Find the sum
(2x−6)+4(x−3)
ANSWER QUICKLY PLEASE!!

The value of the given equation is 2 and -10.

An equation is a mathematical statement that shows that two mathematical expressions are equal.

For example, 3x + 5 = 14 is an equation, in which 3x + 5 and 14 are two expressions separated by an 'equal' sign.

Given is an equation, x²+8x-20 = 0, we need to solve for x,

x²+8x-20 = 0

Solving for x, by using factorization,

x²+8x-20 = 0

Splitting the middle term,

x²+10x-2x-20 = 0

x(x+10)-2(x+10) = 0

(x-2)(x+10) = 0

x = 2 and x = -10

Hence, the value of the given equation is 2 and -10.

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The complete question is attached

Answer:

Second option is the correct answer

[tex](x+11)^2+(y+6)^2 = 324[/tex]

Step-by-step explanation:

[tex]x^{2} +12y+22x+y^2-167=0\\x^{2}+22x +y^2 +12y-167=0\\(x^{2}+22x +121)-121 +(y^2 +12y+36)-36-167=0\\(x+11)^2+(y+6)^2-324 = 0\\\huge\red{\boxed{(x+11)^2+(y+6)^2 = 324}}\\[/tex]

Answer:

[tex](x+11)^2+(y+6)^2=324[/tex]

Step-by-step explanation:

[tex]x^2+12y+22x+y^2-167=0\\\mathrm{Circle\:Equation}\\\left(x-a\right)^2+\left(y-b\right)^2=r^2\:\:\mathrm{is\:the\:circle\:equation\:with\:a\:radius\:r,\:centered\:at}\:\left(a,\:b\right)\\\mathrm{Rewrite}\:x^2+12y+22x+y^2-167=0\:\mathrm{in\:the\:form\:of\:the\:standard\:circle\:equation}\\x^2+12y+22x+y^2-167=0\\\mathrm{Move\:the\:loose\:number\:to\:the\:right\:side}\\x^2+22x+y^2+12y=167\\Group\:x-variables\:and\:y-variables\:together\\\left(x^2+22x\right)+\left(y^2+12y\right)=167[/tex]

[tex]\mathrm{Convert}\:x\:\mathrm{to\:square\:form}\\\left(x^2+22x+121\right)+\left(y^2+12y\right)=167+12\\Convert\:to\:square\:form\\\left(x+11\right)^2+\left(y^2+12y\right)=167+121\\\mathrm{Convert}\:y\:\mathrm{to\:square\:form}\\\left(x+11\right)^2+\left(y^2+12y+36\right)=167+121+36\\Convert\:to\:square\:form\\\left(x+11\right)^2+\left(y+6\right)^2=167+121+36\\\mathrm{Refine\:}167+121+36\\\left(x+11\right)^2+\left(y+6\right)^2=324\\Rewrite\:in\:standard\:form[/tex]

[tex]\left(x-\left(-11\right)\right)^2+\left(y-\left(-6\right)\right)^2=18^2\\\mathrm{Therefore\:the\:circle\:properties\:are:}\\\left(a,\:b\right)=\left(-11,\:-6\right),\:r=18[/tex]

Answer:

The third one.

Step-by-step explanation:

Answer:

575(1+2.5)^x

Step-by-step explanation:

X represents the number of years since they were first counted.

Answer:

For this case we can define y as the response variable and represent the cost and x the independent variable who represent the hours of lessons. We know that the instructor has an initial fee of 12 and charges 8 per hour. So then we can model the situation with this formula:

[tex] y =mx+b[/tex]

Where m = 8 represent the slope and b =12 the intercept so our model would be:

[tex] y = 8x +12[/tex]

And the y intercept would be at x=0 and y=12 and represent the initial amount of money that we need to pay in order to have the instructor.

Step-by-step explanation:

For this case we can define y as the response variable and represent the cost and x the independent variable who represent the hours of lessons. We know that the instructor has an initial fee of 12 and charges 8 per hour. So then we can model the situation with this formula:

[tex] y =mx+b[/tex]

Where m = 8 represent the slope and b =12 the intercept so our model would be:

[tex] y = 8x +12[/tex]

And the y intercept would be at x=0 and y=12 and represent the initial amount of money that we need to pay in order to have the instructor.

Answer:

y= 8x+12

Explanation:

I have just completed it. Thank me later.

Answer:

Hey mate, I think you forgot to attach photo of sets. Check it.

Answer:

  B = (5, -1)

Step-by-step explanation:

We can use the required relation to find an expression for B in terms of the given points.

  AB = (1/3)(BC)

  B -A = (1/3)(C -B)

  B = (1/3)C -(1/3)B +A . . . . . add A

  (4/3)B = (1/3)C +A . . . . . . . add 1/3B

  B = (1/4)C +(3/4)A = (C +3A)/4 . . . . . . multiply by 3/4

  B = ((2, -7) +3(6, 1))/4 = (20/4, -4/4) . . . . . substitute given values

  B = (5, -1)

Answer:

5/-1

tru trust me

Step-by-step explanation:

Answer:

The volume increases by a factor or 64. When the cube is dilated, each side length is increased by 4, so the volume is increased by 64.

Step-by-step explanation:

Let L represents the Length of the cube before it's dilated.

Volume, V1 = Length * Length * Length

Volume, V1 = L * L * L

Volume, V1 = L³

When the cube is dilated by a factor of 4.

The new Length becomes 4L.

The new volume is calculated as thus.

New Volume, V2 = 4L * 4L * 4L

New Volume, V2 = 64L³

Dividing the new volume by the old volume gives the increment factor.

Factor = New Volume ÷ Old Volume

Factor = V2/V1

Factor = 64L³/L³

Factor = 64.

Hence, when the sides of the cube is dilated by 4, the volume increases by a factor of 64.

Filling the gap of the given sentence;

"The volume increases by a factor or 64. When the cube is dilated, each side length is increased by 4, so the volume is increased by 64"

Answer:

i) x = 0.25 and 1.25

ii) x = -0.5 and 1.5

Step-by-step explanation:

Given that y = 4x² - 4x - 1. So for question 1, you can let y = 0, then see which x-value did the curve touches 0 at y-axis.

Same for question 2.

Answer:

H0: μ = 0.125, Ha: μ ≠ 0.125

Step-by-step explanation:

I got the answer correct on the quiz.

The null and alternative hypotheses should the company use for this study H₀: μ = 0.125 Hₐ: μ > 0.125.

An alternate Hypothesis is a statistical experiment that is contradictory to the null hypothesis.

The claim made by the company should be  

Using the company's product will slow down leg growth. According to the study, the average woman's leg hair grows an eighth of an inch per month. So, the company will claim that using its product the average growth will be less than an eighth of an inch per month. Since, the claim contains the word "less than", it will be the alternate hypothesis.

The Null hypothesis, therefore, would be: The average growth is eight of an inch per month.  

Let u represent the growth of hair per month.

The Null and Alternate Hypothesis in symbolic forms would be

Null Hypothesis:

[tex]H_{0} : \mu = 0.125\\[/tex],

Alternate Hypothesis:

[tex]H_{a} : \mu > 0.125[/tex]

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Answer:

[tex] \frac{1}{2} [/tex]

[tex] \\ [/tex]

Step-by-step explanation:

[tex] \frac{5}{8} - \frac{1}{8} \\ = \frac{4}{8} \\ = \frac{1}{2} [/tex]

Answer:

30 cups

Step-by-step explanation:

mango: 16 cups x 3/4 = 12 cups

pomegranate: 1 pint = 2 cups

cranberry: 1 gallon= 16 cups

Cups of fruit punch: 12+2+16= 30

( Hopefully this helped )

Answer:

A. LM ⊥ MN. D. The triangle is isosceles. E. The triangle is a right triangle.

Step-by-step explanation:

edge 2020 <3

Answer:

(a) The correlation is positive

Step-by-step explanation:

Answer:

  y > -x -3

Step-by-step explanation:

The graph is shaded above the dashed line, indicating y-values in the solution are greater than those on the line, so your inequality will start with ...

  y >

The y-intercept of the line is (0, -3), so the "b" value in ...

  y > mx +b

will be -3.

The line has a rise of -3 for a run of 3 (between the marked points), so the slope is ...

  m = rise/run = -3/3 = -1

Then the inequality you want is ...

  y > -x -3

Answer:

  0.5 gallons

Step-by-step explanation:

Let x represent the amount of orange juice (in gallons) Gayle must add to the mix. Then the total amount of orange in the mix is ...

  0.25(2) +x = 0.40(2+x)

  0.50 +x = 0.80 +0.40x . . . . eliminate parentheses

  0.60x = 0.30 . . . . . . . . . . . .  subtract 0.50+0.40x

  x = 0.5 . . . . . . . . . . . . . . . . . divide by 0.60

Gayle should add 0.5 gallons of orange juice to make a 40% solution.

Answer:

[tex]=-8[/tex]

Step-by-step explanation:

[tex]\log _{0.5}\left(256\right)=x\\Switch\:sides\\x=\log _{0.5}\left(256\right)\\\mathrm{Rewrite\:}256\mathrm{\:in\:power-base\:form:}\quad 256=2^8\\x=\log _{0.5}\left(2^8\right)\\\mathrm{Apply\:log\:rule}:\quad \log _a\left(x^b\right)=b\cdot \log _a\left(x\right)\\\log _{0.5}\left(2^8\right)=8\log _{0.5}\left(2\right)\\x=8\log _{0.5}\left(2\right)\\0.5=2^{-1}\\x=8\log _{2^{-1}}\left(2\right)\\[/tex]

[tex]\mathrm{Apply\:log\:rule\:}\log _{a^b}\left(x\right)=\frac{1}{b}\log _a\left(x\right),\:\quad \mathrm{\:assuming\:}a\:\ge \:0\\x=8\cdot \frac{1}{-1}\log _2\left(2\right)\\\mathrm{Apply\:log\:rule}:\quad \log _a\left(a\right)=1\\x=8\cdot \frac{1}{-1}\\\mathrm{Simplify}\\8\cdot \frac{1}{-1}\\\frac{1}{-1}=-1\\\frac{1}{-1}\\\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{-b}=-\frac{a}{b}\\=-\frac{1}{1}\\\mathrm{Apply\:rule}\:\frac{a}{1}=a\\=-1\\=8\left(-1\right)\\[/tex]

[tex]\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a\\=-8\cdot \:1\\\mathrm{Multiply\:the\:numbers:}\:8\cdot \:1=8\\=-8\\[/tex]

The value of x for the expression is, - 8.

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that;

The expression is,

⇒ [tex]log_{0.5} ( 256) = x[/tex]

Now, We can solve the expression by the logarithmic for the value of x as;

⇒ [tex]log_{0.5} ( 256) = x[/tex]

⇒ [tex]x = log_{0.5} ( 256)[/tex]

⇒ [tex]x = log_{0.5} ( 2^8)[/tex]

Apply log rule,

⇒ [tex]x =8 log_{0.5} ( 2)[/tex]

⇒ [tex]x = 8 log_{2^{-1} } ( 2)[/tex]

⇒ [tex]x = 8 *\frac{1}{-1} log_{2 } ( 2)[/tex]

⇒ [tex]x = - 8 log_{2 } ( 2)[/tex]

We know that; [tex]log_{2} 2 = 1\\[/tex]

Hence, We get;

⇒ x = - 8 × 1

⇒ x = - 8

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Answer:

47.13

Step-by-step explanation:

The requried circumference of the circle is given as 47.13 cm.

The circle is the locus of a point whose distance from a fixed point is constant i.e center (h, k). the equation of the circle is given by

(x - h)² + (y - k)² = r²

Where h, k is the coordinate of the center of the circle on the coordinate plane and r is the radius of the circle.

Here,
The circumference of a circle with a radius of 7.5 cm takes pi to be 3.142 is given as,
Circumference of circle = 2πr
Circumference of circle = 2 × 3.142 × 7.5 = 47.13 cm

Thus, the requried circumference of the circle is given as 47.13 cm.

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Answer:

54 ft^2

(54 in green box; 2 in grey box)

Step-by-step explanation:

We have 2 similar triangles, ABC and DEF.

The area of triangle DEF is given as 6 sq ft.

Side BC of triangle ABC measures 12 ft.

The corresponding side to BC in triangle DEF is EF. It measures 4 ft.

That gives us a scale factor from triangle DEF to triangle ABC.

To find the scale factor between two similar polygons, divide the length of a side of the second polygon by the length of the corresponding side of the first polygon.

scale factor = BC/EF = (12 ft)/(4 ft) = 3

The scale factor of side lengths is 3.

The ratio of the areas is the square of the scale factor.

ratio of areas = 3^2 = 9

Now multiply the area of the first triangle (DEF) by the ratio of areas to get the area of the second triangle (ABC).

area of triangle ABC = 9 * (area of triangle DEF)

area of triangle ABC = 9 * (6 sq ft)

area of triangle ABC = 54 sq ft

Answer: 54 ft^2

(54 in green box; 2 in grey box)

Answer: /-2

Step-by-step explanation:

no time to explain but it would make sence using pemdas

Answer:

the answer is B

or

Negative one-half (negative 2) (x + 3) = negative 10 (negative one-half)

Step-by-step explanation:

now give me my brainly plz

I know I wasn't first but the other guy was wrong

Step-by-step explanation:

there are four dogs because each dog at a corner will see the other three dogs at the other corners

Answer:

65

Step-by-step explanation:

6 x 5 = 30

6+ 5 = 11

therefore, the answer is 65

｡☆✼★ ━━━━━━━━━━━━━━  ☾  

12 + 12 + 18 + 18 = 60

The perimeter is 60 cm

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Answer:

The correct option is A

Step-by-step explanation:

From the question we are told that

   The average  number of meetings  hours per week is [tex]\mu= 18 \ hours[/tex]

    The standard deviation is  [tex]\sigma = 5.2 \ hours[/tex]

     The sample size is  n=  35

     The sample average per week is  [tex]p = 16.8 \ hours[/tex]

From each solution statement we can deduce that the confidence level is  

    [tex]t = 95[/tex]%

Thus the significance level is  [tex]\alpha = 0.05[/tex]= 5%

The z value for the significance level is gotten as 1.96 from the z-table

    The confidence level interval for the sample mean is mathematically evaluated as

            [tex]\= x = \mu \pm (1.96 * \frac{\sigma }{\sqrt{n} } )[/tex]

 Sustituting values

           [tex]\= x = 18 \pm (1.96 * \frac{5.2 }{\sqrt{35} } )[/tex]

             [tex]\= x = 18 \pm1.7[/tex]

=>               [tex]18 - 1.7 < \= x < 18 +1.7[/tex]

                  [tex]16.3 < \= x < 19.7[/tex]

Answer:

i think it is 22.75 dollars

Step-by-step explanation:

Answer: perfect squares are the squares of the whole numbers: 1, 4, 9,25,36,49,64,81,100...... For example, 9 is a squared number because it can be written as 3x3. However, imperfect squares are numbers whose square roots contain fractions or decimals. For example square root of 20 = 4 1/2

The square number, sometimes known as a perfect square, is an integer that is the square of another integer and numbers with fractional or decimal square roots are considered imperfect squares.

We need to compare and contrast perfect squares and imperfect squares.

Perfect squares: When you multiply an integer by itself, you get a perfect square, which is a positive integer. Perfect squares are sums that are the products of integers multiplied by themselves, to put it simply. A perfect square is typically expressed as x², where x is an integer and x²'s value is a perfect square.

Imperfect squares: Numbers with fractional or decimal square roots are considered imperfect squares.

Therefore, the square number, sometimes known as a perfect square, is an integer that is the square of another integer and numbers with fractional or decimal square roots are considered imperfect squares.

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Answer:

  1.4

Step-by-step explanation:

Both points are on the vertical line x=4, so the distance between them is the difference of their y-coordinates:

  2.9 -1.5 = 1.4

The points are 1.4 units apart.

Answer:

The probability that he drove the small car is 0.318.

Step-by-step explanation:

We are given that a friend who works in a big city owns two cars, one small and one large. One-quarter of the time he drives the small car to work, and three-quarters of the time he takes the large car.

If he takes the small car, he usually has little trouble parking and so is at work on time with probability 0.7. If he takes the large car, he is on time to work with probability 0.5.

Let the Probability that he drives the small car = P(S) = [tex]\frac{1}{4}[/tex] = 0.25

Probability that he drives the large car = P(L) = [tex]\frac{3}{4}[/tex] = 0.75

Also, let WT = event that he is at work on time

So, Probability that he is at work on time given that he takes the small car = P(WT / S) = 0.7

Probability that he is at work on time given that he takes the large car = P(WT / L) = 0.5

Now, given that he was at work on time on a particular morning, the probability that he drove the small car is given by = P(S / WT)

We will use the concept of Bayes' Theorem for calculating above probability;

So,    P(S / WT)  =  [tex]\frac{P(S) \times P(WT/S)}{P(S) \times P(WT/S)+P(L) \times P(WT/L)}[/tex]

                          =  [tex]\frac{0.25 \times 0.7}{0.25 \times 0.7+0.75 \times 0.5}[/tex]

                          =  [tex]\frac{0.175}{0.55}[/tex]

                          =  0.318

Hence, the required probability is 0.318.

Answer:

To the nearest tenth = 10.8cm

Step-by-step explanation:

Using the cosine rule

J² = i² + k² + 2ikcosj

J² = 3.4² + 7.7² + 2(3.4)(7.7) cos 30

J² = 11.56 + 59.29 + 52.36cos30

J² = 11.56 + 59.29 + 52.36(0.8660)

J² = 11.56 + 59.29 + 45.35

J² = 116.2

J=√116.2

J= 10.78 cm

To the nearest tenth = 10.8cm

Answer:

its 5.1

Step-by-step explanation:

\text{S.A.S.}\rightarrow \text{Law of Cosines}

S.A.S.→Law of Cosines

a^2=b^2+c^2-2bc\cos A

a  

2

=b  

2

+c  

2

−2bccosA

From reference sheet.

j^2 = 7.7^2+3.4^2-2(7.7)(3.4)\cos 30

j  

2

=7.7  

2

+3.4  

2

−2(7.7)(3.4)cos30

Plug in values.

j^2 = 59.29+11.56-2(7.7)(3.4)(0.866025)

j  

2

=59.29+11.56−2(7.7)(3.4)(0.866025)

Square and find cosine.

j^2 = 59.29+11.56-45.34509

j  

2

=59.29+11.56−45.34509

Multiply.

j^2 = 25.50491

j  

2

=25.50491

Add.

j=\sqrt{25.50491} \approx5.05 \approx5.1

j=  

25.50491

​  

≈5.05≈5.1

Square root and round.

Answer:

Step-by-step explanation:

Hello!

Peter is interested in comparing the number of hours adults and teenagers exercise per week, for this selected one random group of adults and a random group of teenagers and surveyed them on their weekly exercise times.

To compare the weekly exercise time of both populations, the best is to use a measure central tendency, so you can compare their positions and see if they are significantly similar or not.

The most common parameters to use for comparing two populations are its population means. So the analysis to do is a two independent sample test.

I hope this helps!