Fructose‑2,6‑bisphosphate is a regulator of both glycolysis and gluconeogenesis for the phosphofructokinase reaction of glycolysis and the fructose‑1,6‑bisphosphatase reaction of gluconeogenesis. In turn, the concentration of fructose‑2,6‑bisphosphate is regulated by many hormones, second messengers, and enzymes.
Answers
Answer:
Activate glycolysis/Inhibit gluconeogenesis: Increased levels of fructose-2,6-bisphosphate, activation of PFK-2
Activate gluconeogenesis/Inhibit glycolysis: Increased levels of glucagon, Increased levels of cAMP, Activation of fructose-2,6-bisphosphatase (FBPase-2)
Note: The question is incomplete. The complete question is given below and in the attachment.
Fructose‑2,6‑bisphosphate is a regulator of both glycolysis and gluconeogenesis for the phosphofructokinase reaction of glycolysis and the fructose‑1,6‑bisphosphatase reaction of gluconeogenesis. In turn, the concentration of fructose‑2,6‑bisphosphate is regulated by many hormones, second messengers, and enzymes. How do the following affect glycolysis and gluconeogenesis?
Explanation:
Fructose-2,6-bisphosphate is an allosteric effector for the enzymes phosphofructokinase-1 (PFK-1) and fructose-1,6-bisphosphatase (FBPase-1). It increases the affinity of PFK-1 for fructose-6-phosphate thereby activating glycolysis. However, it reduces the affinity of FBPase-1 for its substrate, fructose-1,6-bisphosphate thereby inhibiting gluconeogenesis.
Activation of phosphofructokinase-2 activates glycolysis and inhibits gluconeogenesis by catalyzing the phosphorylation of fructose-6-phosphate to form fructose-2,6-bisphosphate.
Increased levels of glucagon stimulates the synthesis of cAMpP which activates cAMP-dependent ptrotein kinase which phosphorylates the bifunctional enzyme PFK-2/FBPase-2. The phosphorylation of this enzyme inhibits its PFK-2 activity and activates its FBPase-2 activity. This results in the activation of gluconeogenesis and inhibition of glycolysis.
Fructose-2,6-bisphosphatase breaks down fructose-2,6-bisphosphate to fructose-6-phospshate and a phosphoryl group. This results in the activation of gluconeogenesis and the inhibition of glycolysis.
Related Questions
Determine whether or not the mixing of each of the two solutions indicated below will result in a buffer.
A. 75.0 mL of 0.10 MHF; 55.0 mL of 0.15 MNaF
B. 150.0 mL of 0.10 MHF; 135.0 mL of 0.175 MHCl
C. 165.0 mL of 0.10 MHF; 135.0 mL of 0.050 MKOH
D. 125.0 mL of 0.15 M CH3NH2; 120.0 mL of 0.25 MCH3NH3Cl
E. 105.0 mL of 0.15 M CH3NH2; 95.0 mL of 0.10 M HCl
Answers
75.0 mL of 0.10 M HF; 55.0 mL of 0.15 M NaF
This combination will form a buffer.
Explanation
Here, weak acid HF and its conjugate base F- is available in the solution
Part B
150.0 mL of 0.10 M HF; 135.0 mL of 0.175 M HCl
This combination cannot form a buffer.
Explanation
Here, moles of HF = 0.15 x 0.1 = 0.015 moles
Moles of HCl = 0.135 x 0.175 = 0.023
Since HCl is a strong acid and the number of HCl is higher than HF. This prevents the dissociation of HF and the conjugate base F- will not be available in the solution
Part C
165.0 mL of 0.10 M HF; 135.0 mL of 0.050 M KOH
This combination will form a buffer.
Explanation
Moles of HF = 0.165 x 0.1 = 0.0165 moles
Moles of KOH = 0.135 x 0.05 = 0.00675 moles
Moles of KOH is not sufficient for the complete neutralization of HF. Thus weak acid HF and its conjugate base F- is available in the solution and form a buffer
Part D
125.0 mL of 0.15 M CH3NH2; 120.0 mL of 0.25 M CH3NH3Cl
This combination will form a buffer
Explanation
Here, weak acid CH3NH3+ and its conjugate base CH3NH2 is available in the solution and form a buffer
Part E
105.0 mL of 0.15 M CH3NH2; 95.0 mL of 0.10 M HCl
This combination will form a buffer
Explanation
Moles of CH3NH2 = 0.105 x 0.15 = 0.01575 moles
Moles of HCl = 0.095 x 0.1 = 0.0095 moles
Thus the HCl completely reacts with CH3NH2 and converts a part of the CH3NH2 to CH3NH3+. This results weak acid CH3NH3+ and its conjugate base CH3NH2 is in the solution and form a buffer
A buffer is a solution that mitigates against changes in acidity/alkalinity.
A buffer consists of a weak acid and its conjugate base. Also, a buffer can be formed from a weak base and its conjugate acid. A buffer is a solution that helps to mitigate against changes in acidity and alkalinity.
Let us now examine the solution mixtures listed in the question:
75.0 mL of 0.10 MHF; 55.0 mL of 0.15 MNaF. This can work as a buffer solution because it contains a weak acid (HF) and its conjugate base(F^-).150.0 mL of 0.10 MHF; 135.0 mL of 0.175 MHCl will not function as a buffer solution 165.0 mL of 0.10 MHF; 135.0 mL of 0.050 MKOH will not function as a buffer solution125.0 mL of 0.15 M CH3NH2; 120.0 mL of 0.25 MCH3NH3Cl will not function as a buffer solution105.0 mL of 0.15 M CH3NH2; 95.0 mL of 0.10 M HCl will not function as a buffer solution.Learn more: https://brainly.com/question/13439771
In the Lewis structure for ICl2–, how many lone pairs of electrons are around the central iodine atom?
a. 0
b. 1
c. 2
d. 3
e. 4
Answers
Answer:
where is rhe structure
Classify the chemical equations as being balanced or not balanced. CaO + 3C → CaC2 + CO Na + H2O → 2NaOH + H2 4Fe + O2 → 2Fe2O3 2Mg + O2 → 2MgO
Answers
Answer:
A) Balanced
B) Not Balanced
C) Not Balanced
D) Balanced
How many atoms are represented by one formula unit of aluminum chromate, Al2(CrO4)3
Answers
Answer:
17 atoms
Explanation:
If what we want is to calculate the number of atoms. We must take into account the subscripts of the formula. We can rewrite the formula taking into account the "ones" implicit in the formula, therefore we will have:
[tex]Al_2(Cr_1O_4)_3 [/tex]
Now we have a "3" outside the parenthesis. Therefore, we must multiply this 3 by the number of atoms within the parentheses:
-) Oxygen atoms: 4 x 3 = 12 atoms
-) Chromium atoms: 1 x 3 = 3 atoms.
If we take into account we have 2 aluminum atoms, in total, we will have:
-) 12 oxygen atoms
-) 3 chromium atoms
-) 2 aluminum atoms
12 + 3 + 2 = 17 atoms
In total, we will have 17 atoms.
See figure 1
I hope it helps!
A 175.3 mg sample of C10H12O2 was dissolved in 1.50 g of chloroform (Kb = 3.63 °C/m). What is the boiling point of this solution.
Answers
Answer:
[tex]Tb=63.8\°C[/tex]
Explanation:
Hello,
In this case, for the boiling point elevation, we have:
[tex]\Delta T=i*m*Kb[/tex]
Whereas the van't Hoff factor for the given substance is 1 since is not ionizing. Moreover, the molality is computed by:
[tex]m=\frac{mol_{solute}}{m_{solvent}}=\frac{175.3mg*\frac{1g}{1000mg}*\frac{1nol}{164g} }{1.50g*\frac{1kg}{1000g} } =0.713m[/tex]
In such a way, since the boiling point of pure chloroform is 61.2 °C, the boiling point of the solution is:
[tex]Tb=61.2\°C+1*0.713m*3.63\frac{\°C}{m} \\\\Tb=63.8\°C[/tex]
Regards.
Which factor is least likely to cause a memory problem
Answers
Determine whether each of the following salts will form a solution that is acidic, basic, or pH-neutral.
a. KCl
b. NaClO
Answers
Answer:
a. Neutral
b. Basic
Explanation:
To determine which of the salts are acidic, neutral or basci we should dissociate them and determine if the ions, can make hydrolysis to water.
KCl → K⁺ + Cl⁻
We need to know, where do the ions come from. In this case, K⁺ comes from the KOH which is a strong base and Cl⁻ comes from the HCl, a strong acid. In conclussion, both are the conjugate weak acid and base, respectively. They do not make hydrolysis, so this salt is neutral. No protons or hydroxides are given.
NaClO → Na⁺ + ClO⁻
The Na⁺ comes from the NaOH, it is the conjugate weak acid from a strong base, while the ClO⁻ comes from the HClO, a weak acid. This means that the ClO⁻ can react to water, to make hydrolysis. The equilibrium will be:
ClO⁻ + H₂O ⇄ HClO + OH⁻
We are giving hydroxides to medium, so the salt is basic.
once energy is applyied to cause a object to vibrate a sound occours
Answers
Answer:
its true
Explanation:
Answer:
true
Explanation:
you stop on ground, ground vibrates and makes sound
If 25.0 g of NH₃ and 45.0g of O₂ react in the following reaction, what is the mass in grams of NO that will be formed? 4 NH₃ (g) + 5 O₂ (g) → 4 NO (g) + 6 H₂O (g)
Answers
Answer:
The correct answer would be : 33.8 g
Explanation:
Molar mass of ammonia,
Molar Mass = 1* Molar Mass(N) + 3* Molar Mass (H)
= 1*14.01 + 3*1.008 = 17.034 g/mol
mass(NH3)= 25.0 g (given)
number of mol of NH3,
n = mass of NH3/molar mass of NH3
=(25.0 g)/(17.034 g/mol)
= 1.468 mol
Now,
Molar mass of O2
= 32 g/mol
mass(O2)= 45.0 g
similar as ammonia
n (O2)=(45.0 g)/(32 g/mol)
= 1.406 mol
Balanced chemical equation is:
4 NH3 + 5 O2 ---> 4 NO + 6 H2O
1.83456 mol of O2 is required for 1.46765 mol of NH3
by the calculation we have only 1.40625 mol of O2
Thus, the limiting agent will be - O2
now the Molar mass of NO,
= 1*14.01 + 1*16.0
= 30.01 g/mol (similar formula used for NH3)
Balanced equation :
mol of NO formed = (4/5)* moles of O2
= (4/5)×1.40625 (from above calculation)
= 1.125 mol
mass of NO = number of moles × molar mass
= 1.125*30.01
= 33.8 g
Thus, the correct answer would be : 33.8 g
The amount of nitrogen oxide that can be formed in the given mass is 44.12 g.
The given parameters;
mass of ammonia, NH₃ = 25.0 gmass of oxygen, O₂ = 45.0 gThe reaction of the ammonia and oxygen is written as follows;
[tex]4NH_3(g) \ + \ 5O_2 (g) \ --> \ 4NO (g) \ + \ 6H_2O(g)\\\\[/tex]
Molar mass of NH₃ = (14) + (3 x 1) = 17 g/mol
Molar mass of NO = (14) + 16 = 30 g/mol
4(17 g/mol) of NH₃ ------------------ 4(30)
25 g/mol of NH₃ --------------------- ?
[tex]= \frac{4(30) \times 25}{4(17)} \\\\= 44.12 \ g[/tex]
Thus, the amount of nitrogen oxide that can be formed in the given mass is 44.12 g.
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A student is using a coffee-cup calorimeter to determine the enthalpy change of the endothermic reaction of two aqueous solutions. After both solutions are added to the cup, the student neglects to put the lid on the cup. This would cause the magnitude of the calculated ΔH° value to be: the answer is: too small, since the solution will absorb heat from the room. But why? Wouldn't depend on if the reaction releases or absorbs heat. Wouldn't it be too large because heat escapes the cup? I'm so confused
Answers
Answer:
See the answer below
Explanation:
First, it should be understood that an endothermic reaction is one that absorbs energy in the form of heat from the surrounding. The products of endothermic reactions usually have higher energy than their reactants. Hence, the ΔH° which is referred to as the enthalpy change is usually positive.
Forgetting to cover the coffee-cup calorimeter means some of the heat energy absorbed by the reactants would be exchanged back to the surroundings - a loss. It also means that the enthalpy change would be smaller compared to if the cup had been covered because some of the heat has been lost to the surrounding.
consider a 1000-ml graduated cylinder with marks every 100 ml. a student records the volume of liquid in the cylinder as 750 ml. is this the correct measurement? explain
Answers
Answer:
Explanation:
The 1000-ml graduated cylinder with marks every 100 ml has least count of 100 ml . It means it can not measure a volume less than 100 ml . It can also measure volume in the integral multiple of 100 ml like 200 ml , 300 ml , 400 ml etc perfectly . All these have significant figure of one .
It can not measure volume like 150 , 250 , 255 , 760 etc because these measurements are not the integral multiple of 100 . 750 is not a integral multiple of 100 so it can not measure volume of 750 ml.
Which of the following has the greatest electronegativity difference between the bonded atoms?
A) A strong acid made of hydrogen and a halogen, such as HCl
B) A diatomic gas, such as nitrogen (N2)
C) Cartoon bonded to a group 6A (16) nonmetal chalcogen, such as in Co
D) A group 1 alkali metal bonded to chloride, such as RbCl
Answers
Answer:
D) A group 1 alkali metal bonded to chloride, such as RbCl
Explanation:
Which of the following has the greatest electronegativity difference between the bonded atoms?
A) A strong acid made of hydrogen and a halogen, such as HCl
The electronegativity difference between H and Cl is:
ΔEN = |EN(H)-EN(Cl)| = |2.1-3.0| = 0.9
B) A diatomic gas, such as nitrogen (N₂)
The electronegativity difference between N and N is:
ΔEN = |EN(N)-EN(N)| = |3.0-3.0| = 0.0
C) Carbon bonded to a Group 6A (16) nonmetal chalcogen, such as in CO
The electronegativity difference between C and O is:
ΔEN = |EN(C)-EN(O)| = |2.5-3.5| = 1.0
D) A group 1 alkali metal bonded to chloride, such as RbCl
The electronegativity difference between Rb and Cl is:
ΔEN = |EN(Rb)-EN(Cl)| = |0.8-3.0| = 2.2
What is the density if the mass of your object is 54.6g and the volume is 15.30 mL?
Answers
Answer:
5ml
Explanation:not sure why
How many moles are present 560.0 g of iron (lll) sulfate
Answers
Answer:
1.400 mol
Explanation:
To convert grams to moles, you will need the molar mass. The molar mass of iron(iii) sulfate is 399.88 g/mol. Divide grams by the molar mass to find moles.
(560.0 g)/(399.88 g/mol) = 1.400 mol
There are 1.400 mol present in 560.0 g of iron(iii) sulfate.
For the reaction of hydrochloric acid and sodium thiosulfate, the rate law is written as:______
A. Rate = k [HCl]m [Na2S2O3]n
B. Rate = k [HCl + Na2S2O3]
C. Rate = t [HCl]a [Na2S2O3]x
D. Rate = t [HCl + Na2S2O3]
Answers
Answer:
A. [tex]Rate =k[HCl]^{m} [Na_2S_2O_3]^{n}[/tex]
Explanation:
Let's consider the reaction between hydrochloric acid and sodium thiosulfate.
2 HCl + Na₂S₂O₃ → H₂O + S + SO₂ + 2 NaCl
The rate law is:
[tex]Rate =k[HCl]^{m} [Na_2S_2O_3]^{n}[/tex]
where,
Rate is the reaction ratek is the rate constantm and n are the reaction orders, which can only be determined experimentally and may or not coincide with the stoichiometric coefficients.how many moles of MgO are produced when .250 mol of Mg reacts completely with O2
Answers
Answer:
0.250 mol
Explanation:
The reaction between Mg and O2 is given by;
2Mg + O2 --> 2MgO
From the equation above; 2 moles of Mg reacts to form 2 moles of MgO.
0.250 mol of Mg would produce x mol of MgO.
2 = 2
0.250 = x
x = 0.250 * 2/2 = 0.250 mol
6. Cross-cuts are best made with which of the following types of knife? A. Utility knife B. Scaler C. Paring knife D. Chef's knife
Answers
Answer:
A
Explanation:
Utility knife
Answer:
Utility knife
Explanation:
If 801 J of heat is available, what is the mass in grams of iron (specific heat = 0.45 J/g･°C) that can be heated from 22.5°C to 120.0°C?
Answers
Answer:
The correct answer will be "18.25 g".
Explanation:
The given values are:
Specific heat,
C = 0.45 J/g･°C
Heat involved,
q = 801 J
Temperature,
ΔT = 120.0°C-22.5°C
= 97.5°C
As we know,
⇒ [tex]C = \frac{q}{m \Delta T}[/tex]
On substituting the given values, we get
⇒ [tex]0.45=\frac{801}{m(97.5)}[/tex]
⇒ [tex]m = 18.25 \ g[/tex]
The mass in grams of iron heated during the change in temperature is 18.26 grams.
Given the following data:
Initial temperature = 22.5°CFinal temperature = 120.0°CQuantity of heat = 801 JoulesSpecific heat capacity of iron = 0.45 J/g°C.To find the mass in grams of iron heated during the change in temperature:
Mathematically, quantity of heat is given by the formula;
[tex]Q = mc\theta[/tex]
Where:
Q represents the heat capacity or quantity of heat. m represents the mass of an object. c represents the specific heat capacity. ∅ represents the change in temperature.Making mass (m) the subject of formula, we have:
[tex]Mass = \frac{Q}{c \theta}[/tex]
Substituting into the formula, we have:
[tex]Mass = \frac{801}{0.45(120\;-\;22.5)} \\\\Mass = \frac{801}{0.45(97.5)} \\\\Mass = \frac{801}{43.875}[/tex]
Mass, m = 18.26 grams.
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The umbilicus in on the __ surface of the hand
Answers
Answer:
Umbilicus can't be on the hand....it is located in the abdomen....
The components that a cell can contain are (check all that apply)
Answers
Answer:
The components that a cell can contain are
nucleuscell membraneCytoplasmvacuolecell wallWhich of these species would you expect to have the highest standard entropy (S°)?
a. CH4(g)
b. C2H2(g)
c. C2H4(g)
d. C2H6(g)
e. C3H8(g)
Answers
Answer:
e. C₃H₈(g)
Explanation:
Standard entropy is the absolute entropy of a substance at 1 atm and 25°C.
For different substances in the same phase, molecular complexity determines which ones have higher entropies.
Consider the gases CH₄, C₂H₂, C₂H₄, C₂H₆, C₃H₈. Propane (C₃H₈) has a more complex structure and hence more ways to execute molecular motions, which also increase its microstates. Therefore, propane has the greatest standard entropy.
The standard entropy of propane has been highest among the given molecules. Thus, option E is correct.
The standard entropy has been the energy possessed by the 1 mole of a pure substance at standard pressure and temperature.
The entropy has been proportional to the molecular weight and structure complexity. The molecule with higher molecular weight and structure complexity tends to have higher entropy.
In the given set of molecules, the molecular mass and structure complexity of propane has been the highest. Thus, the standard entropy of propane has been highest among the given molecules. Option E is correct.
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Abigail obtained 36.6 grams of calcium carbonate after performing a reaction. From her calculations, she knew she should have obtained 44.1 grams. What was her percent yield
Answers
Answer:
it would be 1
Explanation:
Which of the following liquids would have the highest viscosity at room temperature?
1) CH3OCH3
2)CH2Cl2
3) C2H5OH
4) CH3Br
5)HOCH2CH2OH
Answers
Answer:
5)HOCH2CH2OH
Explanation:
This is also known as ethylene glycol. An increase in hydrogen bonds of a compound means an increase in the viscosity. Hydrogen bonds occur as a result of bonding with electronegative elements such as Oxygen, Nitrogen etc.
The compounds with the highest amount of Hydrogen bond represents the one with the highest viscosity which is B) HOCH2CH2OH
The liquid which would have the highest viscosity at room temperature is: Choice 5): HOCH2CH2OH.
Discussion:
The compound HOCH2CH2OH, named ethylene glycol relative to the other compounds has more hydrogen bonding.
By convention, an increase in the number of hydrogen bonds of a compound means an increase in the viscosity.
Hydrogen bonds are characterized by the of hydrogen with electronegative elements such as Oxygen, Nitrogen etc.
The compounds with the highest amount of Hydrogen bond is therefore; HOCH2CH2OH.
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A concentration cell is one in which both the anode and cathode are the same but with different concentrations. Calculate the cell potential with [Zn2+] = 0.10 M[Zn2+] = 0.10 M for the cathode and the [Zn2+] = 0.010 M[Zn2+] = 0.010 M for the anode?
Answers
Answer: 0.029 V
Explanation:
For the given chemical reaction :
[tex]Zn^{2+}(0.10M)(aq)+Zn(s)\rightarrow Zn^2+{0.010M)(aq)+Zn(s)[/tex]
Using Nernst equation :
[tex]E_{cell}=E^0_{cell}-\frac{2.303RT}{nF}\log\frac{\text {anodic ion concentration}}{\text {cathodic ion concentration}}[/tex]
where,
F = Faraday constant = 96500 C
R = gas constant = 8.314 J/mol.K
T = room temperature = 298 K
n = number of electrons in oxidation-reduction reaction = 2
[tex]E^0_{cell}[/tex] = standard electrode potential of the cell = 0 (as both metals are same )
[tex]E_{cell}[/tex] = emf of the cell = ?
[tex]E_{cell}=0-\frac{2.303\times 8.314\times 298}{2\times 96500}\log\frac{0.010}{0.10}[/tex]
[tex]E_{cell}=0.029V[/tex]
Thus the cell potential will be 0.029 V
Use the periodic table to determine the number of valence electrons in each of the following elements.
Na:
E:
V:
Ar:
Answers
Answer:
Na: 1
F: 7
V: 5
Ar: 8
C: 4
Explanation:
The number of valence electrons by using periodic table are Na has 1, F has 7, V has 5, Ar has 8 and C has 4 valence electron.
What is periodic table ?The chemical elements are arranged in rows and columns in the periodic table, sometimes referred to as the periodic table of the elements. It is frequently used in physics, chemistry, and other sciences, and is frequently regarded as a symbol of chemistry.
Because of the orderly arrangement of the elements, it is known as the periodic table. They're arranged in rows and columns, as you'll see. Periods and groups are the names given to the horizontal rows and the vertical columns, respectively.
A system for arranging the chemical elements is the periodic table. The fundamental components of all matter are the chemical elements. The atomic number is a distinct characteristic of each chemical element. This figure is based on how many protons there are in each of the element's atoms.
Thus, The number of valence electrons by using periodic table are Na has 1, F has 7, V has 5, Ar has 8 and C has 4 valence electron.
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Which of the following pairs of aqueous solutions would not produce a reaction when mixed? Select one: a. NaNO3 and CuCl2 b. Ba(OH)2 and HNO3 c. CaCl2 and Na3PO4 d. AgNO3 and HCl
Answers
Answer:
a. NaNO3 and CuCl2
Explanation:
The other 3 react as follows:
Ba(OH)2 and HNO3 ---> BaNO3 + H2O
CaCl2 + Na3PO4 ---> CaPO4 + NaCl
AgNO3 + HCl ---> AgCl + HNO3
If Na was to form a 2 ion, from what orbital subshell would the second electron be lost?
Answers
Answer:
2p
Explanation:
Sodium has an atomic number of 11, thus, the neutral atom has 11 electrons. The electron configuration is:
Na: 1s² 2s² 2p⁶ 3s¹
To gain stability, it loses an electron from its outer shell to form the cation Na⁺. Its electron configuration is:
Na⁺: 1s² 2s² 2p⁶
If it were to lose a second electron to form a Na²⁺ cation, the electron should be lost from the 2p orbital subshell and its electron configuration would be:
Na²⁺: 1s² 2s² 2p⁵
A substance formed in a chemical reaction is called a
O A. reactant
B. equation
C. None of these
D. product
Answers
Answer: Product
Explanation:
A substance formed in a chemical reaction is called a products ,therefore option (d) is correct .
What do you mean by the chemical reaction ?A chemical reaction is a process that occurs when two or more molecules interact to form a new product(s).
Compounds that interact to produce new compounds are called reactants whereas the newly formed compounds are called products.
Products are substances that are created as a result of a chemical reaction. These products of reactions may be ions or molecules.
The result of a chemical reaction might exist in the solid, liquid, or gaseous phases.
A + B → C + D
Here,
A and B are the reactants, and
C and D are the products of their reaction.
A substance formed in a chemical reaction is called a products ,hence option (d) is correct .
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Barium chloride and sodium sulfate react according to the following equation. BaCl 2 + Na 2SO 4 → BaSO 4 + 2NaCl Answer the following question(s) about this reaction. How many grams of barium chloride are needed to make 100. grams of barium sulfate?
Answers
See attached work:
According to the stoichiometry and the given balanced chemical equation 89.22 g of barium chloride are needed to make 100 grams of barium sulfate.
What is stoichiometry?Stoichiometry is the determination of proportions of elements or compounds in a chemical reaction. The related relations are based on law of conservation of mass and law of combining weights and volumes.
Stoichiometry is used in quantitative analysis for measuring concentrations of substances present in the sample.
In the given chemical equation, 208.23 g of barium chloride produces 233.38 g of barium sulfate ,so for 100 g of barium sulfate 208.23×100/233.38 =89.22 g of barium chloride is required.
Thus, 89.22 g of barium chloride are needed to make 100 grams of barium sulfate.
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The SI prefix kilo- indicates _____.
A. hundred
B. thousand
C. hundredth
D. thousandth
Answers
Answer:
b
Explanation: