If 2x+1/3x=4, then find the value of 27x³+1/8x³

The volume of material in a cylindrical shell is 180π.

Cylindrical shell with height 30 in & radius 6 in & and shell thickness 0.5 in.

We estimate the volume of material by using differentials dV with r=6 and d r=0.5.

One way to think of a cylinder is as a grouping of numerous congruent discs piled one on top of the other. We determine the area occupied by each disc separately, add them together, and then determine the area filled by a cylinder. As a result, the product of the base area and height can be used to determine the cylinder's volume.

The volume of a cylindrical shell is

Where, base radius ‘r’, and height ‘h’, the volume will be base times the height.

So,  [tex]$\frac{d V}{d r}=2 \pi r h$[/tex].

[tex]dV & =2 \pi r h d r \\[/tex]

[tex]& =2 \pi \cdot 6 \cdot 30 \cdot 0.5 \\& =180 \pi .[/tex]

Therefore, the volume is 180π.

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Using the triangular inequality we will get that:

A) 2 < x < 34.

B) 0 < x < 130

For a triangle with sides A, B, and C, the triangular inequality says that:

A + B > C

A + C > B

B + C > A

A) two lengths are 18 yards and 16 yards, and the missing length is x, so we can write:

18 + x > 16    →   x > 16 - 18 = -2

16 + x  > 18   →   x > 18 - 16 = 2

16 + 18 > x     →  34 > x

Taking the two more restrictive ones, we can see that 2 < x < 34.

B) Same thing:

x + 65 > 65

x + 65 > 65

65 + 65 >  x

If we simplify that, we will get:

0 < x < 130

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(a) The new x for Set A is 12.00.

(b) The new x for Set B is 10.04.

(c) The addition of the number 26 to each data set changes the mean for Set A more than it does for Set B because Set A has a smaller sample size than Set B.

So the Correct answer is option 4.

When a new value is added to a smaller data set, it has a larger impact on the mean than when added to a larger data set, because the new value represents a larger proportion of the overall data set. This means that adding 26 to Set A had a more significant effect on its mean than adding 26 to Set B.

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The probability that X is between 17 and 27 is given as follows:

0.6826.

The z-score of a measure X of a variable that has mean symbolized by [tex]\mu[/tex] and standard deviation symbolized by [tex]\sigma[/tex] is obtained by the rule presented as follows:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The mean and the standard deviation for this problem are given as follows:

[tex]\mu = 22, \sigma = 5[/tex]

The probability that X is between 17 and 27 is the p-value of Z when X = 27 subtracted by the p-value of Z when X = 17, hence:

Z = (27 - 22)/5

Z = 1

Z = 1 has a p-value of 0.8413.

Z = (17 - 22)/5

Z = -1

Z = -1 has a p-value of 0.1587.

0.8413 - 0.1587 = 0.6826.

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Step-by-step explanation:

from red to green the scale factor was 2 (or rather 1/2).

so, it is not clear if a scale factor of 3 means now enlargement or again reduction ?

if it means reduction then

A'' = A'/3 = (-4, -2)/3 = (-4/3, -2/3)

if it is enlargement then

A'' = A'×3 = (-4, -2)×3 = (-12, -6)

a) The distribution of Z is given by: P(Z = 1) = 1 - F(2T, T), P(Z = 0) = F(2T, T)

b) X and Z are not independent,  Y and Z are not independent, and pair (X, Y) and Z are also not independent.

c) )X and Y are not independently existent.

a) The distribution of Z can be determined by finding the probability that S > 2T. Let F(s,t) be the joint cumulative distribution function of S and T. The probability that S > 2T is given by:

P(Z = 1) = P(S > 2T) = ∫∫_{2t < s} f(s,t) ds dt = 1 - F(2T, T)

Since T is nonnegative and has a continuous distribution, the cumulative distribution function F(2T, T) is also continuous and ranges from 0 to 1. Therefore, the distribution of Z is given by:

P(Z = 1) = 1 - F(2T, T), P(Z = 0) = F(2T, T)

b) X and Z are not independent, since the value of X affects the probability that S > 2T. For example, if X = x, then T >= x/2, so the value of Z depends on the value of X. Similarly, Y and Z are not independent, since the value of Y affects the probability that S > 2T. For example, if Y = y, then T <= y/2, so the value of Z depends on the value of Y.

The pair (X, Y) and Z are also not independent since the joint distribution of (X, Y) affects the probability that S > 2T. For example, if (X, Y) = (x, y), then T >= x/2 and T <= y/2, so the value of Z depends on the values of X and Y.

c) X and Y are not independent, since the value of X affects the value of Y. For example, if X = x, then Y >= x, so the value of Y depends on the value of X.

The complete question is:-

(Order statistics and independence) Let X be the minimum and Y the maximum of two independent, nonnegative random variables S and T with common continuous density f. Let Z denote the indicator function of the event (S > 2T). a) What is the distribution of Z? b) Are X and Z independent? Are Y and Z independent? Are (X, Y) and Z independent? c) Is X independent of Y?

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Answer:

the answer to your question is x=3.

Step-by-step explanation:

hope this helps.

The solution to the parts of the question with regards to the quadratic equation are;

A quadratic equation is an equation of the form f(x) = a·x² + b·x + c

The discriminant, D, of a quadratic equation, f(x) = a·x² + b·x + c, can be obtained using the expression;

D = b² - 4 × a × c

The specified quadratic function is; -4·z² - 3·z + 5 = 0

The discriminant, D of the above quadratic expression is therefore;

D = (-3)² - 4 × (-4) × 5 = 89

The discriminant is larger than zero, therefore, the quadratic expression has two solutions.

The two method to be used to find the specific solution are;

Quadratic Formula;

The solutions of the quadratic equation based on the quadratic formula are;

z = (-(-3) ± √((-4)² - 4 × (-4) × 5))/(2 × (-4))

z = (3 ± √(89))/(-8)

Completing the Square

The completing the square method can be used as follows;

-4·z² - 3·z + 5 = 0

z² + (3/4)·z - 5/4 = 0

z² + (3/4)·z  = 5/4

z² + (3/4)·z + ((3/4)/2)² = 5/4 + ((3/4)/2)²

z² + (3/4)·z + (3/8)² = 5/4 + (3/8)²

(z + (3/8))² = 5/4 + (3/8)²

z + (3/8) = ±√((5/4) + (3/8)²)

z = ±√(5/4 + (3/8)²) - (3/8)

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Answer:

1 cup: 80 cups

Step-by-step explanation:

A unit can be used for measurement and is commonly found in mathematics to describe length, size, etc.

To solve for the number of cups in 5 gallons, we can use this equation:

So, for every 5 gallons there are 80 cups.

The ratio now looks like this:

Therefore, the ratio of bleach to water in the wash is 1: 80

Using Pythagorean theorem, the distance from the top of the hill to the bottom is 404.5 feet

The Pythagorean Theorem is a mathematical concept that states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides. In mathematical terms, the theorem can be expressed as:

x^2 = y^2 + z^2,

where x is the length of the hypotenuse, and y and z are the lengths of the other two sides.

From the diagram given, we can find the hypothenuse by;

x² = 60² + 400²

x² = 163600

x = √163600

x = 404.5ft

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Option c is the correct option.

As a result, the 99% confidence range for the mean germination time is (12.550, 19.050).

As per the question given,  

To find the 99% confidence interval for the mean germination time, we can use the t-distribution with n-1 degrees of freedom.

First, we need to calculate the sample mean and sample standard deviation:

sample mean = (18+12+20+17+14+15+13+11+21+17)/10 = 16

sample standard deviation = sqrt(((18-16)^2 + (12-16)^2 + ... + (17-16)^2)/9) ≈ 3.605

Next, we need to find the t-value for the 99% confidence level with 9 degrees of freedom (n-1). Using a t-distribution table or calculator, we find that t = 3.250.

Finally, we can calculate the confidence interval using the formula:

confidence interval = sample mean ± (t-value) * (sample standard deviation / sqrt(n))

Plugging in the values, we get:

confidence interval = 16 ± (3.250) * (3.605 / sqrt(10))

confidence interval ≈ (12.550, 19.050)

Therefore, the 99% confidence interval for the mean germination time is (12.550, 19.050), which is option (c).

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Answer: draw a number line and plot the 0, 1 , and 2

Explanation:

The statement as an algebrai equation is x + 1/3 = 3/4

From the question, we have the following parameters that can be used in our computation:

The sum of X and one third is three fourths

In mathematics and algebra, we have

One third = 1/3

Three fourths = 3/4

So, the statement becomes

The sum of X and 1/3 is 3/4

Express as a summation equation

This gives

x + 1/3 = 3/4

Hence, the equation is x + 1/3 = 3/4

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The given list of functions can be arranged in ascending order of growth rate as follows: g1(n), g5(n), g3(n), g4(n), g2(n), g6(n), and g7(n).

The Big O notation describes the upper bound of a function's growth rate. In other words, it represents the maximum amount of time or space that a function requires to complete its operations.

Using this concept, we can arrange the given list of functions in ascending order of growth rate as follows:

g1(n) = √2 log n: This function has a growth rate of O(log n), which is less than the growth rates of all other functions in the list.

g5(n) = n log n: This function has a growth rate of O(n log n), which is greater than the growth rate of g1(n), but less than the growth rates of all other functions in the list.

g3(n) = n 4/3: This function has a growth rate of O(n 4/3), which is greater than the growth rates of g1(n) and g5(n), but less than the growth rates of all other functions in the list.

g4(n) = n(log n)3: This function has a growth rate of O(n(log n)3), which is greater than the growth rates of g1(n), g5(n), and g3(n), but less than the growth rates of all other functions in the list.

g2(n) = 2n: This function has a growth rate of O(2n), which is greater than the growth rates of g1(n), g5(n), g3(n), and g4(n), but less than the growth rates of g6(n) and g7(n).

g6(n) = 22 n: This function has a growth rate of O(2n), which is greater than the growth rates of g1(n), g5(n), g3(n), g4(n), and g2(n), but less than the growth rate of g7(n).

g7(n) = 2n2: This function has a growth rate of O(2n2), which is greater than the growth rates of all other functions in the list.

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Complete Question:

Arrange the following list of functions in ascending order of growth rate, i.e. if the function g(n) immediately follows f(n) in your list then, it should be the case that f(n) = O(g(n)).

g1(n) = √2 log n

g2(n) = 2n

g3(n) = n 4/3

g4(n) = n(log n)3

g5(n) = n log n

g6(n) = 22 n

g7(n) = 2n2

the volume of the solid is x²/2R.

Let x be the length of the base of the rectangle.

The volume of the solid is given by:

V = ∫R 2x dx

= 2∫R x dx

= 2[x²/2]∫R dx

= x²/2 ∫R dx

= x²/2 (R - 0)

= x²/2 R

The volume of the solid is given by the integral of the cross sectional area of the solid. The cross sectional area is a rectangle whose base is x and the height is twice the length of the base. Therefore, the area of the cross section is 2x. The volume of the solid is calculated by integrating the area over the range of the variable, which in this case is R. The integral of 2x over the range R is 2x times R (2x*R). This can be simplified to x squared over two times R (x^2/2*R). Therefore, the volume of the solid is x squared over two times R.

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The volume of the solid generated by revolving the region about the y-axis is approximately 0.200 cubic units.  

To use the shell method to find the volume of the solid generated by revolving the region bounded by the curves [tex]$y=1$[/tex], [tex]$y=\frac{1}{2\pi e^{x^2/7}}$[/tex], [tex]$x=0$[/tex], and [tex]$x=1$[/tex] about the y-axis, we need to integrate along the x-axis.

The basic idea of the shell method is to take a vertical strip of width [tex]$dx$[/tex]and height [tex]$f(x)$[/tex] and revolve it about the y-axis to generate a thin shell of thickness [tex]$dx$[/tex] and radius x.

The volume of the solid is then given by the integral:

[tex]$$V = \int_{x=0}^{x=1} 2\pi x f(x) dx $$[/tex]

where [tex]$f(x)$[/tex] is the height of the shell at the position [tex]$x$[/tex]. In this case,

[tex]$f(x) =[/tex] [tex]1 - \frac{1}{2\pi e^{x^2/7}}$.[/tex]

So, we have:

[tex]$$V = \int_{x=0}^{x=1} 2\pi x \left(1 - \frac{1}{2\pi e^{x^2/7}}\right) dx $$[/tex]

Now, we can evaluate this integral using integration by substitution.

Let [tex]$u=x^2/7$[/tex], so [tex]$du/dx = 2x/7$[/tex] and [tex]$x,dx = 7/2,du$[/tex]. The integral becomes:

[tex]$$V = \int_{u=0}^{u=1/7} \frac{2\pi}{7} e^{-u} (7/2) du = \pi\int_{0}^{1/7} e^{-u} du$$[/tex]

Evaluating this integral gives:

[tex]$$V = \pi\left[-e^{-u}\right]_{0}^{1/7} = \pi\left(1 - e^{-1/7}\right) \approx \boxed{0.200}$$[/tex]

Therefore, the volume of the solid generated by revolving the region about the y-axis is approximately 0.200 cubic units.

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Answer:

The bananas weigh 1 [tex]\frac{7}{8}[/tex] pounds

Step-by-step explanation:

How many pounds of apples?

5 [tex]\frac{3}{4}[/tex] - (2 [tex]\frac{1}{2}[/tex] + 1 [tex]\frac{3}{8}[/tex])

5 [tex]\frac{3}{4}[/tex]  -( 2 [tex]\frac{4}{8}[/tex] + 1 [tex]\frac{3}{8}[/tex])     I multiplied [tex]\frac{1}{2}[/tex] x [tex]\frac{4}{4}[/tex] to get [tex]\frac{4}{8}[/tex]

5 [tex]\frac{3}{4}[/tex] - 3 [tex]\frac{7}{8}[/tex]

5 [tex]\frac{6}{8}[/tex] - 3 [tex]\frac{7}{8}[/tex]        I multiplied [tex]\frac{3}{4}[/tex] x[tex]\frac{2}{2}[/tex] to get [tex]\frac{6}{8}[/tex]

(4 [tex]\frac{8}{8}[/tex] + [tex]\frac{6}{8}[/tex]) - 3 [tex]\frac{7}{8}[/tex]   I rewrote 5 [tex]\frac{6}{8}[/tex] so I could regroup ( 1 means the same as [tex]\frac{8}{8}[/tex]

4 [tex]\frac{14}{8}[/tex] - 3 [tex]\frac{7}{8}[/tex]

1 [tex]\frac{7}{8}[/tex]

The integral Z sec3 x dx can be solved using substitution in two ways: either with u = tan x, or with u = sec x. The solutions are x + 1/4 (tan x)4 + C and 1/3 (sec x)3 + C, respectively.

a) Let u = tan x. Then du = sec2 x dx and dx = du/sec2 x, so

Z sec3 x dx = Z sec3 (tan x) (du/sec2 x)

                = Z sec2 (tan x) du

                = Z u sec2 u du

                = Z u (1 + u2) du

                = Z du + Z u3 du

                = x + 1/4 u4 + C

                = x + 1/4 (tan x)4 + C

b) Let u = sec x. Then du = sec x tan x dx = sec2 x dx and dx = du/sec2 x, so

Z sec3 x dx = Z sec3 (sec x) (du/sec2 x)

                = Z sec2 (sec x) du

                = Z u2 du

                = 1/3 u3 + C

                = 1/3 (sec x)3 + C

The integral Z sec3 x dx can be solved using substitution in two ways: either with u = tan x, or with u = sec x. The solutions are x + 1/4 (tan x)4 + C and 1/3 (sec x)3 + C, respectively.

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The composite function of f(x) and g(x) is given as follows:

f(g(x)) = 6x² - 10x - 21.

The composite function of f(x) and g(x) is given by the following rule:

(f ∘ g)(x) = f(g(x)).

It means that the output of the inside function serves as the input for the outside function.

The function g(x) in this problem is given as follows:

g(x) = 3x² - 5x - 7.

Hence, for the composite function in this problem, the lone instance of x in f(x) is replaced by 3x² - 5x - 7, as follows:

f(g(x)) = f(3x² - 5x - 7) = 2(3x² - 5x - 7) - 7 = 6x² - 10x - 21.

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The set of all numbers x that are at a distance of 3 from the number 11 is {8, 14} or can be expressed using absolute value notation: |x - 11| = 3

The set of all numbers x that are at a distance of 3 from the number 11 can be described using absolute value notation as:

|x - 11| = 3

The absolute value of x minus 11 must be equal to 3. This can be interpreted geometrically as the set of all points on the number line that are 3 units away from the point 11. These points can be found by adding and subtracting 3 from 11, giving us the two solutions:

x = 11 + 3 = 14

x = 11 - 3 = 8

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The probability of flipping a heads or tails is the same, which is P(H or T) = 1.0.

The experiment of flipping a coin is an example of a binomial experiment as it has two possible outcomes, heads (H) or tails (T). The trial is the act of flipping the coin, and the outcome is the result of the flip, either heads or tails. The probability of flipping a heads is 50%, which can be expressed as a fraction: P(H) = 1/2, or a decimal: P(H) = 0.5. The probability of flipping a tails is also 50%, which can be expressed as P(T) = 1/2, or P(T) = 0.5. Therefore, the probability of flipping a heads or tails is the same, and this probability can be calculated as follows: P(H or T) = P(H) + P(T) = 0.5 + 0.5 = 1.0.

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Answer:

djsushf sjsushsjd sjdusbs

Step-by-step explanation:

iahsjsidjdjdudjdbdjdid

To find the monthly mortgage payment for a $175,000 house with a down payment of $18,000 and a 25-year mortgage at an annual interest rate of 8%, we can use the following formula:

M = P [ i(1 + i)^n ] / [ (1 + i)^n – 1 ]

where M is the monthly mortgage payment, P is the principal (loan amount) which is $175,000 - $18,000 = $157,000 in this case, i is the monthly interest rate, and n is the total number of payments, which is 25 years x 12 months/year = 300 months.

To find the monthly interest rate, we divide the annual interest rate by 12:

i = 8% / 12 = 0.00666666667

Plugging in these values, we get:

M = $157,000 [ 0.00666666667(1 + 0.00666666667)^300 ] / [ (1 + 0.00666666667)^300 – 1 ]

Simplifying this expression using a calculator or spreadsheet software, we get:

M ≈ $1,222.11

Therefore, the monthly mortgage payment for a $175,000 house with a down payment of $18,000 and a 25-year mortgage at an annual interest rate of 8% is approximately $1,222.11.

The Least Common Multiple ( LCM ) of 20 and 48 is 240

The Greatest Common Divisor GCF or the Highest Common Factor HCF is the highest number that divides exactly into two or more numbers. It is also expressed as GCF or HCF

Least Common Multiple (LCM) is a method to find the smallest common multiple between any two or more numbers. A common multiple is a number which is a multiple of two or more numbers

Product of HCF x LCM = product of two numbers

Given data ,

Let the first number be A

Now , the value of A = 20

Let the second number be B

Now , the value of B = 48

The least common multiple LCM of A and B is calculated by

Prime factorization of 20 = 2 x 2 x 5

Prime factorization of 48 = 2 x 2 x 2 x 2 x 3

Now , LCM = 2 × 2 × 2 × 2 × 3 × 5

The LCM of 20 and 48 = 240

Hence , the LCM is 240

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From the given information provided, for random variable x, Var(2X + 1) = 12,  E[(3X - 4²)] = 31.

A random variable is a variable whose value is subject to random variation, meaning that the outcome of an experiment or process is not deterministic, but rather is determined by chance.

(a) Using the properties of variance, we have:

Var(2X + 1) = Var(2X) = 4Var(X) = 4(3) = 12

(b) Using the linearity of expectation and the properties of variance, we have:

E[(3X - 4)²] = Var(3X - 4) + [E(3X - 4)]²

= Var(3X) + Var(-4) + [3E(X) - 4]²

= 9Var(X) + 0 + [3(2) - 4]²

= 27 + 4

= 31

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The function T(t) has a vertical asymptote at t = 0, since the denominator T² approaches zero as t approaches 0.

A differential equation is an equation that contains one or more functions with its derivatives.

The given function is T(t)=1-5/t²

We need to find the vertical asymptote of the given function.

To find the vertical asymptotes, set the denominator equal to zero and solve for t.

The function T(t) has a vertical asymptote at t = 0, since the denominator T² approaches zero as t approaches 0 from either side.

There are no other vertical asymptotes for T(t).

Hence, the function T(t) has a vertical asymptote at t = 0, since the denominator T² approaches zero as t approaches 0.

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