Find the value of x in the figure below

Answer:

7 < 8.5 < 9

Step-by-step explanation:

Well < and > mean greater and less than so put it from the smallest to the largest

Answer:

A number,m,is seven point two . Eighteen divided by a number,m,is seven point two

Answer:

its c

Step-by-step explanation:

just to make it easier for you:)

Answer:

5 < 10x - 3

Step-by-step explanation:

5 - 2x < 8x - 3

Add '2x' to both the sides

5 - 2x + 2x < 8x + 2x - 3

5 < 10x - 3

Answer:

1/8, 0.13,1/2, 7/8 it already is in order

Step-by-step explanation:

Answer:

Step-by-step explanation: 1/8, 0.13,1/2, 7/8 it already is in order

1 km = 1000 meters

2 km = 2 x 1000 = 2,000 meters

Area = length x width

Area = 2,000 x 8.3 = 16,600 square meters

Cost:

Multiply total area by cost per square meter:

16,600 x 30 = £498,000

Answer: [tex]2x^{2} y^{3} (\sqrt[3]{4x^{2} y} )[/tex]

Step-by-step explanation:

[tex]\sqrt[3]{32x^{8} y^{10} } =\sqrt[3]{2^{3} \cdot 2^{2} \cdot x^{2} \cdot (x^{2} )^{3} \cdot y \cdot (y^{3})^{3} } =2x^{2} y^{3} (\sqrt[3]{4x^{2} y} )[/tex]

Answer:

Option C :

               [tex]\sqrt[3]{32x^8y^10} = 2x^2 y^3 \sqrt[3]{4x^2 y}[/tex]

Step-by-step explanation:

[tex]\sqrt[3]{32x^8y^{10}}} = ( 32 x^8 y^{10})^{\frac{1}{3}}[/tex]

              [tex]= ( 2^5 \times x^8 \times y^{10})^{\frac{1}{3}}\\\\= ( 2^{5\times\frac{1}{3}} \times x^{8 \times \frac{1}{3}} \times y^{10 \times \frac{1}{3}})\\\\=(2^{\frac{3}{3} + \frac{2}{3}}} \times x^{\frac{6}{3} + \frac{2}{3}} \times y^{\frac{9}{3} + \frac{1}{3}})\\\\= 2 \times 2^{\frac{2}{3}} x^2 \times x^{\frac{2}{3}} \times y^3 \times y^\frac{1}{3}\\\\=2x^2 y^3 \times 2^{\frac{2}{3} \times }x^{\frac{2}{3}} \times y^{\frac{1}{3}}\\\\=2x^2 y^3 (2^2x^2 y)^{\frac{1}{3}}\\\\= 2x^2y^3 \ \sqrt[3]{ \ 4 x^2 \ y }[/tex]

Answer:

[tex]\frac{18}{p}[/tex]

Step-by-step explanation:

Answer:

2/3

Step-by-step explanation:

25=125^k

5^2=5^3k

2=3k

k=2/3

The value of k is k = 2/3.

The number of times a number is multiplied by itself is referred to as an exponent.

Given that, [tex]25 = 125^k[/tex].

Follow the steps to find the value of k:

[tex]25 = 125^k\\\\5^2=(5^3)^k\\\\5^2=5^{3k}[/tex]

Since the base of the exponents is the same, it follows:

2 = 3k

k = 2/3

Hence, the value of k is k = 2/3.

Learn more about exponents here:

https://brainly.com/question/5497425

#SPJ2

Answer:

l

Step-by-step explanation:

A sequence is an ordered list of numbers.....

A term is an element in a sequence.

You can expand a sequence by finding and writing....

The next term in the sequence is A = (general term)

Answer:

population=300,000

population size per year=4.5%

population size for 8 years=8 × 4.5%

=0.36

=108000

Answer:

C

Step-by-step explanation:

[tex]5x+y=-23[/tex]

Graph it and see which plots are on the line:

-3, -4 is not.

-5, -3 is not.

-4, -3 is.

-3, -5 is not.

Answer:

[tex]2x^{2} +bx-3=0[/tex]

Step-by-step explanation:

General form. A quadratic function [tex]f(x)[/tex] is of the form [tex](ax^2+bx+c)[/tex] where [tex]a,b,c[/tex] ∈ R or C and [tex]a[/tex] ≠ [tex]0[/tex].

We obtain an equation when [tex]f(x)=0[/tex]

⇒ [tex]ax^{2} +bx+c=0[/tex] is an quadratic equation.

Solution.

Given, [tex]a=2,c=-3[/tex], but b is not given

Thus the quadratic function with leading coefficient [tex]a=2[/tex] and constant term [tex]c=-3[/tex] is given by

[tex]f(x)=2x^{2} +bx-3[/tex]

∴ the required quadratic equation is

[tex]2x^{2} +bx-3=0[/tex]

Answer:

the perfect cube is [A] 1

Answer:

2/15

Step-by-step explanation:

1/5 + 2/3

= 3/15 + 10/15

= 13/15

15/15 - 13/15

= 2/15

Answer:

The sequence converges to 1.

Step-by-step explanation:

Sequence 2/4, 3/5, 4/6, 5/7

This sequence can be summarized as:

[tex]\sum_{n=0}^{\infty} \frac{n+2}{n+4}[/tex]

To test if it converges, we can calculate the limite of [tex]\frac{n+2}{n+4}[/tex] as n goes to infinite.

Limit:

[tex]\lim_{n \rightarrow \infty} \frac{n+2}{n+4}[/tex]

Considering only the terms with the highest exponent in the numerator and the denominator:

[tex]\lim_{n \rightarrow \infty} \frac{n+2}{n+4} = \lim_{n \rightarrow \infty} \frac{n}{n} = \lim_{n \rightarrow \infty} 1 = 1[/tex]

Thus, the sequences converges to 1.

Answer:

[tex]circumference = 25.13 \ cm[/tex]

Step-by-step explanation:

[tex]circumference = 2 \pi r = 2 \pi 4 = 8 \pi =25.13 \ cm[/tex]

Answer:

y = 1.44x⁴

Step-by-step explanation:

From the question,

Y∝d²

To remove the proportionality sign we introduce a constant.

Y = kd²............... Equation 1

make k the subject of the equation

k = Y/d²............. Equation 2

Given: Y = 4, d = 10

Substitute these values into equation 2

k = 4/10²

k = 4/100

k = 0.04

Substitute these value of k in equation 1

Y = 0.04d²................ Equation 3

Similarly,

d∝x²,

d = Cx²

make C the subject of the equation

C = d/x²................... Equation 4

Given:  d = 24, x = 2

Substitute into equation 4

C = 24/2²

C = 24/4

C = 6

Hence,

d = 6x²................... Equation 5

Substitute the value of d in equation 5 into equation 3

y = 0.04(6x²)²

y = 0.04(36x⁴)

y = 1.44x⁴

Hence the formula for y in terms of x is y = 1.44x⁴

Answer:

the bank contains 30 nickels and 70 dimes.

Step-by-step explanation:

Answer:

The power is 1.68 W.

Step-by-step explanation:

Voltage, V = 3 V

charge, q = 0.56 C

time, t = 1 s

Let the power is P.

P  = V q /t

P = 3 x 0.56 / 1 = 1.68 W

Answer:

Her average speed from Ashdown to Carton is approximately 48.4 mph

Step-by-step explanation:

The time and speed of the motion of Priti are as follows;

The time it takes Priti to drive from Ashdown to Bridgeton, t₁ = 4 hours

The average speed she drove from Ashdown to Bridgeton = 50 mph

The distance she drove from Bridgeton to Carton, d₂ = 30 miles

Her average speed from Bridgeton to Carton = 40 mph

The distance from Ashdown to Bridgeton, d₁ = 50 mph × 4 hours = 200 miles

The time it takes Priti to drive from Bridgeton to Carton, t₂ = 30 miles/(40 mph) = 0.75 hour

Average velocity, [tex]v_{ave}[/tex] = (Total distance traveled, Δd)/(Total time, Δt)

Δd = d₁ + d₂, Δt = t₁ + t₂

Δd = 200 miles + 30 miles = 230 miles

Δt = 4 hours + 0.75 hour = 4.75 hours

∴ The average velocity, [tex]v_{ave}[/tex] = (230 miles)/(4.75 hours)

∴ [tex]v_{ave}[/tex] = (920/19) mph

Her average speed from Ashdown to Carton, rouded to 1 d,p, [tex]v_{ave}[/tex] ≈ 48.4 mph

Answer:

4

Step-by-step explanation:

Let's say our number is n.

First, we have two times a number. This can be represented by 2 times our number, n, or 2*n

Next, we have that is 16 greater than ... It is hard to conceptualize what 2*n is 16 greater than, so we can move on and save this for later.

Furthermore, we have two times the opposite of the number. Opposite represents the opposite side of a number line, e.g. if the number was 5, the opposite would be -5. This can be represented by multiplying our number n by -1, or -1 * n = -n. We then take two times of this opposite, or 2 * -1 * n = -2 * n.

So far, we have 2*n is 16 greater than -2 * n. We can then say that if a first number is 16 greater than a second number, we must add 16 to the second number to get the first number. Applying that here, we can say that 2*n = -2*n + 16

We then have

2*n = -2*n + 16

We then want to separate the n from the real number(s) (16 in this case). To do that, we can add 2*n to both sides, making our equation

2*n+2*n = 16

4*n = 16

Then, we can finally divide both sides by 4 to get

n = 4

Answer:

y = -(1/6)x - 6

Step-by-step explanation:

slope intercept form is

y = mx + b

m is the slope

b is the y-intercept

---------------------------

x + 6y = -24

Subtract x from both sides

6y = -x  - 24

Divide both sides by 6

y = -(1/6)x - 4

slope = -1/6

-----------------------------

Parallel lines have the same slope

therefor the parallel line is

y = -(1/6)x - 6

The volume is 1024. the base lengths are all 16 inches

Answer: It's A

Step-by-step explanation:

Answer:

7(5sqrt ^2y)

Step-by-step explanation:

Answer: 7(5square root x^2y)

Step-by-step explanation:

By Factorisation

4(5[tex]\sqrt{ x^2y[/tex] )+ 3(5[tex]\sqrt{ x^2y[/tex] )= 4+3(5[tex]\sqrt{ x^2y[/tex] ) = 7(5[tex]\sqrt{ x^2y[/tex] )