Answer:
174
Step-by-step explanation:
Find the the slope of the line that contain 5,3 and -1,4
Answer:
-1/6
Step-by-step explanation:
the equation to do this is y2-y1/x2-x1
therefore you set it up as 4-3/-1-5
then when you simplify it it would be 1/-6
therefore the slope is -1/6
Convert 63° to radians.
Answer:
1.1025rad
Step-by-step explanation:
1°=0.0175rad
63°=0.0175rad*63=1.1025rad
x + 3y=9
x + y = 21
Solve it algebraically
Answer:
[tex]x=27[/tex]
[tex]y=-6[/tex]
Step-by-step explanation:
substitute in values
[tex]x=21-y[/tex]
[tex](21-y)+3y=9[/tex]
[tex]21+2y=9[/tex]
[tex]2y=-12[/tex]
[tex]y=-6[/tex]
[tex]x+(-6)=21[/tex]
[tex]x=27[/tex]
PLSSSS THIS IS 20 POINTS AND U GET BRAINLIEST!!! Are the lines x = 2 and y = 5 parallel? Are the perpendicular? Explain.
i just need someone to tell me i can do it. i know this is wasting someone, somewheres time but i need someone to tell me i can this work done. im so far behind on edgenuity and i feel worthless.
In a recent study on world happiness, participants were asked to evaluate their current lives on a scale from 0 to 10, where 0 represents the worst possible life and 10 represents the best possible life. The mean response was with a standard deviation of . (a) What response represents the percentile? (b) What response represents the percentile? (c) What response represents the quartile? (a) The response that represents the percentile is nothing. (Round to two decimal places as needed.) (b) The response that represents the percentile is nothing. (Round to two decimal places as needed.) (c) The response that represents the quartile is nothing. (Round to two decimal places as needed.)
Answer:
(a) 8.35
(b) 5.98
(c) 3.86
Step-by-step explanation:
The complete question is:
In a recent study on world happiness, participants were asked to evaluate their current lives on a scale from 0 to 10, where 0 represents the worst possible life and 10 represents the best possible life. The mean response was 5.4 with a standard deviation of 2.3. (a) What response represents the 90th percentile? (b) What response represents the 60th percentile? (c) What response represents the first quartile?
Solution:
Assume that the world happiness ratings follows a Normal distribution with parameters μ = 5.4 and σ = 2.3.
(a)
Compute the response representing the 90th percentile as follows:
P (X < x) = 0.90
⇒ P (Z < z) = 0.90
The value of z for the above probability is, z = 1.282.
Compute the value of x as follows:
[tex]x=\mu+z\sigma[/tex]
[tex]=5.4+(1.282\times 2.3)\\\\=5.4+2.9486\\\\=8.3486\\\\\approx 8.35[/tex]
Thus, the response representing the 90th percentile is 8.35.
(b)
Compute the response representing the 60th percentile as follows:
P (X < x) = 0.60
⇒ P (Z < z) = 0.60
The value of z for the above probability is, z = 0.25.
Compute the value of x as follows:
[tex]x=\mu+z\sigma[/tex]
[tex]=5.4+(0.25\times 2.3)\\\\=5.4+0.575\\\\=5.975\\\\\approx 5.98[/tex]
Thus, the response representing the 60th percentile is 5.98.
(c)
Compute the response representing the first quartile of the 25th percentile as follows:
P (X < x) = 0.25
⇒ P (Z < z) = 0.25
The value of z for the above probability is, z = -0.67.
Compute the value of x as follows:
[tex]x=\mu+z\sigma[/tex]
[tex]=5.4+(-0.67\times 2.3)\\\\=5.4-1.541\\\\=3.859\\\\\approx 3.86[/tex]
Thus, the response representing the first quartile is 3.86.
The length of a rectangular parking lot is 32 meters and the width is 20 meters. The parking lot is surrounded by a sidewalk that is x meters wide. Find the expression that represents the area of the parking lot, including the sidewalk.
∠A and ∠B are complementary. The measure of ∠A is 21°.
What is the measure of ∠B?
Enter your answer in the box.
point theif = ban
Answer:
69°Step-by-step explanation:
Complementary angles sum to 90°.
We have the measure of one angle, find the missing one as below.
m∠A + m∠B = 90°21° + m∠B = 90°m∠B = 90° - 21°m∠B = 69°Complementary angles have sum 90°
[tex]\\ \sf\longmapsto x+21=90[/tex]
[tex]\\ \sf\longmapsto x=90-21[/tex]
[tex]\\ \sf\longmapsto x=69[/tex]
Which number belongs to solution set of the inequality 11>x
A.11
B.15
C.12
D.4
Solve the equation P=KTV for the letter K.
Answer:
K = [tex]\frac{P}{TV}[/tex]
Step-by-step explanation:
P = KTV
Divide both sides by TV
(P/TV) = K
Brandon is half of Ella's age. Ella is three times Tristans age. In fifteen years, their combined age will be 89. How old is Brandon?
Answer:
Step-by-step explanation:
Let Brandon's age be [tex]x[/tex]
Therefore Ella=[tex]2x[/tex]
Tristan= [tex]\frac{2x}{3}[/tex]
Fifteen years time add 15 to each age
Brandon: [tex]x+15[/tex]
Ella: [tex]2x+15[/tex]
Tristan:[tex]\frac{2x}{3} +15[/tex]
All their ages together=89
So: [tex]x+15[/tex] + [tex]2x+15[/tex] + [tex]\frac{2x}{3} +15[/tex][tex]=89[/tex]
[tex]3\frac{2}{3} x=44[/tex]
[tex]x= \frac{44}{3\frac{2}{3} } =12[/tex]
Rewrite as equivalent rational expressions with denominator (a−7)(a−2)(a+8):
Answer:
[tex] \dfrac{3(a + 8)}{(a - 7)(a - 2)(a + 8)} [/tex]
[tex] \dfrac{8a(a - 2)}{(a - 7)(a - 2)(a + 8)} [/tex]
Step-by-step explanation:
[tex] \dfrac{3}{a^2 - 9a + 14} = [/tex]
[tex] = \dfrac{3}{(a - 7)(a - 2)} [/tex]
[tex] = \dfrac{3(a + 8)}{(a - 7)(a - 2)(a + 8)} [/tex]
[tex] \dfrac{8a}{a^2 + a - 56} = [/tex]
[tex] = \dfrac{8a}{(a + 8)(a - 7)} [/tex]
[tex] = \dfrac{8a(a - 2)}{(a - 7)(a - 2)(a + 8)} [/tex]
6 6 small bricks have the same mass as 5 large bricks. The mass of one small brick is 2.5 kg. What is the mass of one large brick?
Since 6 small bricks have the same mass as 5 large bricks and the mass of one small brick is 2.5 kg, the mass of one of the large bricks is 3 kg
What is mass?Mass is the quantity of matter in a physical body.
6 small bricks have the same mass as 5 large bricks.
let
the total mass of the small or large bricks = x
Therefore,
6 × 2.5 = x
x = 15 kg
Therefore, the mass of each large bricks can be calculated as follows:
let the mass of each large bricks = y
15 = 5y
divide both sides by 6
y = 15 / 5
y = 3 kg
Therefore, the mass of one of the large bricks is 3 kg
.learn more on mass here: https://brainly.com/question/895643
A triangle has two sides of lengths 4 and 15. What value could the length of
the third side be? Check all that apply.
A skating rink charges $5 per hour plus $3 to rent skates. A second skating rink charges $6 per game plus $2 to rent skates. How many games would person have to play for the two skating rinks to cost the same amount?
Answer:
Each of them would play 2 games to get the same cost amount
Step-by-step explanation:
for example
#1) $5 + $3 = $8 x 2 = $16
#2) $6 + $2 = $8 x 2 = $16
Round 14,465 to the nearest ten thousands place:
Answer:
10,000 is the answer
Step-by-step explanation:
14 465
round up the 4 which is 0 then your answer would be 10000
Find the volume of a right rectangular prism if the dimensions of the base are 4 centimeters by 9 centimeters and the height is 11 centimeters.
A 396^3.
B 241^3.
C 144^3.
D 370^3.
396 cm²
Volume of rectangular prism - -
Formula's :
Length * Width * HeightBase area * HeightHere base area:
Length * Width
4 * 9
36 cm²
Volume:
Base area * Height
36 * 11
396 cm²
how many different simple random samples of size 5 can be obtained from a population whose size is 45
?
This value is slightly over 1.2 million
========================================================
How I got that answer:
We have 45*44*43*42*41 = 146,611,080 different permutations. I started with 45 and counted down by 1 until I had 5 values multiplied out.
If order mattered, then we would stop here. But order doesn't matter. All that matters is the group overall rather than any particular individual or how they rank in the group.
There are 5! = 5*4*3*2*1 = 120 different ways to arrange a five item set, so the very large result we got earlier is overcounting by a factor of 120.
To fix this, we divide by 120 to get
(146,611,080)/120 = 1,221,759
This represents the number of combinations in which we're selecting 5 members from a pool of 45 total.
You could use the nCr formula
[tex]_nC_r = \frac{n!}{r!*(n-r)!}[/tex]
with n = 45 and r = 5 to get the same answer in bold above.
Using the principle of Combination, the number of different random samples of size five which can be obtained form a population of 45 is 1221759
Using the principle of combination, which is defined as :
nCr = n! ÷ (n-r)!r! n = 45 r = 5Hence,
45C5 = 45! ÷ (45 - 5)!5!
45C5 = 45! ÷ 40!5!
45C5 = (45 × 44 × 43 × 42 × 41) / (5 × 4 × 3 × 2 × 1)
45C5 = 1221759
Therefore, there are 1221759 ways of making a selection of 5 samples from a population of size 45.
Learn more :https://brainly.com/question/10699405?referrer=searchResults
(-5xy)(-9xy) (-2xy) =
Simplify
Answer:
-90x^3y^3
Step-by-step explanation:
Multiply: -
2/3 x 6/7
Put your answer in lowest terms.
A. 4/7
B. 4/21
C. 12/21
D. 3/7
Answer:
It should be -4/7
Step-by-step explanation:
I hope i helped. And If you can, can you help me by subing to my YT. It’s called Not Claz and it is the same profile pick I have on Brainly.
FIRST TO ANSWER GETS MARKED BRAINLEST! please look at picture. The probability that a student guesses the correct answer to a four-choice multiple choice question is P(correct) = 0.25. How many correct answers should a student expect to guess on a test with 56 four-choice multiple choice questions?
A student should expect to guess_______correct answers.
Answer:
14 answers
Step-by-step explanation:
since there is 1/4 of a chance to get a question right by guessing you need to see what 1/4 of 56 is, which is 14
write an equation of the line below
Answer:
y=3x
Step-by-step explanation:
Select the expression that will calculate how many eighths are in 2 bars? Use the model to help you.
a. 2÷ 8
b. 8÷ 2
c. 2÷ 1/8
d. 8 ÷ 1/2
Answer:
4
Step-by-step explanation:
4*2=8
and 4/8 also equals four anyway you simplify the question it will equal 4
F(x)=2x^2-5x g(x)=-3x^2 find f(2)
3b. For each differential equation, find the Laplace transform of the solution y:
y'' − y = 5e^−4x + 2x, y(0) = y'(0) = 0.
Answer:
[tex]y(x)=-2x-\frac{11}{6}e^{-x}+\frac{3}{2}e^x+\frac{1}{3}e^{-4x}[/tex]
Step-by-step explanation:
[tex]y''-y=5e^{-4x}+2x,\: y(0)=y'(0)=0\\\\\mathcal{L}\{y''\}-\mathcal{L}\{y\}=\mathcal{L}\{5e^{-4x}\}+\mathcal{L}\{2x\}\\\\s^2Y(s)-sy(0)-y'(0)-Y(s)=\frac{5}{s+4}+\frac{2}{s^2}\\ \\s^2Y(s)-Y(s)=\frac{5}{s+4}+\frac{2}{s^2}\\ \\(s^2-1)Y(s)=\frac{5}{s+4}+\frac{2}{s^2}\\ \\Y(s)=\frac{5}{(s+4)(s^2-1)}+\frac{2}{s^2(s^2-1)}\\ \\Y(s)=\frac{5s^2+2(s+4)}{s^2(s+4)(s^2-1)}\\ \\Y(s)=\frac{5s^2+2s+8}{s^2(s-1)(s+1)(s+4)}[/tex]
Perform the partial fraction decomposition
[tex]\frac{5 s^{2} + 2 s + 8}{s^{2} \left(s - 1\right) \left(s + 1\right) \left(s + 4\right)}=\frac{A}{s}+\frac{B}{s^{2}}+\frac{C}{s + 1}+\frac{D}{s - 1}+\frac{E}{s + 4}\\\\5 s^{2} + 2 s + 8=s^{2} \left(s - 1\right) \left(s + 1\right) E + s^{2} \left(s - 1\right) \left(s + 4\right) C + s^{2} \left(s + 1\right) \left(s + 4\right) D + s \left(s - 1\right) \left(s + 1\right) \left(s + 4\right) A + \left(s - 1\right) \left(s + 1\right) \left(s + 4\right) B[/tex]
[tex]5 s^{2} + 2 s + 8=s^{4} A + s^{4} C + s^{4} D + s^{4} E + 4 s^{3} A + s^{3} B + 3 s^{3} C + 5 s^{3} D - s^{2} A + 4 s^{2} B - 4 s^{2} C + 4 s^{2} D - s^{2} E - 4 s A - s B - 4 B\\\\5 s^{2} + 2 s + 8=s^{4} \left(A + C + D + E\right) + s^{3} \left(4 A + B + 3 C + 5 D\right) + s^{2} \left(- A + 4 B - 4 C + 4 D - E\right) + s \left(- 4 A - B\right) - 4 B[/tex]
Solve for each constant
[tex]\begin{cases} A + C + D + E = 0\\4 A + B + 3 C + 5 D = 0\\- A + 4 B - 4 C + 4 D - E = 5\\- 4 A - B = 2\\- 4 B = 8 \end{cases}[/tex]
[tex]-4B=8\\B=-2[/tex]
[tex]-4A-B=2\\-4A-(-2)=2\\-4A+2=2\\-4A=0\\A=0[/tex]
[tex]A+C+D+E=0\\C+D+E=0\\E=-C-D[/tex]
[tex]-A+4B-4C+4D-E=5\\4(-2)-4C+4D-(-C-D)=5\\-8-4C+4D+C+D=5\\-3C+5D=13\\5D=13+3C[/tex]
[tex]4A+B+3C+5D=0\\4(0)+(-2)+3C+13+3C=0\\-2+6C+13=0\\11+6C=0\\6C=-11\\C=-\frac{11}{6}[/tex]
[tex]5D=13+3C\\5D=13+3(-\frac{11}{6})\\5D=13-\frac{33}{6}\\5D=\frac{15}{2}\\D=\frac{15}{10}\\D=\frac{3}{2}[/tex]
[tex]E=-C-D\\E=-(-\frac{11}{6})-(\frac{3}{2})\\E=\frac{11}{6}-\frac{3}{2}\\E=\frac{2}{6}\\E=\frac{1}{3}[/tex]
Take the inverse transform and solve for the IVP
[tex]Y(s)=\frac{0}{s}+\frac{-2}{s^2}+\frac{-\frac{11}{6}}{s+1}+\frac{\frac{3}{2}}{s-1}+\frac{\frac{1}{3}}{s+4}\\ \\y(x)=-2x-\frac{11}{6}e^{-x}+\frac{3}{2}e^x+\frac{1}{3}e^{-4x}[/tex]
7+3 express as a difference
Answer:
7 - (-3)
Step-by-step explanation:
You want the sum 7 + 3 expressed as a difference.
DifferenceThe difference of A and B is written A - B. The subtraction operation is involved.
Subtraction is the same as addition of the opposite. Or, addition is the same as subtracting the opposite:
7 + 3 = 7 - (-3)
__
Additional comment
We can also write the difference as ...
3 - (-7)
<95141404393>
What is -86 + x = - 4x + 29
Answer:
x = 23
Step-by-step explanation:
Add 4x to the left and add 86 to the right.
5x = 115
Now, divide 5 on both sides to get x.
x = 23.
The result is 23.
Answer:
x= – 115/3
Step-by-step explanation:
I don’t know what exact form you want so I’ll give you mixed number form.
A restaurant decides to test their oven's thermostat to see if it is working properly, that is, if the actual temperature inside the oven is the same as the temperature to which the thermostat was set. Twenty times, the oven was set at 350 degrees and then the temperature was measured with a thermometer. The chef wants to know if the average oven temperature is different from 350, when the thermostat is set at 350. What is the correct null and alternative hypothesis for this test
Considering the situation described in the exercise, it is found that the correct null and alternative hypothesis for this test are given by, respectively:
[tex]H_0: \mu = 350[/tex]
[tex]H_1: \mu \neq 350[/tex]
What are the hypothesis tested?At the null hypothesis, it is tested if the mean is of 350 degrees, that is:
[tex]H_0: \mu = 350[/tex]
At the alternative hypothesis, it is tested if the mean is different of 350 degrees, hence:
[tex]H_1: \mu \neq 350[/tex]
More can be learned about the test of an hypothesis at https://brainly.com/question/26454209
a box of 40 chocolates contains 56g of saturated fat. How much saturated fat is there in 1 chocolate
Divide total fat by number of chocolates
56/40 = 1.4 grams
answer: 1.4 grams
3x-8=3(x-3)-2
Is there a answer to this problem? I cant find one
Answer:
The input is a contradiction: it has no solutions