Answer:
True
Explanation:
A family pool holds 10,000.0 gallons of water. How many cubic meters is this?
264.2 gal = 1.0 cubic meter
Answer:
Hey there!
10000 gallons would be 37.85 cubic meters.
Let me know if this helps :)
Answer: 37.8501 m³
Explanation:
10000.0 gal × 1 m³/264.2 gal
=37.8501 m³ (significant digits)
Which of the following is considered a form of technology?
Select one:
a. A line of thought used to explain logically what happened in an experiment.
b. A beaker used in an experiment.
C. A series of procedures followed in an experiment.
d. The ethical practice of considering human and animal rights in research studies.
Answer:
B. a beaker used in an experiment
Explanation:
Calculate the solubility of BaCO3 (a) in pure water and (b) in a solution in which [CO32-] = 0.289 M. Solubility in pure water = M Solubility in 0.289 M CO32- = M
Answer:
(a). The solubility of [tex]BaCO_{3}[/tex] in pure water is [tex]4.4\times10^{-5}\ M[/tex]
(b). The solubility of [tex]BaCO_{3}[/tex] in solution is [tex]6.92\times10^{-9}\ M[/tex]
Explanation:
Given that,
(a). The solubility of [tex]BaCO_{3}[/tex] in pure water
(b). The solubility of [tex]BaCO_{3}[/tex] in a solution
Solubility of [tex]CO_{3}^{-2}[/tex] is 0.289 M
We know that,
The solubility product constant of [tex]BaCO_{3}[/tex] is [tex]2\times10^{-9}[/tex]
Let the solubility of [tex]BaCO_{3}[/tex] is s.
We need to calculate the solubility of [tex]BaCO_{3}[/tex] in pure water
Using formula of solubility
[tex]ksp=s\times s[/tex]
[tex]ksp=s^2[/tex]
[tex]s=\sqrt{ksp}[/tex]
Put the value into the formula
[tex]s=\sqrt{2\times10^{-9}}[/tex]
[tex]s=4.4\times10^{-5}\ M[/tex]
(b). We need to calculate the solubility of [tex]BaCO_{3}[/tex] in solution
Using formula of solubility
[tex]ksp=s\times s[/tex]
Put the value into the formula
[tex]2\times10^{-9}=s\times 0.289[/tex]
[tex]s=\dfrac{2\times10^{-9}}{0.289}[/tex]
[tex]s=6.92\times10^{-9}\ M[/tex]
Hence, (a). The solubility of [tex]BaCO_{3}[/tex] in pure water is [tex]4.4\times10^{-5}\ M[/tex]
(b). The solubility of [tex]BaCO_{3}[/tex] in solution is [tex]6.92\times10^{-9}\ M[/tex]
The tosylate of (2S,3S)-3-phenylbutan-2-ol undergoes an E2 elimination on treatment with sodium ethoxide. Draw the structure of the alkene that is produced
Answer:
Please find the attachment to this question:
Explanation:
By eliminating the agent produced in the reaction, it will give a structure of the alkene. please find the given attachment.
LiAlH4 reacts with acid chlorides to yield secondary alcohols after hydrolysis.
a. True
b. False
Answer:
a. True
Explanation:
In this reaction, we will have a hydride transfer to the carbon of the carbonyl group, moving the electrons of the double bond towards the oxygen producing a negative charge. The double bond is then regenerated by removing the chlorine atom from the molecule, producing an aldehyde.
Then, another molecule the LiAlH4 transfers another hydride to the carbon of the carbonyl group, again producing a negative charge on the oxygen. Finally, the hydrogen is protonated producing a primary alcohol.
See figure 1
I hope it helps!
Nonmetallic elements form ions by _______ valence electrons to complete their outer shell. The ______ valence electrons an element has in its outer shell, the easier it is to complete. The _______ electron shells an element has, the easier it is to fill its outermost shell. Reactivity in nonmetals _______ as you go from left to right in a group, and ______ as you go from top to bottom.
Answer:
Nonmetallic elements form ions by gaining valence electrons to complete their outer shell.
The more valence electrons an element has in its outer shell, the easier it is to complete.
The fewer electron shells an element has, the easier it is to fill its outermost shell.
Reactivity in nonmetals increases as you go from left to right in a group, and
decreases as you go from top to bottom.
Explanation:
Nonmetallic elements form ions by gaining valence electrons to complete
their outer shell.
The more valence electrons an element has in its outer shell, the easier it is to complete.
The fewer electron shells an element has, the easier it is to fill its outermost shell.
Reactivity in nonmetals increases as you go from left to right in a group, and decreases as you go from top to bottom.
When there are more valence electrons then it makes it easy for the element
to complete its outermost shell as against if it was less as it would be harder
due to a bigger number of electrons needed.
Non metals are elements which accepts valence electrons to complete its
outermost shell and becomes negatively charged when this happens.
When an element has fewer electron shells then filling the outermost shell
will be easier as the electron shells require a lesser number of electrons and
increases as the number of shells increases.
This is because the tendency to accept electrons increases from left to right
and decreases down the group.
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Balance this reaction ch3oh+02 c02 h20
Answer:
2CH3OH + 3O2 --> 2CO2 + 4H2O
This is called Combustion of Methanol
Explanation:
Count the numbers of atoms on each sides and try to get the same amount of quantity on each sides, so you'll eventually get "balanced".
or
Watch this video: "How to Balance CH3OH + O2 = CO2+ H2O (Combustion of Methanol)"
Good luck with future work! Keep studying chemistry!
- D
This graduated cylinder is being used to measure an amount of a liquid. The numbers represent milliliters. What is the most precise measurement of the volume of this liquid? 37.0 ml 37.1 ml 37.2 ml 37.3 ml
Answer:
37.1 mL
Explanation:
To accurately read the measurement using a cylinder, we read the measurement at the meniscus i.e measurement under the curve as shown in the diagram above.
The meniscus i.e the measurement under the curve as shown above is 37.1 mL.
Therefore, the volume of the liquid as obtained from the cylinder is 37.1 mL
Answer:
37.1 ml
Explanation:
a graduated cylinder's measurement is taken at the bottom of the meniscus
Which of the following reactions should have the larger emf under standard conditions? Why?
CuSO4(aq)+Pb(s) ⇌ PbSO4(s)+Cu(s)
Cu(NO3)2(aq)+Pb(s) ⇌ Pb(NO3)2(aq)+Cu(s)
Answer:
Cu(NO3)2(aq)+Pb(s) ⇌ Pb(NO3)2(aq)+Cu(s)
Explanation:
If we look at the both reactions closely, we will quickly discover that the reaction CuSO4(aq)+Pb(s) ⇌ PbSO4(s)+Cu(s) involves PbSO4.
The compound PbSO4 is insoluble in water and sinks to the bottom of the reaction vessel. When this occurs, the concentration of Pb^2+ becomes low. This will bring about a low voltage in the cell.
On the other hand, Pb(NO3)2 is soluble in water hence the cell voltage in this case is higher than the former.
In the case when we look at both reactions so here we discovered that the reaction of
CuSO4(aq)+Pb(s) ⇌ PbSO4(s)+Cu(s) includes PbSO4.
The compound PbSO4 should be insoluble in water and sinks to the bottom of the reaction vessel. At the time When this occurs, the concentration of Pb^2+ becomes low. This will bring about a low voltage in the cell.
On the other hand, Pb(NO3)2 is soluble in water so the cell voltage in this case is more than the former.
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Calculate the [Cu2') remaining in 425 mL of a solution that was originally 0.366 M CuSO4 after passage of 2.68 A for 282 s and the deposition of Cu at the cathode.
Answer:
[tex][Cu]^{remaining}=0.357 M[/tex]
Explanation:
Hello,
In this case, we may use the following equation in order to compute the moles of copper that are processed, considering it goes from Cu⁰ to Cu²⁺, so two electrons are transferred:
[tex]n_{Cu}=\frac{2.68C/s*282s}{96500C/mol*2} =3.9x10^{-3}mol[/tex]
After that, we compute the initial moles of copper in the solution, considering that the concentration of copper (II) equals the concentration of copper:
[tex]n_{Cu,0}=0.366mol/L*0.425L=0.156mol[/tex]
In such a way, we can subtract the process moles to the initial moles to compute the remaining moles of copper:
[tex]n_{Cu}^{remaining}=0.156mol-0.0039mol=0.152mol[/tex]
Finally, the concentration is:
[tex][Cu]^{remaining}=0.152mol/0.425L[/tex]
[tex][Cu]^{remaining}=0.357 M[/tex]
Regards.
The cylinder of aluminum in class was approximately 13mm in circumference and 42mm in length. What would be it's approximate mass?
Answer:
Mass, m = 1.51 grams
Explanation:
It is given that,
The circumference of Aluminium cylinder, C = 13 mm = 1.3 cm
Length of the cylinder, h = 4.2 cm
We know that the density of the Aluminium is 2.7 g/cm³
Circumference, C = 2πr
[tex]r=\dfrac{C}{2\pi}\\\\r=\dfrac{1.3}{2\pi}\\\\r=0.206\ cm[/tex]
Density is equal to mass per unit volume.
[tex]d=\dfrac{m}{V}[/tex]
m is mass of the cylinder
V is the volume of the cylinder
[tex]V=\pi r^2h\\\\V=\dfrac{22}{7}\times0.206^2\times 4.2\\\\V=0.5601\ cm^3[/tex]
So,
[tex]m=d\times V\\\\m=2.7\times 0.5601\\\\m=1.51\ g[/tex]
So, the mass of the cylinder is 1.51 grams.
A certain solution has a molarity of M = 3.14 mol/L and has a volume of V = 0.760 L . What is the value of n? Express your answer numerically in moles.
Answer:
Thinking...
o-O
(ﾉ◕ヮ◕)ﾉ*:･ﾟ✧
what is point group of allene?
Allene (1,2-propadiene) has point group D2d, itself is achiral because it has two planes of symmetry. ... An allene with substituents on one terminal carbon atom are unlike and substituent on other terminal carbon atoms are same, allene will be achiral. It will have one symmetry plane.
Hope this helped :)
Which number has four significant figures? 0.05730 meters 40.007 meter 0.00073 meter 8765 meter
Answer:
All non-zero digits are significant
Explanation:
In cell notation, all species appearing to the left of the double vertical line represent:________.
a. the anode.
b. the cathode.
c. the salt bridge.
d. a phase boundary.
Answer:
a. the anode.
Explanation:
An anode is an electrode through which the conventional current enters into a polarized electrical device. This contrasts with a cathode, an electrode through which conventional current leaves an electrical device
hope it helps :)
please mark it the brainliest!
Answer: the cathode, by convention the components of the cathode are always listed last
Draw a Lewis structure for BCl3 and answer the following questions based on your drawing.
1. For the central boron atom:
A. The number of lone pairs = ___
B. The number of single bonds = ___
C. The number of double bonds = ___
2. The central boron atom __
A. Obeys the octet rule
B. Has an incomplete octet.
C. Has an expanded octet.
Answer:
1. For the central boron atom:
A. The number of lone pairs = 0.
B. The number of single bonds = 3.
C. The number of double bonds = 0.
2. The central boron atom B. Has an incomplete octet.
Explanation:
Hello,
In this case, as shown on the attached picture containing the required Lewis structure of boron chloride, we can see that:
1. For the central boron atom:
A. The number of lone pairs = 0 since all the three valance electrons are bonded with the chlorine atoms.
B. The number of single bonds = 3 as each chlorine atom needs only one bond to obey the octet.
C. The number of double bonds = 0 considering the previous explanation.
2. The central boron atom B. Has an incomplete octet since it reaches six electrons only from its initial three and other three provided by the three chlorine atoms.
Regards.
What is the pH of a solution made by mixing 30.00 mL 0.10 M HCl with 40.00 mL of 0.10 M KOH? Assume that the volumes of the solutions are additive.
Answer:
pH = 12.15
Explanation:
To determine the pH of the HCl and KOH mixture, we need to know that the reaction is a neutralization type.
HCl + KOH → H₂O + KCl
We need to determine the moles of each compound
M = mmol / V (mL) → 30 mL . 0.10 M = 3 mmoles of HCl
M = mmol / V (mL) → 40 mL . 0.10 M = 4 mmoles of KOH
The base is in excess, so the HCl will completely react and we would produce the same mmoles of KCl
HCl + KOH → H₂O + KCl
3 m 4 m -
1 m 3 m
As the KCl is a neutral salt, it does not have any effect on the pH, so the pH will be affected, by the strong base.
1 mmol of KOH has 1 mmol of OH⁻, so the [OH⁻] will be 1 mmol / Tot volume
[OH⁻] 1 mmol / 70 mL = 0.014285 M
- log [OH⁻] = 1.85 → pH = 14 - pOH → 14 - 1.85 = 12.15
The pH of the solution is 12.15.
Calculation of the pH of the solution:The following equation should be
HCl + KOH → H₂O + KCl
Here we have to measured the moles of each compound i.e.
M = mmol / V (mL) → 30 mL . 0.10 M = 3 mmoles of HCl
M = mmol / V (mL) → 40 mL . 0.10 M = 4 mmoles of KOH
So, it be like
3 m 4 m -
1 m 3 m
Now the pH should be like
= [OH⁻] 1 mmol / 70 mL
= 0.014285 M
Now
= - log [OH⁻] = 1.85
pH = 14 - pOH
= 14 - 1.85
= 12.15
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Calculate the mole fraction of KI in a solution made by dissolving 3.4 g of KI in 5.8 g of water. (Step by step)
A. 0.060
B. 0.064
C. 0.37
D. 0.59
E. 6.4
Answer:
The correct answer is 0.058
Step-by-step explanation:
The mole fraction of KI (X) in the solution is the number of moles of KI divided into the total number of moles of the solution (nt):
X= moles KI/nt
First we have to calculate the molecular weights of the components of the solution: KI and water (H₂O):
Molecular weight (Mw) of KI:
Mw(KI)= 39 g/mol + 127 g/mol = 166 g/mol
Molecular weight of H₂O:
Mw(H₂O)= (1 g/mol x 2) + 16 g/mol = 18 g/mol
Then, we calculate the number of moles there is of each component in the solution by dividing the mass into Mw:
Moles of KI= mass KI/Mw(KI) = 3.4 g/166 g/mol = 0.020 mol KI
Moles of H₂O= mass H₂O/Mw(H₂O)= 5.8 g/18 g/mol = 0.322 mol H₂O
Thus, the total moles of solution will be:
nt= moles KI + moles H₂O= 0.020 mol + 0.322 mol = 0.342 mol
Finally, we divide the moles of KI into the total moles of solution (nt) to obtain the mole fraction (X):
X= moles KI/nt = 0.020 mol/0.342 mol = 0.058
According to the following reaction, how many moles of dichloromethane (CH2Cl2) will be formed upon the complete reaction of 0.766 moles methane (CH4) with excess carbon tetrachloride?
methane (CH4) (g) + carbon tetrachloride (g) → dichloromethane (CH2Cl2) (g)
Answer:
[tex]1.53~moles~CH_2Cl_2[/tex].
Explanation:
We can start with the reaction, if we know the formula for each compound:
-) Methane: [tex]CH_4[/tex]
-) Carbon tetrachloride: [tex]CCl_4[/tex]
-) Dichloromethane: [tex]CH_2Cl_2[/tex]
With this in mind, we can write the reaction:
[tex]CH_4~+~CCl_4~->~CH_2Cl_2[/tex]
Now, we can balance the reaction:
[tex]CH_4~+~CCl_4~->~2CH_2Cl_2[/tex]
After this, we have 2 carbon atoms on each side, 4 hydrogen atom on each side, and 4 chlorine atoms on each side.
If we want to know how many moles of [tex]CH_2Cl_2[/tex] would be produced with .766 moles of [tex]CH_4[/tex], we have to check the balanced reaction and use the molar ratio. In this case, the molar ratio is 1 mol [tex]CH_4[/tex] will produce 2 moles of [tex]CH_2Cl_2[/tex] (1:2). So:
[tex]0.766~moles~CH_4\frac{2~moles~CH_2Cl_2}{1~mol~CH_4}=1.53~moles~CH_2Cl_2[/tex]
We wil have [tex]1.53~moles~CH_2Cl_2[/tex].
I hope it helps!
Vegetable oil has a specific heat of 1.67/* Calculate the heat required (in kilojoules) to raise the temperature of 500 g of
vegetable oil from room temp (20.0°C) to 150.0°C
Answer:
[tex]Q=108.55kJ[/tex]
Explanation:
Hello,
In this case, we can compute the required heat by using the following equation:
[tex]Q=mCp(T_2-T_1)[/tex]
Thus, by considering the given mass, specific heat and both initial and final temperature, we obtain:
[tex]Q=500g*1.67\frac{J}{g\°C} *(150.0\°C-20.0\°C)*\frac{1kJ}{1000J} \\\\Q=108.55kJ[/tex]
Regards.
Which one of the following would produce 2-ethoxypropane in high yield?
a. t-butyl chloride + sodium methoxide
b. t-butanol + methanol in presence of H2SO4 at 140 C
c. t-butyl bromide + bromomethane in presence of NaOH
d. sodium t-butoxide + bromomethane
Answer:
d. sodium t-butoxide + bromomethane
Explanation:
Sodium t-butoxide is a strong base with the chemical formula (CH3)3CONa and it is a non-nucleophilic base while bromomethane with the chemical formula CH3Br.
They both together gives 2-ethoxypropane (C5H12O).
(CH3)3CONa + CH3Br => C5H12O + NaBr
Hence, the correct option is "d".
A5 gram ball has a volume of 2.5 milliliters. What is the density of the ball?
(Mass is measure in grams, volume is measured in milliliters and density is measured in
grams/milliliter.)
Answer:
2 g/mL
Explanation:
The following data were obtained from the question:
Mass (m) = 5 g
Volume (V) = 2.5 mL
Density (D) =.?
Density is simply defined as the mass of substance per unit volume of the substance. Mathematically, it is expressed as:
Density (D) = mass (m) /volume (V)
D = m/V
With the above formula, we can obtain the density of the ball as follow:
Mass (m) = 5 g
Volume (V) = 2.5 mL
Density (D) =.?
D = m/V
D = 5/2.5
D = 2 g/mL
Therefore, the density of the ball is 2 g/mL.
3. Explain why environmental science is an interdisciplinary science.
Answer:
Environmental science is also referred to as an interdisciplinary field because it incorporates information and ideas from multiple disciplines. Within the natural sciences, such fields as biology, chemistry, and geology are included in environmental science.
Explanation:
Environmental science is an interdisciplinary science because it integrates physics, biology, and geography to the study of the environment, and the solution of environmental problems.
What do you mean by the environmental science and interdisciplinary science ?Environmental science is the field of science that studies the interactions of the physical, chemical, and biological components of the environment and the relationships .
Interdisciplinary science allows you to study according to your professional and academic abilities and goals .
Environmental science is an interdisciplinary science because it integrates physics, biology, and geography to the study of the environment, and the solution of environmental problems.
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Given: There are 39.95 grams of Argon (39.95 g/1 mole) and one mole has a volume of 22.4 Liters (1 mole/22.4 L). What is the volume, in Liters, of 34.3 grams of Argon?
Answer:
[tex]V_2=19.23L[/tex]
Explanation:
Hello,
In this case, by using the Avogadro's law which allows us to understand the volume-moles behavior as a directly proportional relationship:
[tex]\frac{V_2}{n_2} =\frac{V_1}{n_1}[/tex]
We can compute the volume of 34.3 g of argon by representing it in mole as shown below:
[tex]n_1=1 mol\\\\n_2=34.3g*\frac{1mol}{39.95g} =0.859mol[/tex]
Thus, we find:
[tex]V_2=\frac{V_1*n_2}{n_1}=\frac{22.4L*0.859mol}{1mol} \\\\V_2=19.23L[/tex]
Best regards.
Will the addition of NaC2H3O2 to a CH3COOH solution cause the pH to increase or decrease? Explain.
Answer:
pH will be increased.
Explanation:
When you mixed sodium acetate and acetic acid, pH will be maintained and will have slight changes. This constitutes what is known as a buffer solution.
But if you analize the reactions:
First of all, you have a weak acid, acetic:
CH₃COOH + H₂O ⇄ CH₃COO⁻ + H₃O⁺ Ka
And the salt can be dissociated as:
NaCH₃COO → CH₃COO⁻ + Na⁺
As you are adding acetate, this is the conjugate strong base from the weak acid and as every base, it brings hydroxides to medium, so the pH will be increased. Protons from the acid will be neutralized, thouhgh.
CH₃COO⁻ + H₂O ⇄ CH₃COOH + OH⁻ Kb
What is a Spontaneous charge
This means a release of free energy from the system corresponds to a negative change in free energy, but to a positive change for the surroundings.
Which method did Dalton use to develop his atomic theory?
He changed atoms of one element into atoms of a different element.
He split individual atoms to identify the particles inside them.
He searched for natural materials that did not contain atoms.
He studied the way in which elements combined during chemical reactions.
Answer:
He studied the way in which the elements combined during chemical reactions
Explanation:
Which method did Dalton use to develop his atomic theory?
D.) He studied the way in which elements combined during chemical reactions.
Answer: It’s D
Explanation:
Calculate the molar solubility of magnesium fluoride (MgF2) in a solution that is 0.250 M in NaF. For magnesium fluoride, Ksp = 5.16 * 10 - 11.
Answer:
Molar solubility of magnesium fluoride (MgF2) = 8.26 × 10⁻¹⁰ M
Explanation:
Given:
Ksp = 5.16 × 10⁻¹¹
NaF = 0.250
Find:
Molar solubility of magnesium fluoride (MgF2)
Computation:
Molar solubility of magnesium fluoride (MgF2) = Ksp / NaF²
Molar solubility of magnesium fluoride (MgF2) = 5.16 × 10⁻¹¹ / (0.250)²
Molar solubility of magnesium fluoride (MgF2) = 8.26 × 10⁻¹⁰ M
The molar solubility of magnesium fluoride (MgF2) is 8.26 × 10⁻¹⁰ M.
Calculation of the molar solubility:Since
Ksp = 5.16 × 10⁻¹¹
NaF = 0.250
Now we know that
Molar solubility of magnesium fluoride (MgF2) = Ksp / NaF²
= 5.16 × 10⁻¹¹ / (0.250)²
= 8.26 × 10⁻¹⁰ M
hence, The molar solubility of magnesium fluoride (MgF2) is 8.26 × 10⁻¹⁰ M.
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The internal energy of 10 moles of helium (a monatomic gas) is 15 kJ. What is the rms speed of the molecules? (The molar mass of helium is 4.00 g/mole.)
Answer:
[tex]v_{rms}=866.32m/s[/tex]
Explanation:
Hello,
In this case, since the rms speed of the molecules is computed by:
[tex]v_{rms}=\sqrt{\frac{3RT}{M} }[/tex]
Whereas the absolute temperature is computed from the internal energy (by using the Cp of helium (3.1156 J/g*K) as shown below:
[tex]U=nCvT\\\\T=\frac{U}{nCv}=\frac{15kJ*\frac{1000J}{1kJ} }{10mol*\frac{4.00g}{1mol} *3.1156\frac{J}{g*K} } \\\\T=120.36K[/tex]
Thereby, the rms speed results:
[tex]v_{rms}=\sqrt{\frac{3*8.314\frac{kg*m^2}{s^2*mol*K}*120.36K}{4.00\frac{g}{mol}*\frac{1kg}{1000} } } \\\\v_{rms}=866.32m/s[/tex]
Regards.
8. An unknown mixture that is uniform, does show the Tyndall Effect, and does
not have any particles settling out is a... *
solution
colloid
suspension
pure substance
Answer:
B. Colloid
Explanation:
Colloid is a mixture that is made up of very small homogeneous particles, thus can not be separated into fractions. Its particles do not settle as other solution, but are evenly dispersed in the medium. Some examples are: liquid milk, jelly, rubber etc
Since colloid is a solution, thus it is made up of two parts; its particles and dispersing medium.