Answer:
12:24:6- divide by 3
4:8:2 - divide by 2
2:4:1- simplest form
please help me Solve the following equations simultaneously:
solve for x and y
x+3y =6 and 2x+8y=-12
Answer:
x+3y =6
2x+8y=-12
The solutions to your equations are:
x= 42 and y= -12
lets check this
42+-36 =6
84+-96=-12
Hope This Helps!!!
In the triangle below, which is equivalent to sinA?
Right triangle A B C is shown. B is the right angle and side A C is the hypotenuse.
sinC
sinB
cosA
cosC
Answer:
CosC
Step-by-step explanation:
EDG
Find the whole using the percent proportion. 70% of what number of hay bales is
63 hay bales?
Answer:
90
Step-by-step explanation:
Let the whole number be x.
100% is to x as 70% is to 63
100/x = 70/63
10/x = 10/9
10x = 90 * 10
x = 90
Answer: 90
Step-by-step explanation:
0.7x = 63, x = 63/0.7 = 90
PLEASE HELP ME PLEASE DUE IN 30 MINUTES
Answer:
x = 82.1º
Step-by-step explanation:
tan = opp/adj
tan75 = x/22
multiply both sides by 22
22 * tan75 = x
use calculator
82.1051177665153 = x
Rounded
x = 82.1º
Which graph represents the solution set of the compound inequality -4 s 3x-1 and 2x+4 518?
-10
-5
0
10
O
+
-10
-5
0
5
10
5
-10
0
5
10
+
-10
-5
0
10
Answer:
it's the first one where X is greater or equals to -1 and X is less or equals to positive 7
The compound inequality in x : -1 ≤ x ≤ 7
The correct graph is A .
Given, inequality: -4 ≤ 3x -1 and 2x + 4 ≤ 18 .
First inequality:
-4 ≤ 3x -1
Take -2 from RHS to LHS .
-4 + 1 ≤ 3x
-3 ≤ 3x
x ≥ -1
X will have values greater than equal to -1 .
Second inequality:
2x + 4 ≤ 18
take 4 from LHS to RHS.
2x ≤ 18 - 4
2x ≤ 14
x ≤ 7
x will have values less than equals to 7.
Combined result of both inequalities: -1 ≤ x ≤ 7 .Thus graph A is correct.
Know more about inequality,
https://brainly.com/question/28823603
#SPJ3
Polygon ABCD is a rectangle. What is its area? Round your answer to the
nearest tenth.
(2,4)
(4,1)
(-4,0)
4
(-2, -3)
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Answer:
26 square units
Step-by-step explanation:
Counting grid squares on the graph, we see that segment AB is the hypotenuse of a right triangle with legs 2 and 3. Its length is ...
AB = √(2²+3²) = √13
We can also see that the adjacent longer sides are twice this length, each being the hypotenuse of a triangle that is 6 wide and 4 high.
AC = √(6² +4²) = √52 = 2√13
Then the area is ...
A = LW
A = (2√13)(√13) = 2·13 = 26 . . . square units
What is the volume of a sphere with a radius of 20 m? 10,666.67π m3 6,000π m3 85,333.33π m3 533.33π m3
Answer:10,666,66 [tex]\pi[/tex]m^3
Step-by-step explanation:
V=[tex]\frac{4}{3} \pi r^{3}[/tex]
[tex]\frac{4}{3} \pi 20^{3} \\ V=10,666.66 \pi[/tex]
The ratio of girls to boys in a particular classroom is 4:3. What fraction of the total number of students are boys?
The ratio of boys to the total number of students in a particular classroom is
Answer:
3:7
Step-by-step explanation:
We know that there are 4 girls and 3 boys and 4+3=7.
Solve the Inequality: [tex]\frac{b}{3} \geq -1[/tex]
[tex] \frac{b}{3} \geq - 1 \\ = 3 \times \frac{b}{3} \geq \times ( -1 ) \\ = b \geq3 \times ( - 1) \\ = b \geq - 3 \times 1 \\ \\ = b \geq - 3[/tex]
Step By Step Explanation:
Multiply both sides of the inequality by 3Reduce the numbers with the greatest common factor 3Multiplying a positive and a negative equals a negative Any expression multiplied by 1 remains the same ☆彡Hanna#CarryOnLearning
5 > Chapter 2: Modeling with Quadratic Functions > Secti
Write an equation of the parabola in intercept form.
IN AY
х
-2.
(-1,0)
(2,0)
(1, -2)
-4
4
An equation of the parabola is y=0
Answer:
the awnser is 2,0
Step-by-step explanation:
Answer:
(1,-2) is the correct answer
Find the degree measures of the next two positive and the previous two negative angles that are coterminal with the angle 75°.
The angles are:
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Answer:
435°, 795°-285°, -645°Step-by-step explanation:
Add or subtract multiples of 360° to find coterminal angles.
Positive
75° +360° = 435°
75° +2×360° = 795°
Negative
75° -360° = -285°
75° -2×360° = -645°
What is the vertex of the quadratic function below?
(-4, 0)
There is no y-intercept
(0, -1)
(-2, 3)
Answer:
(-2, 3)
Step-by-step explanation:
What is the nearest quarter hour to 10:40
[tex]\Huge \bf \over \rightarrow\mid\mathcal {\underline{ \orange{12 \: : \: 00}}} \mid[/tex]
Answer:
I think 10:45 is the nearest quarter hour.
HW HELP ASAP PLZZZZZ
Answer:
last step is (2x + 5)(2x + 1)
Step-by-step explanation:
4x^2 + 12x + 5
4x^2 + (10 + 2)x + 5
4x^2 + 10x + 2x + 5
2x(2x + 5) +1(2x + 5)
(2x + 5)(2x + 1)
pls I have limited time left pls help
Answer:
2B+5C
Step-by-step explanation:
Multiply them out....
2B=2*(4i-j) = 8i-2j
5C=5*(2i+3j) = 10i+15j
2B+5C= 8i-2j+10i+15j =18i+13j = A
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Answer:
a) 2B +5C
Step-by-step explanation:
It is probably easiest to simply try the answer choices. You find the first one works, which means it is the one you want.
2B +5C = 2(4i -j) +5(2i +3j) . . . . choice (a)
= 8i -2j +10i +15j
= 18i +13j = A
__
In general, you can solve for the coefficients p and q that make ...
pB +qC = A
p(4i -j) +q(2i +3j) = 18i +13j
(4p+2q)i +(-p +3q)j = 18i +13j
Equating the coefficients of i and j gives us 2 equations in p and q.
4p +2q = 18
-p +3q = 13
Adding 2 times the second equation to 1/2 the first, we get ...
1/2(4p +2q) +2(-p +3q) = 1/2(18) +2(13)
7q = 35
q = 5
Using the second equation to find p, we get ...
p = 3q -13 = 3(5) -13 = 2
These coefficients tell us ...
A = 2B +5C . . . . . . . matches choice (a)
Police response time to an emergency call is the difference between the time the call is first received by the dispatcher and the time a patrol car radios that it has arrived at the scene. Over a long period of time, it has been determined that the police response time has a normal distribution with a mean of 8.1 minutes and a standard deviation of 2.0 minutes. For a randomly received emergency call, find the following probabilities.
a. between 5 and 10 min
b. less than 5 min
c. more than 10 min
Answer:
a) 0.7683 = 76.83% probability that a randomly selected emergency call is between 5 and 10 minutes.
b) 0.0606 = 6.06% probability that a randomly received emergency call is of less than 5 min.
c) 0.1711 = 17.11% probability that a randomly received emergency call is of more than 10 min.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 8.1 minutes and a standard deviation of 2.0 minutes.
This means that [tex]\mu = 8.1, \sigma = 2[/tex]
a. between 5 and 10 min
This is the p-value of Z when X = 10 subtracted by the p-value of Z when X = 5.
X = 10
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{10 - 8.1}{2}[/tex]
[tex]Z = 0.95[/tex]
[tex]Z = 0.95[/tex] has a p-value of 0.8289
X = 5
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{5 - 8.1}{2}[/tex]
[tex]Z = -1.55[/tex]
[tex]Z = -1.55[/tex] has a p-value of 0.0606
0.8289 - 0.0606 = 0.7683
0.7683 = 76.83% probability that a randomly selected emergency call is between 5 and 10 minutes.
b. less than 5 min
p-value of Z when X = 5, which, found from item a, is of 0.0606
0.0606 = 6.06% probability that a randomly received emergency call is of less than 5 min.
c. more than 10 min
1 subtracted by the p-value of Z when X = 10, which, from item a, is of 0.8289
1 - 0.8289 = 0.1711
0.1711 = 17.11% probability that a randomly received emergency call is of more than 10 min.
Flying against the wind a jet travels 1590 miles in 3 hours flying with the wind the same jet travels 8240 miles in 8 hours. What is the rate of the j et in still air and what is the rate of the wind?
Answer: See explanation
Step-by-step explanation:
From the information given, the following can be deduced:
Let rate of jet in still air be J
Let rate of wind be W
The formula for distance:
d = rt
Therefore, r = d/t
When, flying against the wind, then the Jet flies at a rate of J - W which will be:
= 1590mi/3hrs
= 530mph
When flying with the wind the jet will fly at a rate of J+W which will be:
= 8240mi/8hrs
= 1030 mph
Their average rate will be:
J = (530+1030)/2
= 1560/2
J = 780 mph
Since J - W = 530
Therefore, so
780 - W = 530
W = 780 - 530
W = 250 mph
The Jet in still air flies at a rate of 780 mph and the wind speed is 250 mph
The box plots show the weights, in pounds, of the dogs in two different animal shelters.
Weights of Dogs in Shelter A
2 box plots. The number line goes from 6 to 30. For the weights of dogs in shelter A, the whiskers range from 8 to 30, and the box ranges from 17 to 28. A line divides the box at 21. For shelter B, the whiskers range from 10 to 28, and the box ranges from 16 to 20. A line divides the box at 18.
Weights of Dogs in Shelter B
Which is true of the data in the box plots? Select three choices.
The median weight for shelter A is greater than that for shelter B.
The median weight for shelter B is greater than that for shelter A.
The data for shelter A are a symmetric data set.
The data for shelter B are a symmetric data set.
The interquartile range of shelter A is greater than the interquartile range of shelter B.
Answer:
The median weight for shelter A is greater than that for shelter B.
The data for shelter B are a symmetric data set.
The interquartile range of shelter A is greater than the interquartile range of shelter B.
Step-by-step explanation:
The median weight for shelter A is greater than that for shelter B.
The median of A = 21 and the median of B = 18 true
The median weight for shelter B is greater than that for shelter A.
The median of A = 21 and the median of B = 18 false
The data for shelter A are a symmetric data set.
False, looking at the box it is not symmetric
The data for shelter B are a symmetric data set.
true, looking at the box it is symmetric
The interquartile range of shelter A is greater than the interquartile range of shelter B.
IQR = 28 - 17 = 11 for A
IQR for B = 20 -16 = 4 True
How to find the account balance
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Answer:
$163,002
Step-by-step explanation:
If you're working problems of this sort, you have been shown formulas and examples. Use the appropriate formula with the numbers of this problem.
For the formula below, you have d=3000, r=0.045, k=4, N=11
P = (3000)(1 -(1 +0.045/4)^(-11·4))/(0.045/4) ≈ 163,002
The account needs to hold about $163,002 to make this possible.
calculate the surface area and show work :) please help me no links!!
Answer:
294 in.²
Step-by-step explanation:
I believe this figure is a rectangular prism.
------------------------------------------------------------------------------------
Explain:
To find the surface area of a rectangular prism, use this formula:
[tex]SA=2lw+2lh+2wh[/tex]
or
[tex]SA=2(lw+lh+wh)[/tex]
[tex]l-length[/tex]
[tex]w-width[/tex]
[tex]h-height[/tex]
A phrase I use to help remember this formula is:
LISA WILSON LOST HER WITCH HAT TWICE (2)
------------------------------------------------------------------------------------
Solve:
The length of this rectangular prism is 9 in.
This width is 10 in.
The height is 3 in.
Now, I will plug the numbers into the first formula.
[tex]SA=(2*9*10)+(2*9*3)+(2*10*3)=294 in.^2[/tex]
------------------------------------------------------------------------------------
Conclude:
I, therefore, believe the area of this rectangular prism is 294 in.²
sum of 15,-2 and 7 is
Answer:
20
Step-by-step explanation:
15+(-2)+7=13+7=20
[tex]\longrightarrow{\blue{20}}[/tex]
[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]
[tex]\:15 + ( - 2) + 7[/tex]
➺ [tex] \: 15 - 2 + 7[/tex]
➺ [tex] \: 22 - 2[/tex]
➺ [tex] \: 20[/tex]
Note:-[tex]\sf\pink{PEMDAS\: rule.}[/tex]
P = Parentheses
E = Exponents
M = Multiplication
D = Division
A = Addition
S = Subtraction
[tex]\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{.}}}}}[/tex]
f(x) = 4x² + 3x - 2 g(x) = 6x³ - 3x²-4 Find (f +g) (x)
Answer:
6x^3+x^2+3x-6
Step-by-step explanation:
f(x) = 4x² + 3x - 2
g(x) = 6x³ - 3x²-4
(f +g) (x) =4x² + 3x - 2+6x³ - 3x²-4
Combine like terms
=6x^3+4x^2-3x^2+3x-2-4
=6x^3+x^2+3x-6
The equation of the line passing through (2, 3) with a slope of 5 is y = [] x - []
what are the answers to []
Answer:
y = 5x - 7
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Here m = 5, then
y = 5x + c ← is the partial equation
To find c substitute (2, 3) into the partial equation
3 = 10 + c ⇒ c = 3 - 10 = - 7
y = 5x - 7 ← equation of line
The run scored in a cricket match by 11 players is as follows: 7, 16, 121, 51,101, 81, 1, 16, 9, 11, and 16. Find the mean of this data
John, Jack, and Jill have 159 marbles altogether. John has 2 more marbles than Jack, and if Jill gave 5 marbles to Jack, Jack would have the same number of marbles as Jill. How many marbles does each of them have?
Answer:
someone else tell me to thank you
VIVIAN: My friend Sharon told me today that she will be driving back to Victorville, her hometown, this weekend for the first time in almost two years. NATALIE: You must not have been listening very carefully to what Sharon was saying, because I know for sure that Sharon's hometown is Vacaville, not Victorville.
Is dispute C a verbal dispute or a factual dispute?
a. Factual
b. Verbal
Answer:
The answer is "Option a".
Step-by-step explanation:
Dispute C comes under factual dispute because the words Vacaville or Victorville are two different places and they are arguing about the fact that's why option a is correct.
Ms.James shared 5/8 of the candies she had in a bag and had 15 left.How many candies did she have before sharing?
Answer:
40
Step-by-step explanation:
If you take 15, and divide it by the 3 out of the 3/8 left, you get 5. You then multiply 5 by 8 to get the full amount of candies she had before sharing, 40.
I hope this helped!
Thanks!
Your friend in answering,
~Steve
Answer:
40.
Step-by-step explanation:
If 15 candies are the rest of 3/8, then the total candies were 40.
The manufacturer claims the mean bursting pressure for a certain type and size of PVC irrigation pipe to be at least 350 psi. A sample of 10 such pipes were experimentally determined to have the following bursting pressures: 401 359 383 427 414 415 389 463 394 428 State the null and alternative hypotheses:
Answer:
H0 : μ ≥ 350
H1 : μ < 350
Step-by-step explanation:
It is claimed that the mean is atleast 350 psi ;
10 such pipes were experimentally sampled ;
Here, the null hypothesis is the claim ; this means that the alternative hypothesis will be the opposite of the claim.
The hypothesis
H0 : μ ≥ 350
H1 : μ < 350
Use the Law of Sines to write an expression that represents the angle measure x.
Answer:
Step-by-step explanation:
Law of sines says that the length of sides are proportional to the sine of the opposing angle.
Using the sine rule,
sin(x)/2.5 = sin(28)/3
therefore
sin(x) = 2.5 * sin(28) / 3
or
here we have
x = asin (2.5*sin(28) / 3)
so
box 1 = 2.5
box 2 = 28°
box 3 = 3
Solve for H.[tex]V = \pi r^{2} h[/tex]
Answer:
h = [tex]\frac{V}{\pi r^2}[/tex]
Step-by-step explanation:
Given
V = πr²h ( isolate h by dividing both sides by πr² )
[tex]\frac{V}{\pi r^2}[/tex] = h