Answer:
The space when they meet each other is from town A = 46.67km
s= ut
Let's consider x as the distance from town A to the meeting point:
Time duration,
Mega taken = Anton taken
x/ 30 = (140 - x)/ 60
2x = 140- x
3x = 140
x = 46.67km
A box has a mass of 75 g. It has a length of 2.0 cm, a width of 2.0 cm and a height of 3.0 cm. What is the density?
Answer:
6.25 g/cm³
Explanation:
2 cm * 2 cm * 3 cm = 12 cm³ (volume)
75 g / 12 cm³ = 6.25 g/cm³
To explore the bottom of a 25-m-deep lake, your friend Tom proposes to get a long garden hose, put one end on land and the other in his mouth for breathing underwater, and descend into the depths. Susan, who overhears the conversation, reacts with horror and warns Tom that he will not be able to inhale when he is at the lake bottom.
Why is Susan so worried?
The pressure at a depth 01 25 m is 3 x 10^5 Pa. This is almost three times greater than atmospheric pressure. But he air pressure in the hose will be only slightly higher than atmospheric pressure, because the density of air is so low. So Tom will have great difficulty breathing in the low-pressure air when the large pressure of the water is pressing in on his chest.
The pressure at a depth 01 25 m is 3.5 x 10^5 Pa. This is almost 3.5 times greater than atmospheric pressure. But he air pressure in the hose will be only slightly higher than atmospheric pressure, because the density of air is so low. So Tom will have great difficulty breathing in the low-pressure air when the large pressure of the water is pressing in on his chest.
The pressure at a depth 01 25 m is 2 x 10^5 Pa. This is almost two times greater than atmospheric pressure. But he air pressure in the hose will be only slightly higher than atmospheric pressure, because the density of air is so low. So Tom will have great difficulty breathing in the low-pressure air when the large pressure of the water is pressing in on his chest.
The pressure at a depth 01 25 m is 2.5 x 10^5 Pa. This is almost 2.5 times greater than atmospheric pressure. But he air pressure in the hose will be only slightly higher than atmospheric pressure, because the density of air is so low. So Tom will have great difficulty breathing in the low-pressure air when the large pressure of the water is pressing in on his chest.
Answer:
The pressure at a depth 01 25 m is 2.5 x 10^5 Pa. This is almost 2.5 times greater than atmospheric pressure. But he air pressure in the hose will be only slightly higher than atmospheric pressure, because the density of air is so low. So Tom will have great difficulty breathing in the low-pressure air when the large pressure of the water is pressing in on his chest.
Explanation:
The depth is h = 25 m
The density of water p = 1000 kg/m^3
Acceleration due to gravity g = 9.81 m/s^3.
Pressure due to a depth is gotten from
P = pgh
P = 1000 x 9.81 x 25 =245250 Pa
==> 2.45 x 10^5 Pa
Approximately 2.5 x 10^5 Pa
Atmospheric pressure = 1.01325 x 10^5 Pa
Dividing the pressure at the bottom of the pond by the atmospheric pressure gives a value of about 2.5,which means that the pressure is 2.5 times the atmospheric pressure.
Express the following units into their basic units
a)neuton
b)joule
Expand (2x + y) (2x - y).
Answer: 4x²-y²
Explanation:
FORMULA
a²-b²=(a+b)(a-b)
-----------------------------
(a+b)(a-b)=a²-b²
(2x+y)(2x-y)=(2x)²-(y)²
=4x²-y²
Hope this helps!! :)
Please let me know if you have any question
Lanzamos desde el suelo una pelota con un ángulo de 45° y queremos colarla en una cesta que está a 7 m de distancia horizontal y a 3.5 m de altura. Calcular con qué velocidad hay que lanzarla.
Answer:
v₀ = 11.72 m / s
Explanation:
This is a missile launch exercise. Let's write the relations for the final position
x = v₀ₓ t
y = [tex]v_{oy}[/tex] t - ½ g t²
Let's use trigonometry to find the initial velocities
sin 45 = v_{oy} / v₀
cos 45 = v₀ₓ / v₀
v_{oy} = v₀ sin 45
v₀ˣ = v₀ cos45
we substitute
x = v₀ cos 45 t
y = v₀ sin 45 t - ½ g t²
in this equation system we have two unknowns and two equations for which it can be solved, let's substitute the values
7 = v₀ 0.707 t
3.5 = v₀ 0.707 t - ½ 9.8 t²
we clear the time in the first equation and substitute in the second
3.5 = v₀ 0.707 (7 / v₀ 0.707) - 4.9 (7 / v₀ 0.707) 2
3.5 = 7 - 480.345 / v₀²
480.345 / v₀² = 7-3.5
v₀² = 480.345 / 3.5
v₀ = √ 137.24
v₀ = 11.72 m / s
Where are the most asteroids founds
Answer: Mars and Jupiter
Explanation:
What minimum separation between two parallel plates of glass (nglass =1.5) produces constructive interference for the reflected light with a 710 nm wavelength if the gap between the plates is filled with oil with noil =1.8?
Answer:
The value is [tex]t = 9.861 *10^{-8} \ m[/tex]
Explanation:
From the question we are told that
The refractive index of glass is [tex]n_{glass} = 1.5[/tex]
The wavelength is [tex]\lambda = 710 nm = \frac{710}{1 * 10^9} = 710*10^{-9} \ m[/tex]
The refractive index of oil is [tex]n_{oil} = 1.8[/tex]
Generally the condition for refractive index is mathematically represented as
[tex]2 * t = [m + \frac{1}{2} ] \frac{\lambda}{n_{oil}}[/tex]
Where t is the separation between two parallel plates of glass , now at minimum m which is the order of maxima produced is = 0
So
[tex]2 * t = [0 + \frac{1}{2} ] \frac{710 *10^{-9}}{1.8}[/tex]
[tex]t = 9.861 *10^{-8} \ m[/tex]
A particle has a displacement of 12m towards east, then 5m towards north and then 6m vertically
upwards what is the magnitude of the sum of these displacements ?
1) 10.28m
2) 14.32m
3) 22.42m
4) 30.82m
Answer:
D = 14.31 m
Explanation:
It is given that,
Displacement due east is 12 m
Displacement due north is 5 m
Displacement in vertically upward direction is 6 m
We need to find the magnitude of the sum of these displacements. We know that, vertically upward, east and north are mutually perpendicular direction. So, the resultant is given by :
[tex]R=\sqrt{12^2+5^2+6^2} \\\\R=\sqrt{144+25+36} \\\\R=14.31\ m[/tex]
So, the magnitude of the sum of these displacements is 14.31 m.
No one can answer this, guaranteed
Answer:
T = 40.08 °C
Explanation:
Given:
m₁ = 0.33 kg, mass of iron horseshoe
T₁ = 693°C, initial temperature of horseshoe
c₁ = 448 J/(g-°C), specific heat
m₂ = 24 kg, mass of water
T₂ = 39°C, initial temperature of water
c₂ = 4186 J/(g-°C), specific heat of water
let T be the equilibrium temperature.
For energy balance,
m₁c₁(T₁ - T) = m₂c₂(T - T₂)
(0.330) * (448) * (693 - T) = (24) * (4186) * (T - 39)
147.84 * (693 - T) = 100,464 * (T - 39)
102,453.12 - 147.84T = 100,464T - 3,918,096
102,453.12 + 3,918,096 = 100,464T - 147.84T
4020549.12 = 100316.16T
T = 40.08 °C
The statement "Chimpanzees like to eat fruit" is an example of a(n)
a. qualitative observation
C. inference
b. quantitative observation
d. prediction
Answer:
inference
Explanation:
took the test hope I helped :p
what is the difference between science and trickery?
Answer:
science is the intellectual pratical activity encompassing the scientific study of structure of the physical and natural world through observations while trickery is the practice if decep5
You and a friend each drive 50.0 km. You travel at 90.0 km/h; your friend travels at 95.0 km/h. How long will your friend have to wait for you at the end of the trip?
Answer:
1.08 hours
Explanation:
Distance = speed × time
Time = distance / speed
The time you spend driving is:
t = 50.0 km / (90.0 km/hr)
t = 0.555 hr
The time your friend spends driving is:
t = 50.0 km / (95.0 km/hr)
t = 0.526 hr
The total time is 0.555 hr + 0.526 hr = 1.08 hr.
(PLEASE HELP THANK YOU) A car is going 8 meters per second on an access road into a highway and then accelerates at 1.8 meters per second squared for 7.2 m seconds. How fast is it then going?
Answer:
20.96 m/s
Explanation:
Apply the kinematic equation:
Vf=Vi+at
Vi=8m/s
a=1.8m/s^2
t=7.2s
Putting this all in should give you your answer of 12.96m/s
a child hits a ball with a force of 350 N. (a) If the ball and bat are in contact for 0.12 is, what impulse does the ball receive? (b) what is its change in momentum?
Explanation:
(a) Impulse is force times time.
J = FΔt
J = (350 N) (0.12 s)
J = 42 Ns
(b) Change in momentum is equal to impulse.
J = Δp
Δp = 42 Ns
Answer:
A.4200Ns
Explanation:
Impulse=Force*Time
I=F*t
350N*0.12s
=42Ns
Prompt Writing
People interact with data and communicate with others on computers in order to carry out many of their job functions. In one
paragraph, describe three risks of developing a strategic role for
information systems and
information communication
technology. In a second paragraph, describe three rewards (or benefits) of developing a strategic role for information systems
and information communication technology, pointing out ways in which these systems can help businesses grow and be
successful.
Please help me !!!
Answer:
problems: incomplete written, can be seen by everyone and private facts
Benefits: enlist the help of the other, works can be divided among all the members, see the progress of each one
Explanation:
First paragraph on the problems.
When it is written in the computer system, the information can be incomplete written without sufficient analysis, it can also be used out of context and, most importantly, the written things can be seen by everyone and private facts of each authorized person can be found out.
Second paragraph. Benefits.
When you write in an automated system, enlist the help of the other members of the group to improve the ideas. They can place an idea without debugging and improve them together. The works can be divided among all the members and see the progress of each one and collaborate with the problems that it presents.
Third paragraph.
Well managed systems can make work progress much faster, by collaboration between all members of the group. Which improves the performance of the company and reduces the response time to problems that arise.
Nail tips exert tremendous pressures when they are hit by hammers because they exert a large force over a small area. What force (in N) must be exerted on a nail with a circular tip of 1.45 mm diameter to create a pressure of 2.33 ✕ 109 N/m2? (This high pressure is possible because the hammer striking the nail is brought to rest in such a short distance.)
Answer:
The force is [tex]F = 3587.2 \ N[/tex]
Explanation:
From the question we are told that
The diameter is [tex]d = 1.4 \ mm = 0.0014 \ m[/tex]
The pressure is [tex]P = 2.33*10^{9} \ N/m^2[/tex]
Generally the radius is mathematically represented as
[tex]r = \frac{0.0014}{2}[/tex]
[tex]r = 0.0007 \ m[/tex]
The cross-sectional area of the nail is mathematically represented as
[tex]A = \pi r^2[/tex]
=> [tex]A = 3.142 * 0.0007 ^2[/tex]
=> [tex]A = 1.54 *10^{-6}[/tex]
Generally the pressure is mathematically represented as
[tex]P = \frac{F}{A}[/tex]
=> [tex]F = P * A[/tex]
=> [tex]F = 1.54*10^{-6} * 2.33*10^{9}[/tex]
=> [tex]F = 3587.2 \ N[/tex]
A fisherman notices that his boat is moving up and down periodically, owing to waves on the surface of the water. It takes 3.5 s for the boat to travel from its highest point to its lowest, a total distance of 0.57 m. The fisherman sees that the wave crests are spaced 5.8 m apart.
(a) How fast are the waves traveling?
(b) What is the amplitude of each wave?
(c) If the total vertical distance traveled by the boat were 0.30 m but the other data remained the same, how would the answers to parts (a) and (b) be affected?
Answer:
1.2 m/s
0.31 m
0.15 m
Amplitude is 0.31 m
The waves are traveling at 1.2 m/s
The amplitude would be 0.15 m. The speed would remain the same.
(i think) (but try it)
a solution contains 5.6ml of alcohol mixed with 75ml of water calculate the concentration of this solution.
Answer:
[tex]\huge \boxed{6.948 \%}}[/tex]
Explanation:
Volume of solute (Alcohol) ⇒ 5.6 ml
Volume or solvent (Water) ⇒ 75 ml
Total volume of solution ⇒ 5.6 ml + 75 ml ⇒ 80.6 ml
[tex]\displaystyle \sf Concentration \ of \ solution \ (\%)= \frac{Volume \ of \ solute}{Volume \ of \ solution} \times 100[/tex]
[tex]\displaystyle \sf Concentration \ of \ solution \ (\%)= \frac{5.6}{80.6} \times 100=\frac{5600}{806} = 6.947891[/tex]
a wave is represented by the equation y=0.5 sin0.6×(x-60t) where the distance x is measured in cm and time t is seconds. what is the wave length of the wave
Answer:
lamda=10.5m
Explanation:
using the equation of progressive wave.
y=Asin(wt-kx)
comparing the two equations together, we have
kx=0.6x , k=0.6
k=2π/λ
0.6=2*3.142/λ
cross multiply
0.6λ=6.284
divide both sides by 0.6
λ=6.284/0.6
λ=10.47m
approximate
λ=10.5m
Which acid is naturally found in foods and can be safe to eat? sulfuric acid citric acid hydrochloric acid nitric acid
Answer:
[tex]\Huge \boxed{\mathrm{citric \ acid}}[/tex]
Explanation:
Citric acid is naturally found in foods and can be safe to eat.
Citric acid is present in oranges, lemons, and other types of citrus fruits that we can eat.
The acid that is naturally found in foods and can be safe to eat would be citric acid, therefore the correct answer is option B .
What is a Chemical compound?
A chemical compound is a combination of two or more either similar or dissimilar chemical elements.
For example, H₂O is a chemical compound made up of two oxygen atoms and a single hydrogen atom.
As given in the problem statement we have to find out the acid from the given list of options that are naturally found in foods and can be safe to eat.
The sulphuric acid found in batteries, therefore, is not safe to eat, while the citric acid found in different fruits can be safe to eat.
The correct response is option B since citric acid is a naturally occurring acid that may be consumed without harm.
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Question 2 (1 point)
(01.01 MC)
Blake is a member of the cross-country track team and runs six days a week. He also helps around the house by washing his family's cars,
mowing the grass, and taking out the garbage and recycling. Which of the following describes a possible benefit of Blake's physical activity
point)
O
a
Blake may be less likely to commit to a healthy future.
Ob
Blake may have a decreased chance of disease.
Oc
Blake may require more assistance performing daily tasks.
O
Blake may struggle to achieve healthy body fat levels.
Answer: Blake may have a decreased chance of disease.
Explanation:
Research has shown that on average, a person who engages in more physical activity will live longer than a person who does not with one reason for this being that engaging in physical activity helps reduce the risk of diseases such as; heart disease, diabetes, and many forms of cancer.
Obesity (risk factor) and high blood pressure are also reduced by engaging in physical activity.
A cylinder has a radius of 4 inches (in.) . If its volume is 144 pi cubic inches (in.^ 3 ) what is the height of the cylinder?
Answer:
18 inches of cube
Explanation:
I have no idea of how to approach this problem
Answer:
p=1
Explanation:
Well me know that v=m/s
and that a=m/s^2
so
[tex](m/s)^{2} = (m/s^2)(x^p)\\\\(m^2/s^2)/(m/s^2)=x^p\\\\m^2s^2/ms^2=x^p\\\\(m^2/m)(s^2/s^2)=x^p\\\\m=x^p\\\\p=1[/tex]
Note: We don't take into account 2 because it's a scalar, it doesn't have units so it doesn't add anything to the equation.
A child goes down a slide, starting from rest. If the length of the slide is 2 m and it takes the child 3 seconds to go down the slide, what is the child's acceleration?
Answer:
0.44 m/s^2
Explanation:
initial velocity = 0 (since the child starts from rest)
distance covered by the child = 2 m (the length of the slide)
time taken = 3 sec
acceleration of the child = ?
using Newton's equation of motion
s = [tex]ut + \frac{1}{2}at^{2}[/tex]
where s is the distance covered by the child
u is the initial velocity
a is the acceleration
t is the time spent
substituting values, we have
2 = 0(3) + [tex]\frac{1}{2}a*3^{2}[/tex]
2 = 9a/2
4 = 9a
a = 4/9 = 0.44 m/s^2
A bus travels 6 km east and the 8 km south. The magnitude of the bus's resultant displacement is km
Answer:
Displacement, d = 10 km
Explanation:
It is given that,
Distance covered by the bus in east direction is 6 km and the distance covered by the bus in south direction is 8 km.
We need to find the resultant displacement. Displacement is the shortest path covered by an object. It can be given by :
[tex]d=\sqrt{6^2+8^2} \\\\d=\sqrt{36+64}\\ \\d=10\ km[/tex]
So, the displacement of the bus is 10 km.
The unit of pressure is a derived unit.why?
Answer:
[tex] \fbox{ \text{See \: below}}[/tex]
Explanation:
[tex] \star[/tex] The unit of pressure i.e Pascal is derived from fundamental units : kilogram , metre and second. So , it is called a derived unit.
[tex] \text{Hope \: I \: helped ! }[/tex]
[tex] \text{Best \: regards !!}[/tex]
~[tex] \text{TheAnimeGirl}[/tex]
A football is kicked from ground level with an initial velocity of 23.6 m/s at angle of 57.5° above the horizontal. How long, in seconds, is the football in the air before it hits the ground? Ignore air resistance.
Answer:
6 seconds is the best answer
It will take 6 seconds to the football in the air.
What is Initial velocity?Velocity is the rate that the position of an item changes relative to time. When forces are applied to an item, it accelerates. This acceleration affects the velocity.
The object's initial velocity, vi, is its speed before acceleration changes it. The new velocity, which has increased for a while, is the final velocity, or vf.
Initial Velocity, denoted as u, is the velocity at time period t = 0. It is the speed at which motion first occurs. There are four equations for starting velocity: The starting velocity is expressed as u = v - at if time, acceleration, and final velocity are given.
Therefore, It will take 6 seconds to the football in the air.
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Please help ASAP!! I need a good grade on this!!!!
What is Momentum Quick Check
1) A billiard ball moves with 3 kg•m/s of momentum and strikes three other billiard balls. What is the total momentum of the balls after the collision?
A)3kg•m/s
B)It depends on the mass of each ball
C)More than 3kg•m/s
D)Less than 3kg•m/s
An object has a mass of 5kg and a velocity of 20m/s. What is the momentum of the object?
A)4kg•m/s
B)0.25kg•m/s
C)25kg•m/s
D)100kg•m/s
A small rock bounces off the windshield of a moving car and experienced a large change in velocity. How does the car’s momentum change?
A)It has a much smaller change in momentum that that of the rock in the opposite direction
B)it has a change in momentum greater than that of the rock in the opposite direction
C)it has a change in momentum equal to that of the rock in the opposite direction
D)it does does not change
Two objects in a closed system collide while moving directly toward each other. Each has a mass of 1.00kg and is moving at 1.80 m/s. What is the total momentum after the collision?
A)1.80 kg•m/s
B)3.60 kg•m/s
C)0.90 kg•m/s
D)0.00 kg•m/s
An object has a velocity of 5m/s and a momentum of 100 kg•m/s. What is the mass of the object?
A) 500 kg
B) 20 kg
C) 0.05 kg
D) 105kg
Answer:
1A) 3kg * m/s
2D) 100
3, Guess: A smaller change of momentum
4, Guess: A, 1.80
5B) 20
Explanation:
(1) The total momentum of the balls after collision is 3 kg.m/s
(2) The momentum of the object is 100 kg.m/s
(3) The change in the car's momentum is equal to change in the rock's momentum in opposite direction.
(4) The total momentum of the objects is 0 kg.m/s
(5) The mass of the object is 20 kg.
(1) From the principle of conservation of linear momentum, total initial momentum before collision is equal to the momentum after collision.
initial momentum = final momentum
Thus, the total momentum of the balls after collision is 3 kg.m/s
(2) Linear momentum is defined as the product of mass and linear velocity of an object.
momentum of the object is calculated as;
P = mv
P = 5 x 20
P = 100 kg.m/s
(3) Apply the principle of conservation of linear momentum;
[tex]m_1u_1 + m_2u_2 = m_1v_1 + m_2 v_2[/tex]
In order to ensure that momentum is conserved;
if u₁ is smaller than u₂, then v₁ must be greater than v₂Let u₁ represents the initial velocity of the small rock and u₂ is the initial velocity of the moving car. In this case, the momentum of the car is bigger.
To conserve the momentum, the final velocity of the rock v₁ must be greater than the final velocity of the car. When this happens, the rock will experience a large change in velocity.
From the equation above will have;
[tex]m_1u_1 + m_2u_2 = m_1v_1 + m_2 v_2\\\\m_1u_1 - m_1v_1 = m_2v_2 - m_2u_2\\\\\Delta P_{rock} = \Delta P_{car}[/tex]
Thus, the change in the car's momentum is equal to change in the rock's momentum in opposite direction.
(4) In a closed system the momentum will be conserved;
Initial momentum = final momentum
Total momentum = final momentum + Initial momentum
The total momentum = 1 x 1.8 + 1 x (-1.8)
Note: the negative sign is because one is moving in opposite direction
The total momentum = 1.8 kg.m/s - 1.8 kg.m/s = 0 kg.m/s
(5) The mass of the object is calculated as;
[tex]m = \frac{P}{v} \\\\m = \frac{100}{5} \\\\m = 20 \ kg[/tex]
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solve P= a+b+c for B
Answer:
b = - a - c + p
Explanation:
P= a+b+c : move the b over to the other side.
-b + p = a + c : move p over the other side.
-b = a + c - p : now just convert the a + c - p into,
b = -a - c + p
The required solution is b = -a - c + p for arithmetic equation p = a+b+c.
What are Arithmetic operations?Arithmetic operations can also be specified by subtracting, dividing, and multiplying built-in functions. The operator that performs the arithmetic operation is called the arithmetic operator.
What is the equation?The equation is defined as mathematical statements that have a minimum of two terms containing variables or numbers that are equal.
We have been given that equation as
⇒ p = a+b+c
Rearrange the term b to the other side and solve for b
⇒ -b + p = a + c
Rearrange the term p to the other side
⇒ -b = a + c - p
Multiply by (-1) the equation, and we get
⇒ b = -a - c + p
Therefore, the required solution is b = -a - c + p.
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the radius of the earth is 6380 km and the height of the mount everest is 8848m . if the value of the acceleration due to gravity on the top of the mount everst is 9.77m/s²,calculate the value of acceleration due to gravity on the surface of the earth .what is the weight of a body of mass 50 kg on the top of mt.everest?
Explanation:
g = GM / R²
9.77 m/s² = GM / (6.38×10⁶ m + 8848 m)²
GM = 3.99×10¹⁴ m³/s²
At the surface of the earth:
g = GM / R²
g = (3.99×10¹⁴ m³/s²) / (6.38×10⁶ m)²
g = 9.80 m/s²
At the top of Mount Everest, the weight of a 50 kg object is:
F = mg
F = (50 kg) (9.77 m/s²)
F = 489 N
Gravity causes items to accelerate as they descend to the ground. Acceleration is a modification of velocity, and velocity is a measurement of the direction and speed of motion. Anything falls through gravity, and the longer it falls, the quicker it falls.
What acceleration due to gravity on surface of the earth?A particular term is given to the acceleration of a free-falling item because it is such a significant value. The acceleration of any object moving only as a result of gravity is referred to as the “acceleration of gravity.”
g = GM / R²
9.77 m/s² = GM / (6.38×10⁶ m + 8848 m)²
GM = 3.99×10¹⁴ m³/s²
At the surface of the earth:
g = GM / R²
g = (3.99×10¹⁴ m³/s²) / (6.38×10⁶ m)²
g = 9.80 m/s²
At the top of Mount Everest, the weight of a 50 kg object is:
F = mg
F = (50 kg) (9.77 m/s²)
F = 489 N
Therefore, 489 N is the weight of a body of mass 50 kg on the top of mt.everest.
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