Answer: Yes, it is a solution
===================================================
Explanation:
Any ordered pair, aka point, is of the form (x,y)
x is always listed first
The point (0,-2) means x = 0 and y = -2 pair up together
Let's plug them into the equation and simplify everything
x-2y = 4
0-2(-2) = 4
0+4 = 4
4 = 4
We end up with a true statement since we get the same thing on both sides, therefore the original equation is true for (x,y) = (0,-2)
(0,-2) is a solution to the given equation
Phrased another way: the point (0,-2) is on the line x-2y = 4. This point is the y intercept.
So sánh √144 và √169
Answer:
Step-by-step explanation:
√144 < √169
Answcăn169
Step-by-step explanat
ion:cvăn 144
What is the equation, in point-slope form, of the line
that is parallel to the given line and passes through the
point (- 1, - 1)?
Answer:
y=-1x-1
Step-by-step explanation:
it should be this
Answer:
D. y+1=3(x+1)
Identify the coefficient(s) of the variable in the expression below.
25 - 6z
A
z
B
1
C
6
D
25 and 6
Answer:
D
Step-by-step explanation:
25 and 6
Coefficient is the number in front of the unknown variable
Identify the coefficient(s) of the variable in the expression below.
25 - 6z
[tex]\implies {\blue {\boxed {\boxed {\purple {\sf {C. \:6}}}}}}[/tex]
Explanation:
Coefficients are numbers that are attached to variables. In the expression "25 - 6z", 6 is the coefficient since it is attached to the variable z.
[tex]\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{.}}}}}[/tex]
Michael is going to the amusement park, where he has to pay a set price of admission
and another price for tickets to go on each of the rides. The total amount of money
Michael will spend is given by the equation y = 3x + 28, where y represents the
total amount of money, in dollars and cents, and a represents the number of rides
Michael goes on. What could the number 3 represent in the equation?
Express in simplest form -45%
Answer: hello, your answer is -0.45
10. Volume =
pls help me i wanna go home ;(
Answer:
1248 cm^2
Step-by-step explanation:
Volume = Length · Width · Height
Volume = 24 · 6 · 5
Volume = 720 cm^2
Volume = Length · Width · Height
Volume = 8 · 6 · 11
Volume = 528 cm^2
528 + 720 = 1248
Answer:
1248 cm³
Step-by-step explanation:
V = lwh
V = 24 cm × 6 cm × 5 cm
V = 720 cm³
V = lwh
V = 8 cm × 6 cm × 11 cm
V = 528 cm³
720 cm³ + 528 cm³
1248 cm³
GIVEN: f(x)=3x-7, g(x)=2x^(2)-3x+1, h(x)=4x+1, k(x)=-x^(2)+3
FIND: (hg)(x)
a. 2x^2+x+2
b. none of these answers
c. 32x^2+4x
d. 8x^2-12x+5
Answer:
32x^2+4x
3x-7, g(x)=2x^(2)-3x+1, h(x)=4x+1, k(x)
The isosceles triangle theorem says "If two sides of a triangle are congruent,
then the angles opposite those sides are congruent."
If you are using this figure to prove the isosceles triangle theorem, which of
the following would be the best strategy?
S
Answer:
Draw QS so that S is the midpoint of PR, then prove ΔPQS is congruent to ΔRQS using SSS.
Step-by-step explanation:
Explanation,
(For Proper Question And Diagram Please Find In attachment)
Draw QS, so that S is the midpoint of PR .Solution,
Now, We know that PS = SR ( S is Midpoint of PR)QS = QS (Common Side) and PQ=QR (given Isosceles Triangle)then triangles are congruent and thus ∠QPS equals to ∠QRS.Thus, the triangle PQR is then the isosceles Triangle.every evening Jenna empties her pockets and puts her change in a jar. At the end of the week she counts her money. One week she had 38 coins, all of them being quarters and dimes. When she added them up she had a total of $6.95. Let d=number of dimes and q= number of quarters. How many dimes did Jenna have?
d = dimes
q = quarters
d+q = 38 coins
q=38-d
0.25q + 0.10d=6.95
0.25(38-d)+0.10d=6.95
9.5-0.25d+0.10d=6.95
-015d=-2.55
d=-2.55/-0.15 = 17
q=38-17 =21
21*0.25 =5.25
17*0.10 = 1.70
5.25+1.70 = 6.95
she had 21 quarters and 17 dimes
Find the greatest number of student among whom 120 oranges and 130 apples can be divided equally.
Answer:
10
Step-by-step explanation:
We need to find the greatest number of student among whom 120 oranges and 130 apples can be divided equally.
It means we need to find the HCF of 120 and 130.
HCF is highest common factor.
The HCF of 120 and 130 is 10.
So, the greatest number of student is 10.
In parallelogram QRST if m∡TQR=50∘ find m∡STQ.
The volume (v) of water stored in an open tank varies due to evaporation as v=x^4-50x^2+700 where v is expressed in gallons and x is number of months elapsed. If January correspond to x=0 what will the volume of water (in gallons) in the tank be in june
A.700
B.1200
C.75
D.100
Answer:
C) 75
Step-by-step explanation:
If January corresponds to x=0 then June corresponds to x=5.
Knowing this we can replace all values of x with 5.
[tex]v=x^4-50x^2+700[/tex]
[tex]v=5^4-50(5)^2+700[/tex]
[tex]v=625-1250+700[/tex]
[tex]v=75[/tex]
Helpppp
Will
Give Brainlist
:)))
Answer:
3.14 million
Step-by-step explanation:
I already answered it on the 1st post
Answer:
3.14 million is the correct answer
Find the missing side. Round to the nearest tenth.
A.7.4
B.4.4
C.6.4
D.5.4
Answer:
option D
Step-by-step explanation:
take 39 degree as reference angle
using cos rule
cos 39 = adjacent / hypotenuse
0.77 = x / 7
x = 7*0.77
x = 5.39
x = 5.4
Answer:
D. 5.4
Step-by-step explanation:
Using trigonometric ratio
cos 39 = x/7
cross multiple
x = cos39(7)
x=5.4
An aeroplane flies 1860 miles in 4 hours. What is its average speed?
Answer:
The average speed is 465 mph
Step-by-step explanation:
1860/4 = 465
Answer:
The average speed is 465 mph
Step-by-step explanation:
Average speed = distance/time
1860 miles / 4 hours = 465 mph
Find the sum difference 104 - (-92)
Answer:
12
Step-by-step explanation:
x^{2} -(3+\sqrt{3} )x +\sqrt{3} -2=0
Answer:
[tex]{ \tt{ {x}^{2} -( 3 + \sqrt{3} ) x + \sqrt{3} - 2 = 0}} \\ \\ x = 4.8 \: \: and \: \: - 0.05[/tex]
A 95% confidence interval is (70,110). what is the margin for error? A. 19 B.38 C.20 D.40
Answer:
C.20
Step-by-step explanation:
Confidence interval concepts:
A confidence interval has two bounds, a lower bound and an upper bound.
A confidence interval is symmetric, which means that the point estimate used is the mid point between these two bounds, that is, the mean of the two bounds.
The margin of error is the difference between the two bounds, divided by 2.
In this question:
Lower bound: 70
Upper bounf: 110
Margin of error:
[tex]M = \frac{110 - 70}{2} = \frac{40}{2} = 20[/tex]
Thus the correct answer is given by option C.
which numbers are the extremes of the proportion shown below [tex]\frac{4}{7} =\frac{20}{35}[/tex]
9514 1404 393
Answer:
4 and 35
Step-by-step explanation:
Written as 4/7 = 20/35, the extremes are the outside numbers: 4 and 35.
Explain two procedures that you can use to draw two adjacent complementary angles. Then draw a pair of adjacent complementary angles so that one angle has a measure of 30°.
Answer:
Complementary angle of 30° is 60°.
Step-by-step explanation:
The complementary angles are the angles whose sum is 90.
If one angle is x then the other angle is 90 - x, they both are complementary to each other.
One angle is 30°, so the other angle is 90° - 30° = 60°
find the next two terms in this sequence
0.1, 0.02, 0.004, 0.0008, 0.00016 ___ ___
Answer:
0.000032 and 0.0000064
Give answer to the Nearest degrees
Answer:
[tex]\theta = 79.9^{\circ}[/tex]
Step-by-step explanation:
Given hypotenuse = x , opposite = 1.7 , adjacent = 0.3
Using trigonometric ratios :
[tex]sin \theta = \frac{opposite}{hypotenuse}\\\\cos \theta = \frac{adjacent}{hypotenuse}\\\\tan \theta = \frac{opposite}{adjacent}[/tex]
[tex]tan \theta = \frac{1.7}{0.3} = \frac{17}{3} = 79.9^{\circ}[/tex]
What is the area of ABC?
This value is approximate.
=========================================================
Work Shown:
area = 0.5*side1*side2*sin(included angle)
area = 0.5*AB*AC*sin(A)
area = 0.5*11*18*sin(55)
area = 81.0960523846101
area = 81.1 cm^2
The cm^2 refers to "square cm".
Notice that the angle must be between the two sides, hence the "included".
PLEASE HELP QUICK, NO FAKE ANSWERS
The linear functions f(x) and g(x) are represented on the graph, where g(x) is a transformation of f(x):
A graph with two linear functions; f of x passes through 1, 3 and 3, 13, and g of x passes through negative 1, 3 and 1, 13.
Part A: Describe two types of transformations that can be used to transform f(x) to g(x). (2 points)
Part B: Solve for k in each type of transformation.
Part C: Write an equation for each type of transformation that can be used to transform f(x) to g(x).
Step-by-step explanation:
(A) We can shift f(x) to the left or up, both resulting in a transformation to g(x) if the values are right.
If we shift all of the values of f(x) to the left, forming a horizontal translation, we can get g(x)
Similarly, if we shift all of the values of f(x) up, forming a vertical translation, we can get g(x)
(B) k represents how much a graph is shifted up or down. In a horizontal translation, we do not shift k up or down, making it 0
In our second, we can make k 10 as the values of g(x) are 10 steps higher than
(C) First, we can see that the values of g(x) are two steps to the left of f(x). As shifts a graph to the left h units, we can turn into to get g(x)
Next, as stated previously, we can see that the values of g(x) are 10 steps higher than f(x). As fx* + k shifts a graph up k units, we can turn into +10 to get g(x)
* this is f(x), needed to bypass content filter
in trapezium abcd diagonals ac and bd intersect at o ar(COD) = 24cm² ar( AOB) = 96 cm² find the area of trapezium
Answer:
The area of the trapezium is 216 cm²
Step-by-step explanation:
The parameters of the trapezium are;
The point of intersection of the diagonals ac and bd = point o
The area of ΔCOD = 24 cm²
The area of ΔAOB = 96 cm²
Let h represent the height of the trapezium and let x represent the height of triangle ΔCOD, we have;
The height of ΔAOB = h - x
Therefore;
The area of ΔCOD = (1/2) × The length of CD × x = 24
∴ The length of CD = 24/((1/2) × x) = 48/x
The area of ΔAOB = (1/2) × The length of AB × (h - x) = 96
The length of AB = 96/((1/2) × (h - x)) = 192/(h - x)
The area of the trapezium, A = ((48/x + 192/(h - x))/2) × h
We note that ΔCOD ~ ΔAOB, therefore;
(AB)²/(CD)² = (h - x)²/x² = (arΔAOB)/(arΔCOD) = 96/24 = 4
∴ √((h - x)²/x²) = (h - x)/x = √4 = 2
∴ h - x = 2·x
h = 2·x + x = 3·x
A = ((48/x + 192/(h - x))/2) × h
∴ A = ((48/x + 192/(2·x))/2) × 3·x = ((48 + 192/(2))/2) × 3 = 216
The area of the trapezium, A = 216 cm².
Question 37 of 55 James buys headphones that cost $10.00. He pays 6% sales tax. How much does he pay for the headphones with tax?
A. $11.60
B. $10.60
C. $12.00
D. $6.00
solve for x and y x+y/ху=1 and x-y/xy = 5
Answer:
(x, y) = (-1/2, 1/3)
Step-by-step explanation:
Given the simultaneous equation
x+y/ху=1. ...1
x-y/xy = 5 .... 2
From 1; x+y = xy ...3
From 2; x - y = 5xy ...4
Substituting 3 into 4
x - y = 5(x+y)
x - y = 5x + 5y
x - 5x = 5y + y
-4x = 6y
-2x = 3y
x = -3y/2 ... 4
Add 3 and 4
2x = 6xy
2 = 6y
y = 2/6
y = 1/3
x = -3(1/3)/2
x = -1/2
Hence (x, y) = (-1/2, 1/3)
Help Please!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
4/8 = 1/2
Step-by-step explanation:
hope it thepled u
in a sale, normal prices are reduced by 10%
nathalie bought a pair of shoes in the sale for £54
what was the original price of the shoes
in a sale, normal prices are reduced by 10%
nathalie bought a pair of shoes in the sale for £54
what was the original price of the shoes
Answer[tex]x = 60[/tex]
Explanation
[tex] \sf based \: on \: the \: given \: conditions \: write : x = \frac{54}{ 1 - 01} [/tex]
[tex] \sf calculate \: the \: sum \: difference: x = \frac{54}{0.9} [/tex]
convert decimal to fraction: x= 54 / 9 / 10
[tex] \sf \: divide \: a \: fraction \: by \: multiplying \: its \: reciprosal : x = 54 \times \frac{10}{9} [/tex]
[tex] \sf \: write \: as \: a \: single \: fraction : x = \frac{54 \times 10}{9} [/tex]
[tex] \sf \: reduce \: fraction \: to \: the \: lowest \: term \: by \: cancelling \: the \: greatest \: [/tex]
[tex] \sf \: common \: factor : x = 6 \times 10[/tex]
[tex] \sf \: calculate \: the \: product \: or \: quotient : x = 60 [/tex]
[tex] \sf{ \boxed{answer : x = 60}}[/tex]
Work out m and c for the line:2y+3x=5
Answer:
[tex]{ \tt{2y + 3x = 5}} \\ { \tt{2y = - 3x + 5}} \\ { \tt{y = - \frac{3}{2} x + \frac{5}{2} }} \\ { \boxed{ \bf{general \: equation : { \tt{y = mx + c}}}}} \\ by \: relation : \\ { \tt{m = - \frac{3}{2} }} \\ \\ { \tt{c = \frac{5}{2} }} \\ \\ { \underline{ \blue{ \tt{becker⚜jnr}}}}[/tex]