Block A has mass of mA = 58kg and rests on a flat surface. The coefficient of static friction between the block and the surface is 0.300. The coefficient of static friction between the rop and the fixed peg B is 0.310. The width of the block is d = 0.290m. Find the greatest mass, mC, that weight C can have such that block A does not move.​

Answer:

10.80 mm

Explanation:

Given that the reading of the fixed scale is : 10.5 mm

The thimble scale specifies : 0.30 mm

The micrometer reading will be : 10.5 + 0.30 =10.80 mm

Answer:

Technician B says that the reading is determined by where a dial points on a scale.

Explanation:

A refractometer is a devise used by scientists to gauge a liquids index of refraction.

The refractive index of a liquid is the ratio of light velocity of a specific wavelength in air to its velocity in the substance in evaluation.

The steps of reading a measurement are;

Answer:

Explanation:

Given that:

[tex][\sigma] = \left[\begin{array}{cc}800&300\\ \\300&-400\end{array}\right] (MPa)[/tex]

[tex][\sigma] = \left[\begin{array}{cc}\sigma_{xx}&\sigma_{xy}\\ \\\sigma_{yx}&\sigma_{yy}\end{array}\right][/tex]

Using Determinant method

The principal stress is the maximum or minimum normal stress acting on any plane. For the 2D stress system, the 2-principle plane always carries zero shear stress.

For principal stress [tex]( \sigma_1, \sigma_2)[/tex]

[tex]\sigma_{1,2} = \dfrac{\sigma_x+ \sigma_y}{2} \pm \sqrt{( \dfrac{\sigma_x - \sigma_y}{2} )^2 + \sigma^2_{xy}}[/tex]

[tex]\sigma_{1} = \dfrac{800+(-400)}{2} \pm \sqrt{( \dfrac{800 -(-400)}{2} )^2 + (300)^2}[/tex]

[tex]\sigma_{1} = \dfrac{400}{2} \pm \sqrt{ (600)^2 + (300)^2}[/tex]

[tex]\sigma_{1} = 200+ 670.82 \\ \\ \sigma_{1} = 870.82 \ MPa[/tex]

[tex]\sigma_{2} = \dfrac{800+(-400)}{2} \pm \sqrt{( \dfrac{800 -(-400)}{2} )^2 + (300)^2}[/tex]

[tex]\sigma_{2} = 200- 670.82 \\ \\ \sigma_{1} = - 470.82 \ MPa[/tex]

According to Mohr's circle;

Mohr's circle is the locus provided that the position of the normal stress and the shear stress is acting on any plane.

Center = (a,0)

[tex]a = \dfrac{\sigma_{x}+\sigma_{y}}{2}[/tex]

[tex]a = \dfrac{800+(-400)}{2}[/tex]

a = 200 MPa

radius (r) = [tex]\sqrt{ (\dfrac{\sigma_{x}-\sigma_{y}}{2})^2 + \sigma^2 _{xy}}[/tex]

[tex]=\sqrt{ (\dfrac{800-(-400)}{2})^2 + (300)^2}[/tex]

[tex]=\sqrt{ (600)^2 + (300)^2}[/tex]

r = 670.82 MPa

[tex]\sigma_1 = a +r \\ \\ \sigma_1 = 200 + 670.82 \\ \\ \sigma_1 = 870.82 \ MPa[/tex]

[tex]\sigma_2 =-(r-a)[/tex]      (it is negative because of the negative x-axis)

[tex]\sigma_2 =670.82 - 200 \\ \\ \sigma_1 = 470.82 \ MPa[/tex]    

[tex]\tau_{max} = radius \ of \ Mohr's \ circle[/tex]

[tex]\tau_{max} = 670.82 \ MPa[/tex]

Answer:

1: Attaching a fork and wip eggs/batter/ ect.

2: You can entertain a cat by putting yarn on the gun/drill

3: If you get yarn everywere, you can spin the yarn up on the drill/gun

Explanation:

I hope this helps you out somehow

Answer:

5 rad/sec

0.796 Hz

1.256 seconds

Explanation:

Y(t) = 23sin5t ----1

Y(t) = aSin(w)t----2

w = 5 rad/sec

Then we get the Oscillation frequency from the formula below

w = 2πf

We make f to be the subject of this formula

f = w/2π

f = 5/2*3.24

f = 5/6.28

f = 0.796Hz

From the calculated frequency, we get the period = 1/f

= 1/0.796

= 1.256 seconds

Answer:

He can take the job at the fast food restaurant to make money in order to pursue his career in robotics it doesnt mean he cant pursue it just he needs to make money for it first.

Answer:

true

Explanation:

Answer:

90 degrees

Explanation:

In the case when the sheer stress acts in the one plane of an element so it should be equal and opposite also the shear stress acted on a plan i.e. 90 degrees from the plane

Therefore as per the given situation it should be 90 degrees from the plane

hence, the same is to be considered and relevant too

Answer:

1

Explanation:

Answer:

vom = Volt Ohm Meter

Explanation:

Answer:

1. Cut off region: Vgs < 0.7 volts

2. Linear region: Vgs > 2.5

3. Saturation region: 0.7 < Vgs < 2.5

Explanation:

This question has provided us with these details

Vds = 1.8V

Vt = 0.7V

1. To get The cutoff region

Vgs < Vt

Such that when we put in the value, we have:

Vgs < 0.7 volts

This gives us the cut off region

2. The we get the Linear region using this formula:

Vds < Vgs - Vt

After we put in the values;

1.8V < Vgs - 0.7V

Such that

1.8V + 0.7V < Vgs

2.5V < Vgs

This is therefore the linear region of the transistor when Vgs > 2.5 volts

3. We get The saturation region using

Vgs < Vt and

Vds > Vgs - Vt

When we put in the values we have:

Vgs < 0.7V and

1.8V > Vgs - 0.7V

1.8V+0.7V > Vgs

2.5V > Vgs

Then our saturation region would be

0.7V < Vgs < 2.5 V

Answer:

A. How the driver understands and processes the things his or her eyes receive.

Explanation:

When driving, visual interpretation occurs in two things;

Proper vision is vital while driving. There is the central vison and the peripheral vision. The central vision is what the driver sees in front through the windshield straight ahead. The Peripheral vision is what is seen at the corners of the eyes.

In driving, visual interpretations are important as it entails what the driver sees and A. How the driver understands and processes the things his or her eyes receive.

It's important for drivers to have proper vision when driving. A driver should be able to interpret what the driver sees around him or her passively.

Also, it's important for the drive to be able to understand and processes the things his or her eyes receive. This is vital in order to prevent accidents.

Learn more about driving on:

https://brainly.com/question/24606937

Answer:

A sole proprietorship, also known as the sole trader, individual entrepreneurship or proprietorship, is a type of enterprise that is owned and run by one person and in which there is no legal distinction between the owner and the business entity.

Explanation:

Answer:

A business owned by one people is a-Sole proprietorship

Explanation:

This is correct i did it for my electives class which was career reaserch and decision making.

brainliest?

Answer:

[tex]W = 12.5\ lb/ft^2[/tex] --- in [tex]lb/ft^2[/tex]

[tex]W = 598.503N/m^2[/tex] --- in [tex]N/m^2[/tex]

Explanation:

Given

[tex]Weight=2000lb[/tex]

[tex]Area = 160ft^2[/tex]

Required

Determine the wing loading (W)

Wing loading is calculated using:

[tex]W = \frac{Weight}{Area}[/tex]

Substitute values for Weight and Area

[tex]W = \frac{2000lb}{160ft^2}[/tex]

[tex]W = 12.5\ lb/ft^2[/tex]

The answer can also be converted to N/m^2

[tex]1\ lb = 4.4482216153N[/tex]

[tex]1ft^2 = 0.092903m^2[/tex]

So, we have:

[tex]W = \frac{12.5 * 4.4482216153N}{0.092903m^2}[/tex]

[tex]W = \frac{55.6027701912N}{0.092903m^2}[/tex]

[tex]W = 598.503N/m^2[/tex]

Hence, the wing loading is:

[tex]W = 12.5\ lb/ft^2[/tex] --- in [tex]lb/ft^2[/tex]

[tex]W = 598.503N/m^2[/tex] --- in [tex]N/m^2[/tex]

Answer:

See how many inches are in a foot

measure width and hight of places

Nail grabbing

Explanation:

Answer:

$199.87

Explanation:

Just take $253 times 0.21 to get $53.13. This is how much lower the bill was. Next take 253 - 53.13 to get 199.87, which is the total bill amount for September.

Answer: I'm pretty sure your taking a W.

your getting a W, lucid isn't that bad to trade, you can probably flip lucid for more shiny's and getting a better offer because omen has bad demand and you can tell someone to switch it for something better you can flip lucid and get better pets ok so accept and trade lucid unless you wanna keep it.

Explanation:

Answer:

gg's if you did it cause w

Explanation:

Answer:

1. Vgs<0.7

2. Vgs>2.5

3. 0.7<vgs<2.5

Explanation:

The information below was used to answer to answer this question.

Vds = 1.8V

Vt = 0.7V

1.

The cutoff region

Vgs < Vt

= Vgs < 0.7 volts

This the cut off region

2.

Linear region

Vds < Vgs - Vt

When we put in the values

1.8V < Vgs - 0.7V

1.8V+0.7V < Vgs

2.5Volts < Vgs

This is the linear region when Vgs > 2.5 volts

3.

The saturation region

Vds > Vgs - Vt

When we put in the values we have:

1.8V > Vgs - 0.7V

2.5V > Vgs

And 0.7 < Vgs

Then the saturation region is:

0.7V < Vgs < 2.5 V

Answer:

C - Prototype model

Explanation:

I believe it's C but Hope this Helps!

Answer:

The distance between the station A and B will be:

[tex]x_{A-B}=55.620\: km[/tex]  

Explanation:

Let's find the distance that the train traveled during 60 seconds.

[tex]x_{1}=x_{0}+v_{0}t+0.5at^{2}[/tex]

We know that starts from rest (v(0)=0) and the acceleration is 0.6 m/s², so the distance will be:

[tex]x_{1}=\frac{1}{2}(0.6)(60)^{2}[/tex]

[tex]x_{1}=1080\: m[/tex]

Now, we need to find the distance after 25 min at a constant speed. To get it, we need to find the speed at the end of the first distance.

[tex]v_{1}=v_{0}+at[/tex]

[tex]v_{1}=(0.6)(60)=36\: m/s[/tex]

Then the second distance will be:

[tex]x_{2}=v_{1}*1500[/tex]

[tex]x_{2}=(36)(1500)=54000\: m[/tex]        

The final distance is calculated whit the decelerate value:

[tex]v_{f}^{2}=v_{1}^{2}-2ax_{3}[/tex]

The final velocity is zero because it rests at station B. The initial velocity will be v(1).

[tex]0=36^{2}-2(1.2)x_{3}[/tex]

[tex]x_{3}=\frac{36^{2}}{2(1.2)}[/tex]  

[tex]x_{3}=540\: m[/tex]

Therefore, the distance between the station A and B will be:

[tex]x_{A-B}=x_{1}+x_{2}+x_{3}[/tex]  

[tex]x_{A-B}=1080+54000+540=55.620\: km[/tex]  

I hope it helps you!

Answer:

thanks for the poiunts

Explanation: