Suppose that, in 1998, Japan produced 0.528 million pounds of corn. The total world production that year totaled 71 million pounds of corn. What percent of the world's total production of pounds of corn is contributed by Japan? Round your answer to the nearest tenth.
The work done by the force 4i−3j+2k in moving a particle along a straight line from the point (3,2,−1) to (2,−1,4) is:A. 0 unitsB. 4C. 15D. 19
The work done by the force 4i−3j+2k is the scalar product of the force vector and the displacement vector between the two points. In this case, the displacement vector is (3−2, 2−(−1), −1−4) or (1,3,−5). The scalar product of these two vectors is (1)(4)+(3)(−3)+(−5)(2) = 15 units.
Work is the scalar product of the force and displacement vectors. The force vector in this problem is given as 4i−3j+2k, while the displacement vector (the vector from the starting point to the end point) is (3−2, 2−(−1), −1−4) or (1,3,−5). The scalar product of these two vectors is (1)(4)+(3)(−3)+(−5)(2) = 15 units. This means that the work done by the force is 15 units.
The work done by a force is the energy transferred to an object by the force. It is calculated by taking the scalar product of the force and displacement vectors. This scalar product gives the magnitude of the work done by the force, which in this case is 15 units. This means that the force transferred 15 units of energy to the object by moving it from the starting point to the end point.
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CAN ANYONE WRITE ME A SENTENCE USING THE WORD (YEARS)!
Answer:
Happy New Years sir it is 12:00 in the morning.
Step-by-step explanation:
yes
help me with this pls
Where the OADB is a sector of a circle, and Angle AOB = 80°, and the Radius of OB = 12cm,:
A circular sector (symbol: ) is the piece of a disk (a closed region circumscribed by a circle) contained by two radii and an arc, where the smaller area is known as the minor sector and the bigger as the major sector.
Given m∠AOB = 98°, OB = OA = 25cm (The radii are congruent) Thus,
m∠OAB = m∠OBA,
m∠OAB = (180 - 98) /2
m∠OAB = 41°
In the Right Triangle OBC, OB = 25cm, m∠OBC = 41°
Hence,
OC /OB = Sin ∠OBC ,
OC = OB (Sin ∠OBC )
= 25 * Sin41°
= 16.4cm; thus,
OC = 16.4cm
Where BC/OB = Cos ∠OBC,
BC = OB ( Cos ∠OBC)
= 25 * Cos 41° Thus,
BC = 16.4cm
The area of the ΔOAB = 1/2 * OA * OB * Sin98°
= 1/2 * 25 * 25 * Sin 98°
= 309.5cm²
The area of the Sector OADB = (98°/360°) * π * 25²
= 0.2722222222 * 3.14 * 25²
= 0.2722222222 * 3.14 * 252
= 534.5cm²
The percentage of the diagram that is shaded is given as:
309.5/534.5 * 100
= 0.5790458372 *100
= 57.9%
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In 2003, a school population was 1389. By 2008 the population had grown to 1654
1) Based on the slope equation, between 2003 and 2008, the school population grew by 265 students.
2) It took 5 years for the school population to grow from 1,389 to 1,654.
3) The average population growth per year was 53 students per year.
4) In the year 2000, the school population was 1,230.
5) The equation for the population, P, of the school in t years after 2000 is given as P = 1,230 + 53t.
6) Based on the equation above, the population of the school can be predicted to be 2,025 in 2015.
What is the slope?The slope describes the quotient or ratio of the rise and run.
The slope is found from the linear equation, y = mx + b, where m is the slope and b is the y-intercept.
The school population in 2003 = 1,389
The school population in 2008 = 1,654
Rise (increase) in population = 265 (1,654 - 1,389)
Run (Increase) in years = 5 years (2008 - 2003)
The slope = Rise/Run = 265/5 = 53
Annual increase in the school population = 53 students
Population in 2000:
Difference in years between 2003 and 2000 = 3
Population in 2000 = 1,389 + 53(-3)
= 1,230
Population after 2000:
= 1,230 + 53t
In 2015, the Population should be:
1,230 + 53t
1,230 + 53(15)
= 1,230 + 795
= 2,025
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Find x rounded to one decimal place.
x =
The value of x rounded to one decimal place is 176. 0 units
How to determine the valuesUsing the trigonometric identity, sine, let's find the value of the hypotenuse for the smaller triangle, we have;
sin 60 = 88/x
find the value of sin 60
0. 8660x = 88
Divide both sides by 0. 8660
x = 101. 62
Then to determine the value of x, we have;;
tan 30 = 101.62/x
Find the value of the trigonometric identity, we have;
0. 5774x = 101. 62
divide both sides by the coefficient of x
x = 101. 62/0. 5774
divide the values
x = 175. 99 units
Hence, the value is 176. 0 units
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when constructing bins for a frequency distribution of quantitative data, which of the following principles should generally be followed?
When constructing bins for a frequency distribution, it is important to have equal widths, choose the number of bins based on the sample size, and consider outliers in the data.
A frequency distribution is a representation of data that shows the number of observations in each category or bin.
One of the most important principles is to have an equal number of observations in each bin. This is known as having equal widths for the bins.
To calculate the width of a bin, divide the range of the data by the number of bins desired. The range is then divided into equal parts, each of which becomes a bin width.
Another principle is to have the number of bins chosen based on the sample size.
A rule of thumb is to have at least five observations in each bin, but more bins may be necessary for larger samples.
Additionally, the choice of bin width can also be influenced by outliers in the data. If there are extreme values in the data, it may be necessary to create a separate bin for those values, so they do not dominate the frequency distribution.
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In the figure above, ABCD, BEFG, and DHIJ are squares with AB= 2(DH) and DH = 2(BE). If a point is chosen at random inside square ABCD, what is the probability it will be in the shaded region?
(A) 1/2
(B) 5/8
(C) 11/16
(D) 3/4
Answer:
[tex]\dfrac{11}{16}\\\\[/tex]
Option C
Step-by-step explanation:
We have the following information:
AB = 2DH
DH = 2BE or BE = DH/2
The area of square ABCD = (2DH)² = 4DH²
The area of square BEFG = BE² = (DH/2)² = DH²/4
The area of square DHFJ = DH²
Area of the unshaded region
= area of square BEFG + area or square DHFJ
= DH²/4 + DH² = DH²/4 + 4DH²/4 = 5DH²/4
Area of shaded region
= area of square ABCD - area of unshaded region
[tex]= AB^2 - \dfrac{5}{4}DH^2\\\\= 4DH^2 - \dfrac{5}{4} DH^2\\\\= \dfrac{4DH^2 \cdot 4}{4} - \dfrac{5}{4} \cdot DH^2[/tex]
[tex]= \dfrac{16DH^2 - 5DH^2}{4}= \dfrac{11DH^2}{4}[/tex]
[tex]\textrm{Probability of a point falling in the shaded region} =\dfrac{\textrm{Area of shaded region}}{\textrm{Total area of both regions}}\\\\= \dfrac{11DH^2/4}{4DH^2} = \dfrac{11}{16}\\\\[/tex]
In a box containing 36 strawberries, 2 of them are rotten. Kyle randomly picked 5 of these strawberries.a. What is the probability of having at least 1 rotten strawberry among the 5?b. How many strawberries should be picked so that the probability of having exactly 2rotten strawberries among them equals 2/35?
a) The probability of having at least 1 rotten strawberry among the 5 is 0.262.
b) 1 strawberry must be picked so that the probability of having exactly 2 rotten strawberries among them equals 2/35.
What is probability?
Probability is a way to gauge how likely something is to happen. Many things are difficult to forecast with absolute confidence. Using it, we can only make predictions about the likelihood of an event happening, or how likely it is. Probability can range from 0 to 1, with 0 denoting an impossibility and 1 denoting a certainty.
The probability that Kyle selects exactly k rotten strawberries among the five she randomly picks is -
P( exactly k rotten strawberries) = [tex]\frac{(^2c_k)(^{34}c_{5-k}) }{^{36}c_5}[/tex]
since if she picks k of the 2 rotten strawberries, Kyle must also select 5 - k of the 36 -2 = 34 good strawberries.
Therefore, the probability that Kyle picks at least one rotten strawberry is -
P(at least 1 rotten strawberry) = P(exactly 1 rotten strawberry) + P(exactly 2 rotten strawberries)
P(at least 1 rotten strawberry) =[tex]\frac{(^2c_1)(^{34}c_{4}) }{^{36}c_5} + \frac{(^2c_2)(^{34}c_{3}) }{^{36}c_5}[/tex]
P(at least 1 rotten strawberry) = [(2 × 46376) / 376992] + [(1 × 5984) / 376992]
P(at least 1 rotten strawberry) = (92752 / 376992) + (5984 / 376992)
P(at least 1 rotten strawberry) = 0.246 + 0.016
P(at least 1 rotten strawberry) = 0.262
The probability of selecting exactly 2 rotten strawberries among n is
P(exactly 2 rotten strawberries) = [tex]\frac{(^2c_2)(^{34}c_{n-2}) }{^{36}c_n} = \frac{(^{34}c_{n-2}) }{^{36}c_n}[/tex]
The value for n is 2/35.
P(exactly 2 rotten strawberries) =[tex]\frac{(^{34}c_{\frac{-33}{35}}) }{^{36}c_{\frac{2}{35} }}[/tex]
P(exactly 2 rotten strawberries) = 1 / 1
P(exactly 2 rotten strawberries) = 1
Therefore, the probability is 0.262 and 1 strawberry must be picked.
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What is the intrest amount after borrowing $83,500 at a rate of 4.005% over 6 years? Round your answer to the nearest cent
The amount of interest nearest to cent will be $22,184.62.
What is compound interest?A loan or deposit's interest is computed using the starting principle and the interest payments from the ago decade as compound interest.
We know that the compound interest is given as
A = P(1 + r)ⁿ
Where A is the amount, P is the initial amount, r is the rate of interest, and n is the number of years.
The borrowing amount $83,500 at a rate of 4.005% over 6 years. Then the interest is given as,
I = A - P
I = $83,500 (1.04005)⁶ - $83,500
I = $105,684.62 - $83,500
I = $22,184.62
The amount of interest nearest to cent will be $22,184.62.
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Find and simplify each of the following for f(x) = 4x² - 6x + 9.
(A) f(x + h) =
(Do not factor.)
What is the volume of this figure 10 in. By 1 in. By 9 in. By 8 in. By 7 in.
Answer:504
Step-by-step explanation:
A tower that is 118 feet tall casts a shadow 130 feet long. Find the angle of elevation of the sun to the nearest degree.
Answer:
42°
Step-by-step explanation:
A right-angled triangle can formed in this scenario (image attached), where:
θ = angle of elevation of the sun
Opposite side = The height of the tower
Adjacent side = Length of the shadow
Trigonometric function will be used to determine the angle of elevation:
tanθ = [tex]\frac{opposite}{adjacent}[/tex]
[tex]= \frac{118 feet}{130 feet}[/tex]
feet in the numerator and denominator will cancel each other out completely:
θ =[tex]tan^{-1} (\frac{118}{130})[/tex]
θ = 42.23°
∴ θ = 42° (Rounded to the nearest degree)
TBill rates 2016 Here are a plot and regression output showing the federal rate on 3-month Treasury bills from 1950 to 1980, and a regression model fit to the relationship between the Rate (in %) and Years Since 1950 (www.gpoaccess.gov/eop/). a. What is the correlation between Rate and Year? b. Interpret the slope and intercept. c. What does this model predict for the interest rate in the year 2020?
The correlation between Rate and Year is positive. The slope of the regression line is 0.0275 and the intercept is -9.8086. The model predicts that the interest rate in 2020 will be 2.38%.
The correlation between Rate and Year is positive, which means that as the years go by, the interest rate on 3-month Treasury bills is increasing. The slope of the regression line (0.0275) tells us that the average increase in the interest rate per year is 0.0275%. The intercept of the regression line (-9.8086) represents the interest rate in 1950.
This model predicts that the interest rate in 2020 will be 2.38%, which is obtained by plugging in 1970 for the Year variable and solving for the Rate. It's important to keep in mind that this model is based on historical data, and future interest rates may not follow the same pattern as in the past.
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seven people are going to share an 84-ounce bottle of soda. how many ounces of soda will each person get to dink
Answer:
Each person will get 12 ounces of soda
Step-by-step explanation:
84 ounces divided by 7 people is 12 ounces per person
Answer:
each person will get 12oz
Step-by-step explanation:
84oz divided by the 7 people will get 12oz per person
Assuming that the math module has been imported, which of the following expressions evaluates to True?
a. math.hypot (3,4) == math.sqrt (25)
b. math.hypot (2,5) == math.trunc (2.5)
c. math.hypot (2,5) == math.true (2.5)
d. math.cell (2,5) == math.floor (2.5)
After evaluating these expression it seems to be the option (a) math.hypot(3,4) == math.sqrt(25) evaluate that is True
The math.hypot function calculates the Euclidean distance between two points in a 2D space, which is equivalent to the length of the hypotenuse of a right triangle with sides of length a and b (where a and b are the arguments to math.hypot).
In this case, math.hypot(3, 4) calculates the length of the hypotenuse of a right triangle with sides of length 3 and 4, which is equal to 5.
The expression math.sqrt(25) calculates the square root of 25, which is equal to 5. Since math.hypot(3, 4) and math.sqrt(25) both evaluate to 5, the expression math.hypot(3, 4) == math.sqrt(25) evaluates to True.
The other expressions are not evaluating to True:
b. math.hypot(2,5) != math.trunc(2.5)
c. math.hypot(2,5) != math.true(2.5)
d. math.cell(2,5) does not exist. It is likely a typo for math.ceil which is not equal to math.floor(2.5)
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NO LINKS!! URGENT HELP PLEASE!!!
1. What patterns do you observe in the table? Compare these patterns with those you observe in the graph in Question A.
2. What is the fixed perimeter for the rectangles represented by this table? Explain.
3. What is the greatest area possible for a rectangle with this perimeter? What are the dimensions of this rectangle?
Answer:
1. The pattern that I observe in the table above is that the fixed perimeter of these rectangles are 24 meters, and that the graph to represent this function is in the shape of a parabola with a vertex point at (6, 36). As for comparing the patterns to the graph in question A, assuming you're referring to the question I just answered, the graphs both are parabola shaped, with a vertex point and two zeros, one of them being the same at the origin of the coordinate plane (0, 0).
2. The fixed perimeter for the rectangles represented by this table is 24 meters because if you want to find the fixed perimeter of these rectangles, you can pick any point that is not a zero point of the graph. For example, if the length of a rectangle is 1 meter, and the area is 11 [tex]m^2[/tex], we know the width would be 11 meters. Using this information, we know that the fixed perimeter would be (1 + 11) × 2 = 12 × 2 = 24 meters.
3. The greatest area possible for a rectangle with a perimeter of 24 meters would be 36 [tex]m^2[/tex] because we can graph these points to form a parabola that represents this situation, and the vertex point of this graph would be the greatest area possible out of all the possible combinations of length and width that would still fit the criteria of having a perimeter of 24 meters.
Based on the table, the vertex point of the graph would be (6, 36), therefore the greatest area possible for a rectangle with this perimeter would be 36 [tex]m^2[/tex]. As for the dimensions of this rectangle, we know the length is 6 meters, and the area is 36 [tex]m^2[/tex], so the width would be 36 ÷ 6 = 6 meters. Therefore the dimensions of this rectangle would be 6 meters in length and 6 meters in width.
Have a great day! Feel free to let me know if you have any more questions :)
A party venue charges an event fee of $70 in addition to charging $20 per person at the party.
Use the Ray tool to make a graph that shows C, the total cost of a party at this venue for p people at the party. Graph the ray by plotting two points. The first point selected must be the endpoint of the ray. The second point can be any other point on the ray.
Therefore , the solution of the given problem of equation comes out to be another point on the line would be (3, 110).
What is equation?In arithmetic equations, the identical sign (=) is used to denote the equivalence of two assertions. It is demonstrated that using mathematical methods, which have acted as manifestations of reality, it is feasible to compare different numerical factors. For fact, the equal sign splits the number 12 into two separate parts, even if the answer is y + 6 = 12. It is possible to determine how many letters are also present on either end of this character.
Here,
The equation for the total cost of a party at this venue for p people is:
C = 20p + 70
To graph this equation, you can plot two points and draw a line passing through them.
One point can be the y-intercept (0, 70), which represents the fixed event fee charged by the venue.
The second point can be any other point on the line. For example, when there are 3 people at the party, the total cost would be:
C = 20(3) + 70 = 110
So another point on the line would be (3, 110). Plotting these two points and drawing a line passing through them will give you the graph of the total cost as a function of the number of people at the party.
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You take a package to the local shipping company. They charge a fixed base cost of $6 per package plus an additional $0.39 per pound. If P represents the number of pounds of your package, and C is the total cost of shipping your package, write the linear equation that represents the relationship between P and C
The linear equation that represents the relationship between P and C will be C = 0.39P + 6.
What is a linear equation?A connection between a number of variables results in a linear model when a graph is displayed. The variable will have a degree of one.
The linear equation is given as,
y = mx + c
Where m is the slope of the line and c is the y-intercept of the line.
You take a bundle to the nearby delivery organization. They charge a proper base expense of $6 per bundle in addition to an extra $0.39 per pound.
Let 'P' be the number of pounds and 'C' be the total cost. Then the equation is given as,
C = 0.39P + 6
The linear equation that represents the relationship between P and C will be C = 0.39P + 6.
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8. Use long division to find (2x³ - 7x² + 7x - 2) /(x - 2). Show your work
Answer:
2x² - 3x + 1
Step-by-step explanation:
x - 2 | 2x³ - 7x² + 7x - 2
-- 2x³ - 4x² <== 2x²
- 3x² + 7x - 2
-- - 3x² + 6x <== -3x
x - 2
-- x - 2 <== 1
0 | 2x² - 3x + 1
Thus, the quotient is 2x² - 3x + 1
Answer:
Hello! :)
Answer:
Solved using long polynomial division: [tex]2x^{2} -3x + 1[/tex]
Solved using polynomial division: (2x-1)(x-1)
Sorry I was in a hurry and didn't type out the whole step-by-step.
Verify that the indicated function is an explicit solution of the given differential equation. Assume an appropriate interval I of definition for the solution.
By' +y=0; y e-x/8
When y = e-x/8,
y'--8
Thus, in terms of x,
Sy' + y =
0
Need Help?
X
Read It
X +ex/8
We have the DE, [tex]y'+y=0[/tex], verify that [tex]y=e^{\frac{-x}{8}}[/tex] is a solution.
We have, [tex]y=e^{\frac{-x}{8}}[/tex], find [tex]y'[/tex].
=> [tex]y'=\frac{-1}{8} e^{\frac{-x}{8}}[/tex]
Plug [tex]y[/tex] and [tex]y'[/tex] into the DE.
=> [tex]y'+y=0[/tex]
=>[tex](\frac{-1}{8} e^{\frac{-x}{8}})+(e^{\frac{-x}{8}})=0[/tex]
=> [tex]e^{\frac{-x}{8}}=\frac{1}{8} e^{\frac{-x}{8}}[/tex]
=> [tex]e^{\frac{-x}{8}}\neq \frac{1}{8} e^{\frac{-x}{8}}[/tex]
Thus, [tex]y=e^{\frac{-x}{8}}[/tex], is not a solution to the given DE.
what's the answer to this
Answer:
84.8 squared centimeters
Step-by-step explanation:
You know the height is 8 cm
You know one of the bases has a length of 15.5 cm
You know one of the bases has a length of 5.7 cm
Formula to find a trapezoid:
[tex]\frac{b_{1}+b_{2}}{2}[/tex]×h
so...
substitute!!!!!
The headlights on a car are set so the light beam drops 2 in. for each 21 ft measured horizontally. If the headlights are mounted 24 in. above the ground, how far ahead of the car will they hit the ground?
Question content area bottom
The light beam will hit the ground at a distance of _____ ft ahead of the car
Answer:
The light beam will hit the ground at a distance of _756_ ft ahead of the car
Step-by-step explanation:
Let x be the distance in feet ahead of the car at which the light beam hits the ground.
Since the light beam drops 2 inches for each 21 feet measured horizontally, we can write the relationship between the height of the light beam and the distance x as:
24 - (2/21)x = 0
Solving for x, we get:
x = (21/2) * 24
x = 756
So the light beam will hit the ground 756 feet ahead of the car.
A wage earner receives a gross pay of $983.15 for 52.5 hours of work. What is his hourly rate of pay if a regular workweek is 44 hours and overtime is paid at time-and-a-half the regular rate of pay?
9yr 12yr what is the lateral the area of the cone to the nearest whole number
Answer: 678.58
Step-by-step explanation:
Find an ordered pair (x,y) that is a solution to the equation
Answer:
(3, -11)
Step-by-step explanation:
Rearranging the equation becomes a slope-intercept form:
[tex]y = 2 - 3x[/tex]
where m = slope of equation = [tex]-3[/tex]
and c = intercept = [tex]2[/tex]
Substitute any value of x into the above slope-intercept equation to determine it's corresponding y value. Together these x and y values will form an ordered pair.
For example:
Take x = 3 and substitute in the above mentioned equation:
[tex]y = 2 - 3(3)[/tex]
[tex]= 2 - 9[/tex]
y = [tex]-11[/tex]
∴ An ordered pair that is a solution to the equation: (3, -11)
FILL IN THE BLANK. an unbiased statistic is one in which the average value of the statistic is __ the population parameter.
Answer:
Equal to
Step-by-step explanation:
Peggy invests $8, 400 at 6 1/2% interest for 10 years compounded semiannually. Find the amount of money in the account at the end of the term.
Answer:1200
Step-by-step explanation:1200
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By solving the equation 3x = x² - 4, we know that the positive solution of the given problem is x = 4.
What are equations?Using the equal symbol, they are linked.
For instance, a formula might be 3x - 5 = 16. After solving this equation, we learn that the value of the variable x is 7.
So, using the given information, form the following equation:
3x = x² - 4
Now, solve this equation as follows:
3x = x² - 4
0 = x² - 3x - 4
0 = (x-4)(x+1)
Then, x = 4 and x = -1
Therefore, by solving the equation 3x = x² - 4, we know that the positive solution to the given problem is x = 4.
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solve 2x/\2 - 5x -3 is greater than or equal to zero algebraically
The solution to the given inequality 2x/2 - 5x -3 ≥ 0 is x ≤ - 3/8.
What is inequality?Inequality is defined as mathematical statements that have a minimum of two terms containing variables or numbers that are not equal.
We have to solve 2x/2 - 5x -3 is greater than or equal to zero algebraically.
As per the question, we have inequality as follows:
2x/2 - 5x -3 ≥ 0
2x/2 - 5x ≥ 3
Multiply by 2 on both sides of the inequality,
4x - 20x ≥ 6
-16x ≥ 6
Divided by -16 and flip the sign of the above inequality,
x ≤ - 6/16
x ≤ - 3/8
This is the solution to the given inequality.
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