse and an elephant want to find balance by sitting on a really long see-saw that is balanced at its center of mass. Of the 5000 kg elephant is sitting 0.75m away from the axis of rotation, how far away from the axis of rotation must the mouse sit
Answer:
3.75 km away
Explanation:
From the law of moments, clockwise moments = anticlockwise moment
So WL = wl where W = weight of elephant = Mg and M = mass of elephant = 5000 kg, L = distance of elephant from axis of rotation = 0.75 m, and w = weight of mouse = mg where m= mass of mouse = 100 g = 0.1 kg and l = distance of mouse from axis of rotation = unknown and g = acceleration due to gravity.
So, MgL = mgl
ML = ml
l = ML/m
= 5000 kg × 0.75 m/0.1 kg
= 3750 kgm/0.1 kg
= 37500 m
= 3.75 km away
Three tension forces OA, OB and OC are equal in magnitude and magnitude of their summation is 200 N. What is the magnitude of each force
Answer:
The magnitude of each force is 66.67 N
Explanation:
Given that the magnitude of the tension forces are equal. Let the magnitude of the tension forces be represented by x, such that;
|OA| = |OB| = |OC| = x
Since their summation = 200 N, then;
|OA| + |OB| + |OC| = 200
This implies that;
x + x + x = 200
3x = 200
x = [tex]\frac{200}{3}[/tex]
= 66.6667
x = 66.67 N
Therefore, the magnitude of each tension force is approximately 66.67 N
Which is another way of saying the law of conservation of mass?
The mass of the reactants always equals the mass of the products.
Matter cannot be created or destroyed.
the law of conservation of matter
all of the above
Answer:is there a 1 2 3 4 answer?
Explanation:
Summarize what you have learned about power and electrical energy.
Answer:
i dont know.
Explanation:
school is pointless
Water runs out of a horizontal drainpipe at the rate of 135 kg/min. It falls 3.1 m to the ground. Assuming the water doesn't splash up, what average force does the water exert on the ground
Answer:
The average force exerted by the water on the ground is 17.53 N.
Explanation:
Given;
mass flow rate of the water, m' = 135 kg/min
height of fall of the water, h = 3.1 m
the time taken for the water to fall to the ground;
[tex]h = ut + \frac{1}{2}gt^2\\\\h = 0 + \frac{1}{2}gt^2\\\\t = \sqrt{\frac{2\times 3.1}{9.8} } \\\\t = 0.795 \ s[/tex]
mass of the water;
[tex]m = m't\\\\m = 135 \ \frac{kg}{min} \ \times \ 0.795 \ s \ \times \ \frac{1 \ \min}{60 \ s} \ = 1.789 \ kg[/tex]
the average force exerted by the water on the ground;
F = mg
F = 1.789 x 9.8
F = 17.53 N
Therefore, the average force exerted by the water on the ground is 17.53 N.
Expert Answer please 100 points \\ Find the largest value P can have and the boxes move together with equal accelerations?
An electric motor spins at 1000 rpm and is slowing down at a rate of 10 t rad/s2 ; where t is measured in seconds. (a) If the motor radius is 7.165 cm, what is the tangential component of acceleration at the edge of the motor at t = 1.5 seconds? (b) How long will it take, in seconds, to decrease its angular velocity by 75%?
Answer:
a) The tangential component of acceleration at the edge of the motor at [tex]t = 1.5\,s[/tex] is -1.075 meters per square second.
b) The electric motor will take approximately 3.963 seconds to decrease its angular velocity by 75 %.
Explanation:
The angular aceleration of the electric motor ([tex]\alpha[/tex]), measured in radians per square second, as a function of time ([tex]t[/tex]), measured in seconds, is determined by the following formula:
[tex]\alpha = -10\cdot t\,\left[\frac{rad}{s^{2}} \right][/tex] (1)
The function for the angular velocity of the electric motor ([tex]\omega[/tex]), measured in radians per second, is found by integration:
[tex]\omega = \omega_{o} - 5\cdot t^{2}\,\left[\frac{rad}{s} \right][/tex] (2)
Where [tex]\omega_{o}[/tex] is the initial angular velocity, measured in radians per second.
a) The tangential component of aceleration ([tex]a_{t}[/tex]), measured in meters per square second, is defined by the following formula:
[tex]a_{t} = R\cdot \alpha[/tex] (3)
Where [tex]R[/tex] is the radius of the electric motor, measured in meters.
If we know that [tex]R = 7.165\times 10^{-2}\,m[/tex], [tex]\alpha = 10\cdot t[/tex] and [tex]t = 1.5\,s[/tex], then the tangential component of the acceleration at the edge of the motor is:
[tex]a_{t} = (7.165\times 10^{-2}\,m)\cdot (-10)\cdot (1.5\,s)[/tex]
[tex]a_{t} = -1.075\, \frac{m}{s^{2}}[/tex]
The tangential component of acceleration at the edge of the motor at [tex]t = 1.5\,s[/tex] is -1.075 meters per square second.
b) If we know that [tex]\omega_{o} = 104.720\,\frac{rad}{s}[/tex] and [tex]\omega = 26.180\,\frac{rad}{s}[/tex], then the time needed is:
[tex]26.180\,\frac{rad}{s} = 104.720\,\frac{rad}{s}-5\cdot t^{2}[/tex]
[tex]5\cdot t^{2} = 104.720\,\frac{rad}{s}-26.180\,\frac{rad}{s}[/tex]
[tex]t^{2} = \frac{104.720\,\frac{rad}{s}-26.180\,\frac{rad}{s} }{5}[/tex]
[tex]t = \sqrt{\frac{104.720\,\frac{rad}{s}-26.180\,\frac{rad}{s} }{5} }[/tex]
[tex]t \approx 3.963\,s[/tex]
The electric motor will take approximately 3.963 seconds to decrease its angular velocity by 75 %.
mmmeeeee,I'M BEING TIMED
Answer:
D) See the explanation below.
Explanation:
Heat transfer is always given from a body of higher temperature to a lower temperature. In this way the heat from the boiling water is transferred to the ice bars and the energy of the phase change from solid to liquid from the ice is transferred to the environment
Distinguish between elastic collasin
and inelastic collasin
Explanation:
In an elastic collision, two or more bodies are in contact with one another and there is no net loss of kinetic energy in the system. By the virtue of this, the bodies and objects do not stick together after they collide.
Both momentum and kinetic energy are conserved in an elastic collision. An example is when a football hits a wall.
For an inelastic collision, the bodies sticks together after they collide and there is a loss of kinetic energy after they collide. An example of this type of collision is when a gum is throw against a wall.
Small cuts or scratches on your body, which are easier to "repair," lead to very rapid
blood clotting; more serious wounds, like a deep gash in your leg, clot more slowly.
True
False
Small cuts or scratches on your body, which are easier to "repair," lead to very rapid
blood clotting; more serious wounds, like a deep gash in your leg, clot more slowly.
TRUE ☜(ﾟヮﾟ☜)
Experiencing a "jump scare" in a frightening movie most immediately activates your:
somatic nervous system.
sympathetic nervous system.
parasympathetic nervous system.
decentralized nervous system.
Answer:
Somatic I think
Explanation:
Answer:Sympathetic nervous system
Explanation:
If both the pressure and volume of a given sample of an ideal gas are doubled, what happens to the temperature of the gas in Kelvins
Answer: Four times
Explanation:
Given
If Pressure and Volume is double
For ideal gas
PV=nRT
where P=Pressure
V=volume
n=no of moles
R=gas constant
T=temperature
Initially
PV=nRT......(i)
after doubling
(2P)(2V)=nRT'.......(ii)
divide (i) and (ii)
[tex]\frac{PV}{4PV}=\frac{nRT}{nRT'}\\T'=4T[/tex]
So, Temperature becomes 4 times