Answer:
[tex]2^{3}[/tex]×5×3×[tex]x^{2}[/tex]×[tex]y^{4}[/tex]
Step-by-step explanation:
[tex]8xy^{4}[/tex]= [tex]2^{3}[/tex]×[tex]x[/tex]×[tex]y^{4}[/tex]
6[tex]x^{2} y[/tex]= 2×3×[tex]x^{2}[/tex]×[tex]y^{}[/tex]
10[tex]x^{2} y^{2}[/tex] = 2×5×[tex]x^{2}[/tex]×[tex]y^{2}[/tex]
[tex]2^{3}[/tex]×5×3×[tex]x^{2}[/tex]×[tex]y^{4}[/tex]
What is the circumference of D if the length of EF is 9 cm?
Answer:
It should be B, 180 cm
Step-by-step explanation:
x = circumference of circle D
18/360 = 9/x
9*360 = 18x
9*360/18 = x
x = 180
Find all solutions to the equation
in the interval [0, 21). Enter the
solutions in increasing order.
sin 2x = 2 sin x
x = [?],[1]
TT
Remember: sin 20 = 2 sin 0 cos 0
Answer:
[tex]x=0, \\x=\pi[/tex]
Step-by-step explanation:
Recall the trigonometric identity [tex]\sin 2x=2\sin x\cos x[/tex].
Therefore, given [tex]\sin 2x=2\sin x[/tex], rewrite the left side of the equation:
[tex]2\sin x\cos x=2\sin x[/tex]
Subtract [tex]\sin x[/tex] from both sides:
[tex]2\sin x\cos x-2\sin x=0[/tex]
Factor out [tex]2\sin x[/tex] from both terms on the left:
[tex]2\sin x(\cos x-1)=0[/tex]
We now have two cases:
[tex]\begin{cases}2\sin x=0, x=k\pi\text{ for }k\in \mathbb{Z}\\\cos x-1=0,x=k2\pi\text{ for }k\in \mathbb{Z}\end{cases}[/tex]
Since the problem stipulates that [tex]x[/tex] is in the interval [tex][0, 2\pi)[/tex], we have:
[tex]\text{For }x\in [0, 2\pi):\\\sin x=0\rightarrow \boxed{x=0, x=\pi}\\\cos x-1=0\rightarrow \boxed{x=0}[/tex]
Recall that square brackets mean inclusive and parentheses mean exclusive. Therefore, [tex]2\pi \notin [0, 2\pi)[/tex].
given the figure below, what is the value of x?
Answer:
x = 6
Step-by-step explanation:
6 is x so this is the answer
When two parallel lines are cut by a transversal then the interior angles on the same side of the transversal are
Answer:
Same side interior angles
Step-by-step explanation:
Same side interior angles are interior angles and on the same side. Sorry don't know how to better explain.
3. The following are the scores you shot in five rounds of golf: 70,80,75,75,80. The variance is: A. 3.74 C. 14 B. 196 D. 70
Answer:
Option C.
Step-by-step explanation:
For a given set of N elements:
{x₁, x₂, ..., xₙ}
The mean is given by:
[tex]M = \frac{x_1 + x_2 + ... + x_n}{N}[/tex]
And the variance is given by:
[tex]v = \frac{(x_1 - M)^2 + (x_2 - M)^2 + ... + (x_n - M)^2}{N}[/tex]
Then for our set:
{70, 80 ,75, 75, 80}
We have 5 elements, then N = 5
The first thing we need to find is the mean.
[tex]M = \frac{70 + 80 + 75 + 75 + 80}{5} = 76[/tex]
Then the variance will be:
[tex]v = \frac{(70 - 76)^2 + (80 - 76)^2 + (75 - 76)^2 + (75 - 76)^2 + (80 - 76)^2}{5} = 14[/tex]
The correct option is C, 14.
The owner of a coffee shop compared the amount of hot coffee per day, in fluid ounces, sold and the daily high temp. In degrees f per day, 5.9x+850=
The question is not complete as the scatter plot is missing.
Thus, I have attached the complete question showing the scatter plot.
Answer:
D: On a day with a high temperature of 0°C, the shop can expect to sell about 850 fluid ounces of hot coffee
Step-by-step explanation:
From the attached image showing the question and scatter plot, we can see that the scatter plot is modeled by the line; y = -5.9x + 850
Where;
x is the high temperature in °F
y is the amount of fluid ounces sold
Let's try x = 0°F
Thus;
y = 0 + 850
y = 850 fluid ounces
Let's try x = 10°F
Thus;
y = -5.9(10) + 850
y = 850 - 59
y = 791
This means for every increase in temperature of 10°F, the amount sold is approximately 60 fluid ounces lesser.
Looking at the options in the attached file, the only correct one that corresponds to our answer is option D where it says;. On a day with a high temperature of 0°C, the shop can expect to sell about 850 fluid ounces of hot coffee
solve the problems. write the complete proof in your paper homework and for online (only) complete the probing statement (if any) that is a part of your proof or related to it
Answer:
[tex]m \angle A = m \angle C[/tex] by reason [tex]\overline{AB} \cong \overline{BC}[/tex] and [tex]m \angle B = m \angle M = m \angle P[/tex].
[tex]\triangle AMO \cong \triangle CPO[/tex] SAS Theorem
Step-by-step explanation:
We proceed to demonstrate the statement by Geometric means:
1) [tex]\overline{AB} \cong \overline{BC}[/tex], [tex]\overline {AM} \cong \overline {PC}[/tex], [tex]m\angle AMO = m\angle CPO[/tex] Given.
2) [tex]\frac{AM}{AB} = \frac{PC}{BC}[/tex] Proportionality.
3) [tex]\frac{AM}{AM + MB} = \frac{PC}{BP + PC}[/tex] Definition of line segments.
4) [tex]\frac{1}{1+\frac{MB}{AM} } = \frac{1}{\frac{BP}{PC}+1}[/tex] Algebra.
5) [tex]\frac{BP}{PC} + 1 = 1 +\frac{MB}{AM}[/tex] Algebra.
6) [tex]\frac{BP}{PC} = \frac{MB}{AM}[/tex] Algebra.
7) [tex]BP = BM[/tex] By 1)
8) [tex]m \angle B = m \angle M = m \angle P[/tex] By 1), 7)
9) [tex]\triangle AMO \sim \triangle ABC[/tex], [tex]\triangle CPO \sim \triangle ABC[/tex] By 1), 7), 8). Defintion of simmilarity.
10) [tex]\frac{AM}{MO} = \frac{AB}{BC}[/tex], [tex]\frac{PO}{PC} = \frac{AB}{BC}[/tex] Definition of proportionality.
11) [tex]\frac{AM}{MO} = \frac{PO}{PC}[/tex] Algebra.
12) [tex]AM^{2} = PO\cdot MO[/tex] Algebra.
13) [tex]PO = MO[/tex] By 12) and Algebra.
14) [tex]\overline{PO} \cong \overline{MO}[/tex] By 13).
15) [tex]\triangle AMO \cong \triangle CPO[/tex] SAS Theorem/Result.
Solve for congruent triangles
Answer:
11. B.
12. C.
13. A.
14. D.
Step-by-step explanation:
for 11: we know that angles D and J are congruent from the tick marks, we also know that ∠FKD and ∠LKJ are congruent (vertical angles are congruent) therefore we need the sides between them
for 12: we know that ∠STU and ∠TUG are congruent, we also know that line TU is congruent to TU (reflexive property), therefore we need the angles adjacent to the first angles listed.
for 13: we know that ∠PQR and ∠CQR are congruent, we also know that lines RQ and RQ are congruent (reflexive property), therefore we need the other angles to which line RQ is between.
for 14: we know ∠B is congruent to ∠T and line AB is congruent to line ZY. therefore the angle cannot be connected to lines AB and ZY.
Solve for x. Round to the nearest tenth of a degree, if necessary
Answer:
31.80°
Step-by-step explanation:
In ∆ ABC :-
sin x = BC / AC sin x = 39/74 x = sin -¹ ( 39/74) x = 31.80 °What is the value of p?
A)180
B)90
C) 116
D)58
Can someone help I don’t understand
Answer:
58
Step-by-step explanation:
Helppp and explain !!!!
Answer:
try 4
Step-by-step explanation:
basically need to find number that when multiplied 3 times equals 64 so 4*4*4=64
Beth wants to build a thin wire frame for a photo that is $$15 cm long and $$6 cm wide. What length of wire will she need to go around the entire photo?
Answer:
42
Step-by-step explanation:
1. PerimeterPerimeter is [tex]2l+2w[/tex]
2. Solving[tex]2(15)+2(6)=30+12=42[/tex]Answer: 42
Hope this helped! Please mark brainliest :)
At maximum speed, an airplane travels
1680 miles against the wind in 5 hours.
Flying with the wind. the plane can
travel the same distance in 4 hours.
What is the speed of the plane with no wind?
Answer:
The speed of the plane with no wind is 378 miles per hour.
Step-by-step explanation:
Since at maximum speed, an airplane travels 1680 miles against the wind in 5 hours, and flying with the wind. the plane can travel the same distance in 4 hours, to determine what is the speed of the plane with no wind, the following calculation must be performed:
Against the wind = 1680/5 = 336
With the wind = 1680/4 = 420
420 - ((420 - 336) / 2) = X
420 - 42 = X
378 = X
Therefore, the speed of the plane with no wind is 378 miles per hour.
Can someone please help me. If you do thanks
Answer:
(B)
Step-by-step explanation:
Can't explain lol, but that's the answer
hamood spelled backwards is hamood also let me know if u want my account by 12 AM PDT 6/2/21
Answer:
yo congratulations on finishing 10th grade (congratulate me on finishing 8th)
hamood spelled backwards is doomah so...um...
also do u mean 7/2/21..bc 6/2/21 is like in June and we're in July
What is the midpoint of the segment shown below?
Step-by-step explanation:
simply take the average of the x and y coordinates
What is the standard form equation of the line shown below? Graph of a line going through negative 1, 5 and 2, 4
Answer:
y = -1/3x + 14/3
Step-by-step explanation:
We have the standard equation as;
y = mx + b
where m is the slope and b is the y-intercept
the given points are;
(-1,5) and (2,4)
So we plug x and y for each of the points
then we create two linear equations which we can solve simultaneously to get the values of m and b
From the points;
5 = -m + b•••••••(i)
4 = 2m + b
from i;
b = 5 + m
substitute this into equation ii
4 = 2m + 5 + m
4 = 3m + 5
4-5 = 3m
3m = -1
m = -1/3
Recall;
b = 5 + m
b = 5-1/3
b = 14/3
so we have the equation as;
y = -1/3x + 14/3
Multiply through by 3
3y = -x + 14
What is the first step in solving the equation x2 - 25 = 0?
What is the second step in solving the equation?
Answer:
first step - make x² the subject of the formula
x² = 25
second step :
find the square root of both sides
√x² = √25
x = 5
Step-by-step explanation:
what is the sum of all the exterior angle of a polygon
Answer:
From what I learn it is 360 degrees
Find the value of x that will make A||B.
Please help!
Answer:
x=30
Step-by-step explanation:
Hi there!
For A to be parallel to B, 5x would be equal to 3x+60. (If they were parallel, these two angles would be alternate exterior angles, which are equal.)
[tex]5x=3x+60[/tex]
Subtract 3x from both sides
[tex]5x-3x=3x+60-3x\\2x=60[/tex]
Divide both sides by 2
[tex]x=30[/tex]
I hope this helps!
The area (A) of a circle is a function of its radius (r) and is given by the function A=f(r)=pie r^2. What is the domain of this function
A. All positive real numbers
B. All real numbers
C. All positive real numbers including 0
D. All real numbers excluding fraction
What should the follow equations is equivalent to 6.87p+9.2=-7.056
Answer:
P=-2.3662299854
Step-by-step explanation:
6.87p = - 7.056 -9.2
So 6.87p= - 16.256
P=-2.3662299854
Darryl is finding the product of -5y(-4y^3+6y^2-5) Is he correct? If not, what changes should be made?
Describe the steps required to determine the equation of a quadratic function given its zeros and a point.
Answer:
Procedure:
1) Form a system of 3 linear equations based on the two zeroes and a point.
2) Solve the resulting system by analytical methods.
3) Substitute all coefficients.
Step-by-step explanation:
A quadratic function is a polynomial of the form:
[tex]y = a\cdot x^{2}+b\cdot x + c[/tex] (1)
Where:
[tex]x[/tex] - Independent variable.
[tex]y[/tex] - Dependent variable.
[tex]a[/tex], [tex]b[/tex], [tex]c[/tex] - Coefficients.
A value of [tex]x[/tex] is a zero of the quadratic function if and only if [tex]y = 0[/tex]. By Fundamental Theorem of Algebra, quadratic functions with real coefficients may have two real solutions. We know the following three points: [tex]A(x,y) = (r_{1}, 0)[/tex], [tex]B(x,y) = (r_{2},0)[/tex] and [tex]C(x,y) = (x,y)[/tex]
Based on such information, we form the following system of linear equations:
[tex]a\cdot r_{1}^{2}+b\cdot r_{1} + c = 0[/tex] (2)
[tex]a\cdot r_{2}^{2}+b\cdot r_{2} + c = 0[/tex] (3)
[tex]a\cdot x^{2} + b\cdot x + c = y[/tex] (4)
There are several forms of solving the system of equations. We decide to solve for all coefficients by determinants:
[tex]a = \frac{\left|\begin{array}{ccc}0&r_{1}&1\\0&r_{2}&1\\y&x&1\end{array}\right| }{\left|\begin{array}{ccc}r_{1}^{2}&r_{1}&1\\r_{2}^{2}&r_{2}&1\\x^{2}&x&1\end{array}\right| }[/tex]
[tex]a = \frac{y\cdot r_{1}-y\cdot r_{2}}{r_{1}^{2}\cdot r_{2}+r_{2}^{2}\cdot x+x^{2}\cdot r_{1}-x^{2}\cdot r_{2}-r_{2}^{2}\cdot r_{1}-r_{1}^{2}\cdot x}[/tex]
[tex]a = \frac{y\cdot (r_{1}-r_{2})}{r_{1}^{2}\cdot r_{2}+r_{2}^{2}\cdot x +x^{2}\cdot r_{1}-x^{2}\cdot r_{2}-r_{2}^{2}\cdot r_{1}-r_{1}^{2}\cdot x}[/tex]
[tex]b = \frac{\left|\begin{array}{ccc}r_{1}^{2}&0&1\\r_{2}^{2}&0&1\\x^{2}&y&1\end{array}\right| }{\left|\begin{array}{ccc}r_{1}^{2}&r_{1}&1\\r_{2}^{2}&r_{2}&1\\x^{2}&x&1\end{array}\right| }[/tex]
[tex]b = \frac{(r_{2}^{2}-r_{1}^{2})\cdot y}{r_{1}^{2}\cdot r_{2}+r_{2}^{2}\cdot x +x^{2}\cdot r_{1}-x^{2}\cdot r_{2}-r_{2}^{2}\cdot r_{1}-r_{1}^{2}\cdot x}[/tex]
[tex]c = \frac{\left|\begin{array}{ccc}r_{1}^{2}&r_{1}&0\\r_{2}^{2}&r_{2}&0\\x^{2}&x&y\end{array}\right| }{\left|\begin{array}{ccc}r_{1}^{2}&r_{1}&1\\r_{2}^{2}&r_{2}&1\\x^{2}&x&1\end{array}\right| }[/tex]
[tex]c = \frac{(r_{1}^{2}\cdot r_{2}-r_{2}^{2}\cdot r_{1})\cdot y}{r_{1}^{2}\cdot r_{2}+r_{2}^{2}\cdot x + x^{2}\cdot r_{1}-x^{2}\cdot r_{2}-r_{2}^{2}\cdot r_{1}-r_{1}^{2}\cdot x}[/tex]
And finally we obtain the equation of the quadratic function given two zeroes and a point.
A circular sheet covers 425cm on the table,find the area of the sheet.
solve this question plz.
Answer:
sorry i cannot help you
the lines given by the equations y=6x and y=6x+2 are ____
They are parallel, as shown by the graph.
7 of 8
Write the number three million and eighty-two thousand in figures
Answer:
3,082,000
Step-by-step explanation:
THE ANSWER IS 3,082,000 HOPE IT HELPS
Pls answer 13 b ill mark u brainlist
Answer:
7 students
Step-by-step explanation:
1+2+4=7students
question 3 help pls in algebra
Answer:
50
Step-by-step explanation:
simplify the radical by breaking the redicand up into a product of known factors, assuming positive real numbers.
Arturo is building a flower bed in the shape of a right triangle. The hypotenuse of the right triangle is 13 feet. One of the legs needs to be 7 feet longer than the other leg.
Which equation can be used to find x, the length of the shorter leg?
x(x + 7) = 13
x(x + 7) = 169
x2 + (x + 7)2 = 13
x2 + (x + 7)2 = 169
Answer:
x(x + 7) = 169
Step-by-step explanation:
We are given that
Let length of shorter leg of right triangle = x ft
Length of other leg = x+7 ft
Hypotenuse of right triangle = 13 ft
We have to find the equation which can be used to find x, the length of shorter leg.
By pythagorous theorem
(Hypotenuse)^2=(Base)^2+(Perpendicular\;side)^2
Substitute the values then, we get
(13)^2=x^2+(x+7)^2
x^2+(x+7)^2=169
This is required equation which can used to find x.
Answer:
d. x2 + (x + 7)2 = 169
Step-by-step explanation:
use Pythagorean theorem, substitute in the given values, and you get this