Answer:
C. 39 m/s
Explanation:
First we need to calculate the total force required to move the train along the inclined plane. So, it is clear that the work done will be equal to the component of the weight that is parallel to the inclined plane, because there is no frictional force present:
Force = F = mg Sin θ
where,
m = mass of train = 3.3 x 10⁶ kg
g = 9.8 m/s²
θ = Angle of Inclination = 0.64°
Therefore,
F = (3.3 x 10⁶ kg)(9.8 m/s²)Sin 0.64°
F = 3.612 x 10⁵ N
Now, the formula for power is:
P = FV
V = P/F
where,
V = Velocity of Train = ?
P = Power of Engine = 14 MW = 1.4 x 10⁷ W
Therefore,
V = 1.4 x 10⁷ W/3.612 x 10⁵ N
V = 38.75 m/s
which is approximately equal to:
C. 39 m/s
The speed of train is 39 m/s. Hence, option (C) is correct.
Given data:
The mass of train is, [tex]m = 3.3 \times 10^{6} \;\rm kg[/tex].
The angle of inclination is, [tex]\theta = 0.64^ {\circ}[/tex].
The useful power output value is, [tex]P= 14 \;\rm MW = 14 \times 10^{6} \;\rm W[/tex].
The work done will be equal to the component of the weight that is parallel to the inclined plane, because there is no frictional force present. So, the total force required to move the train along the inclined plane is given as,
[tex]F = mg sin \theta\\\\F = 3.3 \times 10^{6} \times 9.8 \times sin0.64\\\\F = 361233.75 \;\rm N[/tex]
Now, use the formula of the power to obtain the value of speed as,
[tex]P = F \times v\\\\14 \times 10^{6} =361233.75 \times v\\\\v \approx 38.75 \;\rm m/s[/tex]
Thus, the speed of train is 39 m/s. Hence, option (C) is correct.
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Solve for the unknown variables: (8, 3) + (b, 2) = (4, a).
Answer:
The value of a is 5 and b is -4.
Explanation:
You have to solve it by comparison :
(8 , 3) + (b , 2) = (4 , a)
(8+b , 3+2) = (4 , a)
8 + b = 4
b = 4 - 8
b = -4
3 + 2 = a
a = 5
The figure below shows two forces F1 = 30.0 N and F2 = 20.0 N acting on an object that
can rotate around a center axle. Find the net torque in Nm. (Tolerance +/- 0.05)
Answer:
0.2Nm
Explanation:
F1 = 30.0N
F2 = 20.0N
R = 2.0cm = 0.02m
F1R1 - F2R2 = net Torque
30(0.02) - 20(0.02) = net Torque
0.6-0.4 = net Torque
Therefore net Torque = 0.2Nm
The figure below shows two forces [tex]F_1[/tex] = 30.0 N and [tex]F_2[/tex] = 20.0 N acting on an object that can rotate around a centre axle. The net torque in 0.2 N-m
What is torque?The force that can cause an object to rotate along an axis is measured as torque. Similar to how force accelerates an item in linear kinematics, torque accelerates an object in an angular direction. A vector quantity is a torque.
Torque is defined as Γ=r×F=r F sin(θ). In other words, torque is the cross product of the force vector, where 'a' is the angle between r and F, and the distance vector (the distance between the pivot point and the place where force is applied).
Torque due to [tex]F_1[/tex] = 30.0 N is 0.6 N-m outside the plane and due to [tex]F_2[/tex] = 20.0 N is 0.4 N-m inside the plane so net torque is 0.2 N-m outside the plane.
The figure below shows two forces [tex]F_1[/tex] = 30.0 N and [tex]F_2[/tex] = 20.0 N acting on an object that can rotate around a centre axle. The net torque in 0.2 N-m outside the plane.
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By what factor must you increase the intensity of a sound in order to hear a 1.0-dB rise in the sound level?
Answer:
The right approach will be "1.3". A further explanation is given below.
Explanation:
As we know,
In Decibels, the change in sound volume will be:
= [tex]10log\frac{I_1}{I_2}[/tex]
Now,
According to the question,
⇒ [tex]1=10 log \frac{I_1}{I_2}[/tex]
By applying cross multiplication and putting the value of log, we get
⇒ [tex]10^{\frac{1}{10} }=\frac{I_1}{I_2}[/tex]
⇒ [tex]1.26=\frac{I_1}{I_2}[/tex]
⇒ [tex]\frac{I_1}{I_2}=1.3[/tex]
An object with a mass of 10.5kg is traveling at a velocity of 9m/s. What is the kinetic energy of
the object?
80g of kerosene was burned to raise the temperature of 3 l of water to 90c ⁰C. What is the efficiency of the burner?
Answer:
363
Explanation:
80g of kerosene was burned to raise the temperature
k = 90+273
= 363
Your eyes see different wavelengths of light as different ________.
amplitude
color
detectors
spectrum
Answer:
Its color
Explanation: I got it right
A person swings a 0.546-kg tether ball tied to a 4.56-m rope in an approximately horizontal circle. If the maximum tension the rope can withstand before breaking is 11.0 N, what is the maximum angular speed of the ball
Answer:
2.1 rad/s
Explanation:
Given that,
Mass of a tether ball, m = 0.546 kg
Length of a rope, l = 4.56 m
The maximum tension the rope can withstand before breaking is 11.0 N
We need to find the maximum angular speed of the ball. Let v is the linear velocity. The maximum tension is balanced by the centripetal force acting on it. It can be given by :
[tex]F=\dfrac{mv^2}{r}\\\\v=\sqrt{\dfrac{Fr}{m}} \\\\v=\sqrt{\dfrac{11\times 4.56}{0.546}} \\\\=9.584\ m/s[/tex]
Let [tex]\omega[/tex] is the angular speed of the ball. The relation between the angular speed and angular velocity is given by :
[tex]v=r\omega\\\\\omega=\dfrac{v}{r}\\\\=\dfrac{9.584}{4.56}\\\\=2.1\ rad/s[/tex]
So, the maximum angular speed of the ball is 2.1 rad/s.
How to play track and field
Explanation:
Track and Field is a sport, which is includes disciplines of running, jumping, and throwing events. The sport traces back to Ancient Greece. The first recorded examples of this sport were at the Ancient Greek Olympics. In Ancient Greece, only one event was contested, the stadion footrace. Later on, the game expanded to more events.Events of track and field are divided into three: track events, field events, and combined events. Track events consist of Sprints, middle-distance, long distance, hurdles and relays; Field events consist of jumps and throws; while combined events consist of pentathlon, heptathlon, and decathlon. Track and field is usually played outdoors in stadiums. The usual features of a track and field stadium are the outer running track, and the field within the track
A boy on a treasure hunt walks 12 paces West, then 21 paces North, then 25 paces East. What is the magnitude of boy’s resultant displacement in meters?
Answer: The displacement is 18.8 meters.
Explanation:
Let's define the North as the positive y-axis and the East as the positive x-axis.
We also can assume that if the point (x, y) represents the position of the boy, the initial position is (0 paces, 0 paces).
"A boy on a treasure hunt walks 12 paces West,"
West would be the negative x-axis in this case, then:
the position will be (-12 paces, 0 paces)
"then 21 paces North"
Now the position will be (-12 paces, 21 paces)
"then 25 paces East."
Now the position will be (-12 paces + 25 paces, 21 paces)
= (13 paces, 21 paces)
Now we have the initial and final positions of the boy, (0 paces, 0 paces) and (13 paces, 21 paces) respectively.
We want to find the displacement, which is defined as the distance between the final position and the initial position.
Remember that for two vectors (a, b) and (c, d), the distance is:
D = √( (a - c)^2 + (b - d)^2)
In this case, the displacement will be:
D = √( ( 13 paces - 0 paces)^2 + (21 paces - 0 paces)^2) = 24.7 paces.
But we want this quantity in meters, so we can use the relation:
1 pace = 0.762 meters.
Then 24.7 paces, are 24.7 times 0.762 meters.
D = 24.7*0.762 m = 18.8 meters.
Four charges are placed on the corners of a rectangle. What is the resultant force on the positive charge (a = 1.1 m, b = 0.9 m, q = 2.3 × 10-9C)?
Answer:
F = 93.49 × 10^(-9) N
Explanation:
We are given;
Length of rectangle; a = 1.1 m
Width of rectangle; b = 0.9 m
Charge on rectangle; q = 2.3 × 10^(-9) C
Formula for force is;
F = kq²/r²
Where;
k is a constant = 8.99 x 10^(9) N.m²/C²
a) on the width side, we have;
F = [8.99 x 10^(9) × (2.3 × 10^(-9))²]/0.9²
F = 58.79 × 10^(-9) N
This is on the y-axis
b) on the length side, we have;
F = [8.99 x 10^(9) × (2.3 × 10^(-9))²]/1.1²
F = 39.3 × 10^(-9) N
This is on the x-axis
C) using pythagoras theorem, for the diagonal side, we have c² = a² + b².
Thus;
F = [8.99 x 10^(9) × (2.3 × 10^(-9))²]/(1.1² + 0.9²)
F = 23.54 × 10^(-9) N
Using trigonometric ratios, we can find the angle θ.
tan θ = b/a
tan θ = 0.9/1.1
tan θ = 0.8182
θ = tan^(-1) 0.8182
θ = 39.29°
Resolving along x and y axis, we have;
F_x = 23.54 × 10^(-9) × cos 39.29°
F_x = 18.22 × 10^(-9) N
F_y = 23.54 × 10^(-9) × sin 39.29°
F_y = 14.91 × 10^(-9) N
Resultant force will be;
F = √((Σf_x)² + (ΣF_y)²)
F = √[(18.22 × 10^(-9)) + (39.3 × 10^(-9))]² + [(14.91 × 10^(-9)) + (58.79 × 10^(-9))²]
F = √[(33.0855 × 10^(-16)) + (54.317 × 10^(-16))]
F = 93.49 × 10^(-9) N
When the magnetic flux through a coil of wire changes, what is generated between the ends of the coil? Which equation predicts this?
Answer:
induced electromotive force (Voltage) E = - N dΦ / dt
Explanation:
When the magnetic flux this coil induces a current in each turn of the coil, which is why an induced electromotive force (Voltage) appears at the ends of the coil.
This phenomenon is fully explained by Faraday's law
E = - dΦ / dt
where in the case of a coil with N turns of has
E = - N dΦ / dt
Rl flux is the product of the normal to the area by the magnetic field, in this case the flux changes so we can assume that the area of the coil is constant
HELP ASAP !!!
A train rolls past a stationary observer. To him, the train is moving at a speed
of 25 m/s west, and a woman on the train is moving at a speed of 24.6 m/s
west. How long does it take the woman to move 4 m relative to the train?
A. 7.1 s
B. 9.0 s
C. 8.4 s
D. 10 s
Answer:
10 seconds a mile. D. 10 s
Explanation:
25-24.6= .4
To find how long she will take to move 4 m relative to the train, take the distance she wants to travel divided by her velocity relative to the train.
4 / .4 = 10
Hope this helps you! :)
Answer:
10s
Explanation:
How high of a hill should an 80-kg person climb to expend 40,000 joules of energy?
A. 4.1 km
B. 4.9 km
C. 51 m
D. 500 m
Answer:
1: 51 m
2: some energy was transformed to other forms
3: 3.24
4: 45j
5: 1020
Explanation:
The required height of hill is 51 m. Hence, option (C) is correct.
Given data:
The mass of person is, m = 80 kg.
The energy expended during climbing is, E = 40,000 J.
The energy possessed by the body by virtue of height is known as potential energy. In the given case, the energy expended by the person will be stored in the form of potential energy. Then,
E = U
E = mgh
here, h is the height of hill and g is the gravitational acceleration.
Solving as,
40000 = 80(9.8) h
h ≈ 51 m
Thus, we can conclude that the required height of hill is 51 m. Hence, option (C) is correct.
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Riding a bicycle on a flat, smooth surface is a lot easier than riding it along a bumpy surface or up a hill. A bumpy surface creates more friction with your bike tires than a smooth surface does, and going up a hill means fighting gravity.
Write about a time you had to ride a bicycle on a difficult surface. What did you have to do to adjust your riding?
Answer:
one time i was one the flat ground at my aunts house then we went on a hike so i brought my bike it had just rained that day so it was kinda muddy so there was sticks everywhere.i was riding up hill and noticed that it was very hard,then i rode down hill and it was much better
Explanation:
Find the magnitude of the vector v given its initial and terminal points. Round your answer to four decimal places.
Complete Question
The complete question is shown on the first uploaded image
Answer:
The value is [tex]|v| = 6.93[/tex]
Explanation:
From the question we are told that
The initial point is [tex](x_1 , y_1 , z_1 ) = (-1 , 7 , 4 )[/tex]
The terminal point is [tex](x_2 , y_2 , z_2) = (-5 , 11, 8 )[/tex]
Generally the magnitude of the vector is mathematically represented as
[tex]|v| = \sqrt{(x_2 -x_1 )^2 + (y_2 - y_1 )^2 + (z_2 -z_1)^2}[/tex]
=> [tex]|v| = \sqrt{(-5 -(-1) )^2 + (11 - 7 )^2 + (8 -4)^2}[/tex]
=> [tex]|v| = 6.93[/tex]
according to newton's first law of motion what is the reason for a ball throwing up in the airfall back to earth
What is the height of a building that an object is dropped from if it has a mass of 3 kg and hits the ground with a velocity of 50 m/s?
Answer:
125 m
Explanation:
m = 3kg
v = 50m/s
u = 0m/s
a = +g = 10m/s²
s = H = ?
using the formula,
v² = u² + 2as
50² = 0² + 2(10)(H)
2500 = 20H
H = 2500/20
H = 125m
matter can be a solid, lquid or gas. but you cannot see the particles or adoms that make up matter because they are
Answer:
very small...
Explanation:
i guess... but i may be missing something. the question feels too straightforward
2. An 85.5 kg astronaut is training for accelerations that he will experience upon reentry. He is placed in a centrifuge (r = 12.0 m) and spun at a constant angular velocity of 18.4 rpm. Answer the following:
(a) What is the angular velocity of the centrifuge in ?
(b) What is the linear velocity of the astronaut at the outer edge of the centrifuge?
(c) What is the centripetal acceleration of the astronaut at the end of the centrifuge?
(d) How many g’s does the astronaut experience?
(e) What is the centripetal force experienced by the astronaut?
Answer Expert Verified
Hello here is your answer and also please mark me as brainlest
Since one revolution around a circle is 2 pi radian; hence 1 rpm equals 2 pi radians per minute. And because a minute has 60 seconds, 1 rpm equals 1/60 revolution per second. Therefore, we have 2 pie/60 * 15.3 = 0.2513 rps. The linear velocity v = wr where w is the angular velocity in rad/s and r is the distance. So we have 0.2513 * 10.0 = 2.513 rad/s The centripetal acceleration is given by a = w^2 r = (2.513)^2 * 10 = 63.15 rad/s2 The centripetal force F = mass * centripetal acc = 75 * 63.15 = 4736.25 N The torque = centripetal force * distance = 4736 * 63.15 = 299078.4 Nm Two forces acts on the astronaut. The normal force and acceleration due to gravity.
I hope this help you
brainlest
Rotational kinematics and Newton's second law allow to find the results for the astronaut's movement in the centrifuge are:
a) The angular velocity is: w = 1.927 rad / s
b) The linear velocity is: v = 23.1 m / s
c) The centripetal acceleration is: a = 6.417 10³ m / s²
d) The centripetal acceleration is: a = 6.548 10² g
e) The centripetal force F = 5.49 10⁵ N
given parameters
The mass of the astronaut m = 85.5 kg Centrifuge radii r = 12.0 m Angular velocity w = 18.4 rpm (2prad / 1rev) (1min / 60s) = 1.927 rad / sTo find
a) angular velocity
b) linear velocity
c) centripetal acceleration
d) acceleration in units of gravity (g)
e) the centripetal force
The angular velocity is defined as the rotated angle in the unit of time.
[tex]w = \frac{\Delta \theta}{t}[/tex]
Angular and linear variables are related.
v = w r
Where w is the angular velocity, θ is the angle, t the time, v the lienal velocity and R the radius of the cetnrifuga
Let's answer the questions:
a) The angular velocity of the centrifuge and the astronaut are equal
w = 1.927 rad / s
b) Linear velocity
v = 1.927 12.0
v = 23.1 m / s
c) Centripetal acceleration has the formula:
a = [tex]\frac{v^2}{R}[/tex]
a = [tex]\frac{23.1^2}{12.0}[/tex]
a = 6.417 10³ m / s²
d) The value of this eceleration as a function of gravity
[tex]\frac{a}{g}[/tex] = 6.417 10³ / 9.8
[tex]\frac{a}{g}[/tex] = 6.548 10²
a = 6.548 10² g
e) The centripetal force
F = ma
F = 85.5 6.417 10³
F = 5.49 10⁵ N
In conclusion, using rotational kinematics and Newton's second law we can find the results for the movement of the astronaut in the centrifuge are:
a) The angular velocity is: w = 1.927 rad / s
b) The linear velocity is: v = 23.1 m / s
c) The centripetal acceleration is: a = 6.417 10³ m / s²
d) The centripetal acceleration is: a = 6.548 10² g
e) The centripetal force F = 5.49 10⁵ N
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WHAT IS CHANGES IN SOLID MATERIALS
Answer: Solid to a Liquid Liquid to a Solid Liquid to a Gas Gas to a Liquid Solid to a Gas Gas to a Solid
Explanation:
Did the energy you used to lift the notebook get stored in the book as potential energy? Explain your answer with reasons.
Answer:
Because when you move a object the energy stored in moving objects. As the object moves faster, more energy is stored. Motion energy is the sum of potential and kinetic energy in an object that is used to do work.
Explanation:
answer it please
What is the Central Idea of "Shelter Dog Protects Owner with Epilepsy“
What is the author’s viewpoint?
Do you agree or disagree with that viewpoint?
Why? Explain your answer.
parpgraph 1-2
Answer:
Yes, the energy used to lift the book was stored in the book as potential energy. The book moved when it was let go.
Explanation:
This is what edmentum sample answer says so I hope this helps out!
What is the acceleration a of the refrigerator 4 s after the person begins pushing on it with a force of 400 N?
Answer:
What is the acceleration a of the refrigerator 4 s after the person begins pushing on it with a force of 400 N? a=2m/s^2 Applying Newton's 2nd law, a=Fnet/m=(400N)/(200kg)=2m/s^2. The acceleration is constant.
Explanation:
The person begins to push a refrigerator with a force of 400 N. So, the acceleration of the refrigerator will be 2 m/s².
What is Acceleration?In mechanics, acceleration is the measure of how rapidly an object's velocity changes over time. It is a vector quantity. An object's acceleration depends on the direction of the net force exerted on it.
A vector quantity, acceleration is something that has both a magnitude and a direction. As a vector quantity, velocity is also. The ratio of the velocity vector change over a time interval to that interval is the definition of acceleration.
There are several types of acceleration :
Uniform AccelerationNon-Uniform AccelerationAverage AccelerationAccording to the question, the given values are :
Force applied to the refrigerator is 400 N.
The mass of the refrigerator is 200 kg.
Use the 2nd law of newton,
[tex]Force= mass*acceleration[/tex]
Acceleration = 400/200
Acceleration = 2 m/s².
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How much energy is stored in a 2.80-cm-diameter, 14.0-cm-long solenoid that has 200 turns of wire and carries a current of 0.800 A
Answer:
The energy stored in the solenoid is 7.078 x 10⁻⁵ J
Explanation:
Given;
diameter of the solenoid, d = 2.80 cm
radius of the solenoid, r = d/2 = 1.4 cm
length of the solenoid, L = 14 cm = 0.14 m
number of turns, N = 200 turns
current in the solenoid, I = 0.8 A
The cross sectional area of the solenoid is given as;
[tex]A = \pi r^2\\\\A = \pi (0.014)^2\\\\A = 6.16*10^{-4} \ m^2[/tex]
The inductance of the solenoid is given by;
[tex]L = \frac{\mu_0 N^2A}{l} \\\\L = \frac{(4\pi*10^{-7})(200^2)(6.16*10^{-4})}{0.14}\\\\L = 2.212*10^{-4} \ H[/tex]
The energy stored in the solenoid is given by;
E = ¹/₂LI²
E = ¹/₂(2.212 x 10⁻⁴)(0.8)²
E = 7.078 x 10⁻⁵ J
Therefore, the energy stored in the solenoid is 7.078 x 10⁻⁵ J
The energy stored in a 2.80-cm-diameter, 14.0-cm-long solenoid that has 200 turns of wire and carries a current of 0.800 A is 7.07 × 10⁻⁵ J.
A solenoid is a type of electromagnet, whose purpose is to generate a controlled magnetic field through a coil wound into a tightly packed helix.
First, given the diameter of the solenoid (d) is 2.80 cm (0.0280 m), we can calculate the cross-sectional area (A) using the following expression.
[tex]A =\pi \times (\frac{d}{2} )^{2} = \pi \times (\frac{0.0280}{2} )^{2} = 6.16 \times 10^{-4} m^{2}[/tex]
Next, we will calculate the inductance (L) of the solenoid using the following expression.
[tex]L = \frac{\mu _0 \times N^{2} \times A}{l} = \frac{(4\pi \times 10^{-7}H/m ) \times 200^{2} \times (6.16 \times 10^{-4}m^{2} )}{0.140m} = 2.21 \times 10^{-4} H[/tex]
where,
μ₀ is the vacuum permeabilityN is the number of turnsl is the length of the solenoidFinally, for a current (I) of 0.800 A, we can calculate the energy stored (E) using the following expression.
[tex]E = \frac{1}{2} \times L \times I^{2} = \frac{1}{2} \times (2.21 \times 10^{-4}H ) \times (0.800A)^{2} = 7.07 \times 10^{-5} J[/tex]
The energy stored in a 2.80-cm-diameter, 14.0-cm-long solenoid that has 200 turns of wire and carries a current of 0.800 A is 7.07 × 10⁻⁵ J.
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sound is faster than light that is why we hear thunder before we see lightning
Answer:
false
Explanation:
sound travels slower than light. that is why we see lightning before we hear the thunder
When discussing Newton's laws of motion which terms do people most likely use when talking about Newton's third law of motion
Answer:
Explanation:
When discussing Newton's laws of motion, the most likely used terms when talking about Newton's third law of motion are action and reaction. According to this law, for every action there is an equal and opposite reaction
Answer: C. "action" and "reaction"
Explanation: Newtons 3rd law of motion: for every action, there is an equal and opposite reaction (action and reaction forces are described by this law).
Have a nice day. :)
A cup of coffee is sitting on a table in a train that is moving with a constant velocity. The coefficient of static friction between the cup and the table is 0.30. Suddenly, the train accelerates. What is the maximum acceleration that the train can have without the cup sliding backward on the table?
Answer:
a = 2.94 m/s²
Explanation:
In order for the cup not to slip, the unbalanced force on cup must be equal to the frictional force:
Unbalanced Force = Frictional Force
ma = μR = μW
ma = μmg
a = μg
where,
a = maximum acceleration for the cup not to slip = ?
μ = coefficient of static friction = 0.3
g = acceleration due to gravity = 9.8 m/s²
Therefore,
a = (0.3)(9.8 m/s²)
a = 2.94 m/s²
Two cylinders P and Q are made of copper
P
The height of P is twice the height of Q. The diameter of P is half the diameter of
Which statement is comrect?
A The density of cylinder Pis four times that of cylinder o
The density of cylinder Pis twice that of cylinder
The density of cylinder P is equal to that of cylinder Q
The density of cylinder P is half that of cylinder o
с
D
Let H and D denote the height and diameter, respectively, of cylinder P, and h and d the height and diameter of cylinder Q.
Then the volumes of P and D, denoted V and v, respectively, are
V = π (D / 2)² H = π D ² H / 4
v = π (d / 2)² h = π d ² h / 4
The height of P is twice the height of Q, so H = 2h.
The diameter of P is half the diameter of Q, so D = d / 2.
Substitute these into equation for the volume of cylinder P:
V = π (d / 2)² (2h) / 4
V = π (d ² / 4) (2h) / 4
V = π d ² h / 8
V = 1/2 • π d ² h / 4
V = v / 2
That is, cylinder P has half the volume of cylinder Q.
Recall that density is equal to mass per unit of volume. So R and ρ, the respective densities of cylinders P and Q, are
R = m / V = m / (v / 2) = 2 m / v
ρ = m / v
which means cylinder P has twice the density of cylinder Q (assuming both cylinders have the same mass m).
A food processor draws 8.47 A of current when connected to a potential difference of 110 V.
a. What is the power consumed by this appliance?
b. How much electrical energy is consumed by this food processor monthly (30 days) if it is used on average of 10.0 min every day?
c. Assume that the price of electrical energy is 7.00 $/kWh. What is the monthly cost of using this food processor?
2. The electric meter in a house indicates that the refrigerator consumes 70.0 kWh in a week.
a. What is the power consumption of the refrigerator?
b. Assuming it is connected to a potential difference of 120 V , how much current does the refrigerator draw?
3. The heating element of an electric broiler dissipates 2.8 kW of power when connected to a potential difference of 120 V.
a. What is the resistance of the element?
b. How much current does the broiler draw? Use two ways to find out, and verify your answer.
Answer:
i want the answer
Explanation:i want the answer
a. The power consumed by this appliance is 931.7W
b. The electrical energy is consumed by this food processor monthly (30 days) if it is used on average of 10.0 min every day is 4.65kWh
c. The monthly cost of using this food processor is 32.55 $
What is power?
The rate of consumption of energy is power. it is given by the product of potential difference(V) and current(I)
a. P = VI
here V = 110V . I = 8.47 A
P = 110 x 8.47 = 931.7W
hence power consumed is 931.7 W
b. electrical energy consumed by this food processor monthly (30 days) if it is used on average of 10.0 min every day is
E = P/t
Here, P = 931.7 W = 0.93kW
t = 10 x 30 = 300 min = 5 h
So, E =0.93 x 5 = 4.65 kWh
hence electrical energy consumed is 4.65kWh
c. The monthly cost of using the food processor is
given ,
Cost of one unit is 7.00$
Cost of 4.65 unit will be 7.0 x 4.65 = 32.55$
monthly cost of using the food processor is 32.55$
2.
a. Power consumption of refrigerator is 416 W
P = E/t
Here, E = 70 kwh . t = 1 week = 168 h
So, P= 70/168 = 0.416 kW = 416 W
b. Current drawn by the refrigerator is 3.46A
P = VI
Here, V = 120V, P = 416 W
So, I = P/V = 416/120 = 3.46 A
3.
a. The resistance of the element is 5.14 Ω
b. Current drawn by the boiler is 23,33A
What is resistance?Resistance is the hindrance caused in the flow of current
a. The resistance is given by [tex]R = v^{2} / P[/tex]
here V = 120V , P = 2.8kW = 2800W
R = (120 x 120)/ 2800 = 5.14Ω
Hence Resistance of the boiler is 51.4Ω
b. V = IR so, I = V /R
Here, V = 120V , R = 5.14Ω
So, I = 120/51.4 = 23.33 A
Hence current drawn by the boiler is 23.33A
The alternate way to find the current is by using formula
P = VI
I = P/V
Since, P = 2800W, V = 120V
So, I = 2800/120 =23.33 A
Hence Current comes out to be the same from both the method which verifies the answer .
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Answer:
Frequency and period are distinctly different, yet related, quantities. Frequency refers to how often something happens. Period refers to the time it takes something to happen. Frequency is a rate quantity.
Answer:
Frequency and period are distinctly different, yet related, quantities. Frequency refers to how often something happens. Period refers to the time it takes something to happen. Frequency is a rate quantity.
Explanation:
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