Hunter is bisecting the angle shown. When drawing the arcs centered on points P and Q, why must he keep the compass the same width for both arcs?


If Hunter adjusts the width of the compass between drawing the first and second arc, it will be impossible for both arcs to be drawn in the interior of the angle. <-- MY ANSWER


If Hunter adjusts the width of the compass between drawing the first and second arc, it will be impossible for the arcs to intersect.


The compass width should not be adjusted at all when bisecting the angle. This means that Hunter should keep the compass at the same width as when he drew the arc through P and Q.


The arcs are drawn to find a point on the bisecting ray. If the arcs are the same width, it makes sure that they are equidistant from the points on the rays of the angle. This causes the point to be on the bisecting ray.


thanks!

Hey There!!

The answer to this is: 25 times larger. The scale factor is 5, so each side length of the polygon was multiplied by 5.

Key Idea

If the length of a figure scales by x, then area of the figure scales by x^{2}

The Polygon B is created with a scale factor of 5. So, the area of Polygon B scales by 5^{2}

5^{2} = 5 × 5=25

The area of Polygon B is 25 times larger than the area of Polygon A

Hope It Helped!~ ♡

ItsNobody~ ☆

Answer:

If the value of our test statistics is less than the critical values of z at a 5% level of significance (where critical values are -1.645 and 1.645), then we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.

If the value of our test statistics is more than the critical values of z at a 5% level of significance (where critical values are -1.645 and 1.645), then we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.

Step-by-step explanation:

We are given that the population mean equals 500 and we use a 0.10 level of significance in a two-tail hypothesis test.

Let [tex]\mu[/tex] = population mean.

So, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu[/tex] = 500

Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu[/tex] [tex]\neq[/tex] 500

Here, the null hypothesis states that the population mean is equal to 500.

On the other hand, the alternate hypothesis states the population mean is different from 500.

Now, firstly we should note that for the two-tailed test, the level of significance to be taken is ([tex]\frac{\alpha}{2}=\frac{0.10}{2}[/tex]) = 0.05 or 5%.

So, the decision rule for rejecting a null hypothesis is given by;

Answer:

$2

Step-by-step explanation:

$24 ÷ 12 issues = $2 per issue

Answer:

$2 / issue

Step-by-step explanation:

We want to find the cost of each issue. We need to find the unit rate.

Divide the cost by the number of issues.

cost / issues

It costs $24 for 12 issues.

cost = $24

issues = 12 issues

$24 / 12 issues

Divide 24 by 12

$2 / issue

It costs $2 per issue.

Answer:

(a) the new angle the ladder makes with the ground is [tex]32.7^o[/tex]

(b) the ladder slipped back about 5 meters

Step-by-step explanation:

Notice that the ladder doesn't change its length in the process.

So let's start from the initial situation , finding the distance from the ground at which the ladder touches the wall when the angle with the ground is 70^o. Notice that this situation is represented by a right angle triangle with the right angle between the wall and the ground (see attached image), and that we can use the sine function to find the side opposite to the 70 degree angle:

[tex]sin(70^o)=\frac{opposite}{hypotenuse} \\sin(70^o)=\frac{h}{10}\\h=10\, sin(70^o) \approx 9.4 \,\,m[/tex]

therefore 9.4 meters is approximately the height at which the ladder touches the wall initially.

Now, if the tip of the ladder goes down the wall 4 meters, it is now at 9.4 m - 4 m = 5.4 m from the ground. We can therefore use again the sine function to solve for the new angle:

[tex]sin(x)=\frac{opposite}{hypotenuse} \\sin(x)=\frac{5.4}{10} \\sin(x)=0.54\\x=arcsin(0.54)\\x= 32.7^o[/tex]

To answer the second question we need to find the original distance from the wall that the bottom of the ladder was originally, and for that we can use the cosine function:

[tex]cos(70^o)=\frac{adjacent}{hypotenuse} \\cos(70^o)=\frac{x}{10}\\x=10\,cos(70^o)\\x\approx 3.4 \,\,m[/tex]

Now fro the new position of the bottom of the ladder relative to the wall:

[tex]cos(32.7^o)=\frac{adjacent}{10} \\adjacent=10\,cos(32.7^o)\\adjacent\approx 8.4\,\,m[/tex]

then the difference in between those two distances is what we need:

8.4 m - 3.4 m = 5 m

Answer:

Following are the answer to this question:

Step-by-step explanation:

Given value:

[tex]\to x > 0[/tex]

[tex]\to S= { n\varepsilon N : x^n \leq 0 } \\\\ s \neq \phi \\\\ \to x^n \leq 0\\[/tex]

[tex]\to x^{n-1} x\leq 0\\\\ \to x>0 = x^{n-1} \leq 0 \\\\\to n-1 \varepsilon s \\ \ \ _{where} \ \ n-1 < n \\\\\to s= \phi \\\\\to \hence x^n > 0 \\[/tex]

Answer:

A

Step-by-step explanation:

a x-vaule can't have more than one y-vaule so a problem like (-4,3) and (-4,5) cant be a function

Answer:

x= -35 because you have tk get x alone. so you subtract 20 from -15

Answer:

x = -35

Step-by-step explanation:

20 + x = -15

(20 + x) - 20 = -15 - 20

x = -35

Answer:

Identify the Sequence 1, 1/4, 1/16, 1/64 11, 1414, 116116, 164164 This is a geometric sequencesince there is a common ratiobetween each term. In this case, multiplying the previous termin the sequenceby 1414gives the next term.

Step-by-step explanation:

Answer:

4

Step-by-step explanation:

Sequence:

Common ratio is the ratio between the next term and the previous term:

or

or

Answer: $180

Step-by-step explanation:

If she purchased 20 shares of ad stock for $43 per share then multiply 20 by 43 to find the total amount of money.

20 * 43 = $860   which means that she spent a total of $860  for the 20 shares.

If she then sold the 20 stocks for $52 each then you will multiply 20 by 52 and subtract 860 from it to find the total amount she made.

20 * 52 = 1040    

$ 1040 - $860 = $180

Answer:

Step-by-step explanation:

When two lines intersect they form two pairs of opposite angles, A + C and B + D. Another word for opposite angles are vertical angles. Vertical angles are always congruent, which means that they are equal. Adjacent angles are angles that come out of the same vertex.

Answer:

When two lines intersect they form two pairs of opposite angles, A + C and B + D. Another word for opposite angles are vertical angles. Vertical angles are always congruent, which means that they are equal. Adjacent angles are angles that come out of the same vertex.

Step-by-step explanation:

Adjacent angles are angles that come out of the same vertex.

Answer:

y = - 0.681 % ≈ -0.7 %

Step-by-step explanation:

Given:

                                                               April 19,1998            October 30, 1998

Value immediately prior to deposit                95                               105

                     Deposit                                       2X                                 X

amount in the account on January 1, 1999 = 115

effective dollar weighted yield = 0%

annual effective time weighted yield = y

To find:

Calculate y

Solution:

Given that the dollar weighted return is 0%

100 is deposited into investment account on January 1, 1998. So, add 100 to the deposits 2X X

100 + 2x + x = 115

3x = 115 - 100

3x = 15

x = 15/3

x = 5

Compute y

1 + y = (95/100)(105/105)(115/110)

1 + y = 0.95 * 1 * 1.045

1 + y = 0.99318

y = 0.99318 - 1

y = - 0.0068 * 100

y = - 0.681 % ≈ -0.7 %

y = -0.7 %

Answer:

No solution

Step-by-step explanation:

I hope it helps

Answer:

You'll find out once you go through the steps below.

Step-by-step explanation:

First look at x and y being multiplied. You'll get an idea of what are the possible pair of numbers that multiply together. So in this case they could be 6 and 4 but it cant be possible since they will add and become 10 but we need eight. We now know that the answer is in a decimal. I hope these steps were helpful. Have a nice day. :)

Answer:

The Alpha Level

Step-by-step explanation:

The critical value is obtained by applying the alpha value to an area. For example if we choose the alpha level of 0.05 the critical value would be 1.96 for a two tailed test. But if the alpha is 0.1 the critical value would be 1.645 and similarly the critical value would be 2.58 for 0.01 alpha level.

The critcal value depends on the alpha level and is set accordingly depending on one tailed or tailed test. It does not involve the use of The Obtained Statistic  or The Population Mean.

Answer:

14 is less than 21

Answer:

-3

Step-by-step explanation:

-3 is the slope y=mx + b m is -3

Answer:

m= -3

Step-by-step explanation:

[tex]y = - 3x + 4\\y = \:mx+b\\where \:m\:is\:slope[/tex]

Answer:

x = -3

Step-by-step explanation:

expand -23x + 36 = 105

subtract 36 from both sides -23x +36 -36 = 105 - 36

Simplify -23x = 69

Divid both sides by -23: -23x / - 23 = 69 / -23

x = -3

Answer:

8

Step-by-step explanation:

n×8=8n

8n+136=144n

144n÷8=18n

18n-n = 18

Answer:

Hey there!

If you mean, to the nearest ten,  this would be 84000.

Let me know if this helps :)

Answer:

84,000

Rounded to the nearest 10 or

the Tens Place.

Answer:

[tex]A)y + 2 = 4(x - 3)[/tex]

Hey there! I'm happy to help!

First, let's multiply the numerators. We will put q+5 in parentheses so we can multiply it by 4q.

4q(q+5)

We use the distributive property to undo the parentheses.

First, we multiply 4q by q.

4q×q=4q²

And we multiply 4q and 5.

4q×5=20q

So, our numerator right now is 4q²+20q.

Now, for the denominators.

2(q+4)

We do 2 by q.

2×q=2q

And 2×4, which is 8.

So, our denominator is 2q+8.

Right now, our fraction is [tex]\frac{4q^2+20}{2q+8}[/tex], and this is your correct answer. However, we can simplify it a bit more. We can divide the 4 by 2, q² by q, and simplify the 20 and the 8.

4/2=2

q²/q=q

20/8=5/2

Now, our final product is (2q+5)/2

But, mark down your answer as [tex]\frac{4q^2+20}{2q+8}[/tex] because that is technically correct.

Have a wonderful day! :D

Answer:

Area = 13.15 square units

Step-by-step explanation:

Let the given vertices be represented as follows:

A(2, -1, 1) = 2i - j + k

B(5, 1, 4) = 5i + j + 4k

C(0, 1, 1) = 0i + j + k

D(3, 3, 4) = 3i + 3j + 4k

(i) Let's calculate the vectors of all the sides:

[tex]\\[/tex]AB = B - A =  (5i + j + 4k) - (2i - j + k)

AB = 5i + j + 4k - 2i + j - k                 [Collect like terms]

AB = 3i + 2j + 3k

BC = C - B =  (0i + j + k) - (5i + j + 4k)

BC = 0i + j + k - 5i - j - 4k                 [Collect like terms]

BC = -5i + 0j - 3k

CD = D - C =  (3i + 3j + 4k) - (0i + j + k)

CD = 3i + 3j + 4k - 0i - j - k                [Collect like terms]

CD = 3i + 2j + 3k

DA = A - D =  (2i - j + k) - (3i + 3j + 4k)

DA = 2i - j + k - 3i - 3j - 4k                [Collect like terms]

DA = -i - 4j - 3k

AC = C - A =  (0i + j + k) - (2i - j + k)

AC = 0i + j + k - 2i + j - k                [Collect like terms]

AC = -2i + 2j

BD = D - B = (3i + 3j + 4k) - (5i + j + 4k)

BD = 3i + 3j + 4k - 5i - j - 4k                [Collect like terms]

BD = -2i + 2j

(ii) From the results in (i) above, we can deduce that;

AB = CD This implies that AB || CD  [AB is parallel to CD]

AC = BD This implies that AC || BD  [AC is parallel to BD]

(iii) Therefore, ABDC is a parallelogram since opposite sides (AB and CD) are parallel. Hence, the points are vertices of a parallelogram

Now let's calculate the area

To find the area of the parallelogram, we find the magnitude of the cross product of any two adjacent sides.

In this case, we'll choose AB and AC

Area = |AB X AC|

Where;

[tex]AB X AC = \left[\begin{array}{ccc}i&j&k\\3&2&3\\-2&2&0\end{array}\right][/tex]

AB X AC = i(0 - 6) - j(0 + 6) + k(6 + 4)

AB X AC = - 6i - 6j + 10k

|AB X AC| = [tex]\sqrt{(-6)^2 + (-6)^2 + (10)^2}[/tex]

|AB X AC| = [tex]\sqrt{172}[/tex]

|AB X AC| = 13.15

Area = 13.15 square units.

PS: ACBD is also a parallelogram. The diagram has also been attached to this response.

To find the slope of this line, let's use the slope formula.

m = y2 - y1 / x2 - x1

m = 4 - 2 / 8 - 0 ⇒ 2/8 ⇒ 1/4

So m = 1/4.

Answer:

The circumference is 31.42 and the area is 78.54

Step-by-step explanation:

For circumference you use the formula

C=2 r

R= radius and = 3.14

For area use the formula

A= r^2

I hope this helps

Step-by-step explanation:

-(7x² + 5x) / (x² + 1) − 5x / (x² − 6)

To add or subtract fractions, you need a common denominator.

The common denominator of these fractions is (x² + 1) (x² − 6).

Multiply the first fraction by (x² − 6) / (x² − 6).

-(7x² + 5x) (x² − 6) / ((x² + 1) (x² − 6))

-(7x⁴ + 5x³ − 42x² − 30x) / ((x² + 1) (x² − 6))

(-7x⁴ − 5x³ + 42x² + 30x) / ((x² + 1) (x² − 6))

Multiply the second fraction by (x² + 1) / (x² + 1).

5x (x² + 1) / ((x² − 6) (x² + 1))

(5x³ + 5x) / ((x² − 6) (x² + 1))

Subtract the fractions.

(-7x⁴ − 5x³ + 42x² + 30x − 5x³ − 5x) / ((x² + 1) (x² − 6))

(-7x⁴ − 10x³ + 42x² + 25x) / ((x² + 1) (x² − 6))

Answer:

  11,481 km

Step-by-step explanation:

Longitude 90.30° W is equivalent to 360° -90.30° = 269.70° E. Then the difference in longitude of the islands is ...

  269.70° -166.56° = 103.14°

The circumference of the earth at the equator is 40,075 kilometers. Hence the distance will be 103.14/360 times that distance:

  (103.14/360)(40,075 km) = 11,481 km

_____

Additional comment

As always with global distance measures, the result of a calculation depends on the assumptions you make. Attached is another take on the question. Apparently, the distance depends on precisely where in the islands you're measuring from/to. The distance computed above differs from the one below by 136 km. The extent of the Galapagos Islands is on the order of 265 km. So, the number we have computed is at least approximately correct.

Answer:p= -18

Step-by-step explanation:Let's solve your equation step-by-step.

5/4 P= 4/3 P + 3/2

Step 1: Subtract 4/3p from both sides.

5/4 P - 4/3 P = 4/3 P + 3/2 - 4/3 P

-1/12 P = 3/2

Step 2: Multiply both sides by 12/(-1).

(12/-1) × (-1/12 P) = (12/-1) × (3/2)

P = -18

Answer:

p = - 18

Step-by-step explanation:

5        4          3

--- p =  --- p + ---

4         3         2

5        2²          3

--- p =  --- p + ---

2²         3         2

5p     2² * p       3

---  =  ---------  +  ---

2²          3          2

p = - 18

Complete Question

Two different red-light-running signal systems were installed at various intersection locations with the goal of reducing angle-type crashes. Red-Light-Running System A resulted in 60% angle crashes over a sample of 720 total crashes. Red-Light-Running System B resulted in 52% angle crashes over a sample of 680 total crashes. Was there a difference between the proportions of angle crashes between the two red-light-running systems installed? Use an alpha of 0.10.

Answer:

Yes there is a difference between the proportions of angle crashes between the two red-light-running systems installed

Step-by-step explanation:

From the question we are told that

   The first sample  proportion  is  [tex]\r p_ 1 = 0.60[/tex]

   The  second sample proportion is  [tex]p_2 = 0.52[/tex]

    The first sample size is  [tex]n_1 = 720[/tex]

     The second sample size is  [tex]n_2 = 680[/tex]

     The  level of significance is  [tex]\alpha = 0.10[/tex]

The null hypothesis is [tex]H_o : \r p_1 - \r p_2 = 0[/tex]

The  alternative hypothesis is  [tex]H_a : \r p_1 - \r p_2 \ne 0[/tex]

Generally the pooled proportion is mathematically represented as

       [tex]p_p = \frac{(\r p_1 * n_1 ) + (\r p_2 * n_2)}{n_1 + n_2 }[/tex]

=>     [tex]p_p = \frac{(0.6 * 720) + ( 0.52 * 680)}{720 +680 }[/tex]

=>    [tex]p_p = 0.56[/tex]

 Generally the test statistics is evaluated as        

       [tex]t = \frac{ ( \r p_1 - \r p_2 ) - 0 }{ \sqrt{ (p_p (1- p_p) * [ \frac{1}{n_1 } + \frac{1}{n_2 } ])} }[/tex]

        [tex]t = \frac{ (0.60 - 0.52 ) - 0 }{ \sqrt{ (0.56 (1- 0.56) * [ \frac{1}{720} + \frac{1}{680 } ])} }[/tex]    

       [tex]t = 3.0[/tex]

The  p-value obtained from the z-table is  

      [tex]p-value = P(Z> t ) = 0.0013499[/tex]

From the question we see that [tex]p-value < \alpha[/tex] so the null hypothesis is rejected

 Hence we can conclude that there is a difference between the proportions

Answer:

Ammount of fencing required = perimeter of the rectangular storage.

Perimeter of a rectangle = 2(l+b), where l = length, b = breadth.

so perimeter = 2(40+20) = 2(60) = 120 feet

so fencing required = 120 feet

HOPE IT WAS HELPFUL!

Answer:

[tex]\Huge \boxed{\mathrm{120 \ feet}}[/tex]

Step-by-step explanation:

The length of the rectangular storage is 40 feet.

The width of the rectangular storage is 20 feet.

The length of fencing is needed to fence the entire rectangular storage.

The perimeter of the rectangle is required.

[tex]P=2l+2w \\ \\ \sf P=perimeter \\ l=length \\ w=width[/tex]

[tex]P=2(40)+2(20) \\ \\ P=80+40 \\ \\ P=120[/tex]

120 feet of fencing is needed to fence the rectangular storage.