Answer:
[tex]P = (\frac{1}{3}t^\frac{3}{2} + \sqrt 2 - \frac{1}{3})^2[/tex]
Step-by-step explanation:
Given
[tex]\frac{dP}{dt} = \sqrt{Pt[/tex]
[tex]P(1) = 2[/tex]
Required
The solution
We have:
[tex]\frac{dP}{dt} = \sqrt{Pt[/tex]
[tex]\frac{dP}{dt} = (Pt)^\frac{1}{2}[/tex]
Split
[tex]\frac{dP}{dt} = P^\frac{1}{2} * t^\frac{1}{2}[/tex]
Divide both sides by [tex]P^\frac{1}{2}[/tex]
[tex]\frac{dP}{ P^\frac{1}{2}*dt} = t^\frac{1}{2}[/tex]
Multiply both sides by dt
[tex]\frac{dP}{ P^\frac{1}{2}} = t^\frac{1}{2} \cdot dt[/tex]
Integrate
[tex]\int \frac{dP}{ P^\frac{1}{2}} = \int t^\frac{1}{2} \cdot dt[/tex]
Rewrite as:
[tex]\int dP \cdot P^\frac{-1}{2} = \int t^\frac{1}{2} \cdot dt[/tex]
Integrate the left hand side
[tex]\frac{P^{\frac{-1}{2}+1}}{\frac{-1}{2}+1} = \int t^\frac{1}{2} \cdot dt[/tex]
[tex]\frac{P^{\frac{-1}{2}+1}}{\frac{1}{2}} = \int t^\frac{1}{2} \cdot dt[/tex]
[tex]2P^{\frac{1}{2}} = \int t^\frac{1}{2} \cdot dt[/tex]
Integrate the right hand side
[tex]2P^{\frac{1}{2}} = \frac{t^{\frac{1}{2} +1 }}{\frac{1}{2} +1 } + c[/tex]
[tex]2P^{\frac{1}{2}} = \frac{t^{\frac{3}{2}}}{\frac{3}{2} } + c[/tex]
[tex]2P^{\frac{1}{2}} = \frac{2}{3}t^\frac{3}{2} + c[/tex] ---- (1)
To solve for c, we first make c the subject
[tex]c = 2P^{\frac{1}{2}} - \frac{2}{3}t^\frac{3}{2}[/tex]
[tex]P(1) = 2[/tex] means
[tex]t = 1; P =2[/tex]
So:
[tex]c = 2*2^{\frac{1}{2}} - \frac{2}{3}*1^\frac{3}{2}[/tex]
[tex]c = 2*2^{\frac{1}{2}} - \frac{2}{3}*1[/tex]
[tex]c = 2\sqrt 2 - \frac{2}{3}[/tex]
So, we have:
[tex]2P^{\frac{1}{2}} = \frac{2}{3}t^\frac{3}{2} + c[/tex]
[tex]2P^{\frac{1}{2}} = \frac{2}{3}t^\frac{3}{2} + 2\sqrt 2 - \frac{2}{3}[/tex]
Divide through by 2
[tex]P^{\frac{1}{2}} = \frac{1}{3}t^\frac{3}{2} + \sqrt 2 - \frac{1}{3}[/tex]
Square both sides
[tex]P = (\frac{1}{3}t^\frac{3}{2} + \sqrt 2 - \frac{1}{3})^2[/tex]
What is the area of 4cm×7cm×8cm
Answer:
[tex]224cm^3\\[/tex]
Step-by-step explanation:
[tex]4cm*7cm*8cm=[/tex]
[tex]=224cm^3[/tex]
Hope this is helpful.
LWH=A
Plug in the numbers:
4*7*8=224^2
The area would be 224cm^2.
Determine which statements about the relationship are true. Choose two options. g is the dependent variable. u is the dependent variable. g is the independent variable. u is the independent variable. The two variables cannot be labeled as independent or dependent without a table of values.
Answer:
1) g is the dependent variable.(A)
2) u is the independent variable.(D)
Step-by-step explanation:
Can someone help me with me? Thanks!
Answer:
(0.38, 4.79)
Step-by-step explanation:
Use cross products to identify the equation needed to solve this proportion:
5
x
=
2
9
Answer:
x=22.5
Step-by-step explanation:
We are given the proportion:
5/x=2/9
Cross multiply. Multiply the numerator (top number) of the first fraction by the denominator (bottom number) of the second. Then multiply the denominator of the first by the numerator of the second.
5*9=2*x
45=2x
2 and x are being multiplied. The opposite of multiplication is division. Divide both sides by 2. This will cancel out the 2 being multiplied by x, and leave x by itself.
45/2=2x/2
45/2=x
22.5=x
If we substitute 22.5 in for x, the final proportion will be:
5/22.5=2/9
-8(9r - 1) - 9(-8r+2)
Simplest form
Answer:
-10
Step-by-step explanation:
Step-by-step explanation:
-8(9r-1)-9(-8r+2)-72r+8-72r-18-72r-72r+8-18-144r-10-(144r+10)hope it helps
stay safe healthy and happy...Can someone help me please!!
Determine the value of the missing letters in the sum of numbers
below:
ab1
+ ba
abb
49x
Answer:
a=2, b=3,x=6
Step-by-step explanation:
We are given that
We have to find the value of the missing letters in the sum of numbers.
From given sum
1+a+b=x ....(1)
b+b+b=9 .....(2)
a+a=4 ......(3)
From equation (2) we get
[tex]3b=9[/tex]
[tex]\implies b=3[/tex]
From equation (3) we get
[tex]2a=4[/tex]
[tex]a=4/2[/tex]
[tex]a=2[/tex]
Now, substitute the values in equation (1) we get
[tex]1+2+3=x[/tex]
[tex]x=6[/tex]
Therefore,
231+32+233=496
Find the values of X and Y that makes these triangles congruent by the HL theorem
Answer:
C. x = 3, y = 2
Step-by-step explanation:
If both triangles are congruent by the HL Theorem, then their hypotenuse and a corresponding leg would be equal to each other.
Thus:
x + 3 = 3y (eqn. 1) => equal hypotenuse
Also,
x = y + 1 (eqn. 2) => equal legs
✔️Substitute x = y + 1 into eqn. 1 to find y.
x + 3 = 3y (eqn. 1)
(y + 1) + 3 = 3y
y + 1 + 3 = 3y
y + 4 = 3y
y + 4 - y = 3y - y
4 = 2y
Divide both sides by 2
4/2 = 2y/2
2 = y
y = 2
✔️ Substitute y = 2 into eqn. 2 to find x.
x = y + 1 (eqn. 2)
x = 2 + 1
x = 3
find the equation of the line shown
Answer:
y=1/2x+1/2
Step-by-step explanation:
In order to find the slope, you can use rise/run, in this case, the slope is 1/2 and the y-intercept is at (0, 0.5)
the focus of a parabola is (-5,-1) and the directrix is y= -3.
what is an equation of the parabola? (one of the answered above)
Answer:
Step-by-step explanation:
-2
An 80% confidence interval is (150, 170). What is the margin of error?
Answer:
10
Step-by-step explanation:
it is what it is
what is 221st number out of 5,6,7,8,9
Answer:
221
Step-by-step explanation:
Given sequence is ,
> 5 , 6 , 7 , 8 , 9.
The common difference is 6-5 = 1 .
Therefore , the 221st number will be
> 221 st term = 221 × 1 = 221 .
Hence the 221 st term is 221 .
Answer:
225
Step-by-step explanation:
d = 6 - 5 = 1 (common differences)
a = 5 (first term)
221st term
a+(n-1)d
5 +(221 - 1) 1
5 + 220 =225
Therefore the answer is 225
Which formula can be used to describe the sequence?
O f(x + 1) = f(x)
O f(x + 1) = - f(x)
O f(x) = f(x + 1)
O f(x) = - 3 f(x + 1)
Answer:
f(x+1) = -3/4 × f(x)
Step-by-step explanation:
first of all, the sign of the numbers in the sequence is alternating. so, there must be a "-" involved.
that eliminates the first and third answer options.
and the absolute values of the numbers in the sequence are going down. |f(x+1)| < |f(x)|
that eliminates the fourth answer option, as this says that
|f(x)| < |f(x+1)|. and that is the opposite of how the actual sequence behaves.
NEED HELP
The average amount of money spent for lunch per person in the college cafeteria is $6.75 and the standard deviation is $2.28. Suppose that 18 randomly selected lunch patrons are observed. Assume the distribution of money spent is normal, and round all answers to 4 decimal places where possible.
C. For a single randomly selected lunch patron, find the probability that this
patron's lunch cost is between $7.0039 and $7.8026.
D. For the group of 18 patrons, find the probability that the average lunch cost is between $7.0039 and $7.8026.
Answer:
C.[tex]P(7.0039<x<7.8026)=0.1334[/tex]
D.[tex]P(7.0039<\bar{x}<7.8026)\approx 0.2942[/tex]
Step-by-step explanation:
We are given that
n=18
Mean, [tex]\mu=6.75[/tex]
Standard deviation, [tex]\sigma=2.28[/tex]
c.
[tex]P(7.0039<x<7.8026)=P(\frac{7.0039-6.75}{2.28}<\frac{x-\mu}{\sigma}<\frac{7.8026-6.75}{2.28})[/tex]
[tex]P(7.0039<x<7.8026)=P(0.11<Z<0.46)[/tex]
[tex]P(a<z<b)=P(z<b)-P(z<a)[/tex]
Using the formula
[tex]P(7.0039<x<7.8026)=P(Z<0.46)-P(Z<0.11)[/tex]
[tex]P(7.0039<x<7.8026)=0.67724-0.54380[/tex]
[tex]P(7.0039<x<7.8026)=0.1334[/tex]
D.[tex]P(7.0039<\bar{x}<7.8026)=P(\frac{7.0039-6.75}{2.28/\sqrt{18}}<\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}})<\frac{7.8026-6.75}{2.28/\sqrt{18}})[/tex]
[tex]P(7.0039<\bar{x}<7.8026)=P(0.47<Z<1.96)[/tex]
[tex]P(7.0039<\bar{x}<7.8026)=P(Z<1.96)-P(Z<0.47)[/tex]
[tex]P(7.0039<\bar{x}<7.8026)=0.97500-0.68082[/tex]
[tex]P(7.0039<\bar{x}<7.8026)=0.29418\approx 0.2942[/tex]
What is the value of x in the diagram below? If necessary, round your answer
to the nearest tenth of a unit.
9514 1404 393
Answer:
A. 7.2
Step-by-step explanation:
In this geometry, all of the right triangles are similar. This means corresponding sides have the same ratio.
short side/hypotenuse = x/12 = 12/20
Multiplying by 12 gives ...
x = 12(12/20) = 144/20
x = 7.2
Find the area of the rectangle shown.
914
323
323
914
The solution is
Answer: The answer is 295,222.
Step-by-step explanation: The area of a rectangle is base times height, which is 914 x 323. If you do the math correctly, you will get 295,222.
[tex] \huge\boxed{\mathfrak{Answer}}[/tex]
Length (l) = 914 units
Breadth (b) = 323 units
Area = ?
Area of a rectangle (a) = l × b ----> use this formula
[tex]a = l \times b \\ a = 914 \times 323 \\ a = 295222 \: \: sq.units[/tex]
=> The area of the rectangle is 295222 sq.units.
Jose bought a piece of fabric that was 5.6 meters long. From that, he cut 0.4
meter. How much fabric is left?
Answer:
Jose has 5.2 meters of fabric left.
Step-by-step explanation:
5.6 - 0.4 = 5.2
Candice is preparing for her final exam in Statistics. She knows she needs an 74 out of 100 to earn an A overall in the course. Her instructor provided the following information to the students. On the final, 200 students have taken it with a mean score of 68 and a standard deviation of 4. Assume the distribution of scores is bell-shaped. Calculate to see if a score of 74 is within one standard deviation of the mean.
a) Yes, 74 is the upper limit of one standard deviation from the mean.
b) Yes, the upper level of one standard deviation is 72.
c) Yes, 74 is greater than the 64, one standard deviation below the mean.
d) No, 74 is greater than the mean of 68.
Answer:
Hence the correct option is option b) Yes, the upper level of one standard deviation is 72.
A score of 74 is not within one standard deviation of the mean.
Step-by-step explanation:
Here the given details are,
Mean = 68
SD = 4
Distribution is normal.
Z-score for x = 74 is given as below:
[tex]Z = (X - mean)/SD\\Z = (74 - 68)/4\\Z = 1.5[/tex]
So, the score of 74 is 1.5 standard deviations from the mean.
[tex]Mean + 1\timesSD = 68 + 1\times4 = 72Mean - 1\timesSD = 68 - 1\times4 = 64[/tex]
Therefore the score is not lies between 64 and 72.
Yes, the upper level of one standard deviation is 72.
21. The mean salary of twelve men is $58,000, and the
mean salary of eight women is $42,000. Find the
mean salary of all twenty people.
-32=?
it told me to write atlest 20 words so ignore this
Answer:
I don't think it's possible.
testing for a disease can be made more efficient by combining samples. If the samples from two people are combined and the mixture tests negative, then both samples are negative. On the other hand, one positive sample will always test positive, no matter how many negative samples it is mixed with. Assuming the probability of a single sample testing positive is 0.15, find the probability of a positive result for two samples combined into one mixture. Is the probability low enough so that further testing of the individual samples is rarely necessary?w./search?q=%E2%80%8B"At+least%E2%80%8B+one"+is+equivalent+to%E2%80%8B+_______.&oq=%E2%80%8B"At+least%E2%80%8B+one"+is+equivalent+to%E2%80%8B+_______.&aqs=chrome..69i57j0i22i30l3.409j0j4&sourceid=chrome&ie=UTF-8 The probability of a positive test result is nothing
Answer:
(a) [tex]P(Two\ Positive) = 0.2775[/tex]
(b) It is not too low
Step-by-step explanation:
Given
[tex]P(Single\ Positive) = 0.15[/tex]
[tex]n = 2[/tex]
Solving (a):
[tex]P(Two\ Positive)[/tex]
First, calculate the probability of single negative
[tex]P(Single\ Negative) =1 - P(Single\ Positive)[/tex] --- complement rule
[tex]P(Single\ Negative) =1 - 0.15[/tex]
[tex]P(Single\ Negative) =0.85[/tex]
The probability that two combined tests are negative is:
[tex]P(Two\ Negative) = P(Single\ Negative) *P(Single\ Negative)[/tex]
[tex]P(Two\ Negative) = 0.85 * 0.85[/tex]
[tex]P(Two\ Negative) = 0.7225[/tex]
Using the complement rule, we have:
[tex]P(Two\ Positive) = 1 - P(Two\ Negative)[/tex]
So, we have:
[tex]P(Two\ Positive) = 1 - 0.7225[/tex]
[tex]P(Two\ Positive) = 0.2775[/tex]
Solving (b): Is (a) low enough?
Generally, when a probability is less than or equal to 0.05; such probabilities are extremely not likely to occur
By comparison:
[tex]0.2775 > 0.05[/tex]
Hence, it is not too low
Eight less than four times a number is less than 56. What are the possible values of that number?
X> 12
x < 12
ООО
x < 16
O x> 16
Answer:
x < 16
Step-by-step explanation:
Let the number be x
Four time the number = 4x
Eight less than four times the number = 4x - 8
Eight less than four times the number is less than 56,
that is , 4x - 8 < 56
4x - 8 + 8 < 56 + 8 [ adding both sides by 8 ]
4x + 0 < 64
4x < 64 [ divide both sides by 4 ]
x < 16
A study of the pay of corporate chief executive officers (CEOs) examined the increase in cash compensation of the CEOs of 104 companies, adjusted for inflation, in a recent year. The mean increase in real compensation was x¯=6.9%, and the standard deviation of the increases was s=55%. Is this good evidence that the mean real compensation μ of all CEOs increased that year? The hypotheses are
Answer:
The p-value of the test is 0.1017, which is greater than the standard significance level of 0.05, which means that this is not good evidence that the mean real compensation μ of all CEOs increased that year.
Step-by-step explanation:
At the null hypothesis, we test if there was no increase, that is, the mean is 0, so:
[tex]H_0: \mu = 0[/tex]
At the alternative hypothesis, we test if there was an increase, that is, the mean is greater than 0, so:
[tex]H_1: \mu > 0[/tex]
The test statistic is:
[tex]t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}[/tex]
In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.
0 is tested at the null hypothesis:
This means that [tex]\mu = 0[/tex]
104 companies, adjusted for inflation, in a recent year. The mean increase in real compensation was x¯=6.9%, and the standard deviation of the increases was s=55%.
This means that [tex]n = 104, X = 6.9, s = 55[/tex]
Value of the test-statistic:
[tex]t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}[/tex]
[tex]t = \frac{6.9 - 0}{\frac{55}{\sqrt{104}}}[/tex]
[tex]t = 1.28[/tex]
P-value of the test:
The p-value of the test is a right-tailed test(test if the mean is greater than a value), with 104 - 1 = 103 df and t = 1.28.
Using a t-distribution calculator, this p-value is of 0.1017.
The p-value of the test is 0.1017, which is greater than the standard significance level of 0.05, which means that this is not good evidence that the mean real compensation μ of all CEOs increased that year.
Find out the quotient
-72 ÷ (-2) = ?
-72 ÷ 2 = ?
72 ÷ (-2) = ?
(Thank you to whoever helps me out )
Answer/Step-by-step explanation:
✔️-72 ÷ (-2)
The division of two negative numbers will give us a positive number. i.e. - ÷ - = +
Therefore:
-72 ÷ (-2) = 36
✔️-72 ÷ 2
The division of a negative number and a positive number will give us a negative number. i.e. - ÷ + = -
Therefore:
-72 ÷ 2 = -36
✔️72 ÷ (-2)
The division of a positive number and a negative number will give us a negative number. i.e. + ÷ - = -
Therefore:
72 ÷ (-2) = -36
If f(x) = 3X + 10x and g(x) = 4x - 2, find (f+g)(x).
O A. 17x - 2
O B. 3* + 6x + 2
O C. 3* - 6x + 2
D. 3X + 14x-2
help!!!
Let T be the event that an adult admits to texting while driving and N be the event an adult does not admit to texting while driving. We previously determined
P(T) = 0.61
and
P(N) = 0.39.
Since three adults are chosen randomly, we have the following simple events.
TTT TTN TNT NTT TNN NTN NNT NNN
The adults were randomly selected, indicating these can be seen as independent events. Therefore, the multiplication rule can be used. Recall the multiplication rule states that for independent events, the probability that they all occur is the product of their respective probabilities. Let x be the number of adults who admit to texting while driving. Since three adults are randomly selected, then x can take on the values 0, 1, 2, or 3.
When x = 0, then no adult in the group of three admits to texting while driving. This corresponds to the simple event NNN whose probability is calculated as below.
P(x = 0) = P(NNN)
= P(N)P(N)P(N)
= 0.39(0.39)(0.39)
=
When x = 1, then only one adult in the group admits to texting while driving. This corresponds to the simple events TNN, NTN, and NNT. First, calculate the probability of each simple event by multiplying the individual probabilities. Then sum the three simple events to find
P(x = 1).
Calculate
P(x = 1).
P(x = 1) = P(TNN) + P(NTN) + P(NNT)
= P(T)P(N)P(N) + P(N)P(T)P(N) + P(N)P(N)P(T)
= 0.61(0.39)(0.39) + 0.39(0.61)(0.39) + 0.39(0.39)(0.61)
=
Find the remaining probabilities
P(x = 2)
and
P(x = 3).
P(x = 2) = P(TTN) + P(TNT) + P(NTT)
= P(T)P(T)P(N) + P(T)P(N)P(T) + P(N)P(T)P(T)
= 0.61(0.61)(0.39) + 0.61(0.39)(0.61) + 0.39(0.61)(0.61)
=
P(x = 3) = P(TTT)
= P(T)P(T)P(T)
= 0.61(0.61)(0.61)
=
Answer:
Step-by-step explanation:
X P(X=x)
0 0.39*0.39*0.39 = 0.059319
1 3*0.61*0.39*0.39 = 0.278343
2 3*0.61*0.61*0.39 = 0.435357
3 0.61*0.61*0.61 = 0.226981
Solve the equation for x.
2/3x-1/9x+5=20
Answer:
x = 27
Step-by-step explanation:
I'm assuming the equation looks like this:
[tex]\frac{2}{3}x-\frac{1}{9}x+5=20[/tex]
Here's how to solve for x:
[tex]\frac{2}{3}x-\frac{1}{9}x+5=20[/tex]
(subtract 5 from both sides)
[tex]\frac{2}{3}x-\frac{1}{9}x=15[/tex]
(Find the GCF of 3 and 9, which is 3. Multiply 2/3 by 3/3. You get 6/9)
[tex]\frac{6}{9}x-\frac{1}{9}x=15[/tex]
(add like terms)
[tex]\frac{5}{9}x=15[/tex]
(multiply 9/5 to both sides, which is the same as dividing both sides by 5/9)
x = 27
Hope it helps (●'◡'●)
Which angle is the vertical angle toBEC
Answer:
∠AED
Step-by-step explanation:
Vertical angles are the opposite angles of intersecting lines. ∠BEC and ∠AED are opposite and would therefore also be congruent angles.
Answer:
[tex]\angle BEC=\angle AED [vertical ~angle][/tex]
[tex]\angle AED~vertical~ angle ~to~ \angle BEC[/tex]
[tex]ANSWER:\angle AED[/tex]
-----------------------------
hope it helps...
have a great day!!
please help me i begging.
Answer:
The two equivalent expressions are 6(x − y) and 6x − 6y.
Step-by-step explanation:
The equation y - 5 = 6X + 1 is written as point-slope form. What is the equation written in slope intercept form
Answer:
y = 6x + 6
Step-by-step explanation:
The general formula is y = mx +cso; the y as seen will be constant as well as the x
With change of subject the 5 will be moved to the other side having y= 6x +1 + 5 .Given us y = 6x + 6.